5 13. If a train going 60 m/s hits the brakes, and it takes the train 2 minute 25 seconds to stop, what is the train's acceleration?​

Answers

Answer 1

Answer:

Acceleration = -12/17 m/s ^2

Explanation:

Name the variables

V = final velocity( velocity after the train stops) u= intial velocity(velocity when the train was moving at constant speed, before brakes are applied)

A = acceleration( in this case, it is deceleration)

T = time ( time taken to fully stop)

Second Step: What equation should we use?

The 3 Big Motion in One Dimension Formulas are:

V = u+at

v^2 = u^2 + 2as

S = ut+ (1/2) at^2

For this question, we will be using the first one.

Third Step: Solve

V = 0 (the final velocity is 0, because the train stopped)

U = 60 (the train was going at 60 mps)

T = 85 seconds( 1 min and 25 sec)

0 = 60+ 85a

Answer 2
First convert the minutes to seconds. That’s the standard unit for time in physics. 2 minutes is 120 seconds, add that to the 25 second to get 145 seconds.

Use the first kinematic equation Vf = Vi + at. We are given everything here besides acceleration. We know Vf equals zero because it says the train comes to a stop.
0 = 60m/s + a*145s
-60m/s = 145a
a = -60/145 = -12/29 m/s^2

Related Questions

What are the two types of precipitation?
In precipitation, rainwater can fall as either

Answers

In precipitation, Rainwater can fall as either Liquid or Solid.

Precipitation is a part of the water cycle. Precipitation falls to the floor as snow and rain. It subsequently evaporates and rises back into the surroundings as a gas. In clouds, it turns back into a liquid or stable water, and it falls to Earth again

The water cycle shows the non-stop motion of water within the Earth and its surroundings. it's miles a complex system that consists of many one-of-a-kind techniques. Liquid water evaporates into water vapor and condenses.

There are four fundamental ranges in the water cycle. they are evaporation, condensation, precipitation, and collection. permit's examined every one of these ranges. Evaporation: that is whilst warm temperature from the sun causes water from oceans, lakes, streams, ice, and soils to upward push into the air and grow to be water vapor.

Disclaimer: your question is incomplete, please see below for the complete question.

Liquid

Steam cloud

2nd half

Steam

Solid

Cloud

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Select the correct answer.
A boat moves 60 kilometers east from point A to point B. There, it reverses direction and travels another 45 kilometers toward point A. What are the total
distance and total displacement of the boat?
O A.
OB.
O C.
O D.
The total distance is 105 kilometers and the total displacement is 45 kilometers east.
The total distance is 60 kilometers and the total displacement is 60 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east.
The total distance is 60 kilometers and the total displacement is 45 kilometers east.

Answers

The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C

How to solve for the  total distance

To calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.

However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.

Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.

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A car traveling south is 200 kilometers from its starting point after 2 hours what is the a

Answers

Answer:

\(\huge\boxed{\sf a = 100\ kmh^{-2}}\)

Explanation:

Given Data:

Distance = 200 km

Initial Velocity = Vi = 0 m/s

Time = 2 hours

Required:

Acceleration = a = ?

Formula:

2nd equation of motion

Solution:

\(\displaystyle S = Vit+\frac{1}{2} at^2\\\\200 = (0)(2)+\frac{1}{2} a(2)^2\\\\200 = \frac{1}{2} a (4)\\\\200 = 2a\\\\Divide\ both\ sides\ by\ 2\\\\200/2 = a\\\\a = 100\ kmh^{-2}\\\\\rule[225]{225}{2}\)

Hope this helped!

~AH1807Peace!

Complete each statement by dragging the forms of energy into their appropriate boxes.
wind turbine
roller coaster going downhill
toaster
car
A
converts electrical energy into thermal energy.
A
converts rotational energy into electrical energy.
A
converts gravitational energy into mechanical energy.
A
converts rotational energy into mechanical energy.

Answers

Statements 1,2,3 and 4 match statements B, C, A, and D respectively.A wind turbine converts rotational energy into electrical energy.

What is the law of conservation of energy?

According to the Law of conservation of energy. Energy can not be created nor be destroyed, it can transfer from one to another form.

