Could you help me answer this question
Answer:
Statement 4 in true.
Step-by-step explanation:
1. f(-2)=(-3*(-2)+2)^2+(-2)=(6+2)^2+(-2)=8^2-2=62, FALSE
2. f(-5)=(-3*(-5)+2)^2+(-5)=(15+2)^2+(-5)=17^2+(-5)=289-5=284, FALSE
3. f(3)=(-3*3+2)^2+3=(-9+2)^2+3=(-7)^2+3=49+3=52, FALSE
4. f(5)=(-3*5+2)^2+5=(-15+2)^2+5=(-13)^2+5=169+5=174, TRUE
Answer:
option 4
Step-by-step explanation:
f(- 2) = (6 + 2)² - 2 = 8² - 2 = 64-2 = 62 ≠ 64
f(- 5) = (15 + 2)² - 5 = 17² - 5 = 289 - 5 = 284 ≠ 29
f(3) = (- 9 + 2)² + 3 = (- 7)² + 3 = 49 + 3 = 52 ≠ - 11
f(5) = (- 15 + 2)² + 5 = (- 13)² + 5 = 169 + 5 = 174 ← True
Let R(s, t) = F(u(s, t), v(s, t)), and assume the following are true.
u(1, 0) = 2
us(1, 0) = −2
ut(1, 0) = 6
v(1, 0) = 3
vs(1, 0) = 5
vt(1, 0) = 4
Fu(2, 3) = −1
Fv(2, 3) = 10
Find the values below.
Rs(1, 0) =
Rt(1, 0) =
Answer:
To find Rs(1,0) and Rt(1,0), we need to use the chain rule of partial differentiation.
Rs(1,0) can be found by computing the partial derivative of R with respect to s, while holding t constant and then evaluating the result at (1,0). Similarly, Rt(1,0) can be found by computing the partial derivative of R with respect to t, while holding s constant and then evaluating the result at (1,0).
Using the chain rule, we have:
Rs = Fu * us + Fv * vs
Rt = Fu * ut + Fv * vt
We are given the values of u, v, us, ut, vs, vt, Fu, and Fv at the point (1,0) and the values of u and v at the point (2,3). We can use these values to compute Rs(1,0) and Rt(1,0) as follows:
Rs(1,0) = Fu(2,3) * us(1,0) + Fv(2,3) * vs(1,0)
= (-1) * (-2) + (10) * (5)
= 52
Rt(1,0) = Fu(2,3) * ut(1,0) + Fv(2,3) * vt(1,0)
= (-1) * (6) + (10) * (4)
= 34
Therefore, Rs(1,0) = 52 and Rt(1,0) = 34
If x = 3 and y = 5 then which of the following expression has the value ( -8)
당신에게 도움이됩니다
\(( - 3) - 5 \\ = ( - 8)\)
if x = y and y=z which statement is true?
Answer:
Step-by-step explanation:
if x = y, and y = z, you can write that as x = y = z, which means that x = z
I set z=t=0(x,y,z,t)
and I got a partial solution (0,1,0,0).
I solved two homogeneous matrices once for z=1
and t=0
, then for z=0
and t=1
and I got two solutions (1,1,1,0)
and (1,1,0,1).
Then, I got (0,1,0,0)+a∗(1,1,1,0)+b∗(1,1,0,1
)
Therefore, all possible results are (0,1,0,0),(1,0,1,0),(1,0,0,1),(0,1,1,1)
Would this be correct?
The correct set of possible results would be (0, 1, 0, 0), (1, 2, 1, 0) and (1, 2, 0, 1).
Your approach seems to be correct, but there seems to be a minor mistake in your final list of possible solutions. Let's go through the steps to clarify.
Given the initial conditions z=t=0, you obtained a partial solution (0,1,0,0).
Next, you solved the homogeneous equations for z=1 and t=0, which resulted in a solution (1,1,1,0).
Similarly, solving the homogeneous equations for z=0 and t=1 gives another solution (1,1,0,1).
