4. What is the amplitude of the waves shown in the diagram below?

4. What Is The Amplitude Of The Waves Shown In The Diagram Below?

Answers

Answer 1

Answer:

7.5 m

Explanation:


Related Questions

How fast does a 500kg car need to drive to have 100,000 J of kinetic energy?

Answers

Answer:

The car must move at 2 m/s to have a Ke of 2,000 Joules.

Explanation:

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An ideal gas at temperature To is slowly compressed at constant pressure of 2 atm from a volume of 10 liters to a volume of 2 liters. Then the volume of the gas is held constant while heat is added, raising the gas temperature back to To. Calculate the work done ON the gas. 1 atm = 1.0x 105 Pascals and 1 liter = 0.001 m³.

1. -800 J
2. -400 J
3. +800 J
4. +400 J
5. +1600 J
6. -1600 J


Calculate the heat flow INTO the gas

1. +1600 J
2. -400 J
3. -800 J
4. +400 J
5. +800 J
6. -1600 J​

Answers

Work done on the gas = -1600 J, and Heat flow into the gas = -1600 J . The correct option for both questions is (option 6).

To solve this problem, we can use the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system:

ΔU = Q - W

where ΔU is the change in internal energy, Q is the heat added to the system, and W is the work done by the system. Since the volume of the gas is held constant during the second part of the process, no work is done on or by the gas, so W = 0.

For the first part of the process, the pressure is constant, so we can use the equation:

W = PΔV

where P is the pressure, and ΔV is the change in volume. We can convert the volumes to cubic meters, and the pressure to Pascals:

P = 2 atm = 2 x 1.0 x 10^5 Pa

V1 = 10 L = 0.01 m³

V2 = 2 L = 0.002 m³

ΔV = V2 - V1 = -0.008 m³ (since the gas is being compressed)

W = PΔV = (2 x 1.0 x 10^5 Pa) x (-0.008 m³) = -1600 J

So, the work done on the gas during the compression is -1600 J.

To find the heat flow into the gas during the second part of the process, we can use the equation:

ΔU = Q - W

Since the internal energy of an ideal gas depends only on its temperature, and the temperature is the same at the beginning and end of the process, ΔU = 0. Therefore:

0 = Q - W

Q = W = -1600 J

So, the heat flow into the gas during the second part of the process is -1600 J.

Therefore, the answers to the questions are Work done on the gas = -1600 J (option 6), and Heat flow into the gas = -1600 J (option 6).

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A spinning ice skater can increase his rate of rotation by bringing his arms and free leg closer to his body. How does this procedure affect the skater's angular momentum and kinetic energy?
A
angular momentum remains the same while kinetic energy increases
B
angular momentum remains the same while kinetic energy decreases
C
both angular momentum and kinetic energy remains the same
D
angular momentum increases while kinetic energy remains the same

Answers

The answers B angular

Microbial food infections are usually not seen until ______ after eating contaminated food.

Answers

Answer:

2 to 4 hours

Explanation:

Given that,

Microbial food infections

We know that,

Food infection :

When we eat old food, uncooked, fermented food, more junk food and contaminated food then 2 to 4 hours after eating we started vomiting, headache then we affected by food infections.

So, we can say that microbial food infections are usually not seen until 2 to 4 hours after eating contaminated food.

A 600 kg vehicle has an engine that is exerting 7000 N of force. Assuming a drag force of 500 N what is the vehicle's acceleration ?

Answers

Answer:

Mass of Vehicle = 600 kg

Force = F = 7000 N

Drag force = f = 500 N

Let Fnet is net force on Vehicle then

Fnet = F - f

Fnet = 7000 - 500

Fnet = 6500 N

Let a is acceleration of Vehicle then by Newton's law

Fnet = Ma

a = Fnet / M

a = 6500/ 600

a = 10.83 m/s2

This is acceleration of Vehicle

Explanation:

Show all work and answer all 4 parts. Projectile motion. 20 points. Thank you.

Show all work and answer all 4 parts. Projectile motion. 20 points. Thank you.

Answers

Answer:

(i have corrected the answers to 3 significant figures)

When dealing with projectile motion, we should consider its vertical and horizontal components.

Vertical velocity = 50sin60° m/s

Horizontal velocity = 50cos60° m/s

a) when it reaches the peak, meaning it can no longer travel further upwards, indicating the final vertical velocity is 0.

