7.46 - A 0.0500-mol sample of a nutrient substance is burned in a bomb calorimeter containing 2.00 x 10g H20. If the formula weight of this nutrient substance is 114 g/mol, what is the fuel value (in nutritional Cal) if the temperature of the water increased 5.70C?​

The statement "Each member of a homologous series differs from its nearest neighbors by 14 amu" is true of members about a homologous series.

In organic chemistry, a homologous series unveils itself as a sequential assembly of compounds exhibiting an identical functional group, boasting akin chemical traits. Within this series, the constituents can either sport a branched or unbranched structure, or deviate through the molecular formula of CH2 and a molecular mass variation of 14u.

This divergence may manifest as the elongation of a carbon chain, as observed in the linear alkanes (paraffins), or as the augmentation in the count of monomers forming a homopolymer, such as amylose.

The entities belonging to a homologous series typically embrace a fixed assortment of functional groups, thereby conferring upon them resemblant chemical and physical characteristics.

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Answer:

no it wont dissolves

Explanation:

iodine will only dissolve in solvents that lack of polarity. acetone is a strongly polar solvent. therefore iodine would not disslove in acetone.

hope this helps!

Question

Research: Find 4 strategies that are used to prevent rusting of car parts and/or water pipes? Briefly explain how they work in your own words. What are some pros and cons of these methods?

Answer

Method 1: Applying Oil - Coating materials with oil will help to prevent rust or slow its formation since it prevents moisture from reaching the iron, which can get oxidized.

Pros: It can be applied easily to most materials and it's of relatively low cost

Cons: Some materials can't be covered with oil because they can interfere with the process they are designed for. Example: Food transport machinery

Method 2: Paint the metal - Similarly to the oil a good amount of paint can cover the metallic parts and prevent moisture from the air to get in direct contact with the iron.

Pros: It is easy to apply paint to most metals.

Cons: Contrarily to oil, paint can be more expensive depending on the application.

Method 3: Galvanization - is the process of applying a protective zinc coating to iron or steel materials to prevent or slow the rusting processes.

Pros: The galvanization process makes steel highly durable and the material usually becomes scratch free.

Cons: Steel structures that are either too big or too small are unsuitable for the galvanization process.

Method 4: Store in a controlled environment - Metals corrode easily when exposed to environments with high humidity. To preserve a metal in good condition, it should be stored in environments with low humidity content and not in contact with salts or acids.

Pros: It does not alter the properties of the equipment.

Cons: Not all metal objects can be stored in environments containing low humidity.

From the calculations, we can see that the theoretical yiled of NO2 is 100L of NO2

The theoretical yield is that calculated from the stoichiometry of the reaction.

We can see that 1 mole of O2 produced 2 moles of NO2. Thus;

2.23 moles of O2 will produce 4.46 moles of NO2

Since 1 mole of NO2 occupies 22.4 L

4.46 moles of NO2 occupies 100L of NO2

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It will be used 1.95 grams of the reactant in the reaction.

To calculate the density of a given substance, use the following expression:

                                                     \(d = \frac{m}{v}\)

Thus, having the values ​​of volume and density, just apply the formula above to find the value of mass, so that:

                                               \(0.975 = \frac{m}{2}\)

                                            \(m= 1.95 grams\)

So, it will be used 1.95 grams of the reactant in the reaction.

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Answer:

hydrogen, carbon, oxygen and nitrogen

Explanation:

Most organic compounds are made up of the four elements: hydrogen, carbon, oxygen and nitrogen.

Most organic compounds are made of just four elements are  hydrogen, carbon, oxygen and nitrogen.

The term organic compound is defined as a substance that contains covalently - bonded carbon and hydrogen and often with other elements.

Benzoic acid, aromatic compounds, benzoic aldehyde, propanoic acid, butanoic acid, malonic acid, amines, heterocyclic compounds, VOC, benzoic acid, and diethyl malonate are some examples of organic compounds.

Carbohydrates, lipids, proteins, and nucleotides are all organic compounds that are required for human function. Because they contain both carbon and hydrogen, these compounds are classified as organic.

Thus, Most organic compounds are made of just four elements are  hydrogen, carbon, oxygen and nitrogen.

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Answer:

178.55

Explanation:

5*176+19*177+27*178+14*179+35*180 /100

= 880+3363+4806+2506+6300 /100

=17855 /100

178.55

The volume of hydrogen gas produced is 19.8 L.

