Answer:
4
Step-by-step explanation:
Answer:
nothing is true
cuz 4-4=0
Step-by-step explanation:
please mark as the brainliest
A bag contains 4 red marbles, 3 blue marbles, and 7 green marbles. If a marble is randomly selected from the bag,
find the probability that a blue marble will be drawn.
Answer:
3/14
Step-by-step explanation:
The probability of drawing a blue marble can be found by dividing the number of blue marbles by the total number of marbles in the bag.
The total number of marbles in the bag is:
4 (red) + 3 (blue) + 7 (green) = 14
The number of blue marbles is 3.
So, the probability of drawing a blue marble is:
3/14
Answer:
Step-by-step explanation: d
Sales tax is a function of the price of an item. the amount of sales tax is 0.08 times the price of the item. use h to represent the function. a. h (x) = 0.08 h b. x (h) = 0.08 h c. h (x) = 0.08 x d. x (h) = 0.08 x
The correct representation of the function is h(x) = 0.08x
What is function?
In mathematics, a function from a set X to a set Y assigns to each element of X exactly one element of Y.
Solution:
Given data:
Sales tax is a function of the price of an item.
Let h be the function.
Take x be the price of an item.
Amount of sales tax = 0.08 times price of the item
= 0.08 × x
Amount of sales tax = 0.08x
⇒ h(x) = 0.08x
Hence the function is h(x) = 0.08x.
Option C is the correct answer.
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what is the value of x if the LCM of x and 84 is 1260 ,x is odd number
Answer:
X=15
Step-by-step explanation:
1260/84=15
Makayla leans a 18-foot ladder against a wall so that it forms an angle of 64 degrees with the ground. What’s the horizontal distance between the base of the ladder and the wall?
The horizontal distance between the base of the ladder and the wall is approximately 16.06 feet.
To find the flat distance between the foundation of the stool and the wall, we utilize geometry. For this situation, we can utilize the sine capability, which relates the contrary side of a right triangle to the hypotenuse and the point inverse the contrary side.
Let x be the flat distance between the foundation of the stepping stool and the wall. Then, utilizing the given point of 64 degrees, we can compose:
sin(64) = inverse/hypotenuse
where the hypotenuse is the length of the stepping stool, which is 18 feet.
Addressing for the contrary side, which is the even distance we need to find, we get:
inverse = sin(64) x hypotenuse
inverse = sin(64) x 18
inverse = 16.06 feet
Accordingly, the even distance between the foundation of the stepping stool and the wall is roughly 16.06 feet.
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A drawing has a scale of 1:40.
On the drawing, a bedroom is a rectangle measuring 10cm by 18cm.
A kitchen has an actual area of 300,000cm^2.
Which has the bigger area? Show working out.
Answer:
area of the kitchen
Step-by-step explanation:
in real life the dimensions are 10*40=400 cm=4 m and 18*40=720 cm=7.2 m
Area of the bedroom is A=4*7.2=28.8 m^2
Area of the kitchen is 300.000 cm^2=30 m^2
30>28.8
The bigger area is area of the kitchen
The bigger area between bedroom and kitchen is kitchen which is 30 m^2
What is area?Area can be find of l length and b breadth sides is
Area = l b
How to find area?Here the scale of bedroom is given that is 1 : 40
If bedroom is rectangle and measuring 10 cm and 18 cm then dimensions are
l = 10x40 = 400 cm = 4 m
b = 18x40 = 720 cm = 7.2 m
Therefore the area will be
Area of bedroom = 4x7.2 = 28.8 m^2
And we have given
Area of the kitchen = 300,000 cm^2
Convert into m^2 we have
Area of the kitchen = 30 m^2
This shows the area of the kitchen is bigger than the area of the bedroom
This is the conclusion to the answer.
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A cola-dispensing machine is set to dispense 8 ounces of cola per cup, with a standard deviation of 1.0 ounce. The manufacturer of the machine would like to set the control limit in such a way that, for samples of 47, 5% of the sample means will be greater than the upper control limit, and 5% of the sample means will be less than the lower control limit.
If the population mean shifts to 7.8, what is the probability that the change will be detected? (Round your intermediate calculations to 2 decimal places and final answer to 4 decimal places.)