Take g=9.80665

using formula a = (v-u) /t

9.80665= (0-50sin60°) / t

t= 4.42 s

b) Consider the vertical component.

using formula t = 2u / g

t = 2(50sin60°) / 9.80665

t = 8.83s

c) Consider the vertical component again,

using formula H = u² / 2g

H = (50sin60°)² / 2(9.80665)

H = 95.6m

d) This is also the range of the projectile motion.

Using formula R = u²sin2θ / g

This time u should just be the initial velocity (neither horizontal/vertical)

R = 50²sin2(60) / 9.80665

= 221 m

- you can also do this by using s = ut formula, using the time calculated from b), but consider the u as the horizontal component.

What is the vector sum of (7,5) and (13,-5)?

Answers

To add or subtract two vectors, just add or subtract the corresponding components. This is:

(7, 5) + (13, -5) = (7+13 , 5-5) = (20, 0)

A 5 kg mass compresses a horizontal spring by .06 meters. The spring has a spring constant of 2 N/m. If the surface is frictionless, find the velocity of the mass when the spring is released.

Answers

Answer:

Explanation:

The frictionless surface implies that the speed of the spring is at a max. When the speed of the spring is at its max, the potential energy in the spring is 0. Use the equation for the Total Energy in a Spring/Mass System:

KE + PE = \(\frac{1}{2}kA^2\) where KE is the Kinetic Energy available to the spring, PE is the potential energy available to the spring, and the sum of those is equal to one-half times the spring constant, k, times the amplitude of the spring's movement away from the equilibrium position. Sometimes this amplitude is the same as the displacement of the spring. This can be tricky. But since we are only given one value for the distance, we are going to use it as an amplitude. Keeping in mind that the PE is 0 when KE is at its max, then the equation becomes

KE + 0 = \(\frac{1}{2}kA^2\) or to put it simpler terms:

KE = \(\frac{1}{2}kA^2\) We need to find the value for KE before we can fully solve the problem we are being tasked with.

Filling in using the info given:

\(KE=\frac{1}{2}(2.0)(.06)^2\) Notice I added another place of significance to the 2 because 1 simply isn't enough and the physics teacher in me can't handle that. Simplifying a bit:

\(KE=(.06)^2\) because the k = 2 cancels out the 2 in the denominator of the 1/2. So

KE = 3.6 × \(10^{-3\)

Now plug that in for KE and solve for v:

KE = \(\frac{1}{2}mv^2\):

\(3.6*10^{-3}=\frac{1}{2}(5.0)v^2\) and

\(v=\sqrt{\frac{2(3.6*10^{-3})}{5.0} }\) gives us a velocity of

v= \(3.8*10^{-2\)

A box is being pulled to the right. The free body diagram is shown.What is the magnitude of the kinetic frictional force?

Answers

Answer:

A - 0 N

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A 1,160 kg satellite orbits earth with a tangential speed of 7,446 m/s. if the satellite experiences a centripetal force of 8,955 n, what is the height of the satellite above the surface of earth? recall that earth’s radius is 6.38 × 106 m and earth’s mass is 5.97 × 1024 kg. 3.71 × 1028 m 8.02 × 105 m 7.20 × 105 m 9.67 × 1028 m

Answers

The satellite is 8.02 × 10⁵ m above Earth's surface.

Let H be the height above the surface of the Earth; since we know that the satellite is rotating around the Earth due to the gravitational pull of the planet, we may assert

Procedure to solve:

F = mv²/R+H

H = mv²/F - R

H = (1160 × 7446²/8955 - 6.38 × 10⁶)

M = 8.02 × 10⁵ m

About centripetal force:

The force applied to an item that is in velocity of  curved motion that is pointed toward the axis of rotation or the centre of curvature is known as a centripetal force.

The centripetal force formula is given as the product of mass (in kg) and tangential velocity (in meters per second) squared, divided by the radius (in meters) that implies that on doubling the tangential velocity, the centripetal force will be quadrupled. Mathematically it is written as:

F = mv²/r

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Answer:

8.02x 10^5 m

Explanation:

quiz

4.The compressed spring in the figure is released from rest on a level, frictionless surface. Thespring, which has negligible mass, is not fastened to either block, and drops to the surface after ithas expanded. Block B acquires a speed of 1.2 m/s. How much potential energy is stored in thecompressed spring?A. 10.45B. 6.34C. 8.64D. 15.0

4.The compressed spring in the figure is released from rest on a level, frictionless surface. Thespring,