To find the general solution, you combine the partial solution with the solutions obtained in the previous step, using parameters a and b.
(0,1,0,0) + a(1,1,1,0) + b(1,1,0,1)
Expanding this expression, you get:
(0+a+b, 1+a+b, 0+a, 0+b)
Simplifying, you obtain the following set of solutions:
(0, 1, 0, 0)
(1, 2, 1, 0)
(1, 2, 0, 1)
Therefore, the correct set of possible results would be:
(0, 1, 0, 0)
(1, 2, 1, 0)
(1, 2, 0, 1)
Note that (0, 1, 1, 1) is not a valid solution in this case, as it does not satisfy the initial condition z = 0.
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Evaluate m³ +n if m= 1.2 and n = 13
Answer:
14.728
Step-by-step explanation:
m³ + n if m = 1.2 and n = 13
= (1.2)³ + 13
= 1.728 + 13
= 14.728
x, y, and z are identifier of boolean type with values, true, false, and false repectively. What is the value of the following logical expression:
(x || y) || (y || z)
The overall value of the logical expression (x || y) || (y || z) is true.
The value of the logical expression (x || y) || (y || z) can be determined by evaluating the OR (||) operator between the given boolean identifiers.
Given that x is true, y is false, and z is false, we can substitute these values into the expression:
(true || false) || (false || false)
The OR operator returns true if at least one of the operands is true. Evaluating each sub-expression:
true || false evaluates to true.
false || false evaluates to false.
Substituting the results back into the main expression:
true || false evaluates to true.
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How do you write 80% as a decimal?
Answer:
0.8
Step-by-step explanation:
plz help me i have been asking this question way too much will give brainiset
Answer:
A. 5 in= 5/12 ft
B. 13 in= 1 1/12 ft
C. 9 oz = 9/16 Ib
D. 18 oz = 1 1/8 lb
If the endpoints of AB are located at (0,7) and (8,8) what is the length of AB?
Answer:
√65
Step-by-step explanation:
The distance formula can be represented as
\(\sqrt{(x_{2} -x_1)^2 + (y_2-y_1)^2}\)
Taking (8,8) as (x₂, y₂) and (0,7) as (x₁, y₁), we have
\(\sqrt{(8 -0)^2 + (8-7)^2}\\= \sqrt{8^2 + 1^2}\\= \sqrt{65}\)
as our answer
Help will give brainliest and don't put any links or I will report u and thx
Answer:
option H.
Line A increase more rapidly than B
hope it helps
Find
the
reciprocal
0f
0.65 to three
Significant
figurs
Answer:
100/ 56
Step-by-step explanation:
100/65 because 0.65 is a decimal number
hope it helps!
Answer:
100/65 because 0.65 is in decimal
Kindly help to solve questions
Applying notable products, the expanded expressions are given by:
a) (x + 1)² = x² + 2x + 1.
b) (x - 2)² = x² - 4x + 4.
c) (x + 3)² = x² + 6x + 9.
What is the notable product for the square of the sum?The notable product for the square of the sum is given by:
(a + b)² = a² + 2ab + b².
Hence:
a) (x + 1)² = x² + 2x + 1.
c) (x + 3)² = x² + 6x + 9.
What is the notable product for the square of the subtraction?The notable product for the square of the subtraction is given by:
(a - b)² = a² - 2ab + b².
That is, just the middle term changes compared to the square of the sum.
Hence:
b) (x - 2)² = x² - 4x + 4.
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To solve the following system by elimination of the x terms, if the first equation were multiplied by -4, by what number would you multiply the second equation?
Answer:
6
Step-by-step explanation:
Multiply by 6 and you can eliminate x or y.
please answer the questions
If a car is going 100 Miles Per Hour, how many miles does the car go in one hour?
PLEASE HELP THIS IS VERY HARD!!!
If a car is going 100 miles per hour, the car goes 100 miles in one hour.
Answer:36 seconds
Step-by-step explanation:
100 miles per hour, it would take me approximately 36 seconds to travel 1 mile.
