Answer:
2 moles
Explanation:
For a mole NaCi, we have a mole of sodium ion and a mole of chloride.
Which of the following properties is associated with the existence of glycine as a dipolar ion in aqueous solution?
A) High dipole moment
B) High molecular weight
C) Low dielectric constant
D) Low solubility in water
The property associated with the existence of glycine as a dipolar ion in aqueous solution is High dipole moment
What is dipole moment?Dipole moments occur when there is a separation of charge. Dipole moments can exist between two ions in an ionic bond or between atoms in a covalent link; they are caused by changes in electronegativity. The dipole moment grows in proportion to the difference in electronegativity.
According to the question,
Glycine exists as a "dipolar ion in aqueous solution." Polarity in neutral molecules is caused by an unequal distribution of electron density, which might result from the separation of opposite charges. This happens in zwitterions. Also, molecules that have strong electron-withdrawing or electron-donating substituents are highly polar and have high dipole moments.
The property associated with the existence of glycine as a dipolar ion in aqueous solution is High dipole moment.
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Which statements describe inorganic compounds? Check all that apply
Inorganic compounds contain carbon
Inorganic compounds usually lack carbon
Inorganic compounds are not associated with or made from living things,
Inorganic compounds include fruits and vegetables,
Inorganic compounds include salt and water
Answer:
b, c, e
Explanation:
Inorganic compounds usually lack carbon.
Inorganic compounds are not associated with or made from living things.
Inorganic compounds include salt and water.
Answer:
yes the answer id bce
Explanation:
1)Grignard reagent when reacted with methanol will yield A) ethanol (B) secondary alcohols (C) tertiary alcohols (D ropanol (E) primary alcohol
When the reaction of Grignard reagent reacted with methanol will yield a tertiary alcohol. Therefore, Option C tertiary alcohol is correct.
Contains a carbon-metal link, Grignard reagents are chemicals used in catalysis. They generally result from the anhydrous reaction of magnesium metal with an alkyl or aryl halide. Because of their high reactivity, Grignard reagents frequently act as nucleophiles in organic reactions.
An alkyl group from a Grignard reagent binds to the oxygen atom of methanol (CH3OH) when it interacts with the methanol, breaking the carbon-metal connection. A precursor alkoxide is created as a result. The equivalent alcohol is then produced by protonating the intermediate alkoxide.
The reaction of a Grignard reagent with methanol leads to the formation of a tertiary alcohol.
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what are the limiting and excess reactants when 3.22 moles of Al react with 6.96 moles of HBr
Answer
HBr is the limiting reactant
Al is the excess reactant.
Explanation
Given:
Moles of Al = 3.22 mol
Moles of HBr = 6.96 mol
Equation: 2 Al + 6 HBr → 2 AlBr₃ + 3 H₂
What to find;
The limiting and excess reactants.
Solution:
Note: The limiting reactant is the reactant that is completely used up in a reaction, and thus determines when the reaction stops. While the excess reactant is the opposite.
From the given balanced chemical equation;
2 moles of Al require 6 moles of HBr
Therefore, the given 3.22 moles of Al will require (3.22/2) x 6 = 9.66 moles of HBr
Since the given moles of HBr is 6.96 mol not up to 9.66 moles required, then HBr is the limiting reactant and Al is the excess reactant.
HBr is the limiting reactant
Al is the excess reactant.
is a pH an atom, ion, molecule, macromolecule, or a cell?
Although there is some variation amongst tissues, the physiologically typical intracellular pH ranges from 7.0 to 7.4. Skeletal muscle in mammals typically has a pHi of 6.8 to 7.1.
A cell is it an atom?A cell is the basic membrane-bound living thing and can either have one or more cells. All the molecules required for an organism to function are found in cells. An atomic is 10-10m in size. In contrast, a cellular is 10-6 metres in size. Because all cells are composed of atoms, they are therefore bigger than atoms.
What keeps a cell's pH stable?Acid excretion, efflux through plasma membranes, and buffering mechanisms all work together to precisely preserve the pH of body fluids. Protons are extruded from the cytosol into the extracellular space through the organic cation transporter (MCT) and the Na+/H+ exchanger (NHE).
