Please somebody help me which property of the powder is identified by the data a. It’s mass and volume do not change with the temperature be. It’s temperature remains the same as mass is increased see. It’s texture remains the same as temperature or volume are increased D. It’s sellability and water does not change with the temperature
Answer: I think it is this: Its texture remains the same as temperature or volume is increased.
Explanation:
explain the difference between a ligand-gated k channel and a voltage-gated k channel. match the words in the left column to the appropriate blanks in the sentences on the right. make certain each sentence is complete before submitting your answer. resethelp 1. the ligand-gated channel opens or closes in response to blank .target 1 of 2 2. the voltage-gated channel opens or closes in response to blank .
The voltage-gated ion channels allows permeation of only one type of ion whereas, ligand-gated channels are less selective and allows permeation of two or more types of ions via the channel pore.
What is the difference between ligand-gated and voltage gated K channels?Ligand-gated ion channels are integral membrane proteins that contain a pore which allows regulated flow of selected ions across plasma membrane. Voltage-gated potassium channels are transmembrane channels specific for potassium and are sensitive to voltage changes in the membrane potential of cell .
1. Ligand-gated channel opens or closes in response to blank the binding of a ligand.
2. Voltage-gated channel opens or closes in response to differences in membrane potential.
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How are satellites used in GPS?
to keep the International Space Station in orbit
to communicate with the International Space Station
to communicate with possible extraterrestrial life
to pinpoint specific locations on Earth
Answer:
To pinpoint specific locations on Earth
Explanation:
The satellite has a full specific view of a specific area just like other satellites do. Satellites communicate together which also communicates with your GPS to give you an accurate location where you are or where you want to be. That is how satellites are used in GPS.
Hope this helps you out :)
a 0.5 kg car is moving at a constant velocity 5 m/s. What is the kinetic energy of the car?
For a specific gas, how does its emission spectrum relate to its absorption spectrum?
a) Bright lines in its emission spectrum have different wavelengths than the dark lines of its absorption spectrum.
b) They do not relate directly.
c) Dark lines in its emission spectrum have the same wavelengths as the bright lines of its absorption spectrum.
d) Bright lines in its emission spectrum have the same wavelengths as the dark lines of its absorption spectrum.
Bright lines in its emission spectrum have the same wavelengths as the dark lines of its absorption spectrum. Hence, option (d) is correct.
What are emission spectrum and absorption spectrum?The electromagnetic radiation spectrum that is emitted when an atom or molecule changes from a high energy state to a lower energy state is known as the emission spectrum of a chemical element or chemical compound.
Absorption spectrum: An electromagnetic spectrum where a drop in radiation strength at particular wavelengths or ranges of wavelengths indicative of an absorbing substance (such as chlorophyll) is particularly visible as a pattern of dark lines or bands, in contrast to emission spectrum.
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A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm,find the emf of the cell.
A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.
To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.
Given:
Resistance of the coil, R1 = 4 ohm
Resistance of the other resistor, R2 = 8 ohm
Current passing through the 8-ohm resistor, I = 2A
First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.
The total resistance of two resistors in parallel can be calculated using the formula:
1/Rp = 1/R1 + 1/R2
Substituting the given values, we have:
1/Rp = 1/4 + 1/8
1/Rp = 2/8 + 1/8
1/Rp = 3/8
Rp = 8/3 ohm
Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).
R_total = R_internal + Rp
R_total = 0.5 + 8/3
R_total = 1.833 ohm
Now, we can find the emf of the cell using Ohm's Law:
emf = I * R_total
emf = 2 * 1.833
emf ≈ 3.667 volts
Therefore, the emf of the cell is approximately 3.667 volts.
However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.
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How much impulse is imparted on a 0.14 kg baseball initially traveling at 32 m/s when it is struck by a baseball bat and begins to travel in the opposite direction at 49 m/s
ANSWER AND EXPLAINATION:
To calculate the impulse imparted on the baseball, we can use the impulse-momentum principle, which states that the impulse experienced by an object is equal to the change in momentum of the object. Mathematically, it can be expressed as:
Impulse = Change in momentum
The momentum of an object is given by the product of its mass and velocity:
Momentum = mass × velocity
In this case, the baseball has an initial mass of 0.14 kg and an initial velocity of 32 m/s. After being struck by the bat, it travels in the opposite direction at a velocity of 49 m/s.
