6. The petrol in a petrol can weighs 2000g. The density of petrol is 0.8g/cm3.
What is the volume of the petrol in the can in a) cm3 b)litres (1000cm3=1 litre)

Pls help :((

Answers

Answer 1

Answer:

a. 2500 cm³.

b. 2.5 litres.

Explanation:

Given the following data:

Density = 0.8g/cm³

Mass = 2000g

To find the volume of the petrol;

Density can be defined as mass all over the volume of an object.

Simply stated, density is mass per unit volume of an object.

Mathematically, density is given by the equation;

\(Density = \frac{mass}{volume}\)

Making volume the subject of formula, we have;

\(Volume = \frac{mass}{density}\)

Substituting into the equation, we have:

\(Volume = \frac{2000}{0.8}\)

Volume = 2500 cm³

a. The volume of the petrol in the can in cubic centimeters (cm³) is 2000.

b. The volume of the petrol in the can in litres;

1000 cm³ = 1 litre

2500 cm³ = x litres

Cross-multiplying, we have;

1000x = 2500

x = 2500/1000

x = 2.5 litres.

Therefore, the volume of the petrol in the can in litres is 2.5.


Related Questions

construction worker Bob IS standing at the top of a slanted rooftop when he accidentally drops & orange from his lunch bag; The orange rolls down the rool, which i> angled at 0 28,58 relative t0 Ihe harizontal as shown the figure below The bottom edge of the roofus meters above Ihe ground. Ihe orarge leaves the right edge ol Ihe rooftop with velocity 0l Ti 4.471,how fal, Arto the right of the roof edge does his 8 meter tall fellow consiruction warker Werdy have sland on the ground 50 that the orange just barely passes over her head? [Figure not diawn t0 scalel Imapa *x4: ALhae

Answers

Wendy must stand 1.19m to the left of the edge of the roof so that the orange just barely passes over her head.

Bob's orange will travel down the slanted roof with a velocity of 4.47 m/s, and it will hit the ground 3.0 m below the edge of the roof. The height of the orange above the ground at the edge of the roof is 1.8 m, and the angle of the roof is 28.5° relative to the horizontal.

To calculate the distance Ar that Wendy has to stand from the edge of the roof, we must first calculate the time it takes for the orange to reach the ground. Using the equation for the vertical displacement of an object with an initial velocity, we can solve for the time, t:

d = v*t - (1/2)*g*t^2

0 = 4.47*t - (1/2)*9.8*t^2

t = 0.938s

Next, we must calculate the horizontal displacement of the orange from the time, t. Using the equation for the horizontal displacement of an object with an initial velocity and a constant acceleration we can solve for the displacement:

x = v*t + (1/2)*a*t^2

x = 4.47*0.938 + (1/2)*0*0.938^2

x = 4.19m

To calculate the distance Ar that Wendy must stand from the edge of the roof, we must subtract the horizontal displacement of the orange from the height of the edge of the roof:

Ar = 3.0 - 4.19

Ar = -1.19m

Therefore, Wendy must stand 1.19m to the left of the edge of the roof so that the orange just barely passes over her head.

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construction worker Bob IS standing at the top of a slanted rooftop when he accidentally drops &

7. A rock of mass 5 kg is pushed over the edge of a cliff which is 200 m high. a) Ignore air resistance and calculate the speed of the rock at the bottom of the cliff. In reality, air resistance cannot be ignored. The rock eventually reaches terminal velocity of 30 m.s-¹.
b) Calculate the kinetic energy of the rock at the bottom of the cliff.
c) Calculate the work done by air resistance.
d) Calculate the average force exerted by the air on the rock.​

Answers

Speed of the rock at the bottom of the cliff is 44.3 m/s.

Kinetic energy of the rock at the bottom of the cliff is 4915 J.

Work done by air resistance is -2250 J

Average force exerted by the air on the rock is 11.25 N.

