- 46 = -5(3 – b) + 6
b=
Help! Please

Answer:

32 degrees.

Step-by-step explanation:

A triangle is 180 degrees.

180 - 85 - 63 = 32 degrees.

Answer:

x = 32

Step-by-step explanation:

All interior angles in a triangle equal to 180

use this to solve for x

180 = 85 + 63 + x

180 - 85 - 63 = x

32 = x

Answer:

A

Step-by-step explanation:

Answer:

A is correct

Step-by-step explanation:

I took the test and got it right and (x, y) → (x – 6, y – 1) if you do the equation it fits the image

Answer:

The \(n^{th}\) of the sequence

\(t_{n} = ar^{n-1}\)

The  \(10^{th}\) of the sequence

\(t_{10} = 5(5)^{10-1} = 9,765,625\)

Step-by-step explanation:

Explanation:-

Given that the geometric sequence

5, 25 , 125 ,....

First-term  a= 5

Difference    \(r = \frac{25}{5} =5\)

The \(n^{th}\) of the sequence

\(t_{n} = ar^{n-1}\)

The  \(10^{th}\) of the sequence

\(t_{10} = 5(5)^{10-1} = 9,765,625\)

(a) The plot of y versus t for several values of y₀ between 1/2 and 1 shows oscillations with higher y₀ resulting in larger oscillations.

(b) The critical initial population \(y_c\) below which the population becomes extinct is \(y_c\) = 2.5k.

(c) For different values of k, the corresponding critical initial populations \(y_c\) are found

(d) The relationship between the critical initial population \(y_c\) and the predation rate k can be summarized as \(y_c\) = 2.5k.

(a) Plotting y versus t for several values of y₀ between 1/2 and 1:

To solve the initial value problem dy/dt = r(t) * y - k, y(0) = y₀, we need to integrate the differential equation numerically.

Given:

- r(t) = (1 + sin t) / 5

- k = 1/5

We can observe the following:

For each value of y₀ between 1/2 and 1, the population y will exhibit a fluctuating behavior over time. The sine function in r(t) causes the growth rate to oscillate, leading to oscillations in the population as well. The magnitude of the oscillations depends on the initial population y₀.

Higher values of y₀ will result in larger oscillations, while lower values will lead to smaller oscillations. As time progresses, the population may increase or decrease depending on the interplay between the growth rate and the predation rate.

(b) Estimating the critical initial population \(y_c\) below which the population will become extinct:

To estimate the critical initial population \(y_c\), we need to find the value of y₀ for which the population becomes extinct. This occurs when the population y drops to zero or a very small positive value.

For the given differential equation dy/dt = r(t) * y - k, we can see that when y is very close to zero, the rate of decrease (k) dominates over the growth rate (r(t) * y). Therefore, we can set up the following equation:

0 = r(t) * y - k

Solving this equation for y, we find:

y = k / r(t)

Substituting r(t) = (1 + sin t) / 5, we have:

y = 5k / (1 + sin t)

To find the critical initial population \(y_c\), we need to determine the smallest value of y for all t. Since the minimum value of sin t is -1, the smallest value of y is obtained when sin t = -1, yielding:

\(y_c\) = 5k / (1 - (-1))

   = 5k / 2

   = 2.5k

Therefore, the critical initial population \(y_c\) is 2.5 times the predation rate k.

(c) Choosing other values of k and finding the corresponding \(y_c\) for each one:

Let's consider different values of k and calculate the corresponding critical initial population \(y_c\) using the formula derived in part (b):

For k = 1/10:

\(y_c\) = 2.5 * (1/10) = 1/4 = 0.25

For k = 1/4:

\(y_c\) = 2.5 * (1/4) = 5/8 = 0.625

For k = 1/2:

\(y_c\) = 2.5 * (1/2) = 5/4 = 1.25

For k = 1:

\(y_c\) = 2.5 * 1 = 2.5

For k = 2:

\(y_c\) = 2.5 * 2 = 5

For k = 5:

\(y_c\) = 2.5 * 5 = 12.5

These are the corresponding critical initial populations \(y_c\) for different values of k.

(d) Plotting \(y_c\) versus k:

Using the values of \(y_c\) and k calculated in part (c), we can plot \(y_c\) versus k:

k       |   \(y_c\)

-------------------

1/10   |  0.25

1/4    |  0.625

1/2    |  1.25

1       |  2.5

2      |  5

5      |  12.5

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Finding the union of the sets A and C is the first step in solving P(A U C). Since set C only contains the number 6, the union of A and C has the elements 1, 2, 3, 4, and 6. A U C thus equals 1, 2, 3, 4, and 6.