The balanced chemical equation is given as;

Zn + 2HCl → ZnCl₂ + H₂

from the reaction above;

1 mole of Zn = 1 mole of H₂

number of mole of 48.5 g Zn  is calculated as

48.5 g  /65.4 g/mol

= 0.74 mol Zn  = 0.74 mol H₂

The volume of hydrogen gas produced is calculated as follows;

PV = nRT

where;

T = 27°C + 273 = 300 K

V = nRT/P

V = (0.74 x 0.08206 x 300) / (0.921)

V = 19.8 L

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6.02 x \(10^{20\) formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

To convert formula units of MgCl₂ to moles of MgCl₂, we need to use Avogadro's number, which relates the number of formula units to the number of moles.

Avogadro's number (NA) is approximately 6.022 x 10^23 formula units per mole.

Given that we have 6.02 x 10^20 formula units of MgCl₂, we can set up a conversion factor to convert to moles:

(6.02 x 10^20 formula units MgCl₂) * (1 mol MgCl₂ / (6.022 x 10^23 formula units MgCl₂))

The formula units of MgCl₂ cancel out, and we are left with moles of MgCl₂:

(6.02 x 10^20) * (1 mol / 6.022 x 10^23) = 0.1 mol

Therefore, 6.02 x 10^20 formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

It's important to note that this conversion assumes that each formula unit of MgCl₂ represents one mole of MgCl₂. This is based on the stoichiometry of the compound, where there is one mole of MgCl₂ for every one formula unit.

Additionally, this conversion is valid for any substance, not just MgCl₂, as long as you know the value of Avogadro's number and the number of formula units or particles you have.

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The growth of the new plant depicts the asexual reproduction characteristic. The characteristic that describes the growth of the new plant in Stephan's mother cutting a twig from a rose bush and planting it in the soil is asexual reproduction.

Asexual reproduction is the mode of reproduction by which organisms generate offspring that are identical to the parent's without the fusion of gametes. Asexual reproduction is a type of reproduction in which the offspring is produced from a single parent.

The offspring created are clones of the parent plant, meaning they are identical to the parent.The new plant in Stephan’s mother cutting a twig from a rose bush and planting it in the soil depicts the process of asexual reproduction, which is the ability of a plant to reproduce without seeds. In asexual reproduction, plants can reproduce vegetatively by cloning themselves using their roots, bulbs, or stems.

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Answer:

ugh stop iyts the same question so

Explanation:just leave ur school its not that hard

Answer:

D

Explanation:

Answer:

2875 s

Explanation:

From the question given above, the following data were obtained:

Power (P) = 80 J/s

Energy (E) = 2.3×10⁵ J

Time (t) = ?

Power can simply be defined as the rate at which energy is used. Mathematically, power is expressed as:

Power = Energy / time

P = E/t

With the above formula, we can obtain the time taken for the bulb to consume 2.3×10⁵ J. This can be obtained as follow:

Power (P) = 80 J/s

Energy (E) = 2.3×10⁵ J

Time (t) = ?

Power = Energy / time

P = E/t

80 = 2.3×10⁵ /t

Cross multiply

80 × t = 2.3×10⁵

Divide both side by 80

t = 2.3×10⁵ / 80

t = 2875 s

Therefore, it will take 2875 s for the bulb to consume 2.3×10⁵ J of energy.

Answer:

iron and chlorine

Explanation:

The half reaction with a more positive standard reduction potential will proceed spontaneously in a redox reaction

The half reaction with a more positive standard reduction potential will undergo reduction when compared to the half reaction with a more negative standard reduction potential.

Oxidation-reduction reactions, often known as redox reactions, are a set of chemical reactions that involve electron transfer between reactants. In a redox reaction, one reactant is oxidized, losing electrons, while the other reactant is reduced, gaining electrons.

The oxidation half-reaction is the process of losing electrons and increasing the oxidation number, whereas the reduction half-reaction is the process of gaining electrons and decreasing the oxidation number. The total reaction is referred to as the redox reaction.

Half-reaction:Half-reaction refers to the two parts of an oxidation-reduction reaction that happen separately. A half-reaction must always be either an oxidation reaction or a reduction reaction. It also describes the movement of electrons and hydrogen ions in an equation.

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Answer:

For safety.

Explanation:

Because uncovered wires are conductors, an electric current could damage someone if touched. Plastic and rubber are insulators, meaning that current cannot pass through them.

Answer:

two unpaired electrons

Explanation:

each of which are located in a different pi* antibounding orbital.

Answer:

ok, here is your answer

Explanation:

AI-generated answer

To find the mass of oxygen that reacted, we need to use the Law of Conservation of Mass, which states that in a chemical reaction, the mass of the reactants equals the mass of the products.

