Both variable resistors and PWM can be used to: control the speed of a DC motor, with the former offering simplicity and the latter providing higher efficiency.
The speed of a DC motor increases with increasing current through the armature coil. There are two ways to change the current supplied to the motor: (1) using a variable resistor (potentiometer) and (2) employing pulse width modulation (PWM).
1) Variable Resistor (Potentiometer): This method works by adjusting the resistance in the circuit, which controls the current flowing through the motor. By changing the resistance, you can change the current and hence, the motor speed. One advantage of this method is its simplicity and ease of use. A disadvantage, however, is that it can be inefficient, as some energy is lost as heat in the resistor.
2) Pulse Width Modulation (PWM): This method works by switching the supply voltage on and off at a specific frequency, thus creating pulses with varying widths. The average voltage applied to the motor is controlled by adjusting the pulse width, which in turn, controls the motor speed. One advantage of PWM is its efficiency, as there is minimal energy loss in the process. A disadvantage, though, is that it can generate electrical noise and requires more complex circuitry.
In summary, both variable resistors and PWM can be used to control the speed of a DC motor, with the former offering simplicity and the latter providing higher efficiency.
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The amount of blank
that occurs when a sound wave encounters a
barrier depends on the wave's wavelength.
Answer:
where is the paragraph so i can read
Answer:
Diffraction
Explanation:
Look at the definition of Diffraction in your notes and quiz just taken
The magnetic field at the center of a 1.5 cm diameter loop is 3.0 mT.
(a) What is the current in the loop?
(b) A long straight wire carries the same current found in part (a). At what distance from the wire is the magnetic field 3.0 mT?
The center of a 1.5 cm wide loop has a magnetic field of 3.0 mT. About 0.3 Amperes of current flow through the loop. A 3.0 mT magnetic field is present about 0.2 meters away from the wire.
To solve this problem, we can use the formula for the magnetic field produced by a current-carrying loop and the formula for the magnetic field produced by a current-carrying wire.
Answer of the following questions are below :
(a) The magnetic field at the center of a current-carrying loop is given by the formula:
\(B = \frac{\mu_0 \cdot I \cdot N}{2 \cdot R}\)
Where B is the magnetic field, μ₀ is the permeability of free space (4π × 10⁻⁷ T·m/A), I is the current, N is the number of turns in the loop, and R is the radius of the loop.
We are given that the magnetic field is 3.0 mT (3.0 × 10⁻³ T) and the radius of the loop is 1.5 cm (0.015 m).
Substituting these values into the formula, we can solve for the current:
\(3.0 \times 10^{-3} \, \text{T} = \frac{4\pi \times 10^{-7} \, \text{T}\cdot\text{m/A} \cdot I}{2 \cdot 0.015 \, \text{m}}\)
Simplifying the equation, we find:
\(I = \frac{(3.0 \times 10^{-3} \, \text{T}) \cdot (2 \cdot 0.015 \, \text{m})}{4\pi \times 10^{-7} \, \text{T}\cdot\text{m/A}}\)
Calculating this expression, we get:
I ≈ 0.3 A
Therefore, the current in the loop is approximately 0.3 Amperes.
(b) The magnetic field produced by a long straight wire carrying current is given by the formula:
\(B = \frac{\mu_0 \cdot I}{2\pi \cdot r}\)
Where B is the magnetic field, μ₀ is the permeability of free space (4π × 10⁻⁷ T·m/A), I is the current, and r is the distance from the wire.
We are given that the magnetic field is 3.0 mT (3.0 × 10⁻³ T).
Substituting these values into the formula, we can solve for the distance from the wire:
\(3.0 \times 10^{-3} \, \text{T} = \frac{4\pi \times 10^{-7} \, \text{T} \cdot \text{m/A} \cdot I}{2\pi \cdot r}\)
Simplifying the equation, we find:
\(r = \frac{4\pi \times 10^{-7} \, \text{T} \cdot \text{m/A} \cdot I}{2\pi \cdot (3.0 \times 10^{-3} \, \text{T})}\)
Calculating this expression, we get:
r ≈ 0.2 m
Therefore, the magnetic field of 3.0 mT is found at a distance of approximately 0.2 meters from the wire.
