3.An object that begins at rest has an acceleration of 2 m/s/s What is its instantaneous speed after 3 seconds?​ ​

Answer:It shows the size of the range of the moisture contents at which the soil remains plastic. In general, the plasticity index depends only on the amount of clay present. It indicates the fineness of the soil and its capacity to change shape without altering its volume.

Answer:

d. the force is reduced by one quarter to 3.6 n

Explanation:

Answer:

the car has greater momentum.

the car has greater kinetic energy.

Explanation:

FOR MOMENTUM:

Momentum is given as the product of mass and velocity of an object:

\(P = mv\)

where,

P = momentum

m = mass

v = velocity

For Truck:

\(P_{truck} = (3530\ kg)(21\ m/s)\\P_{truck} = 74130 Ns\)

For Car:

\(P_{car} = (1620\ kg)(54\ m/s)\\P_{car} = 87480\ Ns\)

Therefore, car has greater momentum.

FOR KINETIC ENERGY:

Kinetic Energy is given as:

\(K.E = \frac{1}{2} mv^{2}\)

where,

K.E = Kinetic Energy

m = mass

v = velocity

For Truck:

\(K.E_{truck} = \frac{1}{2} (3530\ kg)(21\ m/s)^{2}\\K.E_{truck} = 778365\ J = 778.36\ KJ\)

For Car:

\(K.E_{truck} = \frac{1}{2} (1620\ kg)(54\ m/s)^{2}\\K.E_{truck} = 2361960\ J = 2361.96\ KJ\)

Therefore, car has greater kinetic energy.

Examples of reactions could include burning sugar or steel wool, fat reacting with sodium hydroxide, and mixing zinc with hydrogen chloride.

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The velocity of the horse is 0 m/s, so the correct option is C.

The velocity is a vector that is given by the rate of change of the displacement.

\( v = \frac{d}{t} \)

Where:

d: is the displacement

t: is the time      

Since in the horse track the starting point and the finish line are at the same point, the velocity of the horse is zero because the velocity depends on the direction of the displacement, and here the displacement is zero (the horse returns to the starting point).  

Therefore, the correct option is C: 0 m/s.

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I hope it helps you!      

Answer:

The velocity of the horse is 0 m/s:

Correct answer is C.

Answer:

is there more information for the question

Answer:

11,000 kg

(a) 11.2 m/s

(b) 1.6 m/s

Explanation:

Momentum is conserved.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(2200 kg) (60.0 km/h) + m (0 km/h) = (2200 kg) (10 km/h) + m (10 km/h)

132,000 kg km/h = 22,000 kg km/h + m (10 km/h)

110,000 kg km/h = m (10 km/h)

m = 11,000 kg

Momentum is conserved.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(m) (-v) + (2m) (5v) = (m) (v₁) + (2m) (v₂)

-mv + 10mv = m v₁ + 2m v₂

9mv = m (v₁ + 2 v₂)

9v = v₁ + 2 v₂

Since the collision is elastic, kinetic energy is also conserved.

½ m₁u₁² + ½ m₂u₂² = ½ m₁v₁² + ½ m₂v₂²

m₁u₁² + m₂u₂² = m₁v₁² + m₂v₂²

(m) (-v)² + (2m) (5v)² = m v₁² + (2m) v₂²

mv² + 50mv² = m v₁² + 2m v₂²

51mv² = m (v₁² + 2 v₂²)

51v² = v₁² + 2 v₂²

We know v = 1.60 m/s.  So the two equations are:

14.4 = v₁ + 2 v₂

130.56 = v₁² + 2 v₂²

Solve the system of equations using substitution.

130.56 = (14.4 − 2 v₂)² + 2 v₂²

130.56 = 207.36 − 57.6 v₂ + 4 v₂² + 2 v₂²

0 = 6 v₂² − 57.6 v₂ + 76.8

0 = v₂² − 9.6 v₂ + 12.8

v₂ = [ 9.6 ± √(9.6² − 4(1)(12.8)) ] / 2(1)

v₂ = 1.6 or 8

If v₂ = 1.6 m/s, then v₁ = 14.4 − 2 v₂ = 11.2 m/s.

If v₂ = 8 m/s, then v₁ = 14.4 − 2 v₂ = -1.6 m/s.

We know v₁ can't be -1.6 m/s, since that would mean puck A didn't change speeds after the collision.  Therefore, v₁ = 11.2 m/s and v₂ = 1.6 m/s.

Answer:

Antonie van Leeuwenhoek

Explanation:

Answer:

30.2 Earth years for the new planet to orbit the Sun once.

Explanation:

An AU (astronomical unit) is the average distance from the Earth to the Sun, approximately 93 million miles or 150 million kilometers. So a semi-major axis of 10.5 AU is roughly equivalent to 987.5 million miles or 1.58 billion kilometers.

The time it takes for a planet to orbit the Sun is called its orbital period. The formula for calculating the orbital period of a world is:

T = 2π * √(a^3 / G(M_s)), where T is the orbital period, a is the semi-major axis, G is the gravitational constant, and M_s is the mass of the Sun.

Since the mass of the Sun is known, we can use the formula to calculate the orbital period of the new planet:

T = 2π * √(10.5^3 / (4π^2)) ≈ 30.2 Earth years

So, it will take approximately 30.2 Earth years for the new planet to orbit the Sun once.

When a piece of iron cools from 100 °C to 40 °C, 2,208,000 J of specific heat are released.

The equation q = mcT, where m is the mass of the sample, c is the specific heat, and T is the temperature change, may be used to determine how much heat a sample absorbs or loses (q).

The following formula may be used to determine how much heat the iron piece emits:

Q = mcΔT

Here, the mass of the iron is 80.0 g, its specific heat capacity is 460 J/kg℃, and the temperature change is

(100℃-40℃)=60 ℃.

Q = (80.0 g) x (460 J/kg℃) x (60 ℃)

Q = 2,208,000 J

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The period of oscillation of the system nearest to three decimal places

= 1.092 seconds

The period of an oscillation occurring in a system is the time taken to complete one cycle.

The formula that is used to calculate the period of oscillation (T) is

                = 2π√\(\frac{l}{g}\)

But,

π = 3.14159 (constant)

g= 10m/s² (acceleration due to gravity)

l = 0.302 m

Therefore T = 2 × 3.14159 × √\(\frac{0.302}{10}\)

                    = 6.28318 x √0.0302

                    = 6.28318 x 0.17378

                    = 1.09189s

                    = 1.092 seconds ( to the nearest three decimal places)

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Answer:

\(I_{rms}=2.12\ A\)

Explanation:

Given that,

The instantaneous current in the circuit is giveen by :

\(I=3\sin\theta\ A\)

We need to find the rms value of the current.

The general equation of current is given by :

\(I=I_o\sin\theta\)

It means, \(I_o=3\ A\)

We know that,

\(I_{rms}=\dfrac{I_o}{\sqrt2}\\\\=\dfrac{3}{\sqrt2}\\\\=2.12\ A\)

So, the rms value of current is 2.12 A.

The time taken for one revolution of a rigid rotor to cross the nucleus is 6,240,000×10⁻¹⁵ sec .

Microwave rotational spectroscopy utilizes microwave radiation to quantify the energies of rotational advances for atoms in the gas stage. It achieves this through the communication of the electric dipole snapshot of the particles with the electromagnetic field of the astonishing microwave photon.

To test the unadulterated rotational advances for particles, researchers use microwave rotational spectroscopy. This spectroscopy uses photons in the microwave reach to cause changes between the quantum rotational energy levels of a gas particle.

We know that time taken to complete one revolution of a rigid rotor is

given by the formula J×(J+1)× B × h

where J is rotational quantum number,

B  or I is rotational constant

and h or A is value of atomic mass of the nucleus.

So, on putting we get

=>t=2×(2+1)×5000×208

=>t=2×3×5000×208

=>t=6,240,000fm-sec or

=>t=6,240,000×10⁻¹⁵ sec  

Hence, required time is 6.240,000×10⁻¹⁵ sec .

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Answer:

h = 3.6 m

Explanation:

This is the case of a projectile motion. We assume the air resistance to be negligible. So the speed of the rock remains constant in x-direction. Therefore,

s = V₀ₓ t

where,

V₀ₓ = x - component of launching velocity = V Cos θ = (35 m/s)(Cos 22°)    V₀ₓ = 32.45 m/s

s = distance traveled horizontally by the rock = 10 m

t = time taken to cover the distance = ?

Therefore,

10 m = (32.45 m/s)(t)

t = (10 m)/(32.45 m/s)

t = 0.31 s

Now, we consider the vertical motion. The vertical motion is taking place under the action of gravity. So it is uniformly accelerated motion. Applying 2nd equation of motion to the vertical motion:

h = (Vi₀)(t) + (0.5)gt²

where,

h = height of rock = ?

Vi₀ = Vertical Component of Launching Velocity = V₀Sinθ = (35 m/s)(Sin 22°)

Vi₀ = 13.11 m/s

g = - 9.8 m/s² (negative for upward motion)

Therefore,

h = (13.11 m/s)(0.31 s) + (0.5)(-9.8 m/s²)(0.31 s)²

h = 4.06 m - 0.47 m

h = 3.6 m

Answer: the motion of an object

Explanation:

I just took the test

Answer:the motion of an object

Explanation:

I finished the sample work

The acceleration of the wildebeest is increasing.

The vertical axis represents the velocity of the wildebeest.

The horizontal axis represents the time of motion of the wildebeest

The acceleration of an object is defined as the change in velocity per change in time of motion.

\(a = \frac{\Delta v }{\Delta t } = \frac{v_2 - v_1 }{t_2 - t_1}\)

where;

The acceleration of the wildebeest is calculated as;

\(a'= \frac{0- (-a) }{b - 0} \\\\a' = \frac{a}{b}\)

In the given chart, you will notice that the acceleration of the wildebeest at time (0) is negative a (-a).

At time (b), the acceleration becomes positive with a value of \(\frac{a}{b}\)

Thus, we can conclude that the acceleration of the wildebeest is increasing.

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Answer:

(A) 0.54 kg

(B) 15.5 m/s west

Explanation:

Mass is conserved.

M = m₁ + m₂

0.86 kg = 0.32 kg + m₂

m₂ = 0.54 kg

Momentum is conserved (take east to be positive).

Mv = m₁v₁ + m₂v₂

(0.86 kg)(-6 m/s) = (0.32 kg)(10 m/s) + (0.54 kg) v₂

v₂ = -15.5 m/s

Answer:

Explanation:

To find the current flowing in the circuit, we can use Ohm's Law and Kirchhoff's circuit laws.

Ohm's Law states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R):

I = V / R

In this case, the voltage (V) is the electromotive force (EMF) of the current source, which is 14 V. The total resistance (R) in the circuit is the sum of the internal resistance (r) and the resistances of the two resistors (R1 and R2):

R = r + R1 + R2

Given that the internal resistance (r) is 1Ω and each resistor (R1 and R2) has a resistance of 3Ω, we can substitute these values into the equation:

R = 1Ω + 3Ω + 3Ω = 7Ω

Now we can calculate the current (I):

I = V / R = 14 V / 7Ω = 2 A

Therefore, the current flowing in the circuit is 2 Amperes.

Answer:

The very small particles that make up matter are I) Atoms

Matter - Anything that have mass and occupies space is called matter . it is made up of atoms and molecules

Atoms - The smallest part of matter is called atom.

Molecule - Group of atoms combine together to form a molecule.

In this case, we have to use the potential energy definition

Where U = 1,780 Joules, h = 15 meters, g = 10 m/s2. Let's replace these values and solve for m

Answer:

how can you support to leprosy victims?

According to the information, the ball will just pass over the net (question A); and the ball hits the ground approximately at 7.04 meters from the player and after a time of flight of approximately 1.31 seconds (question B).

To determine if the ball will clear the net, we compare the vertical displacement of the ball with the net height. The ball's initial height is 1.1 meters, and it reaches its highest point during flight. By calculating the trajectory, we can confirm that the ball's vertical displacement at its highest point will be higher than the net height of 1.81 meters, ensuring it clears the net.

To find when and where the ball hits the ground, we need to calculate the time of flight and horizontal displacement. Using the given initial velocity and angle, we can determine the time it takes for the ball to reach the ground. By calculating the horizontal displacement based on the initial horizontal velocity and total time of flight, we find that the ball hits the ground approximately 7.04 meters from the player. The time of flight is approximately 1.31 seconds. The specific values may vary depending on the given initial conditions.

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The speed of the sound wave is 2000 meters per second.

The given calculation assumes a hypothetical medium where the speed of sound is 2000 m/s.The speed of sound can be calculated using the formula: speed = wavelength × frequency.Given that the wavelength of the sound wave is 2 m and its pitch produces a frequency of 1000 Hz, we can substitute these values into the formula:

Speed = 2 m × 1000 Hz = 2000 m/s.

It's important to note that the speed of sound can vary depending on the medium through which it is traveling. In air at standard temperature and pressure, the speed of sound is approximately 343 meters per second.

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Answer:

Asch's experiment showed that about 75% of people were "yielders" who conformed and 25% were "independent" who didn't conform. Asch concludes that people ignored reality and gave an incorrect answer in order to follow the rest of the group.

Answer: An 8 kg book at a height of 3 m has the most gravitational potential energy.

Explanation:

Gravitational potential energy is the product of mass of object, height of object and gravitational field.

So, formula to calculate gravitational potential energy is as follows.

U = mgh

where,

m = mass of object

g = gravitational field = \(9.81 m/s^{2}\)

h = height of object

(A) m = 5 kg and h = 2m

Therefore, its gravitational potential energy is calculated as follows.

\(U = mgh\\= 5 kg \times 9.81 m/s^{2} \times 2 m\\= 98.1 J (1 J = kg m^{2}/s^{2})\)

(B) m = 8 kg and h = 2 m

Therefore, its gravitational potential energy is calculated as follows.

\(U = mgh\\= 8 kg \times 9.81 m/s^{2} \times 2 m\\= 156.96 J (1 J = kg m^{2}/s^{2})\)

(C) m = 8 kg and h = 3 m

Therefore, its gravitational potential energy is calculated as follows.

\(U = mgh\\= 8 kg \times 9.81 m/s^{2} \times 3 m\\= 235.44 J (1 J = kg m^{2}/s^{2})\)

(D) m = 5 kg and h = 3 m

Therefore, its gravitational potential energy is calculated as follows.

\(U = mgh\\= 5 kg \times 9.81 m/s^{2} \times 3 m\\= 147.15 J (1 J = kg m^{2}/s^{2})\)

Thus, we can conclude that an 8 kg book at a height of 3 m has the most gravitational potential energy.

Answer:

False

Explanation:

17%

the answer to your question is false

1.98 kilograms

weight on the moon = (weight on Earth / acceleration of Earth's gravity) x acceleration of the moon's gravity

weight on the moon = (12 kg. / 9.81 m/s^2) x 1.63 m/s^2

weight on the moon = 1.98 kg.

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