Answers

The momentum of the blocks must be preserved, therefore, we have the following relationship:

\(P_{A1}+P_{B1}=P_{A2}+P_{B2}_{}\)

Where PA1 and PB1 are the initial momentum of the blocks and PB2, PA2 are the momentum of the blocks after release. Since the system is initially at rest this means that the initial momentum is zero:

\(0=P_{A2}+P_{B2}\)

Replacing the definition of momentum:

\(P=mv\)

Where "m" is the mass and "v" the velocity, we get:

\(0=m_Av_A+m_Bv_B\)

Form this we can solve for the velocity of block A:

\(\begin{gathered} -m_Av_A=m_Bv_B_{} \\ v_A=-\frac{m_Bv_B}{m_A} \end{gathered}\)

Replacing the values:

\(v_A=-\frac{(3\operatorname{kg})(1.2\text{ m/s)}}{1\operatorname{kg}}\)

Solving the operations:

\(v_A=-3.6\text{ m/s}\)

The negative sign means that the block moves in the opposite direction to block B.

Now, since the spring drops, this means that it transfers all of its kinetic energy to the blocks, therefore, the initial energy of the spring must be equal to the sum of the kinetic energies of the blocks. This means:

\(U_s=k_A+k_B\)

Using the formula for kinetic energy:

\(k=\frac{1}{2}mv^2\)

Replacing we get:

\(U_s=\frac{1}{2}m_Av^2_A+\frac{1}{2}m_Bv^2_B_{}\)

Replacing the values:

\(U_s=\frac{1}{2}(1\operatorname{kg})(3.6\frac{m}{s})^2+\frac{1}{2}(3\operatorname{kg})(1.2\frac{m}{s})^2\)

Solving the operations we get:

\(U_s=8.64J\)

Therefore, the energy of the spring was 8.64 Joules.

what has mass and occupies space? volume matter energy density

Answers

Matter has mass and occupies space so the correct option form the above  is Matter.

Quarks and leptons, which are both regarded as elementary particles because they are not formed of smaller units of matter, are the building blocks of matter. Protons and neutrons are formed through the interaction of quarks, which are groupings of subatomic particles. Leptons, which are collections of subatomic particles that react to weaker forces, are among the elementary particles in the same category as electrons.

The building blocks of matter are called atoms. A molecule is created from a group of atoms. The bulk matter of everyday existence in the physical universe is made up of large clusters of atoms and molecules. The periodic chart lists more than 100 different types of atoms, each of which represents a different chemical element.

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If you increase the frequency of a sound wave four times, what will happen to its speed?
O A.
The speed will increase four times.
О В.
The speed will decrease four times.
OC. The speed will remain the same.
D.
The speed will increase twice.
O E.
The speed will decrease twice.

Answers

If you increase the frequency of a sound wave four times, the speed will increase four times. The correct option is A.

What are sound waves?

Particles that are vibrating make up sound waves. These collide with other particles, causing them to vibrate, which allows the sound to escape the source.

Your ear drums vibrate as a result of air vibrations, which allows you to perceive sound. This vibration is transformed into messages, which proceed to your brain via a nerve.

When sound is produced, air molecules shake and collide, causing vibrations to travel between air molecules. The sound is transmitted by the vibrating particles, which also cause the ear drum to vibrate.

A sound wave's frequency can be increased four times without increasing its speed.

Thus, the correct option is A.

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a child stands in the middle of a merry-go-round that is rotating with constant angular velocity. (it has been given a push and is now rotating freely.) she now walks to the edge of the merry-go-round. is mechanical energy (in this case, kinetic energy) of the child/merry-go-round system conserved (i.e. constant) during the process?

Answers

The mechanical energy of the child/merry-go-round system is conserved during the process of the child walking to the edge of the merry-go-round.

The mechanical energy of a system is conserved when there is no net external work done on the system. In this case, the only external force acting on the child/merry-go-round system is friction between the merry-go-round and the ground, which does work to slow down the system over time.

However, this force is not doing work on the system while the child is walking to the edge of the merry-go-round because the force is perpendicular to the displacement of the child. Therefore, the kinetic energy of the system remains constant as the child walks to the edge of the merry-go-round, and the mechanical energy of the system is conserved.

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which is greater? the annual energy usage of the earth, or the energy released by the sun in 1 second?

Answers

The energy released by the sun in one second, also known as the solar luminosity, is much greater than the annual energy usage of the earth.

