50 BRAINLY POINTS PLS HELP

let's take a peek at the picture above, hmmm let's notice the vertex is at (-1 , 2), now let's get a point besides the vertex hmmm let's see it passes through (-2 , -1).

So we can reword that as what's the equation of a quadratic whose vertex is at (-1 , 2) and it passes through (-2 , -1)?

\(~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{a~is~negative}{op ens~\cap}\qquad \stackrel{a~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill\)

\(\begin{cases} h=-1\\ k=2\\ \end{cases}\implies y=a(~~x-(-1)~~)^2 + 2\hspace{4em}\textit{we also know that} \begin{cases} x=-2\\ y=-1 \end{cases} \\\\\\ -1=a( ~~-2-(-1) ~~ )^2 + 2\implies -3=a(-2+1)^2\implies -3=a \\\\\\ ~\hfill~ {\Large \begin{array}{llll} y=-3(x+1)^2 + 2 \end{array}} ~\hfill~\)

Answer:

y = -3(x + 1)^2 + 2

Step-by-step explanation:

y = a(x - h)^2 + k is the vertex form of a quadratic, where

Finding (h, k):

We see from the graph that the vertex is a maximum and its coordinates are (-1, 2).  Thus h is -1 and k is 2.  Since h becomes negative, it will be 1 in the parentheses: (x - (-1) = (x + 1).

Finding a:

In order to find a, we will need to plug in a point on the parabola for (x, y) and (-1, 2) for h and k.  We see that (0, -1) lies on the parabola so we can use this point for (x, y).

-1 = a(0 - (-1))^2 + 2

-1 = a(0 + 1)^2 + 2

-3 = a(1)^2

-3 = a

Thus, a = -3.

Thus, the exact equation in vertex form of the parabola is:

y = -3(x + 1)^2 + 2

I attached a picture from Desmos Graphing Calculator that shows how the equation I provided works and contains the two points you marked on the parabola, including (-1, 2) aka the maximum, and (0, -1) aka the y-intercept.

Answer:

\(\tt (D)\; \tt x=\cfrac{2}{5}\)

Step-by-step explanation:

\(\tt \cfrac{2}{3}+\cfrac{1}{3}x=2x\)

Simplify 1/3x = x/3:-

Join denominators:-

Multiply both sides by 3:-

Subtract x from both sides :-

Divide both sides by 5:-

______________________

Hope this helps!

We are given a table of frequencies of each grade. To calculate the probabilities, we simply divide the reported number by the total number of students (35). So we have the table

Grade Pr(Grade)

A 5/35

B 10/35

C 15/35

D 3/35

F 2/35

As we want to calculate the probability that the student earns a grade D or a F, we simply add the probabilities of each grade. That is

we also have that

which rounded to the nearest hundredth is 0.14. So the probability that a student earns a grade of D or F is 0.14

The solution of the given inequality is y ≤ -3.

The given inequality is -

3y ≤ −9

We have to solve this given inequality.

Now, we have the inequality as -

3y ≤ −9

=> y ≤ -3

Thus, the solution of the given inequality is y ≤ -3.

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A = 122

2 = 58

Can I have brainliest

Answer:

Step-by-step explanation:

To write y as a function of x using the given functions, we can substitute the value of "a" in the first equation with the expression "-5x + 1" from the second equation.

Given:

y = -3a + 3

a = -5x + 1

Substituting the value of "a" in the first equation:

y = -3(-5x + 1) + 3

Now, let's simplify this expression:

y = 15x - 3 + 3

y = 15x

Therefore, y can be expressed as a function of x as:

y = 15x

\(\dfrac{x+4}{3} =7\)

Multiply both sides by 3:

\((\dfrac{x+4}{3} )\times3=(7)\times3\)

\(x+4=21\)

Subtract 4 from both sides:

\(x+4-4=21-4\)

\(\boxed{x=17}\)

Answer:

3(x + 5y) - 2(x + y)

3x + 15y - 2x - 2y

x + 13y

(3x + 15y) + (-2x + -2y)

x + 13y

Given a rectangle of which its length is nine more than triple the width. The width is _10_inches. The length is 39 inches.

