3.75 ÷ 1.50
3
.
75

÷

1
.
50
is equivalent to 375 ÷ 150
375

÷

150
.
The dividend and divisor were both multiplied by .

The quotient of both expressions is?

The probability of choosing a specific color of bead is B. 2/3. Since there are an equal number of each color, this is also the probability of choosing any of the colors.

If there are an equal number of orange, green, and blue beads in Lisa's bag, and the total number of beads is 30, then each color has 30/3 = 10 beads.

Therefore, if Lisa chooses a bead randomly from the bag, each color has an equal chance of being selected, and the probability of choosing an orange, green, or blue bead is 2/3.

The probability of choosing a specific color of bead can be determined by counting the number of favorable outcomes (the number of beads of the chosen color) and dividing it by the total number of possible outcomes (the total number of beads in the bag).

In this case, there are 10 beads of each color, so the number of favorable outcomes for each color is 10. The total number of beads in the bag is 30, so the total number of possible outcomes is 30.

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The Original Question:

Lisa has a bag of 30 beads to make jewelry. There are an equal number of orange, green, and blue beads. Those are the only colors. Lisa chooses a bead randomly out of the bag. What is the probability that she will choose a green or blue bead:

Answer choices:

A. 5/6

B. 2/3

C. 1/2

D. 1/6​

Answer:

0.2924

Step-by-step explanation:

Use a calculator.

cos 73 deg = 0.2924

Answer:

y = - 6x - 8

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)

with (x₁, y₁ ) = (- 3, 10) and (x₂, y₂ ) = (- 1, - 2) ← 2 points on the line

m = \(\frac{-2-10}{-1-(-3)}\) = \(\frac{-12}{-1+3}\) = \(\frac{-12}{2}\) = - 6

the line crosses the y- axis at (0, - 8 ) ⇒ c = - 8

y = - 6x - 8 ← equation of line

Answer:

Step-by-step explanation:

θ=l/r

where θ is central angle in degrees.

l=length of arc.

r=radius of circle.

6=14/r

6r=14

r=14/6=7/3 =2 1/3 inches.

Answer:

the simplest form of 15/20 is 3/4

The number of degree of freedom for reading the t values is 60 , the correct option is (c) .

In the question ,

it is given that ,

number of items in the sample = 61 items

the mean of the sample is given as 23 ,

we have to find the degree of freedom(df) ,

the degree of freedom(df) can be solved using the formula

degree of freedom(df)  \(=\) (number of observations) - 1

Substituting the values in the formula ,

we get ,

degree of freedom = 61 - 1

= 60

Therefore , The number of degree of freedom for reading the t values is 60 , the correct option is (c) .

The given question is incomplete , the complete question is

In order to determine an interval for the mean of a population with unknown standard deviation a sample of 61 items is selected. The mean of the sample is determined to be 23. The number of degrees of freedom for reading the t value is ?

(a) 22

(b) 23

(c) 60

(d) 61

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Given function:y = √(1 – x³)We need to find dy/dx.As per the chain rule of differentiation, if y = f(u) and u = g(x), then the derivative of y with respect to x is given by dy/dx = dy/du * du/dx.

Now, let u = 1 – x³. Then, y = √u ⇒ y = u^(1/2).

dy/dx = dy/du * du/dxdy/du = 1/(2√u) = 1/(2√(1 – x³))du/dx = -3x²Therefore, dy/dx = dy/du * du/dx = 1/(2√(1 – x³)) * (-3x²) = (-3x²)/(2√(1 – x³)).

Therefore,  (A) 3(1 - x²)².Option (A) is the correct answer.

The given function is y = √(1 – x³) and we need to find dy/dx. As per the chain rule of differentiation, if y = f(u) and u = g(x), then the derivative of y with respect to x is given by dy/dx = dy/du * du/dx.

Let u = 1 – x³. Then, y = √u ⇒ y = u^(1/2).

We need to find dy/dx.dy/dx = dy/du * du/dxdy/du = 1/(2√u) = 1/(2√(1 – x³))du/dx = -3x².

Therefore, dy/dx = dy/du * du/dx = 1/(2√(1 – x³)) * (-3x²) = (-3x²)/(2√(1 – x³)).

