87 divided by 17 and what is the remainder

Answer:

(4 + 8) * 6  - 2  

Step-by-step explanation:

P - Parenthesis

E - Exponent

D - Division

M = Multiplication

A -  Addition

S - subtraction

(4 + 8) * 6  - 2  = 12 *6 - 2    

                        = 72 - 2

                        = 70

Answer:

d.) ( 4 + 8 ) × 6 - 2

Step-by-step explanation:

( 4 + 8 ) × 6 - 2

Add 4 and 8.

Multiply; 12 by 6.

Subtract 2 from 72.

Answer:

708

Step-by-step explanation:

Using trig we know that tan of an angle is equal to opposite/adjacent, using this we can conclude that tan(42)=top half of x/518 so we do tan(42)*518 to find the side of the top triangle and then do the same process for the bottom one but instead of using tan(42) you use tan(25)

The octagon's remaining equal angles are each 121.5 degrees.

The sum of the interior angles of any polygon is given by the formula:

Sum of interior angles = (n - 2) * 180 °

where n is the number of sides of the polygon.

In the case of an octagon, which has 8 sides, the sum of the interior angles is:

Sum of interior angles = (8 - 2) * 180°

= 6 * 180°

= 1080°

Now, we subtract the known angles from the sum:

1080 ° - (120 ° + 110° + 130 ° + 144° + 90°) = 486°

We are left with 486 °, which is the sum of the equal angles in the octagon. Since there are four equal angles remaining, we divide 486 ° by 4:

486° / 4 = 121.5°

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The size of each of the equal angles is 162 degrees. All the remaining three angles are equal to each other and have a value of 162 degrees.

We know that the sum of all interior angles in a polygon = (n-2)180

where n is the number of sides of that polygon.

In this case, we have an octagon,

The sum of all interior angles in an octagon = (8-2) 180

n = 8 ( an octagon has 8 sides)

The sum of all interior angles in an octagon, A = 1080 degrees.

Sum of given angles = 120 + 110 +130 +144 + 90 = 594

We have 3 more angles in the octagon which are all equal, let's say x

A + x + x + x = 1080

594 + 3x = 1080

3x = 486x

x = 162 degrees

Hence, the remaining equal angles are 162 degrees.

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Approximately 34% of American adults have a mobile phone but not a landline, based on the given proportions from the study conducted by the Centers for Disease Control.

The proportion of American adults who have a mobile phone but not a landline, we need to subtract the proportion of those who have both a mobile phone and a landline from the proportion of those who have a mobile phone.

Let's denote the proportion of American adults who have a mobile phone as P(M), the proportion who have a landline as P(L), and the proportion who have neither as P(N).

Given information:

P(M) = 89% (proportion with a mobile phone)

P(L) = 57% (proportion with a landline)

P(N) = 2% (proportion with neither)

We can now calculate the proportion of adults who have a mobile phone but not a landline using the following equation:

P(M and not L) = P(M) - P(M and L)

To find P(M and L), we can subtract P(N) from P(L) since those who have neither are not included in the group with a landline:

P(M and L) = P(L) - P(N)

P(M and L) = 57% - 2%

P(M and L) = 55%

Now we can substitute the values back into the equation to find P(M and not L):

P(M and not L) = P(M) - P(M and L)

P(M and not L) = 89% - 55%

P(M and not L) = 34%

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Answer:

Step-by-step explanation:

If you mean 3x^3 - 42x^2 - 4x + 5 = 0 you can graph it manually or with technology

The roots are 14.09, 0.30 and -0.39 to nearest hundredth.

The area of the surface S, represented parametrically as F(u, v) = [(1-v)cosu]i + [(1-v)sinu]j + vk for 10≤z≤12, cannot be determined without additional information or constraints.

To calculate the area of the surface S using the evaluation theorem of surface integrals, we need to have a specific parameterization or limits of integration provided for u and v. Without these details, it is not possible to determine the area of the surface.

In general, to find the area of a surface represented parametrically, we use the formula: Area = ∬S ||F_u × F_v|| dA

where F_u and F_v are the partial derivatives of F(u, v) with respect to u and v, respectively, ||F_u × F_v|| is the magnitude of the cross product of F_u and F_v, and dA represents the differential area element.

To apply the evaluation theorem of surface integrals, we would need to specify the parameterization of the surface, such as the range of values for u and v, or any additional constraints on the surface. Without this information, it is not possible to proceed with the calculation.

