50POINTS!
Using the ideal gas law (PV=nRT) solve for the missing. Variable. R= 0.08206atm*L/mol*k

If 22.9L of an ideal gas was collected at STP. How many moles of the gas were present?

A. 1.02 moles
B. 5.99 moles
C. 3.05 moles
D. 2.74 moles

Answer:

Atoms gain energy as a solid changes to a liquid. If atoms energy during a change of state, they are pulled together by attractive forces and become more organized.

Answer:

its B

Explanation:

Answer:

B.) The flask on the left is the strong acid because 100% of the molecules dissociate.

Explanation:

First, let's review the concept of strong acid: A strong acid is an acid that is completely ionized in an aqueous solution. Let's see an example of this:

Now, you can see the picture and imagine that the grey circles are Cl and the black circles are H, so as HCl is a strong acid and it dissociates completely in two different ions, the strong acid would be the first flask. It wouldn't be the second flask because there are some molecules that don't dissociate completely (because they are not 'separated').

Based on this logic, the answer would be B.) The flask on the left is the strong acid because 100% of the molecules dissociate.

Answer:

The chemical compound Mg(NO3)2, also known as magnesium nitrate, is very soluble, especially in water.

Answer:

115.6 kJ/mol

Explanation:

The ΔG of a reaction can be calculated using the following equation:

ΔG = ΔG° + RT ln(Q)

where:

ΔG° is the standard free energy change, which is given as 137.0 kJ/mol in this case

R is the gas constant, which is 8.314 J/(mol·K)

T is the temperature in Kelvin, which is 25°C + 273.15 = 298.15 K

Q is the reaction quotient, which is the ratio of the concentrations of the products to the concentrations of the reactants, each raised to their stoichiometric coefficients.

From the chemical equation given, the stoichiometric coefficients of Mg2+ and PO43- are 3 and 2 respectively. Therefore, the reaction quotient can be expressed as:

Q = [Mg2+]^3 [PO43-]^2

Substituting the given initial concentrations of Mg2+ and PO43- into the reaction quotient expression, we get:

Q = (0.65 M)^3 (0.43 M)^2 = 0.011 M^5

Now we can calculate the ΔG of the reaction:

ΔG = ΔG° + RT ln(Q)

ΔG = (137.0 kJ/mol) + (8.314 J/(mol·K) × 298.15 K) × ln(0.011 M^5)

ΔG = 137.0 kJ/mol - 21.38 kJ/mol

ΔG = 115.6 kJ/mol

Therefore, the ΔG for the reaction at 25°C and the given initial concentrations of Mg2+ and PO43- is 115.6 kJ/mol.

Answer:

The Ranking from

Hardest to softest is as follows :

0.80 wt% C with fine pearlite.

0.80 wt% C with spheroidite

0.25 wt% C with coarse pearlite

0.25 wt% C with spheroidite

Explanation:

To find - Rank the following iron-carbon alloys and associated microstructures from the hardest to the softest. Justify this ranking.

Solution -

Ranking is as follows :

(d) 0.80 wt% C with fine pearlite.

(b) 0.80 wt% C with spheroidite

(a) 0.25 wt% C with coarse pearlite

(c) 0 25 wt% C with spheroidite

Justification -

For some wt% C,

Fine pearlite is stronger than spheroidite

and

Coarse pearlite is stronger than spheroidite.

Now,

Due to carbon content,

0.80 wt% C with spheroidite is stronger than 0.25 wt% C with coarse pearlite.

So,

The Ranking from

Hardest to softest is as follows :

0.80 wt% C with fine pearlite.

0.80 wt% C with spheroidite

0.25 wt% C with coarse pearlite

0.25 wt% C with spheroidite

Answer:

See picture and explanation below

Explanation:

In the attached picture you have the answer for this.

In the first step, we have an acid base reaction between HCN and NaOH. When this happens, its formed the following:

HCN + NaOH --------> CN⁻ + H₂O + Na⁺

As a second step, The CN⁻ attacks the carbonile group in the cyclopentane. This causes to open the double bond, and then, the Cyano enters the molecule.

The final step is another acid base reaction, where the oxygen substracts a hydrogen atom of the water in the medium, and then, the alcohol group is formed. With this step, the cyanohydrin is finally formed. See the mechanism below in the picture.