Let:

l = length of the rectangle

w = width of the rectangle

"The length of a rectangle is nine more than triple the width" can be translated as:

l = 9 + 3w

perimeter = 2 l + 2w

Substitute perimeter = 98 and  l =  9 + 3w into the perimeter equation:

98 = 2 x (9 + 3w) + 2w

98 = 18 + 8w

8w = 98 - 18

8w = 80

w = 80/8 = 10 inch.

Substitute w = 10 into the length equation:

l = 9 + 3w

l = 9 + 3 x 10

l = 9 + 30 = 39

Therefore the correct answer is:

The width is _10_inches. The length is 39 inches.

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Solution

Step 1

Write the two points

(6,7) and (16,22)

Step 2:

Write the slope formula

Step 3

Substitute all the values in the formula to find the slope.

Final answer

Answer:

C

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

this is a correct answer

Solutions of these equations is y < - x / 140x + 23 / 140x

Graphs present information to you as a picture or visual representation. This knowledge is referred to as "data." Graphs come in a wide variety of forms. You can compare various data sets using bar graphs. Small dots are used in line graphs to represent the data, and a line is drawn between the dots to indicate what happens to the data.

4x . 35y < - x + 23

4x . 35y + (x-23) < (-x+23) + (x-23) (x-23)

4x .35y + x-23 < -x + 23 + x -23

4x .35y + x-23 < -x + x + 23-23

The formula is as follows: 140xy + x-23 0 140xy + x-23 0 (140xy +x-23) + (-x + 23) -x + 23 140xy + x -23 -x +23 +23 < - x +23\s140xy <-x +23

140xy/140x/(-x +23)/140xy/(-1/140x)+23/140xy/(-x)/140xy/(-x)/140x +23/140x

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Answer:

1 cm^3

Step-by-step explanation:

Length x Width x Height

1 x 1 x 1 = 1

Answer:

x=16

Step-by-step explanation:

(x-8)+2x+2x=4(x+2)

x-8+4x=4x+8

x=16

Answer:

x=16

Step-by-step explanation:

perimeter of triangle=a+b+c =perimeter of Square =L²

2x+2x+x-8=4(x+2)

5x-8=4x+8

C.L.T

5x-4x=8+8

x=16

The dimension of the rectangular of a norman window will be 1.6803*3.3606.

What is the area of Rectangle?

In any quadrilateral which have equal and parallel opposite sides is considered to be a rectangle. It is also called as a polygon with four sides and the four angles that are all 90 degrees each. A rectangle is a shape with only two dimensions. The product of the length and the breadth calculates its area. The length of the diagonals of any rectangle are equal in length. Thus, the length of the diagonals can be calculated easily using the Pythagoras theorem where, the diagonal is considered to be the hypotenuse.

Let r represents the radius, and b be the breadth.

Then, perimeter = 3.14*r+2r+2b = 12

For the dimension needed for the most light to enter we need to maximize the area.

Hence, area of the window : area of the semicircle + area of the rectangle

= \(\frac{3.14*r^2}{2} + 2rb\)

= \(12r - (\frac{3.14+4}{2}) r^2\)

A'(r) = 0

Therefore, \(r=\frac{12}{3.14+4}\) which is nearly equal to 1.6803m

From this value of r we can calculate the value of b to be;

b= 1.6803m

Thus, a= 3.606m

Thus the required dimension is : 1.6803*33606

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line A and line B are showing that object A and B are moving with a different rate.

they both are moving with constant speed but we can see that line A has a large slope as compare to line B, that means object A has more speed than the object B.

so the speed of object A is greater than the object B.

Answer:

9 seconds

Step-by-step explanation:

right side of the graph touches the x axis at 9

Caitlin has 3 3/4 feet more of red yarn than purple yarn.

To find out how much more red yarn Caitlin has compared to purple yarn, we need to subtract the length of the purple yarn from the length of the red yarn.

Given:

Red yarn: 9 3/8 feet

Purple yarn: 5 5/8 feet

To subtract mixed numbers, we need to convert them to improper fractions.

