7. what do the key results indicate?

Explanation:

Thanx for the figure;
The force component of F   UP the ramp that  moves the crate must equal the force of the crate DOWN the ramp

75 kg = mg Newtons = 735.8 Newtons

    Downplane force is   735.8 sin 34°  = 411.4 Newtons

   Fn =The horizontal force will be found by   cos 34 = 411.4/ F                                                                       F = 411.4/cos (34) = 496 N

Normal Force =  735.8 cos 34°  = 610 N   This part is due to the mass of the crate....there is additional normal force from the force pushing the crate up the hill  (from below)

   = F sin34   =  496 sin 34 = 277.4 N

            SUM of normal forces = 610 + 277.4 = 887.4 N

Answer:

  a.  |F| ≈ 496 N

  b.  normal force ≈ 887 N

Explanation:

You want the magnitude of the horizontal force F that moves a crate up a 34° ramp at constant speed, and you want the magnitude of the normal force on the crate.

The constant speed of the crate tells you the net force up the ramp is zero. This is the sum of the component of force F in that direction and the force due to gravity in the opposite direction:

  F·cos(34°) - m·g·sin(34°) = 0

  F = mg·tan(34°) = (75 kg)(9.8 m/s²)tan(34°) ≈ 496 N

The magnitude of force F is about 496 N.

The normal force on the crate will be the sum of the component of F in that direction and the force due to gravity in the same direction:

  F·sin(34°) +m·g·cos(34°) ≈ 887 N

The magnitude of the normal force is about 887 N.

Option B is correct; It describes the third (missing) ray

here is a concept known as "angle of incidence" which refers to the angle between an incident ray and the normal (perpendicular) to a surface at the point of incidence.

When light or a ray of any electromagnetic wave encounters a boundary between two different mediums (e.g., air and water), the angle of incidence is the angle at which the ray approaches the surface before it is either reflected, refracted, or absorbed.

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Answer:

9000m

Explanation:

Given parameters:

Time  = 30s

Acceleration  = 20m/s²  

Unknown:

Distance traveled  = ?

Solution:

To solve this problem, we use one of the kinematics equation.

     S  = ut + \(\frac{1}{2}\)at²  

u is the initial velocity = 0m/s

t is the time taken

a is the acceleration

           S  = (0 x 30) + ( \(\frac{1}{2}\) x 20 x 30² ) = 9000m

The time elapsed between the first splash and the second splash is approximately 0.69 seconds.

To calculate this, we consider the motion of two rocks thrown simultaneously from a bridge. Heather throws a rock straight down with a speed of 14 m/s, while Jerry throws a rock straight up with the same speed.

We use the equation for displacement in uniformly accelerated motion: s = ut + (1/2)at^2.

For Heather's rock, which is thrown downwards, the initial velocity (u) is positive and the acceleration (a) due to gravity is negative (-9.8 m/s^2). The displacement (s) is the height of the bridge (46 m).

Solving the equation, we find two possible values for the time (t): t ≈ -4.91 s and t ≈ 1.91 s.

Since time cannot be negative in this context, we discard the negative value and consider t ≈ 1.91 s as the time it takes for Heather's rock to hit the water.

For Jerry's rock, thrown upwards, we use the same equation with the same initial velocity and acceleration. The displacement is also the height of the bridge, but negative.

Solving the equation, we find t ≈ -5.68 s and t ≈ 1.22 s. Again, we discard the negative value and consider t ≈ 1.22 s as the time it takes for Jerry's rock to reach its maximum height before falling back down.

To find the time difference between the first and second splash, we subtract t ≈ 1.91 s (Heather's rock) from t ≈ 1.22 s (Jerry's rock). This gives us a time difference of approximately 0.69 seconds.

Therefore, the time elapsed between the first splash and the second splash is approximately 0.69 seconds.

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Given data:

Position of the particle along the x-axis;

Here, A and B are constants with A=-3.15 m/s and B=2.4 m/s².

