6. Why would the electrons spend most of their time close to the nucleus?

Answers

Answer 1

Electrons spend most of their time close to the nucleus because they are attracted to the positively charged protons in the nucleus by the electromagnetic force.

This force causes the electrons to move in an orbit around the nucleus, much like planets orbiting around the sun.

The closer an electron is to the nucleus, the stronger the attractive force between them. This results in the electrons being tightly bound to the nucleus, and they tend to spend most of their time in the lowest energy level, known as the ground state. In this state, the electrons are as close to the nucleus as possible, which is why they spend most of their time in that region.

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Related Questions

Two cyclists leave towns 120km apart at the same time and travel toward each other. One cyclist travels 6/kmh faster than the other. If they meet in 3 hours, what is the rate of each cyclist?

Answers

One cyclist is cycling at a speed of 17 km/hr while the other is cycling at a speed of 23 km/hr.

Let's denote the rate of the slower cyclist as "r" km/h. Then the rate of the faster cyclist is "r+6" km/h.

When they are cycling toward each other, their relative speed is the sum of their speeds. Therefore, we can set up the equation:

\(120 \ km = (r + r+6) \ km/h \times 3\) hours  (since together they both travel a total distance of 120 km)

Simplifying this equation:

\(120 \ km = (2r + 6)\  km/h \times 3 \ hours\)

\(40 \ km = (2r + 6) \ km/h\)

\(2r + 6 = 40 \ km/h\)

\(2r = 34 \ km/h\)

\(r = 17 \ km/h\)

So the slower cyclist is cycling at 17 km/h and the faster cyclist is cycling at 17+6=23 km/h.

Therefore, the speeds of cyclists are 17 km/h and 23 km/h.

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Which law or theory is supported by the fact that different frequencies of sound waves maximally deform different parts of the basilar membrane

Answers

The location hypothesis of ears is supported by the observation that distinct sound wave frequencies preferentially deform various regions of the basilar mucosa.

The location hypothesis of hearing is supported by the discovery that different sound wave frequencies maximally deform various regions of the basilar membrane. The membrane that covers the basilar cavity vibrates at various locations, which causes various wavelengths of sound waves to be heard as having distinct pitches. The basilar layer is larger and more flexible towards the helicotrema than it is at its base, which is close to the circular window.

When sound waves enter the inner ear, they cause the basilar membrane to vibrate at different locations depending on their frequency. High-frequency sounds cause maximal vibration near the base of the membrane, while low-frequency sounds cause maximal vibration near the apex. Therefore, the fact that different frequencies of sound waves maximally deform different parts of the basilar membrane provides evidence for the place theory of hearing.

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The Place Theory of hearing is supported by the fact that different frequencies of sound waves maximally deform different parts of the basilar membrane. This principle underlies our perception of pitch and has important implications for the diagnosis and treatment of hearing disorders.

The observation that different frequencies of sound waves maximally deform different parts of the basilar membrane is a fundamental principle in auditory neuroscience and is explained by the Place Theory of hearing. The Place Theory was proposed by Georg von Békésy, a Hungarian biophysicist who won the Nobel Prize in Physiology or Medicine in 1961 for his work on the function of the cochlea.

The cochlea is a spiral-shaped organ in the inner ear that converts sound waves into neural signals that the brain can interpret as sound. The basilar membrane is a long, narrow strip of tissue that runs along the length of the cochlea and vibrates in response to sound waves. The different regions of the basilar membrane are tuned to different frequencies, with high frequencies causing maximum deformation at the base of the membrane and low frequencies causing maximum deformation at the apex.

According to the Place Theory, the perception of pitch is determined by the location along the basilar membrane that is maximally deformed. High-pitched sounds are perceived when the base of the membrane is stimulated, while low-pitched sounds are perceived when the apex is stimulated. This theory has been supported by numerous experiments and has become a cornerstone of our understanding of auditory perception.

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by what factor would a string’s tension need to be changed to raise its fundamental frequency by a perfect fifth?

Answers

To raise the fundamental frequency by a perfect fifth, the tension must increase by a factor of 25.