1.A wind turbine converts rotational energy into electrical energy.

2.A roller coaster going downhill converts gravitational energy into mechanical energy

3. Toaster converts electrical energy into thermal energy

4.A car converts rotational energy into mechanical energy.

Hence,statements 1,2,3 and 4 match statements B, C, A, and D respectively.

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A substance with a pH value of 2.3 would be classified as
O strong acid
O weak acid
O strong base
O weak base

Answers

weak base i think since it’s a lower ph

A substance with a pH value of 2.3 would be classified as a strong acid. Option A is correct.

What is ph value?

pH stands for "potential hydrogen," and it is a measure of the acidity or basicity (alkalinity) of a solution. The pH scale ranges from 0 to 14, with 7 being neutral (neither acidic nor basic). Solutions with a pH less than 7 are considered acidic, and solutions with a pH greater than 7 are considered basic.

Here,
The pH scale is used to measure the acidity or basicity of a solution. Values on the pH scale range from 0 to 14. Solutions with a pH value less than 7 are considered acidic, and solutions with a pH value greater than 7 are considered basic. The lower the pH value, the more acidic the solution.

A pH value of 2.3 indicates that the solution is strongly acidic, as it is well below the neutral value of 7.

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You have been managing your time for years so you probably already have some ideas about what works for you. What are some effective time management strategies you have used at home at school or in the workplace? Why were they successful?

Answers

One of the most effective time management strategies that I have used is creating a to-do list. They are successful because they help me to prioritize tasks, remain organized, increase productivity, and reduce stress.

One of the most effective time management strategies that I have used is creating a to-do list.

Creating a to-do list helps me to prioritize tasks and ensures that I do not forget any important tasks.

When creating a to-do list, I ensure that I put the most important tasks at the top of the list and then work my way down.

The to-do list has helped me to organize my work, manage my time effectively and reduce stress.

Another effective strategy that I have used is breaking large tasks into smaller manageable tasks.

When dealing with complex tasks, I break them down into smaller, more manageable chunks.

This helps me to focus on the individual parts of the task, which are easier to handle and manage.

When I focus on smaller tasks, I find it easier to get started, and I gain momentum as I make progress on each small task.

This method has helped me to increase my productivity and reduce the stress that comes with handling large tasks.

In conclusion, the above time management strategies have helped me to manage my time effectively at home, school, and in the workplace.

They are successful because they help me to prioritize tasks, remain organized, increase productivity, and reduce stress.

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The current flowing through a lamp is 1.5AIt is plugged into a 120 V outletWhat is the resistance of the lamp? Ω

Answers

Given the flow of current and the voltage, the resistance of the lamp is 80 Ohms.

What is the resistance of the lamp?

Ohm’s law states that the potential difference between two points is directly proportional to the current flowing through the resistance.

V = IR

Where V is the voltage or potential difference, I is the current and R is the resistance.

Given the data in the question;

Current I = 1.5AVoltage V = 120VResistance R = ?

Plug the given values into the equation above and solve for R.

V = IR

120 = 1.5 × R

R = 120/1.5

R = 80Ω

Given the flow of current and the voltage, the resistance of the lamp is 80 Ohms.

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Answer:

80 is the answer

Explanation:

The current flowing through a lamp is 1.5AIt is plugged into a 120 V outletWhat is the resistance of

What are the major energy transformations that occur between when energy starts from a primary energy source, becomes a piece of wood, which is then burned in a fire?​

Answers

Sunlight to chemistry energy conversion, energy transfer as from sun to plants, kinetic energy is created by converting thermal energy. when wood is burned, mechanical energy is converted to thermal energy.

What are the primary six energy forms?

Chemical, electrical, infrared, mechanical, thermal, et nuclear energy are the six main types of energy. Different research may focus on other forms, such as electric, acoustic, electromagnetic, and some others.

What is an indication of an energy revolution?

Energy transition describes the change in the global energy industry away from fossil-based methods of hydropower, such as oil, natural gas, and coal, and toward rechargeable batteries with renewable sources of electricity like wind and solar.