Therefore,

The velocity of the particle is given as,

Substituting x(t),

The time when the velocity will be zero is calculated by substituting v(t)=0 in the above expresion,

Therefore, the position of the particle when the velocity is zero is calculated by substituting t=0.66 s in the equation for the position of the particle,

Therefore, the position of the particle when the velocity is zero is -1.03 m (1.03 m to the left of its initial position).

Answer:

money is not rare. you can find it everywhere. what exactly is the question? whether it is bad or not is an opinion.

Explanation:

The mass of the wire of lowest A on a piano is 0.00165 kg.

The frequency of a vibrating string is given by the equation:

f = (1/2L) * sqrt(T/μ)

where f is the frequency of the string, L is the length of the string, T is the tension in the string, and μ is the linear mass density of the string (mass per unit length).

We know the frequency of the lowest A on a piano is 27.5 Hz. We also know that one half wavelength occupies the string, so the length of the string is half the wavelength:

L = (1/2) * λ

The wavelength of a sound wave is given by:

λ = 2L/n

where n is the number of nodes (points of zero displacement) in the wave. For the lowest A on a piano, n = 1, so we can write:

λ = 2L

Substituting this into the equation above for L, we obtain:

L = λ/2

Now we can substitute these values into the first equation:

27.5 = (1/2)(λ/2) * sqrt(308/μ)

Simplifying, we get:

λ = 4L

308/μ = 4(27.5)^2 (1/4)

μ = 0.000824 kg/m.

Since μ = m/L, where m is the mass of the wire and L is its length, we can find the mass of the wire by multiplying the linear mass density by the length of the string:

m = μL

The length of the string is given as 2.00 m, so we can write:

m = 0.000824 kg/m * 2.00 m = 0.00165 kg

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Answer:

5.92×10⁷ J

Explanation:

We'll begin by converting 15 tons to Newton. This can be obtained as follow:

1 ton = 9806.65 N

Therefore,

15 ton = 15 ton × 9806.65 N / 1 ton

15 ton = 147099.75 N

Next, we shall convert one-quarter (¼) or 0.25 mile to metre. This can be obtained as follow:

100 mi = 160934 m

0.25 mi = 0.25 mi × 160934 / 100 mi

0.25 mi = 402.335 m

Finally, we shall determine the Workdone. This can be obtained as follow:

Force (F) = 147099.75 N

Distance (d) = 402.335 m

Workdone (Wd) =?

Wd = F × d

Wd = 147099.75 × 402.335

Wd = 5.92×10⁷ J

Thus, the Workdone is 5.92×10⁷ J

Here, we are required to determine which element has atoms with Valence electrons in a higher energy level than those of calcium.

The Valence electrons of the Caesium, Cs atoms has higher energy level than those of Calcium.

First, we need to determine the electronic configuration of each of the elements

Among the elements in the option, the Valence electrons of the Caesium, Cs atoms has higher energy level than those of Calcium.

This is so because the only Valence electron of Cs is located in the 6s orbital and as such has the highest energy level amongst all of the elements.

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Answer:

(Question 1) 5

(Question 2) They have valence electrons in the same energy level

(Question 3) Helium atoms have 2 valence electrons, while atoms of the other elements in the group all have 8 valence electrons

(Question 4) cesium (Cs)

(Question 5) There are two electrons in the first energy level and seven electrons in the second energy level

Explanation:

just finished the quick check, enjoy UwU

Given data

The mass of the board is mb = 4 kg

The mass of block A is mA = 30 kg

The mass of the block B is mB = 25 kg

The location distance of block A from the pivot point is d = 25 m

The location distance of block B from the pivot point at the right end is x.

The figure for the above configuration can be drawn as follows:

Taking the moment about the pivot point, the expression is written as follows:

Substitute the value in the above equation.

Thus, the distance at which it must be located in the right end from the pivot point is 30 m.

