6. Makes sure that oxygen is absorbed into
the blood.
a. Circulatory System
b. Digestive System
c. Respiratory System
d. Excretory System

Answer:

Saliva contains amylase which helps digest starch .

Explanation:

you should've googled it instead of waiting 10,000 years for someone to answer. but sometimes googling doesn't always give you the answer you want

The approximate resistance value at 45 degrees Celsius is around 5.8 ohms.

To calculate the value of the resistance temperature coefficient at 45 degrees Celsius using linear approximation, we can use the formula:

R(T) = R0 + α(T - T0),

where R(T) is the resistance at temperature T, R0 is the resistance at a reference temperature T0, α is the resistance temperature coefficient, and (T - T0) is the temperature difference.

Given that the resistance at 25 degrees Celsius is 5 ohms (R0 = 5) and the resistance at 50 degrees Celsius is 6 ohms (R(T) = 6), we can calculate the value of α.

6 = 5 + α(50 - 25),

Simplifying the equation:

1 = 25α,

Therefore, α = 1/25 = 0.04 ohm/degree Celsius.

Using the linear approximation, we can approximate the value of the resistance at 45 degrees Celsius:

R(45) = 5 + 0.04(45 - 25) = 5 + 0.04(20) = 5 + 0.8 = 5.8 ohms.

Therefore, the value of the resistance at 45 degrees Celsius is approximately 5.8 ohms.

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In a reaction sequence involving an alkyne and reagents, step 1) deprotonates the alkyne using a strong base, then forms a new carbon-carbon bond with an electrophilic alkene, and lastly adds an alcohol across the double bond via oxymercuration-demercuration. The major product is an alcohol, but its specific structure depends on the starting materials.

The given reaction sequence involves the following steps:

NaNH₂

Eti H-C=C—H

HgSO₄, H2SO₄, H2O, R-OH

Step 1) involves the treatment of an alkyne with NaNH₂, which is a strong base. The base will deprotonate the alkyne to form an anion.

Step 2) involves the reaction of the alkyne anion with Eti H-C=C—H. The alkyne anion acts as a nucleophile and attacks the electrophilic alkene, forming a new carbon-carbon bond.

Step 3) involves the addition of HgSO₄, H2SO₄, H₂O, and an alcohol (R-OH). This reaction is known as oxymercuration-demercuration and involves the addition of a mercuric acetate (Hg(OAc)₂) across the double bond of the alkene. This forms a mercurinium ion, which is then attacked by water in a nucleophilic addition reaction. Finally, the mercuric acetate is removed by reaction with sodium borohydride, resulting in the formation of the alcohol product.

The major product expected from this reaction sequence is the alcohol formed in step 3). The specific structure of the alcohol cannot be determined without more information about the starting materials.

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Complete question :

Choose the major product that is expected for the following reaction sequence: 1) NaNH₂ 2) Eti H-C=C—H 3) HgSO H₂SO₄ H₂0 R 0. OH

Answer:

(2-)

Explanation:

the compounds 0(2-) is the stable

Answer:

15g

Explanation:

First, you need to correct the answer to the previous question. The percentage by mass of Mg in MgO =

Mg = 24.3 amu

O = 16.0 amu

The total mass of MgO = 40.3 amu

To calculate the percent composition of Mg:

% = 24.3/40.3 x 100

% = 60

To calculate the mass of Mg needed to make 25g of MgO:

x/25g = 60%/100%

100x = (25)(60)

100x = 1500

x = 15g

Answer: Exothermic: combustion, condensation, neutralization. Endothermic: photosynthesis, evaporation, ionic dissociation of salts

Explanation:

The pH of methylene blue stain can affect the staining of bacteria. When prepared as a basic stain, methylene blue binds to acidic components of bacterial cells, resulting in a blue color. When prepared as an acidic stain, methylene blue binds to basic components of bacterial cells, resulting in a red or pink color.