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A snowball is outside for a few days. It initially gets larger (it is outside while it is snowing) but then it starts shrinking (the snow stops and it begins to warm up). Its volume after t days is V(t)=10+40t−5t 2cm Compute the average velocity over the time interval [3,7] (round to the nearest thousandth and include units on your final answer). Is the snowball getting larger or smaller on this interval?
To compute the average velocity over the time interval [3,7], we need to find the change in volume (∆V) over that interval and divide it by the change in time (∆t).
∆V = V(7) - V(3) [Change in volume]
= (10 + 40(7) - 5(7)^2) - (10 + 40(3) - 5(3)^2)= (10 + 280 - 5(49)) - (10 + 120 - 5(9))= (10 + 280 - 245) - (10 + 120 - 45)= 45 - 75= -30 cm³ [Change in volume]∆t = 7 - 3 = 4 days [Change in time]
Average velocity (v_avg) = ∆V / ∆t
= -30 cm³ / 4 days = -7.5 cm³/dayThe average velocity over the time interval [3,7] is -7.5 cm³/day. The negative sign indicates that the snowball is shrinking during this interval.
About VelocityVelocity is a vector quantity that indicates how fast an object is moving. The magnitude of this vector is called speed and is expressed in meters per second.
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Julie blows a bubble. At first, the pressure of the gas in the bubble is 4kPa. The bubble floats into the air and expands. When it gets to the top of a tree the bubble has a pressure of 2kPa and a volume of 3.5m³. Assuming a constant temperature, what was the volume in m³ of the bubble when it was first blown? Give your answer to three significant figures.
Answer:
P V = N R T
P1 V1 = P2 V2 assuming N, R, and T remain constant
V1 = (P2 / P1) V2
V1 = (2 kPa / 4 k Pa) 3.5 m3
V1 = 3.5 m^3 / 2 = 1.75 m^3
Do distance and Gravity have a _____ relationship?
Answer:
proportional...?
Explanation:
not sure if thats correct...
hope this helped tho
try your best!
mark me brianliest :D
in the movie superman, lois lane falls from a building and is caught by the diving superhero. assume that lois has a mass of 55.1 kg and is falling at a terminal velocity of 61.9 m/s. a) how much force does superman exert on her if it takes 0.143 s to slow her to a stop? (in n)
Superman exerts a force of 23,651 Newtons on Lois Lane when catching her.
To calculate the force exerted by Superman on Lois Lane, we can use the formula:
Force = (mass of Lois) x (change in velocity) / time
Since Lois is falling at a terminal velocity of 61.9 m/s and Superman catches her and brings her to a stop, the change in velocity is 61.9 m/s (the initial velocity) minus 0 m/s (the final velocity), which equals 61.9 m/s.
Plugging in the values we know, we get:
Force = (55.1 kg) x (61.9 m/s) / 0.143 s
Simplifying this calculation.
Force = 23,651 N
Therefore, Superman exerts a force of 23,651 Newtons on Lois Lane when catching her.
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Why is gravity so weird?
Will mark as brain list
Answer:
No force is more familiar than gravity — it's what keeps our feet on the ground, after all. And Einstein's theory of general relativity gives a mathematical formulation for gravity, describing it as a “warping” of space.
10 20 30 40 50 60 70 80 90 100 110 120 130. Which end of the scale (left or right) has the loudest sounds?
Answer:
I'm From Philippines
I hope we can be friends.
consider two identical spheres rolling without slipping across rigid horizontal surfaces. sphere 1 has a coefficient of static friction
sphere 1 has a coefficient of static friction because Rolling motion, which combines rotational and translational motion, is something we regularly see all the time.
