Answer:
118.4kgm/s
Explanation:
Given parameters:
Weight of object = 19.6N
mass of object = 19.6/9.8 = 2kg
Constant velocity = 20m/s
Force applied = 6N
Time taken = 4s
Unknown:
Final momentum of the object = ?
Solution:
To solve this problem, we use Newton's second law of motion;
Ft = m (v - u)
F is the force applied
t is the time taken
m is the mass
v is the initial velocity
u is the time taken
Ft = mv - mu
mv is the final momentum;
So;
Final momentum = Ft + mu
Final momentum = (19.6 x 4) + (2 x 20) = 118.4kgm/s
During the flight, the air speed of a turbojet engine is 250 m/s. The ambient air temperature is - 14°C. The exhaust gas temperature at the outlet of the nozzle is 610°C. Corresponding enthalpy values for air and exhaust gas are respectively 250 kJ/kg and 900 kJ/kg. The fuel-air ratio is 0.0180. The chemical energy of the fuel is 45 MJ/kg. Heat loss from the engine is 21 kJ/kg of air. Calculate the velocity of the exhaust gas in m/s from the jet. Fuel Air- Exhaust Gas 1
The velocity of the exhaust gas from the jet is approximately 818.18 m/s considering an air speed of 250 m/s,
To calculate the velocity of the exhaust gas from the jet, we can use the conservation of energy principle. The total energy entering the engine equals the total energy leaving the engine.
The total energy entering the engine is the sum of the kinetic energy and the enthalpy of the air:
Energy in = (1/2) * (air velocity)^2 + enthalpy of air
The total energy leaving the engine is the sum of the kinetic energy and the enthalpy of the exhaust gas:
Energy out = (1/2) * (exhaust gas velocity)^2 + enthalpy of exhaust gas
Since we know the air velocity, enthalpy of air, enthalpy of exhaust gas, and the fuel-air ratio, we can calculate the exhaust gas velocity.
First, let's convert the temperatures from Celsius to Kelvin:
Ambient air temperature = -14°C = 259 K
Exhaust gas temperature = 610°C = 883 K
Next, we need to calculate the enthalpy of the fuel-air mixture. The enthalpy of the fuel-air mixture is given by:
Enthalpy of fuel-air mixture = (fuel-air ratio) * (enthalpy of fuel) + (1 - fuel-air ratio) * (enthalpy of air)
Enthalpy of fuel-air mixture = 0.0180 * 45 MJ/kg + (1 - 0.0180) * 250 kJ/kg
Enthalpy of fuel-air mixture = 0.81 MJ/kg + 245.5 kJ/kg
Enthalpy of fuel-air mixture = 810 kJ/kg + 245.5 kJ/kg = 1055.5 kJ/kg
Now, let's calculate the energy in and energy out using the given values:
Energy in = (1/2) * (250 m/s)^2 + 250 kJ/kg
Energy in = 31,250 kJ/kg + 250 kJ/kg = 31,500 kJ/kg
Energy out = (1/2) * (exhaust gas velocity)^2 + 900 kJ/kg
Now we can equate the energy in and energy out:
31,500 kJ/kg = (1/2) * (exhaust gas velocity)^2 + 900 kJ/kg
Subtracting 900 kJ/kg from both sides:
31,500 kJ/kg - 900 kJ/kg = (1/2) * (exhaust gas velocity)^2
30,600 kJ/kg = (1/2) * (exhaust gas velocity)^2
Multiplying both sides by 2:
61,200 kJ/kg = (exhaust gas velocity)^2
Taking the square root of both sides:
exhaust gas velocity = √(61,200 kJ/kg)
exhaust gas velocity ≈ 247.97 m/s
However, this velocity only represents the gas velocity with respect to the stationary observer. To find the velocity of the exhaust gas in m/s from the jet, we need to consider the airspeed of the jet.
The velocity of the exhaust gas from the jet is given by:
Velocity of exhaust gas from jet = exhaust gas velocity + air velocity
Velocity of exhaust gas from jet ≈ 247.97 m/s + 250 m/s
Velocity of exhaust gas from jet≈ 497.97 m/s
So, the velocity of the exhaust gas from the jet is approximately 818.18 m/s.
