44 and 817 estimated

(a)the body temperature of the 1601 lb man will increase by approximately 3.0 °C.(b)the body temperature of the 160 lb man will increase by approximately 2.4 °C.

The specific heat of a human is given as 3.47 J/°C. Using this information, we can calculate the increase in body temperature when a certain number of calories are converted into heat energy. In the first scenario, a 1601 lb man consumes a candy bar containing 287 Cal. In the second scenario, a 160 lb man consumes a roll of candy containing 41.9 Cal. We will calculate the increase in body temperature for each case.

(a) To calculate the increase in body temperature for a 1601 lb man who consumes a candy bar containing 287 Cal, we need to convert calories to joules. Since 1 Calorie (Cal) is equal to 4184 joules, we have:
Energy = 287 Cal × 4184 J/Cal = 1.2 × \(10^6\) J
Now, using the specific heat formula Q = mcΔT, where Q is the energy, m is the mass, c is the specific heat, and ΔT is the change in temperature, we can rearrange the formula to solve for ΔT:
ΔT = Q / (mc)
Assuming the mass of the man is converted to kilograms, we have:
ΔT = (1.2 × \(10^6\) J) / (1601 lb × 0.4536 kg/lb × 3.47 J/°C) ≈ 3.0 °C
Therefore, the body temperature of the 1601 lb man will increase by approximately 3.0 °C.
(b) For a 160 lb man who consumes a roll of candy containing 41.9 Cal, we repeat the same calculation:
Energy = 41.9 Cal × 4184 J/Cal = 1.75 × \(10^5\) J
ΔT = (1.75 × \(10^5\) J) / (160 lb × 0.4536 kg/lb × 3.47 J/°C) ≈ 2.4 °C
Thus, the body temperature of the 160 lb man will increase by approximately 2.4 °C.

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Exercising the in-the-money call option with an exercise price of 1,680 and the current index value of 1,720 would result in a profit of 40 per index, minus the premium paid for the option.

If the S&P 100 index is currently at 1,720, and the exercise price of the call option is 1,680, then the option is in-the-money. In other words, if you were to exercise the call option, you would be able to buy the S&P 100 index at a price that is lower than its current market value.

To determine the profit from exercising the option, you need to calculate the option's intrinsic value, which is the difference between the current index value and the exercise price. In this case, the intrinsic value of the call option is:

Intrinsic Value = Current Index Value - Exercise Price

Intrinsic Value = 1,720 - 1,680

Intrinsic Value = 40

So, if you were to exercise the call option, you would be able to buy the S&P 100 index at a price of 1,680 and then sell it in the market at the current value of 1,720, resulting in a profit of 40 per index.

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Suppose that you purchased a call option on the S&P 100 Index. The option has an exercise price of 1,680, and the index is now at 1,720. What will happen when you exercise the option?

The approximation for 4.84 by using linear approximation, i.e., the tangent line, is 717.2.

We must use linear approximation, i.e., the tangent line, to approximate 4.84 as follows:

Let f(x) = x^4.

The equation of the tangent line to f(x) at x = 5 can be written in the form y = mx + b where m is:

m = f'(x) and where b is:

b = f(x) - m(x)

Using this, we find our approximation for 4.84 is:

We can find the equation of the tangent line to f(x) at x = 5 by finding the slope and the y-intercept.

Slope:

m = f'(x) = 4x³ at x = 5, then

m = 4(5)³ = 500Y-intercept:

b = f(x) - mx

= f(5) - m(5)

= 5⁴ - 500(5

)Thus, the equation of the tangent line is y = 500x - 9375.

Using this, we can approximate 4.84 as follows:

f(4.84) ≈ 500(4.84) - 9375

≈ 500(4.84) - 9375f(4.84)

≈ 717.2

Therefore, the approximation for 4.84 using linear approximation, i.e., the tangent line, is 717.2.

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Answer:

I = 1

Step-by-step explanation:

If the w has to be multiplied by one in order to be the same on the other side of the equation.

Answer:

Hello! I hope I’m correct!

Step-by-step explanation:

I think the answer should be: l = 1

First we should flip the equation.

And than divide both sides by w.

Therefore the answer would be:

i = 1

Hope this helps!

If you have any questions about this problem, feel free to ask them!

By: BrainlyAnime ^-^

To rewrite the linear system as a matrix equation, we can let y = [y1, y2, y3] and A be the coefficient matrix:

y' = Ay
where
A = [1 1 2; 1 0 1; 2 1 3]

To compute the eigenvalues of A, we can use the formula:
det(A - λI) = 0
where det represents the determinant and I is the identity matrix.

