The longest wavelength of radiation that can eject a photoelectron from potassium is 5.54 x 10^-7 m or 554 nm. This wavelength falls in the visible range, which ranges from 400-700 nm. Therefore, this radiation will be visible as a violet color.
The energy required to eject a photoelectron from a metal surface is called the work function. The work function of potassium is given as 2.24 eV. The longest wavelength of radiation that can eject a photoelectron from potassium is calculated using the equation:
λ = hc/E
where λ is the wavelength, h is Planck's constant, c is the speed of light, and E is the energy required to eject the photoelectron.
Converting the work function to energy, we get:
E = 2.24 eV = 2.24 x 1.6 x 10^-19 J = 3.58 x 10^-19 J
Substituting the values in the equation, we get:
λ = (6.626 x 10^-34 J s) x (3.0 x 10^8 m/s) / (3.58 x 10^-19 J) = 5.54 x 10^-7 m
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How much time would it take for the sound of thunder to travel at an average speed of 330 meters per second a distance of 8000
what is the maximum acceleration a car can undergo if the coefficient of static friction between the tires and the ground is 0.81?
The maximum acceleration a car can undergo is 0.81 times the acceleration due to gravity (0.81g), where g is the acceleration due to gravity.
The maximum acceleration a car can undergo is determined by the coefficient of static friction between the tires and the ground. The coefficient of static friction, denoted as μs, represents the maximum frictional force that can be exerted between two surfaces without them sliding relative to each other.
In this case, the coefficient of static friction between the tires and the ground is given as 0.81. The maximum acceleration a car can undergo, denoted as amax, is equal to the product of the coefficient of static friction and the acceleration due to gravity (g).
amax = μs * g
Given that the coefficient of static friction is 0.81, we can express the maximum acceleration as:
amax = 0.81 * g
Therefore, the maximum acceleration a car can undergo is 0.81 times the acceleration due to gravity (0.81g). This value represents the maximum acceleration the car can achieve while maintaining traction with the ground without slipping.
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pat is standing on a 25 m cliff overlooking the ocean and throws a rock in a parabolic arc towards the ocean. if the rock took 2 seconds to reach the peak of its arc, and an additional 3 seconds to hit the water, how high (relative to herself) did she throw the rock?
Pat threw the rock approximately 19.6 meters high relative to herself.
To find the height of the rock at its peak, we need to calculate the vertical distance it traveled during the first 2 seconds (upward motion).
We can use the formula h = 0.5 * g * t^2, where h is the height, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time taken (2 seconds).
Plugging in the values, we get h = 0.5 * 9.8 * 2^2 = 0.5 * 9.8 * 4 = 19.6 meters.
Hence, Taking into account the acceleration due to gravity and the time taken to reach the peak of its arc, the rock was thrown 19.6 meters high relative to Pat.
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Three light bulbs are connected in a series, as shown in the diagram.
After the circuit is completed, the middle light bulb breaks. What will happen to the remaining light bulbs?
a
Only the light bulb closest to the positive end of the battery will stay lit.
b
Only the light bulb closest to the positive end of the battery will go out.
c
Both of the remaining light bulbs will go out.
d
Both of the remaining light bulbs will stay lit.
After the circuit is completed, the middle light bulb breaks, both of the remaining light bulbs will go out. Option c is correct.
In a series circuit, components (in this case, light bulbs) are connected end-to-end, so that the current has to flow through each component in turn. The voltage of the battery is divided among the components, so that the sum of the voltage drops across each component equals the total voltage of the battery.
In a series circuit, the current passes through each component in turn. When one component fails or is removed, the current can no longer flow, and the circuit is broken. In this case, when the middle light bulb breaks, it will create an open circuit, preventing the current from reaching the other two light bulbs. Therefore, both of the remaining light bulbs will go out. Option c is correct.
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7) Find F1 and F2
HELP PLEASEEE
The force F1 is equal and opposite to the downward force thus, F1 is equal to 60 N. The force F2 is inclined to 30 ° from leftward force and it is equal to 38.97 N in magnitude.
What is force?Force is an external agent acting on a body to deform it or to change its state of motion or rest. Force is a vector quantity and it is characterised by its magnitude and direction.
If two forces acting on a body from the same directions, then the net force will be the sum of these two forces. If they are acting from opposite directions, they will cancel each other in magnitude.
The force F1 is equal and opposite to the force acting downward. Thus its magnitude is 60 N. The force F2 is inclined to 30 ° from horizontal direction.