Therefore, the change in momentum is given by:
Change in momentum = (mass × final velocity) - (mass × initial velocity)
Change in momentum = mass × (final velocity - initial velocity)
Change in momentum = 0.14 kg × (49 m/s - (-32 m/s))
Change in momentum = 0.14 kg × (49 m/s + 32 m/s)
Change in momentum = 0.14 kg × 81 m/s
Change in momentum = 11.34 kg·m/s
So, the impulse imparted on the baseball is 11.34 kg·m/s.
2 point
Question 9
An object is shot from the ground at 75m/s at an angle of 45° above the horizontal. How high does the object get before beginning its descent?
Answer:
Before beginning its descent, the object gets 143.5 meters high
Explanation:
Projectile Motion
It's known as the type of motion that experiences an object that is projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.
Being vo the initial speed of the object, θ the initial launch angle, and \(g=9.8m/s^2\) the acceleration of gravity, then the maximum height reached by the object is:
\(\displaystyle y_m=\frac{v_o^2\sin^2\theta}{2g}\)
The object is shot at vo=75 m/s at an angle of θ=45°. The maximum height is calculated below:
\(\displaystyle y_m=\frac{75^2\sin^2 45^\circ}{2\cdot 9.8}\)
\(\displaystyle y_m=\frac{5625\cdot 0.707^2}{19.6}\)
\(y_m=143.5\ m\)
Before beginning its descent, the object gets 143.5 meters high
Refraction in ocean waves is identical to refraction in sound and energy waves in that it involves movement through a different medium.a. Trueb. False
Answer:
True
Explanation:
Refraction is the change in the speed, wavelength and direction of a wave as it crosses the boundary between two different media of different densities.
Hence, refraction always involves the movement of a wave from one medium to another. This is the key point to be remembered whether we are discussing refraction in ocean waves or sound waves.
A car accelerates uniformly from rest to a speed of 55.0 mi/h in 13.0 s. (a) Find the distance the car travels during this time. m (b) Find the constant acceleration of the car. m/s2
Answer:
(a) 159.84 m
(b) 1.89 m/s²
Explanation:
Applying,
(a)
s = (v+u)t/2.................. Equation 1
Where s = distance traveled by the car, u = initial velocity, v = final velocity, t = time.
From the question,
Given: u = 0 m/s ( from rest), v = 55 mi/h = (55/2.237) m/s = 24.59 m/s, t = 13 s
Substitute these values into equation 1
s = (24.59+0)13/2
s = 159.84 m
(b)
Also applying,
a = (v+u)/t................. Equation 2
Where a = acceleration of the car.
substituting into equation 2,
a = (24.59+0)/13
a = 1.89 m/s²
1. A 75 g particle is moving to the left at 25 m/s . How much net work must be done on the particle to cause it to move to the right at 47 m/s ?
2. A 8.0-cm-long spring is attached to the ceiling. When a 2.3 kg mass is hung from it, the spring stretches to a length of 16 cm.
A. What is the spring constant k ?
B. How long is the spring when a 3.0 kg mass is suspended from it?
The net work must be done on the particle to cause it to move to the right at 47 m/s is 59.4J, The spring constant of spring is 281.75N/m and the length of spring stretched is 0.02m.
(1.)Given the mass of particle (m) = 75g = 0.075kg
The velocity of particle (Vl) towards left = 25m/s
The velocity of particle towards right (Vr) = 47m/s
The work done to move the particle from left to right = W
Here work done can be considered as change in Kinetic energy then:
W = (KEf - KEi)
\(W = 1/2*m*Vr^2 - 1/2*m*Vl^2\)
\(W = (1/2)*75 g*(47 m/s)^2 - (1/2)*75 g*(25 m/s)^2\)
\(W = (1/2)*75 g*(1584 m^2/s^2)\)
W = 59.4J
Therefore, the net work required to cause the particle to move from 25 m/s to 47 m/s is 59.4 J.