Hope this helps

Answer:

ZnCl2

H2

Explanation:

The products of the given reaction is:

      ZnCl₂  and H₂

The two species are the products of the chemical combination

Answer:

because it absorbs all colours expect for red,

Explanation: making the red light bounce into your eyes, therefore seeing the colour red

Question 2: The wave transfers its energy to the mineral, I think, thats my best guess

Answer: The molecular formula for the given organic compound is \(C_{18}H_{20}O_2\)

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

\(C_xH_yO_z+O_2\rightarrow CO_2+H_2O\)

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of \(CO_2=39.61g\)

Mass of \(H_2O=9.01g\)

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 39.61 g of carbon dioxide, \(\frac{12}{44}\times 39.61=10.80g\) of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 9.01 g of water, \(\frac{2}{18}\times 9.01=1.00g\) of hydrogen will be contained.

Mass of oxygen in the compound = (13.42) - (10.80 + 1.00) = 1.62 g

To formulate the empirical formula, we need to follow some steps:

Moles of Carbon = \(\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{10.80g}{12g/mole}=0.9moles\)

Moles of Hydrogen = \(\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{1g}{1g/mole}=1moles\)

Moles of Oxygen = \(\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{1.62g}{16g/mole}=0.10moles\)

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.10 moles.

For Carbon = \(\frac{0.9}{0.10}=9\)

For Hydrogen = \(\frac{1}{0.10}=10\)

For Oxygen = \(\frac{0.10}{0.10}=1\)

The ratio of C : H : O = 9 : 10 : 1

Hence, the empirical formula for the given compound is \(C_9H_{10}O\)

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

\(n=\frac{\text{Molecular mass}}{\text{Empirical mass}}\)

We are given:

Mass of molecular formula = 268.34 g/mol

Mass of empirical formula = 134 g/mol

Putting values in above equation, we get:

\(n=\frac{268.34g/mol}{134g/mol}=2\)

Multiplying this valency by the subscript of every element of empirical formula, we get:

\(C_{(9\times 2)}H_{(10\times 2)}O_{(1\times 2)}=C_{18}H_{20}O_2\)

Thus, the molecular formula for the given organic compound is \(C_{18}H_{20}O_2\).

Answer:

12.125 moles of Z

Explanation:

Hi! Here, since you only know the number of moles for one of the reactants, you will use the coefficients in the reaction to use the mole ratio to find your answer. Since the question states that there are 4.85 mol A and excess B, A is your limiting reactant. This means that once all of the A is used up in the reaction, you will have your maximum amount of Z left behind because there will only be B left and no A to make more Z.

The mole ratio of A:Z is 2:5, found from the coefficients in the chemical equation(2 moles of A for every 5 moles of Z).

So, start with the information that is given to you (4.85 mol A) and then use the mole ratio, like this:

4.85 mol A(\(\frac{5 mol Z}{2 mol A}\))

This way, the mol A will cancel out, leaving behind mol Z (always put the unit you are looking for on top).

Doing this leads to mol Z = 12.125 mol.

I hope this helps! Good luck with your finals!

As per the given 4.85 moles of A will produce 12.125 moles of Z, assuming excess B.

A chemical reaction is the transformation of one or more substances, known as reactants, into one or more different substances, known as products.

Chemical reactions involve the breaking and forming of chemical bonds between atoms and molecules, causing atoms to rearrange and the chemical and physical properties of the substances involved to change.

From the balanced chemical equation, we can see that 2 moles of A react with 3 moles of B to produce 5 moles of Z.

So the mole ratio of A to Z is 2:5.

Therefore, if 2 moles of A react to produce 5 moles of Z, then 4.85 moles of A will produce:

(4.85 mol A) x (5 mol Z / 2 mol A) = 12.125 mol Z

Thus, 4.85 moles of A will produce 12.125 moles of Z, assuming excess B.

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During the cooling process, we can identify three stages, as shown in the figure attached to the question.

1. Water cooling from 23°C to 0°C, freezing temperature of the water. The energy for this stage will be:

Where,

m is the mass of water, 250g

Cp1 is the specif heat of water, 4.186J/g°C

dT is the difference of temperature, T2-T1=0°C-23°C=-23°C

We have a negative value because the process releases energy

2. Change of phase of water, from liquid water to ice. This process occurs at a constant temperature equal to 0°C. The energy for this stage will be:

dHf is the heat of fusion. We put a negative sign because we have the contrary process of fusion, freezing.