F2 = 45 cos 30 = 38.9 N.
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Combustion products at an initial stagnation temperature and pressure of 1800 k and 850 kpa are expanded in a turbine to a final stagnation pressure of 240 kpa with an:_________
Combustion products at an initial stagnation temperature and pressure of 1800 K and 850 kPa are expanded in a turbine to a final stagnation pressure of 240 kPa with an: unknown change in stagnation temperature.
To determine the change in stagnation temperature, we can use the following equation:
(T2/T1) = (P2/P1)^((gamma-1)/gamma)
Where T1 and T2 are the initial and final stagnation temperatures, P1 and P2 are the initial and final stagnation pressures, and gamma is the specific heat ratio.
Since we have the values for P1, P2, T1, and we want to find T2, we can rearrange the equation to solve for T2:
T2 = T1 * (P2/P1)^((gamma-1)/gamma)
Plugging in the values given, we get:
T2 = 1800 K * (240 kPa / 850 kPa)^((gamma-1)/gamma)
Unfortunately, the specific heat ratio (gamma) is not provided in the question. To find the change in stagnation temperature, we would need to know the specific heat ratio.
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9.00 V is applied to a wire with aresistance of 52.0 2. At what distancefrom the wire is the imagnetic field2.22 x 10-8 T?
Answer:
1.56 m
Explanation:
First, we need to find the current in the wire, so we will use the following equation:
\(V=IR\)Where V is the voltage, R is the resistance and I is the current. Replacing the values and solving for I, we get:
\(\begin{gathered} 9V=I(52\Omega) \\ \frac{9V}{52\Omega}=I \\ 0.17A=I \end{gathered}\)So, the current is 0.17 A.
Now, the magnetic field generated by a wire with current I at a distance r is equal to:
\(B=\frac{\mu I}{2\pi r}\)Where μ is 4π x 10^(-7). So, replacing the values and solving for r, we get:
\(\begin{gathered} (2.22\times10^{-8})=\frac{(4\pi\times10^{-7})(0.17)}{2\pi r} \\ (2.22\times10^{-8})r=\frac{(4\pi\times10^{-7})(0.17)}{2\pi r}\cdot r \\ (2.22\times10^{-8})r=\frac{4\pi\times10^{-7}(0.17)}{2\pi} \\ (2.22\times10^{-8})r=3.4\times10^{-8} \\ \frac{(2.22\times10^{-8})r}{2.22\times10^{-8}}=\frac{3.4\times10^{-8}}{2.22\times10^{-8}} \\ r=1.56\text{ m} \end{gathered}\)Therefore, the distance is 1.56 m
Vector Mechanics For Engineers Statics and Dynamics (Ferdinand P. Beer, E. Russell Johnston Jr. etc.) solution
The provided information is a book title, "Vector Mechanics for Engineers: Statics and Dynamics," authored by Ferdinand P. Beer, E. Russell Johnston Jr., and others.
This book is a widely used textbook that covers the principles of statics and dynamics in engineering mechanics.
It is commonly used in undergraduate engineering courses to teach students the fundamentals of vector analysis, force systems, equilibrium, and motion of particles and rigid bodies.
The book provides theoretical explanations, example problems, and solutions to help students understand and apply the concepts of engineering mechanics.
While the book contains a comprehensive collection of problems and solutions, the specific details and content of each chapter and section can only be obtained by accessing the book itself.
It is designed to provide a solid foundation in engineering mechanics and serves as a valuable resource for students and professionals in the field of engineering.
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A planes kaverage speed between two cities is 610 km/hr. If the trip takes 2. 25 hrs. How far dose the plane fly
A planes average speed between two cities is 610 km/hr. If the trip takes 2. 25 hrs, then the distance covered by a plane is 1372.5 kilometers.
To calculate the distance the plane flies, we can use the formula:
Distance = Speed × Time
Given that the average speed of the plane is 610 km/hr and the trip takes 2.25 hours, we can substitute these values into the formula to find the distance.
Distance = 610 km/hr × 2.25 hrs
To multiply these values, we need to align the units correctly. By canceling out "hrs" in the numerator and denominator, we get:
Distance = 610 km × 2.25
Multiplying 610 km by 2.25 gives us:
Distance = 1372.5 km
Therefore, the plane flies a distance of 1372.5 kilometers.