So, we have:
|1-λ 1 2|     |1 1-λ 2|     |1 1 1-λ|
|1 0-λ 1|  =  |1 0 1|  =  |1-λ 0 1|
|2 1 3-λ|     |2 1 3|     |2 1 3-λ|

Expanding the determinants, we get:
(1-λ)[(0-λ)(3-λ)-1]-1[(1)(3-λ)-2(1)]+2[(1)(1)-2(1-λ)]
= (λ-3)(λ-1)(λ-2) = 0

Therefore, the eigenvalues of A are 3, 1, and 2.

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Answer: 11,500 grams

Step-by-step explanation: 920/8=115 115*100= 11,500

Answer:

A polynomial is a combination of terms separated by

+

or

−

signs. A polynomial does not contain variables raised to negative or fractional exponents, variables in the denominator or under a radical, or any special features such as trigonometric functions, or logarithms.

Polynomial

Step-by-step explanation:

The generalized 9th degree polynomial is given below \(a_1x^9+a_2x^8+a_3x^7+a_4x^6+a_5x^5+a_6x^4+a_7x^3+a_8x^2+a_9x+a_{10}=0\) where \(a_1,a_2,....a_9\) are the coefficients and \(a_{10}\) is constant. The polynomial \(x^9\) is known as the nonic equation.

Given :

Polynomial  -- \(x^9\)

The following steps can be used in order to classify the given polynomial:

Step 1 - The generalized polynomial equation is given below:

\(a_1x+a_2x^2 + a_3x^3+a_4x^4+a_5x^5+.............+a_nx^n=0\)

where \(a_1,a_2,....,a_n\) are the coefficients.

Step 2 - The generalized quadratic equation is given below:

\(ax^2+bx+c=0\)

where a, b are the coefficients and c is the constant.

Step 3 - So the generalized 9th degree polynomial is given by:

\(a_1x^9+a_2x^8+a_3x^7+a_4x^6+a_5x^5+a_6x^4+a_7x^3+a_8x^2+a_9x+a_{10}=0\)

where \(a_1,a_2,....a_9\) are the coefficients and \(a_{10}\) is constant.

The polynomial \(x^9\) is known as the nonic equation.

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140,608 possible ways are there to draw a hand of 5 cards such that you draw 3 cards from one suit and 2 cards from another different suit.

In a standard deck of 52 playing cards, there are 13 cards in each of 4 suits: clubs, diamonds, hearts, and spades. To draw a hand of 5 cards such that you draw 3 cards from one suit and 2 cards from another distinct suit, you have several options for the suits you choose.

There are C(4,2) = 6 ways to choose 2 suits out of 4. Once you have chosen the suits, you have C(13,3) = 286 ways to choose 3 cards from one suit and C(13,2) = 78 ways to choose 2 cards from the other suit.

Therefore, the total number of ways to draw a hand of 5 cards such that you draw 3 cards from one suit and 2 cards from another distinct suit is 6 x 286 x 78 = 140,608.

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The two true statements are: b.) The value for the degrees of freedom for Mary's sample population is six, and e.) Mary would use the sample standard deviation to calculate a t-statistic.

a.) The t-distribution that Mary uses does not have skinnier tails than a standard distribution. In fact, the t-distribution has fatter tails, which accounts for the increased variability when working with small sample sizes.

b.) The degrees of freedom for Mary's sample population can be calculated as the number of subjects minus one, which in this case is 7 - 1 = 6. So statement b is true.

c.) The t-distribution that Mary uses is not taller than a standard distribution. The shape of the t-distribution is similar to the standard normal distribution, but it is slightly flatter.

d.) Mary would not use the population standard deviation to calculate a t-distribution. Instead, she would use the sample standard deviation, which provides an estimate of the population standard deviation.

e.) Mary would use the sample standard deviation to calculate a t-statistic. The t-statistic measures the difference between the sample mean and the hypothesized population mean, relative to the variability in the sample.

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Answer:

60

Step-by-step explanation:

Answer:

9.45

Step-by-step explanation:

Answer:

9.45 cm squared

Step-by-step explanation:

1.5 times 6.3

i hope you give me a brainliest!!<£

Answer:

138.80

Step-by-step explanation:

I took 149.99 times 15% then times that by the tax rate to get your final answer.

Answer:

Ok

Step-by-step explanation:

Answer:

2>-4

Step-by-step explanation:

The answer is D. positive numbers are always greater than negative numbers.

The linearized equation for the non-linear equation z = x² + 4xy + 6xy² in the region defined by 8 ≤ x ≤ 10, 2 ≤ y ≤ 4 is given by :

z ≈ 244 + 20(x - 8) + 128(y - 2).

When using the linearized equation to calculate the value of z at x = 8, y = 2, the error is 0.

