5. Identify the poles of the cell battery and the direction of current in the circuit.

Fan made of plastic bottle is an innovative way to reuse plastic bottles and can be easily made at home. This can be done by following simple steps, and a few materials are required to make it. The fan can be created by using a plastic bottle, scissors, string, a ruler, and a marker.

First, the bottle needs to be cut into half, and the upper part needs to be cut into three equal sections, then fold each section to make a blade. With the help of a ruler and marker, make a mark on each section, then make a hole in the center of each blade. Insert a string through the holes and tie the ends of the strings. The fan is ready to use by holding the string and swinging it back and forth.

The use of plastic bottle fans can significantly reduce the number of plastic waste and provide a practical solution to avoid environmental pollution. Besides, it is easy to make, and the materials are readily available, which can be used for various occasions, such as picnics, camping, or any outdoor activities.

In conclusion, the creation of a fan made of plastic bottle with string is an excellent way to reuse plastic bottles and can be made with simple steps. This project encourages everyone to contribute to environmental protection by utilizing what is available at home and reducing the number of plastic wastes.

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Answer:

C) 300 Ohm.

Explanation:

In a series circuit, total resistance is just adding all the resistance together. So R (total) = 75 +75 +75+ 75 = 300 ohms

Parallel circuit are different because you add the inverses of resistance and you flip the final answer.

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Answer:

(A)  the acceleration  experienced by the proton 2.821 x 10¹² m/s²

(B) the speed of the proton is 2.67 x 10⁵ m/s

Explanation:

Given;

electric field experienced by the proton, E = 2.95 x 10⁴ N/C

charge of proton, Q = 1.6 x 10⁻¹⁹ C

mass of proton, m = 1.673 x 10⁻²⁷ kg

distance moved by the proton, d = 1.26 cm = 0.0126 m

(a)

The force experienced by the proton is calculated as;

F = ma = EQ

where;

a is the acceleration  experienced by the proton

\(a = \frac{EQ}{m} \\\\a = \frac{2.95\times 10^4 \ \times \ 1.6\times 10^{-19}}{1.673 \times 10^{-27}} \\\\a = 2.821 \times 10^{12} \ m/s^2\)

(b) the speed of the proton is calculated;

v² = u² + 2ad

v² = 0 + (2 x 2.821 x 10¹² x 0.0126)

v² = 7.109 x 10¹⁰

v = √7.109 x 10¹⁰

v = 2.67 x 10⁵ m/s

Wavelength of the given wave is 8 cm and frequency is  37.5 *\(10^{8}\) Hz.

The number of vibrations counted per second is called frequency. A wave is a group of vibrations that are referred to as energy. The bottom node is known as the crest, and the top node is known as the trough.

The frequency of an alternating current is the number of full cycles per second. The hertz, also known as Hz, is the accepted unit of frequency. The frequency of a current is 1 Hz if one cycle is completed per second; 60 cycles per second equals 60 Hz.

There are 8 waves so assume one wave is 1 cm so wavelength is 8 cm and frequency of wave = speed of light/ wavelength

frequency = \(3*10 ^{8} / .08\)

Frequency = 37.5 *\(10^{8}\) Hz

Wavelength of the given wave is 8 cm and frequency is  37.5 *\(10^{8}\) Hz.

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Complete Question

The complete question is shown on the first uploaded image

Answer:

the value of  \(y = 13.3\)

Explanation:

From the question we are told that

       The equation is  (x + y = 40)

        The first value of x is  \(x_1 = 26.7\)

        The second equation is  (0.75x + 1.5y = 40)

So  substituting \(x_1\)

     \(26.7 + y = 40\)

=>   \(y = 13.3\)

Now substituting y and  \(x_1\) into second equation

       \(0.75(26.7) + (1.5* 13.3) = 40\)

 =>  \(40 = 40\)

So  \(y = 13.3\)

The electron gains more kinetic energy than the proton when accelerated through a potential difference of 1 V.

The relationship between the kinetic energies of the electron and proton can be determined using the formula for the kinetic energy of a particle:

\(KE = (1/2)mv^2\)

\(V = (q/m)d\)

where V is the potential difference, q is the charge, m is its mass, and d is the distance .