Therefore, without further details, the area of the surface S, represented by F(u, v) = [(1-v)cosu]i + [(1-v)sinu]j + vk for 10≤z≤12, cannot be determined.

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Answer:

85,696

Step-by-step explanation:

4 x 104 = 416

2 x 103 = 203

No sign between parentheses means that you have to multiply the two outcomes of the parentheses.

416 x 203 = 85,696

The relative percent increase can be calculated dividing the absolute change in the population over the initial value.

The absolute increase is:

The relative percent increase is then given by:

Therefore, the absolute increase was 2,300, and the relative percent increase was 70.8%.

Answer:

Step-by-step explanation:

Slope is 1.5

Y intercept is (0,1) A

Equation y = (3x/2) + 1 = 1.5x + 1A

What does it mean by another solution?

If it means the other way to do slope (y=mx+b)

b=4−(3/2) * 2 = 1

The answer is still y=(3x/2)+1

The values of a and b that make the piecewise defined function f(x) = 3x + 4, for x < -3, and f(x) = 2x^2 + ax + b, for x > -3, both continuous and differentiable everywhere are a = 6 and b = 9.

To ensure that the piecewise defined function is continuous at the point where x = -3, we need the left-hand limit and right-hand limit to be equal. The left-hand limit is given by the expression 3x + 4 as x approaches -3, which evaluates to 3(-3) + 4 = -5.

On the right-hand side of the function, when x > -3, we have the expression 2x^2 + ax + b. To find the value of a, we need the derivative of this expression to be continuous at x = -3. Taking the derivative, we get 4x + a. Evaluating it at x = -3, we have 4(-3) + a = -12 + a. To make this expression continuous, a must be equal to 6.

Next, we find the value of b by considering the right-hand limit of the piecewise function as x approaches -3. Substituting x = -3 into the expression 2x^2 + ax + b, we get 2(-3)^2 + 6(-3) + b = 18 - 18 + b = b. To make the function continuous, b must equal 9.

Therefore, the values of a and b that make the piecewise defined function both continuous and differentiable everywhere are a = 6 and b = 9.

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Answer:

y - 7 =  3/5 (x - 1)

Step-by-step explanation:Step-by-step explanation:

For Sienna to be able to take the square root of both sides while solving a quadratic equation, she must have an expression with square on at least, the side that contains the variable she is trying to determine. Equation of the form:

(x + a) ² = b

'a' and 'b' could be any number, -1, 0, 1/3, -5/6, anything really.

So, she can take square roots of both sides then, like this

√(x + a)² = √b

x + a = ±√b

x = -a ± √b

Square roots always cancel out squares, and the '±' is because a square is satisfies by both + and -, 3² = 9, and (-3)² = 9.

It is the nature of the problem being solved that determines if we take just one or both of these answers.

Answer:

m∠CDE = 60°

Step-by-step explanation:

Given that the arc at the center = 2 times the arc at the circumference, we have;

Angle at the center = arc CE = 120°

Whereby the angle at the circumference is given as m∠CDE and it is opposite the circle arc CE

We note that m∠CDE is the acute angle between chord DC and DE

Therefore, we have;

Angle at the center = 120° = 2 times the arc at the circumference = 2 × m∠CDE

120° = 2 × m∠CDE

m∠CDE = 120/2 = 60°

Therefore the angle of m∠CDE is equal to 60°.

To solve this problem, we need to use the concepts of orbital mechanics and gravitational potential energy.

Part A

The velocity of the satellite in the inner circular orbit is given by the equation:

v = sqrt(GM/r)

where G is the gravitational constant, M is the mass of the earth, and r is the radius of the orbit. Substituting the given values, we get:

v = sqrt(6.674 x 10^-11 N*m^2/kg^2 * 5.97 x 10^24 kg / (260 x 10^3 m))

v = 7760 m/s

Part B

The velocity of the satellite at the low point of the elliptical orbit can be found using the equation:

v = sqrt(2GM/r1 - 2GM/r2)

where r1 and r2 are the radii of the inner and outer circular orbits, respectively. Substituting the given values, we get:

v = sqrt(2 * 6.674 x 10^-11 Nm^2/kg^2 * 5.97 x 10^24 kg / (260 x 10^3 m) - 2 * 6.674 x 10^-11 Nm^2/kg^2 * 5.97 x 10^24 kg / (35,900 x 10^3 m))

v = 1.004 x 10^4 m/s

Part C

The work done by the rocket motor to transfer the satellite from the circular orbit to the elliptical orbit is given by the difference in gravitational potential energy between the two orbits. This can be calculated using the equation:

W = mgh = m * G * M/r

where m is the mass of the satellite, g is the acceleration due to gravity, h is the height of the orbit above the earth's surface, and r is the radius of the orbit. Substituting the given values, we get:

W = 1000 kg * 6.674 x 10^-11 Nm^2/kg^2 * 5.97 x 10^24 kg / (260 x 10^3 m) - 1000 kg * 6.674 x 10^-11 Nm^2/kg^2 * 5.97 x 10^24 kg / (35,900 x 10^3 m)

W = 3.80 x 10^9 J

Part D

The velocity of the satellite at the high point of the elliptical orbit can be found using the equation:

v = sqrt(GM/r1 + GM/r2)

Substituting the given values, we get:

v = sqrt(6.674 x 10^-11 Nm^2/kg^2 * 5.97 x 10^24 kg / (260 x 10^3 m) + 6.674 x 10^-11 Nm^2/kg^2 * 5.97 x 10^24 kg / (35,900 x 10^3 m))

v = 2.24 x 10^4 m/s

Part E

The velocity of the satellite in the outer circular orbit can be found using the equation in Part A, with the radius of the orbit set to 35,900 km. This gives:

v = sqrt(6.674 x 10^-11 N*m^2/kg^2 * 5.97 x 10^24 kg / (35,900 x 10^3 m)) v = 2.74 x 10^3 m/s

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The graph meets the vertical line test requirement, it must represent a function (C) The vertical line test shows that the graph is correct, hence the answer is yes.

According to the function, every value in the domain is associated to exactly one value in the range, and they have a predefined domain and range. It is characterized as a certain kind of relationship.

Please refer to the image instead of the graph, which is related to it.

The graphic displays a graph.

A parabola is seen on the graph.

The vertical line test determines if a graph can be a function, as is common knowledge.

The graph passes the vertical line test option, indicating that it does in fact represent a function (C) The vertical line test shows that the graph is correct, hence the answer is yes.

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\(6k^{2}\) as a product of Prime Factors we can write as \(2^{3} * 3^{5} * p^{6}\).

A number can be expressed as the product of its prime components through the process of prime factorization. A number with precisely two elements, 1 and the number itself, is said to be a prime number. As an illustration, let's use the number 30. Even though we are aware that 30 = 5 6 is not a prime number, The factorization of the integer 6 may also be expressed as 2 + 3, where 2 and 3 are prime numbers. As a result, the prime factorization of 30 is 2* 3 *5 with prime integers as each of the elements.

Prime factorization is the technique of expressing a number as the product of prime numbers. The only two components in prime numbers are the number itself and the number itself. Prime numbers include, for instance, 2, 3, 5, 7, 11, 13, 17, 19, and so forth. Any integer may be represented as a sum of prime numbers using prime factorization.

Let the equation be,

\(k = 2 * 3^{2} * p^{3}\)

Therefore ,

\(6k^{2} = 2 * 3 * k^{2}\)

\(k^{2} =(2 * 3^{2} * p^{3})^{2} = 2^{2} * 3^{4} * p^{6}\)

Therefore , simplifing the equation we get,  

\(6k^{2} = 2 * 3 * k^{2} = 2 * 3 *2^{2} * 3^{4} * p^{6} = 2^{3} * 3^{5} * p^{6}\)

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The FSA can be defined as follows:

Q: set of states {q0, q1, q2, q3}

∑: set of input symbols {0, 1}

q0: initial state

F: set of final states {q1, q2, q3}

δ: transition function

δ(q0, 0) = q0

δ(q0, 1) = q1

δ(q1, 0) = q2

δ(q1, 1) = q1

δ(q2, 0) = q3

δ(q2, 1) = q1

δ(q3, 0) = q3

δ(q3, 1) = q3

The FSA (Finite State Automaton) that recognizes binary strings with two or more Os anywhere in the string can be constructed using four states: q0, q1, q2, and q3. The initial state is q0 and the set of final states is {q1, q2, q3}. At state q0, the machine reads input symbol 0 and remains in state q0, while reading input symbol 1 transition to state q1.

At state q1, the machine reads input symbol 0 and transitions to state q2, while reading input symbol 1 remains in state q1. At state q2, the machine reads input symbol 0 and transitions to state q3, while reading input symbol 1 transition to state q1.