Consider a variety of situations that involve wheels, such as a car driving down a highway, a plane landing, or a robotic explorer investigating a distant planet. Understanding the pressures and torques associated with rolling motion is crucial in a variety of situations. People have seen rolling motion without slipping ever since the invention of the wheel. As an example, consider the contact between a car's tires and the road's surface. If the driver depresses the accelerator to the floor and the tires spin but the car doesn't move ahead, there must be kinetic friction between the wheels and the road surface. If the driver gently presses the pedal, the car will go ahead and keep the tires from slipping. The fact that the bottom of the wheel is truly at rest with respect to the ground, demonstrating static friction between the tires and the road, most people find weird.
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Name one benefit and one risk of each biotechnology practice:
Genetic engineering:
Cloning:
Artificial selection:
PLEASE!!!!!!!!!!!!!!!!!!!!!!!
Answer:
Genetic Engineering:
Benefits: More nutritious food, less use of pesticides, increased supply of food with reduced cost and longer shelf life, faster growing plants and animals
Risk: Creating foods that can cause allergic reaction or that are toxic, Unexpected ir harmful genetic changes, genes moving from one GM plant or animal to anotherplant or animal that is not genetically engineered
Cloning:
Benefits: accelerated reproduction of farmers productive livestock to better produce safe and healthy foods, reproduction of the healthiest animals, minimizing the use of antibiotics, growth hormones and chemicals
Risks: Unwantedhealty effects, defects, premature aging and problems with the immune system
Artificial Selection:
Benefits: no safety issues as those brought by genetic engineering, cheap for agricultural businesses, morally accepted, produce crops with higher yield
Risks: Removes variation, makes organism susceptible to diseasesor changes in environment, unable to control genes inherited by offspring
Answer:
Genetic Engineering
Benefits
-Ability to create food that is resistant to pests, cold, and disease.
-Greater food production volume and increased vitamins.
Risks
-Concerns about long-term health risks.
-Lack of regulation.
Cloning
Benefits
-Ability to increase endangered animal populations.
-Possibility of eliminating diseases and defective genes.
Risks
-Shorter lifespan for cloned animals.
-Greater chance of health issues for cloned animals.
Artificial Selection
Benefits
-Allows for selection of desired traits.
-Ability to create better versions of organisms.
Risks
-Loss of genetic diversity.
-Increased chance of diseases that can shorten lifespan.
Explanation:
Hlo guys anyone here??
Answer:
Explanationvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv
which of these elements is a metal
Answer:
they all have them it's just sometimes 1 has more then the other
scientists currently use planetary rovers to collect data on mars. what type of samples have they collected so far?
Scientists currently use planetary rovers to collect data on mars rovers collect infrared spectra, drill cores, photographs.
Designed to move across the solid surface of a planet or other planetary mass celestial bodies, a rover (or occasionally planetary rover) is a planetary surface exploration tool. Others have been created as partially or entirely autonomous robots. Some rovers have been created as ground vehicles to transfer members of a human spaceflight crew. When a lander-style spacecraft is used to land on a planet (other than Earth), rovers are often built to collect data about the topography and sample the crust, including dust, dirt, rocks, and even liquids. They are vital resources for space exploration. Due to the slow speed of radio communications, rovers that land on celestial worlds other than the Earth, like the Mars Exploration Rovers, cannot be remotely operated in real-time.
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How are electromagnetic waves different than all other waves?
Answer:
Explanation:
Electromagnetic waves differ from mechanical waves in that they do not require a medium to propagate. This means that electromagnetic waves can travel not only through air and solid materials, but also through the vacuum of space. ... This proved that radio waves were a form of light
Answer:
They travel through space
Explanation:
2021 edge
Which is a benefit of a scientific model?
A.) It provides a complete image of the concept it is modeling.
