Answer:
7x-42=3x+9
7x-3x=42+9
4x=51
x=51/4
x=12.75
Step-by-step explanation:
Seventy percent of the children went on the excursion. If 27 stayed at school, how many went?
By using the Unitary Method we get the number of children who went on an excursion was 63. Thus, the total number of children at school is 90.
We are given that,
No. of children who stayed at school is 27,
Also, 70% of the children went on an excursion.
Suppose, the total number of children in percentage is 100%
Out of which 70% went on an excursion
Thus, the children who stayed at school is 100% - 70% = 30%
By using the Unitary method, we can find out the number of 70% of children.
If 30% of the children are 27
Then 70% of the children are = 27 × 100
30
= 63
∴ the total no. of children in the school = 27 + 63
= 90
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Complete the area model to describe how to divide 370 by 5.
Enter your answers in the boxes.
Answer: The first box in the model is 60. The box above it is 300. The box above 20 is 70. The answer is 74.
Step-by-step explanation: Self-explanatory.
It is just long text .This is 8 grade . inequalities .I need just equitation .The rest I knew .
So short answer pls. Anybody
Thank you
My recommendation to Carlos and Clarita would be to prepare for 3 cats and 3 dogs. This combination offers the highest profit potential based on the given prices and costs.
How to explain the informationIn order to maximize their profit, Carlos and Clarita should choose the combination of cats and dogs that yields the highest total profit.
In order to make a reasonable recommendation, we can create a profit table based on different values of x and y:
x y Total Profit
0 0 0
1 0 6
0 1 15
1 1 21
2 1 27
1 2 30
2 2 36
3 2 42
2 3 45
3 3 51
From the table, we can see that the highest total profit is achieved when they accommodate 3 cats and 3 dogs. This combination would result in a daily profit of $51.
Therefore, my recommendation to Carlos and Clarita would be to prepare for 3 cats and 3 dogs.
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Which of the scenarios below are considered seller-based discounts? options are in the picture
The scenarios that can be considered a seller-based discount are:
A. The offer by Wire and Cable
B. Carfna's Fine Foods
C. Mouser Electronics offer
E. Carchex Car Maintenance
What is a seller-based discount?A seller-based discount is a discount that is offered by a seller for the early purchase of a product. The goal of the seller in this case is to get cash as he or she is in an immediate need for cash.
The most outstanding example is that of Carchex Car Maintenance where an offer is made by the seller for the early purchase of products.
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-3x - 8 = 10
Usatestprep
Answer:
X = -6
Step-by-step explanation:
Add 8 to both sides
- 3x = 18
divide by -3
x = -6
anwser it pls aaaaaaaassaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
Answer:
Step-by-step explanation:
Volume = Bh
Turn the shape so the trapezoid is on the bottom/base
h=18 for overall shape
B = area of base, trapezoid
B = 1/2 (b₁ + b₂) h
b₁ = 11
b₂ = 25
h = 24 for trapezoid
B = 1/2 (11 + 25)(24)
B = 432
V = Bh
V = (432)(18)
V= 7776 in³
a ball has a diameter of 4 inches what is the volume
Answer:
268.08 cubic inches
Step-by-step explanation:
I'm sorry if this isn't helpful
3.6= − a/0.8 − 1.6 − 0.8 a −1.6
The value of a for the given expression will be -3.31.
What is an expression?The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.
Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.
Given that the expression is 3.6= − a/0.8 − 1.6 − 0.8 a −1.6. The value of a will be calculated as below,
3.6 = − a/0.8 − 1.6 − 0.8 a −1.6
3.6 + 1.6 + 1.6 = -a / 0.8 - 0.8a
6.8 = ( -a - 0.64a ) / 0.8
5.44 = -1.64a
a = -3.31
Therefore, the value of a will be -3.31.
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Find the solutions to y = –8x for x = 2, 4, and 8.
A. (–16, 2), (–32, 4), (–64,8)
B. (16, 2), (32, 4), (64,8)
C. (2, 16), (4, 32), (8, 64)
D. (2, –16), (4, –32), (8, –64)
The solutions to y = –8x for x = 2, 4, and 8 are (2, –16), (4, –32), (8, –64), hence, option D is correct.
We are given the equation y = -8x and asked to find the solutions for x = 2, 4, and 8. To find the solutions, we substitute the given values of x into the given linear equation and solve for y.
For x = 2, we have,
y = -8x
y = -8(2)
y = -16
Therefore, the solution for x = 2 is (2, -16).
For x = 4, we have,
y = -8x
y = -8(4)
y = -32
Therefore, the solution for x = 4 is (4, -32).