9 3/8 = (8 * 9 + 3)/8 = 75/8

5 5/8 = (8 * 5 + 5)/8 = 45/8

Now, we can subtract the fractions:

75/8 - 45/8 = (75 - 45)/8 = 30/8

Simplifying the fraction, we get:

30/8 = 15/4 = 3 3/4

Therefore, Caitlin has 3 3/4 feet more of red yarn than purple yarn.

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Step-by-step explanation:

Given Question

Complete the following tables and plot the points on the graph paper yo represents the equations given below :-

\(\begin{gathered}\boxed{\begin{array}{c|c|c|c} \bf x & \bf 1 & \bf 2& \bf 3\\ \frac{\qquad}{} & \frac{\qquad}{}\frac{\qquad}{} &\frac{\qquad}{} & \frac{\qquad}{} &\\ \sf y = x + 1 & \sf & \sf & \sf \\ \\ \sf (x,y)& \sf & \sf & \sf \\ \end{array}} \\ \end{gathered} \\ \)

and

\(\begin{gathered}\boxed{\begin{array}{c|c|c|c} \bf x & \bf 1 & \bf 2& \bf 3\\ \frac{\qquad}{} & \frac{\qquad}{}\frac{\qquad}{} &\frac{\qquad}{} & \frac{\qquad}{} &\\ \sf y = - 3x & \sf & \sf & \sf \\ \\ \sf (x,y)& \sf & \sf & \sf \\ \end{array}} \\ \end{gathered} \\ \)

\(\large\underline{\sf{Solution-}}\)

Given that,

\(\rm \longmapsto\:y = x + 1\)

On substituting x = 1, we get

\(\rm \longmapsto\:y = 1 + 1\)

\(\rm \longmapsto\:y = 2\)

On substituting x = 2, we get

\(\rm \longmapsto\:y = 2 + 1\)

\(\rm \longmapsto\:y = 3\)

On substituting x = 3, we get

\(\rm \longmapsto\:y = 3 + 1\)

\(\rm \longmapsto\:y = 4\)

Hence,

\(\begin{gathered}\boxed{\begin{array}{c|c|c|c} \bf x & \bf 1 & \bf 2& \bf 3\\ \frac{\qquad}{} & \frac{\qquad}{}\frac{\qquad}{} &\frac{\qquad}{} & \frac{\qquad}{} &\\ \sf y = x + 1 & \sf 2 & \sf 3 & \sf 4\\ \\ \sf (x,y)& \sf (1,2) & \sf (2,3) & \sf (3,4)\\ \end{array}} \\ \end{gathered}\)

Now, draw a graph using the points (1 , 2), (2 , 3) & (3 , 4)

---------------------------------------------

Given equation is

\(\rm \longmapsto\:y = - 3x\)

On substituting x = 1, we get

\(\rm \longmapsto\:y = - 3 \times 1\)

\(\rm \longmapsto\:y = - 3\)

On substituting x = 2, we get

\(\rm \longmapsto\:y = - 3 \times 2\)

\(\rm \longmapsto\:y = - 6\)

On substituting x = 3, we get

\(\rm \longmapsto\:y = - 3 \times 3\)

\(\rm \longmapsto\:y = - 9\)

Hence,

\(\begin{gathered}\boxed{\begin{array}{c|c|c|c} \bf x & \bf 1 & \bf 2& \bf 3\\ \frac{\qquad}{} & \frac{\qquad}{}\frac{\qquad}{} &\frac{\qquad}{} & \frac{\qquad}{} &\\ \sf y = - 3x & \sf - 3 & \sf - 6 & \sf - 9\\ \\ \sf (x,y)& \sf (1, - 3) & \sf (2, - 6) & \sf (3, - 9)\\ \end{array}} \\ \end{gathered}\)

Now, draw a graph using the points (1 , - 3), (2 , - 6) & (3 , - 9)

Answer:

OPTION B - 2

Step-by-step explanation:

What is the upper limit for the zeros of the function P(x) = 4x^4 + 8x^3 - 7x^2 - 21x - 9. Ans: 2 is an upper limit. Use synthetic division. and the remainder are all positive, 2 is an upper limit.

