7. Kayla has set aside $105 to spend on books and CDs. Each book b cost $5 and each CD c costs $12. Which inequality could be used to determine how many books and CDs Kayla can buy?

Answer:

28 g. ................

Answer: $9095.44

Step-by-step explanation:

Given:

P=7380

r=1.9% = .019

t= 11

V = P\(e^{rt}\)                               >substitute

V = 7380 \(e^{(.019)(11)}\)              >Plug into calculator

V= $9095.44

Answer:

-55/78 OR. -0.7

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

Using the chord chord theorem

10(4) = 5x

Solve for x

Simplify multiplication

40 = 5x

Divide both sides by 5

40/5 = 8

5x/5 = x

We're left with x = 8

Note:

Chord chord theorem states that if two chords intersect then the product of the measures of each part of one chord is equal to the product of the measures of the parts of the other chord.

Because the chords shown intersect the product of the parts of each chord should be equal to each other ( 4 * 10 = 5x )

Source: https://www.dummies.com/education/math/geometry/how-to-use-the-chord-chord-power-theorem

The total electric charge inside the cube is -2.52×10^-9 C in the x-direction and 5.72×10^-9 C in the z-direction.

We can calculate the total electric charge inside the cube by using Gauss's law, which relates the electric flux through a closed surface to the total charge enclosed within that surface.

Since the electric field is not uniform, we need to choose a closed surface over which the electric flux is easy to calculate. We can choose a cube with sides of length L centered at the origin, since the electric field is given at all points in space.

Using the symmetry of the problem, we can choose the cube so that it is aligned with the x, y, and z-axes. Each face of the cube has an area of L^2, so the total surface area of the cube is 6L^2.

The electric flux through each face of the cube is given by the dot product of the electric field with the normal vector to that face. For the x-faces, the normal vector is i, and for the z-face, the normal vector is k. The electric field does not have a component in the y-direction, so the flux through the y-faces is zero.

The electric flux through each x-face is

Φx = E•A = (-5.65 N/C)(L^2)i

The electric flux through the z-face is:

Φz = E•A = (3.23 N/C)(L^2)k

Since the electric field is constant over each face, we can add the flux through each face to get the total electric flux through the cube:

Φtotal = 2Φx + 2Φy + 2Φz = (-5.65 N/C)(2L^2)i + (3.23 N/C)(2L^2)k

By Gauss's law, the total electric flux through a closed surface is equal to the total charge enclosed within that surface divided by the permittivity of free space (ε0):

Φtotal = Qenc/ε0

Solving for the total charge enclosed within the cube:

Qenc = Φtotal ε0 = [(-5.65 N/C)(2L^2)i + (3.23 N/C)(2L^2)k] ε0

Using the value of the permittivity of free space ε0 = 8.85×10^-12 C^2/(N m^2), we get:

Qenc = [-2.52×10^-9 C i + 5.72×10^-9 C k]

The total electric charge inside the cube is -2.52×10^-9 C in the x-direction and 5.72×10^-9 C in the z-direction.

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The given question is incomplete, the complete question is:

A cube has sides of length L = 0.370 m . It is placed with one corner at the origin as shown in the figure . The electric field is not uniform but is given by E =( -5.65 N/(C) )xi^+( 3.23 N/(C) )zk Find the total electric charge inside the cube.

Answer:

y<1/2+2

Step-by-step explanation:

Answer:

I think the answer is A because I learned about slope last year

Muscular strength can be measured based on the amount of weight lifted.

Muscular strength can be measured based on the amount of weight lifted. The upper-body and lower-body strength are measured separately. Muscular strength is typically measured which is known as a One Rep Max (1RM).

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Answer:

x = 138

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the opposite interior angles

x = B+ C

x = 68+ 70

x =138

Answer:

138 degrees

Step-by-step explanation:

A triangle is made up of 180 degrees, it lists 2 values already, 68&70. when added that equals 138.

So 180-138 is 42 degrees, which would be the last angle within the triangle.

