7) The intersection of any two intervals is an interval. a) True b) False c) Not enough information. 8) The empty set ∅ is an interval in R. a) True b) False c) Not enough information. 9) The Well Ordering Property states that every nonempty subset of N has a least element. a) True b) False c) Not enough information.

Answer:

Coastal plain

Step-by-step explanation:

Answer:

Below

Step-by-step explanation:

 b2 = 3 * b1    <===given

Area of a trapezoid =    (b1 + b2)/2    *   height      b1 and b2 are the bases

     32         =   (b1 + 3 b1)  / 2    *  4

               32 = 4b1 /2 * 4

                  32 = 8 b1

                   4 = b1    then b2 = three times this = 12 ft

Answer:

3.7r -7

Step-by-step explanation:

Basically you would subtract 6.4 and 2.9 because there is a negative sign and they have the same variable. Then you would put it (2.9r)first since it is in order and you can't combine 7 and 2.9r so you leave it like that.

If a sample size is one-fourth the original size, the margin of error will be affected. Specifically, the margin of error will be affected inversely proportional to the square root of the sample size.

Halving the sample size (from the original) will cause the margin of error to increase by a factor of square root of 2, approximately 1.41.

Doubling the sample size (from the original) will cause the margin of error to decrease by a factor of square root of 2, approximately 0.71.

Quadrupling the sample size (from the original) will cause the margin of error to decrease by a factor of square root of 4, approximately 0.5.

Therefore, if the sample size is reduced to one-fourth the original size, the margin of error will be doubled, because the square root of 4 is 2. Conversely, if the sample size is increased fourfold, the margin of error will be halved, because the square root of 1/4 is 1/2.

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Answer:

180 kg

Step-by-step explanation:

The ratio is

cement : sand : gravel

    1       :    3     :    4

If he used 1 kg cement, 3 kg sand, and 4 kg gravel, he'd get 8 kg of concrete.

He wants to make 480 kg of concrete.

480/8 = 60

He needs 60 times more concrete than the numbers in the ratio.

60 * 3 kg = 180 kg

Answer: 180 kg

Answer:

If sand is 3 in the ratio, it is 180kg

Step-by-step explanation:

480/8=60  60 times 3 is 180

Answer:

50.27 cm

Step-by-step explanation:

We Know

The area of the circle = r² · π

Area of circle = 64π cm²

r² · π = 64π

r² = 64

r = 8 cm

Circumference of circle = 2 · r · π

We Take

2 · 8 · (3.1415926) ≈ 50.27 cm

So, the circumference of the circle is 50.27 cm.

Answer: C=16π cm or 50.24 cm

Step-by-step explanation:

The formula for area and circumference are similar with slight differences.

\(C=2\pi r\)

\(A=\pi r^2\)

Notice that circumference and area both have \(\pi\) and radius.

\(64\pi=\pi r^2\)        [divide both sides by \(\pi\)]

\(64=r^2\)             [square root both sides]

\(r=8\)

Now that we have radius, we can plug that into the circumference formula to find the circumference.

\(C=2\pi r\)          [plug in radius]

\(C=2\pi 8\)          [combine like terms]

\(C=16\pi\)

The circumference Is C=16π cm. We can round π to 3.14.

The other way to write the answer is 50.24 cm.

Answer:

7.6032,7.63,7.6

Sorry if I am wrong.

Step-by-step explanation:

(a) The range of c₁ (the objective coefficient of x₁) for which this BFS remains optimal is c₁ ≤ 2.

(b) The range of b₂ (the right-hand side of the second constraint) for which this BFS remains optimal is 3 ≤ b₂ < 4.

(c) The dual price of the second constraint is 0.

(a) The optimality condition for a linear programming problem requires that the objective coefficient of a non-basic variable (here, x₁) should not increase beyond the dual price of the corresponding constraint. In this case, the dual price of the second constraint is 0, indicating that increasing the coefficient of x₁ will not affect the optimality of the basic feasible solution. Therefore, the range of c₁ for which the BFS remains optimal is c₁ ≤ 2.

(b) The range of b₂ for which the BFS remains optimal is determined by the allowable range of the corresponding dual variable. In this case, the dual price of the second constraint is 0, implying that the dual variable associated with that constraint can vary within any range. As long as 3 ≤ b₂ < 4, the dual variable remains within its allowable range, and thus, the BFS remains optimal.