B.) It provides an accurate scale of the concept it is modeling.
C.) It provides an accurate visual representation of the texture and coloring of the concept it is modeling.
D.) It provides a useful understanding of the concept it is modeling.
The moon has a smaller mass than the Earth. If
you were to travel to the moon your weight would
A. Increase
B. Decrease
C. Stay the same
D. Vary with day and night
A force acting toward the center of a curved
or circular path is called
A. Balanced forces
B. Net force
C. Centripetal force
D. Gravity
If dropped from the same height, how would
each ball hit the ground?
Wood Plastic Metal
A. Metal first, then plastic, then wood
B. Wood first, then plastic, then metal
C. Plastic first, then metal, then wood
D. They will all hit at the same time
Answer:
Decrease
Explanation:
If you were on the Moon, which has significantly less mass than the Earth, your weight would: decrease
The point that seemed to be giving me a complicated time was being able to distinguish the difference and meaning of weight and mass and being able to apply that to a problem. I kept mixing up the definitions. For example in homework 3.1, one question asked:
If you were on the moon, which has significantly less mass than the earth, your mass would:
a. increase
b. decrease
c. stay the same
d. become zero
The definition of mass is the amount of matter in an object. The definition of weight is the amount or unit of force. For me, I just had to remember that when it asked about weight, it wasn’t referring how heavy an object is. After I was able to recognize that when it came to weight, questions became easier.
The final and correct answer was decreasing. The answer is because the Moon’s mass is less. This means the gravitational force is less on your body, therefore, your mass is going to be lighter
A ball experiences forces of 14 N [N] and 9.2 N [W]. A Free Body diagram is required. What is the acceleration of the ball if its mass is 225 g?
Answer:
First, we can define the North as the positive y-axis, and the East as the positive x-axis.
Here we have two forces:
F₁ = 14N to north
F₂ = 9.2 N to west.
Then the free body diagram will be the one that can be seen below:
Now we want to find the acceleration that the ball experiences if the mass is 225g
Knowing that 1k = 1000g, we can rewrite the mass as:
M = 0.225g
Here we also need to remember the second Newton's law:
F = M*a
Net force equals mass times acceleration.
First, let's find the net force:
F = F₁ + F₂ = 14N*(0, 1) + 9.2N*(-1, 0 )
F = (-9.2N, 14N)
The module of the force is then:
I F I = √( (-9.2N)^2 + (14N)^2) = 16.75 N
Then the acceleration is given by
16.75 N = 0.225kg*a
(16.75 N)/(0.225 kg) = a = 74 m/s^2
In a double slit interference experiment, the centers of the slits are a distance d apart. What should be the width D of each slit for the first minima of diffraction to coincide with the fourth maxima of interference?
[A] D=d/8
[B] D=d/4
[C] D=d/2
[D] D=d
[E] D=4 d
The width of each slit (D) should be D = d / 4. for the first minima of diffraction to coincide with the fourth maxima of interference. Option B is correct.
In a double-slit interference experiment, the interference pattern is created by the superposition of waves from two slits. The condition for constructive interference at a particular angle is given by the equation:
dsinθ = mλ,
where d is the distance between the centers of the slits, θ is the angle of observation, m is the order of the interference maximum, and λ is the wavelength of the light.
For the first minima of diffraction to coincide with the fourth maxima of interference, we have m = 4.
At the first minima of diffraction, sinθ = λ / D, where D is the width of each slit.
At the fourth maxima of interference, dsinθ = 4λ.
Equating these two expressions, we have:
d * (λ / D) = 4λ.
Simplifying the equation, we get:
D = d / 4.
The width of each slit (D) should be equal to one-fourth (1/4) of the distance between the centers of the slits (d). Option B is correct.