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Please Help 3. Were there any metallic compounds that did not react with either the acid or the base? Write the type of metal, based on your examination of the periodic table.
Answer:
1)KNO3 ( pottasium trioxonitrate (V)
2)Ca(NO3)2 (calcium trioxonitrate (V
Explanation:
1)KNO3 ( pottasium trioxonitrate (V)
2)Ca(NO3)2 (calcium trioxonitrate (V)
Thses two compounds are metallic compounds and does not react with either the acid or the base.
Write the type of metal, based on your examination of the periodic table?
1)KNO3 ( pottasium trioxonitrate (V) have a potassium element which belongs to group 2 of the Periodic table which is an alkaline metal and can react with water or steàm
2)Ca(NO3)2 (calcium trioxonitrate (V) has calcium metal element which is an alkaline earth metal in the Periodic table and they react with Hallogens
The absolute temperature of a gas is increased four times while maintaining a constant volume. What happens to the
pressure of the gas?
Plzzz help me plz I am timed!!
Answer:
Explanation:
pretty sure its gaillieo
Answer:
Galileo
Explanation:
he was the first one to use a telescope
4.) What is atomic number.
Answer: the number of protons in the nucleus of an atom, which determines the chemical properties of an element and its place in the periodic table.
Explanation:
the aim of an experiment is to
A. massage the data
B.test a hypothesis
C. declare the unknown
Answer:
1) test a hypothesis this is the main aim of experiment
A student borrows $10,000 from a bank but ends up paying $13,000 on the
loan over the next five years. How much interest did the student pay?
The student paid an interest of $3,000 over the next five years.
HOW TO CALCULATE INTEREST:
The interest on a borrowed amount of money can be calculated by subtracting the principal from the amount paid over time. That is;
Interest = principal - amount
According to this question, a student borrows $10,000 from a bank but ends up paying $13,000. This means that the principal is $10,000 while the amount is $13,000. The interest is calculated thus;
Interest = $13,000 - $10,000
Interest = $3,000
Therefore, the student paid an interest of $3,000 over the next five years.
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how do one get this solution
-log10 (2* 10^-2)
The result of the computation when you follow the steps is 1.699.
A logarithm is a mathematical function that represents the exponent or power to which a specific base must be raised to obtain a given number. In simpler terms, it answers the question: "To what power must we raise a base number to obtain a certain value?"
What you should do is that on your calculator, you could press the logarithm key and then put in the value that has been shown and then the result would be displayed on your calculator.
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Mg3N2 (s) + 3H2O (l) —> 2NH3 (g) + 3MgO (s)a) What mass of Magnesium oxide is created from 3.82 g of magnesium nitride and 7.73 g of water? b) if 3.60 g were formed, what is the percent yield?
According to the given reaction, 1 mole of Mg3N2 reacts with 3 moles of H2O.
This, converted to mass, is 101g of Mg3N2 react with 54g of H2O.
From this we can conclude that the limit reagent is Mg3N2.
We have to base our calculation on the mass of Mg3N2 given.
During the reaction, 3 moles of MgO are produced from 101g of Mg3N2. This, converted to mass, is 120.9g of MgO.
a. Use this ratio to find how many grams of MgO are produced from 3.82 grams of Mg3N2:
\(3.82gMg_3N_2\cdot\frac{120.9gMgO}{101gMg_3N_2}=4.57gMgO\)b. To find the percent yield, divide the mass of MgO formed by the theoretical mass of MgO and multiply times 100:
\(\%y=\frac{3.60g}{4.57g}\cdot100=78.8\%\)The percent yield is 78.8%.
Consider the following equilibrium: HCOOH(aq) + H2O(l) ↔ HCOO-(aq) + H3O+(aq). How will the addition of a small amount of NaOH affect the equilibrium?
A. It will shift to the left.
B. It will shift to the right.
C. It won't be affected.
D. More information is needed.
What does evaporation produce?
a precipitation
brain or snow
С
water vapor
d condensation
Answer:
C. Water Vapor
Explanation:
Hope this helps! Have an Amazing day!!