(c) The dual price of a constraint represents the rate of change in the objective function value per unit change in the right-hand side of the constraint, while keeping all other variables fixed. In this case, the dual price of the second constraint is 0, indicating that the objective function value does not change with variations in the right-hand side of that constraint.

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Answer:

Num. 2: A = 25, Num. 3 = 63, Num. 4 = 80

Step-by-step explanation:

I'll help with as many as I can, so a few of them I won't be able too answer. You should re-post those later. Good luck, hope this helps.

For number 2:

First, turn the triangle into a rectangle by cutting it in half and attaching it to the other half so it forms a rectangle.

Since you cut the triangle in half, you also have to split 5 in half, so the bottom length is now 2.5.

Now, simply multiply 2.5 by 10, and you have the area for number 2.

The area for number 2 is 25.

For number 3:

This one is much easier. Just think of the shape as a normal square that has been tipped to the side. That means that you would solve for area the same way: 9 x 7, which means that the area for number 3 is 63.

For number 4:

This one is also easy. Simply cut, and paste. Now the right side is 10, and the top side is 8. Multiply, and the area will be 80 m.

Please re-post 1 and 5, as I am not able to solve them. Sorry this answer took so long!

Given statement solution is :- a) Power set for two sets A and B with any 2 elements:

Set A: {1, 2}, Set B: {3, 4}

Power set of A: {{}, {1}, {2}, {1, 2}}

Power set of B: {{}, {3}, {4}, {3, 4}}

b) Power set for two sets A and B with any 3 elements:

Set A: {1, 2, 3}, Set B: {4, 5, 6}

Power set of A: {{}, {1}, {2}, {3}, {1, 2}, {1, 3}, {2, 3}, {1, 2, 3}}

Power set of B: {{}, {4}, {5}, {6}, {4, 5}, {4, 6}, {5, 6}, {4, 5, 6}}

c) Power set for two sets A and B with any 4 elements:

Set A: {1, 2, 3, 4}, Set B: {5, 6, 7, 8}

Power set of A: {{}, {1}, {2}, {3}, {4}, {1, 2}, {1, 3}, {1, 4}, {2, 3}, {2, 4}, {3, 4}, {1, 2, 3}, {1, 2, 4}, {1, 3, 4}, {2, 3, 4}, {1, 2, 3, 4}}

Power set of B: {{}, {5}, {6}, {7}, {8}, {5, 6}, {5, 7}, {5, 8}, {6, 7}, {6, 8}, {7, 8}, {5, 6, 7}, {5, 6, 8}, {5, 7, 8}, {6, 7, 8},

a) Power set for two sets A and B with any 2 elements:

Set A: {1, 2}, Set B: {3, 4}

Power set of A: {{}, {1}, {2}, {1, 2}}

Power set of B: {{}, {3}, {4}, {3, 4}}

Set A: {apple, banana}, Set B: {cat, dog}

Power set of A: {{}, {apple}, {banana}, {apple, banana}}

Power set of B: {{}, {cat}, {dog}, {cat, dog}}

Set A: {red, blue}, Set B: {circle, square}

Power set of A: {{}, {red}, {blue}, {red, blue}}

Power set of B: {{}, {circle}, {square}, {circle, square}}

b) Power set for two sets A and B with any 3 elements:

Set A: {1, 2, 3}, Set B: {4, 5, 6}

Power set of A: {{}, {1}, {2}, {3}, {1, 2}, {1, 3}, {2, 3}, {1, 2, 3}}

Power set of B: {{}, {4}, {5}, {6}, {4, 5}, {4, 6}, {5, 6}, {4, 5, 6}}

Set A: {apple, banana, orange}, Set B: {cat, dog, elephant}

Power set of A: {{}, {apple}, {banana}, {orange}, {apple, banana}, {apple, orange}, {banana, orange}, {apple, banana, orange}}

Power set of B: {{}, {cat}, {dog}, {elephant}, {cat, dog}, {cat, elephant}, {dog, elephant}, {cat, dog, elephant}}

Set A: {red, blue, green}, Set B: {circle, square, triangle}

Power set of A: {{}, {red}, {blue}, {green}, {red, blue}, {red, green}, {blue, green}, {red, blue, green}}

Power set of B: {{}, {circle}, {square}, {triangle}, {circle, square}, {circle, triangle}, {square, triangle}, {circle, square, triangle}}

c) Power set for two sets A and B with any 4 elements:

