52.887 in significant figures

Answer:

C. is your answer

Edguinity 2020

In the case of  hypertension, heart disease, and stroke, the risk of developing each condition can be reduced through diet and exercise. So, the correct option is C.

Blood pressure is defined as the effect of force exerted by the blood circulating through the blood vessels on the walls of the arteries and blood vessels.

Here,

Hypertension is the condition in which the blood circulating through the arteries exerts force on the artery walls such that it causes too high pressure on the walls.

The normal blood pressure level is 120/80 mm Hg. But during hypertension, the blood pressure increases to more than 140/90. The severe conditions of hypertension occurs when the blood pressure goes above 180/120.

The increased blood pressure in the blood vessels can eventually lead to the damage of arteries and its impact on the heart walls will result in  causing severe heart diseases.

The major risk factor for stroke is the hypertension. A blood pressure level of about 130/80 mm Hg can create a risk of stroke. The highly elevated blood pressure would damage the blood vessels in the brain. As a result, bleeding occurs in the brain, which eventually creates blood clots in the brain, resulting in the stroke.

These severe health conditions are mainly caused due to the lifestyle of people. Proper diet and regular exercise can reduce the risk of these conditions to an extent.  

Hence,

In the case of  hypertension, heart disease, and stroke, the risk of developing each condition can be reduced through diet and exercise.

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1a) Energy is absorbed, and the reaction is endothermic.

1b) The products have higher potential energy, the enthalpy change is positive, indicating an endothermic reaction.

1c) The peak of the potential energy diagram.

2a) The activation energy labeled as the difference between the reactants and the peak

2b) The activation energy can be determined by calculating the difference between the reactants.

2c) The enthalpy change can be calculated by finding the difference between the energy of the reactants and the energy of the products.

2d) The reaction is exothermic. In terms of the graph's shape.

3a) A decrease in potential energy as the products form.

3b)This indicates that a small amount of energy from the spark is needed to overcome the activation energy barrier

Part 1:

1a. To determine if the reaction is endothermic or exothermic, we need to analyze the potential energy diagram. If the products have lower potential energy than the reactants, it indicates that energy is released, and the reaction is exothermic. Conversely, if the products have higher potential energy than the reactants, it suggests that energy is absorbed, and the reaction is endothermic.

1b. The enthalpy change (ΔH) for the reaction can be calculated by comparing the potential energy of the products and the reactants. If the products have lower potential energy, the enthalpy change is negative, indicating an exothermic reaction. If the products have higher potential energy, the enthalpy change is positive, indicating an endothermic reaction.

1c. The activation energy (Ea) can be determined by examining the energy difference between the reactants' potential energy and the peak of the potential energy diagram.

Part 2:

2a. Since the energy of the reactants is 30 kJ, the energy of the products is 5 kJ, and the maximum energy of the system is 40 kJ, we can sketch a potential energy diagram with the reactants at 30 kJ, the products at 5 kJ, the activation energy labeled as the difference between the reactants and the peak, and the enthalpy change as the difference between the reactants and products.

2b. The activation energy can be determined by calculating the difference between the reactants' energy and the peak of the potential energy diagram.

2c. The enthalpy change can be calculated by finding the difference between the energy of the reactants and the energy of the products.

2d. Based on the energy values, if the energy of the products is lower than the energy of the reactants, the reaction is exothermic. In terms of the graph's shape, if the potential energy decreases from reactants to products, it indicates an exothermic reaction.

Part 3:

3a. The potential energy diagram for the striking and burning of a match can be sketched to show the initial potential energy of the reactants, a peak representing the activation energy, and a decrease in potential energy as the products form.

3b. The potential energy diagram would show an initial higher potential energy for the reactants, a peak representing the activation energy required for the reaction to occur, and a decrease in potential energy as the products form. This indicates that a small amount of energy from the spark is needed to overcome the activation energy barrier, leading to the release of a greater amount of energy during the burning process.

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The magnitude is 756.72 N and the coordinate direction angles of the resultant of the two forces acting at point A are alpha(\(149^{0}\)), beta(\(0^{0}\)), and gamma(\(59^{0}\)).

The resultant force is the overall force acting on an object, which is the vector sum of all the individual forces acting on the object. It is the net force that determines the motion of an object. In other words, it is the force that would have the same effect on the object's motion as all the individual forces combined. The direction of the resultant force is the direction of the net force and the magnitude is the sum of the magnitudes of the individual forces.