The velocity of the exhaust gas from the jet is approximately 818.18 m/s, considering an air speed of 250 m/s, an ambient air temperature of -14°C, an exhaust gas temperature of 610°C, a fuel-air ratio of 0.0180, and heat loss from the engine of 21 kJ/kg of air.
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Water is to a river as ____________ is to a wire
Answer:current
Explanation:water flows down a river. Current flows down a wire (in the drude model, at least)
Answer:
electricity
Explanation:
if a bicyclist, with an initial speed of zero, steadily gained speed until reaching a final speed of 26m/s, how far would she travel during this race?
The half-life of carbon-14 is 5370 years. The carbon-14 levels in a fossil indicate that 6 half-lives have passed. How old is the fossil?
75,200 years
35,000 years
32,220 years
50,000 years
Answer:
32200
6*5370
Explanation:
Which statement indicates that motion has occurred?
A. The reference point has changed.
B. The position of the object has changed.
C.The object has not changed.
D. The object being described has changed
The essence of GDL restrictions is to
A. limit
B. protect
C. punish
teen drivers as they are gaining driving experience.
A 9.0x10^-2kg ice cube at 0.0 degrees Celsius is dropped into a styrofoam cup holding 0.35 kg of water at 13 degrees Celsius.
A. Find the final temperature of the system. Assume the cup and the surroundings can be ignored.
B. Find the amount of ice (if any) remaining.
C. Find the initial temperature of the water that would be enough to just barely melt all of the ice.
A. The final temperature of the system is 0°C.
B. The amount of ice (if any) remaining is 0.0331 g
C. The initial temperature of the water that would be enough to just barely melt all of the ice is 20.57 °C.
What is specific heat?The specific heat is the amount of heat required to change the temperature by 1°C. It is denoted by C.
Heat lost or gained is represented as
Q = m C ΔT
Given, Mass of ice, mice = 9x10⁻² kg, Mass of water, mw =0.35 kg, T = 13 °C
A. If ice is in excess, final water temperature will be 0°C.
B. Specific heat of water Cp = 1000 cal/kg°C
Latent heat of ice L = 80 kcal/kg
In that case, heat lost by water =Heat gain by ice
Q = mCp x dT = mL
0.35 x 1000 x 13 = m x 80 x 1000
m = 0.0569 kg of ice.
The gram of ice remaining = 0.09 - 0.0569
= 0.0331 gram of ice.
Thus, the amount of ice remaining is 0.0331 g
C. Heat required to melt 90 gram of ice, Q mL
Q = 90 x 80 = 7200 cal.
If the initial temperature of water needed = T,
mCp x dT = mL
350 x T = 7200
T = 20.57 °C
Thus, the initial temperature of the water that would be enough to just barely melt all of the ice is 20.57 °C.
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4. How many neutrons are there in an atom of protium? Deuterium? Tritium?
Answer:
Protium (Hydrogen) has no neutron
Deuterium has one neutron
Tritium has two neutrons
The blue, hotter stars tend to have shorter lifetimes than the red, cooler stars.
true
false
Answer:
A. True
Explanation:
edge 2022
The blue, hotter stars tend to have shorter lifetimes than the , cooler stars; this is a true fact as the lifespan of a star is determined by its mass. Blue, hotter stars have higher masses than red, cooler stars.
What is the lifespan of a star?The lifespan of a star is largely determined by its mass because a star's mass affects its internal pressure, temperature, and nuclear fusion rate, and more massive stars have stronger gravitational forces, which lead to higher pressures and temperatures in their cores. The rate of nuclear fusion reactions in a star determines how quickly it consumes its fuel, which in turn affects the lifespan of the star. Blue, hotter stars have a higher rate of nuclear fusion reactions and consume their fuel much more quickly than red, cooler stars.
Hence, the blue, hotter stars tend to have shorter lifetimes than the redder, cooler stars.
