6. During the titration, splatter from the drops of NaOH splashed some of the KHP solution onto the sides of the Erlenmeyer flask. If the student did not rinse these droplets back down into the solution with distilled water, how would that have affected the calculation of concentration of NaOH

The Kinetic Molecular Theory is a  scientific model that states atoms in a compound are found in a constant state of motion (movement).

The Kinetic Molecular Theory is a  scientific model that states atoms in a compound are found in a constant state of motion (movement).

Thermal energy refers to the movement of particles and therefore both concepts are interrelated.

In conclusion, the Kinetic Molecular Theory is a  scientific model that states atoms in a compound are found in a constant state of motion (movement).

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Esters, amines, and amides have many uses in medicine, and so do carboxylic acids, such as aspirin. Aspirin is the drug that will be investigated further. Its scientific name is acetylsalicylic acid.

Acetylsalicylic acid contains two functional groups: a carboxylic acid group (-COOH) and an ester group (-COO-CH₃). The carboxylic acid group is responsible for the acidic properties of aspirin and allows it to form salts with bases. The ester group is formed from the reaction between the carboxylic acid group of salicylic acid and acetic anhydride. This esterification reaction makes aspirin more soluble in organic solvents and less irritating to the stomach than salicylic acid.

Aspirin is a widely used medication that has anti-inflammatory, analgesic, and antipyretic properties. It works by inhibiting the production of prostaglandins, which are responsible for pain, inflammation, and fever. Aspirin is commonly used to treat headaches, fever, arthritis, and other inflammatory conditions. It is also used as a blood thinner to prevent heart attacks and strokes.

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Answer:

50/36 = 25/18

Explanation:

Solution at attachment box

Molality = mole of dissolvable (this question glucose) / kg of water

Answer:

Molality = 1.38 mol/Kg

Explanation:

Given data:

Molality of solution = ?

Mass of C₆H₁₂O₆ = 150.0 g

Mass of water = 600.0 g (600 g ×1 kg/1000 g= 0.6 Kg)

Solution:

Number of moles of C₆H₁₂O₆:

Number of moles = mass/molar mass

Number of moles = 150.0 g/180.16 g/mol

Number of moles = 0.83 mol

Molality:

Molality = moles of solute / kg of solvent

Molality =  0.83 mol /0.6 Kg

Molality = 1.38 mol/Kg

Answer:

A. K₂C₂O₄          Potassium oxalate

B. CuC₂O₄          Copper oxalate

C. Bi₂(C₂O₄)₃         Bismuth (III) oxalate

D. Pb(C₂O₄)₂         Lead (IV) oxalate

E. (NH₄)₂C₂O₄       Ammonium oxalate

F. HC₂O₄⁻             Acid oxalate

Explanation:

C₂O₄⁻²  → oxalate anion

This is the conjugate base from the H₂C₂O₄ which is the oxalic acid. A weak dyprotic acid that can release 2 protons.

A. 2K⁺  +  C₂O₄⁻²  → K₂C₂O₄          Potassium oxalate

It can be formed by the neutralization of the acid with the base

H₂C₂O₄  + 2KOH  → K₂C₂O₄  +  2H₂O

B. Cu²⁺ +  C₂O₄⁻²   ⇄  CuC₂O₄  ↓

This is a precipitate.

C.  2Bi³⁺  +  3C₂O₄⁻²   ⇄  Bi₂(C₂O₄)₃  ↓

This is a precipitate.

D.  Pb⁴⁺ +  2C₂O₄⁻²   ⇄  Pb(C₂O₄)₂  ↓

This is a precipitate.

E. 2NH₄⁺  +  C₂O₄⁻²   ⇄  (NH₄)₂C₂O₄  ↓

This is a precipitate.