(2.) Given the length of spring = 8cm = 0.08m
The mass of block = 2.3kg
The extension in spring = 16cm = 0.16m
Let the spring constant = k
(A) We know that the force exerted in stretching the spring = F = kx where
F = mg then
mg = kx
2.3 * 9.8 = k * (0.16 - 0.08)
k = 22.54/0.08 = 281.75N/m
(B) The mass of new block = 3kg
Let the extended spring = x'
Then mg = kx' such that:
3 * 9.8 = 281.75 * x'
x' = 29.4/281.75 = 0.10m
the extension in spring = 0.10 - 0.08 = 0.02m
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Determine the distance that a tennis ball will travel in 2.5 seconds if it has a velocity of 45 m/s
Answer: 112 m/s
Explanation:
Making the material you are trying to memorize personally meaningful to you is called the ____________.
a. constructive effect.
b. elaborative effect.
c. self-referencing effect.
d. flashbulb memory effect.
Answer:
Making the material you are trying to memorize personally meaningful to you is called the?
c. self-referencing effect.
xXxAnimexXx
4.
a) A loaded box car has a total mass of 6.80 x 10 kg. If the train is travelling at a speed
of 23.7 m/s, what is the mechanical kinetic energy of the box car?
b) If a family car has a mass of 1237 kg, how fast would it have to go to have the same
mechanical kinetic energy as the box car in part a)?
GIVING BRAINLIEST
Mechanical kinetic energy is the energy of an object due to its motion.
a) Mechanical kinetic energy = (1/2)*mass*(velocity)^2
Mechanical kinetic energy = (1/2)*(6.80 x 10^3 kg)*(23.7 m/s)^2
Mechanical kinetic energy = 3.27 x 10^7 J
b) The mechanical kinetic energy of a moving object can be calculated using the following formula:
KE = 0.5 * m * v²,
where m is the mass of the object and v is the velocity.
In this case, we know the mass of the family car (1237 kg) and the mechanical kinetic energy of the box car (50444 J). To calculate the speed of the family car, we can rearrange the formula to solve for v:
v = √(2*KE/m)
v = √(2*50444/1237)
v = 42.62 m/s
What is Mechanical kinetic energy?
Mechanical kinetic energy is the energy associated with the movement of a body or object. It is also known as the energy of motion and is equal to one half of the mass of the object multiplied by the square of its velocity.
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1. Which of the following does not affect the resistance of a wire?
a) Length
b) Temperature
c) Usage time
d) Cross-sectional area
2. If a 12V battery is passing current through a resistor with a current of 2A, what is the value of the resistor?
a 24resistance
b) 14resistance
c) 10resistance
d) 6resistance
3. Describe the differences between series and parallel circuits.
4. A circuit contains resistors of 8resistance and 4resistance,what is combined resistance if the resistors are combined:
a) In series
b) In parallel
5. A 0.5A current is passing across three resistors of 8resistance, 4resistance and 12resistance that are linked in series.
What is the potential difference of the circuit?
6. Wire A has a resistance of 24resistance. If wire B is double the length and has a diameter four times as large as wire A, what is the resistance of wire B?
Nowadays, the average person encounters more than a hundred advertisements a day, be it in the form of TV and radio commercials, billboards, online promotions, and print ads, among many others. From all the advertisements you encounter, which one caught your attention? Why? Looking at the root of it, what was the underlying cause of the promotion? What does it target? Whom does it target? How does it convey message to target clientele? Is the promoted product a trend or a fad? ESSAY WRITTING PLEASE HELP ME
The essence of the commercial is to draw the attention of the public to the products of a firm.
What is a commercial?Commercials are the primary ways by which companies promote their products. The essence of the commercial is to draw the attention of the public hence the commercial is designed with music graphics and other means that aid effective communication.
The commercial that got my attention is that of the United Bank for Africa owing to the beautiful blend of orchestra music used in the advertisement which appeals immediately to the mind. The advert targets the business class in the society and aims at granting soft credit to small and medium scale entrepreneurs. It conveys its message to the clientele via music. The advert can be regarded as a trend.
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Which high-level clouds typically form when a broad layer of air is lifted by large scale convergence?
Cirrus is a high-level clouds typically form when a broad layer of air is lifted by large scale convergence.
