6(d-6f)-6f-3(-7f+8d) please help this is for my homework this is Simplify Expressions with Distribution

Hey there!

The answer for adjacent angles is BGC and CGD, CGD and DGE, and DGE and EGF.

The answer for vertical angles is AGB and EGD, DGC and AGF, and BGC and FGE.

Have a good day!

Having a rectangular pasture for the animals to graze in is something a farmer wants in order to start growing cows, horses, goats, and sheep. She has decided to purchase 7500 ft of fencing. 1875 square feet is the maximum possible area that each of the four pens will enclose.

The maximum possible area of each pen is 1875 square feet. To calculate this, first calculate the total area of the large rectangle that the farmer is enclosing. To do this, multiply the total length of the fencing (7500 feet) by the width of the fence (1 foot). This gives us 7500 square feet as the area of the large rectangle.

Next, divide the area of the large rectangle by 4 to get the area of each pen. This gives us 1875 square feet as the maximum area of each pen.

Total Area of Large Rectangle = 7500 ft x 1 ft = 7500 sq ft

Area of Each Pen = 7500 sq ft / 4 = 1875 sq ft

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Answer:

8^50

Step-by-step explanation:

8^100 / 8^50

We know that a^b / a^c = a^(b-c)

8^(100-50)

8^50

Answer:

11.7b

Step-by-step explanation:

If you do 339.30 divided by 29 it equals 11.7 but the full equation would be c=11.7b

The proportional equation for the total cost 'c' in terms of the number of boxed lunches 'b' is:

c = (339.30 / 29) * b

What is proportion?

The size, number, or amount of one thing or group as compared to the size, number, or amount of another. The proportion of boys to girls in our class is three to one.

Let's assume that each boxed lunch costs the same amount, denoted by the variable 'x'.

We are given that the company ordered 29 boxed lunches for a total cost of $339.30. Therefore, we can write the equation:

29x = 339.30

To find the cost 'c' for any number 'b' of boxed lunches, we can set up a proportion:

29x / 29 = 339.30 / b

Simplifying this equation, we get:

x = 339.30 / 29

Now, we can substitute this value of 'x' back into the equation:

c = bx = b * (339.30 / 29)

Therefore, the proportional equation for the total cost 'c' in terms of the number of boxed lunches 'b' is:

c = (339.30 / 29) * b

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Answer:

yes

Step-by-step explanation:

because 6X8=48 and 48 dived by 3 equals 16

Arrays are dataset that are represented in rows and columns. Rosa's claim is correct.

An array is a linear data structure that collects elements of the same data type and stores them in contiguous and adjacent memory locations.

From the question, we have:

6 rows and 8 columns

The number (n) of elements in the array is: n = Rows × Columns.

So, we have: n = 6 × 8 =48

Express as sum of three numbers, that is n=12+16+20

Express each term as a product, that is n=2 × 6 + 4 × 4 + 4 × 5

The above expression means that, the array can be split to:

An array of 2 by 6

An array of 4 by 4

An array of 5 by 4

Hence, Rosa is correct.

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Answer:

-6

Step-by-step explanation:

2x+7=-x+1

x+7=1

x=-6

the flow curve expresses the behavior of a metal in plastic region of the stress strain curve.

When a sample is exposed to various shear rates or shear stressors, the change in shear viscosity is graphically shown by a flow curve.

A flow curve is a measurement performed on a rotating viscometer or rheometer in which the shear rate is increased stepwise and the corresponding shear stress is calculated for each shear rate. The characteristics of the instrument are used to compute the associated shear stress and viscosity.

Thus, the flow curve expresses the behavior of a metal in the plastic region of the stress strain curve.

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The flood frequency curve for the Navasota River, a flood event with a discharge of 60,000 cubic feet per second has a recurrence interval of approximately X years.

The flood frequency curve is a graphical representation that shows the relationship between the discharge of a river during a flood event and the recurrence interval of that event.
To find the recurrence interval for a given discharge, you need to locate the discharge value of 60,000 cubic feet per second on the flood frequency curve.

Once you find this point, you can read the corresponding recurrence interval on the curve.
Keep in mind that the flood frequency curve is specific to the Navasota River, so the recurrence interval you find will be specific to that river. Different rivers will have different flood frequency curves due to variations in geography, climate, and other factors.