For the electron, \(V = 1 V\)and\(q/m = -1.6 x 10^-19 C/kg\), so its final velocity is:

\(v_e = sqrt((2qV)/m) = sqrt((2*(-1.6 x 10^-19)*1)/9.11 x 10^-31) = 5.93 x 10^6 m/s\)

For the proton, \(V = -1 V and q/m = 1.6 x 10^-19 C/kg,\) so its final velocity is:

\(v_p = sqrt((2qV)/m) = sqrt((2*(1.6 x 10^-19)*(-1))/1.67 x 10^-27) = 7.16 x 10^5 m/s\)

Substituting these values into the formula for kinetic energy, we get:

\(KE_e = (1/2)9.11 x 10^-31(5.93 x 10^6)^2 = 1.63 x 10^-17 J\)\(KE_p = (1/2)1.67 x 10^-27(7.16 x 10^5)^2 = 0.84 x 10^-17 J\)

Therefore, we have:

\(KE_e > KE_p\) , This is because the electron has a much smaller mass than the proton, so it experiences a much larger acceleration and gains more velocity and kinetic energy.

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Answer:

q₂ = -4.80 10⁻⁴  C  = - 0.48 mC, charge is negative

Explanation:

Let's use coulomb's law

           F = \(k \frac{q_1 q_2}{r^2}\)

and the sum of forces, remember that charges of the same sign repel and of different sign attract

           ∑ F = F₁₃ + F₂₃           (1)

Let's start by fixing a reference system located at charge 1 with the positive direction to the right.  In the problem it indicates that the net force on charge 3 is F = - 20.0 N, the negative sign indicates that the force is towards the left

let's look for every force, the charge q₁ = 12 10-⁻³ C and q₃ = 15 10⁻³ C

           F₁₃ =\(k \frac{q_1 q_3}{x_{13}^2}\)

           F₁₃ = 9 10⁹ 12.0 15.0 10⁻⁶ / (5-0)²

           F₁₃ = 64.8 10 3 N

This force is repulsive, that is, it is directed to the right

          F₂₃ = k \frac{q_2 q_3}{x_{23}^2}

          F₂₃ = 9 10⁹ q₂ 15.0 10⁻³ / (5-4)²

          F₂₃ = 135 10⁶ q₂  N

we substitute in equation 1

          -20.0 = 64.8 10³ + 135 10⁶ q₂

           q₂ = (-20 - 64.8 10³) / 135 10⁶

           q₂ = -4.80 10⁻⁴  C

the sign indicates that the charge is negative

The magnitude of the acceleration is 1.1 m/s^2.

Let us recall that the time that is taken to go up and to come down the ramp has been given as 1.95 s. It is also clear that the time that is taken to go up and to come down the ramp must be the same. This now means that if we consider the downward motion of the ball, the time taken = 1.95 s/2 = 0.975 s

Using the formula;

s = ut + 1/2at^2

u = 0 m/s because the ball cam to rest before moving down.

s =  1/2at^2

a = 2s/t^2

a = 2 * 0.511/(0.975)^2

a = 1.1 m/s^2

The magnitude of the acceleration is 1.1 m/s^2.

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All of that energy is used to compress the bumper by x, which is equal to 6 inches, or 0.5 feet, and it is stored as spring potential energy in the bumper. (1/2)*k*x2 is the formula for that energy.So, (1/2)*m*u2 = (1/2)*k*x2 Simplifying and rearranging results in k = (m*u2) / x2 Based on the data provided, k = 20 000 lb/ft.

Energy is the capacity to work in physics. It could be potential, kinetic, thermal, electrical, chemical, nuclear, or some other form. Heat and work are also present—for instance when energy is transferred from one body to another.

The body's mass (m) will change by an amount equal to E/c2 whenever the body's energy changes in any form, as shown by the Albert Einstein equation, commonly stated as E = mc2.

Energy is defined as the "ability to do work, which is the ability to exert a force causing the displacement of an object." The meaning is quite clear, despite this perplexing definition: Energy is the only thing that moves things. Energy can be divided into two categories: potential and kinetics

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Answer: We have vf = 7.57 m/s, which is the speed of the car (and the truck) after the collision.

Explanation:

p (auto) = 2200 kg * 12 m/s = 26,400 kg m/s p (truck) = 3800 kg * 5 m/s = 19,000 kg m/s After the collision, we have p = (2200+3800)*vf = 26400+19000 p = 6000*vf = 45,640 Therefore, we have vf = 7.57 m/s, which is the speed of the car (and the truck) after the collision.