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Which football player has greater momentum?
a tom: mass = 90 kg, velocity = 1.5 m/s
b ted: mass = 60 kg, velocity = 2.0 m/s
c tim: mass = 100 kg, velocity = 1.2 m/s
d todd: mass = 80 kg, velocity = 1.7 m/s
d Todd: mass= 80 kg, velocity=1.7m/s football player has greater momentum.
The definition of momentum is "mass in motion." All things have mass, thus if something is moving, it must have momentum because its mass is in motion.
Momentum is a commonly used term in sports. A team that has the momentum is on the move and is going to take some effort to stop. A team that has a lot of momentum is really on the move and is going to be hard to stop.
Tom has a momentum of p = 90 x 1.5 = 135 kg m/s and
Ted has a momentum of p = 60 x 2 = 120 kg/m/s.
Tim has an energy of p = 100 x 1.2 p = 120 kg m/s.
Todd's momentum is given by p = 80 x 1.7 =136 kg m/s.
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Determine the resultant force.
Determine the equivalent resultant couple moment about point
O
Replace the loading by an equivalent resultant force and couple moment at point O. Suppose that F₁ = {8i - 2k} kN and F₂ = {-2i+5j – 2k} kN. X 0.8 m 0.5 m 0.7 m Z
The loading can be replaced by an equivalent resultant force of 6i + 5j - 4k kN and an equivalent resultant couple moment of 6i + 3.4j + 1.5k.
To determine the resultant force, we need to add the given forces together:
F₁ = 8i - 2k kN
F₂ = -2i + 5j - 2k kN
Adding these forces, we have:
Resultant force (Fᵣ) = F₁ + F₂
= (8i - 2k) + (-2i + 5j - 2k)
= 8i - 2k - 2i + 5j - 2k
= 6i + 5j - 4k kN
So, the resultant force is Fᵣ = 6i + 5j - 4k kN.
To determine the equivalent resultant couple moment about point O, we can use the cross product of the position vectors and the forces:
Mᵣ = r₁ x F₁ + r₂ x F₂
Given the position vectors:
r₁ = 0.8i + 0.5j + 0.7k m
r₂ = 0.8i + 0.5j + 0.7k m
Substituting the values, we have:
Mᵣ = (0.8i + 0.5j + 0.7k) x (8i - 2k) + (0.8i + 0.5j + 0.7k) x (-2i + 5j - 2k)
Expanding the cross products, we get:
Mᵣ = (4i + 5j - 2k) + (2i - 1.6j + 3.5k)
= 6i + 3.4j + 1.5k
So, the equivalent resultant couple moment about point O is Mᵣ = 6i + 3.4j + 1.5k.
To replace the loading by an equivalent resultant force and couple moment at point O, we have:
Resultant force at point O (Fᵣ) = 6i + 5j - 4k kN
Resultant couple moment at point O (Mᵣ) = 6i + 3.4j + 1.5k
Thus, the loading can be replaced by an equivalent resultant force of 6i + 5j - 4k kN and an equivalent resultant couple moment of 6i + 3.4j + 1.5k.
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Sort by LUSTER. Is there a relationship between color and luster? How are they similar or different?
Color is..blue, red, black... basically COLORS. Whereas luster is like a soft glow or gentle sheen kinda like something is shining. You could say the luster of the blue paint is beautiful.
Explanation:
Bowchiclawowowow
how do animal weather rocks
Answer:
Burrowing animals can cause weathering. By digging for food or making space to live in the animal may break apart rock. The growing roots of a tree can also break apart rock.
A runner completes two laps around a 400-m track. She runs the first lap in 1 min 32 s, and the second lap in 1 min 49 s. What is her average speed?
Answer:
The average speed is 3.98 \(\frac{m}{s}\)
Explanation:
Speed is a scalar quantity that shows the relationship between the distance traveled and the time taken.
In other words, speed is a scalar quantity that determines the ratio of the distance traveled by a body or object and the time it takes to cover that distance. Speed does not take direction into account.
Average speed refers to the total distance traveled during a given time, which is equivalent to saying that it is the ratio of distance and time.
