(5*5)/5*75/2 = ?
can you tell me the answer

Answer:

its 3 and 60 on edg

Step-by-step explanation:

Answer:

Step-by-step explanation:

For x = 80, we have:

Predicted temperature when 125 coats are sold:

Answer:

hope it helps you.......

The required slope of the line passing through the points is m = 9/2. Option A is correct.

Given that,
To determine the slope of the line that passes through the points (2, −3.5) and (4, 5.5).

The slope of the line is a tangent angle made by line with horizontal. i.e. m =tanx where x in degrees.

Here,

The slope of the line passing through two points is given by,
m = (y₂ - y₁) /  (x₂ - x₁)
Substitute value in the above equation
m= 5.5 +3.5 / 4 - 2
m = 9 / 2

Thus, the required slope of the line passing through the points is m = 9/2. Option A is correct.

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Answer:

Step-by-step explanation:

\(1a - 3a \\ = - 2a\)

The area of the entire rectangle is 20x^2 - 10x - 30

From the question, we have the following parameters that can be used in our computation:

Height = 5

Width = 4x^2 - 2x - 6

Using the above as a guide, we have the following:

The area of a rectangle is the product of its dimension

So, we have

Area = Height * Width

Substitute the known values in the above equation, so, we have the following representation

Area = 5 * (4x^2 - 2x - 6)

Evaluate

Area = 20x^2 - 10x - 30

Hence, the area is 20x^2 - 10x - 30

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Step-by-step explanation:

Let x be the number.

Then the algebraic expression will be x^2 + 11x.

The algebraic expression in x will be : x² + 11x

Given,

Variable x,

The sum of the square of a number and eleven times the number.​

Now,

Let the variable be x .

Square of variable : x²

Eleven times of the variable x : 11x

Now combine the term to get the algebraic expression,

Alegbraic expression : x² + 11x

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Each model should be produced on a weekly basis to maximize net profit is $75,900.

What is Net profit?

In both business and accounting, net income or profit is an entity's revenue less cost of goods sold, costs, depreciation and amortisation, interest, and taxes for a certain accounting period.

As given,

Number of products sold:

T ≥ 1.5G

Maximize Profit Z = 150T + 130G

Labor Constraint:

Labor hours Available:

Production Department:

Number of labor hours available per day = 58 × 7 = 406

Number of days in a week = 5

Number of lobor ours available per week = 406 × 5 = 2030

Assembly Department:

Number of labor hours available per day = 25 × 7 = 175

Number of days in a week = 5

Number of labor hours available per week = 175 × 5 = 875.

Labor hours Required:

Labor hours required for G1 model:

Labor hours required at Production department = 3.5G

Labor hours required at assembly department = 2G

Labor hours required for T1 model:

Labor hours required at Production department = 4T

Labor hours required at Assembly department = 1.5T

Total labor hours required at Production department = 3.5G + 4T

Total labor hours required at Assembly department = 2G + 1.5T.

Constraint:

Labor hours required ≤ Labor hours Available.

Production department Labor constraint

3.5G + 4T ≤ 2030

Assembly department Labor constraint:

2G + 1.5T ≤ 875

The function:

Maximum Profit Z = 150T +130G

Constraint:

3.5G +4T ≤ 2030

2G + 1.5T ≤ 875

T ≥ 1.5G

Suppose that for example:

10.5G +12T = 6090

 16G + 12T = 7000

Solve both equations simultaneously,

5.5G = 7000 - 6090

5.5G = 910

    G = 910/5.5

    G = 363

Since, T > G

Hence,

T = 363,

G = 165

Calculate Profit:

150T + 130G = 150 × 363 + 130 × 165

                     = 54450 + 21450

                     = 75900

Hence, each model should be produced on a weekly basis to maximize net profit is $75,900.

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Answer:

c divided by 1/3

Step-by-step explanation:

if you plug in a number for c and solve for each of the equations you will find that c is false so it can't be used. for example if i use the number 30 for c, i get 10 for every single equation except for the last one

Answer:

the answers 325 hope this helps your day

Answer: y = 8x

Step-by-step explanation:

y = 8x

The answer to your question is Four

Generally, the NEC® permits a fuse to carry 80 percent of its rating when it supplies a load that is not operated continuously. The correct option is b.