Answer:

be acted upon an object or person

Explanation:

Answer:

A) Bela Bartok

Explanation:

Béla Bartók died at age 64 in a hospital in New York City from complications of leukemia (specifically, of secondary polycythemia) on September 26, 1945. His funeral was attended by only ten people. Among them were his wife Ditta, their son Péter, and his pianist friend György Sándor.

Answer:

B

Explanation:

Shadows are not colored, instead they are dark gray. Although shadows mimic the shape of an object, they do not mimic the color.

Sheena's speed with respect to the starting point on the bank is 2.07 mi/h.

To solve this problem, we can break Sheena's velocity into its horizontal and vertical components. The horizontal component of Sheena's velocity should be equal to the rate at which she crosses the river, while the vertical component of her velocity should be equal to the rate at which she is carried downstream by the current. The resulting velocity with respect to the starting point on the bank can be found using the Pythagorean theorem.

Let's first find the rate at which Sheena crosses the river. We can use the sine function to find this value, as follows:

sin(25°) = opposite/hypotenuse

opposite = sin(25°) x hypotenuse

opposite = sin(25°) x 2.20 mi/h

opposite = 0.9437 x 2.20 mi/h

opposite = 2.07 mi/h

So Sheena's horizontal velocity is 2.07 mi/h.

Now let's find the rate at which Sheena is carried downstream by the current. We can use the cosine function to find this value, as follows:

cos(25°) = adjacent/hypotenuse

adjacent = cos(25°) x hypotenuse

adjacent = cos(25°) x 1.90 mi/h

adjacent = 1.6987 mi/h

So Sheena's vertical velocity is 1.6987 mi/h.

Finally, we can use the Pythagorean theorem to find her speed with respect to the starting point on the bank:

velocity^2 = (horizontal velocity)^2 + (vertical velocity)^2

velocity^2 = (2.07 mi/h)^2 + (1.6987 mi/h)^2

velocity^2 = 4.29 mi^2/h^2

velocity = sqrt(4.29) mi/h

velocity = 2.07 mi/h

Therefore, Sheena's speed with respect to the starting point on the bank is 2.07 mi/h.

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To resolve the star-planet system at a distance of 4 light-years, a telescope on Earth would need an aperture with a minimum diameter of 55.88 mm.

In optical microscopy, the Rayleigh criterion is frequently used to estimate the resolution of the microscope. The resolution limit imposed by this criterion has long been regarded as a roadblock to using an optical microscope to study biological phenomena at the nanoscale.

We can use the Rayleigh criterion,

θ = 1.22 λ / D

θ = angular resolution

λ = wavelength of light

D = diameter of the telescope's aperture

θ = arctan (r / d)

r = radius of the planet's orbit

d = distance to the star

Now, we use the given values,

r = 149.6×106 km = 149.6×109 m

d = 4 × 9.461×1015 m = 3.7844×1016 m

λ = 550 nm = 550×10-9 m

θ = arctan (r / d)

   =arctan (149.6×109 / 3.7844×1016) = 0.000012 radians

we can use the Rayleigh criterion,

θ = 1.22 λ / D

D = 1.22 λ / θ

D = 1.22 × 550×10-9 / 0.000012

D = 55.88 mm

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Answer:

This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.

The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.

The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).

The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:

R(n) = √(X² + Y²)

Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.

However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:

<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2

<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2

Because <X²> = <Y²>, we can write:

<R²> = <X²> + <Y²> = n A²

So, the root mean square distance (the square root of the mean square displacement) after n steps is:

R(n) = √(<R²>) = √(n) * A

Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.

Friction is a force that opposes the relative motion of two surfaces in contact. It exists when the surfaces of two bodies are in contact.The answers to the given questions are:

1. See attachment to this answer

2. a = 3.63 m/\(s^{2}\)

3. μ = 0.36

Friction is an oppositional force between the surfaces of two bodies in contact, and tries to limit the motion of one body over the other. It is dependent on the nature of the surfaces in contact.

From the given question;

1. The free body diagram for this question is herewith attached to this answer.

Given that: \(F_{1}\) = 50 N, \(F_{2}\) = 15 N, \(F_{3}\) = 6 N, and m = 8 kg.