How to determine kinetic energy and speed?

a) The speed of the rock at the bottom of the cliff can be calculated using the equation:

v = √(2gh)

where v = final velocity, g = acceleration due to gravity (9.81 m/s²), and h = height of the cliff (200 m).

Plugging in the values:

v = √(2 x 9.81 x 200) = 44.3 m/s

Therefore, the speed of the rock at the bottom of the cliff is 44.3 m/s.

b) The kinetic energy of the rock at the bottom of the cliff can be calculated using the equation:

KE = (1/2)mv²

where KE = kinetic energy, m = mass of the rock (5 kg), and v = velocity (44.3 m/s).

Plugging in the values:

KE = (1/2) x 5 x (44.3)² = 4915 J

Therefore, the kinetic energy of the rock at the bottom of the cliff is 4915 J.

c) The work done by air resistance can be calculated using the work-energy principle:

Work done by air resistance = KE_initial - KE_final

where KE_initial = initial kinetic energy of the rock, and KE_final = final kinetic energy of the rock (at terminal velocity).

Since the rock was initially at rest, its initial kinetic energy is zero. At terminal velocity, the kinetic energy of the rock is:

KE_final = (1/2)mv_terminal²

where m = mass of the rock (5 kg), and v_terminal = terminal velocity (30 m/s).

Plugging in the values:

KE_final = (1/2) x 5 x (30)² = 2250 J

Therefore, the work done by air resistance is:

Work done by air resistance = 0 - 2250 = -2250 J

The negative sign indicates that the work done by air resistance is in the opposite direction to the motion of the rock.

d) The average force exerted by the air on the rock can be calculated using the equation:

Work done by air resistance = Force x Distance

where Force = average force exerted by air on the rock, and Distance = distance travelled by the rock.

Rearrange the equation to solve for Force:

Force = Work done by air resistance / Distance

Plugging in the values:

Force = -2250 / 200 = -11.25 N

Therefore, the average force exerted by the air on the rock is 11.25 N. The negative sign indicates that the force is in the opposite direction to the motion of the rock.

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I’ve been struggling with this question, help!

Ive been struggling with this question, help!

Answers

The masses of the two objects MA and MB in the binary system are 4 Mo respectively.

How can the masses of the binary systems be calculated?

The masses of binary systems can be calculated using Kepler's laws of planetary motion and observations of the system.

Let's denote the masses of the two objects as MA and MB, where MA is the mass of object A and MB is the mass of object B. We know that the total mass of the binary system is 8 Mo, so:

MA + MB = 8 Mo

We also know that the ratio of the distances between the two objects is 1/3. Let's denote the distance between the two objects as d, so we have:

d(A to B) / d(Binary System) = 1/3

We can simplify this equation by using the fact that the distances between the objects and the binary system add up to the total distance between the objects:

d(A to B) + d(B to binary system) = d(Binary system)

Since we know the ratio of the distances, we can substitute 1/3d for d(B to binary system):

d(A to B) + 1/3d = d(Binary system)

3d(A to B) + d = 3d(Binary system)

Substituting d(A to B) for d(Binary system) - d(B to binary system), we get:

3d(A to B) + d = 3(d(A to B) + d(B to binary system))

2d(A to B) = 2d(B to binary system)

d(A to B) / d(B to binary system) = 1

So the two objects are at the same distance from the binary system center of mass. This means that the masses of the two objects are equal:

MA = MB

Substituting this into the first equation, we get:

2MA = 8 Mo

MA = MB = 4 Mo

Therefore, the mass of each object is 4 Mo.

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A plate of iron at 20 °C has shown in the figure below. If the temperature
raised to 100 °C and the coefficient of linear expansion of iron is 1.1 x 10-7 o
1, then what is the final area of the plate?
(5
2 m
2 m

Answers

The final area of the plate is 4.0000352 \(m^2\) if the temperature raised to 100 °C and the coefficient of linear expansion of iron is 1.1 x 10-7.