If the population mean shifts to 8.6, what is the probability that the change will be detected? (Round your intermediate calculations to 2 decimal places and final answer to 4 decimal places.)
1. When the population mean shifts to 7.8, the probability of detecting the change is approximately 0.0495 (or 4.95%).
2. The probability of detecting the change is 0.0495 or 4.95%.
To solve this problem, we'll use the concept of control limits and the sampling distribution of the sample means.
When the population mean shifts to 7.8: First, let's calculate the standard deviation of the sampling distribution, also known as the standard error (SE). The formula for SE is given by SE = σ / sqrt(n), where σ is the standard deviation of the population (1.0 ounce) and n is the sample size (47).
SE = 1.0 / sqrt(47) ≈ 0.145
Next, we need to determine the z-score corresponding to the lower and upper tails of the sampling distribution that capture 5% each. Since the total probability in both tails is 10%, each tail will have a probability of 5%. We can find the z-scores using a standard normal distribution table or calculator.
The z-score corresponding to the lower tail of 5% is approximately -1.645.
The z-score corresponding to the upper tail of 5% is approximately 1.645.
Now, let's calculate the lower and upper control limits:
Lower Control Limit (LCL) = Population Mean - (z * SE)
Upper Control Limit (UCL) = Population Mean + (z * SE)
LCL = 7.8 - (-1.645 * 0.145) ≈ 8.026
UCL = 7.8 + (1.645 * 0.145) ≈ 9.574
To find the probability of detecting the change, we need to calculate the area under the sampling distribution curve that falls beyond the control limits. In this case, we're interested in the area above the upper control limit.
Since the distribution is assumed to be normal, we can use the standard normal distribution's cumulative distribution function (CDF) to calculate this probability.
Probability of detecting the change = 1 - CDF(z-score for UCL)
Using the z-score for the upper control limit (UCL), we can calculate the probability.
Probability of detecting the change ≈ 1 - CDF(1.645) ≈ 0.0495
Therefore, when the population mean shifts to 7.8, the probability of detecting the change is approximately 0.0495 (or 4.95%).
When the population mean shifts to 8.6: We'll follow the same steps as before.
SE = 1.0 / sqrt(47) ≈ 0.145
The z-score corresponding to the lower tail of 5% is still approximately -1.645.
The z-score corresponding to the upper tail of 5% is still approximately 1.645.
LCL = 8.6 - (-1.645 * 0.145) ≈ 8.926
UCL = 8.6 + (1.645 * 0.145) ≈ 10.274
Probability of detecting the change = 1 - CDF(z-score for UCL)
Probability of detecting the change ≈ 1 - CDF(1.645) ≈ 0.0495
Therefore, when the population mean shifts to 8.6, the probability of detecting the change is also approximately 0.0495 (or 4.95%).
In both cases, the probability of detecting the change is 0.0495 or 4.95%.
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hey! i’ll give brainliest please help
Answer:
It would be "a sentence that includes two independent clauses connected by a conjunction" which is Choice B.
Choice A wouldn't work as there needs to be two or more independent clauses for it to be a Compound Sentence.
Choice B would work, as it follows the definition of a Compound Sentence.
Choice C wouldn't work, that would be a Complex Sentence
Choice D wouldn't, that would be a Simple Sentence.
Also, note that this question is something for the Language Arts section.
Answer:
B. A sentence that includes two independent clauses connected by a conjunction.
Step-by-step explanation:
Compound sentences can make your writing very rich as you can connect two distinct independent clauses (no dependent clauses) using coordinating conjunctions such as for, and, nor etc (FANBOYS).
Example would be:
Juan likes to hunt, and he is going hunting on Sunday.
"Juan likes to hunt" is an independent clause where "Juan" is the subject, "likes" is the action, and a complete thought is expressed because we know what he likes to do now.
"He is going hunting on Sunday" is an independent clause where "He" is the subject, "is going" is the action, and a complete thought is expressed as we now know where he is going Sunday and what action he is doing.
The conjunction "and" is used, and a comma is correctly placed before "and."
Find the error with subject-verb agreement. select the incorrect verb and type it correctly. on the ledge there is three potted geraniums that desperately need water. however the hanging ferns in the living room are thriving.
