4. What kept the concept of continental drift from originally being

accepted?

The reaction which displays an example of an arrhenius base is

NaOH(s) → Na⁺(aq) + OH⁻(aq).

According to the Arrhenius theory, those substance which gives H⁺ ion to the aqueous solution is acid and which gives OH⁻ ion to the aqueous solution is known as base.

All given chemical reactions will display an arrhenius acid, but only one reaction display as a arrhenius base as they gives OH⁻ ion to the aqueous solution and that reaction will be:
NaOH(s) → Na⁺(aq) + OH⁻(aq)

Hence option (1) is correct.

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Answer:

A: NaOH(s) ---> Na+(aq) + OH–(aq)

Explanation:

= 18.02 g/mol) im sure its that

The long-chain molecules that consist of many repeating units are called polymers. Polymers are large macromolecules composed of monomer units that are chemically bonded together in a repetitive pattern.

The repeating units, also known as monomers, are linked through covalent bonds, creating a chain-like structure.

Polymers can have various sizes and complexity, ranging from simple structures like polyethylene to highly intricate and specialized macromolecules like proteins and DNA.

It is noticed that due to their repeating nature, polymers often possess unique physical and chemical properties, making them useful in a wide range of applications, including plastics, textiles, adhesives, and biomedical materials.

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Answer:

Acetyl CoA

Explanation:

The pyruvate molecules undergo reactions that convert the three carbon pyruvate to a two carbon acetyl CoA and an one carbon carbon dioxide. The acetyl-CoA molecules are then used as the initial inputs for the citric acid cycle, as they are combined with oxaloacetate.

Answer:what are u asking to do?

Explanation:

Explanation:

Since the oxidation state of Mg is changed to +2 from 0, it is oxidized. (as it is increased)

Similarly, oxidation state of Cu is changed to 0 from +2, it is reduced. (as it is decreased)

Since oxidation & reduction occur at the same time, it is redox reaction.

As Mg is being oxidized, other one must be the oxidizing agent.

Cu is the oxidizing agent

Answer:

Its electrical charge is -2.

Answer:

1.00310 rounded up to it's nearest is the equivalent to 1.0031. hence

c. 8.66

Answer:

go for what ever brother GUESS / imagine this gate brainlyist for literally doing nothing.

Explanation:

The nucleus of 1H is made up of a single proton and therefore has a relative mass loss of 0 g/mol. The deuterium isotope, 2H, on the other hand, has a relative mass loss of 2.014 g/mol. The mass number of 2H is two, indicating that it has one neutron and one proton in its nucleus. Let's look at some additional detail about isotopes: A given element has the same number of protons, but it can have different numbers of neutrons in its nucleus.

A different isotope of the same element is formed by adding or subtracting neutrons from the nucleus. Isotopes of the same element have the same number of protons but a different number of neutrons. The atomic mass of an element is calculated by summing the number of protons and neutrons in the nucleus. The atomic mass unit (amu) is the unit used to calculate atomic mass. In conclusion, The relative atomic mass of 2H is 2.014 g/mol, which is a loss of 0.014 g/mol relative to the mass of 2 protons. The relative mass loss of deuterium, 2H, is 0.014 g/mol.

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Answer:

386.66 g/mol  

Explanation:

To calculate the molar mass of a molecule, you add up the molar masses of its atoms.

Thus, for cholesterol. we get

27C = 27 × 12.011  =  324.297 g

46H = 46 ×   1.008 =    46.368

 1O =    1 × 15.999 =   15.999

                TOTAL = 386.655  g

To two decimal places, the molar mass of cholesterol is 386.66 g/mol

For a certain brand of gasoline, which has a density of 0.733 g/mL at 25 oC, 41848 grammes would fill a 10.7 gal tank. Mass in relation to volume is referred to as density.

Although the Latin letter D can also be used, the symbol for density is most frequently written as (the lower case Greek letter rho). Any combination of gases can be considered a gas gas solution. As a result of their great distance from one another, gas molecules typically only interact very little. All gases can therefore be thought of as being soluble in one another.

15x 3785.41 ml = 56781.15 ml. Consequently, the mass is calculated as 0.737g/ml x 56781.15 ml = 41848 grammes.

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Answer:

D.

Explanation:

The electron cloud has negligible mass. Most mass come from the nucleus.

A 30-day supply of Levoxyl at a dosage of one 13 μg tablet per day contains 0.39 mg of Levoxyl.

For a patient taking one 13 μg tablet of Levoxyl per day, the total amount of levothyroxine they are receiving is 13 micrograms. To calculate the total amount in a 30-day supply, we simply multiply this amount by 30.