Expecting that the plate of iron is rectangular, we can involve the recipe for warm extension of solids to compute the last region of the plate. The equation for direct warm development is given by ΔL = αLΔT, where ΔL is the adjustment of length, α is the coefficient of straight extension, L is the first length, and ΔT is the adjustment of temperature.

Since the region of the plate is given by A = L*W, where L is the length and W is the width, we can involve the equation for straight warm extension to compute the adjustment of length of the plate and afterward use it to compute the last region.

ΔL = αLΔT = \((1.1 x 10^-7 m/oC)(2 m)(80 oC) = 1.76 x 10^-5 m\)

The last length of the plate is L + ΔL = 2 m + 1.76 x \(10^-5\) m = 2.0000176 m (approx.)

The last width of the plate is thought to be unaltered as it isn't impacted by the adjustment of temperature.

Thusly, the last region of the plate is A = L*W = (2.0000176 m)(2 m) = 4.0000352 \(m^2\) (approx.)

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Replace the incandescent bulb with the Voltage meter and return loop # to 3. What happens when you move the bar magnet back-n-forth through the loop? Does this appear to be creating a Direct Current or an Alternating Current? How do you know?

Answers

If we replace the incandescent bulb with a voltage meter and return the loop to its original configuration, then moving the bar magnet back and forth through the loop will induce an electrical current in the loop, as described by Faraday's law of electromagnetic induction.

What is magnet?

A magnet is a material or object that produces a magnetic field, which is a force that can attract or repel certain other materials, such as iron or steel. The magnetic field is created by the motion of electric charges within the magnet, which align in such a way that they produce a net magnetic field. Magnets can be made from a variety of materials, including iron, cobalt, nickel, and certain alloys. They come in many different shapes and sizes, including bars, discs, horseshoes, and rings.

Here,

The type of current that is generated depends on the direction and rate of the magnet's motion. If the magnet is moved back and forth with a constant speed and in a straight line, the current induced in the loop will be an alternating current (AC), because the direction of the current will reverse every time the magnet changes direction. This can be observed by the voltage meter reading a voltage that periodically changes in direction.

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when a hurricane moves onto land, it rapidly declines because of friction and lack of warm, moist air. t/f

Answers

False, supposedly when a hurricane moves ashore, it quickly rises due to friction and a lack of warm, moist air.

Hurricanes are known as cyclones as well as typhoons in other tropical regions. Typhoons are one of the most disturbing types of natural disasters at the moment.

Scientifically, the cause of hurricanes from warm water, warm moist air, and light upper-level winds as the primary ingredients of their formation.

Typhoons have other terms, depending on where they occur. the scientific term for a hurricane is a tropical cyclone. Only tropical cyclones that form over the Atlantic Ocean or the eastern Pacific Ocean are called "hurricanes".

The cause of a hurricane occurs when a warm, moist air mass from the sea surface begins to rise rapidly and collides with a colder air mass. The friction pushes the warm water vapor to condense. During the condensation process, latent heat is emitted.

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The answer is D can someone please explain why. Question 8 btw

The answer is D can someone please explain why. Question 8 btw

Answers

Answer:

Resistance, R = 60 Ohms

Explanation:

Given the following data;

For the first heater;

Voltage, V = 120 V

Resistance, R = 15 Ohms

For the second heater;

Voltage, V = 240 V

To find the resistance in the second heater;

First of all, we would determine the power rating of the heaters using the formula below;

Power = voltage²/resistance

Power = 120²/15

Power = 14400/15

Power = 960 Watts

Next, we find the resistance in the second heater;

Power = V²/R

960 = 240²/R

Cross-multiplying, we have;

960R = 57600

R = 57600/960

R = 60 Ohms

Which of the following is NOT a characteristic of science?
Group of answer choices

Predictions must be testable through observations or experiments.

The results of repeated observations or experiment are more or less the same.

Science is subject to revision and correction based on new observations

It appeals to authority to establish its validity.