Set A: {1, 2, 3, 4}, Set B: {5, 6, 7, 8}

Power set of A: {{}, {1}, {2}, {3}, {4}, {1, 2}, {1, 3}, {1, 4}, {2, 3}, {2, 4}, {3, 4}, {1, 2, 3}, {1, 2, 4}, {1, 3, 4}, {2, 3, 4}, {1, 2, 3, 4}}

Power set of B: {{}, {5}, {6}, {7}, {8}, {5, 6}, {5, 7}, {5, 8}, {6, 7}, {6, 8}, {7, 8}, {5, 6, 7}, {5, 6, 8}, {5, 7, 8}, {6, 7, 8},

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Answer:

She would have to work 28 hours the next week to earn $448.00.

Step-by-step explanation:

Have a nice day/night :)

Also if you can may I please have brainliest

There is a weak relationship between education and income. Education not only raises the level of income is TRUE.

Education is the process of facilitating learning, or gaining of knowledge, skills and personal development.

Education effect on also your future. It makes bright future. if you are study in continuation it develops inner skills of human beings.

The income effect describes that the income effect evaluates consumer spending habits based on a change in their income. This is reflected in microeconomics via an upward shift in the downward-sloping demand curve.

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The given question is incomplete, complete question is:

statistics show that there is a weak relationship between education and income. please select the best answer from the choices provided

1. True

2. False

The quadratic equation with zeros at -6 and 2 is y² + 4y - 12 = 0. This is in standard form, which is ax² + bx + c = 0, with a = 1, b = 4, and c = -12.

To find the quadratic equation with zeros at -6 and 2, we can start by using the fact that if a quadratic equation has roots x₁ and x₂, then it can be written in the form

(y - x₁)(y - x₂) = 0

where y is the variable in the quadratic equation.

Substituting the given values of the zeros, we get

(y - (-6))(y - 2) = 0

Simplifying this expression, we get

(y + 6)(y - 2) = 0

Expanding this expression, we get

y² - 2y + 6y - 12 = 0

Simplifying this expression further, we get

y² + 4y - 12 = 0

So the quadratic equation with zeros at -6 and 2 is

y² + 4y - 12 = 0

This is the standard form of a quadratic equation, which is

ax² + bx + c = 0

where a, b, and c are constants. In this case, a = 1, b = 4, and c = -12.

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The coach's errors are;

Speed is defined as the ratio of the time distance travelled by the body to the time taken by the body to cover the distance.

Given the speed that Aliza needs to run in order to exceed her fastest time in a race = 8.8 feet per second

If her coach determines that she is running at an average rate of 5.8 miles per hour, we need to first convert the speed her coach assumed to feet per second

Convert 5.8miles to feet per second

According to the coach's conversion

\(=5.8\times \dfrac{1}{15}\times 5280\times \dfrac{1}{60}\)

This shows that 5.8mi/hr is equivalent to 34.0ft/s according to the coach conversion rate.

From the coach's calculation, we see that the coach made the first error by using 60s as 1hr instead of 3600s as 1hr

The coach also made an error by saying Eliza is not running fast enough to exceed her fastest time. We can see that Eliza was running fast enough since her speed at 34ft/s exceed 8.8ft/s.

Hence the second error was a wrong conclusion made by the coach.

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Answer:

Step-by-step explanation:

7.80=66(.05)+.10(x)

7.80=3.30+.10(x)

7.80=3.30+.10x

4.50=.10x

x=45

Check

66 nickels at .05=3.30

45 dimes at .10= 4.50

3.30+4.50= 7.80

Answer:

It's prime, the others are for English.

Step-by-step explanation:

Answer:

C

All Real Numbers, this is because it has infinitely MANY solutions.

Step-by-step explanation:

An equation that matches the table include the following: y = x + 5.

In Mathematics and Geometry, the point-slope form of a straight line can be calculated by using the following mathematical equation (formula):

y - y₁ = m(x - x₁)

Where:

First of all, we would determine the slope of this line;

Slope (m) = (y₂ - y₁)/(x₂ - x₁)

Slope (m) = (6 - 5)/(1 - 0)

Slope (m) = 1/1

Slope (m) = 1.

