9 divided by 3/4 pls help

Answer:

4

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

that means that there are 9 boys

Step-by-step explanation:

because 18÷9=2

Answer:

\(\huge\boxed{f(8) = 62}\)

Step-by-step explanation:

\(\sf f(x) = 9x-10\\\\Put\ x = 8\\\\f(8) = 9(8) -10\\\\f(8) = 72-10\\\\f(8) = 62\\\\\rule[225]{225}{2}\)

Hope this helped!

Answer:

f(8) = 62

Step-by-step explanation:

To evaluate f(8) substitute x = 8 into f(x) , that is

f(8) = 9(8) - 10 = 72 - 10 = 62

Answer:

$3780

Step-by-step explanation:

Salary per month = $10500

Expense on food

= 36% of the monthly salary

= 36% of $10500

= (36/100) × $10500

= 36 × $105

= $3780

So, they spend $3780 on food per month.

Answer:

\(\frac{dc}{dt}\approx13.8146\text{ km/min}\)

Step-by-step explanation:

We know that the plane travels at a constant speed of 14 km/min.

It passes over a radar station at a altitude of 11 km and climbs at an angle of 25°.

We want to find the rate at which the distance from the plane to the radar station is increasing 4 minutes later. In other words, if you will please refer to the figure, we want to find dc/dt.

First, let's find c, the distance. We can use the law of cosines:

\(c^2=a^2+b^2-2ab\cos(C)\)

We know that the plane travels at a constant rate of 14 km/min. So, after 4 minutes, the plane would've traveled 14(4) or 56 km So, a is 56, b is a constant 11. C is 90+20 or 115°. Substitute:

\(c^2=(56)^2+(11)^2-2(56)(11)\cos(115)\)

Evaluate:

\(c^2=3257-1232\cos(115)\)

Take the square root of both sides:

\(c=\sqrt{3257-1232\cos(115)}\)

Now, let's return to our law of cosines. We have:

\(c^2=a^2+b^2-2ab\cos(C)\)

We want to find dc/dt. So, let's take the derivative of both sides with respect to t:

\(\frac{d}{dt}[c^2]=\frac{d}{dt}[a^2+b^2-2ab\cos(C)]\)

Since our b is constant at 11 km, we can substitute this in:

\(\frac{d}{dt}[c^2]=\frac{d}{dt}[a^2-(11)^2-2a(11)\cos(C)]\)

Evaluate:

\(\frac{d}{dt}[c^2]=\frac{d}{dt}[a^2-121-22a\cos(C)]\)

Implicitly differentiate:

\(2c\frac{dc}{dt}=2a\frac{da}{dt}-22\cos(115)\frac{da}{dt}\)

Divide both sides by 2c:

\(\frac{dc}{dt}=\frac{2a\frac{da}{dt}-22\cos(115)\frac{da}{dt}}{2c}\)

Solve for dc/dt. We already know that da/dt is 14 km/min. a is 56. We also know c. Substitute in these values:

\(\frac{dc}{dt}=\frac{2(56)(14)-22\cos(115)(14)}{2\sqrt{3257-1232\cos(115)}}\)

Simplify:

\(\frac{dc}{dt}=\frac{1568-308\cos(115)}{2\sqrt{3257-1232\cos(115)}}\)

Use a calculator. So:

\(\frac{dc}{dt}\approx13.8146\text{ km/min}\)

And we're done!

If we randomly select 62 travel mugs and measure the amount of soft drink dispensed in each mug, the sample mean will be within 0.5 ounces of the population mean with 95% confidence.

To determine the number of travel mugs required for the study, we need to use the formula for sample size determination for means. The formula is:

n = (Z^2 * σ^2) / E^2

Where:

n = sample size

Z = Z-score for the desired confidence level (e.g., 1.96 for 95% confidence level)

σ = standard deviation of the population

E = desired margin of error (i.e., the maximum difference between the sample mean and the population mean)

In this case, we are given that the standard deviation of the soft drink dispensed is 2.0 ounces and we want the sample mean to be within 0.5 ounces of the population mean. Let's assume a 95% confidence level, which corresponds to a Z-score of 1.96. Plugging in the values, we get:

n = (1.96^2 * 2^2) / 0.5^2 = 61.6

We need to round up to the nearest whole number, so the final sample size should be 62 travel mugs. The larger the sample size, the smaller the margin of error will be, but it also means more time and resources required for the study.