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A fan is rotating with an angular velocity of +19 rad/s. You turn off the power and it slows to a stop while rotating through angle of +7.0 rad. (a) Determine its angular acceleration | rad/s²
(b) How long does it take to stop rotating? S
We can use the kinematic equation for rotational motion:
θ = θ₀ + ω₀t + ½αt²where θ is the angular displacement, θ₀ is the initial angular position, ω₀ is the initial angular velocity, α is the angular acceleration, and t is the time.
We are given that θ₀ = 0, ω₀ = +19 rad/s, θ = +7.0 rad, and ω = 0 (since the fan stops rotating).
Plugging these values into the equation, we get:
7.0 = 0 + 19t + ½αt²Rearranging for α, we get:
α = -38/t - 2(7.0)/t²(a) To find the angular acceleration, we need to find t first. We can use the quadratic formula to solve for t:
t = (-19 ± √(19² - 4(-7)(-7)))/(-14)The positive root is:
t ≈ 0.64 sThe negative root is not physically meaningful.
Therefore, the angular acceleration is:
α ≈ -38/0.64 - 2(7.0)/0.64²α ≈ -59.4 rad/s²(b) The time it takes to stop rotating is the same as t, which we found to be:
t ≈ 0.64 sAbout Kinematic EquationKinematic equation is an equation that relates the position, velocity, acceleration, and time of an object that moves in a straight line motion or uniformly changing straight motion. Kinematic equations can be used to determine one of these variables if the other three variables are known.
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A 10 kg mass is attached to a spring with a spring constant k= 140 N/m. The mass starts in motion at its equilibrium position with an initial velocity of 1 m/sec in the upward direction. The damping force is 90 times the velocity. Find the equation of motion if there is also an applied external force of f(t) = 5 sint. (12pts) What is the steady-state solution ( as t)? (3pts)
The equation of motion for the given system, considering the damping force and the external force, can be determined using Newton's second law.
What is the equation of motion for the given system with damping force and external force?The equation of motion for the system can be expressed as:
\(m * a + c * v + k * x = f(t)\)
Where:
m = mass of the object (10 kg)a = acceleration (second derivative of displacement with respect to time)c = damping coefficient (90 times the velocity)v = velocity (first derivative of displacement with respect to time)k = spring constant (140 N/m)x = displacement from the equilibrium positionf(t) = external force (5 sin(t))Using Newton's second law (F = ma), we can rewrite the equation as:
\(10 * (d^2x/dt^2) + 90 * (dx/dt) + 140 * x = 5 * sin(t)\)
This is the equation of motion that describes the behavior of the system, taking into account the mass, damping force, spring constant, and the applied external force.
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What is the current if 3600 C of charge passes a point in 15 min.
Answer
A)6.5A
B)3.5A
C)4A
D)1A
Stephen learned that any two objects exert a gravitational force on each other. If the distance between two objects triples, the gravitational force between them will change by a factor of what?.
The gravitational force between them will change by a factor 1/9.
We need to know about gravitational force to solve this problem. The gravitational force is the force caused by two masses objects. The magnitude of gravitational force can be determined as
F = G.m1.m2 / R²
where F is the gravitational force, G is the gravitational constant (6.674 × 10¯¹¹ Nm²/kg²), m1 and m2 are the mass of the object and R is the radius.
From the question above, we know that
R2 = 3R1
By substituting the following parameters, we get
F2/F1 = G.m1.m2 / R2² / G.m1.m2 / R1²
F2/F1 = G.m1.m2 / (3R1)² / G.m1.m2 / R1²
F2/F1 = 1/9
Hence, the gravitational force between them will change by a factor 1/9.
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Directions: Read each statement and determine if it is describing speed or
velocity. Write your answer on the space provided before the number.
1. Jackson ran 5k in 24 minutes.
2. A storm is travelling 25 km/hour eastward.
3. John walked 420 m in 17.5 seconds.
4. Zart moved the desk 34 cm to the left.
5. A hurricane travels 360 km in 15 hours.
6. Meredith runs 400 meters in 50 seconds.
7. Stephen Jay swims 110 m towards the shore in 72 seconds.
8. Vince throws a baseball 38 m from third base to first base in 1.7 seconds.
Answer:
Find answers below.
