7. Samples were taken from two schools regarding students' allowances. A sample from 25 students from School X revealed an average allowance of $200 per week with a standard deviation of $15. Meanwhile, a sample from 35 students from School Y revealed an average of $180 per week with a standard deviation of $20. Consider a 5% level of significance. Test the hypothesis that students from School X have a higher allowance compared to School B and identify the appropriate test statistic. A. t=4.425 B. t=4.220 C. z=4.425 D. Z=4.245 8. From 20 applicants consisting of 12 woodwind musicians and 8 brass musicians, the conductor will select 7 members who will join the ensemble. If every applicant has an equal and independent chance of being chosen, what is the probability of choosing 5 woodwind musicians?
A. 0.6396 B. 0.0477 C. 0.8485 D. 0.2861 9. Which of the following is true about the relationship between sample size, margin of error, and confidence interval using the t-distribution? A. A larger sample allows for a smaller margin of error which results in a wider confidence interval. B. A larger sample allows for a smaller margin of error which results in a narrower confidence interval. C. A smaller sample allows for a larger margin of error which results in a narrower confidence interval. D. A smaller sample allows for a smaller margin of error which results in a wider confidence interval.
10. A 6-sided die is biased in such a way that the probability of a "six" appearing on top is 20% and all other possibilities have an equal chance of appearing on top. If the die is thrown 5 times, what is the probability that a "six" will appear at most 3 times? A. 0.0026 B. 0.0080
C. 0.9974 D. 0.9920
Answers
7. The appropriate test statistics is t=4.425. Option A
8. The probability of choosing 5 woodwind musicians 0.2861. Option D
9. The true statement is "A larger sample allows for a smaller margin of error which results in a narrower confidence interval." Option B
10. The probability of getting at most 3 successes is 0.9974. Option C
How did we identify the appropriate test statistics and probability?7. The test statistic for a two-sample t-test is calculated as:
t = \((X_1 - X_2) / sqrt[(s_1^2/n_1) + (s_2^2/n_2)]\)
Where:
X₁ and X₂ are the sample means
s₁ and s₂ are the sample standard deviations
n₁ and n₂ are the sample sizes
t = (200 - 180) / √((15²/25) + (20²/35))
Calculating the above equation gives:
t = 20 / sqrt[(225/25) + (400/35)] = 4.425
8. the total possibie outcome ⇒ \(C^{7}_{20} }\)
Possible outcome that 5 woodwind muscians and 8 brass musicians will be selected \(C^{5}_{12}\) and \(C^{2}_8\)
therefore P = \(\frac{C^{5}_{12} C^{2}_{8} }{C^{7}_{20} }\) = 0.2861
9. When we increase the sample size, our estimates become more precise, and hence our margin of error decreases. This results in a narrower confidence interval because we are more confident that our true population parameter lies in a smaller range.
10. P(X ≤ 3) = Σ P(X=k) for k = 0, 1, 2, and 3.
Let's calculate:
P(X = 0) = \(C(5, 0) * (0.2^0) * ((1-0.2)^(5-0)) = 1 * 1 * (0.8^5\)) = 0.32768
P(X = 1) = \(C(5, 1) * (0.2^1) * ((1-0.2)^(5-1)) = 5 * 0.2 * (0.8^4)\)= 0.4096
P(X = 2) = \(C(5, 2) * (0.2^2) * ((1-0.2)^(5-2)) = 10 * 0.04 * (0.8^3)\) = 0.2048
P(X = 3) = \(C(5, 3) * (0.2^3) * ((1-0.2)^(5-3)) = 10 * 0.008 * (0.8^2)\) = 0.0512
P(X ≤ 3) = 0.32768 + 0.4096 + 0.2048 + 0.0512 = 0.99336
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Related Questions
10. Find the unit rate: A UPS worker makes 288 deliveries in 18 hours. She made deliveries each hour. *
Answers
Answer:
16 deliveries in each hour
Step-by-step explanation:
1. 288 divided by 18 hours
2. 288 divided by 18 = 16
3. So in each hours she delivers 16 packages
Kai has begun to list, in ascending order, the positive integers which are not factors of
240
.