3. Ice cooling from 0°C to -23°C.

Where,

m is the mass of ice, 250g

Cp3 is the specific heat of ice, 2.1J/g°C

dT is the difference of temperature, -23°C-0°C=-23°C

So, the total energy released will be:

Answer: The total energy will be -119.6kJ, which means that the energy is released.

The pH of an aqueous solution that has a concentration of 0.35 M NaF and pKa for HF = 3.14 is 3.6.

The pH of a solution refers to the degree of acidity or alkalinity of the solution. It can be calculated using the Henderson-Hasselbalch Equation as follows:

pH = pka + log ([A-]/[HA])

Where;

pH = pKa + log([F-]/[HF])

pH = 3.14 + log(1/0.35)

pH = 3.14 + 0.4559 = 3.595

Therefore, the pH of an aqueous solution that has a concentration of 0.35 M NaF and pKa for HF = 3.14 is 3.6.

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Macronutrients and micronutrients are combined to create a healthy, nutritious diet.

This type of diet comprises of macronutrients and micronutrients in which the former is responsible for provision of energy to the body.

The latter helps to digest the macronutrients thereby making option B the most appropriate choice.

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Answer:

Macronutrients and micronutrients

Explanation:

The order of increasing ionic property is;

WO3 < ZrS2 < MnS2< ZnS < MnS

Ionic compounds are compounds that contain an ion pair. Typically, ionic compounds are formed between metals and nonmetals.

The degree of ionic character depends on the type of metal involved and the magnitude of charge it carries.

Typically, first row transition metals form ionic compounds. The degree of ionic character depends on the row in which the metal is found and the magnitude of charge it carries.

Hence, the order of ionic character of the compounds from most ionic to least Ionic is; WO3 < ZrS2 < MnS2< ZnS < MnS.

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264.5 grams of Cl₂ are needed to produce 1.25 moles of CHCl₃.; 74.4 grams of HCl are produced from 0.64 moles of CH₄.; 51.2 grams of Cl₂ are needed to produce 11.9 grams of CHCl₃.

To balance the equation, we need to make sure that number of atoms of each element is the same on both the sides of equation.

The balanced equation is: CH₄(g) + 3Cl₂(g) → CHCl₃(l) + 3HCl(g)

1.25 mol CHCl₃ x (3 mol Cl₂/1 mol  CHCl₃.) x (70.91 g Cl2/1 mol Cl₂) = 264.5 g Cl₂

Therefore, 264.5 grams of Cl₂ are needed to produce 1.25 moles of  CHCl₃.

0.64 mol CH₄ x (3 mol HCl/1 mol CH₄) x (36.46 g HCl/1 mol HCl) = 74.4 g HCl

Therefore, 74.4 grams of HCl are produced from 0.64 moles of CH₄.

11.9 g CHCl₃ x (1 mol CHCl₃/119.38 g CHCl₃) x (3 mol Cl2/1 mol CHCl₃) x (70.91 g Cl₂/1 mol Cl₂) = 51.2 g Cl₂

Therefore, 51.2 grams of Cl₂ are needed to produce 11.9 grams of CHCl₃.

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Using the molecular weight a calculator or the molar mass of CH₃CH₂OH, 1 gram Ethanol = 0.021706834440237 mole.

Ethanol is an renewable transportation fuel that is produced in the United States. Ethanol contributes to lower emissions when used in low-level blends like E10 10% ethanol, 90% fuel), E15 10.5% in 15% ethanol as a or E85 flex boost)—a gasoline-ethanol mix containing 51% to 83% a solution of depending on geography or season.

Ethanol (CH₃CH₁OH) is a chemical compound (alcohol) that contains the group hydroxyl (OH) bonded to a the carbon atom. Ethanol is made by fermenting crop residue such as sugar cane, maize, and manioc.

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Answer:

Explanation:

2Al(s) + 3 2 O2(g) → Al2O3(s) And given the stoichiometry ...and EXCESS dioxygen gas...we would get 6.25⋅ mol of alumina. the which represents a mass... ...6.25 ⋅ mol ×101.96 ⋅ g ⋅ mol−1 molar mass of alumina ≡ 637.25 ⋅ g.

Answer:

56.7 grams of aluminum oxide (AI²O³) are produced.Need a fast expert's response.

