Answer:14.9s
Explanation:
a ceramic rod that is 10 cm long has a thermal expansion coefficient of 8 x 10-5 °c-1. what percent strain elongation does the rod undergo when it undergoes a temperature increase of 1000°c?
0.8 percent strain elongation does the rod undergo when it undergoes a temperature increase of 1000°c
As per given information;
Thermal expansion coefficient = \(8\times10^{-5}\)°\(C^{-1}\)
The original length of the rod = 10 cm
change in temperature = 1000°c
The change in length of the ceramic rod ΔL can be calculated using the formula:
ΔL = α * L * ΔT
where:
α = thermal expansion coefficient
L = original length of the rod
ΔT = change in temperature
By placing in the values given in the problem,
we get:
ΔL = (\(8\times10^{-5}\)°\(C^{-1}\)) * (10 cm) * (1000 °C)
ΔL = 0.08 cm
By using the formula we can calculate the percent strain elongation (ε) :
ε = (ΔL / L) * 100%
where:
ΔL denotes a change in the length of the rod
L denotes the original length of the rod
By plugging in the values, we get:
ε = (0.08 cm / 10 cm) * 100%
ε = 0.8%
Therefore, the ceramic rod undergoes a percent strain elongation of 0.8% when it undergoes a temperature increase of 1000°C.
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12. In the last three months mr sharma lost 11\2 kg gained 9\4 kg and then lost 15\4 kg. if he now weigh 95 kg, how much did me sharma weigh to begin with ?
(a)100 kg (b)102kg
(c) 106.5. (d) 104kg
Answer:
(b) 102 kg
Explanation:
95 +15/4- 9/4+11/2 = 102 kg
when refrigeration is being charged with a vapor from a refrigerant sylinder that is not being warmed, what will happend to the pressure of the cylinder
The refrigerant undergoes this process with a rise in volume and enthalpy but no change in pressure or temperature.
A thermodynamic cycle called the refrigeration cycle is used to remove heat from a particular location that you want to chill.
A heat pump cycle is another name for the refrigeration cycle. This cycle is intended for heat pumps, air conditioners, and refrigeration systems.A mechanical device called a heat pump is used to move heat from a low-temperature reservoir to a high-temperature reservoir.The refrigerant absorbs heat from the cold reservoir and turns it into vapor as it enters the evaporator at low pressure and low temperature. The refrigerant undergoes this process with a rise in volume and enthalpy but no change in pressure or temperature.Learn more about refrigeration here:
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a golf club exerts an average horizontal force of 1000 n on a 0.045-kg golf ball that is initially at rest on the tee. the club is in contact with the ball for 0.0018 s. what is the speed of the golf ball just as it leaves the tee?
The speed of the golf ball just as it leaves the tee is 40 m/s.
The force applied over a period of time is equal to the change in momentum of the ball. Thus, the initial momentum of the ball is 0 and the final momentum is equal to the force multiplied by the time.
Final Momentum = Force x Time
Final Momentum = 1000 N x 0.0018 s
Final Momentum = 1.8 kg m/s
What is momentum?
Momentum is the product of an object's mass and its velocity. It is a measure of an object's tendency to remain in motion, and is represented by the equation p = mv, where p is the momentum, m is the mass and v is the velocity.
Since momentum is equal to mass times velocity, we can calculate the velocity of the ball as it leaves the tee by dividing the final momentum (1.8 kg m/s) by the mass of the ball (0.045 kg):
Velocity = Final Momentum / Mass
Velocity = 1.8 kg m/s / 0.045 kg
Velocity = 40 m/s
Therefore, The speed of the golf ball just as it leaves the tee is 40 m/s.
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How does the energy stored in a capacitor change, as the capacitor remains connected to a battery, if the separation of the plates is doubled? How does the energy stored in an isolated capacitor change if (a) the potential difference is doubled, or (b) the separa- tion of the plates is doubled? A huge 4.0-F capacitor has enough stored energy to heat 2.8 kg of water from 21°C to 95°C. What is the potential difference across the plates?
Connected capacitor: doubling plate separation has no energy effect. Isolated capacitor: separation decreases by 4x, doubling potential difference increases energy by 4x. Specific heat capacity needed for 4.0-F capacitor's potential difference heating water.