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A uniform rod of length 50cm and mass 0.2kg is placed on a fulcrum at a distance of 40cm from the left end of the rod. At what distance from the left end of the rod should a 0.6kg mass be hung to balance the rod?
a.48 cm
b. 50 cm
c. 45 cm
d. the rod can not be balanced with this mass. e.42 cm​

Answers

Answer:

x = 45 cm

Explanation:

Given that,

The length of a rod, L = 50 cm

Mass, m₁ = 0.2 kg

It is at 40cm from the left end of the rod.

We need to find the distance from the left end of the rod should a 0.6kg mass be hung to balance the rod.

The centre of mass of the rod is at 25 cm.

Taking moments of both masses such that,

\(15\times 0.2=x\times 0.6\\\\x=\drac{3}{0.6}\\\\x=5\ cm\)

The distance from the left end is 40+5 = 45 cm.

Hence, at a distance of 45 cm from the left end it will balance the rod.

How much thermal energy is required for liquid water to turn in to a gas on
Mars?
O 100°C
O 10°C
0 212°C
O 50°C

Answers

Answer:

thanks you too for boys sweater in parallel and remember word on mangal I can do a few

Explanation:

free download in every way you are you sure about my experience with the same you for the following information to facilitate this answer and I can do the same to your email program I was not understand you want with you on Monday to Thursday morning I was speaking and listening at a later flight and

An ice skater with a mass of 80 kg pushes off against a second skater with a mass of 32 kg. Both skaters are initially at rest. (a) What is the total momentum of the system after they push off? (b) If the larger skater moves off with a speed of 3 m/s, what is the corresponding speed of the smaller skater

Answers

A. The total momentum of the system after they push off is zero.

B. m1v1=m2v2

v2=m1v1/m2

v2=80*3.0/32

v2=7.5 m/s

in fact

m1v1=80*3= 240 kgm/s

m2v2= 32*7.5= 240 kgm/s.

A penny board is a type of skateboard characterized by a short, narrow deck made of plastic. If you're on the short side, consider choosing a smaller deck. Smaller decks are easier to operate and control, lighter, and more portable. If you are taller, you should choose a larger deck.

The larger deck gives more stability and power when skating. A big part of being a skater girl is looking like that which means wearing skate-branded shoes and clothes. Other skaters tend to wear these clothes cut to allow the skater's movement. Good skatesHer brands include Vans DC Nike especially basketball lines and Etnies I have.

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A cart moving across a level surface accelerates
uniformly at 1.0 meter per second² for 2.0
seconds. What additional information is
required to determine the distance traveled by
the cart during this 2.0-second interval?

Answers

The initial velocity of the cart.

Newton, There can be a mass is four.080, So acceleration might be equal to 2.50 m in step with cent within the rectangular. Initial is that amount that relies upon total mass. The greater mass the more inertia. So Mass is 2000 kg and acceleration is 3 ms square. So this offers us an internet pressure identical to 6000 newtons or 6.0 and 210 to the power

In case you roll a ball, it initially will keep rolling except friction or something else stops it by means of pressure. you could also think about the way that your body maintains transferring ahead when you hit the brake on your bike. Translational Inertia = ma, in which m is the mass, and a is the acceleration of the object. Calculate the rotational inertia or the instant of inertia velocity by way of multiplying the mass of the object with a square of the gap between the item and the axis, the radius of rotation.

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How has Physics improved
or affected our society?

Answers

By supplying the fundamental knowledge required to create new instruments and techniques for medical use, physics enhances our quality of life

From can openers, light bulbs, and mobile phones to muscles, lungs, and brains; from paintings, piccolos, and pirouettes to cameras, vehicles, and cathedrals; from earthquakes, tsunamis, and storms to quarks, DNA, and black holes, physics aids us in understanding the workings of the world around us.

The science of physics is the most fundamental and has many applications in contemporary technology. Because it makes it possible for smartphones, computers, televisions, watches, and many other modern technologies to function automatically, physics is crucial to modern technology.

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A world-class tennis player can serve a tennis ball at 150 mi/h (about 67 m/s). The length of a tennis
court is 78 ft. Approximately how long does an opponent have to react from the instant the ball is served
until the ball reaches the opponent?