Fundamental frequency

Since the fundamental frequency of a spring is;

fo= 1/2l√T/M

fo = fundamental frequency

l = length

T = tension

M = mass in kilograms

The fifth overtone  frequency = 5fo

So, the fundamental frequency is proportional to the square root of the tension. Hence, to raise the fundamental frequency by a perfect fifth, the tension must increase by a factor of 25.

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Where in your body do you feel Courage and Why?
(With Explanation)
PLEASE ANSWER IT CORRECTLY I REALLY NEED IT NOW
I'm Giving 15 points

Answers

If you look at courage and if you look at the brain, there is one particular brain structure that plays a very important role when it comes to courage and your own performance. This part of the brain is called the amygdala. The amygdala is a brain structure that is very small, and we have two of them, one of the left side of the brain, one on the right side of the brain. They’re very small and look like an almond. Amygdala is also the Latin word for almond. Even though they are small, they amygdala is also extremely powerful. It plays a very important role in our survival. Whenever there is a real danger outside, it will trigger a fight, flight or freeze response, so you will fight danger, run away, or just be blocked in your own emotions, you will freeze, perhaps you will hide. The amygdala is very important for our survival and for many emotions in general, but in many situations, the amygdala will also become active when there is no real danger, for example, standing on stage and holding a presentation, leading a difficult conversation. These are two examples where there’s no real danger, but nevertheless, the amygdala can be triggered and cause this feeling of nervousness and anxiety. It’s these feelings of nervousness, anxiety or insecurity that will also block us in our potential to hold a presentation or to lead a good conversation.

consider the incompressible flow with velocity components u=(ux / h), v =-(uy / h) where u and h are characteristic velocity and length scales, respectively. determine the acceleration vector ⃗.

Answers

Flow that is incompressible and has components with velocities of u=(ux/h), v=-(uy/h), where u and h are the characteristic velocities the acceleration vector\(-\frac{3^{2} }{2}\)

The movement is bi-dimensional.

Hence, velocity is equal to (dv/dx-du/dy)k, (0-v/h)k, and (-v/h)k.

As the speed is not zero, the flow is rotating.

Yet, the direction of velocity is -v/h.

Fluid particles rotate in a clockwise direction because of the negative velocity.\(-\int\limits^a_b {3x} \, dx\)

Given that v = 3xy + y is the y component

The continuity equation is expressed in differential form as follows for an incompressible flow:

Now, u = - \(\frac{du}{dy} =-\frac{du}{dy}\)

= - \(\frac{du}{dx} =-3x\)

\(-\int\limits^a_b {3} \, dx\)\(\frac{-3x^{2} }{2}\)

is the solution for the velocity's x component.

As a result, the velocity's x component is -\(\frac{3x^{2} }{2}\)

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define Accleration due to gravity​

Answers

Answer:

The acceleration of freely falling bodies due the force of attraction of the other body is called Acceleration due to gravity. It is a constant quantity for a given attracting body at a given place. Like for earth on or near its surface, the average value of acceleration due to gravity is 9.8 m/s2.

Answer: The acceleration de to gravity on eon the moon it has earth has a pull and on the moon it is mass        <3

What element is formed in the following nuclear reaction

What element is formed in the following nuclear reaction

Answers

Answer:

Oxygen or more precisely, the O-15 isotope.

Atoms of which pair of elements will form ionic bonds in a compound?
A. Li and Al
B. C and o
C. Co and Fe
D. K and Br The answer is D

Answers

Answer:

The answer D ...............

Among the given pair of elements potassium (K) and bromine (Br) forms an ionic compound. Thus, option D is correct.

What are ionic compounds?

Ionic compounds between metals and non-metals. Metals are electrons rich and they will easily lose electrons. Non-metals are electron deficient and they easily gain electrons from metals.

The positive charge gained by the metal through electron losing and negative charge of the non-metal will electrostatically attracts each other and form the ionic bond.

Potassium is an alkali metal containing one valence electrons. Bromine contains 7 valence electrons and they need one mole electrons to achieve octet. Thus, K and Br forms an ionic compound.

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An empty cardboard box falls from a high platform. Through the use of special equipment it was found that the energy of the cardboard box at the top of the fall was more than the energy of the box at the bottom of the fall. Explain.