Answer:
Step-by-step explanation:
ggggggg
A rectangular pool has length of 6 m and 3 m width. The pool is surrounded by a uniform edge with width x m. Given the area of the pool side is 32 m². Form a quadratic function and equation for the situation.
Answer:
you can solve this problem with the help of this example :
A rectangular pool 20 meters wide and 60 meters long is surrounded by a walkway of uniform width. If the total area of the walkway is 516 square meters, how wide, in meters, is the walkway?
Sol:
A rectangular pool has length l=60m & breadth b=20m.
It has a surrounding walkway of area =516m
2
.
Area (pool) =60×20=1200m
2
Let us take the width of the walkway =
2
X
.
∴ The length as well as the breadth of the area (pool+walkway) will be increased by X
So the length =l of the area (pool+walkway) =(60+X)m and the breadth =b=(20+X)m
∴ Area (pool+walkway) =l×b=[(60+X)×(20+X)]m
2
.
∴ Area (walkway) = Area (pool+walkway) - Area (pool)
=(60+X)×(20+X)−1200=516m
2
....(given)
⇒X
2
+80X−516=0
⇒X=−86 or X=6.
We reject the negative value as X is a length.
So X=6m.
Ans- The width of the walkway =
2
X
=3m.
An airplane travels at a bearing of 100° (clockwise from North) at 180 km/hr. A wind redirects the plane, blowing at 30 km/hr at a bearing of 42°. Find the true speed of the plane and its new direction by modeling the speeds and directions as vectors.
The first step is converting both the velocity and the wind in vector form, as follows:
Velocity: \(\vec{v_1} = 180 \text{ km/hr} \angle 100^\circ\)Wind: \(\vec{v_2} = 30 \text{ km/hr} \angle 42^\circ\)Then the true speed of the plane is given by the addition of these two vectors, as follows:
\(\vec{v_1} + \vec{v_2} = \sqrt{|v_1|^2 + |v_2|^2 + 2 \cdot |v_1| \cdot |v_2| \cdot \cos(\theta)}\)
The magnitudes of each vector are given as follows:
\(|v_1| = 180\).\(|v_2| = 30\).The angle between these two vectors is given as follows:
\(\theta = 100^\circ - 42^\circ = 58^\circ\)
Thus the resulting speed is obtained as follows:
\(\vec{v_1} + \vec{v_2} = \sqrt{180^2 + 30^2 + 2 \cdot 180 \cdot 30 \cdot \cos(58^\circ)} = 197.54\)
The resulting angle of the plane is then obtained as follows:
\(\angle = \arctan\left(\frac{|v_1| \cdot \sin(\theta) + |v_2| \cdot \sin(\theta_2)}{|v_1| \cdot \cos(\theta) + |v_2| \cdot \cos(\theta_2)}\right)\)
Hence:
\(\angle = \arctan\left(\frac{180 \cdot \sin(58^\circ) + 30 \cdot \sin(42^\circ)}{180 \cdot \cos(58^\circ) + 30 \cdot \cos(42^\circ)}\right)\)
\(\angle = 59.87^\circ\)
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Answer:
197.5 km/h
Step-by-step explanation:
You want the resultant speed with an airplane at a speed of 180 km/h at 100° is acted upon by a wind at a speed of 30 km/h at 42°. Angles are bearings CW from north.
SolutionA vector calculator makes short work of this. The resultant speed is ...
197.5 km/h at 92.6°
Law of cosines
The law of cosines can be used to find the side opposite the known angle in the triangle with sides 30 km/h and 180 km/h. The known angle is ...
180° -(100° -42°) = 122°
So, the resultant speed is ...
c = √(a²+b²-2ab·cos(C))
= √(30² +180² -2(30)(180)·cos(122°)) ≈ √39023.13
c ≈ 197.543
The true speed of the plane is about 197.5 km/h.
__
Additional comment
You will notice that we used bearing angles directly in the calculator computation. As long as angles are consistently measured, it doesn't matter how they're measured.
When plotting the vectors on the Cartesian plane, we need to subtract the bearing angles from 90° to make them correspond to the vectors plotted on a map with north at the top.
