6. When can you say that an object is accelerating?
A. when the speed remains the same
B. When the speed is changing
C. when the instantaneous velocity is the same
D. When there is a uniform motion

give explanation ​

Answer:

Explanation:

1. The waves in which the partciles of medium vibrates in the same direction of propagation of wave, are called longitudinal waves.

The waves in which the partciles of medium vibrates in the perpendicular direction of propagation of wave, are called transverse waves.

2. Period, T = 0.03 s

The frequency is given by the reciprocal of the period.

\(f=\frac{1}{T}\\\\f =\frac{1}{0.03}\\\\f = 33.3 Hz\)

1. Transverse waves carry molecules at right angles to the direction in which the wave travels. Within a cycle, molecules move from their normal position to the highest position, back through the normal position to the lowest point, and then back to the normal position. The molecules retain their horizontal positions while vibrating vertically. Amplitude is measured at right angles to the direction of the travel of the wave. Wavelength can be represented as the distance between any two molecules in phase with each other, such as the two nearest molecules at the crests of the wave.

Longitudinal waves carry molecules parallel to the direction in which the wave travels. Within a cycle, a molecule travels in the same direction as the wave (from normal position to its most distant point on one side of its normal position), changes direction, moves back through its normal position to the opposite side of its normal position at a point that corresponds, and then returns to its normal position. The molecules don’t all move at the same time; some remain stationary as others go through a vibrating motion. Compressions and rarefactions occur here. Amplitude is measured parallel to the direction of the wave. Wavelength may be represented as the distance between the two nearest molecules that didn’t vibrate, the two nearest molecules at maximum compression, or the two nearest molecules at maximum rarefaction.

2. f = 1⁄T  

f = 1⁄0.03

f = 33. 3 Hz

3. The first wave has a frequency of 33.3 Hz:

f1 = 1⁄T1

f1 = 1⁄0.03

f1 = 33. 3 Hz

The second wave has a frequency of 4 Hz. f2 = 1⁄T2

f2 = 1⁄1⁄4

f2 = 1 ÷ 1⁄4

f2 = 1 × 4⁄1

f2 = 1⁄1 × 4⁄1

f2 = 4 Hz

Therefore, the first wave has a higher frequency.

4. v = I⁄T

v= 4.5⁄0.007

v = 642.9 m/s

5. Wavelength

Crest

Trough

Amplitude

Watching Gladiators was a a favorite pastime of Roman civilization. It was a game based on the Roman martial ethics. It lasted for nearly thousands of years. Hence option C is correct.

An armed warrior known as a gladiator amused spectators in the Roman Republic and Roman Empire by engaging in bloody fights with other gladiators, wild animals, and condemned prisoners.

Some gladiators were unpaid volunteers who jeopardized their lives as well as their position in society and the law by participating in the fight. The majority endured severe education, were treated like inferiors in society, and were separated even in death.

Regardless of where they came from, gladiators served as a living example of Rome's martial virtues to onlookers, and by fighting or dying honorably, they may win adulation and widespread renown.

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your answer is going to be False

The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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Answer:

electrical transfers into mechanical energy Explanation:

The ranking is based on the tilt of the Earth's axis and its orbit around the Sun. The figure at 40°N in June receives the most daylight because it is located at a high latitude during the summer solstice in the Northern Hemisphere. The Earth's axis tilts towards the Sun, resulting in longer days and shorter nights. The figure at 40°S in December receives a moderate amount of daylight as it is located at a lower latitude during the summer solstice in the Southern Hemisphere.

The figure at 40°N in December experiences less daylight because it is located at a high latitude during the winter solstice in the Northern Hemisphere, with shorter days and longer nights. Lastly, the figure at 40°S in June receives the least amount of daylight as it is located at a lower latitude during the winter solstice in the Southern Hemisphere, where the days are shortest and the nights are longest. Based on the information given, the ranking of figures based on the amount of daylight they experience in a 24-hour period, from most to least.

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The magnitude of the angular acceleration of the roller is approximately 108.8 rad/s².