F. This is the conjugate strong base, for the weak acid

H⁺  +  C₂O₄⁻²   ⇄  HC₂O₄⁻

HC₂O₄⁻  + H₂O  ⇄  C₂O₄⁻²  +  H₃O⁺    Ka

HC₂O₄⁻  + H₂O  ⇄  H₂C₂O₄  +  OH⁻    Kb

HC₂O₄⁻  is an amphoteric compound

A. K₂C₂O₄            →Potassium oxalate

B. CuC₂O₄           →Copper oxalate

C. Bi₂(C₂O₄)₃        →Bismuth (III) oxalate

D. Pb(C₂O₄)₂        →Lead (IV) oxalate

E. (NH₄)₂C₂O₄      →Ammonium oxalate

F. HC₂O₄⁻             →Acid oxalate

Given:

It is the conjugate base from the H₂C₂O₄ which is the oxalic acid. A weak diprotic acid that can release 2 protons.

The reactions involved in this are:

A. 2K⁺  +  C₂O₄⁻²  → K₂C₂O₄          

B. Cu²⁺ +  C₂O₄⁻²   ⇄  CuC₂O₄  ↓

C. 2Bi³⁺  +  3C₂O₄⁻²   ⇄  Bi₂(C₂O₄)₃  ↓

D. Pb⁴⁺ +  2C₂O₄⁻²   ⇄  Pb(C₂O₄)₂  ↓

E. 2NH₄⁺  +  C₂O₄⁻²   ⇄  (NH₄)₂C₂O₄  ↓

↓- This symbol denotes the precipitate formation.

F. H⁺  +  C₂O₄⁻²   ⇄  HC₂O₄⁻

HC₂O₄⁻  is an amphoteric compound.

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When copper is placed in water, it reacts with the water molecules to form copper(II) ions and hydrogen gas. The reaction is exothermic, which means it releases heat energy into the surroundings. By measuring the temperature changes that occur, we can determine the amount of heat that is released by the reaction.

The temperature changes can be measured using a thermometer. We can place the copper metal in a container of water and take the initial temperature reading. Then, we can add the copper to the water and record the temperature change over time. By monitoring the temperature changes, we can observe the exothermic reaction taking place.

The heat released by the reaction between copper and water has many practical applications, including in the design of power plants and in the production of steam for heating and electricity generation. Therefore, understanding the heat released during this reaction is important for a variety of scientific and engineering fields.

In conclusion, step 7 of putting copper metal in water and measuring the temperature changes allows us to observe and measure the heat released by the exothermic reaction between copper and water, which has important applications in various scientific and engineering fields.

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Answer:

Aluminum

copper

Iron

Lead

The Final Slide:

Aluminum- 0.90

Copper- 0.35

Iron- 0.44

Lead- 0.12

Explanation:

I hope this helps! :))))

All of the equation-related claims are not entirely true. The appropriate chemical formula should be:

Fe(OH)3 + 3NH4Cl = FeCl3 + 3NH4OH

Because the total mass of the reactants and products are equal, as well as the number of each type of atom in each of the reactants and products, mass is conserved in this balanced equation. Depending on the stoichiometric coefficients in the balanced equation, there may or may not be an equal amount of molecules in the reactants and products.

Iron(III) hydroxide (Fe(OH)3) and ammonium chloride (NH4Cl) are the products of the chemical reaction between iron(III) chloride (FeCl3) and ammonium hydroxide (NH4OH).

The coefficients (the numbers in front of the chemical formulae) must be changed to make sure that the number of each type of atom is the same on both sides of the equation in order to ensure that the equation is balanced. The coefficients in this instance are:

Fe(OH)3 + 3NH4Cl = FeCl3 + 3NH4OH

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A. The incandescent light bulb does not create as much as much light energy as the fluorescent light bulb.

Incandescent light bulbs have the drawback of wasting a lot of electricity due to heat. All the energy used to create heat is a waste because heat does not produce light, and the light bulb's intended function is to produce light. Thus, incandescent lamps are quite ineffective.

Mercury vapor is excited by an electric current in the gas to produce short-wave ultraviolet light, which illuminates a phosphor coating inside the lamp. Compared to an incandescent lamp, a fluorescent lamp is far more efficient at converting electrical energy into usable light.