For x = 8, we have,
y = -8x
y = -8(8)
y = -64
Therefore, the solution for x = 8 is (8, -64).
Putting these solutions together, we get {(2,-16), (4,-32), (8,-64)}. Hence, the correct answer is option D.
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why have I been blocked?
Complete the table of values
Answer:
x = 0 —> y = 0 —> ( 0 , 0 )
x = 1 —> y = – 2 —> ( 1 , – 2 )
x = 5 —> y = – 10 —> ( 5 , – 10 )
x = -3 —> y = 6 —> ( -3 , 6 )
Step-by-step explanation:
x = 0 —> y = -2x = -2(0)=0
x = 1 —> y= -2x = -2(1) = -2
x = 5 —> y = -2x = -2(5) = -10
x = -3 —> y = -2x = -2(-3) = 6
I hope I helped you^_^
helppp please I need it will give brainliest
you have to write an equation
Answer:
c=100g+50
Step-by-step explanation:
c is the total cost
there is a 50 dollar fee and 100 dollars per guest
so for every guest, the cost is increased by 100
since there are g number of gusts, the price for the guests will be 100g dollars
since there is also a 50 dollar fee, 50 dollars has to be added to the 100g
therefore c=100g+50
how to get the area of the base ?
Answer:
LxWxH
Step-by-step explanation:
Triangles Q R S and X Y Z are shown. Angles Q S R and X Z Y are right angles. Angles Q R S and X Y Z are congruent. The length of Y Z is 9, the length of X Z is 12, and the length of hypotenuse X Y is 15.
Given △QRS ~ △XYZ, what is the value of tan(Q)?
Three-fifths
Three-fourths
Four-fifths
Answer:three-fourths
Step-by-step explanation:
because my dad said it was right
Use wage data (Data is posted on blackboard) to estimate the following model and answer the questions: Wage= Bo+ Bi educ+ B2 exper+B3 gender +B4 race+Bs gender*exper+E Gender=1 for male and gender=0 for female Race=1 for white and race=0 for non-white 1- Interpret all the coefficients. 2- Is there a significant wage difference between white and non-white? at a=0.05 3- Test for global usefulness of the model at a=0.05. 4- Test if the experience is a significant determinant of wage at a=0.10.
A unit increase in gender will result in decrement of -52.73 in wage provided holding all other parameter constant.
What is parameter?
A parameter is a piece of information that an equation passes on. In terms of statistics, it means something different. In contrast to statistics, which only provide information about a small portion of the population, this value provides information about the entire population.
A parameter is constant because it was determined by surveying everyone (or everything). The average age of the students in your class, for instance, might be of interest to you. Maybe after asking everyone, you discovered that the average age was 25. Given that you polled the entire class, that qualifies as a parameter. Let's say you were curious about the median age of your grade or year.
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2. Suppose that you are looking for a student at your college who lives within five miles of you. You know that 55% of the 25,000 students do live within five miles of you. You randomly contact students from the college until one says he or she lives within five miles of you.
(a) What is the probability that you need to contact four people?
(b) How many students from the college you expect to contact until you find one lives within five miles of you?
(C) What is the standard deviation of the number of students to be contacted until one says who lives within five miles of you?
(d) Suppose you randomly ask 5 students at your college, what is the probability that 3 of them live within five miles of you?
(e) Suppose you randomly ask 5 students at your college, what is the expected number of students who live within five miles of you?
Using the binomial distribution, it is found that:
a) There is a 0.0501 = 5.01% probability that you need to contact four people.
b) You expect to contact 1.82 students until you find one who lives within five miles of you.
c) The standard deviation is of 1.22 students.
d) 0.3369 = 33.69% probability that 3 of them live within five miles of you.
e) It is expected that 2.75 students live within five miles of you.
For each student, there are only two possible outcomes. Either they live within 5 miles of you, or they do not. The probability of a student living within 5 miles of you is independent of any other student, which means that the binomial distribution is used to solve this question.
Binomial probability distribution
\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)
\(C_{n,x} = \frac{n!}{x!(n-x)!}\)
The parameters are:
x is the number of successes. n is the number of trials. p is the probability of a success on a single trial.In this problem:
55% live within five miles, hence \(p = 0.55\).Item a:
This probability is P(X = 0) when n = 3(none of the first three) multiplied by 0.55(the fourth does live within five miles), hence:
\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)
\(P(X = 0) = C_{3,0}.(0.55)^{0}.(0.45)^{3} = 0.091125\)
\(p = 0.091125(0.55) = 0.0501\)
0.0501 = 5.01% probability that you need to contact four people.
