7.
If 3 tickets to a certain show cost $13.20, what would 7 tickets cost?

What is this answer?

The trigonometric ratios for angle x in the given right triangle are:

\(sin(x) = a/c\\\\cos(x) = b/c\\\\tan(x) = a/b\)

To find the trigonometric ratios for angle x in a right triangle with side lengths a, b, and c, we need to use the definitions of the trigonometric functions:

sin(x) = opposite/hypotenuse

cos(x) = adjacent/hypotenuse

tan(x) = opposite/adjacent

In a right triangle, the side lengths are related as follows:

a: opposite side to angle x

b: adjacent side to angle x

c: hypotenuse

Using these lengths, we can find the trigonometric ratios:

sin(x) = a/c

cos(x) = b/c

tan(x) = a/b

Therefore, the trigonometric ratios for angle x in the given right triangle are:

sin(x) = a/c

cos(x) = b/c

tan(x) = a/b

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Answer:

The question is blur...

Answer:  C 2.5

Step-by-step explanation:

P-Q=6.5

-4-6.5= -10.5=Q

or

Q-P=6.5

Q-(-4)=6.5

Q= 2.5

Answer: finish the question if you need help

Step-by-step explanation:

Answer: 15 gallon for 26.99

Step-by-step explanation:

15 (gallons) x 2.10 ($ per gallon) = 31.5

therefore cheaper to buy 15 gallons

the Degree of freedom is 9.

What is confidence interval?

A confidence interval (CI) for an unknown parameter in frequentist statistics is a range of estimations. The most popular confidence level is 95%, but other levels, such 90% or 99%, are occasionally used for computing confidence intervals. The fraction of related CIs over the long run that actually contain the parameter's true value is what is meant by the confidence level. The degree of confidence, sample size, and sample variability are all factors that might affect the width of the CI. A larger sample would result in a narrower confidence interval if all other factors remained constant. A wider confidence interval would also be required by a higher confidence level and would be produced by a sample with more variability.

We have given,

Sample size =n=10

Degree of freedom =n-1=10-1=9

Hence the Degree of freedom is 9

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Answer:

>\/<

\(10\)

>/\<

- remember that the midline is always half of the sum of the other two legs.

here,

UX is the midline,

ST is the leg,

VW is the other leg.

so,

ST + VW = 2UX

now plug in,

25 + VW = 2(35)

25 + VW = 70

VW = 45

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Answer:

All real numbers greater than or equal to 0.

General Formulas and Concepts:

Algebra I

Step-by-step explanation:

According to the graph, we see that our x-values span from 0 to infinity. Since 0 is a closed dot, it is inclusive in the domain:

[0, ∞) or x ≥ 0 or All Real Numbers greater than or equal to 0.

The a) , c) & d) are convergent series and b) is divergent series.

a)

Given series,

\(\sum \limits^\infty_{n=1} (7+n(7))^{-7}\\ \\=\sum \limits^\infty_{n=1}7^{-7}+\sum \limits^\infty_{n=1}(7^nn)^{-7}\\\)

consider,

\(\sum \limits^\infty_{n=1}(7^nn)^{-7}=\sum \limits^\infty_{n=1}(n)^{-7}(7)^{-7}\\\\=\sum \limits^\infty_{n=1}(n)^{-7}(7)^{-7}\\\\=\sum \limits^\infty_{n=1}(n)^{-7}(\frac{1}{7})^{7}\)

comparing \(=\sum \limits^\infty_{n=1}(n)^kr^n\) we get,

\(k=-7\ and\ r=\frac{1}{7^7}=\frac{1}{823543}\)

here, \(|r|=|\frac{1}{7^7}|=1.2142*10^{-6}\) which is < 1

here |r| < 1,

Thus, the given series converges.

b)

Given series,

\(\sum \limits^\infty_{n=1} n^{\pi}(\frac{7^{2n}}{6^n+n^9})=\sum \limits^\infty_{n=1}n^kr^n\)clearly, k=π

To find r we need to use ratio test for \(a_n\)

\(a_n=\frac{7^{2n}}{6^n+n^9}\\\\L= \lim_{n \to \infty}|\frac{a_n+1}{a_n} |\\\\=\lim_{n \to \infty}|\frac{7^{2n+2}}{6^{n+1}+(n+1)^{9}}*\frac{6^{n}+(n)^{9}}{7^{2n}}|\\\\=\lim_{n \to \infty}|\frac{7^2(6^n+n^9)}{6{n+1}+(n+1)^9}|\\\\=\lim_{n \to \infty}|\frac{49(6^n+n^9)}{6^{n+1}+(n+1)^9}|\)

here \(r=\frac{49}{6}\) > 1

hence. the series diverges.