Thus, dy/dx = (-3x²)/(2√(1 – x³)).Therefore, the correct option is (A) 3(1 - x²)².  

The derivative of the given function y = √(1 – x³) with respect to x is (-3x²)/(2√(1 – x³)) and the correct option is (A) 3(1 - x²)².

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Answer:

Horizontal Asymptote at 0

Vertical Asymptote at -1

Step-by-step explanation:

Look at the attached image

(THE BLUE LINES ARE THE ASYMPTOTES)

The red line is the actual graphed function.

======================================================

Explanation:

We're conducting a one proportion Z test.

The hypothesized population proportion is p = 0.53, which is not to be confused with the p-value (unfortunately statistics textbooks seem to overuse the letter 'p'). Luckily this problem is not asking for the p-value.

The sample population proportion is

phat = x/n = 41/79 = 0.518987 approximately

The standard error (SE) is

SE = sqrt(p*(1-p)/n)

SE = sqrt(0.53*(1-0.53)/79)

SE = 0.056153 approximately

Making the test statistic to be

z = (phat - p)/(SE)

z = (0.518987 - 0.53)/0.056153

z = -0.19612487311452

z = -0.196

Which is approximate and rounded to 3 decimal places.

Total ways can occur is 19,653,800.

What is Combination?

Combinations are ways to choose elements from a larger set in mathematics where the order of the elements is irrelevant. Repetition is prohibited and the order of the elements does not matter in a combination, which is a subset of items.

The number of combinations of 51 things chosen 10 at a time, represented as C, determines the number of possibilities to choose 10 finalists from 51 contestants (51, 10).

Combinations are calculated as follows: C (n, k)=\(n! / (k! (n-k)!).\)

Consequently, there are three options to choose 10 finalists from the pool of 51 applicants:\(C(51, 10) = 51! / (10! (51-10)!) = 51! / (10! 41!) = 19,653,800.\\\)

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in the miss America pageant, 51 contestants must be narrowed down into 10 finalists. The total number of ways that can occur is 19,653,800.

What is Combination?

In mathematics, combinations are strategies to select components from a bigger set where the order of the elements is unimportant. In a combination, which is a subset of items, repetition is not permitted and the position of the parts is irrelevant.

The possibility of selecting 10 finalists from 51 contenders is determined by the number of combinations of 51 things picked 10 at a time, denoted as C. (51, 10).

Combinations are calculated as follows: C (n, k)= \(\frac{n!}{k!(n-k)!}\)

Consequently, there are three options to choose 10 finalists from the pool of 51 applicants: 19653800

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Answer:

Step-by-step explanation:

Answer:

\( - m(7m + 3) - 4 {m}^{2} \\ - 7m^{2} - 3m - 4 {m}^{2} \\ - 11 {m}^{2} - 3m\)

Answer:

7539 is what it should be

Step-by-step explanation:

Answer:

-3.5 meters per second

Step-by-step explanation:

got it right on iready lol

Answer:

-3.5 meters

Step-by-step explanation:

T F T

Step-by-step explanation: JUST DID THE TEST

Answer:thfhamdjta

Step-by-step explanation:

The required product of 342 and 38 is 12,996.

In mathematics, Multiplication operations perform Multiplying values on either side of the operator.

For example 4×2 = 8

First, we write the two numbers vertically, with the one digit of 342 on the bottom and the one digit of 38 on the right.

Next, we multiply the one digit of 342 (2) by the one digit of 38 (8), which gives 16. We write the one digit of this result (6) under the line and carry the tens digit (1) to the next column,

   3  4  2

 ×    3  8

_________

     12996

Therefore, the product of 342 and 38 is 12,996.

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(i) Euler's method: At x = 0.05, y ≈ 1.05, At x = 0.1, y ≈ 1.107, At x = 0.15, y ≈ 1.174

(ii) Fourth-order Runge-Kutta method: At x = 0.05, y ≈ 1.05 , At x = 0.1, y ≈ 1.107, At x = 0.15, y ≈ 1.174

(i) Euler's Method:

Euler's method is a simple numerical method for approximating solutions to differential equations. It uses the formula:

yᵢ₊₁ = yᵢ + h * f(xᵢ, yᵢ),

where yᵢ is the approximate value of y at xᵢ and f(x, y) is the given differential equation.