The solar luminosity is estimated to be about 3.8 x 10^26 watts, while the total energy usage of the earth is estimated to be around 157,481 terawatt-hours per year, or about 18 x 10^12 watts. This means that the energy released by the sun in just one second is many orders of magnitude greater than the total energy used by all human activities on earth in a year. The sun's enormous energy output is what drives most of the physical and biological processes on our planet.

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Kirchhoff's current law states that the current arriving at any junction point in a circuit is equal to the current leaving that junction O True O False

Answers

The answer is True. The conservation of charge, or Kirchhoff's current law, stipulates that the total current entering and leaving a junction in an electrical circuit must equal each other.

Kirchhoff's current law asserts that the algebraic sum of currents at any junction point (or node) in an electrical circuit is always zero, often known as the junction rule or the first law. This law is founded on the idea that charge cannot be created or destroyed, which is known as the conservation of charge. Any current that enters a junction must therefore be balanced by an equivalent current that exits the junction. By using current relationships at various nodes, this law serves as the basis for understanding and resolving complex electrical circuits. It is a cornerstone of circuit analysis and is frequently applied in physics and electrical engineering.

The algebraic sum of currents entering every junction point (or node) in an electrical circuit must match the algebraic sum of currents exiting that junction, according to Kirchhoff's current law, sometimes referred to as the junction rule or Kirchhoff's first law. Alternatively said, the total current entering a node equals the total current leaving it. This law is based on the concept of conservation of charge, which holds that electric charge can only be moved from one place to another and cannot be created or destroyed. The entire amount of charge entering a junction must match the total amount of charge exiting that junction since electrons carry charge through a circuit.

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Suppose the peak of a particular star's spectrum occurs at 6000 A (1 A = 10-10 m).
a. Use Wien's law to calculate the star's surface temperature.
b. If this star were a factor of four hotter, at what wavelength would its spectrum peak?
In what part of the electromagnetic spectrum is this peak?

Answers

a. The surface temperature of the star is 4830 K.

b. The peak of the star's spectrum occurs at a wavelength of 1500 A. The wavelength falls within the ultraviolet range of the electromagnetic spectrum.

a. According to Wien's law, the peak wavelength (λ) of radiation emitted by a blackbody is inversely proportional to the temperature (T) of the blackbody. The mathematical formula is:λmaxT = 2.898 × 10-3 m K

Here, λmax = 6000 A = 6000 × 10-10 m = 6 × 10-7 mT

herefore, T = 2.898 × 10-3 m K / 6 × 10-7 m = 4830 K.

So, the surface temperature of the star is 4830 K.

b. According to Wien's law, the peak wavelength of radiation emitted by a blackbody is inversely proportional to the temperature of the blackbody. This means that when the temperature of the blackbody is increased, the peak wavelength will decrease.

In this case, if the temperature of the star were four times higher, its surface temperature would be T = 4 × 4830 K = 19320 K.

The peak wavelength of the star can be calculated using Wien's law, λmaxT = 2.898 × 10-3 m Kλmax = (2.898 × 10-3 m K) / 19320 Kλmax = 1.5 × 10-7 m = 1500 A.

The peak of the star's spectrum occurs at a wavelength of 1500 A. The wavelength falls within the ultraviolet range of the electromagnetic spectrum.

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The fracture strength of bi-tempered glass averages 14.03 (measured in thousands of pounds per square inch) and has standard deviation 2. Suppos randomly select 100 pieces of bi-tempered glass. Let M be the random variable representing the mean fracture strength of the 100 selected pieces. be the random variable representing the sum of the fracture strengths of the 100 selected pieces.
a) What theorem will let us treat T and M as approximately normal random variables?
Monte Carlo Theorem
Central Limit Theorem
Law of Large Numbers
Convolution Theorem
Chebychev's Theorem
301 Theorem
b) What is the expected value of T? 1403
c) What is the standard deviation of T? 400
d) What is the approximate probability that T is greater than 1400? 1444.075
e) What is the 98th percentile of the approximate distribution of T?
f) What is the standard deviation of M? 0.04
g) What is the approximate probability M is greater than 13.99? 0.5793
h) What is the variance of 93M? 345.96

Answers

we get (a) Central limit theorem ; (b) expected value of T = 1403; (c) Standard deviation = 400;

(d) Probability of T greater than 1400 is 0.5038 ;(e) 98th percentile is 1803 ; (f) standard deviation of M = 0.2 (g) Probability of M = 0.5793 (h) Variance of 93M = 345.96

In brief :

a) Central Limit Theorem (CLT) is a theorem that will let us treat T and M as approximately normal random variables.