c)

Given series,

\(\sum \limits^\infty_{n=1}\frac{n^5+2}{n^6+7}\)

let \(u_n=\frac{n^5+2}{n^6+7}\)

take \(v_n=\frac{n^5}{n^6}=\frac{1}{n}\)

Now,

\(\lim_{n \to \infty} \frac{u_n}{v_n}= \lim_{n \to \infty}\frac{n^5+2}{n^6+2}*\frac{n}{1}\\=1\\Now,\\\\\sum v_n=\sum \frac{1}{n}\\\\=\sum (n)^{-1}(1)^n\\\\\)

comparing with \(\sum n^kr^n\) we get,

k=-1 and r=1

So, the series converges.

d)

Given series,

\(\sum \limits^\infty_{n=1} (\frac{2n^2+7n+7^{-3n}}{8^{n+2}+6n+7\sqrt{n}})^3\)

The dominant terms are \(2n^2\) and \(8^{n+2}\), the sum can be approximated as,

\(\sum \limits^ \infty_{n=1} (\frac{2n^2}{8^{2+n}})^3\\\\=\frac{2^3}{8^6}\sum \limits^ \infty_{n=1} n^6(\frac{1}{512})^n\)

comparing with \(\sum n^kr^n\) we get,k=6 and \(r=\frac{1}{512}\)

here also 0 < r <1,

Thus, the series converges.

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2 of Spades: There's only one 2 of spades card in the deck, so the probability of choosing the 2 of spades is 1/52.

A Jack: There are 4 Jacks in the deck, so the probability of choosing a jack is 4/52, or 1/13.

A red King: There are 2 red kings in the deck, so the probability of choosing one is 2/52, or 1/26.

A Diamond suit: There are 13 diamond cards in the deck, so the probability of choosing one is 13/52, or 1/4.

Answer:

Step-by-step explanation:

Probability = favorable outcome / total number of outcomes

5 numbers left and 3 of them are even.

So combined probability is:

For the mutual fund investment, the chosen options are a starting amount of $900 and a rate of annual return of 7%.
To calculate Khalid's weekly profits based on the number of weeks, a function is determined using the given data. The graph of Khalid's profits is plotted alongside Harper's profits.
The solution to the system of equations is found by determining the point where Harper's and Khalid's profit functions intersect. This represents the week when their profits are equal.
The average rate of change of Khalid's profits from week 3 to week 6 is calculated, representing the rate at which his profits are changing over that period.

The chosen options for the mutual fund investment are a starting amount of $900 and a rate of annual return of 7%. To calculate the future value of the investment after 30 years, we can use the compound interest formula: FV = PV * (1 + r)^n. Plugging in the values, we get FV = 900 * (1 + 0.07)^30 = $6,084.38.
To calculate Khalid's weekly profits based on the number of weeks, we can observe the given table and identify the pattern. The function for Khalid's profits can be determined by fitting a curve to the given data points. Plotting Khalid's profits on the same graph as Harper's profits allows for a visual comparison.
The solution to the equation h(x) = k(x) represents the point where Harper's and Khalid's profit functions intersect. It indicates the week when.
their profits are equal. By finding the x-coordinate of this point, the specific week can be determined.
The average rate of change of Khalid's profits from week 3 to week 6 can be calculated by finding the slope of the line passing through those two points. It represents the average rate at which Khalid's profits are changing over that specific period, indicating the growth or decline in his business during that time.

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Answer: 24.86miles/hr

Step-by-step explanation: Divide the speed by 1.609 to convert

These results indicate the strength of evidence against the null hypothesis in each test. A p-value below the chosen significance level (such as 0.05) suggests strong evidence against the null hypothesis, while a p-value above the significance level indicates weak evidence to reject the null hypothesis.

For the given situations:

(a) In an upper-tailed test with df = 7 and t = 2.0, the p-value is greater than 0.05.

(b) In an upper-tailed test with n = 13 and t = 3.2, the p-value is less than 0.005.

(c) In a lower-tailed test with df = 10 and t = -2.4, the p-value is less than 0.005.

(d) In a lower-tailed test with n = 23 and t = -4.2, the p-value is less than 0.005.

(e) In a two-tailed test with df = 14 and t = -1.7, the p-value is greater than 0.1.

(f) In a two-tailed test with n = 15 and t = 1.7, the p-value is greater than 0.1.

(g) In a two-tailed test with n = 14 and t = 6.1, the p-value is less than 0.01.