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The conjugate base of CO3-2 is hydrogen carbonate.

A conjugate base can be defined as a base that can be derived from another base by the reason of it loosing or gaining an electron.

Conjugate base are very similar because they both posses the same elements.

In conclusion, The conjugate base of CO3-2 is hydrogen carbonate.

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Answer: There are \(61.24 \times 10^{23}\) molecules present in 183.2 grams of \(H_{2}O\) gas.

Explanation:

Given: Mass = 183.2 g

Number of moles is the mass of substance divided by its molar mass.

As molar mass of water is 18 g/mol. Therefore, moles of \(H_{2}O\) are calculated as follows.

\(Moles = \frac{mass}{molar mass}\\= \frac{183.2 g}{18 g/mol}\\= 10.17 mol\)

According to the mole concept, there are \(6.022 \times 10^{22}\) molecules present in one mole of a substance.

Hence, molecules present in 10.17 moles are calculated as follows.

\(10.17 mol \times 6.022 \times 10^{23}\\= 61.24 \times 10^{23}\)

Thus, we can conclude that there are \(61.24 \times 10^{23}\) molecules present in 183.2 grams of \(H_{2}O\) gas.

Answer:

Explanation:

IUPAC nomenclature is based on naming a molecule's longest chain of carbons connected by single bonds, whether in a continuous chain or in a ring. All deviations, either multiple bonds or atoms other than carbon and hydrogen, are indicated by prefixes or suffixes according to a specific set of priorities

Answer:

basalt

Explanation:

you hav a calculater u know

Answer:

32.2 g of Na will produce 43.4 g of Na2O.

Explanation:

The balanced chemical equation for the reaction between sodium and oxygen shows that 4 moles of sodium react with 1 mole of oxygen to produce 2 moles of sodium oxide:

4Na(s) + O2(g) → 2Na2O(s)

To solve this problem, we can use the following steps:

Step 1: Convert the mass of Na given in the problem to moles using the molar mass of Na.

molar mass of Na = 23 g/mol

moles of Na = mass of Na / molar mass of Na

moles of Na = 32.2 g / 23 g/mol

moles of Na = 1.4 mol

Step 2: Use the mole ratio from the balanced chemical equation to determine the moles of Na2O produced.

From the balanced chemical equation, we can see that 4 moles of Na react to produce 2 moles of Na2O.

moles of Na2O = (moles of Na / 4) x 2

moles of Na2O = (1.4 mol / 4) x 2

moles of Na2O = 0.7 mol

Step 3: Convert the moles of Na2O to grams using the molar mass of Na2O.

molar mass of Na2O = 62 g/mol

mass of Na2O = moles of Na2O x molar mass of Na2O

mass of Na2O = 0.7 mol x 62 g/mol

mass of Na2O = 43.4 g

Therefore, 32.2 g of Na will produce 43.4 g of Na2O.

We can see here that the catalytic cycle for the hydrogenation of alkenes using Wilkinson's catalyst involves several steps.

Here's an overview of the catalytic cycle, including the necessary details:

i. Chemical structure of the catalyst:

Wilkinson's catalyst, also known as chloridotris(triphenylphosphine)rhodium(I), has the following chemical structure: [RhCl(PPh3)3]

ii. Molecular geometry of the catalyst:

The Wilkinson's catalyst has a trigonal bipyramidal geometry around the rhodium center. The three triphenylphosphine (PPh3) ligands occupy equatorial positions, while the chloride (Cl) ligand occupies an axial position.

iii. Type of reactions involved:

The catalytic cycle involves several reactions, including:

iv. Starting material, reagent, and solvent:

The starting material is an alkene, and the reagent is Wilkinson's catalyst ([RhCl(PPh3)3]). The reaction is typically carried out in a suitable solvent, such as dichloromethane (CH2Cl2) or tetrahydrofuran (THF).

v. Major and minor end-products:

The major end-product of the hydrogenation reaction is the fully saturated alkane, resulting from the addition of hydrogen across the double bond. The minor end-product may include cis- or trans-configured alkanes if the original alkene substrate possesses geometric isomers.

vi. Intermediates:

The intermediates in the catalytic cycle include:

These intermediates play a crucial role in facilitating the hydrogenation reaction and enabling the catalytic cycle to proceed.