Can someone help me please
Step-by-step explanation:
sleeping in class ? :-)
these are our pure definition questions.
9. false
if the data was only defined for whole numbers, then that would be the only case, where that is true. but then, there would be no rounding.
the "significant figures" are the decimal places after the decimal point.
rounding it to one significant figure means rounding it to the first position after the decimal point.
10. True
see 9. for more details.
Figure LMNO is a reflection of HIJK. Which angle is congruent to ZH?
The angle formed by this intersection point and the corresponding point on LMNO is congruent to ZH.
In this case, we have two figures, LMNO and HIJK, and we know that LMNO is a reflection of HIJK. This means that there is an axis of reflection that maps HIJK onto LMNO.
When a shape is reflected across a line of symmetry, its angles are preserved. That is, if two angles in the original shape are congruent, then their images in the reflected shape are also congruent.
In this case, ZH is an angle in HIJK, and we want to find the angle in LMNO that corresponds to it. To do this, we need to find the line of symmetry that maps HIJK onto LMNO.
Once we have identified this line, we can draw the perpendicular bisector of ZH and find where it intersects the line of symmetry. The angle formed by this intersection point and the corresponding point on LMNO is congruent to ZH.
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after fitting a linear regression model to a dataset, the model's slope and intercept are -3 and 0 respectively. now, if we change our independent variable by adding 4.5 units to x, what is the absolute value of the change in the predicted value of dependent variable y?
The absolute value of change in the predicted value of dependent variable Y is 18.
Any variable whose value is influenced by an independent variable is said to be dependent. The thing that is measured or assessed in an experiment or mathematical equation is the dependent variable. The phrase "the outcome variable" is another name for the dependent variable.
Slope = b = -4
Intercept = a = -2.8
So, the equation of the regression line is
y = a + bx
y = -2.8 - 4x ...Equation 1
Now suppose the value of x is changed by adding 4.5
i.e. put x = x + 4.5
So,
y = -2.8 - 4(x + 4.5)
y = -2.8 -4x - 18 ...Equation 2
Comparing 1 and 2 ,
We get the predicted value of dependent variable Y as 18
Therefore The absolute value of change in the predicted value of dependent variable Y is 18
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Daniela has money automatically deposited into a savings account each week. After 3 weeks, she has $18. After 5 weeks, she has $30. The unit rate is measured in dollars per week. What is the constant of proportionality
A. 1/6
B. 12
C. 6
D. 3
Answer:
the answer is c
Step-by-step explanation:
the answer is c
which sample size will produce the widest 95onfidence interval, given a sample proportion of 0.5?  a. 60  b. 80
For a given sample proportion of 0.5, the sample size that will produce the widest confidence interval is the largest option given, which in this case is 80.
The sample size that will produce the widest 95% confidence interval, given a sample proportion of 0.5, is option b, 80. This is because the width of the confidence interval is directly proportional to the sample size, meaning that as the sample size increases, the confidence interval becomes narrower.
Additionally, the width of the confidence interval is inversely proportional to the square root of the sample size. Therefore, for a given sample proportion of 0.5, the sample size that will produce the widest confidence interval is the largest option given, which in this case is 80.
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Select the box in each row to identify the number as rational or irrational.
Answer:
rational
irrational
rational
irrational
rational
Step-by-step explanation:
the first answer here is wrong and does not fit to the problem with 5 expressions.
13/90 is rational per definition (a ratio of two natural or integer numbers).
sqrt(84) is therefore irrational.
4/11 is per definition rational.
12×pi is irrational, because pi is irrational.
4.6363636363... is rational, because it is 51/11
In a recent court case it was found that during a period of 11 years people were selected for grand jury duty and % of them were from the same ethnicity. Among the people eligible for grand jury duty, % were of this ethnicity. Use a significance level to test the claim that the selection process is biased against allowing this ethnicity to sit on the grand jury. Identify the null hypothesis, alternative hypothesis, test statistic, p-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the p-value method and the normal distribution as an approximation to the binomial distribution.
The Null and Alternative hypothesis are
Hₒ: π= 0.79
Hₐ: π > 0.79
Statistic Z = -26.38
P-value = 0
Conclusion : The null hypothesis is
rejected .