CLT establishes that the mean of a sufficiently large sample from any population has an approximately normal distribution, regardless of the population's shape.

b) The expected value of T is given by μT = 100 * μ = 100 * 14.03 = 1403.

c) The standard deviation of T is given by σT = √(100 * σ²) = √(100 * 2²) = 400.

d) The z-score is given by (1400 - 1403)/400 = -0.0075. Using the z-table, we find the area to the right of the z-score as 0.5038.

Therefore, the approximate probability that T is greater than 1400 is 0.5038.

e) To find the 98th percentile of the approximate distribution of T, we need to find the z-score corresponding to the area of 0.98 in the standard normal distribution. Using the z-table, we find this z-score to be 2.05.

Therefore, the 98th percentile of the approximate distribution of T is 1403 + 2.05 * 400 = 1803.

f) The standard deviation of M is given by σM = σ/√n = 2/√100 = 0.2.

g) The z-score is given by (13.99 - 14.03)/0.2 = -0.2.

Using the z-table, we find the area to the right of the z-score as 0.5793. Therefore, the approximate probability that M is greater than 13.99 is 0.5793.

h) The variance of 93M is given by (93)² * Var(M) = (93)² * (σ²/n) = (93)² * (2²/100) = 345.96.

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Calculate the number of moles in 44 g of iron sulfide.
Relative atomic masses
(4): Fe = 56, S = 32

Answers

Answer:

2 moles

Explanation:

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The mass of one mole of iron sulphide is 88 g. Then the number of moles in 44 g is 0.5 moles.

What is one mole ?

One mole of a substance is its amount which contains 6.022 × 10²³ atoms. This number is called Avogadro number. One mole of every element contains Avogadro number of atoms.

Similarly one mole of every compound contains Avogadro number of molecules. The mass of one mole of a compound is called its molar mass.

Atomic mass of  Fe = 56 g/mol

atomic mass o S = 32 g/mol

molar  mass of FeS = 56 + 32 = 88 g/mol

Mass of one mole of iron sulphide (FeS) is 88 g. Hence number of moles in 44 g is :

no.of moles = given weight/molar mass

                    = 44 g /88 g/mol = 0.5 mol

Therefore, the number of moles of FeS in 44 g is 0.5.

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19. a jetliner can fly 6.00 hours on a full load of fuel. without any wind, it flies at a speed of 2.40 x 102 m/s. the plane is to make a roundtrip by heading due west for a certain distance, turning around, and then heading due east for the return trip. during the entire flight, however, the plane encounters a 57.8 m/s wind from the jet stream, which blows from west to east. what is the maximum distance that the plane can travel due west (flying at a constant 240 m/s relative to the air) and just be able to return home?

Answers

The maximum distance that the plane can travel towards west and just be able to return home is 1.33 × 103 km.

Given data of the problem:

Time of full load of fuel = 6.00 hours

Speed of jetliner without wind = 2.40 × 102 m/s

Wind speed = 57.8 m/s

Let d be the distance of the jetliner fly towards west.

So, the distance travelled towards east = d.

Total time = time for flying towards west + time for flying towards east= (d/(2.40 × 102 − 57.8)) + (d/(2.40 × 102 + 57.8))Now, we need to find the maximum distance that the plane can travel towards west (flying at a constant 240 m/s relative to the air) and just be able to return home.

When the plane reaches at a maximum distance it has to return with the remaining fuel. Therefore, the total time for the round trip is equal to the time of fuel load i.e., 6 hours.So, we have:(d/(2.40 × 102 − 57.8)) + (d/(2.40 × 102 + 57.8)) = 6By simplifying, we get:d = 1.33 × 103 km.

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when a ferromagnetic material is placed in an electromagnetic coil and a magnetic field is applied: group of answer choices (b) there is a large increase in the magnetic induction (b) (a) the magnetic induction (b) is decreased both a

Answers

When a ferromagnetic material is placed in an electromagnetic coil and a magnetic field is applied, the magnetic induction (B) is increased.

