Answer:
When heat is added to a substance, the molecules and atoms vibrate faster. As atoms vibrate faster, the space between atoms increases. The motion and spacing of theparticles determines the state of matter of thesubstance. The end result of increased molecular motion is that the object expands and takes up more space.
which of the following factors did chen, roll, and ross include in their multifactor model?
Chen, Roll, and Ross included several factors in their multifactor model. Specifically, their model included the market factor, size factor, book-to-market factor, and momentum factor.
The market factor captures the overall performance of the stock market and is typically measured by the returns of a broad-based market index such as the S&P 500.
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PLZZZZZ HELP ASAP I WILL MARK BRAINIEST FOR WHOEVER HAS THE BEST ANSWER!!!!!! THIS IS MY THIRD TIME PUTING THIS QUESTION UP I DONT WANT TO DO IT AGAIN!!!
What are some criteria and constraints for sending a rover to Venus?
I only need 2 criteria and 2 constraints
THANK YOU SO MUCH TO THE PEOPLE THAT WILL HELP MEE
Answer:
Well first for criteria think what would the rover need in order to sustain itself on Venus. And for constraints think of anything that could possibly affect the rover( ex: gasses, active volcanoes)
Explanation:
Criteria: Make the rover self sustainable, and allow the rover to have a mission on Venus( ex: collect rock samples)
Constraints, as I mentioned above gasses, and active volcanoes.
I hope this helps! :)
Assume that it is now January 1, 2022. Wayne-Martin Electric Inc. (WME) has developed a solar panel capable of generating 200% more electricity than any other solar panel currently on the market. As a result, WME is expected to experience a 14% annual growth rate for the next 5 years. Other firms will have developed comparable technology by the end of 5 years, and WME's growth rate will slow to 5% per year indefinitely. Stockholders require a return of 12% on WME's stock. The most recent annual dividend (Do), which was paid yesterday, was $1.75 per share. a. Calculate WME's expected dividends for 2022, 2023, 2024, 2025, and 2026. Do not round intermediate calculations. Round your answers to the nearest cent. D2022 = $ X D2023 = $ D2024 = $ X D2025 = $ D2026 = $ b. Calculate the value of the stock today, Po. Proceed by finding the present value of the dividends expected at the end of 2022, 2023, 2024, 2025, and 2026 plus the present value of the stock price that should exist at the end of 2026. The year end 2026 stock price can be found by using the constant growth equation. Notice that to find the December 31, 2026, price, you must use the dividend expected in 2027, which is 5% greater than the 2026 dividend. Do not round intermediate calculations. Round your answer to the nearest cent. X S C. Calculate the expected dividend yield (D2/Po), capital gains yield, and total return (dividend yield plus capital gains yield) expected for 2022. (Assume that Do = P, and recognize that the capital gains yield is equal to the total return minus the dividend yield.) Do not round intermediate calculations. Round your answers to two decimal places. D1/Po = X % Capital gains yield = % Expected total return = % Then calculate these same three yields for 2027. Do not round intermediate calculations. Round your answers to two decimal places. D/Ps = % Capital gains yield = % Expected total return = %
a) D2022 = $1.9975, D2023 = $2.27715, D2024 = $2.60554, D2025 = $2.98868, D2026 = $3.43243
b) Po = $13.63
c) Dividend yield = 13.85%, Capital gains yield = 74.52%, Expected total return = 88.37%. Dividend yield = 17.89%, Capital gains yield = -23.29%, Expected total return = -5.40%.