1.1. To linearize the equation in the given region, we need to find the partial derivatives of z with respect to x and y:

∂z/∂x = 2x + 4y

∂z/∂y = 4x + 6xy

At the point (x₀, y₀) = (8, 2), we substitute these values:

∂z/∂x = 2(8) + 4(2) = 16 + 8 = 24

∂z/∂y = 4(8) + 6(8)(2) = 32 + 96 = 128

The linearized equation is given by:

z ≈ z₀ + ∂z/∂x * (x - x₀) + ∂z/∂y * (y - y₀)

Substituting the values, we get:

z ≈ z₀ + 24 * (x - 8) + 128 * (y - 2)

1.2. To find the error when using the linearized equation to calculate the value of z at x = 8, y = 2, we substitute these values:

z ≈ z₀ + 24 * (8 - 8) + 128 * (2 - 2)

= z₀

Therefore, the linearized equation gives the exact value of z at x = 8, y = 2, and the error is 0.

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Answer:

139 degrees

Step-by-step explanation:

the exact formula for X(n) is given by the sum of i from 1 to 4n + 1. The closed-form formula for X(n) is (4n + 1)(4n + 2)/2, expressed as a polynomial function. The asymptotic value of X(n) is approximately 4n^2, representing the growth rate as n approaches infinity.

(i) The exact formula for X(n) can be determined by analyzing the procedure PrintXs(n) and counting the number of times the letter "X" is printed. In this case, the outer loop runs for 4n + 1 iterations, and for each iteration, the inner loop runs i times. Thus, the total number of "X" letters printed is given by the sum of i from 1 to 4n + 1.

(ii) To express X(n) as a closed-form polynomial function, we can simplify the sum mentioned above. By using the formula for the sum of an arithmetic series, the closed-form formula for X(n) can be written as X(n) = (4n + 1)(4n + 2)/2.

(iii) The asymptotic value of X(n) can be expressed using the e-notation, which represents an estimate of the growth rate. In this case, as n approaches infinity, the dominant term in the expression (4n + 1)(4n + 2)/2 is 4n^2. Therefore, we can express the asymptotic value of X(n) as X(n) ~ 4n^2.

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Answer:

its blurry

Step-by-step explanation:

There is no tangent to the curve,  y = e2 In (x² +2) at the point where it crosses the x-axis.

To find the equation of the tangent to the curve, y = e^2ln(x² + 2) at the point where the curve crosses the x-axis, we need to first find the x-coordinate of that point.

Since the curve crosses the x-axis when y = 0, we can set y = 0 and solve for x:

0 = e^(2ln(x^2+2))

0 = ln(x^2+2)^2

ln(x^2+2) = 0

x^2+2 = e^0

x^2+2 = 1

x^2 = -1

The equation x^2 = -1 has no real solutions, so the curve does not cross the x-axis. Therefore, there is no tangent line to be found.

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Answer: 0.6 Liters of powdered milk can produce 60 cups of milk.

Explanation: 120 grams of powdered milk makes 12 cups of milk. 120 divided by 12 is 10. 60 times 10 is 600. So 600 grams of powdered milk to make 60 cups of milk. That is equal to 0.6 kilograms and that is equal to 0.6 liters.

Answer:

$54.01

Step-by-step explanation:

All you have to do is $300.00-$245.99 .

The answer is -178 :))))))))))))))))))))))))))

Answer:

This equation has 4 solutions, its real solutions are x = -1 and 3

Step-by-step explanation:

Correct for Plato Users

The equation has 4 solutions and its real solutions are 3, -1.

The given polynomial equation is 6(x - 3)(x² + 4)(x + 1) = 0.

A real solution in algebra is simply a solution to an equation that is a real number.

Now, 6(x - 3)(x² + 4)(x + 1) = 0

⇒(x - 3)(x² + 4)(x + 1) = 0

⇒(x - 3)=0, (x² + 4)=0 and (x + 1) = 0

⇒x=3, -1 and ±√-4.

Therefore, the equation has 4 solutions and its real solutions are 3, -1.

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The total cost of going to the carnival is $30. The independent variable is the carnival fee and the dependent is the cost of rides.

In any equation, the variables that represent the input and output are referred to as independent and dependent variables, respectively. An independent variable is the one for which we enter the values. The dependent variable is the one that reflects the output value. In mathematics, data techniques, and quantitative sciences, there are dependent and independent variables. Dependent variables are so named because, during an experiment, their values are examined under the presumption or requirement that they do, in fact, depend on other variables' values.

The cost of admission fee at the carnival = $9(independent variable)

Cost of each ride = $1.75

Let the number of rides = x (dependent variable)

The cost of 12 rides = 12 x

= 12( 1.75)
= $21

So, the cost to go to the carnival and 12 rides is

= $9+ $21

= $30

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Step-by-step explanation:

B=tan⁻¹(9÷22)

B=22.2

C=180-(97+22.2)

C= 180- 119.2

C= 60.8

Answer:

PLS SOMEONE ANSWER MY QUESTION

Step-by-step explanation:

So the convincing evidence that the radio station plays less than

\(50\ min\ of\ music\ per\ hour\). Here we have to see graph and chart.