Since a line is also 180 degrees, its 180-42, which makes x 138 degrees

Answer:

6x+12

Step-by-step explanation:

5 + 2x + 7 + 4x

2x + 4x = 6x

5 + 7 = 12

6x + 12

Hi!  This looks like homework...

so I can help!

What you would need to do first is find the height of the triangle, you know, the dashed line.  15 is the hypotenuse side length.  Now we need to solve for a^2 + b^2 = c^2 (hypotenuse formula)  a^2 = 10^2, and c^2 = 15^2.   So now..

if a^2 + b^2 = c^2, then c^2 - a^2 = b^2.  Just moving stuff around. :D

That would be 15^2 - 10^2 = b^2, which is 225 - 100 = b^2.  The result is 125 = b^2.  

ehaggghh it's a decimal

b^2 is 125... and b is 11.1803398875.  So I can see a snippet of your paper that says round to the nearest tenth.  Yay.

that would be 11.2.  :>

The height is 11.2!! So now... oh noes you have to do it again.

Except this time, you're solving for a^2!

Switch the formula like this: c^2 - b^2 = a^2

13^2 - 11.2^2 = a^2 (base)

43.56 = a^2

6.6 = a

So now, the base is 6.6 + 10, which is 16.6 in total.  13 and 15 are the two side lengths.  But you don't need those.  You only need the height, 11.2.  So multiply 16.6 x 11.2, and you get 185.92, or 185.9.  Then divide that by two, since it's a triangle, not a square.  That's 92.96.  Yay you have the area!  

Hypotenuse formula: a^2 + b^2 = c^2
Use this if you don't have the given height, so you can solve for it.  The dashed line separated the triangle into two parts, so you could find the needed sides of both triangles.  Later, when you get into triangle proofs, you could use the "by construction" postulate to be able to find the similarity or congruence done here.

Have a good day!

Answer:

5+7(3)

5+ 21

26

Answer:

D

Step-by-step explanation:

Its the biggest one

(a) The probability that all 4 missiles will fire is 0.2098 and (b) The probability that at most 2 will not fire is 0.0099.

Here we need to use the concept of combinations to get our required answer.

Here we have been given that 4 out of 14 missiles are defective.

Hence 10 missiles are working.

A sample of 4 missiles was chosen

Hence the simple can be chosen in ¹⁴C₄ ways

a)

The probability that all 4 missiles will fire is

¹⁰C₄/¹⁴C₄

= 0.2098

b)

The probability that at most 2 will not fire is

1 - the probability of including all three defective missiles

= 10³C₃/¹⁴C₄

= 0.0099

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(a) Probability all 4 fire: 0.3297. (b) Probability at most 2 not fire: 0.9591.

(a) To track down the chance that all of the 4 rockets will fire, we actually need to do not forget the quantity of methods we can select 4 operating rockets out of the eleven that are not unsuitable, isolated by the all out range of approaches we will select four rockets out of the whole component.

The amount of ways of selecting four operating rockets out of the eleven that aren't improper is given by way of the combination recipe:

C(eleven,four) = 330

The absolute quantity of methods of selecting four rockets out of the entire part is given via:

C(14,4) = 1001

Subsequently, the chance that each one of the four rockets will hearth is:

P(all four hearth) = C(11,four)/C(14,4) = 330/1001 ≈ zero.3297

(adjusted to 4 decimal spots)

(b) To find the likelihood that at most 2 rockets might not fire, we need to remember every one of the potential conditions in which 0, 1, or 2 poor rockets are selected, and afterward song down the likelihood of every case and upload them up.