a) Dividend is the distribution of earnings to shareholders. Expected dividend for each year can be calculated as follows:
D2022 = D0 (1 + g) = $1.75 (1 + 0.14) = $1.9975
D2023 = D2022 (1 + g) = $1.9975 (1 + 0.14) = $2.27715
D2024 = D2023 (1 + g) = $2.27715 (1 + 0.14) = $2.6055415
D2025 = D2024 (1 + g) = $2.6055415 (1 + 0.14) = $2.98868161
D2026 = D2025 (1 + g) = $2.98868161 (1 + 0.14) = $3.432429195
b) The present value of dividends expected in 2022, 2023, 2024, 2025 and 2026 can be calculated using the following formula:
PVD = D / (1 + r)t
where
PVD = present value of dividends expected
D = dividend expected in a future year
t = number of years from now
r = required rate of return
PVD2022 = $1.9975 / (1 + 0.12)¹ = $1.77700934579
PVD2023 = $2.27715 / (1 + 0.12)² = $1.88843867485
PVD2024 = $2.6055415 / (1 + 0.12)³ = $1.99719364693
PVD2025 = $2.98868161 / (1 + 0.12)⁴ = $2.10928913223
PVD2026 = ($3.432429195 + ($3.432429195 * 1.05)) / (1 + 0.12)⁵ = $2.25661605368
The present value of the stock price that should exist at the end of 2026 can be calculated using the constant growth equation:
Po = D1 / (r - g)
where
Po = price of stock today
D1 = dividend expected at the end of 2026r = required rate of return
g = expected growth rate
Po = $3.60484320761
Total present value of all dividends expected plus the present value of the stock price at the end of 2026 can be calculated using the formula:
Total PV = PVD2022 + PVD2023 + PVD2024 + PVD2025 + PVD2026 + PoTotal PV = $1.77700934579 + $1.88843867485 + $1.99719364693 + $2.10928913223 + $2.25661605368 + $3.60484320761 = $13.6333900619
The value of the stock today, Po, is $13.63.
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1.
Which of the following components in a circuit will most likely have the most resistance?
The components in a circuit that will most likely have the most resistance is light bulb due to heating effect of current.
What is resistance?Resistance is the opposition to the flow of electrons in an electrical conductor.
The mathematical relation for resistance can be understood with the help of the empirical relation provided by Ohm's law.
V=IR
where;
V is voltage in the circuitI is current in the circuitR is resistance of the circuit.High tension transmissionDuring a high tension transmission, electricity is often transmitted at low current and high voltage, due to heating effect of current. The heating effect of current is due to its resistance.
Thus, the components in a circuit that will most likely have the most resistance is light bulb due to heating effect of current.
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The complete question is below:
Which of the following components in a circuit will most likely have the most resistance?
Battery
Copper wire
Closed switch
Light bulb
In the circuit, the lamp is rated at 4 volts and 0. 5 watts. What size resistor must r1 be in order to supply the correct current to this lamp?
For the 4-volt, 0.5-watt lamp to receive the proper power, R1 should be 48 ohms.
To find the required resistance of R1, we need to use Ohm's law, which states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R), i.e., I = V/R.
First, we need to determine the current that the lamp requires. The power (P) of the lamp is given by P = IV, where I is the current flowing through it, and V is its voltage rating. We know that the power of the lamp is 0.5 watts and its voltage rating is 4 volts. Substituting these values, we get:
0.5 = I * 4
Solving for I, we get:
I = 0.5/4 = 0.125 amps
Now, we can use the current value to determine the resistance of R1 using Ohm's law. We know that the voltage drop across R1 is 6 volts (the total voltage of the battery minus the voltage of the lamp). Substituting the values of I and V into the formula, we get:
R1 = V/I = 6/0.125 = 48 ohms
Therefore, R1 should be 48 ohms to supply the correct current to the 4-volt, 0.5-watt lamp.
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A cup of coffee with cooling constant k = -0.09 is placed in a room temperature of 18°C. If the coffee is served at 93 °C, how long will it take to reach a drinking temperature of 73 °C?
The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.
The cooling law is given by:
$$\frac{dQ}{dt}=-k(T-T_0)$$
where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.
We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.
Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.
Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:
dQ = - dQ where dQ is the heat energy gained by the environment.
We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.
We can rearrange the equation as follows:
$$-\frac{dQ}{dt}=k(T-T_0)$$
$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$
$$\frac{d}{dt}T=-k(T-T_0)$$
The differential equation above can be solved using separation of variables as follows:
$$\frac{d}{dt}\ln(T-T_0)=-k$$
$$\ln(T-T_0)=-kt+c_1$$
$$T-T_0=e^{-kt+c_1}$$
$$T=T_0+Ce^{-kt}$$
where C = e^(c1).
We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.
$$T=T_0+Ce^{-kt}$$
$$73=18+C\cdot e^{-0.09t}$$
$$55=C\cdot e^{-0.09t}$$
$$C=55e^{0.09t}$$
$$T=18+55e^{0.09t}$$
We can now solve for the value of t when T=93 as follows:
$$93=18+55e^{0.09t}$$
$$e^{0.09t}=\frac{93-18}{55}$$
$$e^{0.09t}=1.3636$$
$$t=\frac{\ln(1.3636)}{0.09}$$
Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.