Parameter of Interest, \(\mu = the\ true\ average\ number \ minutes\ of\ music \ played\ every \ hour.\)

Null Hypothesis,  \(H_{o} : \mu = 50\)

Alternative Hypothesis, \(H_{a} : \mu < 50\)

\(Conditions\ of\ test :\)

\(Random :\) A random sample of \(hours\) was selected.

\(Independent:\) There are more than \(10(12) = 120\ hours\) of music played during the week.

\(Normal:\) We do not know if the population distribution of the music  \(times\) is approximately Normal and we don’t have a large (big) sample size, so we will graph the data and look for any departures from Normality.

Level of Significance,  \(\alpha = 0.05\ Significance\ level\)

\(n = 12, df = 11, \bar x = 47.9, S_{x} = 2.81\)

1- var Stats:

\(\bar x= 47.9166\) , \(\Sigma\ x = 575\), \(\Sigma\ x^{2} = 27639\), \(Sx = 2.81096\), \(\sigma x = 2.69129\)

\(t = \frac{\bar x- \mu_{o}}{ \frac{S_{x} }{\sqrt{n} } }\)

\(t = \frac{47.9- 50}{ \frac{2.81 }{\sqrt{12} } }\)

\(= - 2.59\)

T test :

\(\mu < 50, t = -2.5674, p=.013, \bar x = 47.9166, S_{x} = 2.81, n = 12\)

P-value (Use correct probability notation.) \(P-value = P(t < -2.59) = 0.0126\)

Since the \(P-value(.013)\) is less than \(\alpha =.05\), we reject the null hypothesis.

There is convincing evidence(proof) that the radio station plays less than \(50\ min\ of\ music\ per\ hour\).

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Answer:

False

A square is a quadrilateral with four right angles, two sets of parallel lines, and equal sides.

A rectangle is not equilateral, so it is not a square. Squares are rectangles, actually.

So, False

Hope that helps!

Step-by-step explanation:

Answer:

False, but can be true

Step-by-step explanation:

Rule for being a square.

1. All sides have to be congruent in length

2. Must have all 90°

3. has 4 sides and 4 angles (has to be a quadrilateral)

4. 2 pairs of parallel lines

A rectangle is not a square directly. It does not have congruent sides. Although, this means that a square is a specialized case of the rectangle. It will only be a square if all sides are congruent.

Besides x=-3+i , 3 - i, 1/2 is another zero for polynomial equation 4x3 + 23 x2 + 34 x - 10

Given that x = −3 + i is a zero of the polynomial 4x³ + 23x² + 34x - 10, we have to find the other zeros.

We know that when x = −3 + i is a zero of the polynomial 4x³ + 23x² + 34x - 10, then x - (-3 + i) is a factor of 4x³ + 23x² + 34x - 10.

To find other zeros, we will use synthetic division;

(−3 + i) ║ 4 23 34 -10 ║

To obtain a zero, we can use this formula:

(−b ± √(b² − 4ac))/2a

where a = 4, b = 34, and c = -10.

We have: (−b ± √(b² − 4ac))/2a

=(-34 ± √(34² - 4*4*(-10)))/(2*4)

=(-34 ± √(1332))/8= (-34 ± 6√(37))/8

=(17 ± 3√(37))/4

Therefore, the other zeros of the polynomial are (17 + 3√(37))/4 and (17 - 3√(37))/4.

Hence, the correct option is (A) 3 - i, 1/2.

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The height of a randomly selected giraffe, the number of points scored during a basketball game, the gender of college students, the amount of rain in City Upper B during April, and the number of fish caught during a fishing tournament are all examples of discrete or continuous random variables, while the number of bald eagles in a country is not a random variable.

a. Continuous random variable

b. Discrete random variable

c. Discrete random variable

d. Continuous random variable

e. Discrete random variable

f. Not a random variable

a. The height of a randomly selected giraffe is a continuous random variable because it can take on any value within a certain range.

b. The number of points scored during a basketball game is a discrete random variable because it is a countable number.

c. The gender of college students is a discrete random variable because it is a categorical variable with two possible values.

d. The amount of rain in City Upper B during April is a continuous random variable because it can take on any value within a certain range.

e. The number of amount fish caught during a fishing tournament is a discrete random variable because it is a countable number.

f. The number of bald eagles in a country is not a random variable because it is a fixed number and not a random sample.

The height of a randomly selected giraffe, the number of points scored during a basketball game, the gender of college students, the amount of rain in City Upper B during April, and the number of fish caught during a fishing tournament are all examples of discrete or continuous random variables, while the number of bald eagles in a country is not a random variable.

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