Case 1: No defective rockets are selected

The amount of ways of selecting four working rockets out of the eleven that are not faulty is given through the mixture recipe:

C(11,four) = 330

Subsequently, the chance of choosing no defective rockets is:

P(0 inadequate) = C(eleven,4)/C(14,four) ≈ 0.3297

Case 2: One defective rocket is chosen

The quantity of ways of selecting three operating rockets out of the eleven that are not poor is given with the aid of the combo equation:

C(eleven,three) = 165

The amount of ways of selecting 1 damaged rocket out of the three that are available is given through the mix equation:

C(three,1) = 3

Subsequently, the all out number of approaches of selecting 1 insufficient and three running rockets is:

C(eleven,three) × C(3,1) = 495

Thusly, the probability of choosing one deficient rocket and three running rockets is:

P(1 deficient) = C(eleven,three) × C(three,1)/C(14,4) ≈ 0.4655

Case three: Two poor rockets are selected

The amount of approaches of choosing 2 poor rockets out of the three which might be handy is given through the combination recipe:

C(3,2) = 3

The amount of ways of choosing 2 running rockets out of the 11 that aren't faulty is given via the mix recipe:

C(11,2) = 55

In this way, the all out number of methods of selecting 2 broken rockets and 2 working rockets is:

C(3,2) × C(eleven,2) = one hundred sixty five

Subsequently, the chance of choosing two incorrect rockets and two operating rockets is:

P(2 insufficient) = C(3,2) × C(11,2)/C(14,four) ≈ 0.1638

Subsequently, the likelihood that at maximum 2 rockets might not fireplace is:

P(at maximum 2 don't fire) = P(zero imperfect) + P(1 blemished) + P(2 deficient) ≈ 0.9591

(adjusted to 4 decimal spots).

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Answer:

1a

2b

3b

4b

5d

i think this is it

The cοrrect answer tο the given questiοn is d. the central limit theοrem.

The gathered data is arranged in tables based οn frequency distributiοn. The infοrmatiοn cοuld cοnsist οf test results, lοcal weather infοrmatiοn, vοlleyball match results, student grades, etc. Data must be presented meaningfully fοr understanding after data gathering. A frequency distributiοn graph is a different apprοach tο displaying data that has been represented graphically.

The basis fοr using a nοrmal prοbability distributiοn tο apprοximate the sampling distributiοn οf the sample means and pοpulatiοn mean is the central limit theοrem.

The central limit theοrem states that fοr a sufficiently large sample size, the sampling distributiοn οf the sample means will be apprοximately nοrmal, regardless οf the shape οf the pοpulatiοn distributiοn. This theοrem allοws us tο make statistical inferences abοut the pοpulatiοn mean based οn the sample mean using the prοperties οf the nοrmal distributiοn, such as the mean and standard deviatiοn.

Therefοre, the cοrrect answer tο the given questiοn is d. the central limit theοrem.

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Answer: GH = 12

Step-by-step explanation:

Don't panic! Remember that a perpendicular bisector divides a segment equally in half. (If you're writing a proof, cite the "Definition of a perpendicular bisector)

It breaks down to: GH = HI

HI = 12

By the transitive property of segment congruence: GH = 12

Good luck!

Answer:

im sorry but i really cant see the image

Step-by-step explanation:

To calculate the rate of interest, compounded continuously, we use the formula: \(\(A = Pe^{rt}\)\) , where A is the ending value, P is the principal, e is Euler's number, r is the rate, and t is the time. In this case, we know the principal, P, is $100,000, the ending value, A, is $117,000, and the time, t, is 2 years.

Thus, we can solve for r as follows:

\(\[117,000 = 100,000e^{2r}\]\)

Divide both sides by 100,000 to get: \(1.17 = \(e^{2r}\)\)

Now, take the natural logarithm of both sides:

\(\[\ln(1.17) = 2r\ln(e) \Rightarrow \ln(1.17) = 2r\]\)

Solve for r: \(\(r = \frac{\ln(1.17)}{2} = 0.0819\)\)  or 8.19%.

2. The formula for radioactive decay is: \(\(N = N_0e^{-\lambda t}\)\), where \(\(N_0\)\)  is the initial quantity, N is the quantity after time t, and \(\(\lambda\)\)  is the decay constant.

To find the decay constant, we need to know the half-life of tritium, which is given as 12 years. This means that after 12 years, the quantity of tritium will be half of what it was originally.