13 μg/tablet x 1 tablet/day x 30 days = 390 μg

Note that the microgram (μg) is a unit of mass equal to one millionth of a gram, while the milligram (mg) is a unit of mass equal to one thousandth of a gram. To convert μg to mg, we divide by 1000:

390 μg / 1000 = 0.39 mg

Levoxyl is a medication used to treat hypothyroidism, a condition where the thyroid gland doesn't produce enough hormones to regulate the body's metabolism. The active ingredient in Levoxyl is levothyroxine sodium, which is a synthetic form of the hormone thyroxine (T4).

Levoxyl tablets are available in several strengths, ranging from 25 mcg to 300 mcg. The recommended dosage depends on the patient's age, weight, and the severity of their hypothyroidism. In general, adults with normal thyroid function usually require about 1.6 mcg of levothyroxine per kilogram of body weight per day.

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Answer:

2a. 0.401 moles de O2

b. 127.7g KClO3

c. 43.95g KCl

3. 9600g Ag2CO3 debieron haberse descompuesto

Explanation:

Basados en la reaccion:

2KCIO 3 (s) → 2KCI(s) + 3O 2

2 moles de KClO3 producen 3 moles de oxígeno:

a. 32.8g de KClO3 son:

Moles KClO3 -Masa molar: 122.55g/mol-

32.8g * (1mol / 122.55g) = 0.2676 moles KClO3

Moles O2:

0.2676 moles KClO3 * (3moles O2 / 2mol KClO3) =

0.401 moles de O2

b. 50g O2 son:

Moles O2 -Masa molar: 32g/mol-

50g O2 * (1mol/32g) = 1.5625 moles O2

Moles KClO3:

1.5625 moles O2 * (2mol KClO3 / 3mol O2) = 1.042 moles KClO3

Masa KClO3:

1.042 moles KClO3 * (122.55g/mol) =

127.7g KClO3

c. Las moles de O2 son:

28.3g O2 * (1mol / 32g) = 0.88 moles O2

Moles KCl:

0.88 moles O2 * (2mol KCl / 3mol O2) = 0.5896 moles KCl

Masa KCl -Masa molar: 74.55g/mol-

0.5896 moles KCl * (74,55g/mol) = 43.95g KCl

3. Basados en la reacción:

2Ag 2 CO 3 → 4Ag(s) + 2CO 2 (g) + O 2 (g)?

2 moles de Ag2CO3 reaccionan produciendo 4 moles de Ag. Las moles de Ag son:

Moles Ag -Masa molar: 107.8682g/mol-

7511g Ag * (1mol/107.8682g) = 69.63 moles Ag

Moles Ag2CO3:

69.63 moles Ag * (2moles Ag2CO3/4molesAg) = 34.82 moles Ag2CO3

Masa Ag2CO3-Masa molar: 275.7453g/mol-

34.82 moles Ag2CO3 * (275.7453g/mol) =

9600g Ag2CO3 debieron haberse descompuesto

The pH values after the given volumes of acid have been added are: a) 12.18, b) 12.39, c) 11.78, d) 11.25, and e) 10.79.To solve the problem, we need to use the balanced chemical equation for the reaction between KOH and HClO4:

KOH + HClO4 -> KClO4 + H2O

At the start of the titration, before any HClO4 has been added, we have a solution of KOH with a concentration of 0.150 M. We can use this concentration to calculate the initial concentration of hydroxide ions in the solution:

[OH-] = 0.150 M

a) Before any HClO4 has been added, the volume of the solution is 20.0 mL. At this point, no HClO4 has reacted with the KOH, so the concentration of OH- ions is still 0.150 M.

To calculate the pH, we can use the formula for the dissociation constant of water:

Kw = [H+][OH-] = 1.0 x 10^-14

pH = -log[H+]

[H+] = Kw/[OH-] = 6.67 x 10^-13 M

pH = -log(6.67 x 10^-13) = 12.18

b) After 1.5 mL of HClO4 has been added, the volume of the solution is 21.5 mL. The moles of HClO4 added is:

0.125 mol/L x 0.0015 L = 1.875 x 10^-5 mol

The moles of KOH initially in the solution is:

0.150 mol/L x 0.020 L = 0.003 mol

Thus, the moles of KOH remaining after reaction with HClO4 is:

0.003 mol - 1.875 x 10^-5 mol = 0.00298125 mol

The total volume of the solution is 21.5 mL, so the new concentration of KOH is:

0.00298125 mol / 0.0215 L = 0.1387 M

Using this concentration, we can calculate the concentration of OH- ions:[OH-] = 0.1387 M