Answer:

PART A :

AREA OF RECTANGLE = LENGTH × BREADTH

A = (4x + 5) (3x + 10)

A = 12(x^2) + 55x + 50

PART B: The above is a trinomial with the second degree. Trinomial because it has 3 terms and second degree because the variable(x) is squared.

PART C : Closure under addition and multiplication. Look at the signs.

Answer:

x intercept (-2,0) y intercept (0,2)

Step-by-step explanation:

Answer:

I'm pretty sure these are the answers

x-intercept (-2,0)

y-intercept (0,2)

Explanation:

x-intercept: Is coordinates where the line hits the x-axis

y-intercept: Is coordinates where the line hits the y-axis

9514 1404 393

Answer:

  sin(θ) = (-5√61)/61

Step-by-step explanation:

The distance from the origin to the given point is ...

  d = √(6² +(-5)²) = √61

The sine of the angle is the ratio ...

  sin(θ) = y/d = -5/√61

Rationalizing the denominator gives us ...

  sin(θ) = (-5√61)/61

Answer:

Step-by-step explanation:

18 times 9 then -9

Answer:

135

Step-by-step explanation:

First, Times 18 x 8. which gives you 144. Then, subtract 9, giving you 135.

Answer: WX, ZY and WX and AB.

The 2nd one is correct.

The dimensions listed above are thus neither exact nor precise.

In the given question the chocolate chip cookies weigh 17.27 g, 13.05 g, 19.46 g, and 16.92 g, respectively and we have to classify the following set of measurements as accurate, precise, both, or neither.

It is the "value" that a buyer is prepared to pay for an object, particularly a used or second-hand car; typically, the "real worth" of any used car is a predetermined price tag after determining its value based on its condition and usage.

The chocolate chip cookies weigh 17.27 g, 13.05 g, 19.46 g, and 16.92 g, respectively. This demonstrates that the weight of chocolate chips is not comparable to their actual worth.

The dimensions listed above are thus neither exact nor precise.

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The solution to the question is mathematically given as

1)

H0: M \(\geqslant\) 300

H0: M \(\geqslant\) 300

2)

Z distribution.

3)

z=-2.4

4)

P=0.0082

5)

"H0" is rejected as a hypothesis with a level of significance of 0.05.

Generally, the equation for is mathematically given as

Solutions

we have, \($u=300$$$\begin{aligned}& \sigma=150 \text { dollars } \\N &=64 \text { individuals } \\\bar{x} &=255 \text { dollare. } \\a=& 0.05 .\end{aligned}\)

(1):

H0: M \(\geqslant\) 300 dollars;  customers save at least 300 dollars per year by switching to them.

H0: M \(\geqslant\) 300 dollars:

(This is a left-tailed test)

(2):

when \(\sigma\) is known, we use the Z test. we use Z distribution.

(3):

\(\begin{gathered}z=\frac{\bar{x}-\mu}{6 / \sqrt{n}}=\frac{255-300}{150 / \sqrt{64}}=\frac{-45}{18.75}=-2.4 \\z=-2.4\end{gathered}\)

(4):

\(Pvalue $=P(z < -2 \cdot 4)$ $=0.0082 \quad\{$ wing $z$ tables $\}$ \\\\\text { Pvalue }=0.0082\)

(5):

In conclusion, Since p-value = 0·0082 <0.05

This is statistically significant at the 0.05 level.

We thus "Refect H0" using a threshold of significance of 0.05.

"H0" is rejected as a hypothesis with a level of significance of 0.05.

There is not enough data to support the assertion that consumers may save at least $300 annually by switching insurance providers.

Therefore, we would not consider making the transition to this firm.

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Based on the information given the new balance is $289.72.

First step is to calculate the finance charge

\(\text{Finance charge}=205.16\times(0.144\div12 \ \text{months})\)

\(\text{Finance charge}=205.16\times0.012\)

\(\text{Finance charge}=2.46\)

Second step is to calculate the New balance

\(\text{New balance}=205.16+2.46+82.10\)

\(\text{New balance}=\bold{\$289.72}\)

In conclusion, the new balance is $289.72.

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