Given,

A = (5, 0, 0) m

B  = (0, 2, 3) m

C = (0, -2, 3) m

AB = B - A  = -5i + 2j + 3k

\(AB_{cap}\) = \(\frac{-5i+2j+3k}{\sqrt{5^{2}+2^{2}+3^{2} } } =\frac{-5i+2j+3k}{6.16}\)  

AC = C - A = -5i - 2j + 3k

\(AC_{cap} =\frac{-5i+2j+3k}{6.16}\)

Fb = 400 (-5i + 2j + 3k ) / 6.16\(F_{b} =\frac{400(-5i+2j+3k)}{6.16} =-324.44i+129.78j+194.67k \\F_{c}=\frac{400(-5i+2j+3k)}{6.16}= -324.44i-129.78j+194.67k\)

\(F_{net} =F_{b} +F_{c}\)= - 648.88i + 389.33k N

Magnitude = |\(F_{net}\)|  = \(\sqrt{648.88^{2}+389.33^{2} } =756.72N\) .......Ans

Coordination angles,

alpha = \(cos^{-1} \frac{F_{net} x}{|F_{net}| } =149^{0}\)

beta = \(cos^{-1}\frac{F_{net}y }{|F_{net} |} =0^{0}\)  

gamma = \(cos^{-1}=\frac{F_{net}z }{|F_{net} |} =59^{0}\)

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The complete question is given below:

The coefficient of static friction between the block and the table is 0.07.

The coefficient of static friction between the block and the table is determined by Newton's second law of motion as shown below;

Fs = μFₙ

where;

μ = Fs/Fₙ

μ = Fs/mg

μ = 2/(3 x 9.8)

μ = 0.07

Thus, the coefficient of static friction between the block and the table is 0.07.

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The well that will have most of the water will be well A.

The underground water supply is defined as a type of water that exists underground in saturated zones beneath the land surface.

From the two wells represented in the diagrams above, Well A has water supply from underground which is lacking in well B.

Therefore, well A will have most of the water more than B.

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Answer:

The correct answer is option E

Explanation:

Relative density of the different phases of the same compound like water are basically determined by their number of molecules per volume when each of the molecules have the same mass in each of their phases.

Now, for the water vapor phase, it's molecules have very little interaction with themselves and so they are at large distance apart, whereas in ice(solid), molecules are in continuous contact with each other because they are at close distance between each other. Therefore, it's obvious that there are less molecules per liter in water vapour than in ice, and thus the density is smaller.

The correct answer is option E

Answer:

distance(d)=.....

time(t)=....

speed =?

we know that

speed =distance /time

The angular velocity in radians per second, given that Microwave ovens rotate at a rate of about 5 revolutions per minute (rpm) is 0.50 radians per second

The angular velocity (in radians per second) can be obtained by simply converting 0.08 revolution per second to radians per second. This is obtained as illustrated below:

1 revolution per second = 2π radians per second

Therefore,

0.08 revolution per second = 0.08 × 2π

Recall

Pi (π) = 3.14

Thus,

0.08 revolution per second = 0.08 × 2 × 3.14

0.08 revolution per second = 0.50 radians per second

Thus, we can conclude that the angular velocity (in radians per second) is 0.50 radians per second

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a.) the ball was going up at 0.95 seconds and coming down at 4.58 seconds

b.) the distance of the wall from the plate is 34 m

Given that a ball player hits a home run, and the ball just clears the wall which is 22.0 m high. The ball is hit at an angle of 37.0" with a velocity of 45.0 m/s.

Since the ball is hit at an angle of 37.0 degrees, We need to find the vertical and horizontal component of the velocity.

\(U_{y}\) = 45 Sin 37 = 27.08 m/s

\(U_{x}\) = 45 cos 37 = 35. 94 m/s

Let us first calculate the maximum height reached.

\(V^{2}\) = \(U_{y} ^{2}\) - 2gH

At maximum height, V = 0

0 = \(27.08^{2}\) - 2 x 9.8H

19.6H = 733.3

H = 733.33/19.6

H = 37.4 m

If the ball is hit from a height of 0.750 m above the ground,

(a) To calculate the time the ball stays in the air until it  clears the wall while on its way down, we will use the formula below.

h =  \(U_{y}\)t - 1/2g\(t^{2}\)

Substitute for all the parameters

22 - 0.75 = 27.08t - 0.5 x 9.8 x \(t^{2}\)

21.25 = 27.08t - 4.9\(t^{2}\)