The power set of A U C, which comprises all conceivable subsets of 1, 2, 3, 4, and 6, must then be located. If all conceivable subsets are listed, the power set of A U C, designated as P(A U C), will be discovered.

P(A U C) = { {}, {1}, {2}, {3}, {4}, {6}, {1,2}, {1,3}, {1,4}, {1,6}, {2,3}, {2,4}, {2,6}, {3,4}, {3,6}, {4,6}, {1,2,3}, {1,2,4}, {1,2,6}, {1,3,4}, {1,3,6}, {1,4,6}, {2,3,4}, {2,3,6}, {2,4,6}, {3,4,6}, {1,2,3,4}, {1,2,3,6}, {1,2,4,6}, {1,3,4,6}, {2,3,4,6}, {1,2,3,4,6}}.

There are 31 subsets in the power set P(A U C) that result from the union of sets A and C.

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Answer:

x=2.2

Step-by-step explanation:

You know that for triangle ABC, side AB=10, CB=2 and AD=AB+BD=10+1=11. Given that triangles ABC and AED have the same angles, they are similar triangles.

So we can use the following ratios to solve for ED=x:

Answer:

The answer is C, (12, -1).

Step-by-step explanation:

Answer:

10+8+2.5+8+6+2.5=37 .

ok you are understand or bot

The probability of a student having a quiz grade of 90 or greater is 7.4%.

The two characteristics feature of normality and symmetricity of a dataset makes calculations pertaining to research theory easier. Further, in a case where symmetricity is observed in data, normal distribution is assumed there as an appropriate probability distribution.

The probability of a student having a quiz grade of 90 or greater can be calculated using the standard normal distribution. The formula used to calculate this probability is P(x ≥ 90) = 1 - P(x < 90).

The standard normal distribution is a normal distribution with a mean of 0 and a standard deviation of 1. To convert our quiz grade to a z-score, we must subtract the mean (80) from our quiz grade (90) and divide by the standard deviation (7). This gives us a z-score of 1.43.

To calculate the probability of a quiz grade of 90 or greater, we subtract the cumulative probability of a z-score of 1.43 from 1. This can be done using a z-table or a calculator. The result of this calculation is 0.0740 or 7.4%.

In conclusion, the probability of a student having a quiz grade of 90 or greater is 7.4%.

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Answer:

y=15

Step-by-step explanation:

Answer:

Y=15

Step-by-step explanation:

4-1=3

18-3=15

15+3=18

So, 15+4-1=18

Answer:

Square 4x³ - x²

Step-by-step explanation:

Given the expression -5x²(4x³ - x²)²

The first step in simplifying the expression is to open the parenthesis by taking the square of 4x³ - x² as shown;

-5x²(4x³ - x²)²

= -5x²[(4x³)²- 2x²(4x³) + (x²)²]

= -5x²[16x^6- 8x^5 + x^4]

Hence the correct answer is Square 4x³ - x²

\(f(x) = \frac{10}{9}x + 11 \\ \)

So :

\(y = \frac{10}{9}x + 11 \\ \)

Subtract the sides of the equation minus 11

\(y - 11 = \frac{10}{9}x \\ \)

Multiply the sides of the equation by 9

\(9(y - 11) = 10x\)

\(9y - 99 = 10x\)

Divided the sides of the equation by 10

\( \frac{9y - 99}{10} = x \\ \)

So :

\( {f}^{ - 1}(x) = \frac{9x - 99}{10} \\ \)

_________________________________

And we're done.

Thanks for watching buddy good luck.

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Slope is  $0.15 of the equation of cost  C=$0.15t+$35.00.

The slope of the line is the ratio of the rise to the run, or rise divided by the run. It describes the steepness of line in the coordinate plane.

The slope intercept form of a line is y=mx+b, where m is slope and b is the y intercept.

The slope of line passing through two points (x₁, y₁) and (x₂, y₂) is

m=y₂-y₁/x₂-x₁

Given that A cell phone company uses the equation C=$0.15t+$35.00

C is the total cost for a month of service.

t is the number of text messages.

We have to find the slope of the equation.

slope is 0.15 and 35.00 is the y intercept of the equation given.

Hence, slope is  $0.15 of the equation of cost  C=$0.15t+$35.00.