Item b:
The expected number of trials in the binomial distribution until q successes is given by:
\(E = \frac{q}{p}\)
In this problem, \(p = 0.55\), and 1 trial, thus \(q = 1\), hence:
\(E = \frac{1}{0.55} = 1.82\)
You expect to contact 1.82 students until you find one who lives within five miles of you.
Item c:
The standard deviation of the number of trials until q successes are found is given by:
\(S = \frac{\sqrt{q(1 - p)}}{p}\)
Hence:
\(S = \frac{\sqrt{0.45}}{0.55} = 1.22\)
The standard deviation is of 1.22 students.
Item d:
This probability is P(X = 3) when n = 5, hence:
\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)
\(P(X = 3) = C_{5,3}.(0.55)^{3}.(0.45)^{2} = 0.3369\)
0.3369 = 33.69% probability that 3 of them live within five miles of you.
Item e:
The expected value of the binomial distribution is:
\(E(X) = np\)
Hence:
\(E(X) = 5(0.55) = 2,75\)
It is expected that 2.75 students live within five miles of you.
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What is the probability that either event will occur? 17 A 29 B 14 P(A or B)
The probability that either event A or B will occur is 43/60
Getting probability value :Using the parameters given
n(A) = 29
n(B) = 14
Total number of events = 29+17+14 = 60
The probability of each event :
P(A) = 29/60
P(B) = 14/60
P(A or B ) = P(A) + P(B)
P(A or B ) = 29/60 + 14/60
P(A or B ) = 43/60
Therefore, the probability of A or B is 43/60
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what is 0.26 rounded to the nearest tenth.
Answer:.3
Step-by-step explanation: if it is 5 or above it rounds up
Find the number of unique permutations of the letters in the word: EXTENT
720
180
900
36
Answer:
180
Step-by-step explanation:
A word has n letters.
There are m repeating letters, each of them repeating \(r_{0}, r_{1}, ..., r_{m}\) times
So the number of distincts ways the letters can be permutated is:
\(N_{A} = \frac{n!}{r_{1}! \times r_{2}! \times ... \times r_{m}}\)
In this question:
Extent has 6 letters.
E and r repeat 2 times. So
\(N = \frac{6!}{2!*2!} = 180\)
So the answer is 180.
Ashley types at a rate of 15 words per minute.
How many words does she type in 5 minutes?
is 141.3 more than 141.05
Answer:
Yes
Step-by-step explanation:
Since the base numbers (141) is the same, we can ignore that.
Now, let's look at .3 and .05.
.3 is the same as .30.
If we remove the decimal point, we're looking at 30 and 5. 30 is greater than 5, so 141.3 is greater than 141.05.
Can someone help me with this pleasee here is the picture
The system of equations as an augmented matrix is \(\left[\begin{array}{ccc|c}1&0&0&100\\0&-5&-7&350\\0&-5&-9&200\end{array}\right]\)
Writing the system of equations as an augmented matrixFrom the question, we have the following parameters that can be used in our computation:
x = 100
-5m - 7c = 350
-5m - 9c = 200
The above means that the variables in the system of equations are
x, m and c
So, we have the following representation
x m c
1 0 0 100
0 -5 -7 350
0 -5 -9 200
When represented as an augmented matrix, we have
\(\left[\begin{array}{ccc|c}1&0&0&100\\0&-5&-7&350\\0&-5&-9&200\end{array}\right]\)
Hence, the augmented matrix is \(\left[\begin{array}{ccc|c}1&0&0&100\\0&-5&-7&350\\0&-5&-9&200\end{array}\right]\)
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Nick prepared 24 kilograms of dough after working 6 hours. How much dough did Nick prepare if he worked for 10 hours? Assume the relationship is directly proportional.
40kg of dough
Step-by-step explanation:
24 kg dough...........................6 hours
? dough.........................10 hours
x=(24*10)/6=240/6=40
Its factorial math pleaseHelp.
\(\dfrac{7!4!}{5!3!}=6\cdot7\cdot4=168\)
In the diagram at right, DE is a midsegment of triangle ABC. If the area of triangle ABC is 96 square units, what is the area of triangle ADE? Explain how you know.
The area of triangle ADE is,
⇒ A = 48 square units
We have to given that,
In the diagram , DE is a midsegment of triangle ABC.
And, The area of triangle ABC is 96 square units
Now, We know that,
Since DE is a midsegment of triangle ABC, it is parallel to AB and half the length of AB. Therefore, DE is half the length of AB.
Hence, the area of triangle ADE is half the area of triangle ABC,
That is,
A = 96 / 2
A = 48 square units
Thus, The area of triangle ADE is,
⇒ A = 48 square units
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Which multiplication fact can help you find 24 divided 4?
