This problem involves the same compound that was examined in Problems 6-14 through 6-17, which in the vapor phase was described by the EOS:
with a = 0.3 × 10−16 m3/mol Pa2 K.
This compound has vapor pressures of Psat = 5 50 kPa at T = 323 K and P = 500 kPa at T = 373 K. Saturated liquid at both T = 323 K and T = 373 K has V ≈ 1.25 × 10−4 m3/mol. Estimate each of the following.
A. The fugacity in the vapor phase at T = 323 K and P = 10 kPa.
B. The fugacity in the liquid phase at T =323 K and P = 10 MPa.
C. The fugacity in the vapor phase at T = 373 K and P = 300 kPa.
D. The fugacity in the liquid phase at T = 373 K and P = 10 MPa.
Answer:
A. The fugacity in the vapor phase at T = 323 K and P = 10 kPa:
Explanation:
A mercury thermometer is constructed as
shown. The capillary tube has a diameter
of 0.0059 cm, and the bulb has a diameter of
0.32 cm. Neglecting the expansion of the glass, find
the change in height of the mercury column
for a temperature change of 36 ◦C. The
volume expansion coefficient for mercury is
0.000182 (◦C)−1
.
Answer in units of
The change in the height of the mercury thermometer column for a temperature change of 36 \(^oC\) would be 1.86 cm.
Change in height in a mercury thermometerTo solve this problem, we can use the formula for the change in height of the mercury column in a thermometer:
Δh = V/(πr²)
where Δh is the change in height of the mercury column, V is the change in volume of the mercury, r is the radius of the capillary tube, and π is the mathematical constant pi.
The change in volume of the mercury can be found using the formula:
ΔV = V₀βΔT
where V₀ is the initial volume of the mercury, β is the volume expansion coefficient for mercury, and ΔT is the temperature change.
The initial volume of the mercury in the thermometer can be approximated as the volume of a cylinder with height equal to the length of the capillary tube and radius equal to the radius of the bulb. Therefore:
V₀ = πr₀²h
where r₀ is the radius of the bulb and h is the length of the capillary tube.
Substituting these values and solving for Δh, we get:
ΔV = V₀βΔT = πr₀²hβΔT
Δh = ΔV/(πr²) = (πr₀²hβΔT)/(πr²)
Δh = (r₀²/r²)hβΔT
Plugging in the values given in the problem, we get:
r₀ = 0.16 cm (radius of the bulb)r = 0.00295 cm (radius of the capillary tube)h = 10 cm (length of the capillary tube)β = 0.000182 (◦C)⁻¹ (volume expansion coefficient for mercury)ΔT = 36 ◦C (temperature change)Therefore:
Δh = (0.16²/0.00295²) × 10 × 0.000182 × 36
= 1.86 cm
So the change in the height of the mercury column for a temperature change of 36 ◦C is approximately 1.86 cm.
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Answer:
he change in height of the mercury column for a temperature change of 36°C will be 2.981 cm.
What is thermal expansion?
Thermal expansion iis the tendency of matter to alter its form, area, volume, and density in response to a change in temperature.
The given data in the problem is;
d is the diameter of capillary tube = 0.0045 cm
D is the diameter of an bulb=0.24 cm.
h is the change in height of the mercury column=?
h is the temperature change = 36 ◦C.
is the volume expansion =0.000182 (◦C)⁻¹
The formula for the thermal expansion is given as;
The initial volume of the mercury in the spherical bulb will be;
The change in the volume will be;
Now, we can use this difference in volume, to estimate the height of the cylinder of mercury with diameter 0.0045 cm (radius r= 0.00225 cm.
Hence the change in height of the mercury column for a temperature change of 36°C will be 2.981 cm.
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Explanation:
A piece of wood 350 mm × 350 mm and 15 mm thick conducts heat through its thickness under steady state conditions. The rate of heat flow is measured to be 14.0 watts when the temperature difference is 28 C°. Determine the coefficient of thermal conductivity for this wood
The coefficient of thermal conductivity (k) is related to the rate of heat flow (Q), the cross-sectional area (A), the length (L), the temperature difference (ΔT), and the thermal resistance (Rth) by the following equation:
k = Q / (A * ΔT * L) = Rth * (A * ΔT)
Reorganizing this equation gives:
Rth = k / (A * ΔT)
The given information in the problem is:
Rate of heat flow (Q) = 14.0 watts
Thermal resistance (Rth) = (350 mm × 350 mm × 15 mm) / (14.0 watts) = 31.5 mm⁴/C
Temperature difference (ΔT) = 28°C
Substituting these values into the equation, we have:
k = Q / (A * ΔT) = 14.0 W / (0.35 m² * 28°C) = 1.94 W/mK
So the coefficient of thermal conductivity (k) for this wood is approximately 1.94 W/mK.