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PLZZZZ HELP QUICK . 30 points. Emma weighs 560 N, she has decided to stay in shape so she is working out every morning, This morning she ran and lifted weight! 1. Calculate Emma's mass ( Gravity g= 9.8 N/kg). 2. If she ran 350 meters in 65 seconds, what was her velocity? 3. When she lifted weights, she exerted a 35 N to lift one of the weight 2 meters over the ground, what is the amount of work she performed? Note that units are important, so do not give any number without a unit to avoid losing points.
Force equals mass time acceleration. Weight is a force and it can replace force in the equation. The acceleration would be gravity, which is an acceleration.
1.)
Fw (weight) = m (mass) · g (gravity, 9.8 m/s²)
Fw = m * 9.81 m/s²
560N = m · 9.81 m/s²
m ≈ 57.08 kg
2.)
d = 350 meters
t = 65 seconds
velocity = d/t
velocity = 350 meters / 65 seconds
velocity ≈ 5.38 meters/sec
3.)
Force = 35N
Distance = 2 meters
Work = Force · Distance
Work = 35N · 2 meters
Work = 70 J
Define Metrology
define Metrology
Answer:
the scientific study of measurement.
If four people push on a block, one from each side and all with the same force, the
block will
OA) move, but you don't know which direction
OB) move up
OC move towards you
D) not move
A relationship in which one variable decreases when another variable increases. *
Answer:
Direct variation suggests that two variables change in the same direction, when one variable decreases the other increases.
an object is located 85 cm from a convex lens the focal point is 25 cm what is the average distance is the image real or virtual brainly
The image is real and is found at a distance of 33.33cm.
What is a convex lens?The term lens is used to describe any refracting surface. We know that a lens could be concave or convex in nature. Given that fact, we are to find the nature of the image that is formed by the convex lens.
Also;
1/f = 1/u + 1/v
1/v = 1/f - 1/u
f = focal length
u = object distance
v = image distance
1/v = 1/25 - 1/85
1/v = 0.04 - 0.001
v = 33.33cm
The image is real and is found at a distance of 33.33cm.
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A stone is thrown horizontally from the top of a 25.00-m cliff. The stone lands at a distance of
40.00 m from the edge of the cliff. What is the initial horizontal velocity of the stone?
The projectiles launch allows to find the answer for the initial velocity of the stone is:
v = 17.71 m / s
Projectile launching is an application of kinematics for motion in two dimensions, where there is no acceleration on the x axis and the acceleration on the y axis is the gravity acceleration.
In the attached diagram we can see a corner of the movement. Where the x axis is horizontal and the y axis is vertical, where the zero of the system is at the base of the cliff
In this case the stone is thrown horizontally, therefore its initial vertical speed is zero, let's find the time it takes to reach the base of the cliff
y = y₀ + \(v_{oy}\) t - ½ g t²
where y and y₀ are the current and initial position, \(v_{oy}\) is the initial vertical velocity, g the acceleration of gravity and t the time
When reaching the bottom its height is zero (y = 0) and the highest part its initial height is y₀ = 25.00 m
0 =y₀ + 0 - ½ g t²
t = \(\sqrt{\frac{2y_o}{g} }\)
Let'se calculate
\(t = \sqrt{ \frac{2 \ 2.25 }{9.8 } }\)
t = 2,259 s
They indicate that the stone fell at a horizontal distance of 40 m,
x = \(v_{ox}\) t
v_{ox} = \(\frac{x}{t}\)
v_{ox} = \(\frac{40}{2.259}\)
v_{ox} = 17.71 m / s
In conclusion, using theprojectiles launch we can find the answer for the initial velocity of the stone is:
v = 17.71 m / s
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Why doesn't the moon turn black during a total lunar eclipse? Explain your answer
Answer:
Thank me mark me brainliest
Explanation:
I did not explain because i got a photo
i points A spring is hanging down from the ceiling, and an object of mass m is attached to the free end. The object is pulled down, thereby stretching the spring, and then released. The object oscillates up and down, and the time T required for one complete up-and-down oscillation is given by the equation T -2were is known as the spring constant. What must be the dimension of k for this equation to be dimensionally correct? When showing your work to turn in, make sure to show that you found the unit of k using dimensional analysis rather than by looking it up. Show (in the work you turn in) that this is equivalent to the units of N/m. This answer has not been graded yet. 2 2- 2 づ丁2- .C
Question 1
T=2*pi*sqrt(m/k)
dimension of T=sec
dimension of 2*pi=nil(dimensionless)
dimension of m=kg
equation dimension
sec=sqrt(kg/k)
sec^2=kg/k
k=kg/sec^2
so dimension of k will be
MT^(-2)
dimension of N/m=kgms^(-2)/m=kgs^(-2) so it is same
Question 2
F=Gm1*m2/r^2
Dimension of F=MLT^(-2)
MLT^(-2)=G*M*M/L^2
G=ML^3T^(-2)/M^2=M^(-1)L^(3)T^(-2)
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2. a tree grows and increases its mass. explain why this is not a violation of the law of conservation of matter.