Using the same formula for Kw and pH as before, we find that:

[H+] = 4.06 x 10^-13 M

pH = -log(4.06 x 10^-13) = 12.39

c) Repeating the above process for a volume of 24.0 mL gives:

[H+] = 1.64 x 10^-12 M

pH = -log(1.64 x 10^-12) = 11.78

d) For a volume of 26.5 mL:

[H+] = 5.67 x 10^-12 M

pH = -log(5.67 x 10^-12) = 11.25

e) For a volume of 29.0 mL:

[H+] = 1.63 x 10^-11 M

pH = -log(1.63 x 10^-11) = 10.79

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There are seven types of hydrophobic amino acids present which are- Alanine, Valine, Leucine, Isoleucine, Methionine, Phenylalanine and Tryptophan. There are total 20 known amino acids present in nature.

The seven hydrophobic amino acids are:

1. Alanine (Ala)

2. Valine (Val)

3. Leucine (Leu)

4. Isoleucine (Ile)

5. Methionine (Met)

6. Phenylalanine (Phe)

7. Tryptophan (Trp)

These amino acids have nonpolar, hydrophobic side chains, which means they tend to avoid contact with water and instead tend to associate with each other or with other hydrophobic molecules. This makes them important for forming the hydrophobic core of proteins, where they can help stabilize the protein structure.

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Answer:

the I really don't know sorry:(

The alkane with the molecular formula C10H16 has one ring. This ring structure reduces the number of hydrogen atoms by two compared to the corresponding straight-chain alkane.

To determine the number of rings in an alkane with the formula C10H16, we can compare it to the corresponding straight-chain alkane, which would be C10H22. Since the alkane C10H16 has 2 fewer hydrogen atoms than its straight-chain counterpart, it suggests the presence of one ring in the molecule.

The molecular formula of an alkane provides information about the number of carbon and hydrogen atoms in its structure. In the given formula C10H16, the presence of 10 carbon atoms indicates that it forms a chain of carbon atoms. However, since it has 16 hydrogen atoms, which is 2 fewer than the maximum number of hydrogen atoms possible for a straight-chain alkane with 10 carbon atoms, there must be a structural deviation. The deviation in the number of hydrogen atoms suggests the formation of one ring in the molecule. Each carbon atom in the ring contributes two hydrogen atoms, whereas in a straight-chain alkane, each carbon atom is bonded to three hydrogen atoms. By forming a ring, two of the carbon atoms in the chain lose one hydrogen atom each, resulting in a net loss of two hydrogen atoms.

Therefore, the alkane with the molecular formula C10H16 has one ring. This ring structure reduces the number of hydrogen atoms by two compared to the corresponding straight-chain alkane. It is important to note that the specific arrangement of the carbon atoms in the ring and their connectivity would determine the isomeric form of the molecule.

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Answer:

it's thermal energy

Explanation:

There are five types of kinetic energy: radiant, thermal, sound, electrical and mechanical.

#carry on learning

Hope it helps

In this exercise we have to use the knowledge of kinetic energy and we can also describe it as a thermal energy.

Kinetic energy is a type of energy that is related to the movement of bodies. The result of kinetic energy is intrinsically linked to the value of the object's mass and its speed of movement.

Kinetic energy does not depend exclusively on the speed of a body but also on its mass. Any type of body in motion is endowed with this type of energy: translation, rotation, vibration and others.

With these definitions we can write that it will be the same as saying that kinetic energy can be transformed into thermal energy.

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The equilibrium constant for the reaction 2SO2(g) + O2(g) → 2SO3(g) is Kc = 0.113.

This value is determined using the reaction quotient equation, which calculates the ratio of product concentrations to reactant concentrations at equilibrium.

The number of significant digits in the equilibrium constant is dependent on the number of significant digits in the concentrations of the reactants and products.

In this case, the concentration for each reactant and product is only known to two significant digits, so the equilibrium constant is also only known to two significant digits. As a result, the equilibrium constant for this reaction is Kc = 0.113.

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Answer:

The elements are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), radon (Rn), and oganesson (Og).

Explanation:

Bohr's model lacked orbitals again for electrons or the electron cloud, contrary to Dalton's theory, which was founded on the idea that every element is made up of its own distinct variety of an indivisible atom.

According to the theory, an atom contains a small, dense, positive charge centre known as the nucleus, where practically every bit of mass was concentrated. Light, particles with negative charges called electrons then orbit far from the nucleus in a manner similar to how planets circle the Sun.