To find the magnitude of the angular acceleration of the roller, we can use the rotational analog of Newton's second law: τ = Iα, where τ is the torque, I is the moment of inertia, and α is the angular acceleration.

First, let's calculate the moment of inertia of the roller. The moment of inertia of a solid cylinder rotating about its central axis is given by the formula: I = (1/2)mr², where m is the mass and r is the radius.

Given:

Mass of the roller (m) = 2.4 kg

Radius of the roller (r) = 3.8 cm = 0.038 m

Moment of inertia (I) = (1/2) * 2.4 kg * (0.038 m)² = 0.0021744 kg·m²

Next, we need to calculate the torque (τ) applied to the roller. Torque is given by the formula: τ = rFsin(θ), where r is the distance from the axis of rotation to the point of application of the force, F is the magnitude of the force, and θ is the angle between the force and the line connecting the axis of rotation and the point of application.

Given:

Force applied (F) = 16 N

Angle (θ) = 35°

Distance from the axis of rotation to the point of application (r) is equal to the radius of the roller, so r = 0.038 m.

Torque (τ) = (0.038 m) * (16 N) * sin(35°) = 0.2366 N·m

Now, we can use the equation τ = Iα and solve for the angular acceleration (α):

0.2366 N·m = (0.0021744 kg·m²) * α

α = 0.2366 N·m / 0.0021744 kg·m² ≈ 108.8 rad/s²

Therefore, the magnitude of the angular acceleration of the roller is approximately 108.8 rad/s².

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Any weapon that loads its bullet and propellant charge from the muzzle is referred to as a muzzleloader. This is separate from the more advanced and complex current breech-loading weapon designs.

Simply said, a muzzle loader is a firearm that loads through the muzzle and is generally lengthy. A spring-loaded arm that hits a replaceable piece of flint on a metal plate to produce sparks, which ignite the gunpowder and light the gun, is the firing mechanism known as a flintlock.

French artist and inventor Marin Le Bourgeoys, who flourished in the Renaissance from 1550 to 1634, is credited with creating the muzzle-loaded rifle.

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Since no work is done, the power exerted is zero. Therefore, the man exerts no power on the wall.

In physics, force is defined as any action that can change the motion of an object or cause an object to accelerate. Force is a vector quantity, meaning that it has both magnitude (size or strength) and direction. The unit of force in the International System of Units (SI) is the Newton (N), which is defined as the amount of force required to accelerate a mass of one kilogram at a rate of one meter per second squared (1 N = 1 kg × 1 m/s^2). Force can be measured using a variety of instruments, such as spring scales, strain gauges, or force plates. Some common types of forces include gravitational force, electromagnetic force, frictional force, and normal force. The study of forces and their effects on the motion of objects is known as mechanics and is a fundamental concept in physics.

Here,

a. The man does not do any work on the wall because the wall does not move. Work is only done when there is a displacement in the direction of the force applied.

b. Since no work is done, no energy is used or transferred.

c. The power exerted by the man can be calculated using the formula:

Power = Work / Time

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Answer:

W = 181.26 J

Explanation:

Given that,

The force acting on the cart, F = 20 N

It is at an angle of 25 degrees above the horizontal to  move a crate a distance of 10m across the floor.

We need to find work done by the student. The work done by the student is given by :

\(W=Fd\cos\theta\\\\W=20\times 10\times \cos25\\W=181.26\ J\)

So, the required work done is 181.26 J.

1. The time taken for the object to reach the ground is 2.47 s

2. The speed with which the object will reach the ground is 26.206 m/s

1. How do I determine the time taken?

We can obtain the time taken for the object to reach the ground as      follow:

h = ½gt²

30 = ½ × 9.8 × t²

30 = 4.9 × t²

Divide both side by 4.905

t² = 30 / 4.9

Take the square root of both side

t = √(30 / 4.9)

t = 2.47 s

Thus, the time taken to reach the ground is 2.47 s

2. How do i determine the speed?

The speed the object will use to reach the ground can be obtained as follow:

v = u + gt

v = 2 + (9.8 × 2.47)

v = 2 + 24.206

v = 26.206 m/s

Thus, the speed is 26.206 m/s

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ANSWER

3. 5.93432

EXPLANATION

The pans are 67.6cm apart. If the fulcrum was centered, the distance from each pan to the fulcrum would be,

Now, the fulcrum was moved 0.974cm towards one of the pans,

The new distances are,

When the shopkeeper weighs the products, the balance is in equilibrium. This means that the torque each weight produces must be equal,

The relationship between the forces is,

Replace with the distances,

Now we have to find the percent change,

Hence, the true weight of the goods is being marked up by 5.93432%.