Methylene blue is a common biological stain that is used to visualize bacterial cells under a microscope. The pH of the stain can affect how it interacts with bacterial cells and how the cells appear when viewed under a microscope.

When prepared as a basic stain, methylene blue has a positive charge and binds to acidic components of bacterial cells, such as nucleic acids and acidic polysaccharides.

This results in a blue coloration of the cells, making them easier to visualize and differentiate from other cells or debris on the slide.

On the other hand, when methylene blue is prepared as an acidic stain, it has a negative charge and binds to basic components of bacterial cells, such as proteins and basic polysaccharides.

This results in a red or pink coloration of the cells. The choice of stain depends on the type of bacteria being visualized and the specific components of the cells that need to be highlighted.

In general, basic stains like methylene blue are more commonly used for bacterial staining due to their ease of use and consistent results.

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Biological specimens are the preserved remains of the biological materials. Compound A. formaldehyde or formalin is used to preserve the specimens. Thus, option A is correct.

Fluid preserved specimens are the biological material of the organism that are kept at the store to study and analyze over a long time without getting any damage. Formaldehyde along with alcohol is the most common preservative.

Formaldehyde is an organic compound that is colorless and pungent in the smell that preserves the dead remains of the organisms intact. It is antiseptic and germicide in nature that makes them best for the purpose.

Therefore, option A. formaldehyde is used to preserve the specimens.

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Answer:

so i put a...

Explanation:

Edge doesnt give correct answers on unit tests, but i passed with an 88 :)

Correct me if im wrong!!

The connection between the reactant and product concentrations at equilibrium is expressed by the equilibrium constant or K value. An equilibrium product concentration greater than the reactant concentration is indicated by a K value greater than 1. Option 3 is correct.

The present concentration of the reactants is greater than the concentration of the products when Q is less than 1. In order to reach equilibrium and boost the product concentration, the reaction must go to the right.  Because the concentration of the products is already greater than the concentration of the reactants, the reaction is not in equilibrium and cannot move to the leftThe correct option is 3.

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To solve this problem, we need to use the formula: moles of electrons = (current × time) / (charge of one electron × Faraday's constant). So, approximately 7.46 × 10^-4 mol of electrons travel through the copper wire during the 118 seconds.

First, let's convert the current to units of Amperes:
610. mA = 0.610 A
Next, we need to know the charge of one electron, which is -1.602 × 10^-19 Coulombs.
Finally, we need to know Faraday's constant, which is 96,485 Coulombs per mole of electrons.
Now, we can plug in the values and solve for moles of electrons:
moles of electrons = (0.610 A × 118 s) / (-1.602 × 10^-19 C × 96,485 C/mol)
moles of electrons = 4.48 × 10^18
Be sure to round your answer to three significant digits and include the correct unit symbol for moles of electrons, which is "mol e^-":
moles of electrons = 4.48 × 10^18 mol e^-

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The label of the periodic table is that the Groups are labeled at the top of the each column and the horizontal rows are called as the periods.

The elements are arranged in the seven horizontal rows, that are called as the periods or the series, and there are the 18 vertical columns that are  called as the groups. The Groups are labeled at the top of the each column. The labelled parts of the element in the periodic table will tells the atomic number and the atomic mass of the element.

The upper labelled part is  the atomic number of the element and The lower part is the atomic mass of the element in the periodic table.

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Answer:You're dealing with a double replacement reaction in which two soluble ionic compounds react in aqueous solution to form an Insoluble solid.

As you know, soluble ionic compounds exist as ions in solution. In your case, a solution of sodium carbonate,

Na

2

CO

3

, will contain

Na

2

CO

3(aq]

→

2

Na

+

(aq]

+

CO

2

−

3(aq]

Likewise, a solution of calcium chloride,

CaCl

2

, will contain

CaCl

2(aq]

→

Ca

2

+

(aq]

+

2

Cl

−

(aq]

When these two solutions are mixed, the calcium cations,

Ca

2

+

, will apir up with the carbonate anions,

CO

2

−

3

, and form the Insoluble calcium carbonate,

CaCO

3

, which precipitates out of solution.

