3(8+7) =
and how to solve it

The power set in roster notation requires listing all the possible subsets of a set, including the empty set and the set itself. The number of subsets in a power set can be calculated using the formula 2^n, where n is the number of elements in the original set.

The power set of a set is the set of all its subsets, including the empty set and the set itself. To write out the power set in roster notation, we need to list all the possible subsets of a given set.
(a) The set {a} has two subsets: {a} and {}. Therefore, the power set of {a} in roster notation is {{}, {a}}.
(b) The set {1,2} has four subsets: {1,2}, {1}, {2}, and {}. Therefore, the power set of {1,2} in roster notation is {{}, {1}, {2}, {1,2}}.
It is important to note that the cardinality (number of elements) of the power set of a set with n elements is 2^n. For example, the set {1,2} has two elements, so its power set has 2^2 = 4 subsets. Similarly, the set {a} has one element, so its power set has 2^1 = 2 subsets.
In conclusion, writing out the power set in roster notation requires listing all the possible subsets of a set, including the empty set and the set itself. The number of subsets in a power set can be calculated using the formula 2^n, where n is the number of elements in the original set.

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The truck can haul 1102 pounds.

According to the question,

We have the following information:

A Ford F-150 truck is considered a half-ton truck because that is how much it can haul.

(We will not directly convert ton into pounds. We will follow the following steps.)

Now, we know that 1 ton is equal to 1000 kilograms.

So, half ton makes 500 kg.

Now, to convert this into pounds, we will multiply 500 kg by 2.205 because we know that 1 kg is equal to 2.205 pounds.

1 kg = 2.205 pounds

500 kg = (500*2.205) pounds

500 kg = 1102.5 pounds

Hence, the truck can haul 1102.5 pounds.

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Answer:

28.284

Step-by-step explanation:

Based on the margin of error, an estimate of the total number of feral cat complaints for planet Purple is A. Between 1018.5 and 1361.5 complaints.

The margin of error shows the statistical difference between the actual and projected or estimated results.

The margin of error gives the difference between the upper limit and the lower limit of the sample estimate.

With the margin of error, one establishes a level of confidence or the confidence interval in the sample results.

The total number of cities on planet Purple = 4,500

Random sample size = 350 cities

Average complaints = 3.4

Margin or error = ± 0.49

Upper limit = 1,361.5 [350 x (3.4 + 0.49)]

Lower limit = 1,081.5 [350 x (3.4 - 0.49)]

Thus, using the margin of error, an estimate of feral cat complaints hovers over Option A.

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The value of x is 13 / 2 which satisfies the equation "-3 (4x - 5 ) = 2( 1 - 5x)".

In order to determine the value of x that satisfies the equation, we need to solve the equation and find the value of x,

Now solving

the given equation,

-3 (4x - 5 ) = 2( 1 - 5x)

(- 12 x + 15 ) = ( 2  - 10 x)

Shifting the constant terms to one side of the equation and terms having the variable x are kept to another side of the equation.

So,

- 12 x + 10 x =  - 15 + 2

 - 2 x =  -  13

  x = - 13/ - 2

  x = 13 / 2

The value of x is 13 / 2 which satisfies the given equation.

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Nonverbal instruments have been developed primarily in an attempt to d. assess issues that individuals cannot verbalize.

The answer is d. Nonverbal instruments have been developed primarily to assess issues that individuals cannot verbalize. These instruments are often used in psychology and educational assessments to measure skills and abilities in areas such as mathematics, language, and pre-reading skills, while controlling for the influences of language and culture. Nonverbal instruments can be particularly useful for individuals who struggle with verbal communication or have language barriers.

The exchange of information between people without the use of spoken or written language is referred to as nonverbal communication. Facial expressions, eye contact, gestures, posture, body movements, tone of voice, and even the use of time and space are all included in this broad category of behaviors.

A lot of information about a person's emotional state, intentions, attitudes, and personality traits can be communicated nonverbally. A person's posture and body language, for instance, might show whether they are feeling confident or uneasy, and their tone of voice and facial expressions can show whether they are happy, angry, or sad.