4.9\(t^{2}\) - 27.08t + 21.25

We will use quadratic formula

a = 4.9

b = - 27.08

c = 21.25

t =  \(\frac{-b+/- \sqrt{b^{2} - 4ac } }{2a}\)

t = \(\frac{27.08 +/- \sqrt{27.08^{2} - 4 * 4.9 * x^{2} 21.25 } }{2 * 4.9}\)

t = \(\frac{27.08 +/-\sqrt{733.3 - 416.5} }{9.8}\)

t = \(\frac{27.08 +/- 17.8}{9.8}\)

t = 44.88/9.8 or 9.28 / 9.8

t = 4.58 s  or 0.95 s

This means that the ball was going up at 0.95 seconds and coming down at 4.58 seconds

(b) The distance of the wall from home plate will be the range which is

R = \(U_{x}\)t

R = 35.94 x 0.95

R = 34.143 m

Therefore, the distance of the wall from the plate is 34 m approximately

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The near point of a human eye is about a distance of 25 cm.

The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.

This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.

The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.

In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.

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Here is a draft of the worksheet for the three main plate boundary types:

Plate Boundary (Movement)      Convergent (Colliding)

Diagram

        ||

        ||

        ||

Lithosphere (Created or Destroyed)  

       Created

Geologic Process      Mountain building

Real World Example

        Himalayas (Along India-Eurasia plate boundary in Asia)

References        

APA reference for research      

Plate Boundary (Movement)        Divergent (Separating)

Diagram

          |||||

Lithosphere (Created or Destroyed)      

        Destroyed  

Geologic Process        

         Volcanic eruptions and rift valleys

Real World Example  

        Mid-Atlantic Ridge (Between North America and Europe plates)

References        

         APA reference          

Plate Boundary (Movement)     Transform (Sliding)

Diagram

          |||||||||

Lithosphere (Created or Destroyed)  

       Neither          

Geologic Process  

       Earthquakes

Real World Example        

         San Andreas Fault (California, USA along Pacific-North America plates)

References

          APA reference

The net force on the airplane window of area 1800 cm² is 3469.47 Pa.m² .

Given:

Pressure inside the cabin: 0.95 atm

Pressure outside the cabin: 0.76 atm

Area of the airplane window: 1800 cm²

Now to find the net force on the airplane window, we can calculate the pressure difference between the inside and outside of the cabin and to calculate the pressure difference, we subtract the outside pressure from the inside pressure.

Pressure Difference = Pressure inside - Pressure outside

Pressure Difference = 0.95 atm - 0.76 atm

Pressure Difference = 0.19 atm

The area of the airplane window is given as 1800 cm². To simplify calculations in SI unit we convert the area to square meters:

Area in m² = (Area in cm²) / 10,000

Area in m² = 1800 cm² / 10,000

Area in m² = 0.18 m²

As we know,

Net Force = Pressure Difference * Area

Net Force = 0.19 atm * 0.18 m²

Net Force = 0.0342 atm·m²

To convert the net force to pascals (Pa), we use 1 atm = 101325 Pa. Multiplying the net force by 101325 Pa, we get

Net Force = 3469.47 Pa·m²

Therefore, the net force on the airplane window is approximately 3469.47 pascals times square meters (Pa.m²).

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The size of the angle θ of a point object moving from point A to point B along a circular path is 2πR / L.

To understand this, consider a simple example. Suppose that a point object that moves from point A to point B along a circular path with a radius of 1 meter. The distance between points A and B is also 1 meter. Therefore, the size of the angle θ is equal to 2π × 1 / 1 = 2π radians.

In general, the size of the angle θ = ratio of the circumference of the circle to the distance between points A and B. The circumference of the circle is equal to 2πR, where R = radius of the circle. Therefore, the size of the angle θ is equal to 2πR / L.

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Complete question:

A point object moves from point A to point B along a circular path with a radius R. What is the size of the angle θ?

The amount of force required to accelerate the given mass of the wagon is 129 Newtons.

A force is simply referred to as either a push or pull of an object resulting from the object's interaction with another object.

From Newton's Second Law, force is expressed as;

F = m × a

Where is mass of object and a is the acceleration.

Given the data in the question;

F = 8.6kg × 15m/s²

F = 129kgm/s²

F = 129N

Therefore the amount of force required to accelerate the given mass of the wagon is 129 Newtons.

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Answer:

Absorbed sunlight is balanced by heat radiated from Earth's surface and atmosphere. ... The atmosphere radiates heat equivalent to 59 percent of incoming sunlight; the surface radiates only 12 percent. In other words, most solar heating happens at the surface, while most radiative cooling happens in the atmosphere

Answer:

(a). The specific volume at the final state is 0.25 m³/kg.