The law of conservation of matter states that matter cannot be created or destroyed, only transformed from one form to another.
When a tree grows and increases its mass, it may seem like this law is being violated.
However, upon closer examination, we can see that the tree is not creating new matter, but rather it is transforming existing matter into new forms.
The tree uses energy from sunlight to convert carbon dioxide from the air and water from the soil into glucose, a type of sugar.
This process, known as photosynthesis, results in the creation of new organic matter in the form of leaves, branches, and roots.
As the tree grows, it continues to transform matter from its environment into new forms, but the total amount of matter in the system remains constant.
Therefore, the growth of a tree is not a violation of the law of conservation of matter, but rather a demonstration of the transformation and conservation of matter in the natural world.
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. Why are the Jovian planets formed from materials different from the terrestrial planets?
a. Terrestrial planets were protected by the asteroid belt between Mars and Jupiter.
b. The composition of elements in a planet was a random process after the big bang.
c. When the solar system first formed, the heaviest elements sank toward the center of the nebulae and the lightest elements floated out.
d. Gaseous Jovian planets, formed farther away from the heat of the Sun, are formed from light weight nebulae "dust."
e. Only the terrestrial planets formed from planetesimals.
The Jovian planets are formed from materials different from the terrestrial planets for the reason that gaseous Jovian planets, formed farther away from the heat of the Sun, are formed from light weight nebulae "dust."
A Jovian planet, also known as a gas giant, is a huge planet that has a primarily gaseous composition. The Jovian planets include Jupiter, Saturn, Uranus, and Neptune. They are primarily made up of hydrogen and helium, and they have enormous atmospheres.Jovian planets are formed farther away from the heat of the Sun, so they are formed from lighter-weight nebulae "dust." Terrestrial planets, on the other hand, are formed nearer to the Sun, so they are formed from heavier-weight nebulae "dust." The density of the materials that make up the Jovian planets is lower than that of the terrestrial planets due to this. This means that the Jovian planets have lower densities and a greater volume than the terrestrial planets.
Hence, the correct option is d. Gaseous Jovian planets, formed farther away from the heat of the Sun, are formed from light weight nebulae "dust."
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can you please help me
Answer: Don't worry I'm here to save u the answer is lithosphere (D) :D
Explanation: I have once done this question and got it right!
Consider the information given below about three Main-Sequence stars A, B, and C. - Star A will be a main sequence star for 10 million years. - Star B has the same luminosity as the Sun. - Star C is a Red Dwarf star. Which of the following is a true statement about these stars? Stars A, B, and C all have approximately the same mass. Star C has the greatest mass. There is not enough information to answer this question. Star B has the greatest mass. Star A has the greatest mass.
The information provided does not directly specify the masses of the stars A, B, and C. Mass is a critical factor that determines a star's evolution and characteristics, including its duration as a main sequence star, luminosity, and classification. The correct answer is 3.
The given information only provides details about the duration of star A as a main sequence star, the luminosity of star B being the same as the Sun, and star C being a Red Dwarf star. None of these pieces of information allows us to conclusively determine the relative masses of the stars.
To determine the mass of a star, additional data such as its spectral type, temperature, or other observational measurements would be required. Therefore, without further information, it is not possible to ascertain which star among A, B, and C has the greatest or similar mass. Hence option 3 is suitable.
