If the elevator is ascending with an acceleration of 3.0 m/s², then the scale reading will be E) 910 N.
To find the scale reading in the given situation, we'll use Newton's second law of motion, which states that force (F) equals mass (m) times acceleration (a). In this case, the man experiences two accelerations: gravity (g = 9.81 m/s²) and the elevator's acceleration (a = 3.0 m/s²). The total acceleration is the sum of both accelerations.
Total acceleration = g + a = 9.81 m/s² + 3.0 m/s² = 12.81 m/s²
Now, we can find the force (weight) that the scale reads:
F = m * total acceleration = 71 kg * 12.81 m/s² ≈ 910 N
So, the scale reads approximately 910 N, which corresponds to option E.
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What is the acceleration of the car between 2 and 5 seconds? hint: acceleration is a change in speed and direction! 15 m/s2 15 m/s 2 0 m/s2 0 m/s 2 5 m/s2 5 m/s 2 30 m/s2
The acceleration of the car between 2 and 5 seconds is 0m/\(s^{2}\).
How can the velocity time graph be used to determine the acceleration?
Calculating acceleration involves dividing the change in velocity, expressed in meters per second, by the time required for the change, expressed in seconds. The acceleration is measured in m/\(s^{2}\).
As we are aware, velocity = distance / time.
And acceleration = velocity / time.
The linear graph shows that the distance travelled at the time interval of 2 seconds is 10 m. Hence the velocity(\(v_{1}\)) =10/2 = 5m/s.
The graph shows that the distance travelled is 25 m at time interval of 5 seconds. Hence the velocity (\(v_{2}\)) =25/5 = 5m/s.
Acceleration between 2 and 5 seconds is now calculated as
(\(v_{1}\)-\(v_{2}\)) / (\(t_{2}\)-\(t_{1}\)) = (5-5)/(5-2) = 0 m/\(s^{2}\)
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How much force is exerted on the object with a mass of 50kg and an acceleration
of 10m/s2 G:____________ S:____________ R:____________ A:____________ E:____________
Answer:
F = 500 N
Explanation:
Given that,
Mass of an object, m = 50 kg
Acceleration of the object, a = 10 m/s²
We need to find the force exerted on the object. The force exerted on it will be given by :
F = ma
Substitute all the values, we get :
F = 50 kg × 10 m/s²
F = 500 N
So, the magnitude of the force exerted on the object is 500 N.
A force of 3kN acts on a car to make it accelerate by 1.5m/s/s. What is the mass of the car?
Answer:
2
Explanation:
To find force it's force = mass times acceleration so to find mass you would divide force by acceleration
What is the speed of a 3.75kg golden eagle after it has fallen freely from the rest through a distance of 15m
Answer:
v = 17.14 m/s
Explanation:
Given that,
Mass of eagle is 3.75 kg
We need to find the speed of Eagle after it has fallen freely from the rest through a distance of 15m. We can use third equation of motion :
\(v^2-u^2=2as\)
u = 0 (at rest) a= g
\(v^2=2gs\\\\v=\sqrt{2gs} \\\\v=\sqrt{2\times 9.8\times 15} \\\\v=17.14\ m/s\)
so, the speed of the eagle is 17.14 m/s.
A cup of coffee with cooling constant k = -0.09 is placed in a room temperature of 18°C. If the coffee is served at 93 °C, how long will it take to reach a drinking temperature of 73 °C?
The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.
The cooling law is given by:
$$\frac{dQ}{dt}=-k(T-T_0)$$
where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.
We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.
Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.
Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:
dQ = - dQ where dQ is the heat energy gained by the environment.
We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.
We can rearrange the equation as follows:
$$-\frac{dQ}{dt}=k(T-T_0)$$
$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$
$$\frac{d}{dt}T=-k(T-T_0)$$
The differential equation above can be solved using separation of variables as follows:
$$\frac{d}{dt}\ln(T-T_0)=-k$$
$$\ln(T-T_0)=-kt+c_1$$
$$T-T_0=e^{-kt+c_1}$$
$$T=T_0+Ce^{-kt}$$
where C = e^(c1).
We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.
$$T=T_0+Ce^{-kt}$$
$$73=18+C\cdot e^{-0.09t}$$
$$55=C\cdot e^{-0.09t}$$
$$C=55e^{0.09t}$$
$$T=18+55e^{0.09t}$$
We can now solve for the value of t when T=93 as follows:
$$93=18+55e^{0.09t}$$
$$e^{0.09t}=\frac{93-18}{55}$$
$$e^{0.09t}=1.3636$$
$$t=\frac{\ln(1.3636)}{0.09}$$
Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.