What is the sixth number on Kai’s list?
Answers
Answer:17
7, 9, 11, 13, 14, 17,
a government auditor will fine the company if a random sample of 5 bottles has a sample mean under 490 ml. find the probability the company will be fined.
Answers
The probability that the company will be fined is approximately 0.0129 or 1.29%.
Since the sample size is very small (n = 5), we may apply the central limit theorem to approximate the distribution of the sample mean. The sample mean has a standard deviation of 500 ml and follows a normal distribution.
\(\sigma' = \frac{\sigma}{\sqrt{n} }=\frac{10}{\sqrt{5} } ml\) ≈ 4.47 ml.We need to calculate the z-score for a sample mean of 490 ml and then discover the related probability using a common normal distribution table or calculator in order to determine the likelihood that the corporation will be punished. In order to determine the z-score, one must:
\(z = \frac{(x - \mu')}{ \sigma'} =\frac{ (490 - 500)}{4.47}\) ≈ -2.24The region to the left of the z-score of -2.24 in the conventional normal distribution can be used to assess the likelihood of receiving a sample mean less than 490 ml:
P(z < -2.24) ≈ 0.0129Therefore, the probability that the company will be fined is approximately 0.0129 or 1.29%.
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Q:- The amount of soda in a half-liter bottle follows a normal distribution. Assume µ= 500 ml and σ = 10 ml. A government auditor will fine the company if a random sample of 5 bottles has a sample mean under 490 ml. Find the probability the company will be fined.
the weight of oranges growing in an orchard is normally distributed with a mean weight of 5 oz. and a standard deviation of 1.5 oz. what is the probability that a randomly selected orange from the orchard weighs less than 4 oz., to the nearest thousandth?
Answers
Answer:
0.251
Step-by-step explanation:
for a normal distribution question, we need to use the z-score formula for finding the area (probability).
use the z-score formula to convert the values.
z = (X - υ) / σ
where X is the test statistic, υ is the mean, σ is the standard deviation.
z = (4 - 5) / 1.5
= -0.67
in the z-table, find -0.6 down the side column and 0.07 on the top row. the number in the table where these two meet is 0.25143. this is the area to the left of z = -0.67. this is what we want for this question since we want an orange that weighs less than 4oz.
that means that the probability is 0.251 to nearest thousandth
A factory produces a batch of toy vehicles, 1/3 of which are cars and the rest are trucks. trucks have defective ratio of 0.02 and cars have defective ratio of 0.01. the quality inspector picks a toy vehicle at random from the batch and finds out that it is defective. what is the probability that the vehicle was a truck
Answers
Answer:
Step-by-step explanation:
b
help ill mark brainliest
Answers
Answer:
y= 16, 64, 256, 1024
y/x= 16/2, 64/3, 256/4, 1024/5,
Step-by-step explanation:
This is just like any other equation, except instead of x being a number, it is an exponent. For example, when x equals 2, y equals 16 because y always equals four to the power of x. This applies to all of the parts in your table. when x equals 3, y equals 4^3 (4 times 4 times 4) which is 64, and when x equals 4, y equals 4^4 (4 times 4 times 4 times 4), which is 256.
For the y over x part that is just the value y, divided by the value x. For the first line on the table x equals 2, and we know y equals 16 (4^2 is 4 times 4, which is 16) so 16 divided by 2 is 8. That is the answer.
Hope this helps :)
plss, help me!!!
Each of four friends orders a sweatshirt from a catalog. There are 16 colors of sweatshirts, 7 of which are all cotton and 9 wich are blend. Each one orders a different color ( no repeats) at random. What is the probability that the friends order only cotton sweatshirts?