Answer:

a

Explanation:

..................

Answer:

In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.

In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.

The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.

So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.

Using the formula for the Doppler effect:

f' = (v + vr) / (v + vs) * f

Given:

Source frequency (horn): f = 625 Hz

Speed of sound: v = 343 m/s (approximate value at room temperature)

The velocity of the receiver, vr, is zero because the person waiting at the crosswalk is stationary.

The velocity of the source, vs, is the speed of the car, which is given as 9.0 m/s.

Thus:

f' = (v + vr) / (v + vs) * f

= (343 m/s + 0) / (343 m/s + 9.0 m/s) * 625 Hz

= (343 m/s) / (352 m/s) * 625 Hz

≈ 609 Hz

Therefore, the person waiting at the crosswalk hears a frequency of approximately 609 Hz.

(2)Using the same Doppler effect formula:

f' = (v - vr) / (v - vs) * f

In this case, the velocity of the receiver, vr, is still zero because the person remains stationary.

The velocity of the source, vs, is now negative, indicating that the car is moving away from the person.

Thus:

f' = (v - vr) / (v - vs) * f

= (343 m/s + 0) / (343 m/s - (-9.0 m/s)) * 625 Hz

= (343 m/s) / (352 m/s) * 625 Hz

≈ 609 Hz

In other words, as the car moves away from the person, they would still hear a frequency of approximately 609 Hz.

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Answer:

24.132 m/s

Explanation:

Note

\(U\) = Initial Velocity

\(U_x\) = Initial Horizontal Velocity

\(U_y\) = Initial Vertical Velocity

\(V\) = Final Velocity

\(V_x\) = Final Horizontal Velocity

\(V_y\) = Final Vertical Velocity

\(B\) = launch angle

\(g\) = gravity

\(t\) = time

\(U_x=U*cos(B)\)

\(U_y=U*sin(B)\)

The horizontal component of the velocity is constant throughout the flight. So \(U_x=V_x\) It can be defined as

\(V_x=U*cos(B)\)

We can use the kinematics equation

\(V=U+at\)

Gravity is acting downwards; gravity would be negative

\(V_y=U_y-gt\)

The magnitude of the velocity can be defined as

\(V=\sqrt{V_x^2+V_y^2}\)

Inserting some of the other equations gives us an equation at a given time (t).

\(V=\sqrt{(U*cos(B))^2+(U*sin(B)-gt)^2}\)

\(V=\sqrt{(UcosB)^2+(UsinB)^2+(gt)^2-2gtU*sinB\)

\(V=\sqrt{U^2+g^2*t^2-2*t*g*U*sinB}\)

\(V(t)=\sqrt{U^2+g^2t^2-2tgUsinB}\)

We are given

\(U=34.6\)

\(B=80.2\)

\(t=1.09\)

\(g=9.81\)

\(V(1.09)=\sqrt{34.6^2+9.81^2*1.09^2-2*1.09*9.81*34.6*sin80.2}\)

\(V(1.09)=\sqrt{34.6^2+114.338-2*1.09*9.81*34.6*sin80.2}\)

\(V(1.09)=\sqrt{34.6^2+114.338-739.94868*sin80.2}\)

\(V(1.09)=\sqrt{34.6^2+114.338-729.151}\)

\(V(1.09)=\sqrt{1197.16+114.338-729.151}\)

\(V(1.09)=\sqrt{582.347}\)

\(V(1.09)=24.132\)

A rating/review would be much appreciated. Hope this helps!