According to the National Electrical Code (NEC), a fuse is generally permitted to carry up to 80% of its rating when supplying a load that is not operated continuously. This provision is based on safety considerations and is intended to prevent the fuse from tripping prematurely during temporary or intermittent overloads.

Allowing a fuse to carry up to 80% of its rating ensures that it can handle short-term surges in current without blowing. This is important because many electrical devices and appliances draw higher currents when they are first turned on or during certain operations. Allowing the fuse to handle these temporary overloads helps avoid unnecessary interruptions in power supply.

By limiting the fuse to 80% of its rating, the NEC provides a safety margin. This margin accounts for factors such as variations in load characteristics, ambient temperature, and other operating conditions that may affect the actual current flowing through the fuse.

In summary, the NEC permits a fuse to carry up to 80% of its rating for non-continuous loads to accommodate temporary overloads while maintaining safety and reliability in electrical systems. Hence, b is the correct option.

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Answer:

n = 4

Step-by-step explanation:

(40 - 2n) ÷ 4 = 8

10 - 0.5n = 8

-0.5n = 8 - 10

-0.5n = -2

n = 4

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Answer:

the correct answer is n=4

The possible lengths of the rectangular parking lot are any value less than or equal to 80 feet or any value greater than or equal to 110 feet, as long as the width is calculated accordingly to satisfy the given conditions of the perimeter and area.

The possible lengths of the rectangular parking lot can vary, but they must adhere to the conditions of having a perimeter of 380 feet and an area of at least 8800 square feet.

Let's assume the length of the parking lot is L and the width is W. The perimeter of a rectangle is given by the formula P = 2L + 2W. In this case, we are given that the perimeter is 380 feet, so we can write the equation as 2L + 2W = 380.

Additionally, the area of a rectangle is given by the formula A = L × W. We are given that the area must be at least 8800 square feet, so we can write the inequality as L × W ≥ 8800.

To determine the possible lengths of the parking lot, we can use these equations. First, let's solve the perimeter equation for W: W = (380 - 2L)/2 = 190 - L. Next, substitute this value of W into the area inequality equation: L × (190 - L) ≥ 8800.

Simplifying this inequality, we get L² - 190L + 8800 ≥ 0. To find the possible values of L, we can solve this quadratic inequality. By factoring or using the quadratic formula, we can determine that the possible lengths are L ≤ 80 or L ≥ 110.

Therefore, the possible lengths of the rectangular parking lot are any value less than or equal to 80 feet or any value greater than or equal to 110 feet, as long as the width is calculated accordingly to satisfy the given conditions of the perimeter and area.

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The estimate of the maximum error in the calculated surface area is approximately \(0.007824w_0^(-0.479)h_0^0.848 + 0.006558w_0^0.521h_0^(-0.152).\)

To estimate the maximum error in the calculated surface area, we can use the concept of differentials and propagate the errors from the measurements of weight and height to the surface area.

Let's denote the weight as w_0 and the height as h_0, which represent the true values of weight and height, respectively. The measured weight is w_0 + Δw, and the measured height is h_0 + Δh, where Δw and Δh represent the errors in the measurements of weight and height, respectively.

Using differentials, we can approximate the change in the surface area ΔS as:

ΔS ≈ (∂S/∂w)Δw + (∂S/∂h)Δh

We need to calculate the partial derivatives (∂S/∂w) and (∂S/∂h) of the surface area function with respect to weight and height, respectively.

∂S/∂w = \(0.521 * 0.288w^(-0.479)h^0.848\)

∂S/∂h = \(0.848 * 0.288w^0.521h^(-0.152)\)

Substituting the true values w_0 and h_0 into the partial derivatives, we get:

∂S/∂w =\(0.521 * 0.288w_0^(-0.479)h_0^0.848\)

∂S/∂h = \(0.848 * 0.288w_0^0.521h_0^(-0.152)\)

Now, we can calculate the maximum error in the calculated surface area using the formula:

Maximum error in S = |(∂S/∂w)Δw| + |(∂S/∂h)Δh|

Given that the errors in measurements of weight and height are at most 1.5%, we have Δw/w_0 ≤ 0.015 and Δh/h_0 ≤ 0.015.