Answers

Answer:

C

Explanation:

it is C because science is an acquiring and defining of knowledge.

A 208g sample of sodium-24 decays to 13.0g of sodium-24 within 60.0 hours. What is the half life of this radioactivity isotope?

Answers

Answer:

15 hours

Explanation:

formula: f(a) = a(0.5)^(T/t)

fill in known values: 13=208(0.5)^(60/t)

use natural log to isolate t:    ln(13/208)=ln(0.5)(60/t)

solve for t: t=15

5 When a salmon swims up a river to breed, it often has to jump up waterfalls. Fig. 3.1 shows a salmon jumping above the surface of the water. On this occasion the salmon falls back down into the river. waterfall Fig. 3.1 river salmon The salmon has a mass of 2.0 kg. (a) The salmon leaves the water vertically with a kinetic energy of 16.2J. (i) Calculate the speed of the salmon as it leaves the water.
speed=​

Answers

Speed = Distance/ time. Kinetic energy is 1/2 mv2. The kinetic energy is 16.2 J.

Thus, A fundamental idea in physics known as kinetic energy quantifies the work done by an object as a result of its motion. It is essential to our comprehension of many commonplace actions like walking, jumping, and throwing as well as more complicated events like falling.

We shall examine the definition, units of measurement, examples, and transformations of the notion of kinetic energy in this article. Additionally, we will develop the kinetic energy equation and look at how it relates to other types of energy.

We'll also look at the many kinds of kinetic energy and talk about the difference between kinetic and potential energy.

Thus, Speed = Distance/ time. Kinetic energy is 1/2 mv2. The kinetic energy is 16.2 J.

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54:29
Mason notices that his boat sinks lower into the water in a freshwater lake than in the ocean. What could explain
this?
The boat is more dense in salt water.
The boat is less dense in salt water.
Salt water is less dense than freshwater
O Salt water is more dense than freshwater
Save and Exit
Sube
Mark this and retum

Answers

Answer:

Salt water is more dense than freshwater

Explanation:

The only and best explanation for this phenomenon for this occurrence is that salt water is more dense than freshwater.

Density is the mass per unit volume of a substance. When a substance is A more dense than the other substance B, B will float on A. So, the density of the salt water is higher than that of the fresh water because it has more particles per unit volume compared to fresh water. Therefore, the boat will go farther into the fresh water compared to the salt water.

Explain the differences between getting burned by fire and getting burned by dry ice?
Need it ASAP

Answers

Getting burned by fire is different than dried ice because Ice is cold and would give you a bruise .
Hope this helps!


please help with my physics homework

please help with my physics homework

Answers

Answer:

The graph data expresses the data started high up and moved into a continuous reaction before slowly decreasing and hit a point, where it remained the same.

Select a track. Select the initial velocity as 12 m/s and the cart mass as 300 kg. At what point in time is the kinetic energy of the roller coaster cart maximum? Explain.

Answers

The kinetic energy of a roller coaster cart is at its maximum when the cart has its maximum velocity.

Where does kinetic energy occur?

The point in time when this occurs will depend on the specific track and design of the roller coaster. Typically, the maximum velocity of a roller coaster cart is achieved at the bottom of a hill or after descending from a drop.

This is because the potential energy of the cart is converted into kinetic energy as it gains speed due to the force of gravity. As the cart descends, its potential energy decreases while its kinetic energy increases. The maximum kinetic energy is reached when all of the potential energy has been converted into kinetic energy, which occurs at the bottom of the hill or after descending from a drop.

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A 90 kg man stands in a very strong wind moving at 17 m/s at torso height. As you know, he will need to lean in to the wind, and we can model the situation to see why. Assume that the man has a mass of 90 kg, with a center of gravity 1.0 m above the ground. The action of the wind on his torso, which we approximate as a cylinder 50 cm wide and 90 cm long centered 1.2 m above the ground, produces a force that tries to tip him over backward. To keep from falling over, he must lean forward.
A. What is the magnitude of the torque provided by the wind force? Take the pivot point at his feet. Assume that he is standing vertically. Assume that the air is at standard temperature and pressure.
B. At what angle to the vertical must the man lean to provide a gravitational torque that is equal to this torque due to the wind force?