High-altitude clouds that typically consist of ice crystals and form above 20,000 feet (6,000 meters).When the sun is low on the horizon, high-level clouds, which are typically thin and white in appearance, can produce a variety of colors.
Clouds, which resemble white fluffy cotton balls or piles, demonstrate the vertical motion or thermal uplift of air occurring in the atmosphere.A flat cloud base, whose height is determined by the humidity of the rising air, indicates the point at which condensation and cloud formation start to occur. The cloud base is lower when the air is more humid. These clouds' tops can soar above 60,000 feet (18,000 meters).
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QUESTION 12
A cannonball is launched with initial speed 56 m/s, and hits a target at speed 35 m/s. Which of the following is correct?
The target was higher than the cannon
O The target was below the height of the cannon
O The target was at the same height as the cannon
Answer:
The target was higher than the cannon
Explanation:
Given that a cannon ball is launched with initial speed 56 m/s, and hits a target at speed 35 m/s.
The initial velocity must be 56 m/s, while the final velocity will be 35 m/s.
When an object is thrown upward with an initial velocity, the object continues to move upwards with decreasing in magnitude of velocity till it reaches the maximum height where the final velocity will be equal to zero.
In this question, since the final velocity is less than the initial velocity, we can conclude that the target is higher.
Therefore, the target was higher than the cannon.
1. On this graph, what is the change in velocity between 5 seconds and 8 seconds?
what do you mean by the mechanical advantage of a leaver is 4.
Explanation:
the ratio of the force produced by a machine to the force applied to it, used in assessing the performance of a machine Is mechanical advantage
If u apply force 1N to lever it will generate a force of 4N
The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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A block with mass 0.50 kg is forced against a horizontal spring of negligible mass, compressing the spring a distance of 0.20 m . When released, the block moves on a horizontal tabletop for 1.00 m before coming to rest. The spring constant k is 100 N/m. What is the coefficient of kinetic friction between the block and the tabletop
Answer:
μ = 0.41
Explanation:
\(\frac{1}{2} kx^2 = \mu mgd\)
\(\mu = (\frac{1}{2} kx^2)/mgd\)
\(\mu = (\frac{1}{2} (100)(0.2)^2)/(0.5)(9.81)(1)\)
\(\mu = 0.41\)
The coefficient of kinetic friction between the block and the tabletop is 0.41.
The given parameters;
mass of the block, m = 0.5 kgextension of the spring, x = 0.2 mspring constant, K = 100 N/mThe coefficient of kinetic friction between the block and the tabletop by applying the principle of conservation of energy as shown below.
Fd = Uₓ
μmgd = ¹/₂kx²
where;
μ is the coefficient of kinetic frictionThe coefficient of kinetic friction between the block and the tabletop;
\(\mu_k = \frac{kx^2}{mgd} \\\\\mu_k = \frac{100\times 0.2^2}{2\times 0.5\times9.8 \times 1 } \\\\\mu_k = 0.41\)
Thus, the coefficient of kinetic friction between the block and the tabletop is 0.41.
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A rollar coaster moves over the creast at location 1 at 10 m/s. HOw fast is it going at location 4? Neglect friction and air resistance.
The velocity of the roller coaster at location 4 is 14.14 m/s (approx) using the given values of v₁ = 10 m/s, h₁ = 30 m, and h₂ = 15 m.
Roller coasters are fascinating machines that deliver an exhilarating experience by defying gravity and physics. Roller coaster physics is a significant concept to comprehend before riding a roller coaster or designing one. The laws of physics govern the motion of a roller coaster, including its velocity, acceleration, and potential energy.
A roller coaster moves over a crest at location 1 with a speed of 10 m/s. The question is how fast it's going at location 4, considering the neglect of friction and air resistance. To solve this, we'll need to consider the conservation of energy law.
The total energy of the roller coaster remains constant throughout the ride, and we can convert between potential and kinetic energy.Using the conservation of energy formula, which is: E1 = E2Where E1 is the total energy of the roller coaster at the crest and E2 is the total energy of the roller coaster at location 4.
