8.3 kg, 1.7 Kg/cm3
-> ? cm3

Answer:

C

Explanation:

running the balloon against your hair

Answer:

The purpose of this lab is to determine the identity of an unknown liquid by measuring its density, melting point, boiling point, and solubility in both water and alcohol, and then comparing the results to the values for the known substance. Hope this helps!! :)

Answer:

62.5 moles of O₂.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2C₈H₁₈ + 25O₂ —> 16CO₂ + 18H₂O

From the balanced equation above,

2 moles of C₈H₁₈ reacted with 25 moles of O₂.

Finally, we shall determine the number of mole of O₂ needed to react with 5 moles of C₈H₁₈. This can be obtained as shown below:

From the balanced equation above,

2 moles of C₈H₁₈ reacted with 25 moles of O₂.

Therefore, 5 moles of C₈H₁₈ will react with = (5 × 25) / 2 = 62.5 moles of O₂.

Thus, 62.5 moles of O₂ is needed for the reaction.

Lattice enthalpy of dissociation of Na₂O is +3739 kJ/mol.

Na₂O dissociates into two Na+ and one O2- ions. Using the Born-Haber cycle and Hess's law, we can calculate the lattice enthalpy of dissociation as the sum of the following steps: Na solid → Na(g) + 108 kJ/mol, 1/2 O2(g) → O(g) + 1st EA = +108 kJ/mol, Na(g) → Na+(g) + e- + 496 kJ/mol, O(g) + e- → O-(g) + 2nd EA = +649 kJ/mol, Na+(g) + O2-(g) → Na2O(s) + Lattice Enthalpy. Solving for Lattice Enthalpy gives +3739 kJ/mol.

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Answer:

The chemical equilibrium of the system will be unaffected. The chemical equilibrium of the system will shift to the right to favor the forward reaction. The chemical equilibrium of the system will shift to the left to favor the reverse reaction. (I hope this helped!!)

The given phrase describes "Electrically conductive functionalized GNP/epoxy based composites" and their transition from a "nanocomposite" to a "multiscale glass fibre composite material." This suggests a progression in the composition and structure of the composites, potentially involving the incorporation of glass fibers at a larger scale.

The phrase highlights the use of electrically conductive functionalized graphene nanoplatelets (GNP) in combination with epoxy to create composite materials. The functionalized GNP enhances the electrical conductivity of the composites.

The transition from a nanocomposite to a multiscale glass fiber composite material suggests a shift in the reinforcement mechanism, where additional glass fibers are incorporated to improve the mechanical properties at a larger scale.

The concept described in the given phrase focuses on the development of electrically conductive composites by incorporating functionalized GNP and epoxy.

This development encompasses a progression from nanocomposites to multiscale glass fiber composites, indicating a shift towards larger-scale reinforcement.

The use of such composites holds potential for applications requiring both electrical conductivity and mechanical strength, providing versatility in material design for various industries, including aerospace, automotive, and electronics. It is essential to conduct further research and experimentation to explore the performance and properties of these composite materials in different applications.

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C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

mole C₃H₈ = 68.5 : Mr C₃H₈ = 68.5 : 44 g/mol = 1.557

mole O₂ = 83.4 : Mr O₂ = 83.4 : 32 g/mol = 2.606

to find limiting reactants :

divide the number of moles by their respective coefficients, and the small quotient will be a limiting reactants

C₃H₈ : O₂ = 1.557/1 : 2.606/5 = 1.557 : 0.521

O₂ as a limiting reactant, C₃H₈ excess reactants

reacted mole of C₃H₈ : 1/5 x 2.606 = 0.5212

unreacted mole of C₃H₈ : 1.557 - 0.5212 = 1.0358

mass of C₃H₈ (unreacted) = 1.0358 x 44/gmol = 45.575 g

Answer: 4848.22 mL

Explanation:

V2= P1V1T2/(T1 P2)  = (400.00 X 12.0 X 300.15)/(270.15 x 1.10)

Answer:

A physical property is a characteristic of a substance that can be observed or measured without changing the identity of the substance. ... A chemical property describes the ability of a substance to undergo a specific chemical change.

Explanation:

The total interaction energy in units of eV/atom assuming λ = 4156 eV and R_0/rho = 12 is 150N eV/atom.

Given Potential for two inert gas (Xe) atoms at separation R :

U=λe^(-R/rho)-R^6/a^6

a) To calculate the potential energy of the two atoms at equilibrium separation R_0,

we have to put dU/dR = 0λ e^(-R_0/rho) = (6R_0^6)/(a^6)λ e^(-R_0/rho) = (6(12rho)^6)/(a^6)

Therefore, λ = (6(12rho)^6)/(a^6) * e^(12)

The potential energy can be expressed as, U=λe^(-R_0/rho) = ((6(12rho)^6)/(a^6)) * e^(12) * e^(-12rho/rho)= ((6*12^6)/a^6) * e^(-11rho)

b) Given R_0 = 12rho, λ = (6(12rho)^6)/(a^6) * e^(12)

Therefore, λ = (6(12rho)^6)/(a^6) * e^(12) = (6 * 12^6)/(a^6) * e^(12) * e^(-12) = (6 * 12^6)/(a^6)

Potential energy U = λe^(-R_0/rho) = (6 * 12^6)/(a^6) * e^(-11rho)c)

The total interaction energy in units of eV/ atom assuming λ = 4156 eV and R_0/rho = 12

Therefore, λ = (6(12rho)^6)/(a^6) * e^(12) = (6 * 12^6)/(a^6) * e^(12) * e^(-12) = (6 * 12^6)/(a^6)

Total energy (U) = (N/2)U = (N/2)λe^(-R_0/rho) = (N/2)(6 * 12^6)/(a^6) * e^(-11rho) = 150N eV/atom.