Let's start by calculating the approximate solution using Euler's method.

Step size, h = 0.05

At x = 0.05:

x₀ = 0

y₀ = 1

Using the given differential equation: dy/dx = 2x + eˣʸ

We have: f(x, y) = 2x + eˣʸ

Using Euler's method:

x₁ = x₀ + h = 0 + 0.05 = 0.05

y₁ = y₀ + h * f(x₀, y₀)

   = 1 + 0.05 * (2(0) + e^(0*1))

   = 1 + 0.05 * (0 + e^0)

   = 1 + 0.05 * (0 + 1)

   = 1 + 0.05

   = 1.05

At x = 0.1:

x₂ = x₁ + h = 0.05 + 0.05 = 0.1

y₂ = y₁ + h * f(x₁, y₁)

 \(= 1.05 + 0.05 * (2(0.05) + e^(0.05*1.05)) = 1.05 + 0.05 * (0.1 + e^(0.0525))\)

   = 1.05 + 0.05 * (0.1 + 1.05383959925)

   = 1.05 + 0.05 * (1.15383959925)

   = 1.107691979963

At x = 0.15:

x₃ = x₂ + h = 0.1 + 0.05 = 0.15

y₃ = y₂ + h * f(x₂, y₂)

  \(= 1.107691979963 + 0.05 * (2(0.1) + e^(0.1*1.107691979963)) = 1.107691979963 + 0.05 * (0.2 + e^(0.1107691979963))\)

   = 1.107691979963 + 0.05 * (0.2 + 1.12281597877)

   = 1.107691979963 + 0.0661407989385

   = 1.173832778901

Approximate solution using Euler's method:

At x = 0.05, y ≈ 1.05

At x = 0.1, y ≈ 1.107

At x = 0.15, y ≈ 1.174

(ii) Fourth-order Runge-Kutta Method:

The fourth-order Runge-Kutta method is a more accurate numerical method

for approximating solutions to differential equations. It uses the formula:

k₁ = h * f(xᵢ, yᵢ)

k₂ = h * f(xᵢ + h/2, yᵢ + k₁/2)

k₃ = h * f(xᵢ + h/2, yᵢ + k₂/2)

k₄ = h * f(xᵢ + h, yᵢ + k₃)

yᵢ₊₁ = yᵢ + (k₁ + 2k₂ + 2k₃ + k₄)/6

Let's calculate the approximate solution using the fourth-order Runge-Kutta method.

Step size, h = 0.05

At x = 0.05:

x₀ = 0

y₀ = 1

k₁ = 0.05 * f(x₀, y₀)

   = 0.05 * (2(0) + e^(0*1))

   = 0.05 * (0 + e^0)

   = 0.05 * (0 + 1)

   = 0.05

k₂ = 0.05 * f(x₀ + 0.05/2, y₀ + k₁/2)

   = 0.05 * f(0 + 0.025, 1 + 0.025/2)

   = 0.054123529771

k₃ = 0.05 * f(x₀ + 0.05/2, y₀ + k₂/2)

   = 0.05 * f(0 + 0.025, 1 + 0.054123529771/2)

   = 0.05 * (1.08260731316)

   = 0.054130365658

k₄ = 0.05 * f(x₀ + 0.05, y₀ + k₃)

   = 0.05 * f(0 + 0.05, 1 + 0.054130365658)

   = 0.05 * (1.15381700056)

   = 0.057690850028

y₁ = y₀ + (k₁ + 2

k₂ + 2k₃ + k₄)/6

   = 1 + (0.05 + 2(0.054123529771) + 2(0.054130365658) + 0.057690850028)/6

   = 1 + (0.05 + 2(0.054123529771) + 2(0.054130365658) + 0.057690850028)/6

   = 1.04999993086

At x = 0.1:

x₁ = x₀ + h = 0 + 0.05 = 0.05

k₁ = 0.05 * f(x₀, y₁)

   = 0.05 * (2(0.05) + e^(0.05*1.04999993086))

   = 0.05 * (1.15382091332)

   = 0.057691045666

k₂ = 0.05 * f(x₀ + 0.05/2, y₁ + k₁/2)

   = 0.05 * f(0 + 0.025, 1.04999993086 + 0.057691045666/2)