Need help this is due in 20 minutes
Answer:
X=4 hope I help
Step-by-step explanation:
llllllllll
What is the probability of rolling a sum of 5 on a standard pair of six-sided dice? express your answer as a fraction or a decimal number rounded to three decimal places, if necessary
The probability of rolling a sum of 5 on a standard pair of six sided dice is 1/9.
According to the given question.
A standard pair of dice is rolled.
So, the sample sapce for rolling a pair of dice = {(1,1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3), (5, 4),(5, 5),(5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}
⇒ Total number of outcomes = 36
And, the outcomes for getting a sum of five on a sandard pair of six sided dice = {(2, 3), (3, 2), (4, 1), (1, 4)}
⇒ Total number of favorable outcomes = 4
As we know that " probability is the ratio of total number of favorable outcomes to the total number of outcomes".
Therefore,
The probability of rolling a sum of 5 on a standard pair of six-sided dice
= 4/36
= 1/9
Hence, the probability of rolling a sum of 5 on a standard pair of six sided dice is 1/9.
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what is the transitive property
Answer:
the transitive property of uniformity reveals to us that on the off chance that we have two things that are equivalent to one another and the subsequent thing is equivalent to a third thing, at that point the primary thing is additionally equivalent to the third thing. The recipe for this property is in the event that a = b and b = c, at that point a = c.
I have attached the definition below with an example too.
Sharlene purchased a new truck, whose value over time depreciates. Sharlene's truck depreciates according to the function y = 45,529(0.78)x, where x represents the number of months since the truck was purchased. What is the range of the exponential function y based on its equation and the context of the problem?
Based on the context of the problem, the range of the exponential function y = \(45,529(0.78)^x\) is y > 0.
The exponential function for depreciation given in the problem is:
y = 45,529(0.78)^x
This function gives us the value of Sharlene's truck in dollars after x months of ownership, assuming that the depreciation follows a constant rate and is modeled by an exponential function.
To find the range of the function, we need to consider the minimum value that y can take. Since depreciation leads to a decrease in value over time, y should always be greater than zero. In other words, the range of the function is:
y > 0
In practical terms, this means that Sharlene's truck will always have some positive value, even if its market value has decreased due to depreciation. In other words, a truck is never worth zero or less than zero (unless it has additional debts associated with it), and Sharlene's truck will always have some resale or scrap value even if it has depreciated significantly.
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Find the perimeter of the polygon Direct lines are for measurement references only and don’t affect the perimeter. If a polygon Appears to be regular you can assume it is
Recall that the perimeter of a figure is the sum of the lengths of its sides.
From the given diagram, we get that the figure has
\(12\text{ sides,}\)and each side measures 5.75 m.
Therefore, the perimeter of the figure is:
\(12*5.75m.\)Finally, we get that the perimeter is:
\(69m.\)Answer: \(69m.\)The sum of 1/2 and 2/3 is ??? 1
Answer:
5/6
Step-by-step explanation:
1/2 + 1/3 You first multiply 1/2 by 3 and 1/3 by 2
3/6 + 2/6 then you add
5/6
Step-by-step explanation:
1/2 + 2/3
find the LCM of 2 and 3
LCM =6
1/2 + 2/3
(you'll divide 6 by the denominator and multiply by the numerator)
denominator= the figure down(2 &3)
numerator= the figure up (1 & 2)
= 3/6 +4/6
=7/6
HELP ASAP WILL MARK AS BRAINLIST IF CORRECT
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these triangles are similar. Find?
EFG ~ TUV
The circumference of a circle is 11π m. What is the area, in square meters? Express your answer in terms of π.
If geometry symbol represented as small triangle with three sides. abc a geometry symbol represented as small triangle with three sides. dec, what is the value of x?
The value of x = 1 so the correct answer is option D.
The complete question is attached in the image below.
What is coordinate geometry?A coordinate plane is a 2D plane that is formed by the intersection of two perpendicular lines known as the x-axis and y-axis.