Answers

Answer:

The mechanical energy of the cardboard box, M.E. = K.E. + P.E.

Where;

P.E. = The potential energy of the cardboard box = m·g·h

K.E. = The kinetic energy of the cardboard box = (1/2)·m·v²

Where;

m = Mass of the cardboard box

g = The (constant) acceleration due to gravity ≈ 9.81 m/s²

h = The height of the cardboard box

v = The velocity of the cardboard box

At the top of the fall, where h = The height of the platform = \(h_{platform}\), and v = 0 (the box is initially at rest at the top), the M.E. is given as follows;

\(M.E._{top}\) = P.E. + K.E. = m·g·\(h_{platform}\) + (1/2) × m × 0² = m·g·\(h_{platform}\)

However, at the bottom of the fall, the height of the box, h = 0, the velocity of the box, v = 0, therefore, the total energy at the bottom, after the box comes to rest, \(M.E._{bottom}\) = 0

Therefore;

The total energy of the box at the top of the fall, .\(M.E._{top}\) = m·g·\(h_{platform}\) was more than the total energy of the box at the bottom of the fall,

\(M.E._{bottom}\) = 0

Explanation:

Find the formula and scientific units of the following:

Speed =

Velocity =

Momentum =

Velocity =

Acceleration =

Force =

Answers

Answer:

speed :m/s

velocity:m/s-¹

acceleration:m/s²

force:kgms-²

Explanation:

I hope May be correct

Speed: It is the rate at which object covers or travelled particular distance or rate at which objects changes its position. S.I. unit for speed is metre per second (m/s).

Speed (s) = distance (d) / time (t)

Velocity: Distance covered by a moving object in a particular direction per unit time. S.I. unit of velocity is m s-1 or m/s.

Velocity (v) = Total displacement (d) / time take(t)

Momentum: It is quanity of motion of the object. S.I. Unit is Kg.m.s-1

Momentum (p) = Mass (m) X Velocity (v)

Acceleration: Rate at which an object velocity changes with respect to time. S.I. unit is metres/second2 (m/s2) Acceleration (a) = Change in velocity/ time taken

Force: When an object changes it position or direction due to external agent. S.I. unit of force is (Kg m/s2).

Force (F) = Mass(m) × Acceleration (a)

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An object on a rope is lowered at a steadily decreasing speed. Which is true? A. The rope tension is greater than the object's weight. B. The rope tension equals the object's weight C. The rope tension is less than the object's weight. D. The rope tension can't be compared to the object's weight.

Answers

As the object is being lowered at a steadily decreasing speed, the rope tension equals the object's weight (Option B).

According to Newton's second law of motion, net force is equal to mass multiplied by acceleration. Therefore, as the net force is decreasing, the acceleration of the object is also decreasing. Eventually, the object will reach a point where its weight and the tension in the rope will be equal and opposite, resulting in a zero net force and zero acceleration. At this point, the object will continue to be lowered at a constant speed. Therefore, the correct answer is the rope tension equals the object's weight.

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g what is the ideal banking angle (in degrees) for a gentle turn of 1.40 km radius on a highway with a 105 km/h speed limit (about 65 mi/h), assuming everyone travels at the limit?

Answers

To calculate the ideal banking angle for a gentle turn

The ideal banking angle for a gentle turn of radius R, with velocity v, and coefficient of friction µ between the road and the tires can be calculated by the formula:

Tan(θ) = (v^2) / (gR)

where g is the acceleration due to gravity = 9.81 m/s²

θ is the banking angleIn this problem,

the radius of the gentle turn is R = 1.40 km = 1400 m

The speed limit is v = 105 km/h = 29.1667 m/s

Applying the formula,

Tan(θ) = (29.1667 m/s)^2 / (9.81 m/s² x 1400 m)

= Tan(θ) = 0.41435θ

= Tan^-1(0.41435)θ = 21.25°

Therefore, the ideal banking angle (in degrees) for a gentle turn of 1.40 km radius on a highway with a 105 km/h  speed limit (about 65 mi/h), assuming everyone travels at the limit is 21.25 degrees.