A. 4 x 6
B. 24 x 4
C. 6-4
D. 24 x 6
The multiplication fact that can help you find 24 divided by 4 is 4 x 6.
When adding two numbers, the number of significant figures in the sum is equal to the number of significant figures in the least accurate of the numbers being added. Group of answer choices True False
Answer: The given statement is true.
Step-by-step explanation:
Significant figures are defined as the figures that are present in a number. It expresses the magnitude of a quantity to a specific degree of accuracy.
There are some rules to detect the significant figures in a number:
All digits ranging from 1 to 9 are always considered significant.Every non-zero number is always considered significant. For example, 274, 2.74, and 27.4 all have three significant figures.All zero’s that are present between the integers is always considered significant. For example, 5007, 5.007, and 50.07 all have four significant figures.All zero’s preceding the first integer is never considered significant. For example, 0.0089 has two significant figures.All zeros that are present after the decimal point are always significant. For example, 4.800, 48.00, and 480.0 all have four significant figures.Rule applied when numbers are added or subtracted:
The number having less number of significant figures after the decimal point will determine the number of significant figures in the final answer.
Hence, the given statement is true.
What is the interval in which both f (x) and g(x) are positive?
The interval in which both functions are positive is the one in option C.
(3, ∞)
In which interval are the two functions positive?First, when we have a graph, to identify when the function is positive we need to see when the graph of the function is above the horizontal axis.
So here we just need to see in which interval are both curves (orange one and blue one) are above the horizontal axis.
We can see that from x = 3 and above, both of the curves are above the horizontal axis, then the interval in which both functions are positive is:
(3, ∞)
So the correct option is C.
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GIVING OUT BRAINLIST QUICK!
A student researcher compares the ages of cars owned by students and cars owned by faculty at a local state college. A sample of 263 cars owned by students had an average age of 7.25 years. A sample of 291 cars owned by faculty had an average age of 7.12 years. Assume that the population standard deviation for cars owned by students is 3.77 years, while the population standard deviation for cars owned by faculty is 2.99 years. Determine the 90% confidence interval for the difference between the true mean ages for cars owned by students and faculty. Step 1 of 3: Find the point estimate for the true difference between the population means.
Answer:
The point estimate for the true difference between the population means is 0.13.
The 90% confidence interval for the difference between the true mean ages for cars owned by students and faculty is between -0.35 years and 0.61 years.
Step-by-step explanation:
To solve this question, before building the confidence interval, we need to understand the central limit theorem and subtraction between normal variables.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \(\mu\) and standard deviation \(\sigma\), the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \(\mu\) and standard deviation \(s = \frac{\sigma}{\sqrt{n}}\).
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Subtraction between normal variables:
When we subtract two normal variables, the mean is the subtraction of the means while the standard deviation is the square root of the sum of the variances.
A sample of 263 cars owned by students had an average age of 7.25 years. The population standard deviation for cars owned by students is 3.77 years.
This means that:
\(\mu_s = 7.25, \sigma_s = 3.77, n = 263, s_s = \frac{3.77}{\sqrt{263}} = 0.2325\)
A sample of 291 cars owned by faculty had an average age of 7.12 years. The population standard deviation for cars owned by faculty is 2.99 years.
This means that:
\(\mu_f = 7.12, \sigma_f = 2.99, n = 291, s_f = \frac{2.99}{\sqrt{291}} = 0.1753\)
Difference between the true mean ages for cars owned by students and faculty.
Distribution s - f. So
\(\mu = \mu_s - \mu_f = 7.25 - 7.12 = 0.13\)
This is also the point estimate for the true difference between the population means.
\(s = \sqrt{s_s^2+s_f^2} = \sqrt{0.2325^2+0.1753^2} = 0.2912\)
90% confidence interval for the difference:
We have that to find our \(\alpha\) level, that is the subtraction of 1 by the confidence interval divided by 2. So:
\(\alpha = \frac{1 - 0.9}{2} = 0.05\)
Now, we have to find z in the Ztable as such z has a pvalue of \(1 - \alpha\).
That is z with a pvalue of \(1 - 0.05 = 0.95\), so Z = 1.645.
Now, find the margin of error M as such
\(M = zs = 1.645*0.2912 = 0.48\)
The lower end of the interval is the sample mean subtracted by M. So it is 0.13 - 0.48 = -0.35 years
The upper end of the interval is the sample mean added to M. So it is 0.13 + 0.48 = 0.61 years.
The 90% confidence interval for the difference between the true mean ages for cars owned by students and faculty is between -0.35 years and 0.61 years.