First, we need to find the number of moles of hydrogen that reacted:

Molar mass of hydrogen (H₂) = 2.016 g/mol

Number of moles of H₂ = mass/molar mass = 46.2 g/2.016 g/mol = 22.92 mol

Next, we need to use the balanced chemical equation to find the number of moles of water produced:

hydrogen + oxygen → water

2H₂ + O₂ → 2H₂O

From the equation, we can see that for every 2 moles of H₂, 1 mole of O₂ is required to produce 2 moles of H₂O. Therefore, the number of moles of O₂ required to produce 22.92 moles of H₂O is:

Number of moles of O₂ = 1/2 x 22.92 mol = 11.46 mol

Finally, we can find the mass of oxygen that reacted by using its molar mass:

Molar mass of oxygen (O₂) = 32.00 g/mol

Mass of oxygen = number of moles x molar mass = 11.46 mol x 32.00 g/mol = 366.72 g

Therefore, the mass of oxygen that reacted is 366.72 g.

Answer:

will you help us with that one please

The masses of dimethylamine and dimethylammonium chloride we need to prepare 8. 00 l of pH = 12. 00 buffer is 905 gm.

A buffer solution is defined as an acid or a base aqueous solution consisting of a mixture of a weak acid and its conjugate base, or vice versa whose pH changes very little when a small amount of a strong acid or base is added to it.

For above given information, the dimethylamine (CH₃)₂NH and dimethylammonium chloride (CH₃)₂NH * HCl are mixed to prepare a buffer solution

The concentration of the components is given as 0.5M , Volume = 5L

No. of moles = CV = 0.5 * 5 =2.5 moles

2.5 moles of dimethylamine = mass/ Molecular weight

Molecular weight of dimethylamine = 45 gm

Therefore the mass of dimethylamine required = 45 * 2.5 = 112.5gm

4 moles of dimethylammonium chloride = 362 gm

Therefore the mass of dimethylammonium chloride required = 362*2.5 = 905 gm

Thus, the masses of dimethylamine and dimethylammonium chloride we need to prepare 8. 00 l of pH = 12. 00 buffer is 905 gm.

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If two quantities are directly proportional, when one quantity increases by 10 percent, the other quantity will also increase by 10 percent.

If two quantities are directly proportional, it means that they vary in such a way that a change in one quantity leads to a proportional change in the other quantity. In this scenario, if one quantity increases by 10 percent, the other quantity will also increase by 10 percent.

Let's consider two variables, x and y, that are directly proportional. Mathematically, we can represent this relationship as y = kx, where k is the constant of proportionality. When x increases by 10 percent, we can express it as (1 + 0.10)x = 1.10x.

Substituting this into the equation y = kx, we get y = k(1.10x). Since k is a constant, it remains unchanged. Therefore, the new value of y is 1.10 times the original value of y, which represents an increase of 10 percent.

To summarize, when one quantity increases by 10 percent in a directly proportional relationship, the other quantity also increases by 10 percent. This concept is fundamental in various fields such as physics, economics, and mathematics, where understanding direct proportionality is crucial for analyzing and predicting relationships between variables.

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a) In the reaction \(H_2CO_3 + CN^- = HCN + HCO^{3-}\), \(H_2CO_3\) acts as an acid by donating a proton (\(H^+\)) to \(CN^-\).

b) In the reaction \(F^- + HSO_4^{-} = HF + SO_4^{2-}\), \(HSO_4^{-}\) acts as an acid by donating a proton (\(H^+\)) to \(F^-\).

c) In the reaction \(HSO_4^- + H_2O = H_3O^+ + SO_4^{2-\), \(HSO_4^{-}\) acts as an acid by donating a proton (\(H^+\)) to \(H_2O\).

a) The acid is both an Arrhenius acid (produces \(H^+\) ions in water) and a Bronsted-Lowry acid (donates a proton to a base).

b) The acid is both an Arrhenius acid (produces \(H^+\) ions in water) and a Bronsted-Lowry acid (donates a proton to a base).

c) The acid is a Bronsted-Lowry acid (donates a proton to a base) but not an Arrhenius acid because it does not produce \(H^+\) ions in water. However, the \(H_3O^+\) ion that is formed can be considered an Arrhenius acid because it produces \(H^+\) ions in water.

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Answer:

the answer woul be 89 if you do the math right

Explanation:

✅The racial numbers are all the numbers that can represent as the quotient of two numbers enter or, more precisely, an entity and a natural positive; The term "racial" refers to a fraction or part of a whole.

IamSugarBee

Answer:

Explanation:

An element with 70 protons and a mass of 170 would be considered radioactive.

