7th GRADE SCIENCE QUESTION PLEASE ANSWER AS FAST AS YOU CAN I NEED IT (it can be 1 day late is fine... Ok I'll give you today like this minute and you can answer it when it is posted about 1-2 days but if you can answer it now that will be great)!!!

Question #1: State the role of a nucleus in a cell.

The chemical reactivity of an atom is determined by the number of electrons present in its outermost shell, also known as the valence electrons.

These electrons play a key role in determining the chemical properties of an atom, such as its reactivity and bonding behavior. An atom with a full or nearly full valence shell is less likely to engage in chemical reactions, while an atom with a partially filled valence shell is more reactive and readily participates in chemical reactions. Thus, the number of electrons in the valence shell is a critical factor in determining the chemical reactivity of an atom. Chemical reactivity refers to the ability of a substance to participate in chemical reactions and form new compounds. It is determined by various factors, including the arrangement of electrons in the outermost shell (valence electrons), the stability of the electronic configuration, and the energy required to break or form chemical bonds.

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Thermal noise is the unavoidable noise that occurs due to the thermal motion of particles in electrical circuits.

This type of noise is present everywhere in the universe as it is due to the thermal motion of particles.

This thermal motion is the random movement of particles that is a result of their temperature. At higher temperatures, the particles in a substance have a higher thermal motion, which results in more thermal noise.

The electrical circuit has resistance, and when a current flows through it, the resistance causes collisions between electrons and other atoms. This interaction between the moving electrons and atoms in the conductor produces thermal noise.

Thermal noise is proportional to the temperature of the conductor and is independent of the current or voltage of the signal passing through it. The power of thermal noise is given by the formula P = kTB, where k is Boltzmann's constant, T is the temperature in Kelvin, and B is the bandwidth of the signal.

Hence, it can be deduced that thermal noise is an inevitable occurrence present universally, as it arises from the thermal agitation of particles within electrical circuits. This phenomenon pervades various environments and cannot be eliminated.

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Answer: DC Current

Explanation:

Battery is a source of constant potential difference and it will create a constant voltage across any conductor

due to this constant voltage difference the current in this conductor will remain constant

So here since the voltage across the conductor is constant so we can say that current in the conductor will remain constant and hence this is known as DC current.

While for variable current in direction and magnitude is to be obtained only when the conductor is connected with AC voltage source as we know that AC voltage is variable with magnitude and direction both

A battery is the power source for DC type of current.  A battery is a source of constant potential difference that produces a constant current unlike in AC source where the voltage and hence the current changes its polarity continuously.Hence, the current produced by battery is direct current and not Alternating current.

Hope this helps........ Stay safe and have a Merry Christmas!!!!!! :D

a) Angular frequency is  12.75 rad/s b)  The wave number is 33.59m c)

y ( x ,t) = 2.34  x  sin(33.59 x - 12.75t)

Given,

wavelength = λ = 18.7 cm

                   = 0.187 m

amplitude , A = 2.34 cm

v = 0.38 m/s

A) angular frequency = ?

f = v/λ

f = 0.38/1.87 = 2.03

angular frequency ,

ω = 2π f

ω = 2π x 2.03

ω = 12.75 rad/s

B) the wave number,

K = 2π/λ = 33.59m

c) as the wave is propagating in -x direction, the sign is positive between x and t

y ( x ,t) = A sin(k  x - ω t)

y ( x ,t) = 2.34  x  sin(33.59 x - 12.75t)

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Answer:

The mass of the apple is 0.49kg

Explanation:

Potential energy=mgh

P=mgh

6=m×1.22×10

6=12.2m

divide both sides by 12.2

m=6/12.2

m=0.49kg

In a lab, while performing the experiment, one question that I will ask will be - How potential energy can be converted into thermal energy? The answer for tat will be by seeing and understanding the sample response in the experiment.

Potential energy is released from them when they are divided. A particle's potential energy increases with distance. As they gain speed, their kinetic energy increases. The thermal energy of an object is the sum of the kinetic and potential energies of all the particles.

Energy from heat transfer as potential and kinetic energy

This occurs as a result of the attractive forces they generate for one another. Additionally, the particles are forced apart by a rise in body temperature. As a result, as their potential energy rises, so do the forces of attraction between them.

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The carbon isotope was cobined with the proton to produce the nitrogen isotope hence it is a fusion reaction.

The term nuclear fusion refers to a kind of reaction in which two nuclei fuse together to give rise to a single nuclei with the evolution of energy.