Answer: Hewo, there! your answer is Below
c. water vapor Is the correct answer.
Explanation:
The molecules move and vibrate so quickly that they escape into the atmosphere as molecules of water vapor.
Hope this helps you!
Have a great day!!
-August-
Chemistry Lab Determination of the Universal Gas Constant (R)
SHOW ALL WORK
Given:
Initial mass of butane lighter: 54.24g
Final Mass of Butane Lighter: 54.01g
Temperature of water: 23.0°C
Volume of gas collected: 100.0mL
FIND:
Barometric pressure of room: 766.86 mmHg CONVERTED TO atm
Vapor pressure of water at room temperature(PH2O) (IN atm)
FIND:
Mass difference if butane lighter in grams
Moles of Butane gas collected in moles of C4H10
Partial pressure if butane gas in atm
Converted temperature of water in Kelvin
Converted volume of gas collected in Liters
Experimental value of R in Latm/molk
Accepted value of R in Latm/molk
Percent error in experimental value of R in %
CONCLUSION QUESTIONS:
1. List at least 3 factors that either did it could contribute to the percent error
2. Should the value of R go up or down if the gas had not been corrected for the partial pressure of water. Why?
3. How could this experiment be repeated to increase the accuracy, or in other words, decrease the percent error?
NOTE: LET ME KNOW IF YOU WANT A PICTURE OF THE LAB INSTRUCTIONS TO HELP SOLVE
ALSO SHOW ALL WORK PLS
To determine the universal gas constant (R), we can use the ideal gas law equation: PV = nRT, where P is the total pressure, V is the volume of gas, n is the number of moles, R is the universal gas constant, and T is the temperature in Kelvin.
Barometric pressure of the room: To find the barometric pressure in atm, we convert 766.86 mmHg to atm by dividing it by 760 mmHg/atm, giving us 1.0089 atm.Vapor pressure of water at room temperature (PH2O).The vapor pressure of water at 23.0°C is 0.0313 atm.
Mass difference of butane lighter:The mass difference is calculated by subtracting the initial mass (54.24 g) from the final mass (54.01 g), resulting in a difference of 0.23 g.
Moles of butane gas collected:To find the moles of butane gas, we can use the equation n = m/M, where n is the number of moles, m is the mass, and M is the molar mass of butane (58.12 g/mol). Thus, n = 0.23 g / 58.12 g/mol = 0.003959 mol.
Partial pressure of butane gas:The partial pressure of butane gas is calculated by multiplying the moles of butane gas (0.003959 mol) by the ideal gas constant (R) and the converted temperature (23.0°C + 273.15 K). Let's assume the converted temperature is 296.15 K.
Converted volume of gas collected:The volume of gas collected is given as 100.0 mL, which needs to be converted to liters by dividing it by 1000, resulting in 0.1 L.
Experimental value of R:The experimental value of R can be determined by rearranging the ideal gas law equation to solve for R: R = (P - PH2O) * V / (n * T).
Accepted value of R:The accepted value of R is 0.0821 Latm/molK.
The percent error can be calculated using the formula: (|Experimental value - Accepted value| / Accepted value) * 100.
Factors contributing to percent error could include experimental error in mass measurements, inaccurate temperature measurements, and loss of gas during collection or transfer.
If the gas had not been corrected for the partial pressure of water, the value of R would be lower because the partial pressure of water would contribute to the total pressure, resulting in a smaller value for P in the ideal gas law equation.
To increase accuracy and decrease percent error, the experiment could be repeated multiple times to obtain an average value, use more precise measuring instruments, conduct the experiment in a controlled environment, and ensure accurate calibration of equipment.
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what is the molar mass of a gas with a density of 1.34g / l at STP?
Considering the STP conditions and the definition of molar mass, the molar mass of the gasis equal to 30.016 g/mole.
STP conditionsThe STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0°C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.
Definition of molar massMolar mass is the amount of mass that a substance contains in one mole.
Molar mass of a gas with a density of 1.34 g/L at STPThe density of a substance is the mass you have per unit of volume of that substance. So you know that 1.43 g/L means that 1 L of this gas has a mass of 1.43 g.