Which would not describe a physical property of
a substance?
how it reacts with another substance
B how shiny it is
C what color it is
D its mass
Answer:
Explanation:
Out of the given options, A would not describe a physical property of a substance. How a substance reacts with another substance is a chemical property, whereas physical properties are intrinsic characteristics that can be observed or measured without changing the substance's identity. B, C, and D are examples of physical properties - shininess, color, and mass respectively.
Use the work-energy theorem to find the force required to accelerate an electron (m
9.11 x 10-31 kg) moving along the x axis from 3.50 x 106 m/s to 1.55 x 107 m/s in a
distance of 0.0135m.
The force of Earths gravity keeps earth in orbit true or false
Answer:
True
Explanation:
The force of gravity keeps all of the planets in orbit around the sun
True. The force of gravity keeps all of the planets in orbit around the sun.
What is Gravity?
The force that pulls items toward the center of a planet or other entity is called gravity. All of the planets are kept in orbit around the sun by gravity.
Gravity applies to everything that has mass. Gravity is stronger for objects with higher mass. Along with distance, gravity weakens as well. Therefore, the gravitational pull of two things becomes stronger the closer they are to one another.
The mass of the Earth is what creates gravity. The combined gravitational force of all of its mass acts on the mass in your body.
Therefore, True. The force of gravity keeps all of the planets in orbit around the sun.
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19. Assume this process is 10% efficient, how much work is done by the gas expanding into the atmosphere?
The amount of work done by the gas is proportional to the pressure and the change in volume, as well as the efficiency of the process. If the pressure and volume are known, the work done by the gas can be calculated by multiplying these values by the efficiency of the process.
The amount of work done by a gas when it expands is proportional to the change in volume, pressure, and temperature. According to the first law of thermodynamics, the energy of a closed system is conserved, so the work done by the expanding gas is equal to the energy transferred from the gas to the environment in the form of work. Therefore, the work done by the gas is equal to the change in energy of the system. Assume that the process is 10% efficient. Then, only 10% of the energy available to the system is converted into work. This means that the remaining 90% of the energy is lost to the environment in the form of heat. As a result, the amount of work done by the gas expanding into the atmosphere is given by the formula
W = E x η, where W is the work done by the gas, E is the energy available to the system, and η is the efficiency of the process. The energy available to the system is determined by the difference between the internal energy of the gas before and after the expansion. The internal energy of a gas is determined by its temperature, pressure, and volume.
Assuming that the temperature and pressure are constant, the change in internal energy is proportional to the change in volume. Therefore, the energy available to the system is equal to the product of the pressure and the change in volume: E = P x ΔV, where P is the pressure of the gas and ΔV is the change in volume during the expansion. Substituting this equation into the formula for work, we get W = P x ΔV x η.
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A moving car initially has kinetic energy K. The car then moves in the opposite direction with four times its initial speed. What is the kinetic energy now
If initial speed was v, Kinetic energy was K = 1/2mv^2
When speed will be 4v, KE will be:
= 1/2 m (4v)^2
=1/2m 16 v^2
=16K
Now kinetic energy will become 16 times of initial Kinetic Energy
WHAT IS THE MEAING OF- Grouping Data
Grouping data refers to the process of categorizing or organizing data based on specific criteria or attributes.
It involves grouping similar data points together to gain a better understanding of patterns, relationships, and trends within the dataset. By grouping data, you can simplify complex information and derive meaningful insights from large amounts of data. The purpose of grouping data is to create subsets or clusters that share common characteristics.
This enables easier analysis, summarization, and comparison of data within each group. Grouping can be performed on various types of data, such as numerical, categorical, or time-based data. Grouping data allows for the exploration of data at different levels of granularity.
For example, you can group sales data by region to analyze regional performance, or group customer data by demographics to identify specific customer segments. This process helps in identifying outliers, detecting patterns, and making data-driven decisions.
Common techniques for grouping data include using functions like GROUP BY in SQL or utilizing data visualization tools to create charts or graphs that illustrate the grouped data. Grouping can be applied in various fields, such as marketing, finance, healthcare, and research, to uncover insights and support decision-making processes.