Answers
===========================================================
Explanation:
Let's label the friends as A,B,C,D.
Person A has a probability of 7/16 when it comes to ordering a certain color of cotton sweatshirt.
Then 6/15 is the probability for person B. Note how the 7 and 16 drop by 1 for each. This is because no repeats are allowed. If person A goes for a blue sweatshirt, then person B cannot select blue as well.
Person C's probability is 5/14 and person D has a probability of 4/13
-------------------------
So we have these fractions: 7/16, 6/15, 5/14, 4/13
Once again, we have the numerators and denominators counting down by 1 each time.
Multiplying those fractions gets us...
(7/16)*(6/15)*(5/14)*(4/13)
(7*6*5*4)/(16*15*14*13)
840/43680
(1*840)/(52*840)
1/52
So if you did 52 trials of this, then you should expect about 1 of those trials is where each friend orders a different color cotton sweatshirt.
1/52 = 0.0192 = 1.92% approximately
So this happens about 1.92% of the time.
2. Given B-4.-6), under which reflection is B*(4, -6)?
A) X-axis
B) y-axis
C) y=x
D) y=4
Answers
Answer:
option b y axis
Step-by-step explanation:
Which of the following statements about coping strategies is TRUE? A.The best coping strategy is visualization. B.An effective coping strategy is any strategy that reduces stress. C.Even ineffective coping strategies at least temporarily alleviate stress. D.Only a coping strategy that eliminates stress is effective.
Answers
The correct statement about coping strategies is: An effective coping strategy is any strategy that reduces stress.
The correct option is B .
Coping strategies are techniques or actions that individuals use to manage or deal with stressful situations. Different strategies work for different people, so there isn't a one-size-fits-all approach. However, an effective coping strategy is any strategy that successfully reduces or manages stress.
Some examples of effective coping strategies include deep breathing exercises, engaging in physical activity or exercise, seeking support from friends or family, practicing mindfulness or meditation, and engaging in hobbies or activities that bring joy and relaxation.
It's important to note that while ineffective coping strategies may not completely eliminate stress, they can still provide temporary relief or distraction. However, it is generally recommended to focus on developing and using effective coping strategies that can effectively reduce stress and promote overall well-being.
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An effective coping strategy is any strategy that reduces stress.
Explanation:The true statement about coping strategies is that an effective coping strategy is any strategy that reduces stress.
Coping strategies are techniques or behaviors that individuals use to manage stressful situations or emotions. While visualization can be a helpful coping strategy, it is not the best strategy for everyone. In addition, even ineffective coping strategies can provide temporary relief from stress, but they may not address the underlying causes or have long-term benefits.Learn more about Coping Strategies here:https://brainly.com/question/14370532
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Write the equation for circle below
Answers
Answer:
Step-by-step explanation:
Please help I’ll make you brainlist PLZZ
Answers
Answer:
1,-3
Step-by-step explanation:
Answer:
-3/1
Step-by-step explanation:
take the two points
(-2,10) and (-1,7)
plug it in into y2-y1/x2-x1
and you get -3/1
I need help im doing horrible
Answers
Answer:
Frame 1 to Frame 2:
Translation (x,y) to (x,-y)
Frame 2 to Frame 3:
Rotation R₉₀
Frame 3 to Frame 4:
Translation (x,-y) to (x,y)
Step-by-step explanation:
I know this very well :)
On earth day 40 people volunteer to work at the city park cleanup. 10 of the 40 volunteers are high-school students. The coordinator wants to know what percent of the volunteers are in high school
Answers
Answer:
10/40
10/40=1/4
Percent= 25%
Step-by-step explanation:
Vanessa deposits $12,000 in a savings account with an annual interest rate of 3.5%. Write the function and determine what her balance will be after 5 years
Answers
Answer:
The function for the balance in a savings account over time, given an initial deposit (P) and an annual interest rate (r), is:
A = P(1 + r)^t
Where A is the balance, P is the initial deposit, r is the annual interest rate (expressed as a decimal), and t is the number of years.