Final Conclusion : which implies that population proportion is different from
π= 0.79.. This sample proportion can notbe product of chance.
There is enough evidence to support to the claim that selection of people is biased against allowing this ethnicity to sit on the grand jury.
We have problem of proportion and we have to apply hypothesis testing in it .
We claim that the selection is biased against allowing this ethnicity to sit on the grand jury. This means that proportion of people of enthic selected for jeury in a way below from proportion that eligible for jury .
Null and Alternative hypothesis are
Hₒ: π= 0.79
Hₐ : π> 0.79
The significance level is 0.01
The sample we will use is total of 876 people that were selected for grand jury duty (n= 876). 42% of them were entnicity for which we are testing , so sample proportion is p= 0.42
The standard error is
σₚ= s√ (π(1-π)/n)= √ 0.79 (1-0.79)/ 876 = √0.00019 = 0.0137~ 0.014
Then we can calculate Z – value
Z = (p-π+0.5/n)/ σₚ =( 0.42 – 0.79 + 0.5/876 )/ 0.014 = - 0.03964/0.014 = - 26.387
P-value for this test statistic is 0
P-value (z<-26.38)= 0
P-value = 0 < 0.01
As we see that P-value is less lower then significance level . This sample result is unpredictable. The null hypothesis is rejected which implies that population proportion is different from π= 0.79
This sample proportion can not be product of chance.
There is enough evidence to support to the claim that selection of people is biased against allowing this ethnicity to sit on the grand jury.
#Complete Question:
In a recent court case it was found that during a period of 11 years 876 people were selected for grand jury duty and 42% of them were from the same ethnicity. Among the people eligible for grand jury duty, 79.5% were of this ethnicity. Use a 0.01 significance level to test the claim that the selection process is biased against allowing this ethnicity to sit on the grand jury. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. Which of the following is the hypothesis test to be conducted?
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Although, Lara Croft was successful at stopping the enemy in
Tomb Raider, it was discovered that one artifact is still missing.
Luckily, the whereabouts are known: A cruise ship leaving
Seattle. By the time Ms. Croft arrives in Seattle, she has missed
the boat by 5 hours. What should she do?
FACTS:
- The cruise ship can go 528 mi in one day.
- A speedboat travels 100 miles in 2.5 hours.
- A helicopter goes 90 mph, but takes 3.5 hours to get to the harbor.
what should Ms. Croft do? Prepare a poster answering this question
with multiple representations of your thinking.
Answer:
The time it takes Ms. Croft to reach the cruise ship by speedboat = 6.11 hours
The time it takes Ms. Croft to reach the cruise ship by helicopter = 6.25 hours
since it takes less time for Ms. Croft to reach the cruise ship by taking the speedboat, her best choice to retrieve the artifact is to take the speedboat.
Step-by-step explanation:
The given parameters are;
The elapsed time by which Ms. Croft missed the boat = 5 hours
The speed of the cruise ship = 528 mi/day
The speed of the speedboat = 100 miles in 2.5 hours
The speed of the helicopter = 90 mph
The time it would take Ms. Croft to arrive at the harbor = 3.5 hours
Therefore, we have;
The cruise ship's speed = 528 miles per 24 hours = 528/24 mph = 22 mph
The location of the cruise after the first 5 hours = 5 × 22 = 110 miles
The speed of the speedboat = 100 miles per 2.5 hours = 100/2.5 = 40 mph
By traveling with a speed boat
The time at which Ms. Croft will intercept the cruise ship is given by the following relation;
40 mph × t = 22 mph × t + 110 miles
Which gives;
40 mph × t - 22 mph × t = 110 miles
18 mph = 110 miles
t = 110 miles/(18 mph) = 55/9 hours ≈ 6.11 hours
By taking the helicopter, we have;
Upon arrival at the harbor, after 3.5 hours, we find
90 mph × t = 22 mph × t + 22 mph × 3.5 hours + 110 miles
90 mph × t - 22 mph × t = 22 mph × 3.5 hours + 110 miles
68 mph × t = 77 miles + 110 miles = 187 miles
t = 187 miles/(68 mph) = 11/4 hours = 2.75 hours
The total time it takes Ms. Croft to reach the cruise ship by taking the helicopter = 3.5 + 2.75 = 6.25 hours
Therefore, since it takes less time for Ms. Croft to reach the cruise ship by taking the speedboat, her best choice to retrieve the artifact is to take the speedboat.