However, you can consult the flood frequency curve for the Navasota River to find the approximate recurrence interval for a flood event with a discharge of 60,000 cubic feet per second.

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The height of the painting in the scale drawing is 10 centimeters if the height of the real painting is 35 inches given that in a scale drawing of a painting, 2 centimeters represents 7 inches. This can be obtained by using the ratio of scale drawing to the real drawing.

Here in the question it is given that,

Thus we can say that, scale of the painting is 2 cm : 7 in

Ratio of scale drawing and real painting is 2 : 7

⇒ Similarly here height of the painting in the scale drawing to the height of the painting in the real drawing will be in the ratio 2 : 7.

We can say that,

2 cm/7 in = x cm/35 in

where x is the height of the painting in the scale drawing

2 cm × 35 in /7 in = x cm

x = 2 × 5 cm

x = 10 cm

Hence the height of the painting in the scale drawing is 10 centimeters if the height of the real painting is 35 inches given that in a scale drawing of a painting, 2 centimeters represents 7 inches.

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Assuming the side lengths in the new phone are proportional to the old phone Then the width of the new phone will be 4.760 inches

Define Proportions

A direct proportion is a relation between variables where their ratio is a constant value.

The original length of a cell phone was L=1.2 inches and the original width was 3.4inches.

A new version of the cell phone is to be released with proportional dimensions with respect to the original cell phone.

We are given the length of the new phone L'=1.68 inches. The ratio of the lengths is 1,2/1.68=0.71428

The new width should be W'=3.4/0.71428=4.760 inches

The width of the new phone will be 4.760 inches

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Volume = rule area × height

Volume = ( 1/2 × 8 × 9 ) × 4

Volume = 36 × 4

Volume = 144 cubic inches

5o% of almost 1500 highway deaths in Pennsylvania each year are attributed to aggressive driving.

Aggressive driving is defined as any behind-the-wheel exertion that, without regard for safety, puts another person( or people) and/ or property in peril.

Aggressive driving can vary from potentially dangerous conduct to serious assault.

From the data attained the percentage of the nearly 1500 highway deaths in Pennsylvania each year attributed to aggressive driving will be 50%

5o% of almost 1500 highway deaths in Pennsylvania each year are attributed to aggressive driving.

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Answer:

64000

Step-by-step explanation:

The absolute value is the non-negative number

|64000| = 64000

Answer:

2.378

Step-by-step explanation:

Answer:

Train P : \(t_{P} =\frac{330}{55}=6\ \text{hours}\)

Train Q : \(t_{Q} =\frac{330}{55}+\frac{1}{2}=6\ \text{hours}\ 30\ \text{minutes}\)

Step-by-step explanation:

The formula to compute the distance traveled by a train is:

\(d=s\times t\)

Here,

d = distance traveled

s = speed of the train

t = time taken

From the provided information:

Train P :

d = 330 km

s = x km/h

Then time taken is:

\(t=\frac{d}{s}=\frac{330}{x}\)

Train Q :

d = 330 km

s = (x - 5) km/h

\(t=\frac{330}{x}+\frac{1}{2}\)

Both the trains traveled the same distance.

\(x\times \frac{330}{x}=(x-5)\times [\frac{330}{x}+\frac{1}{2}]\\\\330=\frac{330(x-5)}{x}+\frac{x-5}{2}\\\\330\times 2x=[660(x-5)+x(x-5)]\\\\660x=660x-3300+x^{2}-5x\\\\x^{2}-5x-3300=0\\\\x^{2}+60x-55x-3300=0\\\\x(x+60)-55(x+60)=0\\\\(x-55)(x+60)=0\\\\x=55\)

Compute the time taken by the two trains as follows:

Train P : \(t_{P} =\frac{330}{55}=6\ \text{hours}\)

Train Q : \(t_{Q} =\frac{330}{55}+\frac{1}{2}=6\ \text{hours}\ 30\ \text{minutes}\)

Answer:

120

Step-by-step explanation:

Just add the 20 back to 40 and times by 2

40 + 20 = 60

60 * 2 = 120

Answer:

The number is: 120

Step-by-step explanation:

We have one-half of "a" decreased by 20 is 40

This means that:

(1/2)a-20=40

(1/2)a=60

a=120

Since y_1(0) = 1, it satisfies the initial condition. However, y_2(0) = 0 does not satisfy the initial condition, as it should be y(0) = 1. Therefore, only y_1(t) is a solution of the initial value problem.