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--The complete Question is, Consider the information given below about three Main-Sequence stars A, B, and C.
- Star A will be a main sequence star for 10 million years.
- Star B has the same luminosity as the Sun.
- Star C is a Red Dwarf star.
Which of the following is a true statement about these stars?
1. Stars A, B, and C all have approximately the same mass.
2. Star C has the greatest mass.
3. There is not enough information to answer this question.
4. Star B has the greatest mass. Star A has the greatest mass. --
The drawings show the mass and weight of four objects on different planets:
(see the picture)
(a)
On which of the four planets is the object with the largest mass?
The object with the highest mass is the one on planet D. This is because mass is a measure of the amount of matter an object contains, and is not affected by gravity. Therefore, although the weight of the object on planet D is lower than that of the other planets, its mass remains the same.
Weight, on the other hand, is a measure of the gravitational force acting on an object. Therefore, the weight of an object will vary on different planets due to different gravitational forces. As shown in the drawings, the object on planet A has the greatest weight, but nevertheless the greatest mass.
In summary, the object with the greatest mass is on planet D, while the object with the greatest weight is on planet A.
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What is a physical property of matter 
A. ability to react with acid
B. State of matter
C. flame ability
D. ability to react with oxygen
(will mark u the brainiest)
Describe how the pendulum concept is used in the pendulum clock.
The concept of the pendulum is used in pendulum clocks to keep time. The pendulum swings back and forth in a continuous motion at a fixed rate that is determined by the length of the pendulum and the force of gravity.
This motion is used to regulate the movement of the clock's gears, which control the hands on the clock face.The mechanism of a pendulum clock is such that when the pendulum swings in one direction, it pushes a toothed wheel or gear, which in turn moves the other gears, causing the clock's hands to move forward.
When the pendulum swings back in the opposite direction, it again pushes the gear, causing the hands to move further forward. This cycle continues, with each swing of the pendulum causing the hands to move forward by a set amount. The length of the pendulum determines the rate at which the hands move forward, with longer pendulums causing the hands to move more slowly.
In a pendulum clock, the pendulum swings back and forth in a continuous motion at a fixed rate that is determined by the length of the pendulum and the force of gravity. This motion is used to regulate the movement of the clock's gears, which control the hands on the clock face. The pendulum clock is an improvement on the original verge escapement clocks, which were prone to errors due to the uneven force of the mainspring.The pendulum is a simple yet effective device that can keep accurate time. Its motion is governed by the law of conservation of energy, which states that energy cannot be created or destroyed, only transferred from one form to another.
When the pendulum is pulled to one side and released, it swings back and forth, converting potential energy into kinetic energy and back again. The period of the pendulum, or the time it takes to complete one full swing, is determined by the length of the pendulum and the force of gravity. By adjusting the length of the pendulum, the rate at which it swings can be altered, allowing it to keep accurate time.
To keep the pendulum clock running accurately, it needs to be adjusted periodically. This is done by altering the length of the pendulum, either by moving a weight up or down along the pendulum rod or by turning a screw at the bottom of the pendulum bob. This alters the period of the pendulum, which in turn changes the rate at which the clock runs.
The pendulum clock is a testament to the ingenuity of humanity. By using the simple yet effective concept of the pendulum, clockmakers were able to create accurate timepieces that revolutionized the way we keep time. Today, the pendulum clock may have been superseded by more advanced technologies, but its legacy lives on in the modern clocks and watches we use every day.
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Determine the total degeneracy for a particle in a 3-D cube with quantum numbers 4, 3, and 2, corresponding to nx, ny, and nz respectively, in the wave function ψ"-"M" Number
The total degeneracy of a quantum state is the number of different ways that state can be realized in terms of the values of the quantum numbers.
In this case, the particle is in a 3-D cube with quantum numbers nx = 4, ny = 3, and nz = 2, and the wave function is given by ψ"-M".
The quantum number M refers to the z-component of the particle's angular momentum, which is given by:
M = mℏ
where m is an integer that can range from -j to +j, where j is the total angular momentum quantum number. In this case, we are not given the value of j, so we cannot determine the total degeneracy based on the angular momentum quantum number alone.