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A certain satellite travels in an approximately circular orbit of radius 8.8 × 10^6 m with a period of 6 h 12 min. Calculate the mass of its planet from this information.
The mass of the planet is 5.98 × 10^24 kg.
To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.
First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.
Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.
Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.
Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2
Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2
Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.
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The radius of the circular path of an ion in a mass spectrometer is given by r=1/B √2Vaccelm/q. Use this equation to explain how a mass spectrometer is able to separate ions of different masses.
The mass spectrometer separates ions of different masses by utilizing the relationship between the strength of the magnetic field, the accelerating voltage, the charge-to-mass ratio of the ions, and the resulting radius of the circular path
What is the mass spectrometer?From the formula in the question;
B is a symbol for the magnetic field's intensity as it is applied to the mass spectrometer.
The accelerating voltage used to move the ions is called Vaccelm.
The charge of the ion, specifically its charge-to-mass ratio (q/m), is represented by the letter q.
The mass spectrometer may selectively alter the radius of the circular route for various ions by varying the magnetic field's intensity (B). This makes it possible to spatially segregate ions with various masses based on their various radii. The ions' locations and masses can then be measured using detectors placed along the journey.
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A rocket is launched straight up with constant acceleration. Five seconds after liftoff, a bolt falls off the side of the rocket. The bolt hits the ground 10.0 s later. What was the rocket's acceleration?
Explanation:
To find the acceleration of the rocket, we need to use the equations of motion for constant acceleration.
We know that the bolt was dropped 5 seconds after the rocket was launched, and that it took 10 seconds for the bolt to hit the ground. This means that the bolt was in free fall for 10 - 5 = <<10-5=5>>5 seconds.
We can use the equation d = 1/2 * a * t^2 to find the acceleration of the bolt. We know that the bolt fell a distance of 10 meters in 5 seconds, so we can plug those values into the equation to get: 10 = 1/2 * a * 5^2. Solving for a gives us a = 2 * 10 / 5^2 = 2 * 10 / 25 = 0.8.
Since the bolt was in free fall, its acceleration was due to gravity, which is about 9.8 meters per second squared. This means that the rocket must have had an acceleration greater than 9.8 meters per second squared in order to cause the bolt to fall off of it.
Therefore, the rocket's acceleration must have been greater than 0.8 meters per second squared. However, we cannot say exactly what the acceleration was without knowing more information about the rocket and its launch conditions.
The acceleration of the rocket is 197.5 m/s² if the bolt hits the ground 10.0 s later.
What is Kinematics ?A branch of physics called kinematics, which was evolved from classical mechanics, defines how points, bodies, and systems of bodies (groups of objects) move without taking into account the forces that propel them. The discipline of kinematics is sometimes thought of as a subfield of mathematics and is sometimes referred to as the "geometry of motion." Any known values of the location, velocity, and/or acceleration of points inside the system are declared as initial conditions for a kinematics issue, together with the geometry of the system. The location, velocity, and acceleration of any unidentified system components can then be calculated using geometrical considerations. Kinematics, not kinematics, is the study of forces and their effects on physical objects. For further information, visit.
Given,
time of the bolt = 10-5 =5s
acceleration due to gravity =9.8m/s²
The height of the bolt s = ut+1/2at²
s = 0+ 1/2 ×9.8×5²
s = 122.5m
We cannot find the acceleration of the rocket without its final velocity (velocity of the rocket at the time of fall of bolt). Therefore Consider the final velocity of the Rocket is 220m/s
Then,
v² = u² + 2as
220² = 0 +2×a×122.5
48400 = 245 a
a = 197.5 m/s²
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A hot air balloon is rising upward with a constant speed of 3.80m/s. When the balloon is 4.25m above the ground, the balloonist accidentally drops a compass over the side of the balloon. How much time elapses before the compass hits the ground
We can calculate the time taken by the compass to hit the ground by using kinematic equations of motion. The motion of the compass is a free-fall motion since it is only under the influence of gravity. When the compass is dropped, it is initially at rest.