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A compressor for a jackhammer expands the air in the hammer’s cylinder at a constant pressure of 8. 6 x 10^5 Pa. The increase in the cylinder’s volume is 4. 0^5 x 10^-4 m^3. During the process, 9. 5 J of energy is transferred out of the cylinder as heat.
A. What is the work done by the air
B. What is the change in the air’s internal energy
C. What type of ideal thermodynamic process does this approximate
The work done by the air is 88.06kJ, the change in the air’s internal energy is 357.8J and the type of ideal thermodynamic process is isobaric process.
Given the constant pressure of cylinder (P) = 8.6 x 10^5Pa.
The increase in the cylinder’s volume is (V) = 4.0^5 x 10^-4 m^3.
The energy transferred out of the cylinder as heat (Q) = 9.5J
(a) We know that work done (W) = -PexternalΔV
W = -8.6 x 10^5 x 4.0^5 x 10^-4 = -88.06kJ
Hence the work done is 88.06kJ.
(b) From first law of thermodynamics we know that change in internal energy is equal to heat released - work done.
ΔU = Q - W where W is work and U is internal energy.
ΔU = -9.5 - 348.3 = -357.8J
(c) The type of ideal thermodynamic process this approximates is isobaric process. Under constant pressure, the isobaric process is a thermodynamic process. Even though the pressure is constant in this operation, the temperature, volume, and internal energy are not.
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Which of the following types of forces is NOT an active force.
A. Tensional Force
B. Applied Force
C. Gravitational Force
D. Friction Force
Answer: A.
Explanation: Because it is like when you rub your knees on a rug it is tensional so that would make it a not active force.
Imagine you are walking along a forest path. Which of the following is not an action-reaction pair in this situation?
A. You push down on Earth; Earth pushes you forward
B. Your foot pushes back on the inside of your shoe; your shoe pushes forward on your foot.
C. Your shoe pushes back on Earth; Earth pushes forward on your shoe.
D. The gravitational force between you and Earth; the gravitational force between Earth and you.
Answer:
C
Explanation:
you are walking on the earth
explain about ohm's law.
Answer:
Statement:
The electric current passing through a conductor is directly proportional to the potential difference across its ends provided temperature and other physical conditions remain constant.
Explanation:
Current is directly proportional to voltage loss through a resistor. That is, if the current doubles, then so does the voltage. To make a current flow through a resistance there must be a voltage across that resistance. Ohm's Law shows the relationship between the voltage (V), current (I) and resistance (R).
V∝I or I∝V⇒V=IR.
Explanation:
Ohm's law states that the current through a conductor is proportional to the voltage across the conductor. This is true for many materials (including metals) provided the temperature (and other physical factors) remain constant. The constant of proportionality, R,R is the resistance and the unit is the ohm, with symbol \Omega,Ω. The relationship can be written as:
V, equals, I, R.
V=IR
where V,V is the voltage across the conductor and I,I is the current flowing through it. If a component is ohmic (it obeys Ohm's Law), then its resistance must be independent of current and voltage.
a physical pendulum consists of a meter stick that is pivoted at a small hole drilled through the stick a distance d from the 50 cm mark. the period of oscillation is 2.5 s. find d.
The physical pendulum consists of a meter stick that is pivoted at a small hole drilled through the stick a distance 0.056mfrom the 50 cm mark
The period of a physical pendulum is given by T = 2π √(L/g), where L is the length of the pendulum and g is the acceleration due to gravity. We can use this formula to find the distance d.
To find d, we use the formula:
T = 2π √(L/g)
Where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.
We know that T = 2.5 s, g = 9.8 \(m/s^2\) and L is the distance from the pivot point to the center of gravity of the pendulum which is the 50 cm mark on the meter stick, so L = 0.5m.
We can rearrange the formula to solve for d :
d = L * √(\(T^2/4$\pi^2\) -1/g)
With the given values we can substitute in the formula
d = 0.5* √(\(2.5^2/4$\pi^2\) -1/9.8)
d = 0.056m
Therefore, The distance d from the 50cm mark is approximately 0.056m.
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please help!!!!!!!!!!!!!!!!!!!!!!
Answer: I'm sure the answer is a.
Explanation: I hope that helped you.