However, we can determine the degeneracy associated with each of the quantum numbers nx, ny, and nz. The degeneracy of a given quantum number corresponds to the number of possible values that quantum number can take on. In this case, the quantum numbers nx, ny, and nz can take on values of 1, 2, 3, 4, corresponding to the dimensions of the cube in the x, y, and z directions.
The degeneracy associated with each quantum number is therefore:
deg(nx) = 4
deg(ny) = 3
deg(nz) = 2
The total degeneracy of the system is given by the product of the individual degeneracies:
deg_total = deg(nx) * deg(ny) * deg(nz) = 4 * 3 * 2 = 24
Therefore, the total degeneracy of the system is 24. This means there are 24 different possible quantum states that can correspond to the values of nx = 4, ny = 3, and nz = 2.
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A gas has a pressure of 220 kPa at a volume of 380K. At what temperature will the gas have a pressure of 256 kPa?
BlueBolt Bottlers has a bottle-filling process with a mean value of 64 ounces and a standard deviation of 8 ounces. a. Suppose that the upper and lower tolerance limits are 71 and 57 ounces, respectively. What is the process capability ratio? What would the standard deviation have to be in order for the process to meet the tolerance limits 99.7% of the time? b. Now suppose BlueBolt Bottlers makes some process improvements, thereby lowering the standard deviation of the process to 1.5 ounces, rather than 8 ounces. Using the data in part (a), and the new standard deviation, calculate the process capability ratio. Is the filling process able to meet the tolerance limits 99.7% of the time? Does the process provide Six Sigma quality levels? Explain.
In part (b), the filling process is unable to meet the tolerance limits 99.7% of the time, and it does not achieve Six Sigma quality levels.
a. To calculate the process capability ratio (Cp) in part (a), we use the formula:
Cp = (Upper Specification Limit - Lower Specification Limit) / (6 * Standard Deviation)
Given:
Mean = 64 ounces
Standard Deviation = 8 ounces
Upper Specification Limit = 71 ounces
Lower Specification Limit = 57 ounces
Cp = (71 - 57) / (6 * 8) = 14 / 48 = 0.2917 (rounded to four decimal places)
To determine the standard deviation required for the process to meet the tolerance limits 99.7% of the time, we use the Z-score corresponding to a 99.7% confidence level, which is approximately 3.
Z = (Upper Specification Limit - Mean) / Standard Deviation
Rearranging the formula, we can solve for the standard deviation:
Standard Deviation = (Upper Specification Limit - Mean) / Z
Standard Deviation = (71 - 64) / 3 = 7 / 3 = 2.3333 (rounded to four decimal places)
b. In part (b), with the improved process having a standard deviation of 1.5 ounces, we can recalculate the process capability ratio using the same formula:
Cp = (Upper Specification Limit - Lower Specification Limit) / (6 * Standard Deviation)
Using the same specification limits as before:
Cp = (71 - 57) / (6 * 1.5) = 14 / 9 = 1.5556 (rounded to four decimal places)
To determine if the filling process is able to meet the tolerance limits 99.7% of the time, we compare the new Cp value to the critical value of 2. Since Cp is less than 2, the process does not provide Six Sigma quality levels.
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If the friction is increased, what would happen to
the speed of an object?
Answer:
Decreases
Explanation:
The friction is acting against the movement of the object, causing the object to slow down.
A charge of 8.4 × 10–4 C moves at an angle of 35° to a magnetic field that has a field strength of 6.7 × 10–3 T.
If the magnetic force is 3.5 × 10–2 N, how fast is the charge moving?
9.1 × 10–5 m/s
1.3 × 10–4 m/s
7.6 × 103 m/s
1.1 × 104 m/s
Answer:
the correct answer is D
Explanation:
The driver of a car slams on the brakes, causing the car to slow down at a rate of 24.0ft/s? as the car skids 253ft to a stop.
How long does the car take to stop?
What was the car's initial speed?
It takes approximately 4.59 seconds for the car to come to a stop. the car's initial speed was approximately 110.2 ft/s,
To determine the time it takes for the car to stop and the car's initial speed, we can use the kinematic equation:
v² = u² + 2as
where:
v is the final velocity (0 ft/s, since the car comes to a stop),
u is the initial velocity (unknown),
a is the acceleration (-24.0 ft/s², as the car slows down),
and s is the distance traveled (253 ft).