Let me know if you have any questions about my work

Surface tension is the energy required to increase the surface area of a liquid.  Option (b)

Surface tension is the propensity of liquid surfaces at rest to shrink to the smallest feasible surface area. Surface tension permits items with a higher density than water, such as razor blades and insects (such as water striders), to float on the water's surface without being immersed.

Surface tension at liquid-air contacts is caused by the higher attraction of liquid molecules to each other (owing to cohesion) than to air molecules (due to adhesion).There are two main systems at work. The first is an inward strain on the surface molecules, which causes the liquid to constrict.

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The magnitude of the acceleration  of the engine that must be produced is 0.068 m/s².

The magnitude of the acceleration of the engine is calculated by applying the following kinematic equation.

s = vt + ¹/₂at²

where;

The acceleration of the engine in x direction is calculated as follows;

( 3.71 x 10⁸ x cos 46 ) = ( 1670 x cos73 )(8.64 x 10⁴) + ¹/₂ (ax)(8.64 x 10⁴)²

2.58 x 10⁸ = 4.22 x 10⁷ + 3.73 x 10⁹ax

3.73 x 10⁹ax = 2.16 x 10⁸

ax = ( 2.16 x 10⁸ ) / ( 3.73 x 10⁹ )

ax = 0.058 m/s²

The acceleration of the engine in y direction is calculated as follows;

( 3.71 x 10⁸ x sin 46 ) = ( 1670 x sin73 )(8.64 x 10⁴) + ¹/₂ (ay)(8.64 x 10⁴)²

2.67 x 10⁸ = 1.38 x 10⁸ + 3.73 x 10⁹ay

3.73 x 10⁹ay = 1.29 x 10⁸

ay = ( 1.29 x 10⁸ ) / ( 3.73 x 10⁹ )

ay = 0.035 m/s²

The magnitude of the acceleration  of the engine that must be produced is calculated as;

a = √ ( ax² + ay² )

a = √ ( 0.035² + 0.058² )

a = 0.068 m/s²

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Explanation:

The answer is (C) \(^{111}_{\:40}\text{Zr}\)

Answer:

ultraviolet light

plz mark me as brainliest.

Answer:

Ultra violet

Explanation:

Answer:

it is my first time to login on brainly thats why i didnt answer your question

The balloon sticks to wall due to electrostatic force

What is electrostatic force?

Electrostatic forces are attractive or repulsive forces between particles that are caused by their electric charges. This force is also called the Coulomb force or Coulomb interaction and is so named for French physicist Charles-Augustin de Coulomb, who described the force in 1785.

The electrostatic force acts over a distance of about one-tenth the diameter of an atomic nucleus or 10-16 m. Like charges repel one another, while unlike charges attract one another. For example, two positively charged protons repel each other as do two cations, two negatively charged electrons, or two anions. Protons and electrons are attracted to each other and so are cation and anions

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Answer:

192.6N

Explanation:

Let's consider the forces acting on the beam:

Weight of the beam (W): It acts vertically downward and has a magnitude of W = mass * gravitational acceleration = 39.4 kg * 9.8 m/s^2.

Force exerted by the link on the beam (F_link): It acts at an angle of 90 degrees with respect to the beam and has two components: the vertical component and the horizontal component.

Tension in the cable (T): It supports the far end of the beam and acts at an angle of 90 degrees with respect to the beam. Since the angle between the beam and the cable is 90 degrees, the tension in the cable only has a vertical component.

Let's break down the forces acting on the beam:

Vertical forces:

W (weight of the beam) - T (vertical component of tension) = 0

T = W

Horizontal forces:

F_link (horizontal component of the force exerted by the link) = ?

To find the magnitude of the horizontal component of the force exerted by the link on the beam (F_link), we need to consider the equilibrium of forces in the horizontal direction.