Substituting the values into the formula, we get:

Maximum error in S = |(∂S/∂w)Δw| + |(∂S/∂h)Δh|

\(|(0.521 * 0.288w_0^(-0.479)h_0^0.848)(0.015w_0)| + |(0.848 * 0.288w_0^0.521h_0^(-0.152))(0.015h_0)|\)

Simplifying the expression, we have:

Maximum error in S ≈ \(0.007824w_0^(-0.479)h_0^0.848 + 0.006558w_0^0.521h_0^(-0.152)\)

Therefore, the estimate of the maximum error in the calculated surface area is approximately\(0.007824w_0^(-0.479)h_0^0.848 + 0.006558w_0^0.521h_0^(-0.152).\)

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Answer:

x = -17

Step-by-step explanation:

20-3.8x becomses 2x  and   -14 -5.8 becomes -14 - 20

-14 - 20= 34

2x = -34 (divide both sides by 2)

hope it helps :)

Answer:

60-x

Step-by-step explanation:

a number = x

The score on the seventh test is 71.5

"Information available from the question"

The average of your first 6 tests is 82.

If your test average after your seventh test is an 80. 5

To find the score on the seventh test.

Now, According to the information:

Average of 6 test is 82

We know that :

Average = Sum of all test / Total no. of test => 82 =  Sum of all test / 6

Sum of all test = 492

Let the seventh test be 'x'

So, Sum of seventh test is = 492 + x

Average = \(\frac{492+x}{7}\)

80.5  = \(\frac{492+x}{7}\)

=> 80.5 × 7 = 492 + x

x =  (80.5 × 7) - 492

=> x = 563.5 - 492

x = 71.5

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mount Saved = $2820 (answer). In other words, a 12% discount for a item with original price of $23500 is equal to $2820 (Amount Saved).

Answer:

Step-by-step explanation:

a) 2,937.5

b) 20,562.5

Answer:

ahh this looks so tuff!

Step-by-step explanation:

the answer is 7³

The ramp will rise approximately 15.95 inches from the ground at its highest end. Rounded to the nearest hundredth of an inch, the height is 15.95 inches.

To find the height the ramp will rise from the ground at its highest end, we can use trigonometry. The tangent function relates the angle of elevation (28°) to the height of the ramp.

Let's denote the height of the ramp as h. We can set up the equation:

tan(28°) = h / 30

To find h, we can rearrange the equation:

h = tan(28°) × 30

Using a calculator, we can calculate the value of tan(28°) ≈ 0.5317. Plugging this value into the equation, we get:

h = 0.5317 × 30

h ≈ 15.95

Therefore, the ramp will rise approximately 15.95 inches from the ground at its highest end. Rounded to the nearest hundredth of an inch, the height is 15.95 inches.

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Answer:

Answer could be number 1 the first one  

Step-by-step explanation:

Hope i get it rigth

The measure of length PQ will be 22 units.

A triangle's third side is stated to be parallel to the line segment uniting its two midpoints, and it is also half as long as the third side.

Given:

PQ = 5x + 62, and MN = 6x-4

Now, using Mid- Point Theorem

PQ= 1/2 MN

-5x+ 62 = 1/2( 6x - 4)

-5x+ 62 = 3x - 2

-5x- 3x = -2 - 62

-8x = -64

x= 8

PQ= 5x+ 62 = -5(8) + 62 = -40 + 62 = 22

Hence, the measure of PQ is 22 units.

The missing image is attached below.

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This notation represents the intervals where tan(θ) is less than -1 within the given range of θ.

To represent the values of θ (between 0 and 2π) where tan(θ) < -1 using interval notation, follow these steps:

1. Identify the range of θ: Since the problem states that θ is between 0 and 2π, the range of θ is (0, 2π).

2. Determine where tan(θ) < -1: The tangent function has a period of π, and it is negative in the second and fourth quadrants. In the second quadrant, tan(θ) will be less than -1 between π/2 and 2π/3, and in the fourth quadrant, it will be less than -1 between 4π/3 and 3π/2.