In this case, Vanessa has deposited $12,000, and the annual interest rate is 3.5% or 0.035 as a decimal, so the function is:
A = 12000(1 + 0.035)^t
To find out what her balance will be after 5 years, we can substitute t = 5 into the function:
A = 12000(1 + 0.035)^5
A = 12000(1.035)^5
A = 12000*1.2094
A = $14,512.8
Vanessa's balance will be $14,512.8 after 5 years.
Step-by-step explanation:
One unit of A is composed of two units of B and three units of C. Each B is composed of one unit of F. C is made of one unit of D, one unit of E, and two units of F. Items A,B,C, and D have 20,50,60, and 25 units of on-hand inventory, respectively. Items A,B, and C use lot-for-lot (L4L) as their lot-sizing technique, while D,E, and F require multiples of 50,100 , and 100 , respectively, to be purchased. B has scheduled receipts of 30 units in period 1. No other scheduled receipts exist. Lead times are one period for items A, B, and D, and two periods for items C,E, and F. Gross requirements for A are 20 units in period 1,20 units in period 2, 60 units in period 6, and 50 units in period 8. Find the planned order releases for all items.
Answers
The planned order releases for each item are as follows: A: 20 units in period 1, B: 10 units in period 1, C: 40 units in period 3, D: No planned order release, E: 100 units in period 5, F: 100 units in period 5
To determine the planned order releases for all items, we need to calculate the net requirements for each period based on the given information. We will start with the highest-level item and work our way down the bill of materials.
Item A:
Period 1: Gross requirement of 20 units.
Since A uses lot-for-lot (L4L) as the lot-sizing technique, we release an order for 20 units of A.
Item B:
Item B is a component of A, and each A requires 2 units of B.
We need to calculate the net requirements for B based on the planned order release for A.
Period 1: Gross requirement of 20 units * 2 (requirement multiplier for B) = 40 units.
B has a scheduled receipt of 30 units in period 1.
Net requirement for B in period 1: 40 units - 30 units = 10 units.
Since B also uses L4L as the lot-sizing technique, we release an order for 10 units of B.
Item C:
Item C is a component of A, and each A requires 3 units of C.
We need to calculate the net requirements for C based on the planned order release for A.
Period 1: Gross requirement of 20 units * 3 (requirement multiplier for C) = 60 units.
C has a lead time of two periods, so we need to account for that.
Net requirement for C in period 3: 60 units - 20 units (scheduled receipt for A in period 1) = 40 units.
Since C uses L4L as the lot-sizing technique, we release an order for 40 units of C.
Item D:
Item D is a component of C, and each C requires 1 unit of D.
We need to calculate the net requirements for D based on the planned order release for C.
Period 3: Gross requirement of 40 units * 1 (requirement multiplier for D) = 40 units.
D has a lead time of one period, so we need to account for that.
Net requirement for D in period 4: 40 units - 60 units (scheduled receipt for C in period 3) = -20 units (no requirement).
Since the net requirement is negative, we do not release any planned order for D.
Item E:
Item E is a component of C, and each C requires 1 unit of E.
We need to calculate the net requirements for E based on the planned order release for C.
Period 3: Gross requirement of 40 units * 1 (requirement multiplier for E) = 40 units.
E has a lead time of two periods, so we need to account for that.
Net requirement for E in period 5: 40 units - 0 units (no scheduled receipt for E) = 40 units.
Since E requires a multiple of 100 to be purchased, we release an order for 100 units of E.
Item F:
Item F is a component of B and C, and each B requires 1 unit of F, while each C requires 2 units of F.
We need to calculate the net requirements for F based on the planned order releases for B and C.
Period 1: Gross requirement for B = 10 units * 1 (requirement multiplier for F) = 10 units.