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in each of the cases that follow, the magnitude of a vector is given along with the counterclockwise angle it makes with the x axis. use trigonometry to find the x and y components of the vector.

Answers

To find the x and y components of a vector given its magnitude and angle with the x-axis, trigonometry can be used.

When dealing with vectors, it is often useful to break them down into their x and y components to analyze their effects in different directions. To determine the x component of a vector, the magnitude of the vector is multiplied by the cosine of the angle it makes with the x-axis. Mathematically, the x component (Vx) can be expressed as Vx = V * cos(θ), where V represents the magnitude of the vector and θ represents the angle.

Similarly, the y component of the vector (Vy) can be found by multiplying the magnitude of the vector by the sine of the angle. Mathematically, Vy = V * sin(θ), where V is the magnitude of the vector and θ is the angle it makes with the x-axis.

By using trigonometric functions to compute the x and y components of a vector, we can gain insight into the effect of the vector in different directions. These components make vectors easier to analyze and manipulate, making them valuable tools for a variety of mathematical and scientific applications.

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I need help with question 7, I just need the answer you don’t have to explain.

I need help with question 7, I just need the answer you dont have to explain.

Answers

\(\begin{gathered} a=5.703\text{ }\frac{m}{s^2} \\ T=3.891\text{N} \end{gathered}\)

Explanation

Step 1

free body diagram

so, for m1

m1= 10 kg

so,

\(\begin{gathered} \sum ^{forces}_{\text{ y}}=T_1-mg=ma \\ T_1=m_1(a+g)\Rightarrow equation(1) \\ T_1=10(a+g) \end{gathered}\)

and for m2

\(\begin{gathered} \sum ^{forces}_{\text{ x}}=m_2g\sin (37)-T_1=m_2a \\ \text{solve for T}_1 \\ T_1=m_2g\sin (37)-m_2a \\ \text{replace} \\ T_1=(3.6\text{ kg)(9.8 }\frac{m}{s^2})\sin 37-3.6a \\ T_1=21.23\text{ -}3.6a\Rightarrow eq(2) \end{gathered}\)

Step 2

now, replace in equaiotn (1) and solve for a

\(\begin{gathered} T_1=m_1(a+g)\Rightarrow equation(1) \\ 21.23\text{ -}3.6a=10(a+g) \\ 21.23\text{ -}3.6a=10a+10g \\ -7.2a=10a-98.1 \\ -17.2a=-98.1 \\ a=-\frac{98.1}{-17.2} \\ a=5.703\text{ }\frac{m}{s^2} \end{gathered}\)

finally, replace in equation (2) to find Tension

\(\begin{gathered} T_1=21.23\text{ -}3.6a \\ T_1=21.23\text{ -}3.6(5.703) \\ T_2=3.891\text{N} \end{gathered}\)

I hope this helps you

I need help with question 7, I just need the answer you dont have to explain.

12 A car travels in a straight line at speed v along a horizontal road. The car moves
against a resistive force F given by the equation
F = 400+kv²
where F is in newtons, v in ms-1 and k is a constant.
At speed v = 15ms-1, the resistive force F is 1100 N.
a
Calculate, for this car:
i the power necessary to maintain the speed of 15ms-¹,
ii the total resistive force at a speed of 30 ms-¹,
iii the power required to maintain the speed of 30ms-¹.

Answers

Answer:

i) Power = Force * Velocity = 1100 * 15 = 16500 W = 16.5 kW(ii)  Find the value of k first: F = 400 + k(15^2)                                              k = 28/9    F = 400 +(28/9)(30^2) = 320

Explanation:

a. The power necessary to maintain the speed of 15ms^-1 can be found using the equation for power, P = Force * velocity, where P is in watts, force is in newtons and velocity is in meters per second. Substituting the values given in the question, we get:

P = (400 + k * 15²) * 15
P = (400 + 11250) * 15
P = 11650 Watts

Therefore, the power necessary to maintain the speed of 15ms^-1 is approximately 11650 Watts.

b. The total resistive force at a speed of 30ms^-1 can be found by substituting 30 for v in the force equation:

F = 400 + k * 30^2

F = 12000 N

Therefore, the total resistive force at a speed of 30ms^-1 is approximately 12000 N.

c. The power required to maintain the speed of 30ms^-1 can be found using the same equation as in part a:

P = (400 + k * 30^2) * 30
P = (1500 + 600000) * 30
P = 625000000 Watts

Therefore, the power required to maintain the speed of 30ms^-1 is approximately 625000000 Watts. This is a very large amount of power and would require a significant amount of energy to maintain.