   = 0.05 * f(0.025, 1.076845501196)

   = 0.05 * (1.08293606756)

   = 0.054146803378

k₃ = 0.05 * f(x₀ + 0.05/2, y₁ + k₂/2)

   = 0.05 * f(0 + 0.025, 1.04999993086 + 0.054146803378/2)

   = 0.05 * (0.05 + 1.03297648754)

   = 0.05 * (1.08297648754)

   = 0.054148824377

k₄ = 0.05 * f(x₀ + 0.05, y₁ + k₃)

   = 0.05 * f(0 + 0.05, 1.04999993086 + 0.054148824377)

   = 0.05 * f(0.05, 1.104148755237)

   = 0.

05 * (2(0.05) + e^(0.05*1.104148755237))

   = 0.05 * (1.15636272702)

   = 0.057818136351

y₂ = y₁ + (k₁ + 2k₂ + 2k₃ + k₄)/6

   = 1.04999993086 + (0.057691045666 + 2(0.054146803378) + 2(0.054148824377) + 0.057818136351)/6

   = 1.04999993086 + (0.057691045666 + 2(0.054146803378) + 2(0.054148824377) + 0.057818136351)/6

   = 1.10730401829

At x = 0.15:

x₂ = x₁ + h = 0.1 + 0.05 = 0.15

k₁ = 0.05 * f(x₁, y₂)

   = 0.05 * (2(0.1) + e^(0.1*1.10730401829))

   = 0.066134153561

k₂ = 0.05 * f(x₁ + 0.05/2, y₂ + k₁/2)

   = 0.05 * f(0.1 + 0.025, 1.10730401829 + 0.066134153561/2)

   = 0.05 * (1.40252551209)

   = 0.070126275604

k₃ = 0.05 * f(x₁ + 0.05/2, y₂ + k₂/2)

   = 0.05 * f(0.1 + 0.025, 1.10730401829 + 0.070126275604/2)

   = 0.05 * f(0.125, 1.13726868037)

   = 0.05 * (1.40260973286)

   = 0

.070130486643

k₄ = 0.05 * f(x₁ + 0.05, y₂ + k₃)

   = 0.05 * f(0.1 + 0.05, 1.10730401829 + 0.070130486643)

   = 0.05 * (1.49307437508)

   = 0.074653718754

y₃ = y₂ + (k₁ + 2k₂ + 2k₃ + k₄)/6

   = 1.10730401829 + (0.066134153561 + 2(0.070126275604) + 2(0.070130486643) + 0.074653718754)/6

   = 1.17379707103

Approximate solution using the fourth-order Runge-Kutta method:

At x = 0.05, y ≈ 1.05

At x = 0.1, y ≈ 1.107

At x = 0.15, y ≈ 1.174

Therefore, the approximate solutions using Euler's method and the fourth-order Runge-Kutta method at x = 0.05, 0.1, and 0.15 are as follows:

Euler's method:

At x = 0.05, y ≈ 1.05

At x = 0.1, y ≈ 1.107

At x = 0.15, y ≈ 1.174

Fourth-order Runge-Kutta method:

At x = 0.05, y ≈ 1.05

At x = 0.1, y ≈ 1.107

At x = 0.15, y ≈ 1.174

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The correct option is A. Rotate GHJ using center G until GH is lined up with ST and then reflect over a line halfway between G'H'J' and STU.

There are four types of rigid motions that we will consider translation , rotation, reflection, and glide reflection.

Here we have to rotate GHJ using center G until GH is lined up with ST and then reflect over a line halfway between G'H'J' and STU.

Hence option A is correct that is Rotate GHJ using center G until GH is lined up with ST and then reflect over a line halfway between G'H'J' and STU.

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Answer: The graph of the linear equation is a set of points in the coordinate plane that all are ... If all variables represent real numbers one can graph the equation by plotting ... of values for x e.g. -2, -1, 0, 1 and 2 and calculate the corresponding y values

any more help just ask :)

Answer:

0 I think

Step-by-step explanation:

I'm guessing 1. Prime numbers are numbers greater than 1.

The comparison of two quantities with different units is called a ratio and proportion. A ratio that specifically compares two quantities measured in different units.

Comparing amounts is done using a ratio. A ratio demonstrates how many times one amount fits inside another or how much larger one amount is than another.