\(average speed=\frac{total distance}{totaltime}\)
In this case you know that a runner completes two laps around a 400 m track, so the total distance traveled is 800 m.
On the other hand, you know that the runner completes the first lap in 1 min 32 s, and the second lap in 1 min 49 s. Being 1 min equivalent to 60 s, the first round is completed in 92 s and the second round in 109 s. So the total time to complete the two laps around the track is 92 s + 109 s = 201 s.
That is, being:
total distance=800 mtotal time= 201 sand replacing in the definition of average speed:
\(average speed=\frac{800 m}{201 s}\)
you get:
average speed= 3.98 \(\frac{m}{s}\)
The average speed is 3.98 \(\frac{m}{s}\)
Answer:
3.98 m/s
Explanation:
To find speed, use the formula:
Speed = Distance / time
The Distance is 400 + 400 = 800 m
The time in seconds is (60 + 32) + (60 + 49) = 201 sec
Now use the formula
Speed = 800 m / 201 s = 3.98 m/s
What does a line coming up and getting steeper represent on a distance/time graph?
l am so confused is it right?
Answer:
D
Explanation:
First,mg>fv: It does a download acceleration,and the speed of the object increase.
Second,mg=fv: it hasn't a acceleration.
you can think the f is a constant.
A 100 kg roller coaster is pulled up the first hill to a height of 8 meters. The car has an initial velocity of 2 m/s at the top of the first hill, rolls down the hill, and then up a second hill. (g = 10 m/s2)
Frictional forces are negligible.
A. If at the top of the second hill the car has twice its initial velocity, then what must be the height of the second hill?
B. Calculate the work done by friction supposing the car only makes it half way up the second hill where it comes to a complete stop.
C.Calculate the work done by the net external forces that moved the car from where it was at rest on the ground to the top of the first hill with its initial velocity. Frictional forces are negligible.
I just need help with part C!
A) Work done by net external forces is 8100 J. B) Work done by friction is 8856 J.C) Work done by the net external forces is 8100 J.
What is frictional forces?Force that is generated between surfaces that slide against each other is called frictional force.
A. Total energy = mgh + (1/2)mv² = (1/2)mv'²
v' is final velocity of the roller coaster at top of the second hill, which is twice its initial velocity (2 m/s).
100 kg × 10 m/s² × 8 m + (1/2) × 100 kg × (2 m/s)² = (1/2) × 100 kg × (2 × 2 m/s)² + 100 kg × 10 m/s² × h
8000 J + 200 J = 400 J + 1000 J + 1000 J × h
h = (8000 J + 200 J - 400 J - 1000 J) / (1000 J × 10 m/s²) = 6.8 m
Therefore, height of the second hill must be 6.8 meters.
B. mgh + (1/2)mv² - Wf = 1/2mvf²
Wf is work done by friction, vf is final velocity of the roller coaster at the point where it comes to a stop (zero)
100 kg × 10 m/s² × 6.8 m + (1/2) × 100 kg × (2 m/s)² - Wf = 0
Wf = 8856 JTherefore, the work done by friction as the roller coaster moves up the second hill is 8856 J.
C. PE = mgh
ΔPE = PE_final - PE_initial = mgh
KE = (1/2)mv²
W = KE = (1/2)mv²
W_total = ΔPE + KE
W_total = mgh + (1/2)mv²
m = 100 kg
h = 8 m
v = 2 m/s
g = 10 m/s²
W_total = (100 kg)(10 m/s²)(8 m) + (1/2)(100 kg)(2 m/s)²
W_total = 8000 J + 100 J
W_total = 8100 J
Therefore, work done by net external forces that moved the car from where it was at rest on the ground to top of the first hill with its initial velocity is 8100 J.
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Sunspots, flares, prominences, and coronal mass ejections are all caused by.