Answer:
Precipitate
Explanation:
A boy runs on a circular path of radius R = 28 m with a constant speed u = 4 m/s. Another boy starts from the centre of the path to catch the first boy. The second boy always remains on the radius connecting the centre of the circle and the first boy and maintains magnitude of his velocity constant V = 4 m/s. If the time of chase is (10 + x) sec then
Answer:
We can solve this problem by using the concept of relative motion. Let's assume that the first boy is running in the clockwise direction and the second boy is chasing him in the counterclockwise direction.
Since the second boy always remains on the radius connecting the center of the circle and the first boy, the distance between them is always equal to the radius of the circle, which is 28 m.
Let's denote the distance covered by the first boy as S1 and the distance covered by the second boy as S2. We know that the first boy is running with a constant speed of 4 m/s, so we can write:
S1 = u*t1
where t1 is the time taken by the first boy to complete the chase.
The second boy is moving with a constant velocity of 4 m/s towards the first boy, so we can write:
S2 = V*t2
where t2 is the time taken by the second boy to catch up with the first boy.
Since the second boy is always moving on the radius connecting the center of the circle and the first boy, the distance covered by him is equal to the distance on the circumference of the circle covered by the first boy, minus the distance covered by the first boy along the radius. We can write:
S2 = S1 - 2*pi*R
where pi is the mathematical constant pi (approximately equal to 3.14).
Substituting the values of S1 and S2, we get:
u*t1 = V*t2 + 2*pi*R
Since the time of chase is (10 + x) sec, we can also write:
t1 + t2 = 10 + x
We have two equations and two unknowns (t1 and t2), so we can solve for them. First, we can solve for t2:
t2 = (u*t1 - 2*pi*R) / V
Substituting this in the second equation, we get:
t1 + (u*t1 - 2*pi*R) / V = 10 + x
Simplifying this equation, we get:
t1*(1 + u/V) = 10 + x + 2*pi*R/V
Finally, we can solve for t1:
t1 = (10 + x + 2*pi*R/V) / (1 + u/V)
Substituting the given values of R, u, and V, we get:
t1 = (10 + x + 56*pi) / 20
Simplifying this expression, we get:
t1 = 2.8*pi + 0.5*x + 2.8
Therefore, the time taken by the first boy to complete the chase is 2.8*pi + 0.5*x + 2.8 seconds.
Explanation:
this gives me nightmare
Can you hear sounds from space or not? Why or Why not?
What is the mass amount of a Proton and a Neutron?
The masses amount of a proton and neutron are 1.0087 and 1.0073 amu respectively.
What is a Proton?This is defined as sub atomic particle which is positively charged and is present in the nucleus while the neutron is also a particle present in the nucleus but has a neutral charge.
Electrons on the other hand are found outside the nucleus and are negatively charged. It is the sub atomic particle which is actively involved in a chemical reaction.
The masses of neutron and proton are 1.0087 and 1.0073 amu respectively and was discovered by scientists thereby making it the most appropriate choice.
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Suppose the Sun is 1.29025 X 108 km from
Earth.
The speed of light is 2.99792 x 108 m/s.
How long does it take for its light to reach
us?
Answer in units of min.
Answer:
It takes the Sun's light 7.17 minutes to reach us.
Explanation:
We can calculate the time that takes the light to reach us by using the following equation:
\( t = \frac{d}{c} \)
Where:
d: is the distance = 1.29025x10⁸ km = 1.29025x10¹¹ m
c: si the speed of light = 2.99792x10⁸ m/s
Hence, the time is:
\( t = \frac{d}{c} = \frac{1.29025 \cdot 10^{11} m}{2.99792 \cdot 10^{8} m/s} = 430.38 s = 7.17 min \)
Therefore, it takes the Sun's light 7.17 minutes to reach us.
I hope it helps you!
explain the difference between mass and weight and how these concepts relate to gravity
Answer:
Your mass is the same no matter where you go in the universe; your weight, on the other hand, changes from place to place. Mass is measured in kilograms; even though we usually talk about weight in kilograms, strictly speaking it should be measured in newtons, the units of force
In summary, mass is a measure of how much matter an object contains, and weight is a measure of the force of gravity acting on the object. ... The amount of gravity is directly proportional to the amount of mass of the objects and inversely proportional to the square of the distance between the objects.
Explanation:
a block weighing (Fg) 50 N is resting on a steel table (us = 0.74). The minimum force to start this block moving is what N
Answer:37
Explanation:
8. True or False. Energy can move in waves.
Answer:
true
Explanation:
How are cactus adapted to survive in deserts?
1. They have evolved their leaves into spikes for minimum water loss through transpiration.
2. They have a waxy layer for minimum water loss.
3. They have thick walls for minimum water loss.
4. They can take water from atmosphere.
5. They change the photo energy from Sun into an intermediate stage and store it, so that they can make food even in night.