Answers

Answer:

The expression for the time taken by an object to move with a speed at some distance is,

t= d/v

Here, t is the time taken by the opponent to react, d is the length of the court, andis the speed of the ball.

Explanation:

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calculate the weight of 100kg object onthe surface of planet with mass and diametre of 4.8×10^24 k and 12000km respectively​

Answers

The weight of the 100 kg object on the surface of the planet is approximately 8.9 × 10¹² Newtons.

To calculate the weight of a 100 kg object on the surface of a planet, we need to use the formula for gravitational force:

F = (G * M * m) / r²

Where:

F is the gravitational force (weight)

G is the gravitational constant (approximately 6.67430 × 10⁻¹¹ N m²/kg²)

M is the mass of the planet (4.8 × 10²⁴ kg)

m is the mass of the object (100 kg)

r is the radius of the planet (diameter / 2)

Given that the diameter of the planet is 12,000 km, we can find the radius by dividing it by 2:

r = 12,000 km / 2 = 6,000 km = 6,000,000 m

Now, we can substitute the values into the formula:

F = (6.67430 × 10⁻¹¹ N m²/kg² * 4.8 × 10²⁴ kg * 100 kg) / (6,000,000 m)²

Simplifying the expression:

F = (6.67430 × 10⁻¹¹ N m²/kg² * 4.8 × 10²⁶ kg) / 36,000,000,000 m²

F ≈ 8.9 × 10¹² N

Therefore, the weight of the 100 kg object on the surface of the planet is approximately 8.9 × 10¹² Newtons.

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Equation of path of projectile is y=x(1-x)

Answers

The equation of the path of a projectile is y = x(1 - x). Projectile motion is the movement of an object in a parabolic trajectory as a result of being propelled or released under the influence of gravity. A projectile, in simple terms, is any object that is launched into the air, such as a bullet, a baseball, or a rock. It's important to note that the parabolic trajectory is due to the force of gravity acting on the object.

To better understand projectile motion, we must first examine the horizontal and vertical components of motion. The horizontal component of motion is constant, indicating that there is no acceleration in that direction. The vertical component, on the other hand, has acceleration because of gravity. The parabolic trajectory is the result of these two components of motion.As the projectile is launched, it travels a certain distance horizontally before beginning to descend as a result of gravity's influence, resulting in a parabolic path.The general formula for the trajectory of a projectile in two dimensions is given by:y = xtanθ - (gx²) / 2(v₀cosθ)²Where:y is the vertical distance covered by the projectilex is the horizontal distance covered by the projectileθ is the angle of projectiong is the acceleration due to gravityv₀ is the initial velocity of the projectile In the case of the given equation, y = x(1 - x), the path of the projectile will be a parabolic trajectory with a vertex at x = 0.5 and y = 0.25. The equation represents the projectile's vertical distance, y, as a function of its horizontal distance, x. It is crucial to note that the projectile's initial velocity and angle of projection are not considered in this equation.

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What is MOST likely to be TRUE about asynchronous communication?
It is rarely used in businesses in today's society.
It offers many opportunities to ask clarifying questions in real time.
It is helpful when employees work across multiple time zones.
It only works when all employees work in the same time zone.

Answers

The most likely true statement about asynchronous communication is that it is helpful when employees work across multiple time zones.

Asynchronous communication refers to a mode of communication where participants do not need to be present or engaged simultaneously. Instead, they can send and receive messages at their convenience.In today's globalized society, businesses often have teams distributed across different geographical locations and time zones. Asynchronous communication becomes invaluable in such scenarios as it allows team members to collaborate effectively without the constraints of real-time interactions. By utilizing tools like email, project management platforms, or messaging apps, individuals can communicate and exchange information regardless of their location or the time differences.

Asynchronous communication also offers benefits such as flexibility and increased productivity. Team members have the freedom to work at their own pace and prioritize tasks accordingly. It provides opportunities for thoughtful and well-crafted responses, as individuals can take time to gather information or reflect on complex matters before replying.While asynchronous communication is advantageous for teams operating across multiple time zones, it does not rely on all employees working in the same time zone. In fact, it is designed to accommodate diverse schedules and allow individuals to collaborate efficiently despite their varying work hours.