Both E1 and E2 comprise kinetic energy (KE) and potential energy (PE). So,E1 = KE1 + PE1E2 = KE2 + PE2Since the roller coaster has no friction and air resistance, we can assume that PE1 = PE2 because the height of the roller coaster doesn't change. The energy is converted from potential energy at the crest to kinetic energy at location 4.
We can now use the formula for kinetic energy:KE = (1/2) mv²Where m is the mass of the roller coaster and v is its velocity. Both E1 and E2 can be written in terms of KE, so: E1 = (1/2) mv₁²E2 = (1/2) mv₂².
Substitute the values into the conservation of energy formula: E1 = E2(1/2) mv₁² = (1/2) mv₂²
Simplifying the equation gives:v₂² = v₁²×(h₁ / h₂)
where h₁ is the height of the crest and h₂ is the height of location 4.
To calculate the velocity, we need to take the square root of both sides:v₂ = v₁×√(h₁ / h₂)
Therefore, the velocity of the roller coaster at location 4 is 14.14 m/s (approx) using the given values of v₁ = 10 m/s, h₁ = 30 m, and h₂ = 15 m.
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Write a note on "Geology".
Answer:
the science that deals with the earth's physical structure and substance, its history, and the processes that act on it.
Explanation:
Hope that helps
Water flows at a speed of 13 m/s through a pipe that has a diameter of 1.2 m. What is the
diameter of the smaller end of the pipe that the water comes out with a speed of 30 m/s?
The diameter of the smaller end of the pipe is approximately 0.78 meters.
To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.
The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity
Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2
Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2
Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30
Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30
0.36 * 13 = (diameter2/2)^2 * 30
4.68 = (diameter2/2)^2 * 30
Dividing both sides by 30:
0.156 = (diameter2/2)^2
Taking the square root of both sides:
0.39 = diameter2/2
Multiplying both sides by 2:
0.78 = diameter2
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Under electrostatic conditions, the electric field just outside the surface of any charged conductor
A. is always zero because the electric field is zero inside conductors
B. can have non zero components perpendicular to and parallel to the surface of the conductor
C. is always perpendicular to the surface of the conductor
D. is always parallel to the surface
E. is perpendicular to the surface of the conductor only if it is a sphere, a cylinder, or a flat sheet.
Answer:
C. is always perpendicular to the surface of the conductor
Explanation:
On a charged conductor , electric charge is uniformly distributed on its surface . The lines of forces are also uniformly distributed on all directions . They repel each other so they emerge perpendicular to the surface so that they do nor cut each other and at the same time they remain at maximum distance from each other.
an object is moving on a horizontal frictionless surface. if the net force applied to the object in the direction of motion is doubled, the magnitude of the acceleration of the object is
1. halved
2. doubled
3. unchanged
4. quadrupled
Using the information from the movie champions what is one conclusion about the history of the sports
One of the conclusion about the history of sports that can be drawn from the movie "Champions" is that sports have a long and rich history that is intertwined with the history of human civilization.
What is Champions about?From the ancient Olympic Games to the modern-day Olympics, sports have been a way for people to come together and compete in a spirit of sportsmanship and competition. Sports have also been a way for people to express themselves, to build community, and to achieve personal goals.
The movie "Champions" tells the story of a group of young men who come together to form a football team. The team is made up of boys from different backgrounds and with different abilities. However, they are all united by their love of football and their desire to win.
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What is the economic term for the act of sacrificing one good or service to purchase or produce another?
Answer:
Trade-off. sacrificing one good or service to purchase or produce another.4. A 9000 kg train car travelling at 4.5 m/s inellastically collides with a 7500 kg train car at rest. If
all of the kinetic energy not conserved in this collision goes into increasing the internal energy of
the cars, how many Joules were absorbed?
Answer:
91125Joules
Explanation:
Given data
M1= 9000 kg
U1= 4.5m/s
M2= 7500 kg
U1= 0 m/s
KE1= 1/2M1U1^2
KE1= 1/2*9000*4.5^2
KE1= 1/2*9000*20.25
KE1= 1/2*182250
KE1=91125joules
KE2= 1/2M2U2^2
KE1= 1/2*7500*0^2
KE1=0 joules
Hence the energy absorbed is
E= KE1-KE2
E= 91125-0
E= 91125Joules