After that, it falls down to the ground with the acceleration due to gravity. Given that the balloon is rising upward with a constant speed of 3.80m/s. Hence, the velocity of the compass when it is dropped will be equal to the velocity of the balloon, which is 3.80m/s. The acceleration due to gravity is 9.81m/s². We can use the following kinematic equation of motion to calculate the time taken by the compass to hit the ground: `y = vi * t + 0.5 * a * t²`, where `y` is the height, `vi` is the initial velocity, `a` is the acceleration, and `t` is the time taken.We know that the initial height of the compass is 4.25m, the initial velocity is 3.80m/s, and the acceleration due to gravity is 9.81m/s². We need to find the time taken by the compass to hit the ground. Using the above kinematic equation, we get:`0 = 3.80t + 0.5 * 9.81 * t²`Simplifying the equation, we get:`4.905t² + 3.80t = 0`Factorizing the equation, we get:`t(4.905t + 3.80) = 0`Solving for `t`, we get:`t = 0` (since time cannot be negative)`t = -3.80/4.905 = -0.776s`We ignore the negative value of time since time cannot be negative. Hence, the time taken by the compass to hit the ground is `t = 0.776s`.Answer: `0.776s`For such more question on acceleration
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How are magnetic fields like vectors?
Answer:Magnetic fields from two sources add up as vectors at each point, so the strength of the field is not necessarily the sum of the strengths1. Magnetic fields are vectors, which means they have direction as well as size. Therefore, the sum of two magnetic fields is not simply the sum of their magnitudes2.
Explanation:
You decide to go skiing but fall over. As you are attempting to get back up, you see a child start to head down the hill straight for you. If the coefficient of friction between the child and the snow is assumed to be 0, and the child appears to be 20 m above you when they start down the mountain, and the incline of the mountain is 31 degrees, how long do you have to get up and out of the way before you and the child collide?
The time taken to get up and out of the way before you and the child collide is 2.82 s.
What is the time taken to get up?The time taken to get up and out of the way before you and the child collide is calculated as follows;
s = v + ¹/₂at²
s = v + ¹/₂(g sin (31)t²
where;
v is the initial velocitys is the displacementt is the time of motionThe time taken to get up is calculated as;
20 = 0 + ¹/₂(9.8 sin (31)t²
20 = 2.524t²
t² = 20/2.524
t² = 7.925
t = 2.82 s
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Remember: Weight (newtons) = mass* gravity and 1 kg = 2.2 pounds. 14. A typical NFL lineman weighs around 314 pounds. Calculate the weight in Newtons.
1,401.88 N is the required weight of the man using the given conversion factor.
Determining the weight of an objectTo calculate the weight of a typical NFL lineman in Newtons, we need to first convert the weight from pounds to kilograms using the conversion factor of 1 kg = 2.2 pounds:
314 pounds ÷ 2.2 pounds/kg = 142.73 kg
Next, we can use the formula Weight (newtons) = mass * gravity, where gravity is approximately 9.81 m/s^2 (meters per second squared):
Weight (newtons) = 142.73 kg * 9.81 m/s^2 = 1,401.88 N
The required weight in Newton of the man is 1,401.88 N
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In Figure below, m₁=2.00kg and m₂-4.00kg. Consider the pulley to be frictionless. (a) If m₂ is released, what will its acceleration be? (b) What is the tension in the string? m₂ 55 m₂
(a) When m₂ is released, its acceleration will be approximately -3.27 m/s².
(b) The tension in the string is approximately -13.08 N.
To determine the acceleration of m₂ when it is released and the tension in the string, we need to consider the forces acting on the system.
(a) Acceleration of m₂:
Since the pulley is assumed to be frictionless, the tension in the string is the same on both sides of the pulley. We can consider the system consisting of m₁ and m₂ as one body. The net force acting on this system is the difference between the weight of m₁ and the weight of m₂:
Net force = m₁g - m₂g
Applying Newton's second law, F = ma, where F is the net force and a is the acceleration, we have:
m₁g - m₂g = (m₁ + m₂)a
Rearranging the equation to solve for the acceleration, we get:
a = (m₁g - m₂g) / (m₁ + m₂)
Substituting the given values, m₁ = 2.00 kg and m₂ = 4.00 kg, and the acceleration due to gravity, g = 9.8 m/s², we can calculate the acceleration:
a = ((2.00 kg)(9.8 m/s²) - (4.00 kg)(9.8 m/s²)) / (2.00 kg + 4.00 kg)
a = (19.6 N - 39.2 N) / 6.00 kg
a = -19.6 N / 6.00 kg
a = -3.27 m/s²
Therefore, when m₂ is released, its acceleration will be approximately -3.27 m/s². The negative sign indicates that the acceleration is in the opposite direction of the gravitational force.
(b) Tension in the string:
The tension in the string can be determined by considering the forces acting on m₂. The net force on m₂ is equal to its mass multiplied by its acceleration:
Net force = m₂a
Substituting the given values, m₂ = 4.00 kg and a = -3.27 m/s², we can calculate the tension:
Tension = (4.00 kg)(-3.27 m/s²)
Tension = -13.08 N
Therefore, the tension in the string is approximately -13.08 N. The negative sign indicates that the tension acts in the opposite direction of the weight of m₂.