We can see that the carbon isotope was cobined with the proton to produce the nitrogen isotope hence it is a fusion reaction.

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Answer:

A. Nuclear fusion

Explanation:

got it right, trust

a) Using Kepler's third law, the orbital period of planet B located at 1.0 AU from the sun can be calculated. b) Given an orbital period of 4 years for planet C, we can determine its average distance from the sun.

Kepler's third law states that the square of the orbital period (P) of a planet is proportional to the cube of its average distance (a) from the sun. Mathematically, it can be expressed as:

\(\[P^2 = a^3\]\)

Given that planet B is located at an average distance of 1.0 AU from the sun, we can substitute this value into the equation to solve for P:

\(\[P^2 = (1.0 \, \text{AU})^3\]\)

Taking the square root of both sides, we find:

\(\[P = \sqrt{(1.0 \, \text{AU})^3}\]\)

Evaluating the expression, we get:

\(\[P \approx 1.0 \, \text{year}\]\)

Therefore, the orbital period of planet B is approximately 1.0 year.

Similarly, using Kepler's third law, we can solve for the average distance (a) of planet C from the sun. We have the equation:

\(\[P^2 = a^3\]\)

Given an orbital period (P) of 4 years, we can substitute this value into the equation to solve for a:

\(\[(4 \, \text{years})^2 = a^3\]\)

Simplifying, we get:

\(\[16 \, \text{years}^2 = a^3\]\)

Taking the cube root of both sides, we find:

\(\[a = \sqrt[3]{16 \, \text{years}^2}\]\)

Evaluating the expression, we get:

\(\[a \approx 2.52 \, \text{AU}\]\)

Therefore, if planet C has an orbital period of 4 years, its average distance from the sun is approximately 2.52 AU.

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An isolated system is completely isolated from its surroundings and no transfer of energy or mass is possible between the system and surroundings.

The law of conservation of energy or the first law of thermodynamics states that the energy can neither be created nor be destroyed, but it can be transformed from one form to another. In other words, the total energy of an isolated system is always conserved.

For example, when you are driving a car or a motorcycle, the chemical energy that was stored either in the fuel or in the battery is getting converted into mechanical energy. Similarly, when an explosion happens, the chemical energy of the fuel is converted into light energy and heat energy.

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Answer:

Explanation:

It's not equal and opposite. You're thinking of Newton's 3rd Law. This is not that. This is gravitational attraction between 2 objects. We can figure out mathematically the pull that the earth has on a single person, by using the equation for gravitational force and the universal gravitational constant, G:

\(F_g=\frac{Gm_1m_2}{r^2}\) where G is the universal gravitational constant, m1 is the mass of one person, m2 is the mass of the earth, and r-squared is the addition of the radius of the earth plus the radius of you in relation to the surface of the earth.

Let's say a person weighs 150 pounds; in Newtons this is 667 N (rounded from 667.233); his mass then, in terms of the metric system (using 9.8 for gravity), is 68.2 kg. Let's also say that this person is 6 feet tall. 6 feet is the same as 1.83 m (rounded to 3 sig fig's) and the radius from that person's center to the surface of the earth would be about half that height at r = .915 meters. Filling in the formula:

\(F_g=\frac{(6.67*10^{-11})(68.2)(5.98*10^{24})}{(6.38*10^6)^2}\) it turns out that the person's radius adds nothing significantly to the radius of the earth, so it doesn't even count mathematically. It's way too small compared to the earth's radius (which is the denominator of that equation). We find that

\(F_g=668N\) That's the pull that the earth has on that person which, not coincidentally, is the weight in pounds we said that the person was. Isn't physics amazing!?

Answer:

d)Both Bulbs A and C will stay lit

Answer:

The answer should be C. some mass was consumed in the reaction

A powder and a liquid with a total mass of 20 grams are combined in an open beaker, then the best explanation for the difference in mass is that some mass was consumed in the reaction. Hence, option C is correct.

A chemical reaction is the process by which any or more compounds, known as reagents, change into one or more new ones, known as products. Active ingredients or compounds make up substances. The atoms that make up the reactants are reorganized in a chemical reaction to create various products.

Technology, society, and even life itself depend on chemical interactions in one way or the other and. Chemical reactions have been recognized and employed for thousands of years in a wide variety of activities, including burning fuels, smelting iron, creating pottery and pottery, brewing beer, making wine, and manufacturing cheese. There are countless examples of complicated chemical reactions in all living systems, as well as in the Earth's geology, atmosphere, and oceans.