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Answer:

b = -5 and c = -4

Step-by-step explanation:

The common ratio here is r = 20/(-5), or -4, and the first term, a(1), is -5.  Thus, the explicit formula is

a(n) = a(1)*r^(n -1)    (must use parentheses, as shown)

and so we have a(n) = -5*(-4)^(n - 1).  b = -5 and c = -4

Answer:

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mathstatistics and probabilitystatistics and probability questions and answerscomplete the sentence below. the _____ _____, denoted modifyingabove p with caret , is given by the formula modifyingabove p with caret equals_____, where x is the number of individuals with a specified characteristic in a sample of n individuals.

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Question: Complete The Sentence Below. The _____ _____, Denoted ModifyingAbove P With Caret , Is Given By The Formula ModifyingAbove P With Caret Equals_____, Where X Is The Number Of Individuals With A Specified Characteristic In A Sample Of N Individuals.

Complete the sentence below.

The _____ _____, denoted ModifyingAbove p with caret , is given by the formula ModifyingAbove p with caret equals_____, where x is the number of individuals with a specified characteristic in a sample of n individuals.

Complete the sentence below

Thedenoted p, is given by the formula

The

where x is the number of individuals with a specified c

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Solution : Given that, n = x = Point estimate = sample propo…View the full answer

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Transcribed image text: Complete the sentence below Thedenoted p, is given by the formula The where x is the number of individuals with a specified characteristic in a sample of n individuals. the number of ▼I, denoted p, is given by the formula p ▼1, where x is the number of individuals with a specified characteristic in a sample of n individuals

The solutions for v are v = (i√7)/√5 and v = -(i√7)/√5.

An imaginary number is a number that can be written in the form a + bi, where a and b are real numbers and i is the imaginary unit, which is defined as the square root of -1. The number a is called the real part of the imaginary number, and b is called the imaginary part.

To solve for v in the equation 5v² + 2 = -5, we can follow these steps:

Move the constant term to the right side of the equation:

5v² = -5 - 2

5v² = -7

Divide both sides of the equation by 5:

v² = -7/5

Take the square root of both sides of the equation, remembering to include both the positive and negative roots:

v = ±√(-7/5)

The square root of a negative number is an imaginary number, denoted by "i". Therefore, we can simplify the solution as:

v = ±(i√7)/√5

So, the solutions for v are v = (i√7)/√5 and v = -(i√7)/√5.

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the complete question is:

Solve for value of v

5v² + 2 = -5

Answer:

The coordinates of b are (3, -5)

Step-by-step explanation:

\(c(1,-1)\)

\(a(-1,3)\)

\(1=\frac{-1+x}{2}\)

\(2=-1+x\)

\(x=2+1\)

\(x=3\)

\(-1=\frac{3+y}{2}\)

\(-2=3+y\)

\(y=-2-3\)

\(y=-5\)

Answer:

10x + x^4/x-2

Step-by-step explanation:

Combine like terms

(10x + x^4)/(x-2)

Answer:

I thought you were quoting danganronpa for a second ...

I hope you feel better!!

Step-by-step explanation:

a)The number of marbles they have altogether willl be 230.

b)The no of marbles that must be given to Pete will be 32.

A ratio is an ordered pair of integers a and b expressed as a/b, with b never equaling 0. A percentage is a mathematical expression in which two ratios are specified to be equal.

Let the no of marble Pete, ben and Leon will have x,y, and z respectively.

From the given condition;

y = 30+x

z=2x

z:y=6:5

z:y=6:5

y=5z/6

Substitute the obtained values;

\(\rm \frac{5z}{6} = 30+\frac{z}{2} \\\\ \frac{5z}{6} =30+\frac{z}{2} \\\\ \frac{10z-6z}{12} =30\\\\\ z=90\)

Substitute the value we get;

x=45

y=95

The no of marble they have all together;

⇒x+y+z

⇒45+95+90

⇒230

If all the marble has to be distributed in an equal manner. The equivalent no of marble for everyone is;

n=(45+95+90)/3

n=76.66≈77

The no of marbles must be given to pete so that the boys are to share the marbles equally;

⇒77-45

⇒32

The number of marbles they have altogether willl be 230 and the no of marbles that must be given to Pete will be 32.

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Answer:

8 Green beads

Step-by-step explanation:

12 divided by 3 = 4

4 times 2 = 8

The volume of the solid is:Volume = \(π ∫0 2 (4 - 2x)2 dx= π ∫0 2 16 - 16x + 4x2 dx= π [16x - 8x2 + (4/3) x3]02= π [(32/3) - (32/3) + (32/3)]= (32π/3)\) square units

The given function is y = 4 - 2x. The region R is the region bounded by the x-axis and the y-axis. To compute the volume of the solid formed by revolving R about the y-axis, we can use the disk method. Thus,Volume of the solid = π ∫ (a,b) R2 (x) dxwhere a and b are the bounds of integration.