Dalton proposed his atomic hypothesis based on all of his observations. It's frequently called the billiards ball model. Due to the lack of understanding of the atomic electrons and the nucleus at the time, he described an atom as a ball-like structure.

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Answer:

B.)Schrodinger's model

Explanation:

The hybridization expect for Carbon in ethyne (C₂H₂) is sp atomic orbital hybridization.

In ethyne (C₂H₂), each carbon atom forms two sigma bonds and two pi bonds. The sigma bonds are formed by the overlap of hybrid orbitals, while the pi bonds are formed by the overlap of unhybridized p orbitals.

In its ground state, carbon has the electronic configuration 1s² 2s² 2p². To form bonds, carbon undergoes hybridization, where its valence electrons are rearranged into hybrid orbitals.

In ethyne, each carbon atom forms two sigma bonds: one sigma bond with another carbon atom and one sigma bond with a hydrogen atom. To accommodate these bonds, carbon undergoes sp hybridization, where one 2s orbital and one 2p orbital combine to form two sp hybrid orbitals.

The hybridization process involves the promotion of one electron from the 2s orbital to an empty 2p orbital. The resulting configuration for each carbon atom is two half-filled sp hybrid orbitals and two unhybridized 2p orbitals. The two sp hybrid orbitals point in opposite directions, creating a linear arrangement.

The two carbon atoms in ethyne then overlap their sp hybrid orbitals to form a sigma bond. Additionally, the unhybridized 2p orbitals on each carbon atom overlap sideways to form two pi bonds. These pi bonds involve the sideways overlap of parallel p orbitals, resulting in the formation of a pi bond above and below the molecular plane.

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Answer: 1: The weight is the total amount of force that is  required to accelerate any object with its mass. Whereas, the mass is the actual amount/ numerical measurement of the weight that the object has in it. And the volume is basically the 3D space an object occupies around itself.

2: The three ways of determining volume of an object are as follows:

a) Make the use of space : Measuring the physical dimensions of different quantities.

b) Use of Density and Mass: The formula; Volume= Mass/Density

c) Use the Displacement value: Measure the volume of the object  which is displaced as soon as the object gets immersed in any gas or liquid.

Explanation:

Answer:

volume= 3

Explanation:

D=m/v

2.7=8.1/v

2.7v=8.1

8.1/2.7= 3

8.1/3= 2.7 which is the density!

Answer:

3 mL

Explanation:

\(V = \frac{8.1 g}{3 mL} = 2.7 g/mL\)

Answer:

Explanation:

The Tacoma Narrows Bridge is the historical name given to the twin suspension bridge—originally built in 1940—that spanned the Tacoma Narrows strait. It collapsed just four months later due to aeroelastic flutter. Since then, this topic has become popular, with several case studies discussing the failure phenomenon of suspension cable bridges.

In the state of Washington, the construction of the Tacoma Narrows Bridge was completed and opened to the traffic on July 1st, 1940. It was the very first bridge to incorporate a series of plate girders as roadbed support, and the first bridge of its type (cable suspension). It was also the third largest suspension bridge of its time, with a 2800-foot central span and two side spans of 1100 feet each.

A west-side approach had a continuous steel girder of 450ft, while the east side had a long reinforced concrete frame of 210ft.  It had two cable anchorages of 26ft. along roadways, two 5ft. sidewalks and two 8ft. deep stiffening girders. Among several other structural details, the suspension cable anchorages to which the cables were connected were made of 20,000 cubic yards of concrete, 6 lakh pounds of structural steel, and 2.7 lakh pounds of reinforcing steel. Because of its extremely long length, it was considered a ‘narrow bridge’. The overall construction cost was estimated to be a whopping $6 Million in 1940. Considering inflation, this is equivalent to almost $1 Billion, and all of this for something that lasted just four months and seven days. Yet, this remains a great engineering feature for civil engineers to ponder over.

Answer:

The mass of one mole of a substance is equal to that substance's molecular weight. ... water is 18.015 atomic mass units (amu), so one mole of water weight 18.015 grams. ... Avogadro's number is a proportion that relates molar mass on an atomic ... one molecule of water (H2O), one mole of oxygen (6.022×1023 of O atoms)

Answer:

The pH scale measures acidity of a substance. known as potential of hydrogen, it varies from 0 to 14 with 7 being the pH value of a neutral solution. Below 7 shows the substance is acidic in nature and above 7 is alkaline in nature. pH 0-3 are considered strong acids while pH 4-6 are weak acids. pH 8-10 are weak alkalines and pH 11-14 are strong alkalines. This is a general trend and there may be exeptions especially if the substance has a negative pH. However, it would not be covered likely unless you are doing university chemistry.