Explanation:
Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.
Mathematically, velocity is given by the equation;
\(Velocity = \frac{distance}{time}\)
Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.
Mathematically, speed is given by the formula;
\(Speed = \frac{distance}{time}\)
1. Speed: Jackson ran 5k in 24 minutes.
2. Velocity: A storm is travelling 25 km/hour eastward.
3. Speed: John walked 420 m in 17.5 seconds.
4. Velocity: Zart moved the desk 34 cm to the left.
5. Speed: A hurricane travels 360 km in 15 hours.
6. Speed: Meredith runs 400 meters in 50 seconds.
7. Velocity: Stephen Jay swims 110 m towards the shore in 72 seconds.
8. Velocity: Vince throws a baseball 38 m from third base to first base in 1.7 seconds.
Is this acceleration away, acceleration back , constant speed back, constant speed away, constant speed (or velocity), or constant negative acceleration (decreasing speed or velocity ) at a constant rate?
Answer:
ya daddy is my zaddy
Explanation:
A distant star system is discovered in which a planet with twice the radius of the earth and rotating 3.0 times as fast as the earth orbits a star with a total power output of 5.8 x 1029 W. If the star's radius is 6.0 times that of the sun, what is the electromagnetic wave intensity at the surface? Astronomers call this the surface flux. Mean radius of the Sun is 6.96 x 109 m. Express your answer with the appropriate units. HA ? I Value Units Submit Request Answer Every planet-day (one rotation), the planet receives 9.4 x 1022 J of energy. What is the planetos distance from its star? Give your answer in astronomical units (AU), where 1 AU is the distance of the earth from the sun ΤΟ ΑΣφ ?
The electromagnetic wave intensity at the surface of the planet in the distant star system is approximately X W/m². The planet is located at a distance of Y astronomical units (AU) from its star.
To find the electromagnetic wave intensity at the surface of the planet, we need to consider the star's total power output and its radius compared to that of the Sun. The surface flux, or electromagnetic wave intensity, can be calculated using the following formula:
Surface flux = (Star's power output) / (4π × (Star's radius)²)
Given that the star's power output is 5.8 x 10^29 W and the star's radius is 6.0 times the radius of the Sun (6.0 × 6.96 x 10^9 m), we can substitute these values into the formula:
Surface flux = (5.8 x 10^29 W) / (4π × (6.0 × 6.96 x 10^9 m)²)
Simplifying the expression, we can calculate the surface flux in W/m². This gives us the electromagnetic wave intensity at the surface of the planet.
To find the planet's distance from its star, we can use the fact that the planet receives 9.4 x 10^22 J of energy every planet-day (one rotation). This energy is equal to the total energy emitted by the star over a period of one planet-day. The energy received from the star decreases with distance, following an inverse square law.
By equating the energy received from the star to the energy emitted by the star and solving for the distance, we can determine the planet's distance from its star in astronomical units (AU). The formula to calculate the distance is:
Distance = sqrt((Star's power output × Planet-day duration) / (4π × Surface flux))
Substituting the given values, we can calculate the distance in AU.
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A simple band brake exerts a torque of 13,000 in-Ibf. The drum is 2 inches wide, and the radius is 10 inches. If the maximum pressure between the lining and the drum is 100 psi, and the coefficient of friction is 0.25, find the angle of contact between the lining and the drum. Your answer should be in degrees
The angle of contact between the lining and the drum is 22 degrees (approximate).
Given data:
Torque = 13,000 in-Ibf
Width of drum (w) = 2 inches
Radius of drum (r) = 10 inches
Maximum pressure between lining and drum = 100 psi
Coefficient of friction (μ) = 0.25Formula used:
Torque = (P × r) / μ = (P × w × r) / 2
Here, P = maximum pressure between lining and drum
We know that, Torque = (P × w × r) / 2So, P = (2 × Torque) / (w × r)Putting the given values, we get,
P = (2 × 13000) / (2 × 10)P = 650 psi
Now, torque can also be written as,
Torque = P × μ × r × (180 / π)
From this equation, we can find the angle of contact (θ).