Therefore, the total interaction energy in units of eV/atom assuming λ = 4156 eV and R_0/rho = 12 is 150N eV/atom.

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Answer:

Iodine

Explanation:

Helium, Radon, and Krypton are all in group 18 but Iodine is not

(it's in group 17)

:)

Answer:

The deuterium-tritium (DT, Figure 2) reaction is the most useful for fusion energy because it most easily overcomes the Coulomb repulsion, and it has the highest energy release among laboratory-feasible reactions.

Explanation:

When a deuterium nucleus (2H) and a tritium nucleus (3H) combine, the result is a helium nucleus and a very energetic neutron. Under the right circumstances, the energy released is sufficient to induce further fusion reactions.

The formula of water is H2O

Explanation:

The water molecule consists of two hydrogen atoms and one oxygen atom. So the chemical molecula formula of water is H2O where H is the symbol of hydrogen and O is the symbol of oxygen and 2 indicates that there are two atoms of hydrogen.

Hope this helps you!

There are several methods for producing nitric acid from nitrogen, but two common methods are:

1. Ostwald process:

4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g)

2 NO(g) + O2(g) → 2 NO2(g)

3 NO2(g) + H2O(l) → HNO3(aq) + HNO2(aq)

Overall equation:

4 NH3(g) + 3 O2(g) + H2O(l) → 2 HNO3(aq) + 2 NO(g)

2. Birkeland-Eyde process:

N2(g) + 3 H2(g) → 2 NH3(g)

2 NH3(g) + 3 O2(g) → 2 NO(g) + 3 H2O(g)

2 NO(g) + O2(g) → 2 NO2(g)

3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g)

Overall equation:

N2(g) + 3 O2(g) + 3 H2(g) → 2 HNO3(aq)

Answer:

H+ contains 1 proton, 0 neutrons, 0 electrons.

Explanation:

Answer:

Francium is the answer

The correct option is 4, Cu + 2Ag+ ==> Cu2+ + 2Ag this equation shows conservation of mass and charge.

The conservation of mass, also known as the law of conservation of mass, is a fundamental principle in physics and chemistry that states that the total mass of a closed system remains constant over time. This means that mass cannot be created or destroyed, only transformed or transferred from one form to another.

The principle of conservation of mass is based on the assumption that no particles are lost or gained from the system. This is known as a closed system, and it can be applied to many different systems, such as chemical reactions, physical processes, and even ecological systems. This principle is based on the law of the conservation of energy, which states that energy cannot be created or destroyed, only transformed from one form to another.

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Answer: I'm not sure but I thinks its  C

Explanation:

Concentration of lead in drinking water in molarity is:\(6.8 * 10^(-8) M\)

To convert the concentration of lead in drinking water from parts per billion (ppb) to molarity, we need to use the molar mass of lead and the density of water. The molar mass of lead is 207.2 g/mol, and the density of water is approximately 1 g/mL.

First, we need to convert the concentration from ppb to mg/L (milligrams per liter), since molarity is calculated in moles per liter. To do this, we can use the following conversion factor:

1 ppb = 1 µg/L = 0.001 mg/L

Therefore, the concentration of lead in drinking water in mg/L is:

14 ppb x 0.001 mg/L = 0.014 mg/L

Next, we can use the molar mass of lead to calculate the number of moles of lead per liter of water:

0.014 mg/L ÷ 207.2 g/mol = \(6.8 * 10^(-8) mol/L\)

Therefore, the concentration of lead in drinking water in molarity is:

\(6.8 * 10^(-8) M\)

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Answer:

The loss of crystalline structure of sucrose was reported at various temperatures, but decomposition, after >50 h of holding at 120 °C in a sealed pan.

Explanation:

As this condition is above the melting temperature of fructose (a possible first decomposition product), and there were water and impurities.

When the reaction is subjected to pressure, the equilibrium will shift to the side with fewer gas molecules, which is the left side. Therefore, the answer is c. left.

According to Le Chatelier's principle, when a system at equilibrium is subjected to a change in pressure, it will respond by shifting in a way that reduces the effect of the change. In this case, increasing the pressure would cause the equilibrium to shift towards the side with fewer gas molecules to alleviate the increase in pressure.

Since there are fewer gas molecules on the left side of the reaction (2 CO + O2), the equilibrium will shift to the left to reduce the total number of gas molecules. This means that the concentrations of CO and O2 will increase, while the concentration of CO2 will decrease until a new equilibrium is established. Thus, the equilibrium will shift to the left.