Plugging in the known values into the equation, we can solve for u:
0² = u² + 2(-24.0 ft/s²)(253 ft)
0 = u² - 48.0 ft/s² * 253 ft
48.0 ft/s² * 253 ft = u²
u² = 12144 ft²/s²
Taking the square root of both sides:
u = √12144 ft/s
u ≈ 110.2 ft/s
So, the car's initial speed was approximately 110.2 ft/s.
Now, to find the time it takes for the car to stop, we can use the equation:
v = u + at
0 = 110.2 ft/s + (-24.0 ft/s²) * t
24.0 ft/s² * t = 110.2 ft/s
t = 110.2 ft/s / 24.0 ft/s²
t ≈ 4.59 s
Therefore, it takes approximately 4.59 seconds for the car to come to a stop.
In summary, the car's initial speed was approximately 110.2 ft/s, and it took approximately 4.59 seconds for the car to come to a stop while skidding a distance of 253 ft.
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HELP!!!! NO LINKS!! Order the events that occur in the removal of thermal energy from an object by a refrigerator.
Answer:
Thermal energy is transferred from the warm object to the coolant in the refrigerator; coolant is compressed and the coolant's temperature rises (work is done on the coolant); thermal energy is transferred from the warm coolant to the outside air; the coolant expands as it passes through the expansion valve and cools.
Explanation:
hope this helps
Thermal energy is transferred from the hot object to the coolant in the refrigerator where the coolant is compressed and the temperature of the coolant rises, so thermal energy is transferred from the hot coolant to the outside air, the coolant expands as it passes through the expansion valve and is cooled.
How is thermal energy transferred in a refrigerator?An evaporator which contains a substance called refrigerant, that evaporates, turning from liquid to gas inside the coil which is located inside the freezer or refrigerator compartment. It transfers thermal energy from the surroundings to the refrigerant molecules.
As a liquid, the refrigerant absorbs thermal energy from the cold air inside the refrigerator and turns into a gas, while as a gas, it transfers thermal energy to the warm air outside the refrigerator and turns back into a liquid.
Thus, thermal energy is transferred from the hot object to the coolant in the refrigerator where the coolant is compressed and the temperature of the coolant rises, so thermal energy is transferred from the hot coolant to the outside air, the coolant expands as it passes through the expansion valve and is cooled.
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HELP PLS
2. How would these gravity forces change if the Sun got much bigger?
Decrease. Increase. Stay the same
3. How would these gravity forces change if the Earth was much closer to the Sum?
Decrease Increase. Stay the same
4. How would these gravity forces change if the Earth got much smaller?
Decrease. Increase. Stay the same
face
Answer:
2. increase
3. stay the same
4. Decrease
Explanation:
(let me know if im wrong on any we learned this last year so I might be a little rusty on this subject)
The force of gravity increases with increase in the size of the Sun and with decrease in the distance between the earth and the Sun. However, it decreases with decrease in the size of the earth.
What is gravity?Gravity is the force of attraction that exists between two bodies separated by a given distance.
The force of gravity increases with increase in the size of the bodies as well as with a decrease in the distance of separation.
However, the force of gravity decreases with decrease in the size of the bodies as well as with a increase in the distance of separation.
Thus, for the force of gravity between the earth and the Sun;
Force of gravity increases with increase in the size of the SunForce of gravity increases with decrease in the distance between the earth and the Sun Force of gravity decreases with decrease in the size of the earth.Therefore, the force of gravity is affected by size of the bodies as well as the distance separating the bodies.
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A motor car is traveling at a steady speed of 30m/s. The engine provides the force needed to oppose the force of air resistance, 1600N
(Calculate the work done by the car each second against the force of air resistance)
If a motor car is traveling at a steady speed of 30m/s then the work done by the car each second against the force of air resistance is 48,000 J.
To calculate the work done by the car each second against the force of air resistance, we need to use the formula for work, which is:
work = force x distance
In this case, the distance is not given, but we know that the car is traveling at a steady speed of 30m/s. We can use this information to calculate the distance traveled in one second:
distance = speed x time
distance = 30m/s x 1s
distance = 30m
Now we can calculate the work done by the car against the force of air resistance:
work = force x distance
work = 1600N x 30m
work = 48,000 J
Therefore, the work done by the car each second against the force of air resistance is 48,000 J.
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