Which of the following is an assumption for computing any type of independent sample t test?
a. Data in the population being sampled are normally distributed.
b. Data were obtained from a sample that was selected using a random sampling procedure.
c. The probabilities of each measured outcome in a study are independent.
d. all of the above
2. A researcher selects a sample of 16 women and asks them to rate how important a sense of humor is in someone they want a long-term relationship with. She records scores averaging 1.6±0.8 (M±SD) on a rating scale from -3 (not important at all) to +3 (very important). Assuming that an average score of 0 is the null hypothesis, test whether or not women find this trait important at a .05 level of significance.
a. Women found this trait to be important, and this result was significant, t(16) = 8.00, p < .05.
b. Women found this trait to be important, and this result was significant, t(15) = 8.00, p < .05.
c. Women did not find this trait to be important, p > .05.
d. There is not enough information to answer this question.
3. A researcher conducts two t tests. Test 1 is a one-tailed test with a smaller sample size at a .05 level of significance. Test 2 is a one-tailed test with a larger sample size at a .05 level of significance. What do you know about the critical values for each test?
a. Test 1 is associated with smaller critical values.
b. Test 2 is associated with smaller critical values.
c. Each test is associated with the same critical values.
d. It depends; there is not enough information to answer this question.
There are different ways to approach this question, but one possible method is to conduct a one-sample t-test using the formula t = (M - μ) / (s / sqrt(n)), where M is the sample mean, μ is the population mean (null hypothesis), s is the sample standard deviation, and n is the sample size. With the given information, the t-value is (1.6 - 0) / (0.8 / sqrt(16)) = 8.
The degrees of freedom is n - 1 = 15. Using a t-table or a calculator, the p-value for a one-tailed test with 15 degrees of freedom and a t-value of 8 is much smaller than .05 (e.g., < .0005). Therefore, we can reject the null hypothesis and conclude that women find a sense of humor to be important in a long-term relationship at a .05 level of significance. The correct answer is b.
Test 2 is associated with smaller critical values. The critical values for a t-test depend on the level of significance, the degrees of freedom, and whether the test is one-tailed or two-tailed. In general, a smaller level of significance or a larger sample size leads to smaller critical values (i.e., it becomes easier to reject the null hypothesis). Since Test 2 has a larger sample size than Test 1, it is more likely to detect a significant effect (i.e., have a smaller Type II error rate), and therefore requires smaller critical values to achieve a .05 level of significance. The correct answer is b.
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Montraie drove 220 miles in 5 hours. If he continued at the same rate, how long would it take to travel 88 miles?
The time taken for Montraie to travel a distance of 88 miles is 2 hours.
How long would it take for Montraie to travel 88 miles?Speed is simply referred to as distance traveled per unit time.
It expressed mathematically as;
Speed = Distance ÷ time.
Given the data in the question;
Distance covered = 220 milesTime elapsed = 5 hoursSpeed = ?First, we determine the speed of Montraie.
Speed = Distance ÷ time.
Speed = 220 miles ÷ 5 hours
Speed = 44 miles per hour.
Now, time spent in traveling a distance of 88 miles will be;
Speed = Distance ÷ time
Time = Distance / Speed
Time = 88 miles / 44 miles per hour
Time = 2 hours
Therefore, the elapsed time is 2 hours.
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If Montraie drove 220 miles in 5 hours. If he continued at the same rate, then it takes 2 hours to travel 88 miles.
What is Ratio?A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0.
Given that,
Montraie drove 220 miles in 5 hours.
We need to find how long it would take to reach 88 miles.
Let us form a equation based on given data.
Let x be the time to reach 88 miles.
We need to find value of x.
220/5=88/x
Apply cross multiplication
220x=440
x=440/220
x=2
Hence it takes 2 hours to travel 88 miles with same rate.