Knowing that one mole of gas at STP occupies 22.4 litres, you can say that 1 mole of this gas will have a mass of:
22.4 L× \(\frac{1.34 g}{1 L} \)= 30.016 g
Finally, if 1 mole of this gas has a mass of 30.016 g, its molar mass is equal to 30.016 g/mole.
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molar mass with this example:https://brainly.com/question/1145279STP conditionshttps://brainly.com/question/8846039https://brainly.com/question/13839640https://brainly.com/question/11863561b. Suppose that you were titrating a 100 mL acid solution with the 0.1 M NaOH solution that you made. You performed the titration multiple times and obtained the data below. Complete the data table below. Show work on a separate piece of paper/ the back of this paper.
Step 1: Write and balance the chemical equation (only need to do this once for each titration)
Step 2: Use the molarity and mL of base used to find the moles of base it took to neutralize the acid
Step 3: Calculate moles of acid neutralized
Step 4: Calculate molarity of acid
Step 5: Calculate pH
1c. Calculate the most likely pH of the acid solution by finding the average of all the pH's you found in each of your multiple titrations. We find the average to minimize human errors made while titrating.
The moles of NaOH used is 0.0008 moles
The molarity of the acid is 0.008 M
What is the molarity of the acid?The molarity of the acid is found as follows:
Moles of NaOH used = concentration of NaOH × volume of NaOH used
the average volume of NaOH used = 8.0 mL
moles of NaOH = 0.1 M × 8.0 mL
moles of NaOH = 0.0008 moles
Molarity of acid:
Assuming the acid is monobasic, the mole ratio of acid to base is 1 : 1
The volume of acid used is 100 mL
The molarity of acid = moles of acid / volume of acid in liters
The molarity of acid = 0.0008 moles / 0.1 L
The molarity of acid = 0.008 M
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At what temperature does Benzene boil when the external pressure is 440 torr
The boiling point of benzene when the external pressure is 440 torr is 80.1 °C (176.2 °F).
What is benzene?
Benzene is an organic compound composed of six carbon atoms in a ring structure, with one hydrogen atom attached to each carbon atom. It is a highly flammable, colorless liquid with a sweet smell. Benzene is a natural component of crude oil and is one of the most important organic chemicals used in industry. It is used in the production of plastics, resins, synthetic fibers, rubber, pesticides, detergents, drugs, and dyes. It is also used as a solvent for fats, oils, waxes, resins, and inks. Benzene is classified as a carcinogen and its exposure can cause a variety of adverse health effects, including acute myelogenous leukemia, lymphomas, and other forms of cancer.
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6. How many moles are in 8.30 x 1023 molecules of CO₂?
a.
b.
C.
d.
1.37
2.8
55.5
100
Hi! I need some solar system facts!
Answer: I can help with that!
Explanation: 1.The tremendous growth in the U.S. solar industry is helping to pave the way to a cleaner, more sustainable energy future. Over the past few years, the cost of a solar energy system has dropped significantly -- helping to give more American families and business access to affordable, clean energy.
Through a portfolio of R&D efforts, the Energy Department remains committed to leveraging America’s abundant solar energy resources -- driving research, manufacturing and market solutions to support widespread expansion of the nation’s solar market.
2.The amount of sunlight that strikes the earth's surface in an hour and a half is enough to handle the entire world's energy consumption for a full year. Solar technologies convert sunlight into electrical energy either through photovoltaic (PV) panels or through mirrors that concentrate solar radiation. This energy can be used to generate electricity or be stored in batteries or thermal storage.
Below, you can find resources and information on the basics of solar radiation, photovoltaic and concentrating solar-thermal power technologies, electrical grid systems integration, and the non-hardware aspects (soft costs) of solar energy. You can also learn more about how to go solar and the solar energy industry. In addition, you can dive deeper into solar energy and learn about how the U.S. Department of Energy Solar Energy Technologies Office is driving innovative research and development in these areas.
3.Solar radiation is light – also known as electromagnetic radiation – that is emitted by the sun. While every location on Earth receives some sunlight over a year, the amount of solar radiation that reaches any one spot on the Earth’s surface varies. Solar technologies capture this radiation and turn it into useful forms of energy.