(b). The energy transfer by work is 50.4 kJ.

(c). The energy transfer by heat  is -10.4 kJ.

Negative sign shows the direction of heat

Explanation:

Given that,

Weight of carbon monoxide = 4 kg

Volume of tank = 1 m³

Constant rate of 14W for 1 hour

The specific internal energy of the carbon monoxide increases by 10 kJ/kg.

(a). We need to calculate the specific volume at the final state

Using formula of specific volume

\(V'=\dfrac{V}{m}\)

Put the value into the formula

\(V'=\dfrac{1}{4}\)

\(V'=0.25\ m^3/kg\)

(b). We need to calculate the energy transfer by work

Using formula of work

\(W=Pt\)

Where, P = power

t = time

Put the value into the formula

\(W=14\times1\times3600\)

\(W=50.4\ kJ\)

(c). The energy transfer by heat transfer, and the direction of the heat transfer

We need to calculate the \(\Delta U\)

Using formula of internal energy

\(\Delta U=m\Delta u\)

Put the value into the formula

\(\Delta U=4\times10\)

\(\Delta U=40\ kJ\)

We need to calculate the energy transfer by heat

Using formula of energy transfer

\(Q=\Delta U-W\)

Put the value into the formula

\(Q=40-50.4\)

\(Q=-10.4\ kJ\)

Negative sign shows the direction of heat that is removed from CO.

Hence, (a). The specific volume at the final state is 0.25 m³/kg.

(b). The energy transfer by work is 50.4 kJ.

(c). The energy transfer by heat  is -10.4 kJ.

Negative sign shows the direction of heat.

Answer:

8 + 6 = 14 miles north

Explanation:

Explanation:

The buoyant force \(F_B\) is defined as

\(F_B = \rho_wgV\)

where \(\rho_w\) is the density of the displaced fluid (freshwater), g is the acceleration due to gravity and V is the volume of the submerged object. In the case of freshwater, its density is \(997\:\text{kg/m}^3.\) Since the buoyant force is 20 N, we can solve for the volume of the displaced fluid:

\(F_B = \rho_wgV \Rightarrow V = \dfrac{F_B}{\rho_wg}\)

Plugging in the values, we get

\(V = \dfrac{20\:\text{N}}{(997\:\text{kg/m}^3)(9.8\:\text{m/s}^2)}\)

\(\:\:\:\:\:= 2.05×10^{-3}\:\text{m}^3\)

Recall that the weight of an object in terms of its density and volume is given by

\(W = \rho gV\)

Using the value for the volume above, we can solve for the density of the object as follows:

\(\rho = \dfrac{W}{gV} = \dfrac{900\:\text{N}}{(9.8\:\text{m/s}^2)(2.05×10^{-3}\:\text{m}^3)}\)

\(\:\:\:\:\:= 44,798\:\text{kg/m}^3\)

The correct answer for the radius of a white dwarf is determined by a balance between the inward force of gravity and the outward push of is Electron Degeneracy Pressure.

 How does a white dwarf's mass affect its radius?

When you raise pressure, you also increase gravity and make the particles closer together, which causes the thing to get smaller because the only way to increase pressure is by adding mass. In other words, the radius of a white dwarf decreases with increasing mass.

A star's gravitational collapse will be stopped by electron degeneracy pressure if its mass is below the Chandrasekhar limit (1.44 solar masses). The force preventing a white dwarf star from collapsing is this one.

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The equilibrium between the outward push of "electron degeneracy pressure" and the inward force of gravity determines a white dwarf's radius.

What is quantum degeneracy pressure?

The more widespread phenomenon known as quantum degeneracy pressure has many different manifestations, including electron degeneracy pressure. As a result, a pressure is created to prevent the compression of matter into smaller amounts of space. The same fundamental process that determines the electron orbital structure of elements produces electron degeneracy pressure.

If a star's mass is below the Chandrasekhar limit, electron degeneracy pressure will prevent gravitational collapse (1.44 solar masses). A white dwarf star is kept from collapsing by this pressure. Because the degeneracy pressure provided by the electrons is weaker than the gravitational pull inward, a star that is larger than this limit.