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Answer:

880.5

Explanation:

Express the result of adding 856.6g and 23.86g to the correct number of significant figures.

856.6 +23.86  = 856.6 + 23.9 = 880.5

The result of adding 856.6 g and 23.86 g after rounding off to correct significant figures is 856.6 + 23.9=880.5.

Significant figures are used for establishment  of a number which is presented in the form of digits. These digits give a meaningful representation  to the numbers.

The significant figures are the significant digits which convey the meaning according to the accuracy. These provide precision to the numbers and hence are called as significant numbers.There are rules for counting significant figures which are as follows:

1)All non-zero digits are significant .

2)All zeroes which occur between non-zero digits are significant.

3)All zeroes to the left and right of  a non-zero digit are not significant.

4) All zeroes on right  of decimal are significant if a non-zero number follows them.

5)All zeroes on right side of non-zero digit are significant.

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Answer: b) calcium sulfide

Explanation:

Answer:

To produce energy from food

Explanation:

It's pretty much an energy cycle

The removal of hydrogen or any other electropositive element, or the addition of oxygen, is said to be the process of oxidation in classical or earlier concepts. An atom or ion gains one or more electrons during the process of reduction.

1. The oxidation half-reaction of copper is:

Cu  → Cu²⁺ + 2e⁻

The reduction half is:

Cu²⁺ + 2e⁻ → Cu

3. An anode in electrochemistry is, in its simplest form, the site of an oxidation reaction. Due to the anode's electrical potential, negative ions or anions usually react there and release electrons. After that, these electrons ascend and enter the drive circuit.

In chemistry, the cathode is referred to as the electrode where reduction takes place. In an electrochemical cell, this is typical. Here, the cathode is negative because the cell's electrical energy supply causes chemical molecules to break down.

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The calculated formula masses to 133.5 amu, we find that the substance with a formula mass closest to 133.5 amu is (d) AlCl3. Therefore, the answer is option D.

To identify the substance with a formula mass of 133.5 amu, we need to calculate the formula mass of each given substance and compare it to 133.5 amu.

(a) MgCl2:

The formula mass of MgCl2 can be calculated by adding the atomic masses of magnesium (Mg) and chlorine (Cl).

Mg: atomic mass = 24.31 amu

Cl: atomic mass = 35.45 amu

Formula mass of MgCl2 = (24.31 amu) + 2(35.45 amu) = 95.21 amu

(b) SCl:

The formula mass of SCl can be calculated by adding the atomic masses of sulfur (S) and chlorine (Cl).

S: atomic mass = 32.07 amu

Cl: atomic mass = 35.45 amu

Formula mass of SCl = 32.07 amu + 35.45 amu = 67.52 amu

(c) BCl:

The formula mass of BCl can be calculated by adding the atomic mass of boron (B) and chlorine (Cl).

B: atomic mass = 10.81 amu

Cl: atomic mass = 35.45 amu

Formula mass of BCl = 10.81 amu + 35.45 amu = 46.26 amu

(d) AlCl3:

The formula mass of AlCl3 can be calculated by adding the atomic mass of aluminum (Al) and 3 times the atomic mass of chlorine (Cl).

Al: atomic mass = 26.98 amu

Cl: atomic mass = 35.45 amu

Formula mass of AlCl3 = 26.98 amu + 3(35.45 amu) = 133.78 amu. Option D

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31.7 g of water formation in the given reaction releases 783.02 kJ of heat energy.