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Given that a plane's average speed between two cities is 610 km/hr and the trip takes 2.25 hrs. We are to find the distance covered by the plane The plane flies 1372.5 km
Let's find the solution to this problem .The formula for distance, speed and time isd
= s * there,
d = distance covered by the planes
= speed t
= time taken
Substituting the given values, we have610 × 2.25 = 1372.5 km
Hence, the plane flies 1372.5 km.
Given that a plane's average speed between two cities is 610 km/hr and the trip takes 2.25 hrs. We are to find the distance covered by the plane
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Two charged objects are separated by some distance. The charge on the first object is greater than the charge on the second object. How do the forces that the two objects exert on each other compare
Even though the charge on the first object is greater, the forces that the two objects exert on each other are equal
How could a thermal camera protect a school
during a pandemic?
Answer: A thermal camera could protect the school during the pandemic because you could detect when students may have a fever or even if the student is hot. Being hot or having a fever is a symptom that doesn't always mean you have Co/vid, however, it does mean you are not keeping the school safe. If anyone in the school has a virus and you have a cold or fever this automatically makes the risk of you getting a cold, or even worse like Cov/id-19 higher.
Explanation: please make me brainliest
A balloon is rubbed against a sweater. Which of the following describes the result of this interaction?(1 point)
The outer shell electrons move from the balloon to the sweater.
The fibers of the sweater lose electrons.
The balloon becomes positively charged.
The free electrons in the balloon decreases.
Fibers of the sweater lose electrons because electrons are leave it.
One of the ways of charging a body is by friction. Charges are transferred from one body to another when an object is rubbed against another. This is charging by friction.
A sweater has negative charges hence when the balloon is rubbed against the sweater, fibers of the sweater lose electrons because electrons are leave it.
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what is the upper block's acceleration if the coefficient of kinetic friction between the block and the table is 0.13?
The answer is 2.416 m/s^2.
Solution:
friction force on the upper block = umg
= 0.13*2*9.81
= 2.5506 N
so writing the equation of motion for the upper block
T - f = ma
or T-2.5506 = 2a
writing the equation of motion for the lower block
mg-T=ma
or 9.8-T=a
Hence, we get a = 2.416 m/s^2.
Since the top block slides to the right, the frictional force acting on it acts to the left. His reaction wall acts on the forward-acting lower block. The frictional force absorbs x mechanical energy from the upper block, but transfers only y mechanical energy to the lower block. To find the acceleration of the body in terms of angle and coefficient of friction.
A material modulus value of 1 means that the friction force is equal to the normal force. This means that the force required to move an object is equal to its weight. An object may have a friction value greater than 1. There are two types of friction coefficients: static friction coefficient and dynamic friction coefficient. The former is sometimes called the initial friction coefficient and the latter is sometimes called the dynamic or sliding friction coefficient.
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Explain why the protons can never change for a particular element. What subatomic particles can change and what do they form?
Protons can never change for any particular element because they're in the nucleus and the force keeping them there is extremely strong and hard to overcome. Electrons, however, orbit the nucleus and they change all the time. When electrons either leave or join an atom they form ions.
Positive ions (cations) are when electrons leave, so the positive charge is greater than the negative charges, and negative ions (anions) are when electrons join so the negative charge is greater than the positive charge.
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What nuclear reaction is shown in the equation below
Answer:
nuclear fission
Explanation:
nuclear fission
Answer: Nuclear fission
Explanation:
_______ are measuring tools used to quickly enlarge or reduce drawing measurements.
The blank in the phrase is “The pantographs are measuring tools used to quickly enlarge or reduce drawing measurements”
We use the pantographs when we need to copy, reduce or enlarge drawings and maps achieving greater details. It is a mechanical device made of links that connect one arm of the pantograph to a pointer and the other section contains a drawing component. The scales are reduced or increased by adjusting the arms.
What is scale?It is the relationship between the magnitudes of a drawing model and the actual dimensions of the object.
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True or false: if the magnitudes of both the x- and y-component of a vector are doubled, then the magnitude of the vector is also doubled.
Yes, if the magnitudes of both the x- and y-component of a vector are doubled, then the magnitude of the vector is also doubled. The given statement is true.
In physics, a quantity having both magnitude and direction is called a vector.
A vector is represented by a straight line with an arrow at one end of the line.
Let's say we have a representative vector F.
A representative vector has always its two components Fx and Fy.
A vector can have both magnitude and direction but it has no specific position. It can be drawn in any direction.
There are four vector quantities in physics: force, acceleration, velocity, and displacement.