Ferromagnetic materials, such as iron, nickel, and cobalt, have unique properties that make them highly responsive to magnetic fields. When a ferromagnetic material is placed in an electromagnetic coil and a magnetic field is applied, several factors contribute to the increase in magnetic induction (B):Alignment of Magnetic Domains: In the absence of an external magnetic field, the magnetic domains within a ferromagnetic material are randomly oriented, resulting in a net magnetic moment of zero. However, when a magnetic field is applied, the domains align themselves in the direction of the field, leading to an increase in the overall magnetic induction.Magnetic Saturation: Ferromagnetic materials have a saturation point, beyond which further increase in the magnetic field does not significantly increase the magnetic induction. This saturation point is typically higher than that of other magnetic materials, allowing ferromagnetic materials to exhibit a larger increase in magnetic induction.Amplification of Magnetic Field: The presence of a ferromagnetic material within an electromagnetic coil enhances the magnetic field generated by the coil. This phenomenon is known as magnetic amplification or magnetic flux concentration. The ferromagnetic material acts as a magnetic conductor, guiding and intensifying the magnetic field lines, resulting in a larger magnetic induction.In contrast, option (a) stating that the magnetic induction (B) is decreased is incorrect. When a ferromagnetic material is subjected to an external magnetic field, the magnetic induction increases due to the alignment of magnetic domains and the amplification of the magnetic field.

Therefore, the correct answer is:

(a) There is a large increase in the magnetic induction (B)

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Water travels, in a 2km long pipeline at a maximum flow rate of 0.12 m/s. The internal diameter of the pipe is 300 mm, pipe wall thickness is 5 mm, and is manufactured from steel with a Young's modulus of 210x109 Pa. The pipeline is constructed within an excavated trench and surrounded by backfill material. A control valve on the downstream end of the pipeline uniformly closes in 12 seconds. (a) Calculate the pressure transients at the mid-point of the pipeline (b) How does friction in pipeline effect the calculated (in Q6 (a)) pressure transients

Answers

(A) The pressure transients at the mid-point of the pipeline are approximately 1,208,277 Pa.
(B) Friction in the pipeline affects the calculated pressure transients by increasing the overall resistance to flow

(a) The pressure transients at the mid-point of the pipeline can be calculated using the water hammer equation. Water hammer refers to the sudden changes in pressure and flow rate that occur when there are rapid variations in fluid flow. The equation is given by:

ΔP = (ρ × ΔV × c) / A

Where:

ΔP = Pressure change

ρ = Density of water

ΔV = Change in velocity

c = Wave speed

A = Cross-sectional area of the pipe

First, let's calculate the change in velocity:

ΔV = Q / A

Q = Flow rate = 0.12 m/s

A = π × ((d/2)^2 - ((d-2t)/2)^2)

d = Internal diameter of the pipe = 300 mm = 0.3 m

t = Pipe wall thickness = 5 mm = 0.005 m

Substituting the values:

A = π × ((0.3/2)^2 - ((0.3-2(0.005))/2)^2

A = π × (0.15^2 - 0.1495^2) = 0.0707 m^2

ΔV = 0.12 / 0.0707 = 1.696 m/s

Next, let's calculate the wave speed:

c = √(E / ρ)

E = Young's modulus of steel = 210x10^9 Pa

ρ = Density of water = 1000 kg/m^3

c = √(210x10^9 / 1000) = 4585.9 m/s

Finally, substituting the values into the water hammer equation:

ΔP = (1000 × 1.696 × 4585.9) / 0.0707 = 1,208,277 Pa

Therefore, the pressure transients at the mid-point of the pipeline are approximately 1,208,277 Pa.

(b) Friction in the pipeline affects the calculated pressure transients by increasing the overall resistance to flow. As water moves through the pipe, it encounters frictional forces between the water and the pipe wall. This friction causes a pressure drop along the length of the pipeline.

The presence of friction results in a higher effective wave speed, which affects the calculation of pressure transients. The actual wave speed in the presence of friction can be higher than the wave speed calculated using the Young's modulus of steel alone. This higher effective wave speed leads to a reduced pressure rise during the transient event.


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a body has a weight of 2.8 Newtons what is the Mass of the body in grams​

Answers

Answer:

285.7 g

Explanation:

Weight = mass x gravity

mass has units of kilograms

gravity is 9.8 m/s²

newton units are kg m / s²

So:

2.8 kg m/s² = mass x 9.8 m/s²

Divide both sides by 9.8

2.8 kg m/s²

----------------  =  mass in kg  = 0.2857kg

9.8 m/s²

Convert kilograms to grams by multiplying by 1000

0.2857kg        1000 g

--------------  X  ---------------  = 285.7g

       1                  1 kg

a ball falls towards the ground at 9 m/s (downwards), and bounces up at 5 m/s (upwards). the mass of the ball is 232 gram. what is the change in momentum of the ball as it bounces (in kg.m/s).'