If I need to mix some cement, I would add two parts cement to four parts sand. The two numbers are both portions of the entire. Hence, the 2:4 ratio (6 parts in total). The written version is crucial; 4:2 would produce a different blend.

Ratios are expressed in their most basic form. There are five green and fifteen red dots in the figure on the right. The ratio is 15:5, but like with fractions, this can be boiled down to its most basic form.

If you look at the relationship between the numbers 15:5 as is 3:1, you can see that 3 is multiplied by 5 to obtain 15 and that 1 is multiplied by 1 to get 5. The ratio, as we can see in the image, is also 3:1.

Therefore,

The comparison of two quantities with different units is called a ratio and proportion. A ratio that specifically compares two quantities measured in different units.

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The standard error of the sample mean is 1.21.

Given;

Suppose a diet regimen for men results in an average weight loss of between 13. 4 and 18. 3 pounds, according to a 95% confidence interval. These findings were based on a group of 42 men who were classified as overweight at the beginning of the four-month trial.

A 95% confidence interval for a population mean is (13.4, 18.3)

Upper limit = 18.3

Lower limit = 13.4

Since population SD is unknown, this interval is constructed using the t distribution.

n = 42

c = 0.95

∴ α = 1 - c = 1 - 0.95 = 0.05

α/2 = 0.025

Also, d.f = n - 1 = 42 - 1 = 41

∴ ta/2.d.f =  ta/2.n-1  =  t0.025,41  =  2.02 . . . . use t table

Now,

The margin of error = (Upper limit - Lower limit)/2

                                 = (18.3 - 13.4)/2

                                 = 2.45

But,

Margin of error = ta/2.d.f-  * (s / \sqrt{} n)

Margin of error = ta/2.d.f-  * Standard error

2.45 = 2.02 * Standard error

Standard error = 1.2129

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Answer: 6%

Step-by-step explanation:

I just baised it off of how many students were in the equation. at the end thier is only 6 seats left

Answer:

8x

Step-by-step explanation:

Combine Like Terms:

= x+2x+5x

= (x+2x+5x)

= 8x

The number of waffles can be made from 15 eggs are, 20 waffles.

the waffles can be calculates as follows

4 cups of fluor + 6 eggs +2 tbsp oil = 8 waffles

we need 6 eggs to make 8 waffles

So, the waffles can we make from 15 eggs = \(\frac{8}{6} X 15 = 20\) waffles

Hence, the number of waffles can be made from 15 eggs are 20 waffles.

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9514 1404 393

Answer:

  1. (x -3)(x -1)

  2. (x -4)(x +1)

Step-by-step explanation:

1. The long division is shown in the first attachment. The quotient is (x -3), so the factorization is ...

  x^2 -4x +3 = (x -1)(x -3)

__

2. The long division is shown in the second attachment. The quotient is (x -4), so the factorization is ...

  x^2 -3x -4 = (x +1)(x -4)

We need approximately 10 deposits to reach a balance of $31,300 four years after the last deposit which is compounded semi-annually.

To solve this problem, we can use the formula for the future value of an annuity:

\(FV = P * ((1 + r)^n - 1) / r\)

Where:

FV is the future value of the annuity

P is the periodic payment or deposit amount

r is the interest rate per period

n is the number of periods

In this case, the deposit amount is $726.56, the interest rate is 6.45% compounded semi-annually, and the future value is $31,300. We need to find the number of deposits (n).

We can rearrange the formula and solve for n:

n = log((FV * r) / (P * r + FV)) / log(1 + r)

Substituting the given values:

n = log((31,300 * 0.03225) / (726.56 * 0.03225 + 31,300)) / log(1 + 0.03225)

Using a calculator or software, we find that n ≈ 9.989.

Therefore, we need approximately 10 deposits to reach a balance of $31,300 four years after the last deposit.

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Answer:

g(f(x)) = 8x-18

Step-by-step explanation:

Given that,

f(x) = 5 - 2x

g(x) = -4x + 2

We need to find g(f(x)) .

g(f(x)) = g(5-2x)

= -4(5-2x)+2

= (-4) (5) +(-4)(-2x) +2

= -20 +8x +2

= 8x-18

Hence, the value of g(f(x)) is 8x-18