PLEASE HELP QUICKLY!!!
HI gas is removed from the system
at equilibrium below. How does the
system adjust to reestablish
equilibrium?
51.8 kJ + H₂(g) + 1₂(g) = 2HI(g)
A. The reaction shifts to the right (products) and the concentrations
of I, and H₂ decrease.
B. The reaction shifts to the left (reactants) and the concentrations
of H₂ and I increase.
C. The reaction shifts to the right (products) and the concentrations
of I, and H₂ increase.
D. The reaction shifts to the left (reactants) and the concentration of
HI increases.
Answer:
A. The reaction shifts to the right (products) and the concentrations of I and H₂ decrease.
Explanation:
If gas is removed from the system at equilibrium, the system will try to compensate for the loss by shifting the reaction in a direction that produces more gas molecules. This is known as Le Chatelier's principle, which states that a system at equilibrium will respond to a disturbance by shifting in a way that minimizes the effect of the disturbance.
In this case, since gas is being removed from the system, the reaction will shift to the side that produces more gas molecules. Looking at the balanced equation, we can see that 2HI(g) has a greater number of gas molecules compared to H₂(g) and I₂(g). Therefore, the system will shift to the right (products) to produce more HI(g) and reestablish equilibrium.
Which reaction is the opposite of a decomposition reaction?
Question 3 options:
Electrolysis of Water
Synthesis
Combustion
Explosion
Answer:
B) Synthesis reaction
Explanation:
synthesis reactions because they take apart larger molecules or compounds
Hope that helps
The word atom comes from the Greek word that means
A. indivisible
B. element
C. volatile
D. miniature
Answer: But when it comes to the word atom, we have to go to ancient Greece of 400 B.C. And there was a brilliant philosopher named Democritus, and he proposed the Greek word atomos, which means uncuttable. And so as he explained, all matter was eventually reducible to discrete, small particles or atomos.
Explanation:
Answer:
indivisible
Explanation:
How many grams of Al2O3 can be produced from 7.5 g AL
Answer:
n=given mass/reaction mass=13.6/27=1/2
Now.,
n=given mole/reaction mole(Al2O3)=1/2/2=1/4
Now.,
n=mass/molar mass(Al2O3)
mass=1/4*102=25.50grams
How many valence electrons are found in P3- ?
Answer:
5 valence elctrons
Explanation:
the outer most orbitals, 3s2 and 3p3 contains 5 electrons, thus valences electrons for P is 5
ofthepistonis1.0m3 ofairat400K,3bar.Ontheothersideis1.0m3 of air at 400 K, 1.5 bar. The piston is released and equilibrium is attained, with the piston experiencing no change of state. Employing the ideal gas model for the air, determine a. the final temperature of the air, in K. b. the final pressure of the air, in bar. c. the amount of entropy produced, in kJ/K.
The entropy indicates the amount of thermodynamic energy that is not
available for work.
a. The final temperature is 400 K
b. The final pressure is 2.25 bar
c. The amount entropy produced, Δs is approximately 0.063712 kJ/K
Reason:
The given parameters are;
Type of box = Insulated
Volumes into which the box is divided = Equal volumes
Type of piston = Frictionless, thermally conducting
Volume on each side of the piston = 1.0 m³
Temperature on each side of the piston, T₁ = T₂ = 400 K
Pressure on one side of the piston = 3.0 bar
Pressure on the other side of the piston = 1.5 bar
a. The final temperature of the air;
Given that the piston is frictionless and allowed move freely, and air is
contained on both sides of the piston, we have;
The system is equivalent to the piston being removed such that the gas
moves freely in the box.
Therefore, the high pressured side drops in temperature while the low
pressure side gains temperature, such that the change in temperature is
zero.