Answers

Answer:

a)  \(t=195.948N.m\)

b)  \(\phi=13.6 \textdegree\)

Explanation:

From the question we are told that:

Density \(\rho=1.225kg/m^2\)

Velocity of wind \(v=14m/s\)

Dimension of rectangle:50 cm wide and 90 cm

Drag coefficient \(\mu=2.05\)

a)

Generally the equation for Force is mathematically given by

\(F=\frac{1}{2}\muA\rhov^2\)

\(F=\frac{1}{2}2.05(50*90*\frac{1}{10000})*1.225*17^2\)

\(F=163.29\)

Therefore Torque

\(t=F*r*sin\theta\)

\(t=163.29*1.2*sin90\)

\(t=195.948N.m\)

b)

Generally the equation for torque due to weight is mathematically given by

\(t=d*Mg*sin90\)

Where

\(d=sin \phi\)

Therefore

\(t=sin \phi*Mg*sin90\)

\(195.948=833sin \phi\)

\(\phi=sin^{-1}\frac{195.948}{833}\)

\(\phi=13.6 \textdegree\)

help please i’m stuck

help please im stuck

Answers

Answer:

no entiendo el inglés soryyy

The answer is direction and magnitude

Do this question by electric flux
A conducting sphere of radius 10cm has an unknown charge. If the electric field 20 cm from the centre of the sphere is \(1.5*10^{3}\) N/C and points radially inwards what is the net charge on the sphere.

Answers

Answer:

To find the net charge on the sphere using electric flux, we can use the formula:  

Φ = Q/ε0

Where Φ is the electric flux, Q is the charge, and ε0 is the permittivity of free space.  

Given that the electric field 20 cm from the center of the sphere is N/C and points radially inwards, we can use the formula for electric field due to a charged sphere to find the charge on the sphere:

E = kQ/r^2  

Where E is the electric field, k is Coulomb's constant, Q is the charge, and r is the distance from the center of the sphere.  

Substituting the given values, we get:  

20 = (1/4πε0)(Q)/(0.2)^2  

Solving for Q, we get:  

Q = (20)(0.2)^2(4πε0)  

Q = 0.64πε0 C  

Now, substituting this value of Q in the formula for electric flux, we get:  Φ = Q/ε0 = (0.64πε0)/(ε0) = 0.64π C  

Therefore, the net charge on the sphere is 0.64π C.

Two cylinders P and Q are made of copper
P
The height of P is twice the height of Q. The diameter of P is half the diameter of
Which statement is comrect?
A The density of cylinder Pis four times that of cylinder o
The density of cylinder Pis twice that of cylinder
The density of cylinder P is equal to that of cylinder Q
The density of cylinder P is half that of cylinder o
с
D​

Answers

Let H and D denote the height and diameter, respectively, of cylinder P, and h and d the height and diameter of cylinder Q.

Then the volumes of P and D, denoted V and v, respectively, are

V = π (D / 2)² H = π D ² H / 4

v = π (d / 2)² h = π d ² h / 4

The height of P is twice the height of Q, so H = 2h.

The diameter of P is half the diameter of Q, so D = d / 2.

Substitute these into equation for the volume of cylinder P:

V = π (d / 2)² (2h) / 4

V = π (d ² / 4) (2h) / 4

V = π d ² h / 8

V = 1/2 • π d ² h / 4

V = v / 2

That is, cylinder P has half the volume of cylinder Q.

Recall that density is equal to mass per unit of volume. So R and ρ, the respective densities of cylinders P and Q, are

R = m / V = m / (v / 2) = 2 m / v

ρ = m / v

which means cylinder P has twice the density of cylinder Q (assuming both cylinders have the same mass m).