Period 3: Gross requirement for C = 40 units * 2 (requirement multiplier for F) = 80 units.
F has a lead time of two periods, so we need to account for that.
Net requirement for F in period 5: 10 units + 80 units - 0 units (no scheduled receipt for F) = 90 units.
Since F requires a multiple of 100 to be purchased, we release an order for 100 units of F.
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Mateo’s school is selling tickets to the spring musical. On the first day of ticket sales the school sold 30 adult tickets and 90 children’s tickets for $750.00. The school made $670.00 on the second day by selling 80 adult tickets and 50 children tickets. What is the price of one adult ticket and one children ticket?
Answers
Answer:
Kids: 6.25
Adults: Also 6.25
Step-by-step explanation:
So I focused on the first day more. I noticed that 1/4 of the people who attended were kids, and that leaves it with 3/4 people which were adults.
25% (or 1/4) of 750 is 187.5
So 75% of 750 is 562.5
187.5+562.5=750 so we are on the right path
If the ticket for kids totaled 187.5 and 30 students got it, then the price for the ticket is 187.5/30=x and x equals 6.25
If the ticket for adults totaled 562.5 and 90 people got it, then the price is 562.5/90=y and y equals 6.25.
Checking if i'm correct:
6.25*30=187.5
6.25*90=562.5
187.5+562.5= 750
i probably didnt make it as clear im only in 7th grade, but hopefully this was the answer you were looking for
two angles that add up to 90 degrees are called ________ angles.
Answers
Answer: Right/complementary angles
Step-by-step explanation:
Two angles that add up to 90 degrees are called complementary angles.
Complementary angles are a pair of angles that, when added together, equal a right angle, which measures 90 degrees.
In other words, the sum of the measures of complementary angles is always 90 degrees.
Complementary angles often arise in geometry and trigonometry, and understanding their properties is important when working with angles and solving problems involving right triangles.
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Help I will. Give brainly
Answers
(5, 3) and (5, 7)
5,920 rounded to the nearest thousand
Answers
Answer:
6,000
Step-by-step explanation:
Please help and thank you
Answers
(782,248 * 1.2%)*10
help me please
Answers
Answer: 93869.76
Step-by-step explanation:
hope it helps
Answer:
Step-by-step explanation:
After a party, Ronen noticed that of a pound of treats remained. He decided to take six tenths, or 0.6 of that amount to school and keep the rest of himself. What fraction of the remaining treats will Ronen bring to school? Drag and Drop the numerical values to make the fraction. 4 15 1 20 27 7
Answers
Treats remain = 1 pound
amount bringed to school = 0.6 = 6/10 =3/5
Multiply the treats remain (1 pound )
6/10 X 1 = 3/5 x1 = 3/5
factorize
(x + y) ^ 2 - (y - 9) ^ 2
Answers
Answ er:
( x + 2 y − 9 ) ( x + 9 )
Step-by-step explanation:
Since both terms are perfect squares, factor using the difference of squares formula,
a ^2 − b ^2 = ( a + b ) ( a − b ) where a = x + y and b = y − 9 .
( x + 2 y − 9 ) ( x + 9 )
(5x-25)+(3x+9)=180 please answer right now
Answers
Answer:
\(x=24.5\\\)
Step-by-step explanation:
So we have the equation:
\((5x-25)+(3x+9)+180\)
Combine like terms:
\((5x+3x)+(-25+9)=180\)
Add:
\(8x-16=180\)
Add 16 to both sides:
\(8x=196\)
Divide both sides by 8:
\(x=24.5\\\)
So, our answer is 24.5 :)
Activity 1. TAKING CHANCES WITH EVENTS A AND B
PS:THIS IS NOT A MULTIPLE CHOICE (use probability, click the picture for example)
1.) A card is randomly drawn from a deck of 52 cards. Find the probability of drawing:
A. A red card or a spade
B. A face card or an ace
C. A diamond and a 9
2.) Two pair of dice is rolled. Determine the probability
A. P(sum is 4or11)
B. P(sum is less than 5 or sum is greater than 8)
NONSENSE➪ REPORT
PLEASE HELP ME I NEED IT NOW
Answers
Answer:
39/52 (or 3/4)
16/52 (or 4/13)
1/52
5/36
16/36 (or 4/9)
Step-by-step explanation:
1.)