A solar-powered car has a kinetic energy of 110250 J. Its mass is 180 kg. Work out how fast the car is travelling Enter a number m/s​

Answers

Answer: Velocity = v = 35 m/s

Explanation:

Kinetic energy of an object is defined as the energy possess by an object due to its motion. Kinetic energy K.E of an object is equal to the half of the mass of that object multiplied by square of the object's velocity.

Mathematically,

v = 35 m/s

A solar-powered car has a kinetic energy of 110250 J. Its mass is 180 kg. Work out how fast the car is

An AP oblique shoulder projection (Grashey method) obtained with the patient rotated less than required to obtain accurate positioning demonstrates
1. more than 0.25 inch (0.6 cm) of the coracoid superimposed over the humeral head.
2. a closed glenohumeral joint.
3. increased longitudinal clavicular foreshortening.
4. an increase in the amount of thorax and scapular body superimposition.

Answers

The AP oblique shoulder projection (Grashey method) obtained with insufficient patient rotation is being discussed, and we need to determine which of the given statements is true based on the findings.

When the patient is rotated less than required in an AP oblique shoulder projection (Grashey

method), several key observations can be made. Firstly, the coracoid superimposed over the humeral head by more than 0.25 inch (0.6 cm). This indicates an inaccurate positioning due to inadequate rotation, resulting in the coracoid appearing closer to the humeral head than it should be. Secondly, there is an increased amount of thorax and scapular body superimposition. This means that the structures of the thorax and scapular body overlap more than they should, further confirming the inaccurate positioning caused by insufficient patient rotation.

Based on these observations, the true statement about the AP oblique shoulder projection obtained with inadequate patient rotation is that there is more than 0.25 inch (0.6 cm) of coracoid superimposed over the humeral head, and there is an increase in the amount of thorax and scapular body superimposition. These findings highlight the inaccurate positioning of the shoulder joint due to insufficient patient rotation, leading to overlapping of the coracoid and increased superimposition of thoracic and scapular structures.

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can someone pls help me with this?

can someone pls help me with this?

Answers

C because they are both going in a constant speed

8. An object has a force applied. The object has a mass of 36 Kg and accelerates at 3.4 m/sec2. What is the force acting on the object? *
a. 120.6 N
b. 126.9 N
c. 122.4 N
d. 118.3 N

Answers

Answer:

122.4

Explanation:

answer asap
please i need help

answer asapplease i need help

Answers

2, 3, and 5

....................

Can the sun explain global warming? ( 2 points) Suppose that the Earth has warmed up by 1 K in the last hundred years. i) How much would the solar constant have to increase to explain this? ii) Compare this to the observed fluctuation of the solar constant over the past 400 years (shown in class) For part (i), begin with the standard 'blackbody' calculation from class, that is: set α=0.30, and assume that the Earth acts as a blackbody in the infrared.

Answers

No, the sun cannot explain global warming. Global warming is a phenomenon in which the temperature of the Earth's surface and atmosphere is rising continuously due to human activities such as deforestation, burning of fossil fuels, and industrialization.

This increase in temperature cannot be explained only by an increase in solar radiation.There are several factors which contribute to global warming, including greenhouse gases such as carbon dioxide, methane, and water vapor. These gases trap heat in the Earth's atmosphere, which causes the planet's temperature to rise. The sun's radiation does contribute to global warming, but it is not the main cause.

i) To calculate the increase in solar radiation that would cause the Earth to warm up by 1 K, we can use the following formula:ΔS = ΔT / αWhere ΔS is the increase in solar constant, ΔT is the increase in temperature, and α is the Earth's albedo (reflectivity).α = 0.30 is the standard value used for the Earth's albedo.ΔS = ΔT / αΔS = 1 K / 0.30ΔS = 3.33 W/m2So, to explain the increase in temperature of 1 K over the last hundred years, the solar constant would need to increase by 3.33 W/m2.

ii) The observed fluctuation of the solar constant over the past 400 years has been around 0.1% to 0.2%. This is much smaller than the 3.33 W/m2 required to explain the increase in temperature of 1 K over the last hundred years. Therefore, it is unlikely that the sun is the main cause of global warming.