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Complete question is:

a baseball parkamount of soft drink dispensed is normally distributed with standard deviation 2.0 ounces. how many travel mugs should be included in a study if it is desiredthat the sample mean soft drink dispensed be within 0.5 ounces of the population mean with 95% confidence.

The required height of the trapezoid is 4 ft.

In geometry, a quadrilateral with at least one pair of parallel sides is referred to as a trapezoid in American, Canadian, and British English. In Euclidean geometry, a trapezoid is inevitably a convex quadrilateral. The trapezoid's parallel sides are referred to as its bases.

Given data;

a= 3 ft, b = 7 ft, height = h, Area = 20 sq, ft

So,

Area = (a + b)h/2

20 = (3 + 7)h/2

20 = 10h/2

2 = h/2

h = 4 ft

Thus, required height of the trapezoid is 4 ft.

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In the equation value of A=\(\frac{-32}{5} , B= \frac{36}{5} , C= \frac{1}{10} , D= \frac{-7}{2}\).

What is equation?

The definition of an equation in algebra is a mathematical statement that demonstrates the equality of two mathematical expressions. For instance, the equation 3x + 5 = 14 consists of the two equations 3x + 5 and 14, which are separated by the 'equal' sign.

Here the given equation is \(\frac{3x^3+4x^2-6x}{x^2+2x+2}= \frac{(Ax+B)}{x^2+2x+2}+\frac {C}{(x-1)}+\frac{D}{x+1}\)

In RHS we multiply to get common denominator. Hence

=> \(\frac{3x^3+4x^2-6x}{(x^2+2x+2)(x^2-1)}= \frac{(Ax+B)(x^2-1)+C(x^2+2x+1)(x+1)+D(x-1)(x^2+2x+2)}{(x^2+2x+2)(x^2-1)}\)

Removing the common denominator we get

=> \({3x^3+4x^2-6x}= (Ax+B)(x^2-1)+C(x^2+2x+1)(x+1)+D(x-1)(x^2+2x+2)\)

=> \(3x^3+4x^2-6x=Ax^3-Ax+Bx^2-B+Cx^3+Cx^2 +2Cx^2 +2Cx+2Cx+2C+D(x^3 +2x^2 +2x-x ^2 -2x-2)\)

=> \($ 3x^3+4x^2-6x =(A+C+D)x^3+ (B+3C+D)x^2+(-A+2C+2C)x + (-B+2C-2D)\)

We can compare the coefficients to get

3=A+C+D−−−−−−−−1

4=B+3C+D−−−−−−2

−6=−A+4C−−−−−3

0=−B+2C−2D−−−−−−4

Add 2 and 4  then

=> 4 = 5C-D -----------5

Add 1 and 3 then

=> -3 =5C+D--------6

Now subtract 5 from 6 then

=> -7=2D

=> D = -7/2

Now put D=-7/2 into 5 then

=> 4=5c+7/2

=> 1/2=5C

=> C= 1/10

Now put value of C into 3 then

=> -6=-A+ 4×1/10

=> -6-2/5 = -A

=> A = -32/5

Now put C and D into 2 then

=> 4=B+3C+D

=> 4 = B+3/10-7/2

=> 4 = B-32/10

=>4+32/10 = B

=> B= 36/5

Hence in the equation value of A=\(\frac{-32}{5} , B= \frac{36}{5} , C= \frac{1}{10} , D= \frac{-7}{2}\).

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Answer:

B , C

Step-by-step explanation:

-2 · 4 = -8

-1 · - 18 = 18

the two numbers are different, so it’s not an inversely proportional relation

The largest angle of the pentagon with the given ratio of angles is: 180°.

A pentagon is a 5-sided polygon with 5 interior angles that have a sum of 540 degrees.

If the ratio of the angles are: 1:2:2:3:4, then the largest angle would be calculated as shown below:

4/(1+2+2+3+4) × 540

4/12 × 540 = 180°

The largest angle is: 180°.

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Answer: 81,000

Step-by-step explanation:

We can solve this by using the formula given.