In general, an element with an atomic number (number of protons) greater than 82 tends to be radioactive. Since the element in question has 70 protons, which is less than 82, it does not fall into the category of naturally radioactive elements. However, it is important to note that the stability of an element also depends on the balance between protons and neutrons in the nucleus. Without information about the number of neutrons in the nucleus, we cannot determine the stability of this specific element definitively.

Answer:

Explanation:

a) The balanced equation for the double replacement reaction between lead (II) nitrate and potassium bromide is:

Pb(NO₃)₂(aq) + 2KBr(aq) → PbBr₂(s) + 2KNO₃(aq)

In this reaction, lead (II) bromide (PbBr₂) will precipitate, while potassium nitrate (KNO₃) will remain in solution.

b) To determine the amount of precipitate produced, we need to first determine the limiting reactant. We can do this by calculating the number of moles of each reactant and comparing it to the stoichiometry of the balanced equation.

The molar mass of lead (II) nitrate is 331.21 g/mol and the molar mass of potassium bromide is 119.00 g/mol.

The number of moles of lead (II) nitrate is 32.5 g / 331.21 g/mol = 0.0981 mol The number of moles of potassium bromide is 38.75 g / 119.00 g/mol = 0.3256 mol

According to the balanced equation, one mole of lead (II) nitrate reacts with two moles of potassium bromide to produce one mole of lead (II) bromide. This means that if all the lead (II) nitrate were to react, it would require 0.0981 mol * 2 = 0.1962 mol of potassium bromide.

Since we have more than enough potassium bromide (0.3256 mol > 0.1962 mol), lead (II) nitrate is the limiting reactant.

The number of moles of lead (II) bromide produced will be equal to the number of moles of lead (II) nitrate consumed, which is 0.0981 mol.

The molar mass of lead (II) bromide is 367.01 g/mol, so the mass of lead (II) bromide produced will be 0.0981 mol * 367.01 g/mol = 36.0 g.

c) To determine the amount of excess reactant remaining, we need to subtract the amount consumed from the initial amount.

The number of moles of potassium bromide consumed is half the number of moles of lead (II) nitrate consumed, which is 0.0981 mol / 2 = 0.04905 mol.

The mass of potassium bromide consumed is 0.04905 mol * 119.00 g/mol = 5.84 g.

The mass of potassium bromide remaining is 38.75 g - 5.84 g = 32.91 g.

Answer:

use of sterile injections for clearanti bodies

Explanation:

Answer:

Hello There!!

Explanation:

They can be used in making products that make it lightweight such as in power tools and luggages.

hope this helps,have a great day!!

~Pinky~

Answer:

Condensation

Explanation:

An exothermic process is one in which heat is lost. Condensation is a change of state from gas to liquid. Thus is loses heat.

HOPE THIS HELPED

Answer:

See explanation

Explanation:

In this question, we have to follow the IUPAC rules. Lets analyze each compound:

a. 1-methylbutane

In this compound we have a chain of 5 carbons, so the correct name is Pentane.

b. 1,1,3-trimethylhexane

In this compound, we longest chain is made of 7 carbons, so, we have to use the name "heptane". Carbon one would be the closet one to the methyl group, so the correct name is  2,4-dimethylheptane.

c. 5-octyne

In this case, carbon 1 would be the closet one to the triplet bond. With this in mind, the correct name is oct-3-yne.

d. 2-ethyl-1-propanol

In this compound, we longest chain is made of 4 carbons, so, we have to use the name "butane". Carbon one would be the carbon with the "OH" group, so the correct name is  2-methylbutan-1-ol.

e. 2.2-dimethyl-3-butanol

In this case, carbon 1 would be the closet one to the "OH". With this in mind, the correct name is 3,3-dimethylbutan-2-ol.

See figure 1

I hope it helps!

Answer:

from nitrogen fixation in plants, lightning and bacteria

Explanation:

Okay, let's solve this step-by-step:

* We are given that the initial volume of the gas is 1.75 L at 1 atm pressure

* We want to know the pressure if the volume increases to 16.60 L

* According to Boyle's Law: Pressure x Volume = Constant

* Since the initial pressure is 1 atm and volume is 1.75 L, the constant is:

1 atm x 1.75 L = 1.75 atm*L

* When the volume increases to 16.60 L, plugging into Boyle's Law:

P x 16.60 L = 1.75 atm*L

* Solving for P (pressure):

P = 1.75 atm*L / 16.60 L

P = 0.105 atm

Therefore, the pressure of the 1.75 L of disulfur monoxide gas if it occupied a volume of 16.60 L would be 0.105 atm.