Which gives; T₁ = T₂ = \(T_f\)
Therefore;
The final temperature, \(\mathbf{T_f}\) = T₁ = T₂ = 400 K
b. The final pressure is given as follows;
We have;
\(\dfrac{P_{1}\times V_{1}}{T_{1}} = \dfrac{P_{f}\times (V_{1} -V) }{T_{f}}\)
\(\dfrac{3\times 1}{400} = \dfrac{P_{f}\times (1+V) }{T_{f}}\)
\(\dfrac{P_{2}\times V_{2}}{T_{2}} = \dfrac{P_{f}\times (V_{2} +V) }{T_{f}}\)
\(\dfrac{1.5\times 1}{400} = \dfrac{P_{f}\times (1 -V) }{T_{f}}\)
\(\dfrac{1 + V}{1 - V} = 2\)
Which gives;
\(V = \dfrac{1}{3}\)
\(T_f\) = 400 K, gives;
\(\dfrac{1.5\times 1}{400} = \dfrac{P_{f}\times \left (1 -\dfrac{1}{3} \right) }{400} = \dfrac{\dfrac{2}{3} \cdot P_f}{400}\)
\(1.5\times 1} =\dfrac{2}{3} \cdot P_f}\)
\(P_f = \dfrac{3 \times 1.5\times 1 }{2} = 2.25\)
The final pressure, \(\mathbf{P_f}\) = 2.25 bar
c. The amount of entropy produced, in kJ/K
The change in entropy is given by the formula;
\(\Delta s = \Delta s_1 + \Delta s_1 = -R \cdot \dfrac{P_1 \cdot V_1}{R \cdot T_1} \cdot ln\dfrac{P_f}{P_1} + \left(-R \cdot \dfrac{P_2 \cdot V_2}{R \cdot T_2} \cdot ln\dfrac{P_f}{P_2} \right)\)
\(\Delta s = -\dfrac{P_1 \cdot \dfrac{V}{2} }{ T_f} \cdot ln\dfrac{P_f}{P_1} + \left(-\dfrac{P_2 \cdot \dfrac{V}{2} }{ T_f} \cdot ln\dfrac{P_f}{P_2} \right)\)
Which gives;
\(\Delta s = -\dfrac{3 \times \dfrac{2}{2} }{ 400} \cdot ln\dfrac{2.25}{3} + \left(-\dfrac{1.5 \cdot \dfrac{2}{2} }{ 400} \cdot ln\dfrac{2.25}{1.5} \right) \approx 6.371 \times 10^{-4}\)
Δs = 6.371 × 10⁻⁴ bar·m³/K = 63.712 J/K = 0.063712 J/K
The entropy produced, Δs = 0.063712 kJ/K.
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What was one important discovery that the Curies made?
O A material's radioactivity cannot be changed by altering the material physically
O A material's radioactivity can be weakened or intensified by changing it chemically.
O Radioactive materials generally contain radium or polonium.
O Radioactive materials are found only in the form of salts.
Answer:
C is the answer to your question
A copper penny will sink in molten copper. What can you infer about the difference in distance between the molecules in a copper penny and in molten copper?
The molecules in a copper penny is closely packed and and has no space to move apart thus the material will be denser than that in the molten state. That's why the penny sink in the molten copper.
What is molten copper?Copper is a transition metal exhibiting all the metallic properties. The molten state of metals is the fluid state where the molecule are not strongly held by the metallic bonds.
Molten material is made by melting them and the liquid like state contains molecules with some space to move apart. Whereas, in solid state as in a copper penny, the molecules are closely packed and have no space to move apart.
An object will sink in a liquid if it is less dense than the liquid. Copper penny is denser than the molten copper because the molecules are densely packed and it will sink on to it.
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12.39 HBr can be added to alkenes in either the absence or presence of peroxides (producing either the Markovnikov or the anti-Markovnikov addition product). What intermediates leading to the formation of the major product are observed when 1-butene is treated with 1) HBr or 2) HBr/peroxides
Answer:
See explanation and image attached
Explanation:
The reaction of HBr with 1-butene is an addition reaction. The HBr adds across the double bond to yield a saturated halogenoalkane.
In the absence of peroxides, the reaction proceeds in accordance with Markovnikov rule which states that;''the negative part of the addendum, is attached to the carbon atom with the least number of hydrogen atoms attached.'' This occurs in the first reaction shown in the image.
In the presence of peroxides, the reaction proceeds in an anti-Markovnikov manner to yield the product shown in the second reaction.