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A rod with a length of L = 1 m is held vertically so that one end rests on the floor. After that
let go of the stick and fall. Let us assume that the supported end does not slip and that the thickness of the bar is very small compared to its length (that is, its moment of inertia with respect to the center of gravity is IT = 1/12mL^2

(a) With what speed does the other end of y hit the floor?
(b) How much does the end impact speed increase if it were a 100 m tall object that was originally
blasted off (and not broken when falling)?
Hint: Use the law of conservation of mechanical energy. Kinetic energy can be written in two ways:
1. Pure rotary movement around the end of the rod. 2. Rotary movement around the center of gravity + movement of the center of gravity. Both procedures,
of course, give the same result (you can try both and see for yourself).

Answers

Explanation:

(a) Let's use the law of conservation of mechanical energy to determine the speed with which the other end of the rod hits the floor. When the rod is released, it begins to rotate around its center of gravity and falls to the floor. At the moment of release, the rod has no kinetic energy or potential energy, but it has potential energy when it reaches the floor. The energy is conserved, so we can equate the initial potential energy to the final kinetic energy.

The initial potential energy of the rod is given by:

U_i = mgh

where m is the mass of the rod, g is the acceleration due to gravity, and h is the height of the center of gravity above the floor. Since the rod is vertical, h = L/2. The mass of the rod can be calculated using its density ρ and cross-sectional area A:

m = ρAL

The final kinetic energy of the rod is given by:

K_f = (1/2)Iω^2 + (1/2)mv^2

where I is the moment of inertia of the rod with respect to its center of gravity, ω is the angular velocity of the rod, and v is the linear velocity of the center of gravity. At the moment when the rod hits the floor, the angular velocity is zero, so the first term in the above equation is zero. We can simplify the equation to:

K_f = (1/2)mv^2

We can equate the initial potential energy and final kinetic energy to get:

mgh = (1/2)mv^2

Solving for v, we get:

v = sqrt(2gh)

Substituting the given values, we get:

v = sqrt(2gL/2) = sqrt(gL/2)

Now, we can substitute the values of g and L to get:

v = sqrt(9.81 m/s^2 x 1 m/2) = sqrt(4.905) m/s

Therefore, the other end of the rod hits the floor with a speed of approximately 2.216 m/s.

(b) If the length of the rod were 100 m instead of 1 m, the speed with which the end hits the floor would increase significantly. The potential energy of the rod when it is released is proportional to its height above the floor, so when the length of the rod is increased by a factor of 100, the potential energy increases by a factor of 100 as well. Therefore, the final speed of the end hitting the floor would be:

v' = sqrt(2gh') = sqrt(2g(100L)/2) = sqrt(100gL/2) = 10sqrt(gL/2)

Substituting the given values, we get:

v' = 10sqrt(9.81 m/s^2 x 100 m/2) = 10sqrt(490.5) m/s

Therefore, the end of the 100 m tall object would hit the floor with a speed of approximately 70.0 m/s, which is a significant increase compared to the initial speed of the 1 m rod.

in order to make a soft landing, you need to reduce the velocity of the lander to less than 2 meters/second. how can you do this without wasting fuel

Answers

Answer:

In the absence of thrust, the lander continues to accelerate downward. As it approaches the surface, use maximum thrust until you get the velocity near zero, then turn off force. Allow it to pick up downward speed and repeat briefly, as necessary. The most important thing is to not waste fuel by “hovering” in one place, or worse, going upward!

The lander keeps speeding downward in the lack of thrust. The most crucial element is to avoid wasting gasoline by moving upward or, worse, by "hovering" in one position.

What is velocity?

When an aircraft changes the distance in relation to the time, then this is known as velocity. This quantity comes under the category of a vector quantity. In math, the velocity is calculated by dividing the distance by the time.

Allow the airplane to begin to descend, then short repeat as necessary. The most crucial element is to avoid wasting gasoline by moving upward or, worse, by "hovering" in one position.

13,500 newtons of thrust are the bare minimum needed to launch the lander from its position of rest.