The complete ionic equation, which features all the ions that are present in solution, will look like this

2

Na

+

(aq]

+

CO

2

−

3(aq]

+

Ca

2

+

(aq]

+

2

Cl

−

(aq]

→

CaCO

3(s]

⏐

⏐

↓

+

2

Na

+

(aq]

+

2

Cl

−

(aq]

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will look like this

CO

2

−

3(aq]

+

Ca

2

+

(aq]

→

CaCO

3(s]

⏐

⏐

↓

To get the overall balanced chemical equation, simply look at he complete ionic equation and group the ions back to an ionic compound

Na

2

CO

3



2

Na

+

(aq]

+

CO

2

−

3(aq]

+

CaCl

2



Ca

2

+

(aq]

+

2

Cl

−

(aq]

→

CaCO

3(s]

+

2

NaCl



2

Na

+

(aq]

+

2

Cl

−

(aq]

Notice that you have two sodium cations and two chloride anions on the products' side, which is why you have

2

NaCl

.

Na

2

CO

3(aq]

+

CaCl

2(aq]

→

CaCO

3(s]

⏐

↓

+

2

NaCl  Hope it helps :)

The word "precipitation reaction" refers to a chemical reaction that takes place within an aqueous solution as two ionic bonds join, resulting in the production of an insoluble salt.

When dissolved substances react, one (or even more) solid products are produced, which is known as a precipitation reaction. These kinds of reactions, which are also occasionally known as double displacement, twofold replacement, or metathesis reactions, frequently involve the exchange or ions between ionic substances in water-based solutions.

Examples include the interaction of calcium chloride (CaCl2) with potassium hydroxide (KOH), which produces the insoluble salt calcium hydroxide. Silver https://brainly.com/question/11527546(AgCl), an insoluble salt, is produced by the interaction of silver nitrate (AgNO3) with sodium chloride (NaCl).

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Soil is a crucial component of the Earth's ecosystem and plays a vital role in sustaining life by nutrient cycling, water storage and filtration, plant growth and carbon storage.

Nutrient Cycling: Soil provides a habitat for a vast array of organisms such as bacteria, fungi, and earthworms that help to break down organic matter into nutrients such as nitrogen, phosphorus, and potassium.

Plant Growth: Soil provides a stable base for plants to grow in, and its physical properties, such as texture and structure, influence the water and nutrient holding capacity of the soil. Plants absorb water and nutrients through their roots from the soil, which allows them to grow and produce oxygen for other organisms.

Water Storage: Soil acts as a reservoir for water, holding it for plant use and slowly releasing it to streams and rivers, which is essential for maintaining healthy aquatic ecosystems. Additionally, soil filtration helps to purify the water that enters groundwater aquifers, which is a critical source of drinking water for people.

Carbon Storage: Soil is an essential carbon sink, storing more carbon than the atmosphere and all vegetation combined. Soil helps to reduce the amount of carbon dioxide in the atmosphere, which is a greenhouse gas that contributes to climate change.

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Answer:

1. V2.

2. 299K.

3. 451K

4. 0.25 x 451 = V2 x 299

Explanation:

1. The data obtained from the question include:

Initial volume (V1) = 0.25mL

Initial temperature (T1) = 26°C

Final temperature (T2) = 178°C

Final volume (V2) =.?

2. Conversion from celsius to Kelvin temperature.

T(K) = T (°C) + 273

Initial temperature (T1) = 26°C

Initial temperature (T1) = 26°C + 273 = 299K

3. Conversion from celsius to Kelvin temperature.

T(K) = T (°C) + 273

Final temperature (T2) = 178°C

Final temperature (T1) = 178°C + 273 = 451K

4. Initial volume (V1) = 0.25mL

Initial temperature (T1) = 299K

Final temperature (T2) = 451K

Final volume (V2) =.?