A.) Let R= red S=Spade RUS= R+S-A∩S odds of getting a red card is 26/52 the odds of getting a spade is 13/52 and the odds of getting a red card and a spade is 0 (which means these events are mutually exclusive)
13/52+26/52= 39/52
B.) F=face A=Ace we want FUA= F+A-F∩A
because these two events are mutually exclusive F∩A = 0
odds of getting a face: 12/52 odds of getting an ace: 4/52
12/52+4/52= 16/52
C.) D= diamond n=nine we're looking for D∩N intuitively we know that only one card in the deck is a nine as well as a diamond so the answer must be 1/52. We can confrim this through the fact that you can find the intersection of two independent events by multiplying them. So diamond: 13/52 and n= 4/52 13/52*4/52= 1/52
2.) let F= four E= eleven
A.) we're looking for FUE or F+E-F∩E (these events are mutually exclusive which means that F∩E = 0)
I think the easiest way to solve questions like these is to list out the possible outcomes
the outcomes that add to 4 are
1,3
2,2
3,1
and therefore the probability of having a sum of 4 is 3/36
the outcomes that add to eleven are
6,5
5,6
therefore the probability of having a sum of 11 is 2/36
3/36+2/36 = 5/36
B.) same deal as the one before
list out the outcomes
less than 5
1,1
1,2
1,3
2,1
2,2
3,1
so the odds of rolling two dice and having a sum less than 5 is 6/36
Now list the outcomes where the sum is greater than 8
3,6
4,5
4,6
5,5
5,6
5,4
6,3
6,4
6,5
6,6
the odds of rolling a sum greater than 8 is 10/36
take the sum and get 16/36
\( \huge \mathcal{ Answer࿐}\)
Question 1.) Find Probability :
A. A red card or a spade .
Total red cards = total hearts + total diamonds
\( \longmapsto \: 13 + 13\)\( \longmapsto \: 26\)Total spades = 13 cards
Favourable outcomes = 26 + 13 = 39now, probability of getting either A red card or a spade is :
\( \mathrm{ \dfrac{favorable \: outcomes}{total \: outcomes} }\)
\( \dfrac{39}{52} \)\( \dfrac{3}{4} \)B. A face card or an ace
total face cards = 4 × 3 = 12total ace cards = 4favorable outcomes = 12 + 4 = 16
The probability of getting a face card or an ace :
\(\mathrm{ \dfrac{favorable \: outcomes}{total \: outcomes} }\)
\( \dfrac{16}{52} \)\( \dfrac{4}{13} \)C. A diamond and a 9
We know there's only one diamond which is 9
So, favourable outcome = 1
Now, probability of getting a diamond and a 9 :
\(\mathrm{ \dfrac{favorable \: outcomes}{total \: outcomes} }\)
\( \dfrac{1}{52}\)_____________________________
2.) Two pair of dice is rolled. Determine the probability :
The outcomes are :
\((1 , 1) (1 , 2) (1 , 3) (1 , 4) (1 , 5) (1 ,6)\)
\((2 , 1) (2 , 2) (2 , 3) (2 , 4) (2 , 5) (2 , 6)\)
\((3 , 1) (3 , 2) (3 , 3) (3 , 4) (3 , 5) (3 , 6) \)
\((4 , 1) (4 , 2) (4 , 3) (4 , 4) (4 , 5) (4 , 6) \)
\((5 , 1) (5 , 2) (5 , 3) (5 , 4) (5 , 5) (5 , 6) \)
\((6 , 1) (6 , 2) (6 , 3) (6 , 4) (6 , 5) (6 , 6)\)
Total number of outcomes = 6² = 36 outcomes
Find :
A. P (sum is 4 or 11 )
Total number of outcomes having sum of 4 is :
3Total number of outcomes having sum of 11 is :
2So, favorable outcome = 2 + 3 = 5
Probablity ( sum is 4 or 11 ) :
\(\mathrm{ \dfrac{favorable \: outcomes}{total \: outcomes} }\)
\( \dfrac{5}{36} \)B. P(sum is less than 5 or sum is greater than 8)