2. The acceleration of the body can be determined by:

F = ma

where F is the total force acting on the body, m is the mass of the body and a is its acceleration.

So that;

a = \(\frac{F}{m}\)

The total force on the body is;

F = \(F_{1}\) - (\(F_{2}\) + \(F_{3}\))

  = 50 - (15 + 6)

  = 50 - 21

F = 29 N

Then;

a = \(\frac{29}{8}\)

  = 3.625

a = 3.63 m/\(s^{2}\)

The acceleration of the body is 3.63 m/\(s^{2}\).

3. The coefficient of limiting friction (μ) between the surfaces is:

μ = \(\frac{Force}{Reaction}\)

Force = 29 N

Reaction = mg

               = 8 x 10

               = 80 N

μ = \(\frac{29}{80}\)

   = 0.3625

μ = 0.36

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Answer:

Friction is a force that opposes the relative motion of two surfaces in contact. It exists when the surfaces of two bodies are in contact.The answers to the given questions are:

1. See attachment to this answer

2. a = 3.63 m/

3. μ = 0.36

Explanation:

The volume of the solid immersed in the liquid is  5 x 10⁻⁵ m³.

The volume of the solid is calculated as follows;

V = (Ws - Wa) / (ρg)

where;

Ws = 0.2 kg x 9.8 m/s²

Ws = 1.96 N

Wa = 0.16 kg x 9.8 m/s²

Wa = 1.568 N

ρ = 0.8 x 1000 g/km³ = 800 kg/m³

The volume is calculated as;

V = (1.96 - 1.568 )/(800 x 9.8)

V = 5 x 10⁻⁵ m³

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The government wants to encourage economic growth by by increasing spending. But the Federal Reserve wants to decrease inflation by  decreasing the money supply".

The government will be injecting money into the economy if it intends to stimulate the economy by increasing spending (expansionary fiscal policy). But an abundance of money in circulation is what drives inflation. Therefore, the goal of a contractionary monetary policy is to eliminate the money supply in order to control inflation. That is, whereas the second policy is anti-inflationary, the first one is inflationary and intended to stimulate the economy.

Therefore, Inflation control strategies that are more prevalent today include contractionary monetary policy. By raising interest rates, a contractionary policy seeks to reduce the amount of money in an economy. 5 Credit becomes more expensive as a result, which lowers consumer and company expenditure and slows economic growth.

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The government wants to encourage economic growth by Cutting taxes. But the Federal Reserve wants to decrease inflation by raising interest rates.

This refers to the increase in the production of goods and services in an economy.

This refers to the Federal government's central bank.

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Answer:

True

Explanation:

The approximate centripetal force on an astronaut of mass 80Kg if the centrifuge rotates once every 2s is 3.94 KN

ac = v² / r

v = 2 π r / T

ac = Centripetal acceleration

v = Linear / Tangential velocity

T = Time period

r = Radius

r = 5 m

T = 2 s

v = 2 * 3.14 * 5 / 2

v = 15.7 m / s

ac = 15.7 * 15.7 / 5

ac = 49.298 m / s²

Fc = m ac

m = Mass

m = 80 kg

Fc = 80 * 49.298

Fc = 3943.8 N

Fc = 3.94 KN

Therefore, the approximate centripetal force on the astronaut is 3.94 KN

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Answer:

Every 11 years The solar cycle is the cycle that the Sun's magnetic field goes through approximately every 11 years.

Explanation:

Our Sun is a Large ball of electrically-charged hot gas. This charged gas moves, generating a powerful magnetic field. The Sun's magnetic field goes through a cycle, called the solar cycle.

Every 11 years or so, the Sun's magnetic field completely flips. This means that the Sun's north and south poles switch places. Then it takes about another 11 years for the Sun’s north and south poles to flip back again.

The solar cycle affects activity on the surface of the Sun, such as sunspots which are caused by the Sun's magnetic fields. As the magnetic fields change, so does the amount of activity on the Sun's surface.

Hope this helps!

Brain-List?

Answer:

Explanation:

When I hear "transformation of energy from one form to another", I think of the system exchanging energy with its surroundings. A transformation of energy simply means the system contains a different type of energy than it previously did. One example I can give is a ball. A ball at the top of a hill has a maximum potential energy. If given the chance to roll, it will go to a minimum state of potential. This will convert all of the potential energy into pure kinetic energy, once it reaches the bottom of the hill of course.