A crucial component of human contact is nonverbal communication since it can improve our ability to understand others, establish rapport, and communicate.

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The directional derivative of f(x, y, z) = xy²z³ at p(3, 1, 1) in the direction of q(0, −5, 7) is given by 33/√74.

The given function is,

f(x, y, z) = xy²z³

Now, Gradient of the function is,

Grad f = f/x i + f/y j + f/z k

Grad f = (y²z³) i + (2xyz³) j + (3xy²z²) k

Now the value of the Gradient of the function at point P (3, 1, 1) is,

Grad f(3, 1, 1) = (1²1³) i + (2*3*1*1³) j + (3*3*1²*1²) k = i + 6 j + 9 k

Now the direction vector is = q(0, - 5, 7) = -5 j + 7 k

|q| = √((-5)² + 7²) = √74

So the unit directional vector = (-5 j + 7 k)/√74

Now the directional derivative is given by,

= Gradient at the point (3, 1, 1) * Unit directional vector [Dot product]

= (i + 6 j + 9 k) * ((-5 j + 7 k)/√74)

= (0 - 30 + 63)/√74

= 33/√74

Hence the required directional derivative is 33/√74.

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The SAT prep class has no influence on the mean difference in SAT writing scores, hence the null-hypothesis (H0) states that the mean difference is zero.

The alternative theory (Ha) states that the SAT prep course has a positive impact on the mean difference in SAT writing scores, resulting in a mean difference that is greater than zero.

The sample size of 50 is sufficient for us to do the hypothesis test using the t-distribution.

The estimated t-test statistic is 1.96, and at the 5% level of significance, it is significant only if it is in the rejection zone of the null hypothesis (1.677 is the crucial value for a one-tailed test with 49 degrees of freedom).

The calculated p-value of 0.028 is less than the threshold of 0.05, the null hypothesis is also rejected in favour of the alternative hypothesis.

To draw the conclusion that the SAT prep course has a favourable impact on the mean difference in SAT writing scores. Particularly, at the 5% level of significance, the sample-mean difference of 5 is statistically significantly greater than zero.

Therefore, it is reasonable.

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Answer:

C) 3.5 hours

Step-by-step explanation:

30 minutes is a half of an hour.

So that would be seven halves of an hour.

If we multiply the amount of halves by the amount of day late we get our answer.

0.5 x 7 = 3.5

Or we could simply add 0.5 seven times.

The number of push-ups did sara did during gym class if for every 7 push-ups Dulce can do, Sara can do 6 is 24 push ups.

Number of push ups Dulce can do : number of push ups Sara can do

Let

number of push ups Sara does = x

7 : 6 = 28 : x

7/6 = 28/x

cross product

7 × x = 28 × 6

7x = 168

divide both sides by 7

x = 168/7

x = 24

Therefore, Sara does 24 push ups during the gym class.

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Answer:

60*0,75=45 are men

60*0,40=24 people with blond hair

60-45=15 number of women

24-15=9

9 is the least number of men with blond hair

Step-by-step explanation:

Therefore, the parameterizations r1(t), r2(t), r3(t), r4(t), and r5(t) are all equivalent to r(t), while r6(t) is not.

To determine if two parameterizations are equivalent, we need to check if they represent the same line. We can do this by checking if the direction vectors of the lines are parallel and if they pass through the same point.

The line parametrized by r(t) = (3,-1,9) + t(8, 12, -6) has a direction vector of (8,12,-6).

r1(t) = (11, 11, 3) + t(8,12,-6) has the same direction vector and passes through the point (11, 11, 3).

r2(t) = (4,0, 10) +1(8,12,-6) also has the same direction vector and passes through the point (4, 0, 10).

r3(t) = (6,-2, 18) + (8,12,-6) has the same direction vector and passes through the point (6, -2, 18).

r4(t) = (3,-1,9) + f(-4, -6,3) represents the same line, as the direction vector (-4,-6,3) is a scalar multiple of (8,12,-6), and it passes through the point (3,-1,9).

r5(t) = (8,12,-6) + t(3,-1,9) represents the same line, as it has the same direction vector and passes through the point (8,12,-6).

r6(t) = (-1, -7,12) + f(4,6,-3) represents a different line, as it has a different direction vector and does not pass through the point (3,-1,9).

Therefore, the parameterizations r1(t), r2(t), r3(t), r4(t), and r5(t) are all equivalent to r(t), while r6(t) is not.

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The rules describes the transformation is (x, y)(x, y).

The correct option is (B)

A transformation is a general term for four specific ways to manipulate the shape and/or position of a point, a line, or geometric figure.

If the figure is rotated 360 degrees then the coordinates remains unchanged.

This is because when from where it started it stops there again.

As the 360 degree rotation is complete circle rotation.

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The calculated expectation of X is 0.1

From the question, we have the following parameters that can be used in our computation:

P{X = -1}=0.2, P{X = 0} = 0.5, P{X = 1}=0.3

The expectation of X is calculated as

E(x) = ∑xp(x)

So, we have

E(x) = -1 * 0.2 + 0 * 0.5 + 1 * 0.3

Evaluate

E(x) = 0.1

Hence, the expectation of X is 0.1

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Answer:

3.1 sec.

Step-by-step explanation:

The solution to the equation using the completing the square are 2 and -3

These are equation that has a leading degree of 2. Given the equation below

-x^2 +x+6=0

This can also be written as

x^2-x-6 = 0

Complete the square

x^2-x = 6

x^2-x+ (1/2)^2 = 6 + (1/2)^2

(x-1/2)^2 = 6 + 1/4

(x+1/2)^2 = 25/4

x+1/2 = ±√25/4

x = 5/2 -1/2  or -5/2-1/2

x = 4/2  or -6/2

x = 2 and -3

Hence the solution to the equation using the completing the square are 2 and -3

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A firm experiences increasing returns to scale if inputs are doubled and output more than doubles.

When the firm's output grows at a faster rate than the growth in inputs, increasing returns to scale result. In this case, the company experiences economies of scale, which makes it more effective as it grows its production.

The firm is able to boost productivity and efficiency as it expands its scale of operations if inputs are doubled and output more than doubles.

This can be ascribed to a number of things, including specialisation, labour division, the use of capital-intensive technology, discounts for bulk purchases, and spreading fixed costs over a higher output. Lower average costs per unit of output result in higher profitability and competitiveness for the company.

The firm gains a number of benefits from growing returns to scale. First off, it lets the company to benefit from cost savings brought about by economies of scale, allowing it to manufacture goods or services for less money per unit. This may enable more competitive pricing on the market or result in larger profit margins.

Second, raising returns to scale can result in better operational effectiveness and resource utilisation. As the company grows in size, it will be able to use resources more wisely and profit from production volume-related synergies.market prices that are competitive.

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Triangle KVM is similar to triangle BVG because angle M = angle G = 90° and angle V is common to both triangles.

Two triangles are similar if the angles are the same size or the corresponding sides are in the same ratio.

For two triangles to be similar, the corresponding angles must be congruent i.e equal.. Also the ratio of the corresponding sides of similar triangles are equal.

angle M and G are both 90° , this means they are equal.

angle KVM = BVG

therefore angle K = angle B

Since all the corresponding angles are equal, we can say triangle KVM is similar to triangle BVG

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Answer:

x = -1

Step-by-step explanation:

-Subtract 1 from both sides of the equation

x + 1 = 0

x + 1 - 1 = 0 - 1

-simplify

x = -1

The function $f(x, y) = 11x - 5y$ has a global maximum of $105$ at $(0, 6)$ and a global minimum of $-54$ at $(0, -9)$, the first step is to find the critical points of the function.

The critical points of a function are the points where the gradient of the function is equal to the zero vector. The gradient of the function $f(x, y)$ is: ∇f(x, y) = (11, -5)

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The gradient of the function is equal to the zero vector at $(0, 6)$ and $(0, -9)$. Therefore, these are the critical points of the function.

The next step is to evaluate the function at the critical points and at the boundary of the region. The boundary of the region is given by the inequalities $y \ge x - 9$, $y \ge -x - 9$, and $y \le 6$.

The function $f(x, y)$ takes on the value $105$ at $(0, 6)$, the value $-54$ at $(0, -9)$, and the value $-5x + 54$ on the boundary of the region.

Therefore, the global maximum of the function is $105$ and it occurs at $(0, 6)$. The global minimum of the function is $-54$ and it occurs at $(0, -9)$.

The first step is to find the critical points of the function. The critical points of a function are the points where the gradient of the function is equal to the zero vector. The gradient of the function $f(x, y)$ is: ∇f(x, y) = (11, -5)

The gradient of the function is equal to the zero vector at $(0, 6)$ and $(0, -9)$. Therefore, these are the critical points of the function.

The next step is to evaluate the function at the critical points and at the boundary of the region. The boundary of the region is given by the inequalities $y \ge x - 9$, $y \ge -x - 9$, and $y \le 6$.

We can evaluate the function at each of the critical points and at each of the points on the boundary of the region. The results are shown in the following table:

Point | Value of $f(x, y)$

The largest value in the table is $105$, which occurs at $(0, 6)$. The smallest value in the table is $-54$, which occurs at $(0, -9)$. Therefore, the global maximum of the function is $105$ and it occurs at $(0, 6)$. The global minimum of the function is $-54$ and it occurs at $(0, -9)$.

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The steps to condensing the expressions
2loga(4)+3loga(X-4)loga(4)

Log(x+3)+log(x-3) is given below.

To condense the   expressions, we can apply the  properties of logarithms. Here are the condensed forms of the given expressions.

2loga (4) + 3loga(X - 4) - loga 4 )  

By using the product and quotient rules of logarithms, we can simplify this expression as follows

2 loga( 4) + 3 loga( X-4) - log a(4)

= loga(4 ²) + loga((X-4)³) -  loga (4) = loga (16 ) + loga((X-4)³) - loga (4)

Combining the logarithms  using the power rule and quotient rule we have

= loga(16(X-4)³/4)

log(x+3) + log (x-3)

By using the product rule of logarithms, we can combine these logarithms

log (x +3) +log (x - 3) = log ((x +3 )(x -3 ))

Simplifying further, we get

= log (x² - 9 )

So this means that the condensed forms of the given expressions are

2loga( 4) + 3loga(X -4) - loga (4) = loga(16 (X-4) ³/4)

log (x+ 3) + log(x- 3) = log(x² - 9)

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Answer:

2348994

Step-by-step explanation:

6789 x 346= 2348994

Hope this helps! Please mark brainiest!!!

Answer:

2348994

Step-by-step explanation:

Answer: 38 mph

Step-by-step explanation:

228 miles/6 hours = 38 miles/hour

The seller earns $116.04 on each furnace microwave sold.

If 314% is the seller's profit, then the cost price of the furnace microwave can be found by dividing the selling price by (100% + 314%) or 4.14,

Cost price of the furnace microwave = Selling price / 4.14

                                                             = $153 / 4.14

                                                             = $36.96

                                                                  (rounded to two decimal places)

The profit earned by the seller on each furnace microwave is equal to the selling price minus the cost price,

Profit per furnace microwave = Selling price - Cost price

                                                 = $153 - $36.96

                                                 = $116.04

Hence, On each furnace microwave sold, the seller receives $116.04 in profit.

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Answer:

The distance around a circle on the other hand is called the circumference (c).

Step-by-step explanation:

A straight line that passes from one side of a circle to the other through the center is called the diameter. The distance around the outside of a circle is called the circumference. All points on the edge of a circle are the same distance to the center.

The length of the outside of a circle is called the "circumference."

The circumference is the total distance around the outer boundary of the circle.

The distance cover while completing one full lap around the track is equivalent to the circumference of the circle.

The formula to calculate the circumference (C) of a circle is:

C = πd

where π (pi) is a mathematical constant equal to 3.14159, and d represents the diameter of the circle.

The formula for circumference in terms of the radius is:

C = 2πr

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