The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?

Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.

Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!

Answers

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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which is a property of bases?​

Answers

Answer:

to turn red litmus blue and react with acid to form salt

An aeroplane is circling above an airport in a horizontal circle at a speed of 400 kmh-1.The banking angle of the wings is 20.What is the radius of the circular path?

Answers

Answer: the radius of the circular path is approximately 1637.58 meters.

Explanation:

The centripetal force acting on the airplane is provided by the component of the gravitational force that acts towards the center of the circular path. This component is given by:

F_c = m * g * tan(banking angle)

Where:

F_c is the centripetal force

m is the mass of the airplane

g is the acceleration due to gravity

tan(banking angle) is the tangent of the banking angle

Now, the centripetal force is also given by the formula:

F_c = (m * v^2) / r

Where:

v is the speed of the airplane

r is the radius of the circular path

Equating the two expressions for F_c, we get:

(m * g * tan(banking angle)) = (m * v^2) / r

Canceling out the mass (m) on both sides of the equation, we have:

g * tan(banking angle) = v^2 / r

Solving for r, we get:

r = (v^2) / (g * tan(banking angle))

Substituting the given values:

v = 400 km/h = 400,000 m/h

g = 9.8 m/s^2

banking angle = 20°

Converting the speed to m/s:

v = 400,000 m/h * (1/3600) h/s = 111.11 m/s

Converting the banking angle to radians:

banking angle = 20° * (π/180) rad/° = 0.3491 rad

Now, substituting the values into the formula:

r = (111.11^2) / (9.8 * tan(0.3491))

r ≈ 1637.58 meters

Therefore, the radius of the circular path is approximately 1637.58 meters.

What happens to your kinectic energy when your gravitational potential energy decreases?

Answers

Answer:

As r decreases, we lose gravitational potential energy - in other words, U G U_G UG​U, start subscript, G, end subscript becomes more negative. Because energy is conserved, the velocity must increase, resulting in an increase in kinetic energy.

Explanation:

A marathon runner runs at a steady 15 km/hr. When the runner is 7.5 km from the finish, a bird begins flying from the runner to the finish at 30 km/hr. When the bird reaches the finish line, it turns around and flies back to the runner, and then turns around again, repeating the back-andforth trips until the runner reaches the finish line. How many kilometers does the bird travel?

Answers

Answer:

The value is \(D =  15 \  km \)

Explanation:

From the question we are told that

   The  speed of the marathon runner is  \(v = 15 \ km /hr\)

   The distance from the distance from the finish is  \(d =  7.5 \  km\)

   The  speed of the bird is  \(v_b  =  30 \ km / hr\)

  Generally the time taken for the runner to reach the finish is mathematically represented as

       \(t =  \frac{d}{v}\)

       \(t =  \frac{7.5}{15}\)

        \(t =  \frac{1}{2}\)

So the distance covered by the bird is  

      \(D =  v_b  *  t\)

      \(D =  30  *  \frac{1}{2}\)

         \(D =  15 \  km \)

Dựa vào môi trường hoạt chất, laser được phân thành

Answers

Answer:

ok

Explanation:

Consider two simple pendula. Pendulum 1 has a length of L and a bob mass of m. Pendulum 2 has a length of 4L and a bob mass of 4m. If the period of pendulum 1 is 4 seconds, then the period of pendulum 2 is...


2 s
16 s
1 s
8 s

Answers

Answer:

8s

Explanation:

period of pendulum = 2π*√(l/g)

l = length of pendulum

period for 1st pendulum = 4 sec

thats 2π*√(l/g) = 4

for 2nd pendulum

length = 4 l

substitute 4l in formula

2π*√4l/g = 2*4= 8s

Given the data from the question, the period of the pendulum 2 is 8 s

Data obtained from the questionLength of pendulum 1 (L₁ ) = LPeriod of pendulum 1 (T₁ ) = 4 sLength of pendulum 2 (L₂) = 4LPeriod of pendulum 2 (T₂) = ?