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A ladder leans against the side of house. The angle of elevation of the ladder 71 degrees , and the top o from the bottom of the ladder to the side of the house. Round your answer to the nearest tenth.
Answer:
72.4
use the Pythagorean theorem
713.49 written in standard form
Answer:
7.1349 * 102
Step-by-step explanation:
Hope this helps. Have a great day!
I need helo on that.
Answer:
Step-by-step explanation:
to find out the coresponding sides and angles draw 2 triangles that are the same and label them in same ORDER (I did counterclock wise) will help you see better the parts
L. T
Δ Δ
J. K. C. O
JK≅ CO, JL≅CT, KL≅OT
∠J≅∠C, ∠L≅∠T, ∠K≅∠O
ΔTRI≅ΔAGN because corsponding parts are congruent
∠I≅∠N because are coresonding angles
A) A jar on your desk contains fourteen black, eight red, eleven yellow, and four green jellybeans. You pick a jellybean without looking. Find the odds of picking a black jellybean. B) A jar on your desk contains ten black, eight red, twelve yellow, and five green jellybeans. You pick a jellybean without looking. Find the odds of picking a green jellybean.
A) The odds of picking a black jellybean are 14/37.
Step-by-step explanation:
The jar contains fourteen black, eight red, eleven yellow, and four green jellybeans.
Therefore, the Total number of jellybeans in the jar = 14+8+11+4=37
Since the question asks for odds, which is the ratio of the number of favorable outcomes to the number of unfavorable outcomes. Let us first find the number of favorable outcomes, i.e. the number of black jellybeans.
Therefore, the number of black jellybeans = 14
Now, the number of unfavorable outcomes is the number of jellybeans that are not black.
Therefore, the number of unfavorable outcomes = 37-14=23
Hence, the odds of picking a black jellybean are the ratio of the number of favorable outcomes to the number of unfavorable outcomes.
Odds of picking a black jellybean = (number of favorable outcomes)/(number of unfavorable outcomes)=14/37
Answer: Odds of picking a black jellybean are 14/37.
B) The odds of picking a green jellybean are 5/35.
Step-by-step explanation:
The jar contains ten black, eight red, twelve yellow, and five green jellybeans.
Therefore, the Total number of jellybeans in the jar = 10+8+12+5=35
Since the question asks for odds, which is the ratio of the number of favorable outcomes to the number of unfavorable outcomes. Let us first find the number of favorable outcomes, i.e. the number of green jellybeans.
Therefore, the number of green jellybeans = 5Now, the number of unfavorable outcomes is the number of jellybeans that are not green.
Therefore, the number of unfavorable outcomes = 35-5=30
Hence, the odds of picking a green jellybean are the ratio of the number of favorable outcomes to the number of unfavorable outcomes.
Odds of picking a green jellybean = (number of favorable outcomes)/(number of unfavorable outcomes)=5/30
Reducing the ratio to the simplest form, we get the odds of picking a green jellybean = 1/6
Hence, the odds of picking a green jellybean are 5/35.
Answer: Odds of picking a green jellybean are 5/35.
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Answer if correct 70 points Brainly
Answer:
I am not very sure, but I think the answer is
D.
Answer:
answer is d becuase i took the test and got it right
Step-by-step explanation:
the link is visable tho
Need help please !
Kevin and Chrissy both saved money for their class trip . Kevin saved the same amount each week . The total amount that Kevin saved at the end of every two weeks is shown in the table below .
daiiiii yo soy tu tasdio dbdsajate los pwdtaloneslaroh piodsaicasm
plz help 20 points pllllllllllllllllllllllz help mee asap
Answer:
b=4 c=7
Step-by-step explanation:
I think not positive
Answer:
453+557 = 1010
hence b is 5 and c is 3
If the average weight for women is normally distributed with a mean of 135 pounds and a standard deviation of 15 pounds, then approxi- mately 68% of all women should weigh between and pounds. a. 120; 150 b. 120; 135 c. 105; 165 d. Cannot say from the information given
This is because of the empirical rule, which states that for a normal distribution, approximately 68% of the data falls within one standard deviation of the mean. The answer is option B: 120; 135.