If f(1)=1000x3^1, then 1,000x3=3,000

If f(2)=1000x3^2, then 3^2=9 and 1000x9=9000,

and so on,

Now, f(4) will equal 1000x3^4, and 3^4 is 3x3x3x3, which is 9x9 or 9^2, which would be equal to 81, and 81x1000=81,000

To complete the table of values for the exponential function f(x) = 1000*3^x, we can evaluate the function for x = 0, 1, 2, 3, and 4, since we are interested in the number of bacteria on the phone after 4 hours.

x f(x)

0 1000

1 3000

2 9000

3 27,000

4 81,000

Therefore, after 4 hours, there will be 81,000 bacteria on the surface of the phone, assuming the number of bacteria triples every hour and can be described by the exponential function f(x) = 1000*3^x.

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Answer:

k = 14

Step-by-step explanation:

k = 14 because if you isolatethe variable by dividing each side by factor that dosent contain the variable

Answer:

I'm pretty sure this is the correct answer hope it helps :)

Based on the transformation of the given parent function f(x), the function g(x) is: C. g(x) = ∛(x) + 2

In Mathematics, the translation of a geometric figure to the right is a type of transformation which simply means adding a digit to the value on the x-coordinate (x-axis) of the pre-image while translating a geometric figure up is a type of transformation that simply means adding a digit to the value on the y-coordinate (y-axis) of the pre-image.

Translating the parent function f(x) = ∛(x) two (2) units up, would produce an image of function f(x):

g(x) = f(x) + 2

g(x) = ∛(x) + 2

In this context, we can reasonably infer and logically deduce that the parent function f(x) was shifted 2 units up to produce function g(x).

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The transformation given as A(-8,7) → A'(-8,-7) represents a reflection over x-axis .

In the reflection of the point (x,y) over x-axis transformation ,the x-coordinate of each point remains the same, but the y-coordinate is negated (changes sign).

Let's consider the coordinates of point A that is  (-8, 7).

The transformation takes this point to A' (-8, -7).

We can see that the x-coordinate of the point remains the same which is -8. but , the y-coordinate changes from 7 to -7.

We know that in a reflection over the x-axis, the x-coordinate remains the same while the y-coordinate changes sign.

Therefore , the transformation that takes A to A' is a reflection over the x-axis.

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The given question is incomplete , the complete question is

Identify the Transformation given as A(-8,7) → A'(-8,-7)?

Answer:

3.92$

Step-by-step explanation:

Answer:

the tax is 3.92

Step-by-step explanation:

the total is: 94.08

Answer:

16 : 28

Step-by-step explanation:

If 12 out of the 28 pupils are female, we can calculate the number of males by subtracting the number of females from the total number of pupils.

28 - 12 = 16

So, there are 16 males in the class. Now, we know that the ratio of males : total is 16 : 28.

I hope this helps! Have a lovely day!! :)

(brainliest is much appreciated!!)

Answer:

give they guy brainliest

Step-by-step explanation:

because hes right

(a)The optimal order quantity is  4609 units.

(b)The time between orders is  1.98 months.

To determine the optimal order quantity and the approximate time between orders, the Economic Order Quantity (EOQ) model. The EOQ model minimizes the total cost of inventory by balancing ordering costs and carrying costs.

Optimal Order Quantity:

The formula for the EOQ is given by:

EOQ = √[(2DS) / H]

Where:

D = Annual demand

S = Cost per order

H = Holding cost per unit per year

calculate the annual demand (D) using the 2020

sales numbers provided:

D = 651 + 808 + 514 + 174 + 435 + 426 + 687 + 582 + 662 + 1551 + 1295 + 1774

= 9559 units

To calculate the cost per order (S) and the holding cost per unit per year (H).

The cost per order (S) is given as $500.

The holding cost per unit per year (H)  calculated as follows:

H = Carrying cost percentage × Unit value

= 0.30 × $3

= $0.90

substitute these values into the EOQ formula:

EOQ = √[(2 × 9559 × $500) / $0.90]

= √[19118000 / $0.90]

≈ √21242222.22

≈ 4608.71

Approximate Time Between Orders:

To calculate the approximate time between orders, we'll divide the total number of working days in a year by the number of orders per year.