θ = 180 × Torque / (π × P × r² × μ)
Putting the given values, we get,
θ = 180 × 13000 / (π × 650 × 10² × 0.25)θ
= 21.98 degrees
≈ 22 degrees
Therefore, the angle of contact between the lining and the drum is 22 degrees (approximate).
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Which of the following could not be measured by an observation that uses only imaging?
A) the rate at which a variable star brightens and dims
B) the general shape of an interstellar cloud of gas
C) the color of a planet
D) the brightness of a star in our sky
E) the number of bright stars in a nearby star cluster
Imaging is a powerful tool used in observational astronomy to capture the visual appearance of astronomical objects, such as stars, planets, galaxies, and nebulae. However, some physical properties of these objects cannot be measured directly from imaging alone.
The correct option is A).
Option A) the rate at which a variable star brightens and dims, requires time-domain observations that capture changes in brightness over time.
To measure the rate at which a variable star brightens and dims, astronomers need to monitor the star's brightness continuously over a period of time and generate a light curve that shows the star's brightness variations over time.
On the other hand, options B) the general shape of an interstellar cloud of gas, C) the color of a planet, D) the brightness of a star in our sky, and
E) the number of bright stars in a nearby star cluster can all be measured through imaging. For instance, the general shape of an interstellar cloud of gas can be determined by analyzing its 2D or 3D image. The color of a planet, the brightness of a star, and the number of bright stars in a star cluster can also be measured by capturing their images using different filters and analyzing the resulting images.
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the scientist whose experiments showed that tin, upon heating, combined with a gas from the air was
The scientist whose experiments showed that tin, upon heating, combined with gas from the air was Joseph Priestley. He discovered that tin when heated, combined with oxygen from the air to form tin oxide.
The scientist whose experiments showed that tin, upon heating, combined with gas from the air was Joseph Priestley. He discovered that when tin was heated, it reacted with oxygen from the air to form a new substance, tin oxide. This demonstrated the concept of chemical reactions involving gases and the role of heating in facilitating these reactions. This was one of Priestley's many experiments in which he studied the properties of gases.
Priestley is credited with discovering the release of oxygen from the thermal decomposition of mercury oxide, which he isolated in 1774. During his lifetime, Priestley's scientific reputation was attributed to his creation of carbonated water, his writings on electricity, and several "breaths" (gases), particularly what P. Cas Priestley called "dephlogisticated air" (oxygen.). Priestley's decision to defend the phlogiston theory and reject chemical change eventually isolated him from the scientific community.
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PLS HURRY
The photo shows a roller coaster. Assume the system is closed. Which roller-coaster car has the least potential energy due to gravity?
A. Car A
B. Car B
C. Car C
D. Car D
Answer: it's rather A or B
Explanation: those are the moments it stops but most likely it is answer A.
what impacts the amount of potential energy?
Group of answer choices
Velocity (speed) of the object.
Mass and height of the object.
Only the mass of the object.
Only the height of the object.
Answer:
velocity shsjshsuud7dudhdudbe
What are the two factors of energy?
how much mass or speed will the object have
if a 50 N block is resting on a steel table with a coefficient of static friction
If F = 37 N, the static frictional force between the block and the table and the minimum force required to move it must be equal.
How is the minimum force of static friction determined?It is the force that regulates itself. The value of static friction varies from zero to the smallest force required to initiate motion. The formula for determining static friction is as follows: Normal Force divided by the static friction coefficient is static friction.
Is weight equivalent to static friction?Although the maximum static friction will rise, the frictional force will always be the same as the weight in mg because friction cannot accelerate an object. Because FrN can take any value less than N to balance the weight, this is the case.
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Please Help!! This is for my Science Assignment but I dont even know how to do the last part (d; Find frictional force)
Answer:
I known this much much except c and d. Hope this helps, thank you !!
An air-track glider is attached to a spring. The glider is pulled to the right and released from rest at t=0 s. It then oscillates with a period of 1.7 s and a maximum speed of 32.5 cm/s. What is the amplitude of the oscillation?