The probability value is often referred to as the P-value. It is described as the likelihood of receiving a result that is either more extreme than the actual observations or the same as those observations.

(a) Upper-tailed test,

df = 7,

t = 2.0

P-value > 0.05

(b) Upper-tailed test,

n = 13,

t = 3.2

P-value < 0.005

(c) Lower-tailed test,

df = 10,

t = -2.4

P-value < 0.005

(d) Lower-tailed test,

n = 23,

t = -4.2

P-value < 0.005

(e) Two-tailed test,

df = 14,

t = -1.7

P-value > 0.1

(f) Two-tailed test,

n = 15,

t = 1.7

P-value > 0.1

(g) Two-tailed test,

n = 14,

t = 6.1

P-value < 0.01

These results indicate the strength of evidence against the null hypothesis in each test. A p-value below the chosen significance level (such as 0.05) suggests strong evidence against the null hypothesis, while a p-value above the significance level indicates weak evidence to reject the null hypothesis.

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Answer:    

29 feet in lenght, 5 feet in width and 12 feet in height

Step-by-step explanation:

that shou

ld be your answer

Answer:

-168

Step-by-step explanation:

8 × -7 × 3

-56 × 3

-168

Answer:

Which of these factors is involved in earthquake formation?

plates getting larger

rocks breaking

stress that decreases

faults that remain stationary

Step-by-step explanation:

Answer:

\(2\sqrt{3}\)

Step-by-step explanation:

f(x) = \(\sqrt{x}\)

Plug x as 12.

f(12) = \(\sqrt{12}\)

f(12) = \(2\sqrt{3}\)

Answer:

2\(\sqrt{3}\)

Step-by-step explanation:

\(\sqrt{12}\)

\(\sqrt{4} \sqrt{3}\)

\(\sqrt{4} =2\)

\(2\sqrt{3}\)

Answer:

c. 1,6-dipropylheptanal

1.) The value of X would be = 3cm. That is option A.

2.). The value of X (in cm) would be = 4cm. That is option B.

For question 1.)

Given that ∆ABC≈∆PQR

Scale factor = larger dimension/smaller dimension

= 6/4.5 = 1.33

The value of X= 4÷ 1.33 = 3cm

For question 2.)

To calculate the value of X the formula that should be used is given as follows:

PB/PB+BR = AB/AB+QR

where;

PB= 3.2

BR = 4.8

AB = 2

QR= X

That is;

3.2/4.8+3.2= 2/2+X

3.2(2+X) = 2(4.8+3.2)

6.4+3.2x = 16

3.2x= 16-6.4

X= 12.8/3.2 = 4cm.

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One ounce of food contains average  about 28 grams of carbs.

One of the three macronutrients that the body needs for energy, carbohydrates can be found in a wide variety of foods. Sugar, starch, and fiber are the three elements that make up carbohydrates. Weight is measured in ounces, which weigh 28.35 grams. As a result, one ounce of food contains about 28 grams of carbs. Carbohydrates are crucial for supplying the body with the 4 calories per gram of energy it needs to function, fuel physical activity, and help with digestion. Foods like fruits, vegetables, grains, nuts, and dairy products all naturally include ounces of carbs. It is crucial to remember that there are several kinds of carbs, some of which are healthier than others.

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The complete question is

How many grams of carbs in an ounce of food ?

Answer:

Lines 2 and 4 are perpendicular

Step-by-step explanation:

Line 2: 4y=3x-4

y=3/4x - 1

Line 4: 4x+3y=-6

3y=-6-4x

y=-2 - 4/3x

The two lines are perpendicular since -4/3= - (inverse of 3/4)

Two lines 2 and 4 are perpendicular to each other. The correct option is C.

An equation of the line is defined as a linear equation having a degree of one. The equation of the line contains two variables x and y. And the third parameter is the slope of the line which represents the elevation of the line.

The general form of the equation of the line:-

y = mx + c

m = slope

c = y-intercept

Slope = ( y₂ - y₁ ) / ( x₂ - x₁ )

For two lines to be perpendicular the slope should be negative reciprocal. For two lines to be parallel the slope of the lines should be equal.

The equation of lines 2 and 4 is,

y = (3/4)x -1

y =(-4/3)x - 2

Here the slope of the two lines is reciprocal as well as negative.

Therefore, two lines 2 and 4 are perpendicular to each other. The correct option is C.

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Option C is the correct choice as it accurately describes the chi-square test for independence. The chi-square test for independence is used to determine if there is a relationship between two categorical variables. It is similar to neither a single-sample t test nor a correlation because it involves categorical variables, not continuous ones.