The change in heat in the given equation is -890.8 kJ/mol. This means that when one mole of CH4 reacts with 2 moles of O2, it produces one mole of CO2 and 2 moles of H2O while releasing 890.8 kJ of heat energy.Now, we have to find out how much heat energy will be released when 31.7 g of water is formed. To do this, we need to first calculate the number of moles of water formed from 31.7 g of H2O.Molar mass of H2O = 2 × 1.008 + 15.999 = 18.015 g/molNumber of moles of H2O = 31.7 g / 18.015 g/mol = 1.759 molNow we know that 2 moles of H2O are formed when 1 mole of CH4 reacts. Therefore, the number of moles of CH4 required to produce 1.759 mol of H2O will be:1 mole of CH4 : 2 moles of H2Ox moles of CH4 : 1.759 moles of H2Ox = 1.759/2 = 0.8795 molSo, 0.8795 moles of CH4 are required to produce 1.759 moles of H2O. And the heat released during the reaction of 0.8795 mol CH4 can be calculated using the given change in heat.ΔH = -890.8 kJ/molHeat released during the reaction of 0.8795 mol CH4= ΔH × number of moles= -890.8 kJ/mol × 0.8795 mol= -783.02 kJ.

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Answer:

Volume = 3.4 L

Explanation:

In order to calculate the volume of CO₂ produced when 15.2 g of CaCO₃ is heated, we need to first write out the balanced equation of the thermal decomposition of CaCO₃:

CaCO₃ (s) + [Heat] ⇒ CaO (s) + CO₂ (g)

Now, let's calculate the number of moles in 15.2 g CaCO₃:

mole no. = \(\mathrm{\frac{mass}{molar \ mass}}\)

                 = \(\frac{15.2}{40.1 + 12 + (16 \times 3)}\)

                 = 0.1518 moles

From the balanced equation above, we can see that the stoichiometric molar ratios of CaCO₃ and CO₂ are equal. Therefore, the number of moles of CO₂ produced is also 0.1518 moles.

Hence, from the formula for the number of moles of a gas, we can calculate the volume of  CO₂:

mole no. = \(\mathrm{\frac{Volume \ in \ L}{22.4}}\)

⇒ \(0.1518 = \mathrm{\frac{Volume}{22.4}}\)

⇒ Volume = 0.1518 × 22.4

                 = 3.4 L

Therefore, if 15.2 g of CaCO₃ is heated, 3.4 L of CO₂ is produced at STP.

Answer:

the temperature increased

Answer:

Force used by fire extinguisher = 60 N

Explanation:

Given:

Mass of skateboard with fire extinguisher = 50 kg

Acceleration of fire extinguisher = 1.2 m/s²

Find:

Force used by fire extinguisher = ?

Computation:

⇒ Force = Mass × Acceleration

⇒ Force used by fire extinguisher = Mass of skateboard with fire extinguisher × Acceleration of fire extinguisher

⇒ Force used by fire extinguisher = 50 kg × 1.2 m/s²

⇒ Force used by fire extinguisher = 60 N

Answer:

Force=60 N

Hope this helps ya'll!                                  

Powerful Electrolytes:

HCl, NaOH, HNO3

Weak electrolyte:

HF, HC2H3O2

• Non-electrolytes:

C2H5OH, C6H12O6

Further explanation

An electrolyte solution is a substance that produces ions when dissolved in water and can conduct electricity.

Strong electrolytes are the solution

Solutes have the strongest electrical conductivity because they are completely ionized when dissolved in water.

• Weak electrolytes are partially ionized solutions with low electrical conductivity.

• Non-electrolytes are solutions that cannot conduct electricity because the solute cannot form ions. One of the most important properties of water is its ability to dissolve various substances. Solutions in which water is actually the dissolution medium are called aqueous solutions. Water is the most important solvent for electrolytes.

HCl = hydrochloric acid, a strong acid.