V1 x T2 = V2 x T1

0.25 x 451 = V2 x 299

Answer:

I think 1.3 moles correct me if I'm wrong

Explanation:

Answer:

Explanation:

To find the volume when the pressure is at 202.6 kPa we use Boyle's law which is

\(P_1V_1 = P_2V_2\)

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the final volume

\(V_2 = \frac{P_1V_1}{P_2} \\\)

From the question

P1 = 99.3 kPa = 99300 Pa

V1 = 455 cm³

P2 = 202.6 kPa = 202600

So we have

\(V_2 = \frac{99300 \times 455}{202600} = \frac{45181500}{202600} \\ = 223.008390...\)

We have the final answer as

Hope this helps you

Answer:

I'm pretty sure you'll be fine

Explanation:

I've swallowed more than a small amount and I'm ok sort of

Citric acid with a pH of 7 can be prepared from the following reagents.

The preparation of 500 ml of pH 7 citric acid requires a combination of the following reagents: 1.8 m citric acid, 1.2 m sodium dihydrogen citrate, 1.5 m sodium hydrogen citrate, 0.8 m sodium citrate, 0.1 m HCl, and 0.1 m NaOH.

Begin by dissolving the citric acid in 500 ml of distilled water. Gradually add the sodium dihydrogen citrate and sodium hydrogen citrate, stirring continuously until the solution is homogenous.

Then, add the sodium citrate while stirring until the solution is homogenous. Finally, adjust the pH to 7 using 0.1 m HCl and 0.1 m NaOH while stirring until the desired pH is achieved.

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In order to determine how much more acid Cameron used in the second experiment:

If you have the amounts of acid used in both experiments, you can subtract the amount used in the first experiment from the amount used in the second experiment to find the difference.

For example, if Cameron used 100 ml of acid in the first experiment and 200 ml of acid in the second experiment, the difference would be 200 ml - 100 ml = 100 ml.

To calculate the difference, use the formula:

Difference = Amount in the second experiment - Amount in the first experiment.

Replace the "Amount in the second experiment" and "Amount in the first experiment" with the actual values you have.

Remember to provide the specific values of acid used in both experiments to determine the exact difference.

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To calculate the concentration of molecular, deprotonated, and protonated species in a water tank solution, we can use the pH and pKa values provided.

First, let's understand the relationship between pH and pKa. The pKa is a measure of the acidity of a compound. It tells us the pH at which the compound is half dissociated. A compound with a pKa lower than the pH is mostly in its protonated form, while a compound with a pKa higher than the pH is mostly in its deprotonated form.

In this case, the pH is 6.5 and the pKa is 1.87. The pH is higher than the pKa, so we expect the compound to be mostly in its deprotonated form.

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Neutral atoms of all isotopes of a given element have the same number of protons and neutrons.

All the isotopes of the same element consists of the same number of protons, which defines the element.

Depending on the neutron count, different isotopes can exist . This is  because electrons are negatively charged and they can counterbalance the positive charge of protons. Also, they are present in equal numbers in neutral atoms of the same element.

Mass number is formed from the addition of protons and neutrons, which varies between isotopes. An isotope's mass can differ between different isotopes since it depends on its mass number and the masses of the particles that it is formed from.

However, the masses of various isotopes of the same element are extremely close. Hence, this can be challenging to distinguish without the help of specialized tools.

Thus, option (a) is correct.

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Answer:

NaOH(aq) + HNO3(aq)------>NaNO3(aq) + H2O(l)

Explanation:

A thing to note is that an acid and a base will react to form a metal salt + H2O.

~Hope it helps:).

In titration, when \(HNO_{3}\) added to NaOH in then it will form \(NaNO_{3}\) and water.

Titration is just a laboratory technique for determining the concentration of an unknown solution using a solution of given volume and concentration. Between the two solutions, redox reaction or acid-base neutralization occurs, and the known numbers are used to calculate the unknown.