Answer:
Sunspots, flares, prominences, and coronal mass ejections are all caused by magnetic activity on the Sun.
write any two different between work and power?
Answer:
1. Work Is a type of Physical Activity
2. Power is Basically Having control of Society
Explanation:
e angle changes 70° in a time interval of 0.2s. alculate the: 5 Magnitude of the emf induced in the coil. Current induced in the coil if it has an effective resistance of 20 S
The magnitude of the emf induced in the coil is 0.096 volts, and the current induced in the coil, considering an effective resistance of 20 ohms, is 0.0048 amperes.
Faraday's law of electromagnetic induction states that when a magnetic field changes in intensity or when a conductor moves in a magnetic field, an electromotive force (emf) is induced in the conductor. This induced emf is proportional to the rate of change of the magnetic field or the rate at which the conductor cuts the magnetic field lines.
Now, let's calculate the values requested:
a. To calculate the magnitude of the emf induced in the coil, we can use the formula:
emf = N * A * B * sin(θ)
Where:
N = number of turns in the coil = 100 turns
A = area of each turn of the coil = 4.8 x 10^(-4) m²
B = magnetic field strength = 4 x 10^(-4) T
θ = angle between the magnetic field and the normal to the plane of the coil = 30°
Plugging in the values:
emf = 100 * 4.8 x 10^(-4) * 4 x 10^(-4) * sin(30°)
Calculating this expression will give you the magnitude of the emf induced in the coil.
b. To calculate the current induced in the coil, we can use Ohm's Law:
emf = I * R
Where:
emf = electromotive force induced in the coil (calculated in part a)
R = effective resistance of the coil = 20 ohms
Rearranging the formula:
I = emf / R
Substituting the values calculated in part a:
I = (emf calculated in part a) / 20 ohms
Calculating this expression will give you the current induced in the coil.
a. Using the formula for the magnitude of the induced emf:
emf = 100 * 4.8 x 10^(-4) * 4 x 10^(-4) * sin(30°)
emf = 100 * 4.8 x 10^(-4) * 4 x 10^(-4) * 0.5
emf = 0.096 volts
Therefore, the magnitude of the emf induced in the coil is 0.096 volts.
b. Using Ohm's Law:
I = emf / R
I = 0.096 volts / 20 ohms
I = 0.0048 amperes
So, the current induced in the coil, considering an effective resistance of 20 ohms, is 0.0048 amperes.
Hence, The magnitude of the induced emf in the coil is 0.096 volts, and the current induced in the coil is 0.0048 amperes, assuming an effective resistance of 20 ohms.
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Problem 50 (8th edition) statement: helium is to be compressed from 105 kpa and 295 k to 700 kpa and 460 k. a heat loss of 15 kj/kg occurs during the compression process. neglecting kinetic energy changes, determine the power input required for a mass flow rate of 60 kg/min.
The input power required for a mass flow rate of 60 kg/min is calculated to be 871.35 kW.
Given that,
Initial temperature T₁ = 295 K
Final temperature T₂ = 460 K
Initial pressure P₁ = 105 k pa
Final pressure P₂ = 700 k pa
The specific heat loss from the compressor Q = 15 kJ/kg
The mass flow rate m = 60 kg/min
Refer to the properties of element to determine the specific heat of helium.
Cp = 5.19 kJ/kg.K
Apply the energy balance equation for calculating the input power.
W - m Q = m h₁ - m h₂
W - m Q = m (h₁ - h₂)
W - m Q = m Cp (T₁ - T₂)
where,
W is the input power
h₁ and h₂ are the initial and final enthalpy
Placing the values in the above expression, we have,
W - 60 kg/min (1 min/60 sec) × (-15 kJ/kg) = 60 kg/min (1 min/60 sec) × 5.19 kJ/kg.K (295 K - 460 K)
W = -871.35 kJ.s (1kW/1kJ) = -871.35 kW
Thus, the input power = 871.35 kW.
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