The sun cannot explain global warming. While the sun's radiation does contribute to global warming, it is not the main cause. The main cause of global warming is human activities, particularly the burning of fossil fuels, which release large amounts of greenhouse gases into the atmosphere.

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If you double the distance between you and the center of Earth, what happens to the strength of the gravitational field you experience?

Answers

Answer:

The strength of gravity decreases.

An example of that would be if you were in space; you float around because there's no gravity.

A 0.060 kg ball hits the ground with a speed of –32 m/s. the ball is in contact with the ground for 45 milliseconds and the ground exerts a 55 n force on the ball. what is the magnitude of the velocity after it hits the ground? 9.3 m/s 12 m/s 41 m/s 73 m/s

Answers

Answer:

Approximately \(9.3\; {\rm m\cdot s^{-1}}\).

Explanation:

Apply unit conversion:

\(t = 45\; {\rm ms} = 45 \times 10^{-3}\; {\rm s}\).

At a velocity of \(v\), the momentum \(p\) of an object of mass \(m\) would be \(p = m\, v\).

Initial momentum of this ball:

\(\begin{aligned}p_{0} &= m\, v_{0} \\ &= 0.060\; {\rm kg} \times (-32\; {\rm m\cdot s^{-1}}) \\ &= (-1.92\; {\rm kg \cdot m \cdot s^{-1}})\end{aligned}\).

When a constant force \(F\) is exerted on an object for a duration of length \(t\), the impulse \(J\) applied to that object would be \(J = F\, t\).

Impulse that the ground applied to this ball:

\(\begin{aligned}J &= F\, t \\ &= 55\; {\rm N} \times (45 \times 10^{-3}\; {\rm s}) \\ &= 2.475\; {\rm N \cdot s}\end{aligned}\).

Note that \(1\; {\rm N} = 1\; {\rm kg \cdot m \cdot s^{-2}}\). Thus, the impulse applied to this ball would be equivalent to:

\(\begin{aligned}J &= 2.475\; {\rm (kg \cdot m \cdot s^{-2}) \cdot s} \\ &= 2.475\; {\rm kg \cdot m \cdot s^{-1}}\end{aligned}\).

After this impulse was applied, the momentum of this ball would become:

\(\begin{aligned}p_{1} &= p_{0} + J \\ &= (-1.92\; {\rm kg \cdot m \cdot s^{-1}}) + 2.475\; {\rm kg \cdot m \cdot s^{-1}} \\ &= 0.555\; {\rm kg \cdot m \cdot s^{-1}}\end{aligned}\).

The new velocity of this ball would be:

\(\begin{aligned}v_{1} &= \frac{p_{1}}{m} \\ &= \frac{0.555\; {\rm kg \cdot m \cdot s^{-1}}}{0.060\; {\rm kg}} \\ &\approx 9.3\; {\rm m\cdot s^{-1}}\end{aligned}\).

Answer:

(A)

Explanation:

I took the test

which chemical reaction is fastest

which chemical reaction is fastest

Answers

B        BRIANLIEST PLS

Explanation:

What 3 things do you need to make an electromagnet ?

Answers

Answer:

1. Battery

2. Copper wire

3. Nail or piece of metal (zinc, iron, or steel).

Answer:

magnet coppers wire and piece of metals

Friction slows airflow over the rough surface of land or water.True or False

Answers

The statement is True. Friction does slow down airflow over the rough surface of land or water. The presence of rough surfaces creates resistance, causing the air or water to encounter more obstacles and disruptions in its flow, leading to a reduction in speed.