So, if we start with a quantity of 1, we can write:\(\(N = 0.5 = 1e^{-\lambda \cdot 12}\)\)

Divide both sides by 1: \(0.5 = \(e^{-12\lambda}\)\)

Take the natural logarithm of both sides:

\(\[\ln(0.5) = -12\lambda\]\)

Solve for \(\(\lambda\)\): \(\(\lambda = \frac{\ln(0.5)}{-12} = 0.0578\)\) or  \(\(5.78 \times 10^{-23}\)\).

To find the amount of money in the account at the end of 5 years, we use the formula: \(\(A = Pe^{rt}\)\), where A is the ending amount, P is the principal (which starts at 0 and increases by $2,500 per day), r is the annual interest rate (which is 0.06 or 6%), t is the time in years (which is 5).

We can simplify the formula by factoring out P and substituting the values we know:

\(\[A = P\left(1 + \frac{r}{e}\right)^{(et)} = P\left(1 + \frac{0.06}{365}\right)^{(365 \cdot 5)} = P(1.0618)^{1825}\]\)

Since $2,500 is deposited each day, the principal, P, increases by $2,500 per day.

So, after 5 years, the total amount deposited is: $2,500 \times 365 \times 5 = $4,562,500

Therefore, the ending amount, A, is:

\(\(A = P(1.0618)^{1825} = $4,562,500(1.0618)^{1825} = $6,024,476.394\).

To find E(p), we differentiate the demand function with respect to p

and multiply by \(\((p/q)\), where q is the quantity demanded:

\(\[E(p) = \frac{p}{q} \cdot \frac{dq}{dp} = \frac{p}{4000 - 40p^2} \cdot (-80p) = -\frac{80p}{4000 - 40p^2}\]\)

We want to find  \(\(E(5)\), which is: \(E(5) = -\frac{80(5)}{4000 - 40(5)^2} = -0.016\) or -1.6%\)

Since E(p) is negative, demand is inelastic at p = 5.

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Unit price is the price of a single unit of a product or service. It is calculated by dividing the total price by the number of units purchased or provided.

To find the unit price for each size of the shampoo, we need to divide the cost of each bottle by its respective size in ounces. For the 14.2-ounce bottle that costs $4.99, the unit price would be $0.35 per ounce (4.99 ÷ 14.2 = 0.35). For the 23-ounce bottle that costs $6.07, the unit price would be $0.26 per ounce (6.07 ÷ 23 = 0.26).

To determine which size is the better buy based on unit price, we should choose the size with the lower unit price. In this case, the 23-ounce bottle is the better buy as it has a lower unit price of $0.26 per ounce compared to $0.35 per ounce for the 14.2-ounce bottle.

Therefore, if we are looking to save money, we should choose the 23-ounce bottle as it offers a better value for the price. However, if we only need a small amount of shampoo or prefer the convenience of a smaller bottle, then the 14.2-ounce bottle may be a better choice despite having a higher unit price.

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The simplified expression for (f ∘ g)(x) is 2 + x (option d).

To find and simplify (f ∘ g)(x), we need to substitute the expression for g(x) into f(x) and simplify.

Given:

f(x) = log₃(9x)

g(x) = \(3^x\)

Substituting g(x) into f(x):

(f ∘ g)(x) = f(g(x)) = log₃\((9 * 3^x)\)

Now, we simplify the expression:

log₃\((9 * 3^x)\) = log₃(9) + log₃\((3^x)\)

Since logₓ(a * b) = logₓ(a) + logₓ(b), we have:

log₃(9) + log₃\((3^x)\) = log₃\((3^2)\) + x

Using the property logₓ\((x^a)\) = a * logₓ(x), we get:

log₃\((3^2)\) + x = 2 * log₃(3) + x

Since logₓ\((x^a)\) = a, where x is the base, we have:

2 * log₃(3) + x = 2 + x

Therefore, (f ∘ g)(x) simplifies to:

(f ∘ g)(x) = 2 + x

So, the correct answer is (d) 2 + x.

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Complete Question:

Given f(x)=log₃(9x) and g(x)=\(3^x\). Find and simplify (f ∘ g)(x)

(a) 2x

(b) x

(c) \(27^x\)

(d) 2+x

(e) None of these.