Option C accurately describes the chi-square test for independence. It states that the test is similar to an independent-measures t test because it compares separate samples to evaluate the difference between separate populations.

The chi-square test for independence involves creating a contingency table that displays the observed frequencies of the two categorical variables. Then, it calculates the expected frequencies under the assumption of independence. The test compares the observed and expected frequencies using the chi-square statistic. If the observed frequencies significantly differ from the expected frequencies, we reject the null hypothesis and conclude that there is a relationship between the variables.

In contrast, options A, B, and D do not accurately describe the chi-square test for independence. Option A refers to a single-sample t test, which is not applicable to the chi-square test. Option B mentions a correlation, which assesses the relationship between continuous variables, not categorical ones. Option D combines elements of both a correlation and an independent-measures t test, which are not applicable to the chi-square test.

Therefore, option C is the correct choice as it accurately describes the chi-square test for independence.
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Answer: A

Step-by-step explanation: It's the first option

In a multiplexer, the number of inputs (k) and the number of selector bits (s) determine the maximum number of inputs that can be selected. The setup that will not work is when k = 4 and s = 5. All the other options, k = 10 with s = 3 or 4, and k = 2 with s = 4, will work.

In a multiplexer, the number of inputs (k) and the number of selector bits (s) determine the maximum number of inputs that can be selected. The formula for calculating the maximum number of inputs (N) is N = 2^s.

For the given options:

1. k = 10 and s = 3: In this case, N = 2^3 = 8, which is greater than or equal to k = 10. So, this setup will work.

2. k = 10 and s = 4: Here, N = 2^4 = 16, which is greater than or equal to k = 10. Hence, this setup will also work.

3. k = 2 and s = 4: In this scenario, N = 2^4 = 16, which is greater than or equal to k = 2. Therefore, this setup will work as well.

However, for the option where k = 4 and s = 5, we have N = 2^5 = 32, which is greater than k = 4. This means that there are not enough inputs to fully utilize the selector's capability.

Therefore, this setup will not work as intended.

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The number of inputs that the Multiplexer can handle is 2^2 = 4,  equal to the number of inputs.

The relationship between the number of inputs (k) and the number of selector bits (s) in a multiplexer.

A multiplexer is a combinational logic circuit that allows us to select one input from multiple inputs based on the selector bits. The number of inputs that a multiplexer can handle is determined by 2^s, where s is the number of selector bits.

Option 1: k = 10, s = 3

In this case, we have 10 inputs (k = 10) and 3 selector bits (s = 3). The number of inputs that the multiplexer can handle is 2^3 = 8, which is less than 10. Therefore, this setup will not work because it has more inputs than the multiplexer can handle.

Option 2: k = 10, s = 4

Here, we have 10 inputs (k = 10) and 4 selector bits (s = 4). The number of inputs that the multiplexer can handle is 2^4 = 16, which is greater than 10. Therefore, this setup will work because it can accommodate all 10 inputs.

Option 3: k = 2, s = 4

In this case, we have 2 inputs (k = 2) and 4 selector bits (s = 4). The number of inputs that the multiplexer can handle is 2^4 = 16, which is greater than 2. Therefore, this setup will work because it can accommodate both inputs.

Option 4: k = 4, s = 2

Here, we have 4 inputs (k = 4) and 2 selector bits (s = 2). The number of inputs that the multiplexer can handle is 2^2 = 4, which is equal to the number of inputs. Therefore, this setup will work because it can accommodate all 4 inputs.

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Answer:

\(y=-3x+2\)

Step-by-step explanation:

Slope-intercept form is:

\(y=mx+b\)

where m is the slope and b is the y-intercept so rearrange your equation in that specific form.

\(y+4=-3(x-2)\\y+4=-3x+6\\y=-3x+6-4\\y=-3x+2\\\)

and if we compare we get the values of m to be -3 and b to be +2 so the slope intercept form is

y = -3x + 2

We can't use any of the pattern

Answer:

Look below

Step-by-step explanation:

Ok, you got a Quadrilateral with the side lengths 6, 9, 9, 12

The shortest of B is 2

Find the scale factor of the A to B

6 -> 2

6/2 = 3

Scale factor is 3

Now divide all the sides by scale factor

6/3, 9/3, 9/3, 12/3 = 2, 3, 3, 4

Add them all together to get the perimeter

2+3+3+4 = 12

Perimeter of B is 12

Answer:

18

-9

30

Step-by-step explanation:

did on edge :)

Answer:

Evaluate the following numerical expressions.

6 + 3 • 4 =  18

(6 + 3) ÷ (4 – 5) = -9

6 + 23 • 3 = 30

Step-by-step explanation:

i took the test