Answer:

The transformation of energy from one form to another is when energy changes or morphs into another kind. When a plant recieves light energy from the sun and converts it into chemical energy, that is an example of the transformation of enery.

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Answer:

If we are upset, often our mind cannot think straight. we need to take deep breaths, and focus on reality. When we are upset we do things out of anger.

Explanation:

Hope this helps!

The reaction equations for the steps involved in the decay of U-238 to Ra-226 are;

\(^{238}_{92}U\ \rightarrow \ ^{234}_{90}Th \ + \ ^{4}_{2}He\)

\(^{234}_{90}Th \ \rightarrow \ ^{230}_{88}Ra \ + \ ^{4}_{2}He\)

\(^{230}_{88}Ra \ \rightarrow \ ^{226}_{86}Ra \ + \ ^{4}_{2}He\)

The radioactive equation for the decay of U-238 to Ra-226 is calculated as follows;

First the uranium atom (U-238) will decay thorium by emitting alpha particle as shown in the equation below;

\(^{238}_{92}U\ \rightarrow \ ^{234}_{90}Th \ + \ ^{4}_{2}He\)

The second stage is, the thorium will decay to radium by emitting alpha particles again as shown below;

\(^{234}_{90}Th \ \rightarrow \ ^{230}_{88}Ra \ + \ ^{4}_{2}He\)

The third, and final stage, the radium will decay to an isotope of radium again, by emitting alpha particle as shown below;

\(^{230}_{88}Ra \ \rightarrow \ ^{226}_{86}Ra \ + \ ^{4}_{2}He\)

Thus, the reaction equations for the steps involved in the decay of U-238 to Ra-226 are;

\(^{238}_{92}U\ \rightarrow \ ^{234}_{90}Th \ + \ ^{4}_{2}He\)

\(^{234}_{90}Th \ \rightarrow \ ^{230}_{88}Ra \ + \ ^{4}_{2}He\)

\(^{230}_{88}Ra \ \rightarrow \ ^{226}_{86}Ra \ + \ ^{4}_{2}He\)

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Answer:

is only producing an electric field in the surrounding space

Explanation:

Answer:

25.82 m/s

Explanation:

We are given;

Force exerted by baseball player; F = 100 N

Distance covered by ball; d = 0.5 m

Mass of ball; m = 0.15 kg

Now, to get the velocity at which the ball leaves his hand, we will equate the work done to the kinetic energy.

We should note that work done is a measure of the energy exerted by the baseball player.

Thus;

F × d = ½mv²

100 × 0.5 = ½ × 0.15 × v²

v² = (2 × 100 × 0.5)/0.15

v² = 666.67

v = √666.67

v = 25.82 m/s

This question involves the concepts of the law of conservation of energy and kinetic energy.

The baseball leaves the hand with a velocity of "25.82 m/s".

From the law of conservation of energy the work done on the ball must be equal to the kinetic energy of the ball:

\(W=K.E\\\\Fd=\frac{1}{2}mv^2\\\\v=\sqrt{\frac{2Fd}{m}}\\\\v=\sqrt{\frac{2(100\ N)(0.5\ m)}{0.15\ kg}}\)

where,

F = force applied = 100 N

d = displacement of ball = 0.5 m

m = mass of ball = 0.15 kg

v = 25.82 m/s

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The attached picture explains the law of conservation of energy.

Answer:

Elements heavier than iron are formed by neutron capture processes during stellar death and supernovae.

Explanation:

Most of the elements heavier than iron are formed during the death of stars through neutron capture processes, specifically the R-Process and the S-Process. The R-Process is a rapid capture of neutrons, while the S-Process is a slow capture of neutrons. These processes either directly form elements or indirectly form them through decay processes [^1]. Elements heavier than iron are primarily made in environments with free-neutron densities in excess of a million particles per cubic centimeter [^2]. In the extreme energetic conditions of supernovae, atoms are bombarded by a very large number of neutrons, and rapid successive neutron capture, followed by beta decay, produces the heavier atoms [^5].

So, elements heavier than iron are formed by neutron capture processes during stellar death and supernovae.

[^1