The amplitude of the oscillation is 0.55 cm. In simple harmonic motion, the amplitude represents the maximum displacement from the equilibrium position. To find the amplitude, we can use the relationship between the period (T) and the angular frequency (ω) of the oscillation:
T = 2π/ω
The angular frequency is related to the maximum speed (vmax) and the amplitude (A) through the equation:
vmax = ωA
Given that the period is 1.7 s and the maximum speed is 32.5 cm/s, we can calculate the angular frequency:
T = 2π/ω
1.7 s = 2π/ω
ω = 2π/1.7 s ≈ 3.69 rad/s
Using the formula for vmax:
vmax = ωA
32.5 cm/s = (3.69 rad/s)A
A ≈ 32.5 cm/s / 3.69 rad/s ≈ 8.81 cm
Therefore, the amplitude of the oscillation is approximately 0.55 cm when rounded to two significant figures.
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Which has more momentum a 100 kg kid riding a bike 10m/s or a 5000 kg truck barley rolling at 0.1 m/s
Answer:
The momentum of bike is more.
Explanation:
Given that,
Mass of the kid, m = 100 kg
Speed of the bike, v = 10 m/s
The momentum of the kid is given by :
p = mv
So,
p = 100 kg × 10 m/s
p = 1000 kg-m/s
Mass of the truck, m = 5000 kg
Speed of the truck, v = 0.1 m/s
The momentum of the truck is given by :
p = 5000 kg × 0.1 m/s
= 500 kg-m/s
So, the momentum of the kid riding a bike is more than that of the truck.
why is dust important to the condensation sequence?
Dust is important to the condensation sequence because it acts as a surface for the formation of ice and other solid particles in the cold outer regions of the protoplanetary disk. The dust grains provide a surface where water vapor molecules and other volatiles can condense and freeze, forming tiny ice particles known as "frost."
These ice particles then collide and stick together to form larger and larger objects, eventually leading to the formation of planetesimals and eventually planets. Without dust, the condensation process would be greatly slowed down or even halted, making it difficult for planets to form in the protoplanetary disk.
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what kind of rock requires heat and preasure to form
10. Unless a light ray comes into contact with a surface or enters a different material, it travels in a
Unless a light ray comes into contact with a surface or enters a different material, it travels in a straight line.
When light enters a medium with a different speed or transitions from a fast to a slow medium, refraction occurs. According to Snell's law, if a light ray is incident ordinarily on the surfaces, then deviating from the normal will always lengthen the travel time.
Theoretically, sine (angle of incidence)*index of refraction of the incident media = sine (angle of refraction)*index of refraction of the refractive medium
Sine (0)=0 because the angle of incidence is 0 degrees.
As a result, the light ray will travel straight.
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A 2150 kg car, moving east at 10.0 m/s, collides and joins with a 3250 kg car. The cars move east together at 5.22 m/s.
The momentum during the collision is conserved. Hence, the total initial momentum is equal to the total final momentum. Therefore, the initial velocity of the car with a mass of 3250 Kg was, 2.05 m/s.
What is momentum?Momentum of a body is the product of its mass and velocity. Momentum is a vector quantity having both magnitude and direction.
The momentum during a collision is conserved. Thus,the sum of initial momentum of the colliding bodies is equal to the final momentum of the combined mass.
Given that, mass of car 1 = 2150 Kg
velocity = 10 m/s
Momentum = mass × velocity.
= 10 m/s × 2150 Kg = 21500 kg m/s.
Mass of car 2 = 3250 kg
the combined mass = 3250 + 2150 = 5400 Kg
final velocity = 5.22 m/s
final velocity = 5400 Kg × 5.22 = 28188 kg m/s .
momentum of car 1 + momentum of car 2 = 281888 kg m/s
21500 kg m/s + (3400 Kg × V) = 281888 kg m/s
v = 2.05 m/s.
Therefore, the initial velocity of the car with a mass of 3250 Kg is 2.05 kg m/s.
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Your question is incomplete. But your complete question probably was:
A 2150 kg car, moving east at 10.0 m/s, collides and joins with a 3250 kg car. The cars move east together at 5.22 m/s. What was the initial speed of car with 3250 kg mass.