3. Use interval notation to represent the solution: Combining the information from steps 1 and 2, the values of θ where tan(θ) < -1 can be represented using interval notation as:

(2π/3, π/2) ∪ (4π/3, 3π/2)

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Answer:

Step-by-step explanation:

Solve 3-4 and (1⁄2)-2

3 - 4, 4 is greater than 3, so the result is negative (-1)

3 - 4 = -1

-----------------

1/2 is equal to 0.5, also here 2 is larger and we will have a negative result (-1.5 or -3/2)

1/2 - 2 =

0.5 - 2 = -1.5 or -3/2

Answer:

5/6

Explanation

Probabaility is the likelihood or chance that an event will occur. Mathematically;

Probabiblity = Expected outcome/Total outcome

Since a pair of dice is rolled;

Total outcome for n dice = 6^n

For a pair of dice, total outcome is 6^2 = 36

For the expected outcome

If we got different numbers on both dice, the outcomes wil be 30 since the only periods we will have the same value are [(1, 1), (2,2), (3,3), (4,4), (5,5), (6,6)] which is 6 outcomes

getting different numbers on both dice = 36 - 6 = 30

Probability of getting different numbers on both dice = 30/36

Probability of getting different numbers on both dice = 5/6

Answer:

$8.50

Explanation:

Given the function f(h) that describes the total dollar amount Tomas earns, based on the number of hours he works:

When h=1, f(1)=250+8.5(1)=$258.5

When h=2, f(2)=250+8.5(2)=$267

Now:

It means therefore that for every additional hour, Tomas earns $8.5.

The hourly wage Tomas earns is $8.5.

Now,

Answer:

The cost of 12 gallons of gas and a quart of oil is 14·x - 30

Step-by-step explanation:

When adding variables, the coefficient of the variables are added followed by multiplication of the sum of the coefficients with variable as follows;

The cost of 12 gallons of gas = 12·x

The cost of a quart of oil is represented by 2·x - 30

Therefore, the cost of 12 gallons of gas and a quart of oil can be represented as follows;

12 gallons of gas and a quart of oil = 12·x + 2·x - 30

Which gives;

The cost of 12 gallons of gas and a quart of oil = 14·x - 30.

the control limits for the x-bar chart are 9.7439 minutes (LCL) and 11.0561 minutes (UCL), and the control limits for the R chart are 0 minutes (LCL) and 2.0529 minutes (UCL).

To compute the control limits for the x-bar (mean) and R (range) charts, we'll use the following formulas:

For the x-bar chart:

Upper Control Limit (UCL) for x-bar = x-double-bar + A2 * R-bar

Lower Control Limit (LCL) for x-bar = x-double-bar - A2 * R-bar

For the R chart:

Upper Control Limit (UCL) for R = D4 * R-bar

Lower Control Limit (LCL) for R = D3 * R-bar

Where:

x-double-bar = Overall mean of the sample means

R-bar = Overall mean of the sample ranges

A2 = Constant from the control chart constants table

D4 = Constant from the control chart constants table

D3 = Constant from the control chart constants table

For sample sizes of 4, the control chart constants are as follows:

A2 = 0.729

D4 = 2.281

D3 = 0

Given the information you provided:

Overall mean (x-double-bar) = 10.4 minutes

Average range (R-bar) = 0.9 minutes

Let's calculate the control limits:

For the x-bar chart:

UCL for x-bar = 10.4 + 0.729 * 0.9

             = 10.4 + 0.6561

             = 11.0561 minutes

LCL for x-bar = 10.4 - 0.729 * 0.9

             = 10.4 - 0.6561

             = 9.7439 minutes

For the R chart:

UCL for R = 2.281 * 0.9

         = 2.0529 minutes

LCL for R = 0

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Answer: x = -2, 2

Step-by-step explanation:

2x^2 + 1 = 9

        -1.     -1

2x^2 = 8

2x^2/2 = 8/2

x^2 = 4

\(\sqrt{x^2} = \sqrt{4}\)

x = -2, 2