How to determine the period of pendulum 2

The period of pendulum 2 can be obtained as illustrated below:

T²₁ / L₁ = T²₂ / L₂

4² / L = T²₂ / 4L

Cancel out L

4² = T²₂ / 4

Cross multiply

T²₂ = 4² × 4

T²₂ = 64

Take the square root of both sides

T₂ = √64

T₂ = 8 s

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High-power experimental engines are being developed by the Stevens Motor Company for use in its new sports coupe. The engineers have calculated the maximum horsepower for the engine to be 630HP
. Twenty five engines are randomly selected for horsepower testing. The sample has an average maximum HP of 650
with a standard deviation of 60HP
. Assume the population is normally distributed.
Step 1 of 2 : Calculate a confidence interval for the average maximum HP for the experimental engine. Use a significance level of α=0.01
. Round your answers to two decimal places.

Answers

The 99% confidence interval for the average maximum HP for the experimental engine is (610.12, 689.88).

To calculate the confidence interval for the experimental engines' average maximum HP, we can use the following formula:

To find the z-score for α=0.01, we can refer to a standard normal distribution table or use a calculator. The z-score is approximately 2.58.

Substituting the given values into the formula, we get:

CI = 650 ± 2.58*(60/√25) CI = 650 ± 30.96

Rounding to two decimal places, the confidence interval for the experimental engines' average maximum HP is:

CI = [619.04 HP, 680.96 HP]

Therefore, we can say with 99% confidence that the true average maximum HP for the experimental engines falls between 619.04 HP and 680.96 HP. Thus, we can conclude that the experimental engines' average maximum HP is likely to be within this range. However, note that this range does not include the manufacturer's claimed maximum HP of 630 HP, which may indicate that the engines are performing below expectations.

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A gun whose mass is 0.8 kg fires a bullet
whose mass is 0.016 kg with a velocity of
700 ms Calculate the velocity of the gun's
recoil​

Answers

Answer:

14m/s

Explanation:

As per Newton's third law, the momentum of the bullet firing will equal the momentum of the guns recoil:

\(m_{g}v_{g} = m_{b}v_{b}\)

(.8)v=(.016)(700)

v=11.2/0.8

v=14m/s

Please help if you can’t see the picture well I can type it out

Please help if you cant see the picture well I can type it out

Answers

Given that : magnitude of vector is 85 units and angle is 11 degree

X-component of vector is 85 cos (11 degree) = 83.385

which can be approximated as 83 units

Y-component of vector is 85 sin (11 degree) = 16.21

which can be approximated as 16 units

Thus, value of x component is 83 units and y-component is 16 units.

Which of the following are true for Martin and his brother?

Answers

Answer:

All the statements above are true for martin and his brother in the book "My Brother Martin".

The late Dr. Martin Luther King Jr.'s older sister and renowned educator Christine King Farris collaborate with renowned illustrator Chris Soentpiet to tell this "outstanding" (School Library Journal) and motivational tale of how a boyhood event sparked a movement that would alter the course of history. In "My Brother Martin," Martin Luther King tells us what it was like to be a young kid of seven. Martin Luther King Jr. was a little boy who played jokes, practised the piano, and made friends without taking race into consideration long before he rose to fame as a global visionary.

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in a typical cop movie we see the hero pulling a gun firing that gun straight up into the air and shouting

Answers

It is not recommended to fire a gun straight up into the air.

When a bullet is fired into the air, it will eventually come down and can pose a danger to people and property below. The bullet can still be lethal when it reaches the ground, especially if it lands on a hard surface or hits someone directly.

Additionally, firing a gun in a residential area can be illegal and can result in legal consequences. In general, guns should only be fired in designated shooting ranges or in self-defense situations where there is an immediate threat to life. It is important to handle firearms responsibly and follow all safety guidelines to prevent accidents and injuries.

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