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A helicopter is ascending vertically with a speed of 5.10m/s. At a height of 105 m above the Earth, a package is dropped from a window. How much time does it take for the package to reach the ground?
Answer:
The time taken for the package to reach the ground is 20.6s
Explanation:
Given that the formula of distance is D = S×T where S represents soeed and T is time. So you have to substitute the following values into the formula :
\(distance = speed \times time\)
\(let \: distance = 105 \\ let \: speed = 5.10\)
\(105 = 5.1 \times t\)
\(5.1t = 105\)
\(t = 105 \div 5.1\)
\(t = 20.6 \: second \: (3s.f)\)
A 2.5 kg sledge hammer hit a cement block with a force of 6.0 Newtons.
How does the force the sledge hammer exerted on the cement block compare with the force the cement block exerted on the sledge hammer?
Responses
The force the sledge hammer exerted on the cement block is less in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.
The force the sledge hammer exerted on the cement block is less in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.
The force the sledge hammer exerted on the cement block is equal in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.
The force the sledge hammer exerted on the cement block is equal in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.
The force the sledge hammer exerted on the cement block is greater in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.
The force the sledge hammer exerted on the cement block is greater in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.
HURRY HURRY HURRY !!!The force the sledge hammer exerted on the cement block is equal in magnitude and in the same direction as the force the cement block exerted on the sledge hammer.
The force the sledge hammer exerted on the cement block is equal in magnitude and in the same direction as the force the cement block exerted on the sledge hammer.
When a 2.5 kg sledgehammer hit a cement block with a force of 6.0 Newtons. The force the sledgehammer exerted on the cement block is greater in magnitude and opposite in direction to the force the cement block exerted on the sledgehammer.
What are opposite forces?This refers to forces that act on an object in opposite directions. The net force is gotten by solving for the difference between the two forces.
When the opposing forces are equal or balanced, the net force is zero. The sledgehammer hits with a force and the cement block is receiving the impart as a stationary object.
Obviously, the force the sledgehammer exerted on the cement block is greater in magnitude and opposite in direction to the force the cement block exerted on the sledgehammer.
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What is the potential energy of a 7kg object 4m off the ground ?
please show your work
Answer:
Gravitational potential energy is mass of the object times the gravitational constant times the height of the object:
U = mgh (I will use 10 for the gravitational constant but you can use 9.8 or 9.81 or something even more accurate)
U = 280
The gravitational potential of the object is 280 joules
The largest stars we know of have masses of a little over 1035 kilograms, while the lowest mass stars have masses of about 1032 kilograms. How many times more massive are the most massive stars than the lowest mass stars?
Group of answer choices
a thousand times more massive.
a hundred times more massive.
ten times more massive.
ten thousand times more massive
Answer:
the bigger stars tend to be hotter and burn through their fuel more quickly than smaller stars they also tend to ether be turned into a black hole or a huge nebula with a neutron star the smaller stars have a tendency to go through their fuel slower and don't get as hot as big stars until the red giant stage.
Explanation:
-0,32 m - 4.2 At the instant the marble leaves the canon, the canon starts moving backwards (recoils) at a constant velocity. 4.1 State the principle of conservation of linear momentum in words. that is stationary canon is placed 0,32 m from a fixed bare After firing, the canon takes 0,33 s to collide with a barrier at a distance of 0,32 m. Calculate the speed the: W< 1 >E S 4.2.1 Canon collides with the barrier
The cannon will completely stop when it collides with the barrier.
To calculate the speed at which the cannon collides with the barrier, we can follow these step-by-step calculations:
Determine the initial momentum of the system.
Since the cannon is initially stationary, the initial momentum is zero.
Apply the conservation of linear momentum.
According to the principle of conservation of linear momentum, the initial momentum of the system (zero) is equal to the final momentum of the system. The final momentum is the momentum of the cannon after firing.
Calculate the final momentum of the system.
Let's assume the mass of the cannon is represented by 'm' and the final velocity of the cannon is represented by 'v'. The final momentum of the system is given by: final momentum = m × v.
Set up the equation.
Since the initial momentum is zero, we have: 0 = m × v.
Solve for the final velocity of the cannon.
Dividing both sides of the equation by 'm', we get: v = 0.
Interpret the result.