(a) In an isolated capacitor, if the separation of the plates is doubled, the capacitance (C) is halved (C' = C/2). The energy stored in a capacitor is given by the formula U = (1/2)CV², where U is the energy, C is the capacitance, and V is the potential difference. Thus, if the separation is doubled, the new energy stored becomes U' = (1/2)(C/2)V² = (1/4)CV², resulting in a decrease by a factor of 4.
(b) When the potential difference (V) across the plates of an isolated capacitor is doubled, the energy stored becomes U' = (1/2)CV'², where V' is the new potential difference. Doubling the potential difference yields U' = (1/2)C(2V)² = 4CV², which represents an increase by a factor of 4.
Determining the potential difference across the plates of a 4.0-F capacitor that can heat 2.8 kg of water requires additional information such as the specific heat capacity of water and the amount of energy needed to heat the water from 21°C to 95°C.
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A 1. 5-kω resistor and 27. 7-mh inductor are connected in series to a vrms = 120 v ac power source oscillating at a frequency of f = 60 hz. The voltage as a function of time is given by
The voltage as a function of time for the power source oscillating at the given frequency is determined as V = 169.7sin(120πt).
Peak voltageThe peak voltage of the source is calculated as follows;
Vrms = 0.7071V₀
120 = 0.7071V₀
V₀ = 120/0.7071
V₀ = 169.7 V
Angular frequency of the waveω = 2πf
where;
f is frequency = 60 Hz
ω = 2π x 60
ω = 120π rad/s
Voltage equation as function of timeV = V₀sin(ωt)
V = 169.7sin(120πt)
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The voltage equation is a function of a time is V = 169.7sin(120πt) if the 1. 5-kω resistor and 27. 7-mh inductors are connected in series to a vrms = 120 v ac power source oscillating at a frequency of f = 60 Hz.
What is induced voltage?Electromagnetic induction causes the induced voltage. Electromagnetic induction is the process of creating emf (induced voltage) by exposing a conductor to a magnetic field.
We have:
\(\rm V{rms} = 120\)
We know:
\(\rm V_{rms} = 0.7071V_o\)
\(\rm 120 = 0.7071V_o\)
\(\rm V_o = 169.70\) Volts
Expression for the angular frequency is given by:
ω = 2πf
Where f is frequency
ω = 2π x 60
ω = 120π rad/s
Voltage equation as a function of time is given by:
V = V₀sin(ωt)
V = 169.7sin(120πt)
Thus, the voltage equation is a function of a time is V = 169.7sin(120πt) if the 1. 5-kω resistor and 27. 7-mh inductors are connected in series to a vrms = 120 v ac power source oscillating at a frequency of f = 60 Hz.
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HELP ASAP PLEASE!!! Lab: Thermal Energy Transfer
Locate the data and observations collected in your lab guide. What are the key results? How would you best summarize the data to relate your findings?
The best way to summarise the key results in a lab guide is by representing them through diagrams.
The important findings in a lab report are those that confirm or refute the working theories. Furthermore, other findings that are crucial to understanding the processes and/or mechanisms explored in the experiment may also be among the significant findings. The best way to summarise these results is by presenting them through diagrams o graphical presentation.
Key outcomes in an experiment can be findings that serve as stepping stones toward the trial's conclusion or findings that may not directly relate to the experiment itself but are nonetheless crucial to its success. A significant finding in an experiment is one that determines whether a hypothesis is accepted or rejected.
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A small car of mass M travels along a straight,horizontal track. As suggested in the figure, the track then bendsinto a vertical circle of radius R.
What is the minimum acceleration that the car must have at the topof the track if it is to remain in contact with the track?
A) 4. 9 m/s2,upward
B) 9. 8 m/s2,downward
C) 4. 9 m/s2,downward
D) 9. 8 m/s2,upward
E) 19. 6 m/s2,upward
According to the given statement the correct answer will be option ( D ) 9.8 m/s², upward.
The minimum acceleration that the car must have at the top of the track in order to remain in contact with the track can be determined by considering the forces acting on the car.
When the car is at the top of the track, it is in circular motion and experiences two forces:
its weight (mg) acting downward and the normal force (N) exerted by the track acting upward.
To remain in contact with the track, the net force acting on the car must be directed towards the center of the circle.
This means that the net force should be the difference between the normal force and the weight, and it should be directed downward.
The net force is given by:
Net force = N - mg
At the top of the track, the net force is equal to the centripetal force required to keep the car moving in a circle of radius R.
The centripetal force is given by:
Centripetal force = mv² / R
where m is the mass of the car and v is its velocity.
Setting the net force equal to the centripetal force, we have:
N - mg = mv² / R
Solving for v², we get:
v² = gR
where g is the acceleration due to gravity.
The minimum acceleration at the top of the track is when v is at its maximum value, which is when v = √(gR).
Therefore, the minimum acceleration that the car must have at the top of the track is:
a = v² / R = (gR) / R = g
The minimum acceleration that the car must have at the top of the track in order to remain in contact with the track is equal to the acceleration due to gravity (g).
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A chemical lab isolates a gaseous element from the atmosphere that does not form chemical compounds. In which group of the periodic table is this element most likely found?
A. 18
B. 17
C. 1
D. 2
Answer:
A- 18
Explanation:
It wont let me explain how
electric potential finding the value of charge q
Electric potential is the amount of electric potential energy per unit charge at a particular point in an electric field.
It is a scalar quantity measured in volts (V). To find the value of charge (q) given the electric potential, we can use the equation:
Electric Potential = Electric Potential Energy / Charge
Rearranging the equation, we have:
Electric Potential Energy = Electric Potential * Charge
The electric potential energy is the work done to bring a charge from infinity to a specific point in the electric field. By knowing the electric potential and rearranging the equation, we can determine the value of the charge (q).
For example, if the electric potential is 10 volts and the electric potential energy is 50 joules, we can substitute these values into the equation:
50 joules = 10 volts * Charge
By rearranging the equation and solving for Charge, we find that the value of the charge (q) is 5 coulombs.
It is important to note that the electric potential is a property of the electric field, while the charge is a property of the particle experiencing the electric field.
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1. If a wagon has a mass of 8 kg and it is accelerating
at 0.5 m/s2, what is the force pulling the wagon?
Answer:
The force is equal to the mass times acceleration:
F = m•a
F = 8•0.5
F = 4 N
A 45-kilogram bicyclist climbs a hill at a constant speed of 2. 5 meters per second by applying an average force of 85 newtons. Approximately how much power does the bicyclist develop?
A 45-kilogram bicyclist climbs a hill at a constant speed of 2. 5 meters per second by applying an average force of 85 newtons.
The bicyclist develops 212.5 Watts of power while climbing the hill at a constant speed of 2.5 meters per second.
Power is defined as the rate at which work is done or energy is transferred. The formula for power is:
Power = Work / Time
When an object is moving at a constant speed, the work done is equal to the force applied multiplied by the distance travelled. In this case, the work done by the bicyclist is equal to the force applied multiplied by the displacement (distance) travelled.
Given:
Mass of the bicyclist, m = 45 kg
Speed of the bicyclist, v = 2.5 m/s
Force applied by the bicyclist, F = 85 N
To determine the displacement, we can use the formula:
Displacement = Speed * Time
Since the speed is constant at 2.5 m/s, the displacement is equal to the product of the speed and the time.
Let's assume the time taken to climb the hill is T.
Displacement = 2.5 m/s * T
Now, let's calculate the work done by the bicyclist:
Work = Force * Displacement
Work = 85 N * (2.5 m/s * T)
The power developed by the bicyclist is given by the formula:
Power = Work / Time
Since the work is calculated as 85 N * (2.5 m/s * T) and the time is T, we can simplify the formula:
Power = 85 N * (2.5 m/s * T) / T
The T cancels out, leaving us with:
Power = 85 N * 2.5 m/s
Power = 212.5 Watts
Therefore, the bicyclist develops approximately 212.5 Watts of power while climbing the hill at a constant speed of 2.5 meters per second.
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5. A hiker accidentally drops an apple from a cliff. She observes that it hits the ground below after 2.4 s. If the apple accelerated at 10 m/s (gravity) while falling, how high was the
cliff?
cliff height -
וח
"Round your answer to the nearest thousandth if necessary,
Answer:
28.8m
Explanation:
Given parameters:
Time of fall = 2.4s
Acceleration due to gravity = 10m/s²
Unknown:
Height of cliff = ?
Solution:
To solve this problem, we use the expression:
H = ut + \(\frac{1}{2}\)gt²
u is the initial velocity
t is the time taken
g is the acceleration
t is the time
H = 0x2.4 + \(\frac{1}{2}\) x 10x2.4² = 28.8m
The armature of a 4-pole series dc generator has 40 slots, with 10 conductors per slot. There are 4 parallel paths in the armature winding. Every pole of the stator produces a flux of 0. 02 wb. Internal resistance of the generator is 5 ω. The generator is coupled to an internal combustion gasoline engine that provides an input torque of 10 n. M. And runs the generator at a speed of 1200 rpm. The electrical load connected to the generator draws a current of 10 a. A. What is the voltage available at the generator terminals? b. How much power is drawn by the load? c. What is the generator efficiency?.
The generator efficiency is 60.19%
What is generator efficacy?
The efficiency of the generator and overall efficiency A generator is a device that converts mechanical energy to electrical energy. The generator efficiency, the ratio of electrical power output to mechanical power input, characterizes a generator's performance. However, no electric motor is actually 100 percent efficient. Heat, noise, and the creation of products like carbon dioxide all result in energy loss. A generator is 70% efficient if it produces 700 watts out of a 1000 watt generator.
Efficiency = (Pout/Pin)x100%
= (756/1256)x100%
=60.19%
hence, the efficacy of the generator is 60.19%.
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What average force magnitude is required to stop a 15,000 kg train in 12.1 s if the train is traveling at 86 km/hr
Answer:
Explanation:
Givens
m = 15000 kg
t = 12.1 seconds
vi = 86 km / hr
vf =0
Formula
F = m*a
a = (vf - vi)/ t
vi has to be converted to m/s
86 km/hr [1000 m / 1 km] * [1 hour / 3600 seconds]
86 * 1000 / 3600 = 23.89 m/s
Solution
a = (vf - vi) / t
a = (0 - 23.89)/12.1
a = - 1.97 m/s^2 The minus means that the trains is slowing down.
F = 15000 kg * - 1.97 m/s^2
F = -29615.7 Newtons.
calculate the potential energy of 20kg object sitting on a 8meter ledge
Answer:
potential energy=mgh (weight × height)
m=20kg
g=9.8m/s2
h=8
20×9.8×8=1568
The potential energy is 1568J
Answer:
Potential energy = m × g × h
m = 20 kg
acceleration due to gravity = 9. 8 m/ s 2
height ( h ) = 8
= 20 × 9.8 × 8
= 1568
:. potential energy = 1568 Joule
Bumper car A (281 kg) moving +2.82 m/s makes an elastic collision with bumper car B (281 kg) moving -1.72 m/s. What is the velocity of car A after collision?
The velocity of car A after the collision is 1.72 m/s in the opposite direction of its initial velocity.
To find the velocity of car A after collisionWe can use the conservation of momentum to solve for the velocity of car A after the collision.
The initial momentum of the system is:
p_initial = m_A * v_A + m_B * v_B
= 281 kg * 2.82 m/s + 281 kg * (-1.72 m/s)
= 0 kg m/s
Since momentum is conserved, the final momentum of the system is also zero:
p_final = m_A * v_A' + m_B * v_B'
= 0 kg m/s
Where
v_A' and v_B' are the velocities of car A and car B after the collision.Solving for v_A', we get:
v_A' = -(m_B / m_A) * v_B
Substituting the given values, we get:
v_A' = -(281 kg / 281 kg) * (-1.72 m/s)
= 1.72 m/s
Therefore, the velocity of car A after the collision is 1.72 m/s in the opposite direction of its initial velocity.
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Which lists the springs based on the amount of elastic potential energy, from greatest to least? x, y, w, z x, w, y, z z, w, y, x z, y, w, x.
The following list also lists spring constant in order from highest to lowest and ranks stored energy from highest to lowest: X, W, Y, and Z.
The best choice is B.
What does potential energy mean?Potential energy is a type of stored energy that depends on how various components interact with one another. The potential energy of a spring rises when it is compressed or stretched. A steel ball has more potential energy if it is lifted off the ground as opposed to falling.
Which point on the spring does the most elastic potential energy exist?Since the hanging mass is subject to forces that are greatest at either end and least in the middle, the mass has its highest elastic potential energy when the spring is most compressed.
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A freight train has a mass of 270, 700 kg and has an acceleration of 40 m/s2. How much force is acting on the train? Formula:
Answer:
1.08 x 10⁷N
Explanation:
Given parameters:
Mass of freight train = 270700kg
Acceleration = 40m/s²
Unknown:
Force acting on the train = ?
Solution:
From Newton's second law of motion, we know that:
Force = mass x acceleration
So;
Force = 270700 x 40 = 1.08 x 10⁷N
What is the kinetic energy of a 2000kg boat moving at 5m/s?
Answer:
25000 J or 25 kJ
Explanation:
K = 1/2 mv^2
where mass is in kilograms kg
and velocity is in metres per seconds m/s
Here, m = 2000, v = 5
v^2 = 5*5 = 25
1/2 mv^2 = 1/2 * 2000 * 25
= 50000/2
= 25000
Hope it helps!
A bullet of mass m=0.05 kg has a velocity v0=150 m/s just before it strikes the target of mass M=2.5 kg. The bullet embeds in the target which is free to move along the two horizontal guides that support two "nested" springs with spring stiffness k=200 N/m. The dashpot has damping coefficient c=5.11 kg/s. Determine the springs' maximum compression xmax. Note: The compression x(t) can be described as the standard response of a damped free vibration with initial condition x(0)=0, i.e. x(t)=Ae−(c/2mt)tsin(ωdt) with mt=m+M
We can then use the displacement equation to find the amplitude of the motion, which gives the maximum compression. In this problem, the maximum compression is 0.
A bullet of mass m=0.05 kg and a velocity v0=150 m/s just before it strikes the target of mass M=2.5 kg. The bullet embeds in the target which is free to move along the two horizontal guides that support two "nested" springs with spring stiffness k=200 N/m. The dashpot has damping coefficient c=5.11 kg/s.
The compression x(t) can be described as the standard response of a damped free vibration with initial condition
x(0) =0, x (t)=Ae−(c/2mt)
t sin (ωdt) with mt=m+ M. We have to determine the springs' maximum compression x max. Therefore, in order to determine the maximum compression, we must find the amplitude of the motion. So, we should use the fact that the velocity of the mass-spring system is zero at the maximum compression and the fact that the initial velocity of the center of mass of the system is equal to the initial velocity of the bullet, v0. Using the principle of conservation of momentum, we have that: m*v0 = (m + M) v where v is the velocity of the target after the impact. So, we can solve for v: v = m*v0 / (m + M)
The displacement of the center of mass, x(t), is then given by:
where wd = sqrt (k/mt - (c/2mt) ^2) is the damped angular frequency.
At maximum compression, the velocity of the center of mass is zero,
so:0 = -A (c/2mt) sin (wd t) + A wd cos (wd t)
tan (wd t) = (c/2mt) / wd
This can be solved for t to give the time at which the system reaches maximum compression. Using the displacement equation, we can then find the amplitude A.
Let us solve for t: tan (wd t) = (c/2mt) / wd wd t = arctan (c/2mt/wd) t = arctan (c/2mt/wd) / wd
Plugging in values, we get:
wd = sqrt (k/mt - (c/2mt) ^2) = sqrt (200 / (0.05 + 2.5) - (5.11/(2 (0.05 + 2.5) ^ 2) = 1.63 rad/st = arctan (5.11 / (2 (0.05 + 2.5)) / 1.63) / 1.63 = 0.00206 s
The amplitude is then given by: A = x(t) / sin (wd t) = 0 / sin (1.63 0.00206) = 0
Thus, the maximum compression is xmax = A / k = 0 / 200 = 0. Therefore, the answer is 0.
The velocity of the center of mass is zero at maximum compression. Using the principle of conservation of momentum, we can find the velocity of the target after the impact. We can then use the displacement equation to find the amplitude of the motion, which gives the maximum compression. In this problem, the maximum compression is 0.
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when a particle is located a distance meters from the origin, a force of newtons acts on it. find the work done in moving the particle from to . find the work done in moving the particle from to . find the work done in moving the particle from to .
When a particle is located a distance 2 meters from the origin, a force of 4 newtons acts on it.
The work done in moving the particle from A to B is 16J
The work done in moving the particle from B to C is -8J
The work done in moving the particle from C to D is 8J
Force F = 4N
Displacement dx = 2m
Total displacement of the particle from point A to B is dAB = 4m.
Work done is given by: W = F.dx (cosθ)
Where,θ is the angle between the force and displacement.
1. Work done in moving the particle from A to B:
Let the particle is located at point A (x = 0). The force F acts in the positive direction of the x-axis. Therefore, the angle between the force and displacement is 0°.The work done in moving the particle from point A to B is
WAB = F(dx) cosθ
= (4 N)(4m) cos 0°
= (4 N)(4m)
= 16 J
2. Work done in moving the particle from B to C:
The displacement of the particle from B to C is dBC = 2m.
Therefore, the total displacement of the particle from point A to C is
dAC = dAB + dBC
=4m + 2m = 6m.
The force F acts in the negative direction of the x-axis. Therefore, the angle between the force and displacement is 180°.The work done in moving the particle from point B to C is
WBC = F(dx) cosθ
= (4 N)(2m) cos 180°
= (4 N)(-2m)
= -8 J
Note: Here, cos 180° = -1.
3. Work done in moving the particle from C to D:
Let the particle is located at point D (x = 6m).
The force F acts in the positive direction of the x-axis. Therefore, the angle between the force and displacement is 0°.
The work done in moving the particle from point C to D is WCD = F(dx) cosθ
= (4 N)(2m) cos0°
= (4 N)(2m)
=8J
Therefore, the work done in moving the particle from A to B is 16 J, the work done in moving the particle from B to C is -8 J, and the work done in moving the particle from C to D is 8 J.
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if the intensity of the light is increased, while the frequency is kept constant, the maximum kinetic energy of the photoelectrons will
If the intensity of the light is increased while keeping the frequency constant, the maximum kinetic energy of the photoelectrons will remain the same. The number of photoelectrons emitted will increase.
According to the photoelectric effect, the maximum kinetic energy of emitted photoelectrons depends on the frequency of the incident light, not its intensity. The equation for the maximum kinetic energy (KEmax) of photoelectrons is KEmax = hν - φ, where h is Planck's constant, ν is the frequency of light, and φ is the work function of the material.
If the frequency is constant and intensity increases, the number of photons per unit of time increases, resulting in more photoelectrons being emitted. However, the individual energy of each photoelectron remains the same as it depends only on the frequency of light and the work function of the material.
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Consider a double Atwood machine constructed as follows: A mass 4m is suspended from a string that passes over a massless pulley on frictionless bearings. The other end of this string supports a second similar pulley, over which passes a second string supporting a mass of 3m at one end and m at the other. Using two suitable generalized coordinates, set up the Lagrangian and use the Lagrange equations to find the acceleration of the mass 4m when the system is released. Explain why the top pulley rotates even though it carries equal weights on each side.
A car is behind a truck going 30 m/s on the highway. The driver looks for an opportunity to Part A pass, guessing that his car can accelerate at 1.4 m/s2, and he gauges that he has to cover the 20-m length of the truck, plus 10−m clear room at the rear of the truck and 10 m more at the front of it. In the oncoming lane, he sees a car approaching, probably also traveling at 30 Should he attempt the pass? m/s. He estimates that the car is about 500 m away.
The driver should not attempt the pass in this situation. Safety should always be a priority on the road.
To determine whether the driver should attempt the pass, we need to calculate the time it would take for the driver's car to complete the pass and compare it to the time it would take for the oncoming car to reach the same position.
Let's calculate the time it takes for the driver's car to complete the pass:
1. Time to cover the length of the truck: 20 m / 30 m/s = 2/3 seconds.
2. Time to cover the clear room at the rear of the truck: 10 m / 30 m/s = 1/3 seconds.
3. Time to cover the clear room at the front of the truck: 10 m / 30 m/s = 1/3 seconds.
So, the total time for the driver's car to complete the pass is 2/3 + 1/3 + 1/3 = 2 seconds.
Now, let's calculate the time it takes for the oncoming car to reach the same position:
The distance between the driver's car and the oncoming car is 500 m. Since both cars are traveling at the same speed of 30 m/s, the time it takes for the oncoming car to cover that distance is:
Time = Distance / Speed = 500 m / 30 m/s ≈ 16.67 seconds.
Comparing the time it takes for the driver's car to complete the pass (2 seconds) with the time it takes for the oncoming car to reach the same position (16.67 seconds), we can see that attempting the pass would not be safe. The oncoming car would reach the same position before the driver's car completes the pass, posing a significant risk of collision.
Therefore, the driver should not attempt the pass in this situation. Safety should always be a priority on the road.
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A swing is moving. You find out that it takes two seconds for the storm to complete one cycle. What is the period of the swing? What is the frequency of the swing?
The period of the storm is 2s
The frequency of the storm is 0.5 Hz
What is the period?When we talk about the period, what we mean is the time that it would take to complete a cycle. In this case, we have to be looking at the question that we have. We are told that it takes two seconds for the storm to complete one cycle. This means that the period of the storm is 2s.
The frequency would be the inverse of the period so we can have that;
Frequency = 1/Period
Frequency = 1/2
= 0.5 Hz as shown
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If it takes two seconds for the swing to complete one cycle, the period of the swing is the time it takes to complete one cycle, which in this case is 2 seconds.
To find the frequency of the swing, you need to calculate the number of cycles completed in one second. Frequency is the reciprocal of the period, so to find the frequency, you can use the formula:
Frequency = 1 / Period
In this case:
Frequency = 1 / 2 seconds = 0.5 Hz (Hertz)
So, the period of the swing is 2 seconds, and the frequency of the swing is 0.5 Hz.
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The cable of a crane is lifting a 950 kg girder. The girder increases its speed from 0.25 m/s to 1.25 m/s in a distance of 2.7 m. Part A How much work is done by gravity? Express your answer with the appropriate units. WgValue Wor Units Submit Request Answer PartB How much work is done by tension? Express your answer with the appropriate units.
the work done by tension is Wt = KEf - KEi = 714.05 J (joules).
Part A: Gravity does not do any work in this scenario as it is a conservative force and the girder is not changing height. Therefore, Wg = 0 J (joules).
Part B: The work done by tension can be calculated using the work-energy principle. The change in kinetic energy of the girder is equal to the work done by tension.
The initial kinetic energy of the girder is KEi = (1/2)mv^2 = (1/2)(950 kg)(0.25 m/s)^2 = 29.7 J.
The final kinetic energy of the girder is KEf = (1/2)mv^2 = (1/2)(950 kg)(1.25 m/s)^2 = 743.75 J.
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Que se debe cumplir para que la tabla permanezca en equilibrio Es un balancin con dos niños el primero m1= 45kg el segundo m2=38kg Del centro a la izquierda existe una distancia de 160 CM Hallar la distancia del centro a la derecha
formula: m1 * d1 = m2 * d2
datos:
m1= 45 kg
d1= 160 cm
m2= 38 kg
d2= x
reemplazamos datos en formula:
45kg * 160cm = 38kg * d2
El 38 pasa al otro lado de la igualdad a dividir:
(45kg * 160cm) / 38 kg = d2
Resolvemos: (kg se cancela con kg, quedando solo los cm)
7200cm / 38 = d2
Resultado:
d2 = 189.5 cm
Respuesta: La condición que se debe cumplir es que la distancia del centro al niño de la derecha sea de 189.5cm
Name and briefly describe the 10 “world climates” or biomes
These are Some climates
Tropical.
Dry.
Temperate.
Continental.
Polar.
And these are some biomes
aquatic, grassland, forest, desert, and tundra,
The inverted U-tube manometer is used to measure the difference in pressure between water flowing in the pipes at A and B. rho_w = 1000 kg/m^3 If the top segment is filled with air, and the water levels in each segment are as indicated, determine the pressure difference between pipes a and b, both of which contain water.
The pressure difference between pipes a and b, both of which contain water is equal to the product of density of water, acceleration due to gravity, and the difference between the heights of the water in pipes A and B.
To calculate the pressure difference between pipes A and B, you can use the following equation:
ΔP = ρw * g * (hA - hB)
where,
ρw = density of water (1000 kg/m3) g = acceleration due to gravity (9.81 m/s2) hA = height of the water in pipe A hB = height of the water in pipe B
Substituting the given values, we get:
ΔP = 1000 kg/m3 * 9.81 m/s2 * (hA - hB)
Therefore, the pressure difference between pipes A and B is equal to the product of density of water, acceleration due to gravity, and the difference between the heights of the water in pipes A and B.
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