Answer:

1.674 x 10^-23 grams

Explanation:

Hydrogen-1 is called Protium

wikipedia

atomic mass of Protium is 1.00794 amu

sciencedirectcom

atomic mass of 10 Protiums is 10.0794 amu

10.0794 amu in grams is

1.6737236x10^-23 grams

Answer:

Water acts as a solvent of carbon dioxide excreted from tissues, in blood and helps in regulating pH (because it forms carbonic acid that lowers pH when it tends to get higher). Blood pH should be maintained at about 7.4. One major reason is that the structure of protein is dependent ton pH because pH determines its ionization hence also affecting the charges and interaction between side groups of amino acids. A change in pH may, therefore, denature proteins and negatively affect cellular functions.

Explanation:

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The volume of gas when the pressure is 45 psi is 2,833.33mL.

The volume of a substance can be calculated using Boyle's law equation as follows:

P₁V₁ = P₂V₂

Where;

According to this question, a tank of carbondioxide has a pressure of 850 psi and a volume of 150 mL. The volume can be calculated as follows:

850 × 150 = 45 × V

V = 127,500 ÷ 45

V = 2,833.33mL

Therefore, 2,833.33mL is the volume of the gas.

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While tumor marker test results can be useful, they are not conclusive. A low result does not imply that you do not have cancer or that you are in remission.

CA 15-3, for example, is raised in less than half of patients with early breast cancer and in more than 80% of those with metastatic breast cancer. Three tumor markers, cancer antigen 15-3 (CA 15-3), cancer antigen 27.29 (CA 27.29), and carcinoembryonic antigen (CEA), have been used in breast cancer care to help monitor metastatic breast cancer (advanced disease), but they have not been found to be useful in detecting a breast cancer recurrence or extending lives. If the level falls, the treatment is effective. If it rises, the cancer may be spreading.

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Answer:

21121.58 grams

Explanation:

Given, 9.96 times 10 to the power of 26 atoms of tellurium

Convert atoms into moles of tellurium,

As we know, 1 mol= 6.02 *10 to the power of 23 atoms

Hence, 9.96 *10 to the power of 26/ 6.02 *10 to the power of 23= 1654 moles of tellurium

Now, mass= molar mass*moles

As we know, tellurium has a molar mass of 127.6000 g/mol

Mass= 1654 *1277 g/mol

       = 21121.58

Answer:

d) It incorrectly describes the two processes

Hope it helps you

And please mark it as the brainliest answer

Answer:

b

Explanation:

When hydrogen bromide (HBr) is added to 2-methylbut-2-ene ((CH3)2CCHCH3), an electrophilic addition reaction takes place, where the π bond of the alkene is broken, and the hydrogen and bromine atoms are added to the resulting carbocation.

The reaction proceeds through a Markovnikov addition, where the hydrogen atom attaches to the carbon atom with the greater number of hydrogen atoms.

In this case, the initial addition of HBr to 2-methylbut-2-ene leads to the formation of a primary carbocation, as the positively charged carbon atom only has one alkyl group attached to it. The primary carbocation is relatively unstable, and it can undergo a rearrangement to form a more stable secondary carbocation.

The major product that is typically obtained is the 2-bromo-2-methylbutane. The hydrogen atom from HBr adds to the carbon with three hydrogen atoms (the more substituted carbon), resulting in the formation of a secondary carbocation.

On the other hand, a minor product is also formed, which is 3-bromo-2-methylbutane. This product arises from the addition of HBr to the primary carbocation, which is less stable. Although the primary carbocation is less favored, it can still be formed and lead to the formation of the minor product.

In summary, the addition of HBr to 2-methylbut-2-ene yields two products: the major product is 2-bromo-2-methylbutane, resulting from the addition of HBr to the more stable secondary carbocation, and the minor product is 3-bromo-2-methylbutane, originating from the less stable primary carbocation.

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Answer:

All is Correct

Explanation:

Fossil fuels have the following properties:

Therefore, the answer is to select all

Answer:

It's A, B, and D

Explanation:

Maybe not D, because that is burning wood like charcoal. Not sure about that. Hope this helps!

Answer:

D. Copper

Explanation:

Less reactive metals like Copper, gold and silver does not react with dilute HCl to produce Hydrogen gas.

Answer:

D. Copper

Explanation:

Copper is less reactive than Hydrogen.