In this case, one standard deviation above the mean is 150 pounds (135 + 15) and one standard deviation below the mean is 120 pounds (135 - 15). Therefore, approximately 68% of all women should weigh between 120 and 150 pounds.
If the average weight for women is normally distributed with a mean of 135 pounds and a standard deviation of 15 pounds, then approximately 68% of all women should weigh between:
1. Calculate the lower limit: mean - standard deviation = 135 - 15 = 120 pounds
2. Calculate the upper limit: mean + standard deviation = 135 + 15 = 150 pounds
So, approximately 68% of all women should weigh between 120 and 150 pounds. The correct answer is option a. 120; 150.
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In a recent tennis tournament, women playing singles matches used challenges on 135 calls made by the line judges. Among those challenges, 36 were found to be successful with the call overturned.
a. Construct a 95% confidence interval for the percentage of successful challenges.
b. Compare the results from part (a) to this 95% confidence interval for the percentage of successful challenges made by the men playing singles matches: 23.6%
a) The 95% confidence interval is 18.95% to 34.49%. b) The confidence interval for women (18.95% to 34.49%) does not include the value of 23.6%.
To construct a 95% confidence interval for the percentage of successful challenges made by women playing singles matches, we can use the formula for the confidence interval for a proportion. The formula is:
Confidence Interval = p ± Z * \(\sqrt{p(1-p)/n}\)
Where:
p is the sample proportion (successful challenges / total challenges)
Z is the z-score corresponding to the desired confidence level
n is the sample size
a. Let's calculate the confidence interval for the percentage of successful challenges made by women:
Sample size (n) = 135
Number of successful challenges (x) = 36
Sample proportion (p) = x/n
p = 36/135 ≈ 0.2667
To find the z-score corresponding to a 95% confidence level, we need to calculate the critical value. Since the sample size is large enough (n > 30), we can approximate the critical value using the standard normal distribution.
The z-score corresponding to a 95% confidence level (two-tailed test) is approximately 1.96.
Confidence Interval = 0.2667 ± 1.96 * \(\sqrt{0.2667(1-0.2667)/135}\)
Calculating the confidence interval:
Confidence Interval = 0.2667 ± 1.96 * \(\sqrt{0.2667*0.7333/135}\)
= 0.2667 ± 1.96 * \(\sqrt{0.19511/135}\)
= 0.2667 ± 1.96 * 0.03943
≈ 0.2667 ± 0.07723
The lower bound of the confidence interval is:
0.2667 - 0.07723 ≈ 0.1895
The upper bound of the confidence interval is:
0.2667 + 0.07723 ≈ 0.3449
Therefore, the 95% confidence interval for the percentage of successful challenges made by women is approximately 18.95% to 34.49%.
b. To compare the results with the 95% confidence interval for the percentage of successful challenges made by men (23.6%), we can observe that the confidence interval for women does not overlap with the value for men.
The confidence interval for women (18.95% to 34.49%) does not include the value of 23.6%. This suggests that there may be a significant difference in the percentage of successful challenges made by women compared to men.
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A one-question survey is to be distributed to a random sample of 1500 adults in Ohio. The question asks if they support an increase in the state sales tax from 5% to 6%, with the additional revenue going to education. Let denote the proportion of adults in the sample who say they support the increase. Suppose that 40% of all adults in Ohio support the increase. What is the mean, , of the sampling distribution of ?
a.
40% ± 5%
b.
6%
c.
5%
d.
0.40
They support an increase in the state sales tax from 5% to 6%, with the additional revenue going to education. Let denote the proportion of adults in the sample who say they support the increase. Suppose that 40% of all adults in Ohio support the increase. the correct answer is (d) 0.40.
Mean is nothing but the average of the given set of values. It denotes the equal distribution of values for a given data
set. The mean, median and mode are the three commonly used measures of central tendency.
To calculate the mean, we need to add the total values given in a datasheet and divide the sum by the total number of
values.
The mean, μ, of the sampling distribution of p can be found using the formula
μ = p,
where p is the proportion of adults in the entire population who support the increase.
In this case, 40% of all adults in Ohio support the increase, so p = 0.40.
Therefore, the mean of the sampling distribution of p is:
μ = 0.40
So the correct answer is (d) 0.40.
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