To verify that both y_1(t) = 1 - t and y_2(t) = -t^2/4 are solutions of the initial value problem, we first need to understand what the problem is. An initial value problem is a differential equation that includes an initial condition. In this case, we can assume that the initial condition is y(0) = 1.
Now, let's substitute both y_1(t) and y_2(t) into the differential equation and see if they satisfy the initial condition. The differential equation is not provided, but assuming it is y'(t) = -t/2, we have:
y_1'(t) = -1
y_2'(t) = -t/2
Substituting y_1(t) and y_2(t) into the differential equation gives:
y_1'(t) = -1

= -t/2 (when t = 2)
y_2'(t) = -t/2

= -t/2 (for all t)
Thus, both y_1(t) and y_2(t) satisfy the differential equation. Now, let's check if they satisfy the initial condition.
y_1(0) = 1 - 0

= 1
y_2(0) = -0^2/4

= 0
In conclusion, y_1(t) = 1 - t is the only solution that satisfies the differential equation and initial condition, while y_2(t) = -t^2/4 is not a solution since it does not satisfy the initial condition.

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Answer:

It is - \(\frac{1}{4}\) throughout the line

Step-by-step explanation:

The points O, A and B lie on the line and so the slope will be the same for OA, OB and AB

Calculate the slope m using the slope formula

m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)

with (x₁, y₁ ) = B(- 12, 3) and (x₂, y₂ ) = O(0, 0)

m = \(\frac{0-3}{0+12}\) = \(\frac{-3}{12}\) = - \(\frac{1}{4}\)

Thus the slope is - \(\frac{1}{4}\) throughout the line.

Rounding to the nearest whole number, she will have run a total distance of 13 kilometers after 16 days.

To find out how far she will have run in total after 16 days, we can use the formula for calculating compound interest:

A = P(1 + r/100)^n

Where:

A = Total distance run after n days

P = Initial distance (4.8 kilometers)

r = Rate of increase per day (6.9%)

n = Number of days (16)

Plugging in the given values, we can calculate the total distance:

A = 4.8(1 + 6.9/100)^16

Using a calculator or performing the calculations step by step, we get:

A ≈ 4.8(1.069)^16 ≈ 4.8(2.092473)^16 ≈ 4.8(2.628)

A ≈ 12.6144

Rounding to the nearest whole number, she will have run a total distance of 13 kilometers after 16 days.

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Answer:

Reflection about the y-axis is according to the rule

(x,y)->(-x,y)

Therefore F(x,y) -> F'(-x,y)

The distance between F' and F is (-x,y)-(x,y)=-2x, or the positive distance is 2x.

Figurative language used are

Simile

Metaphor

Simile

Metaphor

Personification

Personification

Simile

Personification

"The stars were as bright as jewels" is a simile, comparing the brightness of the stars to that of jewels.

"Alex's nose was a red cherry when he came inside" is a metaphor, likening Alex's red nose to a cherry.

"Her smile wilted like day-old lettuce" is a simile, comparing the wilting of a smile to day-old lettuce.

"The cactuses were pincushions" is a metaphor, suggesting that the cactuses resemble pincushions.

"Tulips hung their heads in shame" is personification, giving human-like qualities to the tulips by suggesting they feel shame.

"The dry ground gratefully drank in the moisture" is personification, attributing the action of drinking to the dry ground.

"Tanya can be as pesky as poison ivy" is a simile, comparing Tanya's peskiness to that of poison ivy.

"The stream mumbled to itself as it ran over the rocks" is personification, giving the stream the ability to mumble like a person.

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suppose we should solve the following equation:

\(s = \frac{13}{2} (12 + 75)\)

which equals 565.5

Answer:

To graph a system of linear inequalities, you will need to graph each inequality separately on the same set of axes. Here is the general process for graphing a linear inequality:

Begin by plotting the inequality's equation in standard form: Ax + By > C (or < C, or = C).

Determine the values of x and y that make the inequality true. To do this, set each side of the inequality equal to zero and solve for x and y. For example, if the inequality is 2x + 3y > 6, you would set 2x + 3y = 0 and solve for x and y.

Graph the line that represents the equation.

Determine the direction of the inequality by looking at the inequality symbol. If the symbol is ">," the line will be shaded above it. If the symbol is "<," the line will be shaded below it. If the symbol is "≥," the line will be shaded above it, including the line itself. If the symbol is "≤," the line will be shaded below it, including the line itself.

Repeat the process for each additional inequality in the system.

The solution to the system of inequalities is the area where all of the shaded regions overlap. This is the region where all of the inequalities are simultaneously true.

Here is an example of how to graph a system of linear inequalities:

Suppose we want to graph the following system of inequalities:

2x + 3y > 6

-x + 2y < 4

To graph the first inequality, we set 2x + 3y = 0 and solve for x and y. This gives us x = -(3/2)y. We can then plot this line on a graph.

Next, we determine the direction of the inequality by looking at the inequality symbol. In this case, the symbol is ">," so we shade the area above the line.

To graph the second inequality, we set -x + 2y = 0 and solve for x and y. This gives us x = (1/2)y. We can then plot this line on the same graph.

Next, we determine the direction of the inequality by looking at the inequality symbol. In this case, the symbol is "<," so we shade the area below the line.

The solution to the system of inequalities is the area where the shaded regions overlap. This is the region where both inequalities are simultaneously true.

3⁴ is 3 times larger than 3³, 5³ is 5 times larger than 5², 7¹⁰ is 49 times larger than 7⁸ and 17⁶ is 289 times larger than 17⁴.

3⁴ / 3³ = (3 × 3 × 3 × 3) / (3 × 3 × 3) = 3

This means that 3⁴ is 3 times larger than 3³.

5³ is 5 times larger than 5².

5³ / 5² = (5 × 5 × 5) / (5× 5) = 5

7¹⁰ is 49 times larger than 7⁸.

7¹⁰/ 7⁸ = 7² =49

17⁶ is 289 times larger than 17⁴.

17⁶ /17⁴ = 289

Hence, 3⁴ is 3 times larger than 3³, 5³ is 5 times larger than 5², 7¹⁰ is 49 times larger than 7⁸ and 17⁶ is 289 times larger than 17⁴.

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Answer:

3 oz / 3/4

3*4/3=12/3=4

4 oz/1

4oz per serving

The first thing I did to solve this was notice that since the ones place of the withdrawal was a 5, there had to be an odd number of 5s. Also, the amount of 10s has to be even, so there has to be an odd number of 20s. Then I started trying combinations.

3,6,15 = 15+60+300=375

Hey, I got lucky! I got it first try!

Answer:

C

Step-by-step explanation:

To compare these numbers, we need to express them in the same form. We can convert the percentage and fractions to decimal form.

32.5% as a decimal is 0.325 (by dividing by 100).

8/25 as a decimal is 0.32 (by dividing the numerator by the denominator).

Now we can compare all three numbers in decimal form: 0.323, 0.325, and 0.32.

In order from least to greatest, these numbers are: 0.32, 0.323, and 0.325.

So the correct answer is C: 8/25, 0.323, 32.5%.

Answer:

Option C

Step-by-step explanation:

Firstly, we should convert all of them into a standard format. We will convert all into decimal form.

1) 0.323

2) 32.5% = 32.5 ÷ 100 = 0.325

3) 8/25 = 8 ÷ 25 = 0.320

So, we have all the given elements in decimals. Now we can easily compare them. On comparing,

0.320<0.323<0.325

          or

8/25<0.323<32.5%

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Answer:

I don't have a grid with me but look at it this way. if you look at the first set of points look at where they are starting. and. then look at the second set of points. see if the points plotted bend over the x axis or the y axis:)

The graph of the sine function f(x) = sin(400πx) is given by the image at the end of the answer.

The sine function in this problem is defined as follows:

f(x) = sin (y × 2πx).

In which the relevant variable for the graph is the variable y, which is the number of cycles in a single second of the wave.

In this problem, it is states that the note has a frequency of 440 Hz, meaning that it has 440 cycles in one second, thus the equation is:

f(x) = sin (440 × 2πx).

f(x) = sin (880πx).

The function is not multiplied by any value, hence the amplitude is of 1, meaning that the function oscillates between 0 and 1, and also there is not any phase shift or vertical shift, meaning that it oscillates between -1 and 1 starting at the origin.

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