Since the lander is at rest, there is no net force acting on it. This state of rest is changed to upward motion by the propulsion of 13,500 newtons, proving that the force of gravity acting on the lander is less than 13,500 newtons.

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A car traveled a distance of 30 km in 20 minutes (1/3 hours). What was the
speed of the car?
A. 90 km/hr
OB. 60 km/hr
O C. 30 km/hr
D. 10 km/hr

Answers

The answer is, (A). 90 I’m/hr
The answer will be A.

A rollar coaster moves over the creast at location 1 at 10 m/s. HOw fast is it going at location 4? Neglect friction and air resistance.

Answers

The velocity of the roller coaster at location 4 is 14.14 m/s (approx) using the given values of v₁ = 10 m/s, h₁ = 30 m, and h₂ = 15 m.

Roller coasters are fascinating machines that deliver an exhilarating experience by defying gravity and physics. Roller coaster physics is a significant concept to comprehend before riding a roller coaster or designing one. The laws of physics govern the motion of a roller coaster, including its velocity, acceleration, and potential energy.

A roller coaster moves over a crest at location 1 with a speed of 10 m/s. The question is how fast it's going at location 4, considering the neglect of friction and air resistance. To solve this, we'll need to consider the conservation of energy law.

The total energy of the roller coaster remains constant throughout the ride, and we can convert between potential and kinetic energy.Using the conservation of energy formula, which is: E1 = E2Where E1 is the total energy of the roller coaster at the crest and E2 is the total energy of the roller coaster at location 4.

Both E1 and E2 comprise kinetic energy (KE) and potential energy (PE). So,E1 = KE1 + PE1E2 = KE2 + PE2Since the roller coaster has no friction and air resistance, we can assume that PE1 = PE2 because the height of the roller coaster doesn't change. The energy is converted from potential energy at the crest to kinetic energy at location 4.

We can now use the formula for kinetic energy:KE = (1/2) mv²Where m is the mass of the roller coaster and v is its velocity. Both E1 and E2 can be written in terms of KE, so: E1 = (1/2) mv₁²E2 = (1/2) mv₂².

Substitute the values into the conservation of energy formula: E1 = E2(1/2) mv₁² = (1/2) mv₂²

Simplifying the equation gives:v₂² = v₁²×(h₁ / h₂)

where h₁ is the height of the crest and h₂ is the height of location 4.

To calculate the velocity, we need to take the square root of both sides:v₂ = v₁×√(h₁ / h₂)

Therefore, the velocity of the roller coaster at location 4 is 14.14 m/s (approx) using the given values of v₁ = 10 m/s, h₁ = 30 m, and h₂ = 15 m.

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Consider a satellite in a circular geostationary orbit about the Earth, meaning it orbits above a fixed point on the Earth's equator.

You may use the following values in your calculations:

- Mass of the Earth, M is 6.0x1024kg;

- Gravitational constant G, is 6.67 x 10-11 N m2 kg-2

- Radius of the Earth, r is 6400 km or 6.4 x 106 m. At what distance from the centre of the Earth does the satellite orbit?

Answers

Answer:

m V^2 / R = G M m / R^2          balancing forces

R = G M / V^2   (I)

V = 2 π R / (24 * 3600)      to complete 1 rev in 24 hrs

V = π R / (12 * 3600) = R * 7.27E-5

V^2 = R^2 * 5.29E-9

R = G M / (R^2 * 5.29E-9)             using (I)

R = (G M / 5.29E-9)^1/3

R = (6.67E-11 * 6.0E24 / 5.29E-9)^1/3

R = (66.7 * 6.0 / 5.29)^1/3 E7

R = 4.22E7 meters = 42200 km   about 7 earth radii

A spacecraft is traveling with a velocity of Vox-5690 m/s along the +x direction. Two engines are turned on for a time of 865 s. One
engine gives the spacecraft an acceleration in the +x direction of a, 1.45 m/s², while the other gives it an acceleration in the ty
direction of a, -8.66 m/s2. At the end of the firing, what is a) v, and b) vy?
(a) Number i
(b) Number
Units
Units

A spacecraft is traveling with a velocity of Vox-5690 m/s along the +x direction. Two engines are turned

Answers

For a spacecraft is traveling with a velocity of Vox-5690 m/s:

(a) The final velocity (v) is approximately 685.25 m/s.(b) The vertical component of the velocity (vy) is -7484.9 m/s.