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Answer:

fly apart

Explanation:

gravity holds everything in place by constantly attracting both of the objects

without gravity, the objects would not be attracted anymore. Hence, they fly apart.

Answer:

ω = 2 π f = 2 π / P

The second hand makes 1 revolution every 60 sec (P  = 60 sec)

ω (second hand) = 2 π / 60 sec = .1047 / sec

The second hand makes 60 revolutions for 1 revolution of the minute hand since the minute hand revolves once every hour

ω (minute hand) = 1/60 * .1047 = .001745 / sec

The minute hand makes 60 revolutions in 1 hour or 12 * 60 = 720 revolutions for 1 revolution of the hour hand

.001745 / 720 = 2.424 * 10E-6 / sec

Answer:

There’s nothing in the pic

Explanation:

Just like my bf ... nonexistent

Answer:

:c: H* : A: :C: H* :A: :C: H* :A:

The given statement is true because the light from two different flaslihgts do not produce interference pattern because it's incoherent.

Answer:

how much?

Explanation:

Answer:

Explanation:

i)5889.97 Å = 588.997 nm and frequency=  5.09 × 10^14 Hz.

Converting the given wavelength in Å to nm:1 Å = 0.1 nm. Therefore, 5889.97 Å = 588.997 nm. To calculate frequency: We know, the speed of light (c) = wavelength (λ) × frequency (ν). Therefore, ν = c/λWhere c = 3.0 × 10^8 m/s = 3 × 10^17 nm/sν = 3 × 10^17/588.997 = 5.09 × 10^14 Hz.

ii)  λ = 589.0 nm = 589 × 10^-9 m and frequency= 5.09 × 10^14 Hz.

The wavelength of sodium vapor is 589.0 nm, and the refractive index of NaF is 1.33. The formula for the calculation of the wavelength when it passes through a prism made of NaF is given as:  μd = λ, whereμ = 1.33, d = thickness of the prism = 1 cm = 0.01 m and λ = 589.0 nm = 589 × 10^-9 m. Therefore, 1.33 × 0.01 = λλ = 1.33 × 0.01/589 × 10^-9λ = 2.26 × 10^-5 m = 22.6 μm. The frequency will be the same as it was before, i.e., 5.09 × 10^14 Hz.

iii)The reflection loss= 1.6%

The reflection loss (R) when a beam of radiation of wavelength 496 nm passes through an AlAs plate is given as: R = [1 - (n2 - n1)^2/(n2 + n1)^2]^2 × 100Where n1 and n2 are the refractive indices of air (n1 = 1) and AlAs (n2 = 3.1) respectively. R = [1 - (3.1 - 1)^2/(3.1 + 1)^2]^2 × 100r = 1.6%.

1b. The loss at 532 nm is negligible, whereas, the loss at 1064 nm is >4.5 optical density.

The filter that can block 1064 nm and pass 532 nm is known as a dichroic filter. One example of such a filter is the FF532-Di02-25x36 from Semrock. It has a transmission of >95% at 532 nm and a blocking range of 1025 to 1150 nm with an optical density (OD) >4.5, meaning the attenuation of the laser fundamental at 1064 nm is at least 100,000 times. The loss at 532 nm is negligible, whereas, the loss at 1064 nm is >4.5 OD.

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i) To express the wavelength of 5889.97 Å in nm, we divide by 10 since there are 10 nm in 1 Å. Therefore, the wavelength is 588.997 nm.

To calculate the frequency of this radiation in Hz, we can use the equation:

frequency = speed of light / wavelength

The speed of light is approximately 3 × 10^8 m/s (or 3 × 10^17 nm/s).

Converting the wavelength to meters (588.997 nm = 5.88997 × 10^-7 m), we can calculate the frequency as:

frequency = (3 × 10^8 m/s) / (5.88997 × 10^-7 m) ≈ 5.092 × 10^14 Hz

ii) When light passes through a prism made of NaF, its wavelength and frequency remain unchanged unless the prism causes dispersion. Therefore, the wavelength and frequency of the light will still be 588.997 nm and 5.092 × 10^14 Hz, respectively.

iii) To calculate the reflection loss when a beam of radiation with a wavelength of 496 nm passes through an AlAs plate, we need to know the refractive indices of AlAs for that wavelength. Without that information, it is not possible to accurately calculate the reflection loss.

Overall, the sodium vapor lamp emits radiation with a wavelength of 5889.97 Å (or 588.997 nm) and a frequency of approximately 5.092 × 10^14 Hz. The wavelength and frequency remain unchanged when passing through a NaF prism, and the reflection loss for a beam of radiation with a wavelength of 496 nm passing through an AlAs plate cannot be determined without additional information.