The calculation shows that the final velocity of the cannon is zero. This means that the cannon comes to a complete stop when it collides with the barrier.
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what evidence supports the information consolidation theory?
PLEASE HELP ME ITS DUE NEXT PERIOD
Explanation:
Memory loss in retrograde amnesia has long been held to be larger for recent periods than for remote periods, a pattern usually referred to as the Ribot gradient. One explanation for this gradient is consolidation of long-term memories. Several computational models of such a process have shown how consolidation can explain characteristics of amnesia, but they have not elucidated how consolidation must be envisaged. Here findings are reviewed that shed light on how consolidation may be implemented in the brain. Moreover, consolidation is contrasted with alternative theories of the Ribot gradient. Consolidation theory, multiple trace theory, and semantization can all handle some findings well but not others.
A block of cheese is pulled on by a string and slides to the right along a rough surface.
What is the correct free body diagram for the block of cheese?
Answer:
Explanation:
KHAN ACADEMY
The free body diagram of the cheese block is attached with the answer.
What is free body diagram?A free body diagram consists of a diagrammatic representation of a single body or a subsystem of bodies isolated from its surroundings showing all the forces acting on it.
Given is a block of cheese is pulled on by a string and slides to the right along a rough surface.
The free body diagram of the cheese block is given with the image attached. The force applied for the forward motion of the block is greater in magnitude than the frictional force. The weight of the block is balanced by the normal reaction force. The following mathematical relations can be written -
F - F(f) = ma
and
mg = N
m = N/g
So -
F - F(f) = (N/g)a
Therefore, the free body diagram of the cheese block is attached with the answer.
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A spring has a relaxed length of 7 cm and a stiffness of 200 N/m. How much work must you do to change its length from 10 cm to 15 cm
The work W needed to stretch/compress a spring from rest by a distance x is
W = 1/2 kx²
where k is the spring constant.
This means the work needed to change the length of this spring by 10 cm = 0.01 m is
W = 1/2 (200 N/m) (0.01 m)² = 0.01 J
and by 15 cm = 0.015 m is
W' = 1/2 (200 N/m) (0.015 m)² = 0.0225 J
Then the total work performed on the spring by stretching from 10 cm to 15 cm is
∆W = W' - W = 0.0225 J - 0.01 J = 0.0125 J
what is the difference between each distance traveled and displacement travled
Displacement is a vector magnitude that depends on the position of the body which is individualistic for the trajectory.
While, Distance is a scalar magnitude that measures over the trajectory.
What is downward force
Answer:
The gravitational force, or gravity, is the downward force that causes objects to fall towards the surface of a planet or natural satellite. It is computed by multiplying the mass of an object with the acceleration due to gravity of the planet or natural satellite.
A cannon sits on top of a cliff that is 20 meters above an area of level ground. It fires a 5 kg cannonball horizontally (cannonball A) at 5 meters/second. At the same time, a second cannonball (cannonball B) is dropped from the same height. If air resistance is ignored, which cannonball will hit the ground first?
Note: The gravitational acceleration due to the Earth is 9.8 m/sec².
A. Cannonball A
B. Cannonball B
C. Both will hit the ground at the same time.
D. It can not be found from the given information.
Answer:
d
Explanation:
How many atoms of each element are in 4Na3PO4?
A.) 3 sodium, 1 phosphorus, 4 oxygen
B.) 4 sodium, 4 phosphorus, 4 oxygen
C.) 12 sodium, 1 phosphorus, 4 oxygen
D.) 12 sodium, 4 phosphorus, 16 oxygen
Answer:
D) 12 sodium, 4 phosphorus. 16 oxygen
Explanation:
there is a four in front of the full formula, so you multiply all of the sub numbers by 4
rank in terms of momentum
A. A 10,000 kg train car at rest
B. A 100 kg person running at 5 m/s
C. A 1200 kg car going 15 m/s
D. A 15 kg meteor going at a speed of 1000 m/s
Answer:
See the explanation below,
Explanation:
Momentum is defined as the product of mass by Velocity. In this way, we will replace the following equation in each of the cases.
\(P=m*v\)
where:
P = momentum [kg*m/s]
m = mass [kg]
v = velocity [m/s]
A)
\(P = 10000*0\\P=0\)
B)
\(P=100*5\\P=500[kg*m/s]\)
C)
\(P=1200*15\\P=18000[kg*m/s]\)
D)
\(P=15*1000\\P=15000[kg*m/s]\)
From higher to lower momentum
C,D,B,A