How to calculate velocity and vertical component?

To solve this problem, use the equations of motion to calculate the final velocity and the vertical component of the velocity. Assume that the initial velocity in the y-direction is zero.

Given:

Initial velocity in the x-direction (V₀ₓ) = -5690 m/s

Time of engine firing (t) = 865 s

Acceleration in the x-direction (ax) = 1.45 m/s²

Acceleration in the y-direction (ay) = -8.66 m/s²

(a) To calculate the final velocity (v), use the equation:

v = V₀ₓ + ax × t

Substituting the values:

v = -5690 m/s + 1.45 m/s² × 865 s

v = -5690 m/s + 1254.25 m/s

v ≈ 685.25 m/s

Therefore, the final velocity (v) is approximately 685.25 m/s.

(b) To calculate the vertical component of the velocity (vy), use the equation:

vy = ay × t

Substituting the values:

vy = -8.66 m/s² * 865 s

vy = -7484.9 m/s

Therefore, the vertical component of the velocity (vy) is -7484.9 m/s.

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which of the following characteristics is most useful for flower identification​

Answers

Answer:

basically needing sunlight and water

Explanation:

hope it helps

The nature of light is difficult to grasp because light acts differently in different situations. For example, when light shines through narrow slits, the light behaves as only ________ can. However, when light shines onto a metal and the spray of electrons that comes off is examined, the light behaves as only _________ can.

Answers

Answer:

what do you need us to answer?

Explanation:

A crowbar of 200 cm long is pivoted about to its other end to displace a load of 600 N. 0.5 m Calculate MA, VR and efficiency of the crowbar.

Answers

The mechanical advantage of the crow bar is 3 while the velocity ratio is 4. The efficiency of the machine is 75%.

What is the efficiency of the crow bar?

We know that a machine is any device that can be used to make work a lot much easier. Thus, the machine is the object that could make less effort to be applied in making a greater work to be done as we can see in this case we have here.

From the question, the pieces of information that we can get are;

Distance moved by Effort = 200 cm

Distance moved by load = 0.5 m or 50 cm

Velocity ratio = Distance moved by Effort/Distance moved by load

= 200 cm /50 cm

= 4

Mechanical advantage is found to be; Load/Effort

= 600 N/200 N

= 3

Efficiency = Mechanical advantage/ Velocity ratio * 100/1

= 6/4 * 100/1

=3/4 * 100/1

= 75%

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A 0.0400 kg meter stick is placed on a thin rod at the 30.0 cm mark. What is the minimum mass required to be placed on the 0.00 cm mark on the stick to maintain equilibrium?

Answer in kg

Answers

The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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4. A diver is 20 m underwater and they are startled by a shark. They are tempted to take a big breath of air, drop their gear, and swim to the surface while holding their breath. Explain why this is dangerous g

Answers

Answer:

Explanation:

The air enters their lungs at the same pressure as the water at that depth.

If they hold their breath as they rise to atmospheric pressure, the expanding volume of air (due to decreasing pressure) trapped in their lungs will hyperextend the alveoli in their lungs, likely tearing blood lines and risking death by drowning in their own blood.

if the body is floating in a liquid then can we say that the rise in the level of the liquid is equal to the height of the body

Answers

Yes, if a body is floating in a liquid, the rise in the liquid level is equal to the body height. This phenomenon is known as Archimedes' principle.

Archimedes' principle says when a body is immersed in a fluid (liquid or gas), it experiences an upward buoyant force equal to the weight of the fluid displaced by the body. Buoyant forces act in the opposite direction to gravity.

When a body floats in a liquid, it displaces a volume of liquid equal to its volume. As a result, the liquid level rises by an amount equal to the height of the submerged part of the body.

This principle holds for objects that float or are partially immersed in a liquid, such as a buoyant boat or a floating object. However, if the body sinks completely into the liquid, the liquid level rise will no longer be equal to its height. Instead, it depends on the density and volume of the submerged object.

The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?

Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.

Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!

Answers

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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