At state q3, the machine reads either input symbol 0 or 1 and remains in state q3. If the machine reaches any of the final states, it accepts the input string.

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Answer:

y=\(\frac{3}{5}x\)-6

Step-by-step explanation:

Remember the slope-intercerpt form

y=mx+b

The measured signal could have a dynamic error of approximately 21.6% of the true value due to the limitations of the 1st order system with a time constant of 0.7 seconds.

The dynamic error that could result from measuring a 2 Hz periodic waveform using a 1st order system with a time constant of 0.7 seconds can be estimated using the following formula:

Dynamic error = 100% x (1 - exp(-T/τ)),

where T is the period of the input signal, τ is the time constant of the system, and exp(-T/τ) is the system's gain at the input frequency.

Substituting T = 0.5 s (since the period of a 2 Hz waveform is 0.5 seconds) and τ = 0.7 s, we get:

Dynamic error = 100% x (1 - exp(-0.5/0.7)) ≈ 21.6%

This means that the measured signal could have a dynamic error of approximately 21.6% of the true value due to the limitations of the 1st order system with a time constant of 0.7 seconds. This error is due to the fact that the system cannot respond fast enough to the rapid changes in the input signal, leading to an output that lags behind the input. The larger the time constant of the system relative to the period of the input signal, the larger the dynamic error will be.

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Answer:

\((x+2)(2x-1)(2x+3)\)

Start by multiplying the first two terms:

\((2x^2+3x-2)(2x+3)\)

Now multiply these two terms to prove:

\((4x^3+6x^2+6x^2+9x-4x-6)\)

Simplify:

\((4x^3+12x^2+5x-6)\)

The average change in population each year is a decrease of 70 students.

Since, Population simply means the total number of people living in a particular area.

Here, The expression is given as n - p /5 where n is this year's population and where p represents the previous population.

This will be:

= n - p /5

= 1250 - 1600 / 5

=-350 / 5

= -70

Thus, This implies a reduction of 70 students per year.

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Answer:

Step-by-step explanation:

a bacuse

Answer:

2.5 miles per hour

Step-by-step explanation:

Just take 15 decide by 6 if I am not wrong

Answer:

2.5 miles per hour

Step-by-step explanation:

6 divided by 6=1 hour.

15 divided by 6= 2.5

Answer:

There are 2 solutions to square root x = 9

They are 3, and -3

Step-by-step explanation:

The square root of x=9 has 2 solutions,

The square root means, for a given number, (in our case 9) what number times itself equals the given number,

Or, squaring (i.e multiplying with itself) what number would give the given number,

so, we have to find the solutions to \(\sqrt{9}\)

since we know that,

\((3)(3) = 9\\and,\\(-3)(-3) = 9\)

hence if we square either 3 or -3, we get 9

Hence the solutions are 3, and -3

Since there wer two penalties, each of five yard, the total change in yards due to the penalties is:

there was a change of 10 yards due to the penalties

The property that refers to the intended receiver of a message being able to prove to any third party that the message came from the actual sender is called non-repudiation.

Non-repudiation refers to the concept of ensuring that a party cannot deny the authenticity or integrity of a communication or transaction that they have participated in. It is a security measure that provides proof or evidence of the origin or delivery of a message, as well as the integrity of its contents, thereby preventing the sender or recipient from later denying their involvement or the validity of the communication.

Non-repudiation is commonly used in digital communications, particularly in electronic transactions and digital signatures. It ensures that the parties involved in a transaction cannot later deny their participation or claim that the transaction was tampered with.

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Answer:

9

Step-by-step explanation:

-5 + (-18) +32

-23 + 32

32 -23

The given differential equation dy/dx + 2cos(x+y) = 0 is not separable because it cannot be written in the form of a product of two functions, one involving only y and the other involving only x.

A separable differential equation is one that can be expressed as a product of two functions, one involving only y and the other involving only x. In the given equation, dy/dx + 2cos(x+y) = 0, we have terms involving both x and y, specifically the cosine term. To determine if the equation is separable, we need to rearrange it into a form where y and x can be separated.

Attempting to separate the variables, we would need to isolate the y terms on one side and the x terms on the other side of the equation. However, in this case, it is not possible to do so due to the presence of the cosine term involving both x and y. Therefore, the given differential equation is not separable.

To solve this equation, other methods such as integrating factors, exact differentials, or numerical methods may be required. Separation of variables is not applicable in this case.

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