Answer:

Explanation:

Using Hook's law

                 \(F=-kx\)

Answer:

A stormy ocean, having the most kinetic energy means it moves more and faster

The answers are 4. The distance from where the ball was kicked is 38.06 meters, 5. The speed of the ball 2.5 seconds after it was kicked is 13.82 m/s, and  6. The ball is 21.88 meters above the ground 2.5 seconds after it is kicked.

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Answer: time = 1.42 seconds

Explanation:

The formula for calculating time is expressed as

time = distance/speed

From the information given,

distance of person from cliff = 245

total distance travelled by echo in returning = 245 x 2 = 490

speed of sound = 344 m/s

Thus,

time = 490/344

time = 1.42 seconds

Answer:

Explanation:

(a) Q=ap^n

Function of p and q:

p = q^(1/n)

(b) Q^m=ap^n

Function of p and q:

p = (q^(1/m))^(1/n)

Answer:

As we can see, a string is attached with block A, and three string is folded with ply which is attached with B

x  

B

​  

=3x  

A

​  

Now differentiate with respect to x

V  

B

​  

=3V  

A

​  

Given,

V  

A

​  

=0.6m/s(totheright)

So,

V  

B

​  

=0.6×3

=1.8m/s(downward)

​

Explanation:

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The potential energy of the system is 8.73 x Joules.

To calculate the potential energy of the system, we need to use the formula:

U = k(q1q2/r12 + q1q3/r13 + q2*q3/r23)

where U is the potential energy of the system, k is Coulomb's constant (9x\(10^{9}\) N\(m^{2}\)/\(C^{2}\)), q1, q2, and q3 are the charges of the particles (in Coulombs), and r12, r13, and r23 are the distances between the particles.

Since the charges are all the same and the triangle is equilateral, the distances between the particles are all the same and can be calculated using the Pythagorean theorem:

r12 = r13 = r23 = √(\(90^{2}\) + \((90/√3)^{2}\)) = 103.92 cm

Substituting the values into the formula, we get:

U = (9x\(10^{9}\) N\(m^{2}\)/\(C^{2}\)) x \((0.0000003 C)^{2}\) x [1/103.92 cm + 1/103.92 cm + 1/103.92 cm]

U = 8.73 x \(10^{-12}\)J

Therefore, the potential energy of the system is 8.73 x \(10^{-12}\) Joules.

This calculation shows that even small charges can have a significant effect on the potential energy of a system, especially when the distances between the charges are small. Additionally, the equilateral configuration of the charges results in equal distances between them, making the calculation simpler. The potential energy of a system of charges is an important concept in electrostatics and can be used to analyze and predict the behavior of electrically charged systems.

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Answer:

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Question

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In the circuit shown in Figure, initially K

1

is closed and K

2

is open. What are the charges on each capacitor. Then K

1

was opened and K

2

was closed (order is important), What will be the charge on each capacitor now? [C=1μF]

1796057

expand

Medium

Solution

verified

Verified by Toppr

When K

2

is open and K

1

is closed the capacitors C

1

and C

2

will charge and potential develops across them i.e., V

1

and V

2

respectively which will be equal to the potential of battery 9V

∴V

1

+V

2

=9……..I

∵V=

C

q

=orVα

C

1

Or

V

2

V

1

=

C

1

C

2

V

2

V

1

=

6C

3C

3V

2

=6V

1

V

2

=2V

1

…II

From Eqns. I and II

V

1

+2V

1

=9

3V

1

=9

V

1

=3

Volt

V

2

=2×3Volt=6Volt

∴q

1

=C

1

V

1

=6C×3=18C[(from II C=1μF)

=18×1μF=18μc

q

2

=C

2

V

2

=3C×6

=3×1μF×6=18μC

So, charges on each capacitor i.e., q

1

=q

2

=18μc

When k

1

is open and k

2

is closed then charge q

2

will be distributed among

C

2

and C

3

. Let it be q

2

and q

3

∴q

2

=q

2

+q

3

As C

2

and C

3

are now in parallel combination so their potentials

remain same (V)