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The amount of carbon dioxide produced from the combustion of a candle formula depends on the specific formula and the mass of the candle. However, on average, the combustion of one gram of wax in a candle produces approximately 3 grams of carbon dioxide.

Most candles are made of paraffin wax, which is a hydrocarbon with the general formula CnH2n+2. Let's assume that we are dealing with a simple hydrocarbon, such as C25H52 (a common component of paraffin wax).

During combustion, the hydrocarbon reacts with oxygen (O2) to produce carbon dioxide (CO2) and water (H2O). The balanced chemical equation for the combustion of C25H52 is:

C25H52 + 38O2 → 25CO2 + 26H2O

To find the grams of CO2 produced, we need to know the mass of C25H52 that is combusted. For example, let's say we have 1 mole of C25H52 (molecular weight = 25*12.01 + 52*1.01 = 352.76 g/mol).

From the balanced equation, 1 mole of C25H52 produces 25 moles of CO2. The molecular weight of CO2 is 12.01 (C) + 2*16.00 (O) = 44.01 g/mol. So, the mass of CO2 produced from 1 mole of C25H52 is:

25 moles CO2 * 44.01 g/mol = 1100.25 grams of CO2

So, in this example, the combustion of 1 mole (352.76 grams) of C25H52 from a candle produces 1100.25 grams of carbon dioxide.

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Explanation

To find the molar mass of sulfur dihydride, you will need to find the sum of all the atomic masses making up sulfur dihydride.

sulfur dihydride is H2S.

Atomic mass of H = 1,00784 u

Atomic mass of S = 32,065 u

Molar mass = (1.00784 x 2) + 32,065 = 34.081 g/mol

Answer

34.081 g/mol

Answer:

Explanation:

\(\mathrm {Hey, there!}\)

Let's solve your problem -

The answer to the question is 4.18 10^7.

Here is my clarification/explanation to support:

To convert a standard number to scientific notation, we have to move the decimal point up until we have a 1 digit number.

When we keep moving the decimal point, we get 4.18

Now, we will count the numbers after the 8 to get the 10 area.

There are five numbers after the 8, so we get 10^5.

Now, we will add 2 more to the 5, we get 10^7

Our answer will be: 4.18 10^7

\(\mathrm {Best, of, Luck!}\)

0.2ml is required as 1 : 4 dilution to make 4ml of 1 : 80 dilution.  

Dilution is the addition of solvent, which decreases the concentration of the solute in the solution.

Concentration on the other hand, is the removal of solvent, which increases the concentration of the solute in the solution.

The volume of solution needed to make the solution can be calculated by the formula,

V1 x N1 = V2 x N2

4 ml of 1:80 diluted solution has to be made from 1:4 solution.

Applying these values in the above formula,

V1 x (1/4) = 4 x (1/80)

V1/4 = 1/20

V1 = 4/20

V1 = 0.2 ml

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Answer:

Để trung hoà 50 ml hỗn hợp X gồm HCl và H2SO4 cần dùng 20 ml dung dịch NaOH 0,3M. Cô cạn dung dịch sau khi trung hoà thu được 0,381 gam muối khan. a) Xác định nồng độ mol của các axit trong X. b) Tính pH của dung dịch X.

The pair of reaction will be solvolysis. Both reaction will occur by SN1 mechanism.        

Solvolysis is a chemical reaction in which the solvent, such as water or the alcohol, is one of the reagents and it is present in great excess of that required for the reaction.

For the two reactions, the organic product is the same. Both the reactions will occur by SN1 mechanism since the substrate is a tertiary alkyl halide and the nucleophile is CH3OH as well as the rate of reaction depends on the concentration of the alkyl halide and the independent of the concentration of methanol present.

Therefore, change the volume of the solvent has no effect on the rate of reaction. The two reactions will proceed exactly the same rate since the initial concentration of the alkyl halide is the same for both the reactions.

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Answer: The 3rd one

Explanation: Electronegativity is a measure of how strongly atoms attract bonding electrons to themselves.

I might be wrong

The value of Kb for Bro- at 25°C is 3.57 x 10^-6. To determine the value of Kb for Bro-, we need to use the relationship between Ka and Kb for a conjugate acid-base pair.

The equation for this relationship is: Ka x Kb = Kw

where Kw is the ion product constant of water, which is 1.0 x 10^-14 at 25°C.

In this case, HBrO is the conjugate acid of Bro-, so we can write:

Ka(HBrO) x Kb(Bro-) = Kw

Substituting the given value for Ka(HBrO):

2.8 x 10^-9 x Kb(Bro-) = 1.0 x 10^-14

Solving for Kb(Bro-):

Kb(Bro-) = (1.0 x 10^-14) / (2.8 x 10^-9)

Kb(Bro-) = 3.57 x 10^-6

Therefore, the value of Kb for Bro- at 25°C is 3.57 x 10^-6.

In summary, we used the relationship between Ka and Kb for a conjugate acid-base pair, along with the ion product constant of water, to determine the value of Kb for Bro-.

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