Assuming 360 days in a year and a lead time of 1 week (7 days) for shipping, we have:

Working days in a year = 360 - 7 = 353 days

Approximate time between orders = Working days in a year / Number of orders per year

= 353 / (9559 / 4609)

= 0.165 years

Converting this time to months:

Approximate time between orders (months) = 0.165 × 12

= 1.98 months

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Answer:

25 N

Step-by-step explanation:

Given, the force field is F(x,y,z) = and particle moves along the line segment from (-1, 2, 1) to (1, -2, 3).

Work done by the force field is given by\($$W=\int_C \vec{F}\cdot d\vec{r}$$\)where C is the curve that particle follows.

In this case, C is the line segment from (-1, 2, 1) to (1, -2, 3).We can parametrize the curve C as\($$\vec{r}(t)=\langle -1+2t, 2-4t, 1+2t\rangle$$where $0\leq t\leq 1$.Then,$$\vec{r}(0)\)

\(=\langle -1, 2, 1\rangle$$and$$\vec{r}(1)=\langle 1, -2, 3\rangle$$\)We can differentiate \($\vec{r}$ with respect to t to obtain$$\vec{r'}(t)=\langle 2, -4, 2\rangle$$Then, $d\vec{r}=\vec{r'}(t)dt=\langle 2, -4, 2\rangle dt$.\)

Therefore\(,$$W=\int_0^1 \vec{F}(\vec{r}(t))\cdot \vec{r'}(t)dt$$$$=\int_0^1 \langle t^2, t, t\rangle \cdot \langle 2, -4, 2\rangle dt$$$$=\int_0^1 4t^2-4t+2dt$$$$=\frac{4}{3}-2+2$$$$\)

=\(\frac{2}{3}$$\)Thus, the work done by the force field is\($\frac{2}{3}$.\).

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Question 4: Laura applies for the position of ambulance medic. To give her a job simulation (behavioral interview) screening test, the interviewer...

This question involves providing a job simulation or behavioral interview, which allows the interviewer to observe how the candidate performs in a simulated work situation. This type of question assesses the candidate's skills, abilities, and behavior in a real or simulated work scenario, providing a more accurate evaluation of their capabilities for the job.

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The equation's answer is x = 7.5. 4x - 1 2 = x + 7.

x = 1 is the answer to the problem 3x + 2 = (2x + 13) 3.

a) To solve the equation 4x - 1 ÷ 2 = x + 7, we need to isolate the variable x. Let's follow the steps:

1: Distribute the division operation to the terms inside the parentheses.

  (4x - 1) ÷ 2 = x + 7

2: Divide both sides of the equation by 2 to isolate (4x - 1) on the left side.

  (4x - 1) ÷ 2 = x + 7

  4x - 1 = 2(x + 7)

3: Distribute 2 to terms inside the parentheses.

  4x - 1 = 2x + 14

4: Subtract 2x from both sides of the equation to isolate the x term on one side.

  4x - 1 - 2x = 2x + 14 - 2x

  2x - 1 = 14

5: Add 1 to both sides of the equation to isolate the x term.

  2x - 1 + 1 = 14 + 1

  2x = 15

6: Divide both sides of the equation by 2 to solve for x.

  (2x) ÷ 2 = 15 ÷ 2

  x = 7.5

Therefore, x = 7.5 is the solution to the equation 4x - 1 ÷ 2 = x + 7. However, note that this answer is not an integer, so it may not be valid for certain contexts.

b) To solve the equation 3x + 2 = (2x + 13) ÷ 3, we can follow these steps:

1: Distribute the division operation to the terms inside the parentheses.

  3x + 2 = (2x + 13) ÷ 3

2: Multiply both sides of the equation by 3 to remove the division operation.

  3(3x + 2) = 3((2x + 13) ÷ 3)

  9x + 6 = 2x + 13

3: Subtract 2x from both sides of the equation to isolate the x term.

  9x + 6 - 2x = 2x + 13 - 2x

  7x + 6 = 13

4: Subtract 6 from both sides of the equation.

  7x + 6 - 6 = 13 - 6

  7x = 7

5: Divide both sides of the equation by 7 to solve for x.

  (7x) ÷ 7 = 7 ÷ 7

  x = 1

Hence, x = 1 is the solution to the equation 3x + 2 = (2x + 13) ÷ 3.

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