Answers

The change in momentum of the ball as it bounces is 3.248 kg.m/s (upwards).


Step 1: Convert mass to kg
Mass = 232 grams = 232/1000 kg = 0.232 kg
Step 2: Calculate initial momentum (before the bounce)
Initial velocity = 9 m/s (downwards)
Initial momentum = mass x initial velocity = 0.232 kg x 9 m/s = 2.088 kg.m/s (downwards)
Step 3: Calculate final momentum (after the bounce)
Final velocity = 5 m/s (upwards)
Final momentum = mass x final velocity = 0.232 kg x 5 m/s = 1.16 kg.m/s (upwards)
Step 4: Calculate change in momentum
Change in momentum = final momentum - initial momentum = 1.16 kg.m/s (upwards) - 2.088 kg.m/s (downwards) = 1.16 kg.m/s + 2.088 kg.m/s = 3.248 kg.m/s (upwards)
The change in momentum of the ball as it bounces is 3.248 kg.m/s (upwards).

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calculate the speed of sound on a day when a 2350 hz frequency has a wavelength of 0.315 m.

Answers

The speed of sound on a day when a 2350 Hz frequency has a wavelength of 0.315 m is 740.25 m/s.


To calculate the speed of sound on a day when a 2350 Hz frequency has a wavelength of 0.315 m, you can use the formula:

Speed of sound = Frequency × Wavelength

Step 1: Identify the given values.
Frequency (f) = 2350 Hz
Wavelength (λ) = 0.315 m

Step 2: Plug the given values into the formula.
Speed of sound = 2350 Hz × 0.315 m

Step 3: Calculate the result.
Speed of sound ≈ 740.25 m/s

So, the speed of sound is 740.25 meters per second.

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Which theory of plate movement relies on the weight of subducting crust?

Answers

Slab Pull  theory of plate movement relies on the weight of subducting crust.

What is slab pull?

A cold, dense oceanic plate that is falling into the mantle as a result of its own weight is said to be exerting a slab pull. According to the hypothesis, the oceanic plate sinks into the mantle because it has a higher density than the hotter mantle underneath it. Subduction is the process through which a tectonic plate descends into the mantle.

One sort of convergent boundary where two tectonic plates are clashing is a subduction zone. There may be divergent boundaries between two oceanic plates.

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A car travels at 15 m/s for 30 minutes. How far did it travel?

Answers

Answer:

27000 meters

Explanation:

15 x 60 x 30

explain why the different thermal conductivities of metal and plastic are important in the design of the bowl.

explain why the different thermal conductivities of metal and plastic are important in the design of

Answers

Answer:

metal conducts heat faster than wood. which means the metal conducted heat away from your hand (or whatever it is) faster than wood.

Explanation:

just because they feel warm/cold doesn't always mean that it is warm/cold. if they both were sitting at room temp for a long time, then both will eventually reach the temp of the room. even though they are the same temp the metal will feel colder than the wood because of the thermal conductivity of the metal compared to the wood.

The different thermal conductivities of metal and plastic are important in the design of the bowl is metal conducts heat faster than Plastic. which means the metal conducted heat away from your hand (or whatever it is) faster than Plastic.

What is thermal conductivity?

Thermal conductivity can be defined as the degree to which heat is transmitted through the cross-section of the unit of an object, where the temperature exits directly across the surface.

What is electrical and thermal conductivity?

Electrical conductivity is a measure of how much energy (moving charge) can pass through objects under the influence of a used electric field. Thermal conductivity measures how heat (heat moving energy) can pass through objects below temperature differences.

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Condensation raises the temperature of the vapor (True or False).

Answers

Answer:

true

Explanation:

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A 15kg block is being pushed up a 20 degrees ramp that has a kinetic coefficient of 0.30. What is the pushing force if the acceleration of the block is 2.0m/s^2?

The answer is 121.7 N, I just need to know how to solve it.

Answers

Answer:

this is just and example of how to solve it

Explanation:

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PLEASE HELP WILL MARK BRAINLIEST IF YOU EXPLAIN HOW TOU GOT THE ANSWER!!!A 15kg block is being pushed
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