What distance is moved if we have a 8N force and the work done is 90J
Answer the following questions about Nikola Tesla.
What do you think about the inventions of this man?
How have this man's inventions have changed our lives?
How have this man's inventions changed our technologies?
Why did society ostracize this man's work?
Nikola Tesla is best known for his contributions to the design of the modern alternating current (AC) electricity supply system. Tesla's inventions have had a profound impact on our lives.
His work on AC electricity led to the development of the modern power grid, which provides us with electricity for our homes, businesses, and industries.
His work on AC electricity led to the development of electric motors, which are used in a wide variety of devices, including fans, refrigerators, and electric vehicles. In the early days of his career, he was often ridiculed by his peers for his unconventional ideas.
Nikola Tesla was a Serbian-American inventor, electrical engineer, mechanical engineer, futurist, and polymath.
He invented the Tesla coil, a high-voltage, high-frequency alternating current generator that is used in a variety of applications, including radio broadcasting, medical therapy, and industrial applications.
Tesla's inventions have changed our technologies. He also invented the fluorescent lamp, which is now used in homes and businesses all over the world.
Tesla's work was not always appreciated by society. He was also seen as a threat by the Edison Electric Company, which was the dominant player in the early electrical industry. As a result, Tesla's work was often overlooked or stolen by others.
Despite the challenges he faced, Tesla persevered and made significant contributions to the field of electrical engineering. His work has had a profound impact on our lives and has helped to shape the modern world.
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Nikola Tesla's inventions are groundbreaking and remarkable. He was an extraordinary inventor who contributed significantly to the fields of electricity, electromagnetism, and wireless communication. His inventions, such as the alternating current (AC) system, the Tesla coil, and wireless power transmission revolutionized the world of technology and laid the foundation for many modern advancements.
Nikola Tesla's inventions had a profound impact on our lives. The adoption of Tesla's AC power system, for instance, allowed for the efficient transmission and distribution of electricity over long distances. This innovation brought electricity into our homes, powering lighting, appliances, and various devices. Tesla's inventions greatly improved the quality of life, providing convenient and reliable access to electrical energy.
Furthermore, Tesla's work on wireless communication and the development of the Tesla coil paved the way for advancements in wireless technology. His concepts and inventions laid the foundation for radio transmission, wireless telegraphy, and eventually, the development of modern wireless communication systems. Today, we rely heavily on wireless technologies such as smartphones, Wi-Fi networks, and Bluetooth connections, all of which can be traced back to Tesla's contributions.
However, despite his remarkable inventions and contributions, Nikola Tesla faced certain challenges and societal ostracization during his time. One of the primary reasons was his rivalry with Thomas Edison, who championed the competing direct current (DC) system. Edison's influence and propaganda campaigns led to the portrayal of Tesla's AC system as dangerous, which hindered the widespread adoption of his inventions. Additionally, Tesla's ambitious projects, such as the Wardenclyffe Tower for wireless power transmission, faced financial difficulties, leading to setbacks and the perception of him as an eccentric figure.
Therefore, Nikola Tesla's inventions have had a profound impact on our lives and technologies. From the adoption of AC power to the development of wireless communication, Tesla's innovations have shaped the modern world. While his work was not always appreciated during his time, the significance of his contributions cannot be overstated.
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The table provided shows data collected during an experiment .
Which of the following claims is supported by the data?
A. Gravitational force are proportional to the masses of the two objects.
B. Gravitational forces are strongest between objects with identical masses.
C. Gravitational forces are weakest when one object is more massive than the other.
Answer:
Explanation: the table shows during an experiment
Gravitational forces are strongest between objects with identical masses, claims are supported by the data. Option B is correct.
What is Newton's law of gravitation?Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.
When mass increases and distance reduces, gravity rises. Gravity also lowers when the distance between two points grows and the mass decreases.
From the table, it is observed that gravitational forces are strongest between objects with identical masses, claims are supported by the data.
Hence, option B is correct.
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3. Identify which of the following probably would not have an effect on the climate of a region:
a. the region is next to a mountain range
b. the region is on the equator
c. a thunderstorm just blew through the region
d. the region is next to the Atlantic Ocean
please answer this question
Answer:
11.a) Car B is faster than Car A. This is because Car B covers more distance in less time, whereas Car A covers less distance in more time. Now, as we know that distance is directly proportional and time is inversely proportional to speed. In Car B, a larger distance and less time and a smaller distance and more time in Car A, indicates that the speed of Car B is more than the speed of Car A.
b) Car B accelerates faster than Car A. We know that, the acceleration is directly proportional to the change in linear velocity and inversely proportional to time taken. Here, The overall journey of Car B is short, whereas for Car A, it's longer. Also, as previously mentioned that the final speeds of Car B is more than Car A [remembering that both Cars start from the origin(rest)]. Hence, the change of velocity in Car B is more than Car A. Hence so.