Given that triangles ABC and DEC are congruent to each other.
We are to find the value of x.
From the figure, we note that
AB = 4x - 1, BC = 4, AC = 5, DE = x+2, CE = 4 and EC = 5.
Since ΔABC ≅ ΔDEC, their corresponding sides will be equal.
Therefore, we must have
AB = DE
4x - 1 = x + 2
4x - x = 2 + 1
3x = 3
x = 1
Thus, the required value of x is 1.
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RSM 174f) absolute value of x+1 plus absolute value of x-2 is equal to 3
The absolute value of x + 1 is added to the absolute value of x - 2 is equal to 3. So the value of x is equal to -1, 0 and 2.
To solve the equation | x + 1 | + | x - 2 | = 3. We need to find out the possible cases based on the signs of x + 1 and x - 2. In case of x is less than or equal to -1, both expressions inside the absolute value signs are negative.
f(x ≤ - 1) = | -1 + 1 | + | -1 - 2 | = 3
f(x ≤ - 1) = 0 + 3 = 3
So x can be less than or equal to be -1.
In case, when x = 0, expressions inside the absolute value bars will be positive & negative, so we can rewrite the equation as 0 + 1 + 0 + 2 = 3, which simplifies to x = 0
f(x = 0) = |0 + 1 | + | 0 - 2 | = 3
f(x = 0) = 1 + 2 = 3
so x can be equal to 0.
When x ≥ 2, both expressions inside the absolute value bars will be positive, so we can rewrite the equation as x + 1 + x - 2 = 3, which simplifies to 2x = 4, or x = 2.
f(x ≥ 2) = | 2 + 1 | + | 2 - 2 | = 3
f(x ≥ 2) = 3 + 0 = 3
so x can be greater than or equal to 2.
Therefore, the solutions to the equation |x + 1| + |x - 2| = 3 are x = - 1, x = 0 and x = 2.
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The difference of two numbers is 18, and their sum is 90.
Find the two numbers
Answer:
54 and 36
Step-by-step explanation:
when we add 54 and 36 we get 90 and when we subtract 54 from 36 we get the difference 18
Answer:
54 and 36
explanation
Is the following relation a function?
Answer:
no
Step-by-step explanation:
the x value (-1) repeats therefore it ain't a function
A small rectangular pyramid shaped metal object made of a single metal is found in an archaeological dig. Because of the metals available to the area’s inhabitants at the time, scientists believe the metal could be either iron, lead, nickel, or silver. The weight of the object is 612.4 grams. The rectangular base of the pyramid is 3 cm by 6 cm and the height is 9 cm. The density for each metal is shown below: Iron: 7.874 grams/cm 3 Lead: 11.34 grams/cm 3 Nickel: 8.908 grams/cm 3 Silver: 10.49 grams/cm 3 Select the metal shown below that was used to construct the small rectangular pyramid-shaped metal object found in the archaeological dig. A. Iron C. nickel B. Lead D. silver
The metal that was used to construct the small rectangular pyramid-shaped metal object found in the archaeological dig is B. Lead of density \(11.34 grams/cm^{3}\)
Given :
The weight of the object is 612.4 grams.
The Height of the object = 9cm
The Breadth of the rectangular base = 3cm
The Length of the rectangular base = 6cm
Area of the rectangular base = Length*Breadth = 3*6 sq. cm = 18 sq. cm
Calculating the volume of the Object,
Volume = \(\frac{Length*Width*Height}{3}\)
Volume = \(\frac{6*3*9}{3} = 54 cm^{3}\)
Now, Calculating density,
\(Density = \frac{Mass}{Volume }\\\\\)
Putting the values of mass and volume, we have \(Density =\frac{612.4}{54} = 11.34 grams/cm^{3}\)
Hence, the density of the material is \(11.34 grams/cm^{3}\)
The density matches the density of LEAD.
Hence, the metal that was used to construct the small rectangular pyramid-shaped metal object found in the archaeological dig was B. Lead
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