In titration, when \(HNO_{3}\) is added in a base like NaOH then it will form it will form \(NaNO_{3}\) and water.

The reaction of the titration can be written as:

NaOH + \(HNO_{3}\) → \(NaNO_{3}\) + \(H_{2}O\).

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The creation of sulphur di-oxide and consumption of oxygen as well as the formation of Sulfur trioxideall contribute to the change in pressure. To calculate the moles of Sulfur trioxide produced, further data is therefore required.

Heat is produced when sulphur di-oxideis converted to Sulfur trioxide in an exothermic reaction. Vanadium pentoxide Vanadium Oxideserves as a catalyst for the reaction. Sulphur trioxide is then dissolved in a 94% solution of Sulfuric acid to produce oleum, commonly known as fuming sulfuric acid (Disulfuric acid ).

A crucial stage in the synthesis of sulfuric acid is the catalytic oxidation of sulphur di-oxideto Sulfur trioxide. It generates the Sulfur trioxide needed to make Sulfuric acid(l) later. Oxidation of sulphur di-oxide+0.5oxygen to Sulfur trioxide is always carried out by circulating warm sulphur di-oxide-bearing gas across horizontal catalyst beds made of Vanadium, pottasium , sodium , cesium , sulphur , oxygen, and silicon di-oxide.

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Answer:

C: atomic mass

Explanation:

Answer:Atomic mass

Explanation:

D, 5.6 moles of HCl will be produced when 249 g of AlCl₃ are reacted according to the given chemical equation.

The balanced chemical equation for the reaction is:

2AlCl₃ + 3H₂O → Al₂O₃ + 6HCl

Use the molar mass of AlCl₃ (133.34 g/mol) and the moles of AlCl₃ (249 g / 133.34 g/mol = 1.87 mol) to calculate the moles of HCl produced.

The molar ratio of AlCl₃ to HCl is 2:6, so the moles of HCl produced is 6/2 × 1.87 mol = 5.6 mol.

Therefore, 5.6 moles of HCl will be produced when 249 g of AlCl₃ are reacted according to the given chemical equation.

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Complete question:

How many moles of HCI will be produced when 249 g of AlCl3 are reacted according to this chemical equation?

2AICI3+3H2O(l) → Al2O3+6HCl(g)

Select one:

a. None

b. 6.52 moles

c. 1.33 moles

d. 5.6 moles

Answer:

A compound contains atoms of different elements chemically combined together in a fixed ratio. An element is a pure chemical substance made of same type of atom. Compounds contain different elements in a fixed ratio arranged in a defined manner through chemical bonds

Answer:

it would ether be gray to black or silver to gray and black

Explanation:

because of my calculation ekasillicon would be that color because of the eyes and because of your color seeing .

The heat of vaporization of benzene is 15.2 kJ/g.

In order to determine the heat of vaporization of benzene, we need to use the formula:

Heat of vaporization = heat required/mass of sample converted

The heat required to convert a 9 g sample of aldehyde from the liquid to gas phase is 5.2 kJ.

Therefore, the heat required to convert an 18 g sample of aldehyde from the liquid to gas phase is:Heat required = 5.2 kJ x (18 g/9 g) = 10.4 kJ

Now, we can use the heat required to convert a 26.4 g sample of benzene from the liquid to gas phase to determine the heat of vaporization of benzene:

Heat of vaporization = 26.4 g x (10.4 kJ/18 g) = 15.2 kJ/g

Therefore, the heat of vaporization of benzene is 15.2 kJ/g.

Explanation:

Benzene (C6H6) has a heat of vaporization of 30.8 kJ/mol. Its molecular weight is 78.11 g/mol.

So, for benzene: Heat of vaporization = (30.8 kJ/mol) / (78.11 g/mol)

Heat of vaporization = 0.394 kJ/g

The actual heat of vaporization of benzene is 38.8 kJ/mol or 0.496 kJ/g.

The deviation in the measured value can be due to some experimental errors or impurities in the sample used.

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