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It is true that when the magnitude of vectors x and y components are doubled then the magnitude of the vector is also doubled.
For better understanding, lets take an example,
Vector A=5m, 60degrees south of west. So its X-component= 5 x cos60= -4.76
And Y-component= 5 x sin60= -1.52
Now,
doubling the magnitude of vector A will give A=10m , 60degree south of west
Hence X-component= 10 x cos60= -9.52
Now Y-component is 10 x sin60= -3.04
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A lawyer most likely has __________. a.spatial intelligence b.practical intelligence c.analytical intelligence d.creative intelligence
The type of intelligence required by a profession depends on its job description. Lawyers most likes have analytical intelligence.
A renowned psychologist named Howard Gardner devised a theory of multiple intelligence. This means that nobody is really not intelligent because a person must posses one or more of these multiple intelligence.
A lawyer has a lot to do with analytic reasoning and comparison of evidence to determine their validity. This task requires a strong analytical mind hence a lawyer requires analytical intelligence.
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A skydiver that has a weight of 1050 N. jumps from a plane at an altitude of 5000 m. How much work is performed on the skydiver?
Answer:
5.25MJ
Explanation:
Considering the weight of the skydiver constant over the descent -ie, the acceleration of gravity not decreasing as you go up the earth surfice, the work is simply the product of the two:
\(w= \vec F\cdot \vec x = Fx = 1050\times 5000 = 5,250,000 = 5.25MJ\)
_____________ is a measure of the brand's ability to capture consumer preference and loyalty.
Brand equity is a measure of the brand's ability to capture consumer preference and loyalty.
When compared to a generic equivalent, brand equity is the value premium that a firm raises from a product with a successful brand. Companies can build brand equity for their merchandise by making them easily recognizable, memorable, and superior in terms of quality and dependability.
Customers graciously pay a premium for a company's products when it has good brand equity, even if they could purchase the exact thing from a rival for less. Customers effectively pay a high price to do business with a company they know and respect. Because the business with brand equity does not encounter a higher cost than its competitors to create and distribute the product, the price difference goes to their margin.
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What is weightlessness ? Mention its condition
Answer:
Weightlessness, condition experienced while in free-fall, in which the effect of gravity is canceled by the inertial (e.g., centrifugal) force resulting from orbital flight. The term zero gravity is often used to describe such a condition.
what is the separation in meters between two slits for which 604 nm orange light has its first maximum at an angle of 29.2°?
The separation between two slits for which 604 nm orange light has its first maximum at an angle of 29.2° is approximately 1.63 x 10^(-6) meters.
To calculate the separation between the slits, we can use the equation for the position of the first maximum in a double-slit interference pattern:
sin(θ) = mλ / d
where θ is the angle of the maximum, m is the order of the maximum (which is 1 for the first maximum), λ is the wavelength of light, and d is the separation between the slits.
Rearranging the equation, we can solve for d:
d = mλ / sin(θ)
Substituting the given values:
d = (1)(604 nm) / sin(29.2°)
Converting the wavelength to meters (1 nm = 1 x 10^(-9) meters) and performing the calculation, we get:
d ≈ (1)(604 x 10^(-9) meters) / sin(29.2°)
d ≈ 1.63 x 10^(-6) meters
Therefore, the separation between the two slits is approximately 1.63 x 10^(-6) meters.
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A 0.560 kg box slides from rest down a 4.30 m high ramp that forms an isolated system . The energy lost to friction is 1.00 J. What is the speed of the box at the bottom of the ramp? Take the bottom of the ramp as the reference level.
The speed of the box at the bottom of the ramp is 8.98 m/s.
What is speed?Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
The kinetic energy of the box at the bottom of the ramp = (0.560 × 9.8 × 4.30 - 1.0) Joule
= 22.60 joule.
Hence, the speed of the box at the bottom of the ramp = √(2 × 22.60/0.56) m/s
= 8.98 m/s
Therefore, the speed of the box at the bottom of the ramp is 8.98 m/s.
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What is the average velocity.
Answer:
0.10 m/s
Explanation:
The graph appears to be linear, so the velocity is constant and is represented by the slope of the graph. The slope can be calculating by taking any two points and inputting them into the equation: \(\frac{y_2-y_1}{x_2-x_1}\) which is essentially rise/run. In this case the slope is really easy to calculate taking the two points of (0, 0) and (10, 1). In this case you can easily see the rise is 1 and the run is 10. So the slope is 1/10. So the average velocity of the object was 0.10 m/s or 1/10 m/s
lamp power with what is the current through the lamp when it is connected to a battery ?