At data point (0, 5) and a slope of 1/, a linear equation in slope-intercept form for this line can be calculated by using the point-slope form as follows:

y - y₁ = m(x - x₁)

y - 5 = 1(x - 0)

y - 5 = x

y = x + 5

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From the given results, we found that the relative frequency of rolling a 3 is 9/40.

What is the relative frequency?

The relative frequency is calculated as the ratio of the number of occurrences of a given value of the data in the set of all outcomes to the total number of outcomes. Frequency is a measure of how frequently an event happens. While not a theoretical concept, relative frequency is one that is currently being tested. The fact that it is experimental means that if we repeat the trials, we might get different relative frequencies. In order to compare the frequency of a specific event to all other occurrences, relative frequency is used.

The complete question is given below.

Number of times Danielle rolled a number cube = 40

We are asked to find the relative frequency of rolling a 3.

Relative frequency = frequency/ Total frequency

From the table,

Frequency of 3 = 9

Total frequency = 5 + 5+ 9 + 6 + 7 + 8 = 40

Then the relative frequency of 3 = 9/40

Therefore from the given results, we found that the relative frequency of rolling a 3 is 9/40.

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Answer:

50 p Is a better deal

Step-by-step explanation:

if wrong let me know

The probability that Adam and Betty meet at some point is $1-\frac{1}{16}=\boxed{\frac{15}{16}}$.

To find the probability that Adam and Betty meet while walking on the grid, we can consider their paths. Adam will always move up or right, while Betty will always move down or left. This means that their paths will always be perpendicular, and they will only meet if they intersect at some point.

Let's consider the first minute. Adam can either move up or right, and Betty can either move down or left. There are four possible outcomes: Adam moves up and Betty moves down, Adam moves up and Betty moves left, Adam moves right and Betty moves down, or Adam moves right and Betty moves left.

Out of these four outcomes, only one leads to Adam and Betty meeting: if Adam moves right and Betty moves down, they will meet at the point $(1,3)$. So the probability of them meeting in the first minute is $\frac{1}{4}$.

Now let's consider the second minute. Adam will be one unit away from $(1,3)$, and Betty will be one unit away from $(1,3)$. There are four possible outcomes again, but only one leads to them meeting: if Adam moves up and Betty moves down, they will meet at the point $(1,2)$. So the probability of them meeting in the second minute is $\frac{1}{4}$.

We can continue this process for each minute. At each step, there is only one outcome that leads to them meeting, and the probability of that outcome is $\frac{1}{4}$. So the probability of them meeting after $n$ minutes is $\left(\frac{1}{4}\right)^n$.

Now we need to find the probability that they meet at any point in time. We can do this by taking the complement of the probability that they never meet. The only way they will never meet is if their paths never intersect, which means that Adam always stays to the right of Betty or always stays above Betty.

The probability of this happening is the same as the probability that Adam flips tails $4$ times in a row, or Betty flips heads $2$ times in a row. This probability is $\left(\frac{1}{2}\right)^4=\frac{1}{16}$, since there are $2^4$ possible outcomes for Adam and $2^2$ possible outcomes for Betty.

So the probability that Adam and Betty meet at some point is $1-\frac{1}{16}=\boxed{\frac{15}{16}}$.

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Answer:

Step-by-step explanation:

(1/6)^4

= 1/1296.

Answer:

1/1296

Probability of guessing letter on first try of a dial, 1/6

Equation / 1/6^4

Answer would equal to 1/1296

Answer:

(2,4)

Step-by-step explanation:

It's reflected over the y axis so it would still have the same y value but the x value will be positive instead of negative

The point is (2,4)

Answer:

yep

Step-by-step explanation:

Answer:

Today: Friday, 30 October 2020

Hour: 14.49 WIB (in Indonesia)

________________________

3 (2x - 7) + 1/3 (7x + 2)

= 6x - 21 + 7x/3 + 2/3

= 6x + 7x/3 + 2/3 - 21

= 25x - 61/3

Answer:

Jim is correct

Step-by-step explanation:

A survey of 100 people found that 35 people exercise in the morning,45 people exercise in the afternoon,and 20 people exercise at night.

People who exercise in the morning = 35

= 35/100 = 7/20

Hence, the ratio is 35:100

People who exercise in the afternoon = 45 = 45/100 = 9/20

the ratio is 45:100

People who exercise at night = 20

= 20/100 = 1/5

= The ratio is 20:100

The possible ratios from this date are : 35:100,45:100,and 20:100

Jim is correct