The quantity of three-dimensional space occupied by a solid is referred to as its volume. The solid's shape and geometry are taken into account while calculating the volume. There are specialised formulas to calculate the volumes of simple objects like cubes, spheres, cylinders, and cones. The quantity of three-dimensional space occupied by a solid is referred to as its volume. The solid's shape and geometry are taken into account while calculating the volume. There are specialised formulas to calculate the volumes of simple objects like cubes, spheres, cylinders, and cones.

In this case, we will integrate with respect to x because the region is bounded by the x-axis and the y-axis.Rewriting the function to find the bounds of integration:4 - 2x = 0=> x = 2Now we need to find the value of R(x). To do this, we need to find the distance between the x-axis and the function. The distance is simply the y-value of the function at that particular x-value.

R(x) = 4 - 2x

Thus, the volume of the solid is:Volume = \(π ∫0 2 (4 - 2x)2 dx= π ∫0 2 16 - 16x + 4x2 dx= π [16x - 8x2 + (4/3) x3]02= π [(32/3) - (32/3) + (32/3)]= (32π/3)\) square units

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Answer:

8.3

Step-by-step explanation:

40-4=36

3x3=9

36-9=25

25/3 = 8.3

x=7

Step-by-step explanation:

The x-intercepts or roots of the parabola are the locations where a parabola contacts the x-axis. These are the solutions to the parabola equation where the y-value is equal to zero.

A parabola is an open curve formed by the intersection of a right circular cone with a plane parallel to one of the cone's elements. This is known as the standard form of a quadratic function. A parabola is the graph of a quadratic function that is a U-shaped curve. A parabola is the graph of the equation y=x2 illustrated below. Parabolas are classified into three categories. There are three types of forms: vertex form, standard form, and intercept form. Each type offers a unique important characteristic for the graph. The three major forms from which we graph parabolas are known as standard form, intercept form, and vertex form. Each form will provide you with somewhat different information as well as its own set of pros and downsides.

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answer:

3

step-by-step explanation:

Answer:

Answer:12=2x+1y

Step-by-step explanation:

Answer:

Step-by-step explanation:

$4 4 pounds of bananas, $8 4 pounds of apples

$6 6 pounds of bananas, $6 3 pounds of apples

The statement is true. If the row [0 0 0 1 0] is in echelon form of an augmented matrix, then the associated linear system is always consistent. This means there is at least one solution to the system of linear equations.

Echelon form is a type of row-echelon form that has specific properties. In echelon form, the leading coefficient (non-zero element) of each row is strictly to the right of the leading coefficient of the row above it. In the given row [0 0 0 1 0], the leading coefficient is 1, and it is the only non-zero element in the row.

In an augmented matrix, the rightmost column represents the constants or the right-hand side of the linear equations. Since the leading coefficient in the given row is 1 and there are no non-zero elements to the left of it, this implies that the associated linear equation is of the form 0x + 0y + 0z + w = 0. This equation simplifies to w = 0.

Since w is a free variable and its value can be chosen as 0, the linear system is consistent. Every consistent system has at least one solution, and in this case, the solution is when w = 0, while x, y, and z can take any values.

Therefore, if [0 0 0 1 0] is one row in an echelon form of an augmented matrix, the associated linear system is always consistent.

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The absence of a fixed number of trials is the characteristic that is not common to both binomial and geometric experiments.

Binomial and geometric experiments are both types of probability experiments commonly encountered in statistics. They share several characteristics, such as independent trials and outcomes with two possible outcomes (success or failure). However, one characteristic that distinguishes them is the fixed number of trials.

In a binomial experiment, the number of trials is fixed and known in advance. Each trial is independent and has two possible outcomes. For example, flipping a coin 10 times or rolling a die 20 times are examples of binomial experiments where the number of trials is predetermined. On the other hand, in a geometric experiment, the number of trials is not fixed. The experiment continues until the first success occurs. Each trial is independent and has two possible outcomes. For instance, flipping a coin until getting the first heads or rolling a die until getting a 6 are examples of geometric experiments where the number of trials is uncertain.

While binomial experiments have a fixed number of trials, geometric experiments do not. This distinction makes the fixed number of trials a characteristic specific to binomial experiments and not common to geometric experiments.

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