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a) The equivalent resistance in series = 7.65 kΩ

b) The equivalent resistance in parallel = 0.51 kΩ

The resistances of the given resistors are:

The equivalent resistance in series:

b) The equivalent resistance in parallel

Answer:

Explanation:

total weight acting downwards

= 3g + 10g

13 g

volume of lead = 10 / 11.3 = .885 cm³

Let the volume of bobber submerged in water be v in floating position . buoyant force on bobber  = v x 1 x g

Buoyant force on lead =  .885 x 1 x g

total buoyant force = vg + .885 g

For floating

vg + .885 g  = 13 g

v = 12.115 cm³

total volume of bobber

= 4/3 x 3.14 x 2³

= 33.5 cm³

fraction of volume submerged

= 12.115  / 33.5

= .36  

= 36 %

The fraction of the bobber's volume submerged as a percent of the total volume is 36.2 %.

The given parameters;

The volume of the bobber is calculated as follows;

\(V = \frac{4}{3} \pi \times r^3\\\\V = \frac{4}{3} \pi \times (2)^3\\\\V = 33.52 \ cm^3\)

The buoyant force experienced by the bobber due to the volume submerged is calculated as follows;

\(F _b= \rho Vg\\\\F_b = 1 \times V \times g\\\\F_b = Vg\)

The volume of the lead is calculated as follows;

\(V = \frac{mass}{density} \\\\V = \frac{10}{11.3} \\\\V = 0.885 \ cm^3\)

The buoyant force experienced by the lead due to the volume submerged is calculated as follows

\(F_b = \rho Vg\\\\F_b = 0.885 g\)

The total buoyant force is calculated as;

\(Vg + 0.885g = (3+ 10)g\\\\g(V + 0.885) = 13g\\\\V+ 0.885 = 13\\\\V = 13 -0.885\\\\V = 12.12 \ cm^3\)

The fraction of the bobber's volume submerged as a percent of the total volume is calculated as follows;

\(= \frac{12.12}{33.52} \times 100\%\\\\= 36.2 \ \%\)

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Answer:

is there more?

Explanation:

Although we do not have the necessary information to provide an exact answer, we can confirm that the object will have fallen by a multiple of 9.8 meters due to gravity.

When an object is dropped, its acceleration is determined by gravity. This force applies a constant acceleration of 9.8 meters per second. Therefore, to calculate its speed at distance h, we would need to know the time it has taken the object to reach this point, and use that together with our known acceleration in order to calculate its current speed.

Therefore, we can confirm that in order to calculate the current speed of the object at point h, we require the time taken to reach this point or the value of the distance itself and that the answer will be a multiple of 9.8, due to gravity.

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Answer: They are in the same group because they have similar chemical properties, but they are in different periods because they have very different atomic numbers.

Explanation: On Edgenuity!!

The comparison is best supported by the information given in option 4. They differ due to their atomic number.

A star is a bright spheroid of plasma held together by gravity. The Sun is the most distant star from Earth.

Many additional stars may be seen with the normal eye at night, but their enormous distance from Earth causes them to appear as stationary points of light in the sky.

We are discussing the two-element beryllium (Be) and barium (Ba). The comparison is best supported by this information will be;

They are in the same group because they have similar chemical properties, but they are in different periods because they have very different atomic numbers.

Hence option 4 is correct.

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Answer: \(278\ Hz\)

Explanation:

Given

Distance between two speakers is 8 m

Man is standing 12 away from the wall

When the person moves 3 parallel to the wall

the parallel distances from the speaker become 4+3, 4-3

Now, the difference of distances from the speaker is

\(\Delta d=\sqrt{12^2+(4+3)^2}-\sqrt{12^2-(4-3)^2}\\\Delta d=1.85\ m\)

Condition for destructive interference is

\(\Delta d=(2n-1)\dfrac{\lambda }{2}=(2n-1)\dfrac{\nu }{2f}\\\\\Rightarrow f=(2n-1)\dfrac{v}{2\Delta d}\)

for second destructive interference; n=2

\(\Rightarrow f=(2\times 2-1)\dfrac{343}{2\times 1.85}=278.10\approx 278\ Hz\)

Answer:

V=IR

I=V/R

I=100/1000

I=0.1A

Answer:

Each connection requires 50 centimeters of wire, which is equal to 0.5 meters of wire. Therefore, for eight connections, the electrician would need:

8 * 0.5 = 4 meters of wire

Therefore, the correct answer is option D, 4 m.

:

Answer:

0.21 SECONDS

Explanation:

THE CAR TRAVELS AT A SPEED OF 140M/S AND A DISTANCE AS THE PREVIOUS = 3M THEREFOR S=D/T, T=D/S= 3/140= 0.12 SEC