∴q

2

=C

2

V+C

3

V

18μC=3×1μFxV+3×1μF×V

18=6V

V=3Volt

So potential on C

2

and C

3

capacitors are 3 Volt each

q

2

′

=C

2

V−3×1μF×3Volt=9μC

q

3

=C

3

V=3×1μF×3Volt=9μC

Answer:

15 seconds

Explanation:

Given that the initial speed of a cannon ball is 0.20 km/s. If the ball is to strike a target that is at a horizontal distance of 3.0 km from the cannon. The minimum time of flight for the ball can be calculated by using the formula for speed

speed = distance / time

Where

speed = 0.2 km/s

distance = 3 km

Substitute the two parameters into the formula

0.2 = 3 / t

make t the subject of the formula

t = 3/0.2

t = 15 s

Therefore, the minimum time of flight for the ball is 15 seconds

4.44×\(10^{9}\) kg/s is the rate at which the sun mass is decreasing.

The Sun radiates energy through a process called nuclear fusion, where hydrogen atoms combine to form helium, releasing a tremendous amount of energy in the process. According to Einstein's mass-energy equivalence principle (E=mc²), this energy release corresponds to a decrease in mass.

To calculate the rate at which the Sun's mass is decreasing, we can use the formula ΔE = Δmc², where ΔE is the change in energy, Δm is the change in mass, and c is the speed of light.

Given that the Sun radiates energy at a rate of 4×10^26 W, we can substitute this value into the equation as ΔE and solve for Δm.

ΔE = 4×10^26 W

c = 3×10^8 m/s (speed of light)

Using the equation ΔE = Δmc² and rearranging it, we get Δm = ΔE / c².

Substituting the values, we have:

Δm = (4×10^26 W) / (3×10^8 m/s)²

Evaluating this expression, we find that the rate at which the Sun's mass is decreasing is approximately 4.44×10^9 kg/s.

This calculation demonstrates that the Sun's mass is gradually decreasing as it continuously radiates energy into space, primarily through the process of nuclear fusion in its core.

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Answer:

5.25 J

Explanation:

W = PE = (f)(x)

PE = 35N*0.15m

PE = 5.25 N*m

1 N*m = 1 J

PE = 5.25 J

Answer:

by counting each individual atom and making sure the number of each kind of atom is the same in the reactants and the products. - This is the answer.

Explanation:

Answer:

its A(by counting each individual atom and making sure the number of each kind of atom is the same in the reactants and the products

Explanation:

Answer:

the intensity of the light after passing through the two polarizing filters is 4.11 units  

Explanation:

Given the data in the question;

the intensity of an unpolarized light; I₀ = 25.0 units

when the unpolarized light passes through the first polarizer, its intensity reduces to half of its initial value;

⇒ I₁ = I₀/2 = 25/2 = 12.5 units

the angle between the transmission axes of two polarizers is;

∅ = 55° - 0° = 55°

The intensity of the light after passing through two polarizing filters will be;

I₂ = I₁cos²∅      

we substitute

I₂ = 12.5 × cos²(55)

I₂ = 12.5 × 0.3289899

I₂ = 4.11 units

Therefore, the intensity of the light after passing through the two polarizing filters is 4.11 units

Electronegativity is a tendency of a atom/element to attract the pair of electrons.

electronegativity order = O>B>Ga

electronegativity order = Mg>Ba>Ca

electronegativity order =P>Ga>Al

electronegativity order =O>C>Al

When an atom of a certain chemical element forms a chemical bond, it has a propensity to draw shared electrons (or electron density). The atomic number and the separation of the valence electrons from the charged nucleus have an impact on an atom's electronegativity. An atom or a substituent group will draw electrons in greater amounts the higher the associated electronegativity. The sign and amplitude of a bond's chemical polarity, which characterizes a bond along the continuous scale from covalent to ionic bonding, can be quantitatively estimated using electronegativity. The inverse of electronegativity is electropositivity, which describes an element's propensity to accept valence electrons.

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The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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