Total number of outcomes having sum less than 5 is :
6Total number of outcomes having sum greater than 8 is :
10So, favorable outcomes = 10 + 6 = 16
Probablity of (sum is less than 5 or sum is greater than 8) is :
\(\mathrm{ \dfrac{favorable \: outcomes}{total \: outcomes} }\)
\( \dfrac{16}{36} \)\( \dfrac{4}{9} \)_____________________________
\(\mathrm{ \#TeeNForeveR}\)
at age 20 jhonny invested 50 dollars at 6.75 percent compounded continuously. he is now 50 years old what is the present value of jhonnys investments?
Answers
Answer:
value of Johnny's investments today, at age 50, is approximately 18.39 dollars.....................
Step-by-step explanation:
To find the present value of Johnny's investments, you will need to use the formula for continuous compound interest:
PV = A / (1 + r)^twhere PV is the present value, A is the final amount, r is the annual interest rate, and t is the number of years.
In this case, the final amount is 50 dollars, the annual interest rate is 6.75 percent, and the number of years is 30 (since Johnny is now 50 years old and he invested the money at age 20). Plugging these values into the formula, we get:PV = 50 / (1 + 0.0675)^30Solving this equation gives a present value of approximately 18.39 dollars. This means that the value of Johnny's investments today, at age 50, is approximately 18.39 dollars, given the original investment amount and the interest rate.
It is important to note that this calculation assumes that the interest is compounded continuously, which means that the interest is compounded infinitely often over the course of the year. This results in a slightly higher present value than if the interest were compounded annually or quarterly.
Mackenzie made 38 of 50 free throws. What is the
experimental probability that Mackenzie will NOT
make the next free throw she attempts?
A- 6/25
B- 12/25
C- 19/25
D- 21/25
Answers
A I believe because Against the odds of 38/50 would be 12/50 that is not an option so split in half this would be A cause its an equivalent fraction
Give a verbal description of the following absolute value function
f(x) = 3 | x - 5 | + 4
Answers
Answer:
It is the distance of x from zero. Examples:The absolute value
of 5 is 5.
The absolute value of -10 is 10.
(Complex numbers) The absolute value of 4 + 3 is 5.
Step-by-step explanation:
PLS HELP ME WITH THIS ASAPP
Answers
The value of the function f(x) at x = 1.477.
f(1.477) = 32.857
The value of the function g(x) at x = 20.
g(20) = 1.729
We have,
Two functions:
f(x) = b^x
g(x) = log_b(x)
Now,
From the table,
f(0.699) = b^0.699 = 5
Taking the logarithm of both sides with base b.
log_b(5) = 0.699
b = 5^(1/0.699)
b = 8.343
Now, we can find the value of f(1.477).
f(1.477) = b^1.477 = 8.343^1.477 = 32.857
Similarly, we can find the value of g(20).
g(20) = log_b(20) = log_8.343(20) = 1.729
Thus,
The value of the function f(x) at x = 1.477.
f(1.477) = 32.857
The value of the function g(x) at x = 20.
g(20) = 1.729
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does anybody know how to solve this equation 5+3∣10−4x∣=20
Answers
x = 5/4 or x = 15/4
Step-by-step explanation: