6)
Use VSEPR to predict the electron-pair geometry of O2.
A)
linear
B)
trigonal planar
C)
tetrahedral
ientific
Calc
D)
trigonal bipyramidal

Answer:

Chemical reaction

Explanation:

Answer:

2.52kg

Explanation:

80mm = 8 cm

0.15m = 15 cm

volume of the container = 10m × 8cm × 15cm

= 1200 cubic centimetres

mass = density × volume

= 2.1 × 1200

= 2520g

2520/ 1000

= 2.52kilograms

The standard reaction enthalpy for the given reaction is +235.8 kJ/mol.

The standard reaction enthalpy (ΔH°) for the given reaction is determined as follows:

Equation of reaction: 3 Fe₂O₃ (s) → 2 Fe₃O₄ (s) + ½ O₂ (g)

The standard enthalpy of formation values for Fe₂O₃ (s), Fe₃O₄(s), and O₂(g) is used to calculate the standard reaction enthalpy.

ΔH° = [2 × ΔH°f(Fe₂O₃)] + [½ × ΔH°f(O₂)] - [3 × ΔH°f(Fe₃O₄)]

where;

ΔH°f(Fe₂O₃) = -824.2 kJ/mol

ΔH°f(Fe₃O₄) = -1118.4 kJ/mol

ΔH°f(O₂) = 0 kJ/mol

ΔH° = [2 × (-1118.4 kJ/mol)] + [½ × 0 kJ/mol] - [3 × (-824.2 kJ/mol)]

ΔH° = -2236.8 kJ/mol + 0 kJ/mol + 2472.6 kJ/mol

ΔH° = 235.8 kJ/mol

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The standard Gibbs free energy change (∆G°) for the reaction at 25°C is approximately +24.842 kJ/mol.

The standard Gibbs free energy change (∆G°) for the reaction

CH₃OH(g) → CO(g) + 2 H₂(g) at 25°C

can be calculated using the equation ∆G° = ∆H° - T∆S°.

∆H° = +90.7 kJ/mol and ∆S° = +221 J/(mol·K), we need to convert the units of ∆S° to kJ/(mol·K):

∆S° = +221 J/(mol·K) = +0.221 kJ/(mol·K).

Substituting the values into the equation:

∆G° = ∆H° - T∆S°,

∆G° = +90.7 kJ/mol - (298 K) × (+0.221 kJ/(mol·K)).

Calculating this:

∆G° = +90.7 kJ/mol - 65.858 kJ/mol,

∆G° = +24.842 kJ/mol.

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Answer:

323.76 g

Explanation:

The number of grams of the given atoms of Aluminum is 323.73 grams.

The given parameters:

The number of grams of the given atoms of Aluminum is calculated as follows;

\(= \frac{7.23 \times 10^{24} \times 27 \ g}{6.02 \times 10^{23}} \\\\= 323.73 \ g\)

Thus, the number of grams of the given atoms of Aluminum is 323.73 grams.

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Answer:

s= 0.5 at^2

0.5 x 9.81 x 3^2 = 44m

Explanation:

OB.

44 meters

Answer:

With escape velocity in a direction pointing away from the ground of a massive body, the object will move away from the body, slowing forever and approaching, but never reaching, zero speed. Once escape velocity is achieved, no further impulse need be applied for it to continue in its escape.

Explanation:

Make sure to edit so you're not copy write

Answer: "With escape velocity in a direction pointing away from the ground of a massive body, the object will move away from the body, slowing forever and approaching, but never reaching, zero speed. Once escape velocity is achieved, no further impulse need be applied for it to continue in its escape".

Explanation: This might help lol

One mole of a substance is defined as the amount of that substance that contains the same number of particles as there are atoms in exactly 12 grams of carbon-12. Approximately 550 mL of the 0.3000 M NaCl solution is required to produce 0.1650 moles of NaCl.

In chemistry, a mole (mol) is a unit of measurement used to quantify the amount of a substance. It is a fundamental concept in stoichiometry and plays a central role in understanding the relationships between the masses, numbers of particles, and volumes of substances involved in chemical reactions.

To determine the volume of a 0.3000 M NaCl solution needed to produce 0.1650 moles of NaCl, we can use the equation:

moles = molarity x volume

Rearranging the equation to solve for volume:

volume = moles/molarity

Given that the moles of NaCl is 0.1650 and the molarity is 0.3000 M, we can substitute these values into the equation:

\(volume = 0.1650 moles / 0.3000 M\\ = 0.55 L\)

To convert the volume from liters to milliliters, we multiply by 1000:

\(volume = 0.55 L * 1000 mL/L\\volume = 550 mL\)

Therefore, approximately 550 mL of the 0.3000 M NaCl solution is required to produce 0.1650 moles of NaCl.

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Answer:

C. Compression

Explanation:

edge 2021

Compression stress force produces reverse faults. Therefore, option (C) is correct.

A fault can be described as the rupture of the earth's crust, horizontally, and a reverse fault defines as a 'dip-slip' fault moving vertically. The crust of the earth moves along faults, which are everywhere, both on land as well as on the crust under the oceans.

A reverse fault can be described as a type of dip-slip fault. These faults move vertically and the earth moves up or down relative to these faults.  are different kinds of faults, classified by how the earth on either side of the fault moves.

In a normal fault, one side of the fault slides down so when one side of the fault does go up instead of down, it is known as a reverse fault. A  special kind of reverse fault is known as a thrust fault.

Therefore, the compression stress force produces reverse faults while the tensional stress force produces normal faults.

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Answer:

the oil spreads to cover the water

Answer:

I think it is ; The oil floats to the surface of the water

Explanation:

I don't know about the other one.

Among the given options, the most likely to contain trans fatty acids would be partially hydrogenated vegetable oil.

Trans fatty acids are commonly found in processed foods that use partially hydrogenated oils as an ingredient. Partial hydrogenation is a process that converts liquid vegetable oils into solid or semi-solid fats, thereby increasing their shelf life and stability.

However, this process also generates trans fatty acids as a byproduct. Trans fats have been linked to various health issues, including heart disease. To make healthier choices, it is advisable to avoid products that list partially hydrogenated vegetable oil on their food labels.

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The combination of the compounds can be found in option C

A compound is formed through a chemical reaction or a combination of elements. In a chemical reaction, two or more elements combine or react with each other to form a compound.

The elements involved in the reaction undergo a rearrangement of their atoms and bonding to form new chemical bonds, resulting in the formation of a compound with different properties from the original elements. This is clear from the images that have been shown in the question.

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Answer:

In this reaction, nitrogen acts as the oxidizing agent. Mg is a reducing agent.

Answer:

Geothermal energy

Explanation:

Hope that helps !!!

The correct options based on the information will be:

Enhanced boiling points can be attributed to heightened intermolecular forces since more energy is demanded to break the bonds between molecules in a liquid state and transform them into a gaseous phase.

The presence of strong intermolecular force characterizes Bromine. Fluorine, on the other hand, serves as a gas when under standard temperature and pressure conditions because it experiences weak intermolecular forces consequent to its nonpolar nature and limited size.

Due to the involvement of polarizable electrons and larger proportions, Bromine remains in its liquid state while kept at standard temperature and pressure, attesting thereby to a stronger intermolecular bond compared with Fluorine's relatively weaker bonding property.

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Theoretically, a 100 mg/L solution of methanol would have a COD of 2,500 mg/L.

The quantity of oxygen needed to oxidize organic molecules in water is measured by the chemical oxygen demand. A powerful oxidizing agent, such as potassium dichromate (K2Cr2O7), can oxidize methanol (CH3OH), a straightforward organic molecule, when it is present with sulfuric acid (H2SO4).

The balanced chemical equation for the oxidation of methanol by potassium dichromate is:

CH3OH + 2[O] → CO2 + 2H2O

where [O] represents the oxidizing agent.

The following equation can be used to get the theoretical COD for methanol:

COD = (8 × W × 1000) / (32 × V)

where:

W = mass of methanol in the sample (in mg)

V = volume of the sample (in mL)

Substituting the values given:

W = 100 mg (since the solution concentration is 100 mg/L)

V = 1000 mL (assuming a 1 L sample)

COD = (8 × 100 mg × 1000) / (32 × 1000 mL) = 2,500 mg/L

Therefore, Theoretically, a 100 mg/L solution of methanol would have a COD of 2,500 mg/L.

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Answer:

they are called isotopes

Answer:

The iron present in the solution is reduced because of the presence of SCN⁻ ions in solution

Explanation:

The clue in this problem is the color of the solution:

A solution of Fe³⁻ is yellow but when the Fe³⁺ is reduced by an oxidant to Fe²⁺ the solution change to orange color.

The SCN⁻ ion is a reducing agent than, in presence of a substance that can be reducted as Fe³⁺ ion will promote the reaction. That means the best explanation is:

The correct matching of the various energy forms are as follows:

Energy is defined as the ability to do work.

There are various forms of energy such as:

The correct matching  of the various energy forms are as follows:

The various forms of energy can be interconverted from one form to another.

In conclusion, energy is the ability to do work and it exists in various forms which can be interconverted.

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Answer:

a compound can experience a chemical change if foreign body are in troduced

The distance travelled by the particle between 0 seconds and 6 seconds is 12 m

Velocity is simply defined as the rate of change of displacement with time. Mathematically, it can be expressed as:

Velocity = displacement / time

From the question given above, the following data were obtained:

Velocity = displacement / time

The displacement of the object between 0 and 6 s is calculated as;

2 = displacement / 6

Cross multiply

Displacement = 2 × 6

Displacement = 12 m

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The evidence that a chemical reaction took place in 2 AgNO3 + Cu → Cu(NO3)2 + 2 Ag includes colour change, precipitation, the redox process, and the formation of new substances. These changes all point towards a chemical reaction that has occurred.

In the given chemical reaction, 2 AgNO3 + Cu → Cu(NO3)2 + 2 Ag, there are several pieces of evidence that indicate a chemical reaction took place:
1. Color change: As the reaction progresses, you'll notice a change in colour. The initial colour of copper (Cu) is reddish-brown, while silver nitrate (AgNO3) is colourless. After the reaction, the colourless silver (Ag) and blue-green copper nitrate (Cu(NO3)2) are formed.
2. Precipitation: During the reaction, solid silver (Ag) precipitates out of the solution. This change from a soluble to an insoluble substance indicates a chemical reaction.3. Redox process: The reaction involves an exchange of electrons between the elements, as copper loses two electrons (oxidation) and each silver ion gains one electron (reduction). This redox process is a sign of a chemical reaction taking place.
4. Formation of a new substance: The reaction produces two new substances, silver (Ag) and copper nitrate (Cu(NO3)2), which did not exist before the reaction. The creation of new substances is a strong indication that a chemical reaction occurred.

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The diffusion coefficient is 4.39x10-12 m2/s.

Given information;

Initial nitrogen concentration, c₀ = 0.08 wt %

Nitrogen concentration to be achieved, cₙ = 0.52 wt %

Diffusion coefficient, D = 9.10E-05 m²/s

Temperature, T = 1100 K

Activation energy, Qd = 168 kJ/mol

Gas constant, R = 8.31 J/mol K

To find;

Diffusion coefficient at 1100 K using Arrhenius equation;

The Arrhenius equation for diffusion coefficient is given as;

D = D₀ exp(-Qd / R T)

where; D₀ is the diffusion coefficient at an infinite temperature.

Substituting the given values of D, Qd, R, and T into the equation above;

D = 9.10E-05 m²/s

Qd = 168 kJ/mol

R = 8.31 J/mol

KT = 1100 K

At 1100 K, the value of kT is;

kT = R T

     = 8.31 J/mol K x 1100 K

     = 9141 J/mol

Multiplying by Avogadro's number to get the value in J;

9141 J/mol x (6.022 x 10²³) / (1 mol) = 5.50 x 10²⁹ J-1

                                                          = 5.50 x 10²⁹ m²/kg

Multiplying by the Boltzmann constant to get the value in m²/s;

K = 1.38 x 10⁻²³ J/KD₀ can now be obtained by rearranging the Arrhenius equation as;

D₀ = D / exp(-Qd / R T)

Substituting the values into the equation;

D₀ = 9.10E-05 m²/s / exp(-168 x 10³ J/mol / 8.31 J/mol K x 1100 K)D₀

     = 9.10E-05 m²/s / exp(-21.36)D₀

     = 9.10E-05 m²/s / 1.29E-09D₀

     = 7.05E-04 m²/s

Therefore, the diffusion coefficient at 1,100 K if k = 8.31 is;

D = D₀ exp(-Qd / R T)D

   = 7.05E-04 m²/s exp(-Qd / R T)D

   = 7.05E-04 m²/s exp(-168 x 10³ J/mol / 8.31 J/mol K x 1100 K)

D = 7.05E-04 m²/s exp(-21.36)D

   = 4.39 x 10⁻¹² m²/s

Therefore, the correct option is 4.39x10-12 m2/s.

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Answer:

c

Explanation:i got it right ony my test

Answer:

tertiary

Explanation:

tertiary halogenoalkanes are more reactive than primary and secondary as the carbocation is more stable due to alkyl groups( have high electron density) donating electrons to stabilise the carbocation

Answer: Lanthanoids

Explanation:

Answer:

A bee sting has a ph of 5, and is therefore an acid. Litmus paper goes red (or stays red) in acidic solutions.

Answer:

The Blue Litmus Paper should turn red

Explanation:

Bee venom has a pH of 5.5, which means it is mildly acidic which in turn should make the Litmus paper turn Red. Hope this helps!

Answer:

8.7min

Explanation:

The epicenter is the origin of an earthquake wave.

Since the distance between the earthquake origin and the station is 7000km and we are told to find the time after which the s - wave arrives from that of the p- waves, we follow the procedure below:

So;

  The time difference  = 19min  - 10.3min  = 8.7min

After the p-waves arrived, it took the s-waves  8.7min to reach the station.

Answer:

8.7min

Explanation:

The epicenter is the origin of an earthquake wave.

Since the distance between the earthquake origin and the station is 7000km and we are told to find the time after which the s - wave arrives from that of the p- waves, we follow the procedure below:

we use the graph of the travel time  - distance given

trace the 7000km as the distance and find where it cuts the p-wave curve.

the point is 10.3min

trace it up to where 7000km intersects the s-wave curve which is at 19min

So;

 The time difference  = 19min  - 10.3min  = 8.7min

After the p-waves arrived, it took the s-waves  8.7min to reach the station.

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