Answer:
lamp power with what is the current through the lamp when it is connected to a battery ?
Explanation:
If the light bulbs are connected in parallel, the current flowing through the light bulbs combine to form the current flowing in the battery, while the voltage drop is 6.0 V across each bulb and they all glow. One bulb burning out in a series circuit breaks the circuit.
Janice hits a volleyball straight up into the air at 3.4 m/s. Determine the height to which the ball rises above its initial height.
Janice hits a volleyball straight up into the air at 3.4 m/s, then the height of the ball rises above its initial height would be 0.59 meters.
What are the three equations of motion?There are three equations of motion given by Newton,
v = u + at
S = ut + 1/2 × a × t²
v² - u² = 2 × a × s
Note that these equations are only valid for a uniform acceleration.
As given in the problem Janice hits a volleyball straight up into the air at 3.4 m/s,
v = u +at
0 = 3.4 + 9.81× t
t = -3.4 / -9.81
t = 0.3465 seconds
s = ut +0.5at²
=3.4 × 0.3465 + 0.5 × (-9.81) × 0.3465²
=0.59 meters
Thus, the height of the ball rises above its initial height would be 0.59 meters.
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Suzie Skydiver with her parachute has a mass of 46kg. Before opening her chute what force of air pressure will she have when she reaches terminal velocity
Before opening her chute, Suzie Skydiver would experience a force of air pressure of approximately 450 N at terminal velocity.
Terminal velocity is the point where the force of air resistance, or drag, acting on the skydiver becomes equal in magnitude to the force of gravity pulling the skydiver down. At this point, the net force acting on the skydiver is zero, and they fall at a constant velocity. At terminal velocity, Suzie Skydiver is falling at a constant rate, meaning that the force of gravity pulling her down is balanced by the force of air resistance pushing her up.
This force of air resistance, also known as drag, can be calculated using the formula:
F = 1/2 * rho * v^2 * Cd * A,
where F is the force of drag, rho is the density of the air,
v is the velocity of the object,
Cd is the drag coefficient
A is the cross-sectional area of the object.
Assuming that Suzie Skydiver falls in a typical skydiving posture with a drag coefficient of around 1.0 and a cross-sectional area of 1.0 square meter,
Using the standard atmospheric density of 1.2 kg/m³,
We can calculate that her terminal velocity is approximately 54 m/s.
At this velocity, the force of air resistance, or drag, acting on Suzie Skydiver is equal in magnitude to the force of gravity, which is approximately 450 N.
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A steel ball is released just below the surface of thick oil in a cylinder.
During the first few centimetres of travel, what is the acceleration of the ball?
A constant and equal to 10 m / s2
B constant but less than 10 m / s2
C decreasing
D increasing
Answer:
Increasing
Explanation:
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In simple harmonic motion, the speed is zero at that point in the cycle when a. the acceleration is zero. b. the displacement is a maximum. c. the kinetic energy is a maximum. d. the force is zero. e. the potential energy is zero.
In simple harmonic motion, the speed of an oscillating object is zero at the point in the cycle when the acceleration is zero. So the correct answer is a.
This occurs at the extremes of the motion when the object reaches its maximum displacement from the equilibrium position. At these points, the force acting on the object is at its maximum, causing the acceleration to change direction but momentarily reach zero. As the object moves towards the equilibrium position, the force changes direction again, causing the acceleration to increase, and the speed gradually builds up. Therefore, the zero acceleration points in simple harmonic motion correspond to the moments when the speed of the object is momentarily zero. Hence the correct answer is a.
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An electric field exerts force of 2.60 N on a 3.40 x 10-8 C charge. What is the magnitude of the electric field?Group of answer choices7.65 x 107 N/C8.43 x 107 N/C9.05 x 107 N/C12.0 x 107 N/C
ANSWER
\(7.65\cdot10^7N\/C\)EXPLANATION
We want to find the magnitude of the electric field.
To do this, we have to apply the formula for electric field:
\(E=\frac{F}{q}\)where F = force exerted on the charged particle
q = electric charge on the particle
Hence, the magnitude of the electric field is:
\(\begin{gathered} E=\frac{2.60}{3.40\cdot10^{-8}} \\ E=7.65\cdot10^7N\/C \end{gathered}\)The correct answer is the first option.