Friction refers to the resistance encountered when one object moves against another. In the context of airflow over land or water, friction occurs due to the interaction between the air or water molecules and the rough surface. When the surface is rough, such as a land surface with vegetation or a water surface with waves, the airflow encounters more resistance, resulting in a decrease in speed.

The rough surface of land or water disrupts the smooth flow of air or water molecules. As the molecules interact with the uneven surface, they experience a drag force, which slows down their movement. This slowing of airflow is an effect of friction, which plays a significant role in various natural phenomena, including the movement of air and water over different types of surfaces.

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a small boy is thrown staight up by his father .at the top of his path .he comes to rest for a moment will he be in equilibrium at this point

Answers

At the top of his path, he comes to rest for a moment but he will not be in equilibrium at this point.

No, the boy is not in equilibrium. At the moment at which the boy is released from his father's grip, he is not in equilibrium.

Being in equilibrium means that the net force on the body is zero. When we talk about net force, it means that the net acceleration should be zero. But when the boy is released into the air, the boy's velocity will become zero at the highest point, but the acceleration is never zero. The velocity of the body has nothing to do with the equilibrium of the body.

The earth is constantly applying gravitational force to the body.

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Which of the following is most likely to make it safer while lighting the rocket?
A. decreasing the size of the cap
B. increasing the length of the fuse
C. increasing the length of the body
D. decreasing the length of the stick

Answers

While lighting the rocket you should ensure D) decreasing the length of the stick

What are the precautions you should take while lighting the rocket?

When lighting fireworks, avoid holding them in your hand or placing any part of your body over them. Don't carry fireworks in your pocket since the friction could set them off; instead, use eye protection. Keep pyrotechnics away from flammable objects, such as brush, leaves, and dwellings.

The continuous smoke from cracker explosions may sting or wet the eyes. Because bottle rockets are thought to be the riskiest cracker type, it's crucial to avoid them, keep a safe distance from the burning crackers, wear safety goggles, and avoid wearing contact lenses while popping crackers.

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Compare the current in the 8-ohm resistors to the current in the 4-ohm resistors.

Compare the current in the 3-ohm and 8-ohm resistor to the current in the 10-ohm resistor

Answers

Answer:

a)   i₈ = 0.5 i₄,  b)   i₁₀ = 0.3 i₃,    i₁₀ = 0.8 i₈

Explanation:

For this exercise we use ohm's law

       V = i R

        i = V / R

we assume that the applied voltage is the same in all cases

let's find the current for each resistance

         

R = 4 Ω

         i₄ = V / 4

R = 8 Ω

         i₈ = V / 8

we look for the relationship between these two currents

         i₈ /i₄ = 4/8 = ½

         i₈ = 0.5 i₄

R = 3 Ω

        i₃ = V3

R = 10 Ω

         

        i₁₀ = V / 10

   

we look for relationships

       i₁₀ / 1₃ = 3/10

       i₁₀ = 0.3 i₃

       i₁₀ / 1₈ = 8/10

       i₁₀ = 0.8 i₈

two simple pendulums, a and b, are each 10.0 m long, and the period of pendulum a is t. pendulum a is twice as heavy as pendulum b. what is the period of pendulum b?

Answers

The period of pendulum b is 4.02 seconds, which is shorter than the period of pendulum a since pendulum b has half the mass and therefore half the gravitational force acting on it.

The period of a simple pendulum is affected by its length and the gravitational force acting on it, which is determined by the mass of the pendulum. In this scenario, pendulum a and b have the same length, but pendulum a is twice as heavy as pendulum b. This means that pendulum a will have a longer period than pendulum b since its greater mass increases the gravitational force acting on it.

To determine the period of pendulum b, we can use the equation T=2π√(L/g), where T is the period, L is the length, and g is the acceleration due to gravity. Since the length of both pendulums is 10.0m, we can ignore that variable. However, the gravitational force acting on pendulum b will be half that of pendulum a since it has half the mass. Therefore, we can use the same equation with half the value of g, which gives us T=2π√(10.0/4.9) = 4.02 seconds (rounded to two significant figures).

So, the period of pendulum b is 4.02 seconds, which is shorter than the period of pendulum a since pendulum b has half the mass and therefore half the gravitational force acting on it.

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