Since the beam is inclined at an angle of θ = 33.1 degrees with respect to the horizontal, the horizontal equilibrium equation can be written as:

F_link = W * sin(θ)

Let's substitute the given values:

W = 39.4 kg * 9.8 m/s^2

θ = 33.1 degrees

F_link ≈ (39.4 kg * 9.8 m/s^2) * sin(33.1 degrees)

Using a calculator, we find that the magnitude of the horizontal component of the force exerted by the link on the beam (F_link) is approximately 192.6 N.

Answer:

answer is a very large amount of energy is produced from a very small mass

Explanation:

nuclear energy is produced either by fusion or fission the former is fusion of lighter atoms into heavier elements while the letter is the splitting of a heavier atom into lighter atoms. both produce tremendous amount of energy fusion causes compassion of mass wild fission reduces it. and produce it. fusion does not produce radioactive particles while fission does (alpha and beta particles and neutrons)

Answer:

5.0 x 10^8

Explanation:

because u moved it 8 times to it places

The frequency of the wave is 0.625 waves per second, calculated by dividing the number of waves (10) by the time (16.0 seconds).

To determine the frequency of a wave, you need to divide the number of waves (in this case, 10) by the time it takes for those waves to pass a certain point (in this case, a dock) within 16.0 seconds.

Frequency is usually measured in Hertz (Hz), which represents the number of cycles or events per second. So, to find the frequency, we calculate 10 waves / 16.0 seconds = 0.625 waves per second or 0.625 Hz.

This means that every second, 0.625 waves pass by the dock, giving you the frequency of the wave.

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Answer:

198785.714286 Joules

Explanation:

\(W=f*d\)

\(F=ma\\F=516.326530612*-14\\F=-7228.57142857 N\\\)

To find work:

Now that the force and the distance are known, plug and chug:

\(W=f*d\\W=-7228.57142857*27.5\\W=-198785.714286J\)

Note that the question is asking for the magnitude of work, so the negative can be discarded as it is a directional component.

So, your answer is

198785.714286 Joules

A column of water that is 10.2 m tall would yield same pressure at the bottom as a column of mercury that is 0.76 m tall, assuming that vacuum could be maintained at the top of water column.

In chemistry, pressure refers to the amount of force exerted per unit area by a gas, liquid or solid on surface.

a. The pressure at the bottom of a column of mercury that is 0.76 m tall is given by:

pressure = density x gravity x height

So, pressure at the bottom of column of mercury is:

pressure = (1.36 x 10⁵ N/m³) x (9.81 m/s²) x (0.76 m)

= 9.98 x 10⁵ N/m²

b. pressure = density x gravity x height

height = pressure / (density x gravity)

height = (9.98 x 10⁵ N/m²) / (1.00 x 10⁴ N/m³ x 9.81 m/s²)

= 10.2 m

So, column of water that is 10.2 m tall would yield same pressure at the bottom as column of mercury that is 0.76 m tall, assuming that vacuum could be maintained at the top of water column.

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Conociendo la longitud y frecuencia de un péndulo, queremos encontrar la longitud de otro pendulo de tal forma que tenga otra frecuencia.

Veremos que la longitud del nuevo péndulo debe ser 6.25m

Sabemos que un péndulo de 4m de longitud tiene una frecuencia de 5Hz.

La frecuencia de un péndulo está dada por:

\(f = \frac{1}{2*\pi} *\frac{g}{l}\)

Donde g es la aceleración gravitatoria y l es la longitud del péndulo, remplazando los datos que tenemos en esa ecuación obtenemos:

\(5 Hz = \frac{1}{2*3.14} *\sqrt{\frac{g}{4m} } \\\\(5Hz*2*3.14)^2*4m = g = 3,943.8 m/s^2\)

Ahora debemos encontra la longitud de tal forma que la frecuencia sea 4Hz, entonces debemos resolver:

\(4Hz = \frac{1}{2*3.14} *\sqrt{ \frac{3943.8m/s^2}{l} }\\\\4hz*2*3.14 = \sqrt{ \frac{3943.8m/s^2}{l} }\\\\l =\frac{3943.8m/s^2}{ (4hz*2*3.14)^2} = 6.25m\)

La longitud del nuevo péndulo deve ser 6.25m

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Answer:

it is double the temperature change of iron