If the expression be 23 x² + 3x + 8 then the constant exists 8.

The addition, subtraction, multiplication, and division arithmetic operators are used to write a group of numbers together to form a numerical statement in mathematics. The expression of a number can take on various forms, including verbal form and numerical form.

A mathematical expression is a finite combination of symbols that is well-formed in accordance with context-specific norms.

A mathematical expression is a phrase that includes at least two numbers or variables, at least one arithmetic operation, and the expression itself. Any one of the following mathematical operations can be used. A sentence has the following structure: Number/variable, Math Operator, Number/Variable is an expression.

During the course of a program's execution, a constant's value cannot change. As a result, the value is constant, as implied by its name. During the course of a program's execution, a variable's value can change. As a result, the value might change, as implied by its name.

Let the expression be 23 x² + 3x + 8

then the constant exists 8.

Therefore, the correct answer is option C. 8.

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Answer:

1, 2, and 3

Step-by-step explanation:

5% = 0.05 = 1/20

The first expression is equal, as 5% is equal to 1/20.

The second expression is equal, as 5% in decimal form is 0.05.

The third expression is equal, as 5% is 5/100 in fraction form, which can be simplified to 1/20.

The fourth expression is NOT equal, as it is 20%, not 5%. 1/5 = 0.2.

The fifth expression is NOT equal becauase 0.5 is one half (1/2), which is not equal to 0.05.

Answer:

20000

Step-by-step explanation:

The greatest value obtained by sin(x) is 1.

So the greatest amount of insects is 12,000 + 8000(1)=20000.

The greatest number of insects are 20000.

"Trigonometric functions can be simply defined as the functions of an angle of a triangle. It means that the relationship between the angles and sides of a triangle are given by these trigonometric functions.

The basic trigonometric functions are sine, cosine, tangent, cotangent, secant and cosecant. "

We have,

y = 12000+8000 sinθ

The possible greatest value of trigonometric function in sinθ is 1 i.e., at \(90^{0}\)

∴ sinθ  = 1

substitute sinθ = 1 in given equation

y = 12000+8000 (1)

⇒ y = 12000+8000

⇒ y = 20000

Hence, The greatest number of insects are 20000.

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Answer:

$146.66

Step-by-step explanation:

I bopped this into a percentage calculator and this is what I got

Answer:

Either C or D

Step-by-step explanation:

Answer:

3 x 15 x 8 = 360

so, if there were 3 cone sizes, 25 flavors of ice cream, and 8 toppings, there would be about 360 different operations

Answer:

Fa

Step-by-step explanation:

Answer: 1385.44

Step-by-step explanation:

πr^2*h

The  laplace transform of f(x) = -2x-4 is L{-2x-4} = (8 - 2s - 4e^(-2s))/s

The Laplace transform of f(x) = -2x-4 for 0<=x and x<2 can be found using the formula:

L{f(x)} = ∫[0,∞) e^(-sx) f(x) dx

Substituting the given function and limits, we get:

L{-2x-4} = ∫[0,2) e^(-sx) (-2x-4) dx

= -2 ∫[0,2) x e^(-sx) dx - 4 ∫[0,2) e^(-sx) dx

Using integration by parts, we can evaluate the first integral as:

-2 ∫[0,2) x e^(-sx) dx = [-2xe^(-sx)] [0,2) + 2 ∫[0,2) e^(-sx) dx

= 2 (1 - e^(-2s))

Evaluating the second integral is straightforward:

-4 ∫[0,2) e^(-sx) dx = -4 [e^(-sx)/(-s)] [0,2)

= 4 (e^(-2s) - 1)/s

Therefore, the Laplace transform of f(x) = -2x-4 for 0<=x and x<2 is:

L{-2x-4} = 2 (1 - e^(-2s)) + 4 (e^(-2s) - 1)/s

Simplifying this expression, we get:

L{-2x-4} = (8 - 2s - 4e^(-2s))/s

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Answer:

all are true except the -8