HNO3 = nitric acid, strong acid

• NaOH = sodium hydroxide, a strong base

HF = hydrofluoric acid, a weak acid

HC2H3O2 or CH3COOH = acetic acid, a weak acid

C2H5OH = ethanol, non-electrolyte

C6H12O6 = glucose, non-electrolyte

remarks:

• Some acids are fully ionized in water, while others are partially ionized. Not all acids are equally strong in generating H+ ions in solution. When an acid is fully ionized it is a strong acid. Click here when passing through hydrogen chloride

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The balanced chemical equation for the reaction between chromium and bromine to produce chromium(III) bromide is:

2 Cr + 3 Br2 → 2 CrBr3

This equation shows that two chromium atoms react with three molecules of bromine to form two molecules of chromium(III) bromide.

A redox reaction is a type of chemical reaction that involves the transfer of electrons between reactants. The term "redox" comes from the combination of two processes during the reaction: reduction, which involves the gain of electrons by a reactant, and oxidation, which involves the loss of electrons by a reactant.

The reaction is an example of a redox reaction, where reduction and oxidation occur simultaneously. Chromium is oxidized, while bromine is reduced. The reaction also shows the importance of balancing the number of atoms on both sides of the equation to ensure that the law of conservation of mass is satisfied.

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The molar mass of saccharin is 0.900 g / [Sac].

Saccharin is a weak organic base with a K​b of 4.80 × 10-3 and we are given that a 0.900-g sample of saccharin dissolved in 45.0mL of water has a pH of 12.310.

We are supposed to calculate the molar mass of saccharin.

The formula for finding the molar mass of a substance is:Molar mass = (mass of substance) / (number of moles).

We are given that the Kb of saccharin is 4.80 × 10-3.

Since it is a base, it reacts with water to form the conjugate acid of saccharin (HSac) and hydroxide ions (OH-).

The balanced chemical equation for this reaction is: C7H4NO3S + H2O → HSac + OH-.

We can use the Kb value to find the concentration of the hydroxide ions produced:Kb = [HSac][OH-] / [Sac].

Initial concentration of saccharin, [Sac] = (0.900 g) / (Molar mass) = 0.900 / M Molar mass = 0.900 / [Sac].

Now we can use the given pH value to find the concentration of the hydroxide ions using the expression:pH = 14 - pOHpOH = 14 - pH[OH-] = 10^-pOH.

Substitute these values in the expression for Kb and solve for [HSac]:Kb = [HSac][OH-] / [Sac][HSac] = (Kb x [Sac]) / [OH-]

Now we can substitute the values we have into the expression for the molar mass:Molar mass = (mass of substance) / (number of moles)Number of moles = [Sac]Molar mass = 0.900 / [Sac].

Therefore, the molar mass of saccharin can be calculated by first finding the concentration of hydroxide ions produced using the pH value, then using the Kb value to find the concentration of the conjugate acid of saccharin, and finally using these values to find the molar mass of saccharin using the formula Molar mass = (mass of substance) / (number of moles).

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The redox reactions is balanced as by adding coefficients as follows:2 H+ +ClO²⁻+I⁻⟶2 Cl⁻+H₂O+I₂.

Redox reactions comprise of two parts a reduced part and an oxidized part, which occur simultaneously . The part which is reduced gain electrons and hence there is a increase in oxidation state of the species.

While, the part which is oxidized looses electrons and hence there is a decrease in oxidation state of the species.During redox reactions, there is no net change in the number of electrons . Electrons which are given off in oxidation are used up in reduction.These too are balanced by adding coefficients.

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The SI unit to the quantity it measures are:

Mass: The mass of an object is a measure of its amount of matter. The SI unit of mass is the kilogram (kg) or gram (g).

Temperature: Temperature is a measure of the average kinetic energy of the particles in a substance. The SI unit of temperature is the kelvin (K).

Time: Time is a measure of the interval between two events. The SI unit of time is the second (s).

Electric current: Electric current is a measure of the flow of electric charge. The SI unit of electric current is the ampere (A).

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Complete question:

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Match each SI unit to the quantity it measures.