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F=m*a

T = 142N

Work = Force x distance

distance = 6.1 M

Force = 142 x cos 37 = 113.4 N

W= 113.4N x 6.1M = 691.78 J

After each half-life, approximately 50% of the pennies were removed. This phenomenon can be explained by the nature of radioactive decay, where half of the unstable atoms decay and transform into stable atoms over a specific period.

1. Radioactive decay: The removal of pennies after each half-life can be likened to the process of radioactive decay, where unstable atomic nuclei undergo a transformation into stable nuclei by emitting radiation.

2. Half-life: The half-life is the time required for half of the unstable atoms to decay. In this context, after each half-life, 50% of the pennies are removed.

3. Probability: The removal of pennies is based on the probability of individual atoms decaying. With each half-life, the probability remains constant, resulting in approximately 50% of the remaining pennies decaying.

4. Independent decay: The decay of each individual penny is independent of other pennies. Therefore, even though the initial number of pennies may decrease after each half-life, the percentage of pennies removed remains consistent.

5. Cumulative effect: Over multiple half-lives, the number of pennies removed accumulates. For example, after the first half-life, 50% of the pennies are removed, leaving half of the initial quantity. After the second half-life, 50% of the remaining pennies are removed again, resulting in 25% of the initial quantity remaining, and so on.

6. Exponential decay: The decay of pennies follows an exponential decay curve, with the percentage of pennies removed decreasing over time. However, after each individual half-life, the removal rate remains constant at around 50%.

In conclusion, the approximate removal of 50% of the pennies after each half-life is attributed to the nature of radioactive decay, where the probability of decay remains constant, resulting in a consistent removal rate.

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(a) The mass at time t=0 is 460 grams. (b) Rounding to at least one decimal place, the mass last after 45 years is about 119.0 grams.

(a) To find the mass at time t=0, we alternative into the given characteristic:

m(0) = \(460e^(-0.03(0))\)

Since \(e^0\) is the same for at least one, we've got:

m(0) = 460(1) = 460 grams

Therefore, the mass at time t=0 is 460 grams.

(b) To locate the mass final after 45 years, we substitute t=45 into the given function:

m(45) = \(460e^(-0.03(45))\)

Using a calculator or software program, we will evaluate the expression:

m(45) ≈ \(460e^(-1.35\)) ≈ 460(0.2587) ≈ 118.96 grams

Rounding to at least one decimal location, the mass last after 45 years is about 119.0 grams.

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The correct question is:

"Certain radioactive material decays in such a way that the mass remaining after t years is given by the function m(t)=460e −0.03t where m(t) is measured in grams. (a) Find the mass at time t=0. Your answer is (b) How much of the mass remains after 45 years? Your answer is a Round answer to 1 decimal place."

The energy equation is a way used to assess the body size by taking the height and weight into account. Thus, the given statement is true.

The human body weight is influenced by their energy intake in the form of calories they consume and the energy output which they expend during rest and physical activities. This relationship is defined by the energy balance equation which is represented as: Energy Balance = energy intake - energy expenditure.

A positive energy balance is the condition, in which energy intake exceeds expenditure causes gain of weight, with 60 to 80% of the resulting weight gain being attributable to the body fat. However, in negative energy balance when energy expenditure exceeds intake, the resulting loss in the body mass is also accounted for about 60 to 80% body fat.

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Answer:

d

Explanation:

Answer:

any answer would be correct. its a choose your own answer question lol

Explanation:

Answer:

9828 coulombs

Explanation:

z = \(\sqrt{3x^2 + 3y^2}\)

Relation between the cartesian and polar coordinates

x = r cos ∅

y = r sin ∅

z = \(\sqrt{3x^2 + 3y^2}\) = \(\sqrt{3r}\)

next we calculate the surface charge density of the cone

б ( r, ∅ ) = xyz^2 = 3r^4 sin∅ cos∅

Charge given as

Q = ∫ б(r,∅ )ds

   = ∫ б(r,∅ ) \(\sqrt{1 +( \frac{dz}{dx})^2 + (\frac{dz}{dx} )^2 } dA\)

after integration

Q  = ∫ б(r,∅ ) 2dA

Attached below is the remaining part of the solution

Answer:

Explanation:

freely falling object

Answer:

0

Explanation:

The displacement is zero since it goes in a full circle and ends up where it started.