The figure below shows two crates gliding across a surface without any frictional interaction. Because the smaller crate is moving faster than the larger crate, at some time in the future, the smaller crate will collide with the larger one.
Take into account that the total momentum of the system is equal before and after the smaller crate collides with the larger crater.
Moreover, consider that after the collision, both craters move together.
Then, you have:
momentum before = m*2vi + 3m*vi = 5m*vi
momentum after = (m + 3m)v = 4m*v
If you equal the previous expressions:
4m*v = 5m*vi
By solving for v:
v = (5m*vi)/(4m)
v = 5vi/4
Hence, the speed of the two craters after the collision is 5/4 * vi
What happens to gravitational potential energy as a rollercoaster moves down a hill? Question 4 options: It is converted to elastic potential energy It increases It is converted to kinetic energy It remains constant.
The gravitational potential energy as a rollercoaster converts to kinetic energy when it moves downhill.
What is kinetic energy?
The kinetic energy of an object or body is due to its motion. When the roller coaster moves downhill it accelerates, thus the gravitational potential energy as a rollercoaster converts to kinetic energy.
The gravitational potential energy of an object or body is due to its position above the ground.
Therefore, the gravitational potential energy as a rollercoaster converts to kinetic energy when it moves downhill.
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please correct the wrong
answer. and underline the answer thank you
1. One mole of an ideal gas expands isothermally at T = 20°C from 0.8 m³ to 2.1 m³. The gas constant is given by R= 8.314 J/(mol K). (a) Calculate the work done by the gas during the isothermal exp
The work done by the gas during the isothermal expansion is approximately -4125.40 J. The calculation involves considering the gas constant, temperature, and initial and final volumes.
To calculate the work done by the gas during an isothermal expansion, we can use the formula:
W = -nRT ln(Vf/Vi)
Where:
W is the work done
n is the number of moles of the gas
R is the gas constant (8.314 J/(mol K))
T is the temperature in Kelvin
Vf is the final volume
Vi is the initial volume
Given:
n = 1 mole
R = 8.314 J/(mol K)
T = 20°C
= 293.15 K
Vi = 0.8 m³
Vf = 2.1 m³
Substituting the values into the formula:
W = -1 * 8.314 J/(mol K) * 293.15 K * ln(2.1 m³ / 0.8 m³)
≈ -4125.40 J
Therefore, the work done by the gas during the isothermal expansion is approximately -4125.40 J. The negative sign indicates work done on the gas.
By using the formula for work done during an isothermal expansion and substituting the given values, we calculated that the work done by the gas is approximately -4125.40 J. The negative sign indicates that work is done on the gas during the expansion. The calculation involves considering the gas constant, temperature, and initial and final volumes.
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Hello, I needed help with the question boxes on what to fill in.
Given:
To find:
Fill in the blanks
Explanation:
1) Energy can undergo conversion, changing from one form to another. For example, a wind turbine converts the mechanical energy of the wind into electric energy in the power grid. This power grid can then be converted into thermal energy by an electric heater.
2) Solar panels generate electrical energy by taking radiant energy from the sun and having it undergo conversion. This process does obey the law of conservation of energy because energy isn't randomly created, but it is simply converted.
if a test charge of magnitude twice as large as the original test charge were placed at point a, how would the force it feels compare to the force felt by the original test charge when it was placed at point a?
The force felt by the larger test charge would be twice as large as the force felt by the original test charge.
This is because the force felt by a test charge in an electric field is directly proportional to the magnitude of the test charge. The electric field is a vector field and the force experienced by a test charge is given by the product of the charge of the test particle and the electric field at that point.
So, when the magnitude of the test charge is doubled, the force experienced is also doubled. Therefore, if a test charge of magnitude twice as large as the original test charge were placed at point a, it would feel twice the force that the original test charge felt when it was placed at that same point.
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If a species experiences a helpful mutation, like camouflage, explain how that mutation would help the species to better I survive and flourish. Again, be sure to explain how and why that mutation would be helpful.
HELP I NEED IT FAST PLEASE ILL MARK B!!!! IF CORRECT