32. a sample of ten guinea pigs yielded the following- ing measurements of body temperature in degrees celsius (statistical exercises in medical research, new york: wiley, 1979, p. 26): 38.1 38.4 38.3 38.2 38.2 37.9 38.7 38.6 38.0 38.2 a. verify graphically that it is reasonable to assume the normal distribution. b. compute a 95% confidence interval for the population mean temperature. c.. what is the ci if temperature is re-expressed in degrees fahrenheit? are guinea pigs warmer on average than humans?

Answers

Answer 1

Temperatures between 18 and 23 degrees Celsius are ideal for guinea pigs.

Your pig can get cold if the temperature falls below 15 degrees. Your pig can suffer from heat stroke if the temperature rises above 26 degrees. Blood flow to the epidermis decreases in a cold Guinea Pig in order to maintain body heat.

Although guinea pigs can tolerate cold better than heat, being excessively cold still causes them a lot of worry. If they are too cold for too long, they risk getting sick or possibly dying. between 60 and 85 °F in the middle.

To stay warm in the winter, your guinea pig will want a tonne of extra bedding. Since cardboard is a good insulator, it works well as a liner for hutches in the winter. Before adding a tonne of hay for them to burrow in, add newspaper.

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Related Questions

Solve 21.85 x (-6.2)

Answers

Answer:

= −135.47x

Step-by-step explanation:

^^^^^^^^^^^^^^^

which was EAV-Secure Prove the opposite - i.e. if G is not a PRG, then 3.17 cannot be EAV-secure. Let G be a pseudorandom generator with expansion factor ℓ. Define a private-key encryption scheme for messages of length ℓ as follows: - Gen: on input 1n, choose uniform k∈{0,1}n and output it as the key. - Enc: on input a key k∈{0,1}n and a message m∈{0,1}ℓ(n), output the ciphertext c:=G(k)⊕m. - Dec: on input a key k∈{0,1}n and a ciphertext c∈{0,1}ℓ(n), output the message m:=G(k)⊕c. A private-key encryption scheme based on any pseudorandom generator. THEOREM 3.18 If G is a pseudorandom generator, then Construction 3.17 is a fixed-length private-key encryption scheme that has indistinguishable encryptions in the presence of an eavesdropper. PROOF Let Π denote Construction 3.17. We show that Π satisfies Definition 3.8. Namely, we show that for any probabilistic polynomial-time adversary A there is a negligible function negl such that Pr[PrivKA,Πeav​(n)=1]≤21​+neg∣(n)

Answers

To prove the opposite, we need to show that if G is not a pseudorandom generator (PRG), then Construction 3.17 cannot be EAV-secure.

Assume that G is not a PRG, which means it fails to expand the seed sufficiently. Let's suppose that G is computationally indistinguishable from a truly random function on its domain, but it does not meet the requirements of a PRG.

Now, consider the private-key encryption scheme Π described in Construction 3.17 using G as the pseudorandom generator. If G is not a PRG, it means that its output is not sufficiently pseudorandom and can potentially be distinguished from a random string.

Given this scenario, an adversary A could exploit the distinguishability of G's output and devise an attack to break the security of the encryption scheme Π. The adversary could potentially gain information about the plaintext by analyzing the ciphertext and the output of G.

Therefore, if G is not a PRG, it implies that Construction 3.17 cannot provide EAV-security, as it would be vulnerable to attacks by distinguishing the output of G from random strings. This contradicts Theorem 3.18, which states that if G is a PRG, then Construction 3.17 achieves indistinguishable encryptions.

Hence, by proving the opposite, we conclude that if G is not a PRG, then Construction 3.17 cannot be EAV-secure.

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The Picture is attached below

The Picture is attached below

Answers

Answer:

Step-by-step explanation:

Calculate the volume of a parallelepiped whose sides are described by the vectors, A = [-4, 3, 2] cm, B = [2,1,3] cm and C= [1, 1, 4] cm, You can use the vector triple product equation Volume = A . (BXC)| .

Answers

The volume of the parallelepiped with sides given by vectors A, B and C is 13 cubic cm, which is the final answer.

The given vectors are:

A = [-4, 3, 2] cm, B = [2,1,3] cm and C= [1, 1, 4] cm

In order to calculate the volume of parallelepiped, we will use vector triple product equation:

Volume = A . (BXC)|, where BXC represents the cross product of vectors B and C.

Step-by-step solution:

We have, A = [-4, 3, 2] cm

B = [2,1,3] cm

C = [1, 1, 4] cm

Now, let's find BXC, using the cross product of vectors B and C.

BXC = | i    j     k|                    2      1     3                            1      1     4        | i    j     k |  = -i + 5j - 3k

Where, i, j, and k are the unit vectors along the x, y, and z-axes, respectively.

The volume of the parallelepiped is given by:

Volume = A . (BXC)|

Therefore, we have: Volume = A . (BXC)

\(Volume = [-4, 3, 2] . (-1, 5, -3)\\Volume = (-4 \times -1) + (3 \times 5) + (2 \times -3)\\Volume = 4 + 15 - 6\\Volume = 13\)

Therefore, the volume of the parallelepiped with sides given by vectors A, B and C is 13 cubic cm, which is the final answer.

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Solve using elimination. -2x+2y=2, 2x-y=4.

Answers

Answer:

y=6

x=5

Step-by-step explanation:

x=(y+4)/2

-2(y+4)/2+2y=2

-y-4+2y=2

y-4=2

y=6

x=(6+4)/2

x=5

venf(x)=3x 3
+10x 2
−13x−20, answ Part: 0/2 Part 1 of 2 Factor f(x), given that −1 is a zero. f(x)=

Answers

Given that ven f(x) = 3x³ + 10x² - 13x - 20, we need to find the factor f(x) given that -1 is a zero.Using the factor theorem, we can determine the factor f(x) by dividing venf(x) by (x + 1).

The remainder will be equal to zero if -1 is indeed a zero. Let's perform the long division as follows:So, venf(x) = (x + 1)(3x² + 7x - 20)The factor f(x) is given by: f(x) = 3x² + 7x - 20

Using the factor theorem, we found that f(x) = 3x² + 7x - 20, given that -1 is a zero of venf(x) = 3x³ + 10x² - 13x - 20.

In order to find the factor f(x) of venf(x) = 3x³ + 10x² - 13x - 20, given that -1 is a zero, we can use the factor theorem. According to this theorem, if x = a is a zero of a polynomial f(x), then x - a is a factor of f(x). Therefore, we can divide venf(x) by (x + 1) to determine the factor f(x).Let's perform the long division:As we can see, the remainder is zero, which means that -1 is indeed a zero of venf(x) and (x + 1) is a factor of venf(x). Now, we can factor out (x + 1) from venf(x) and get:venf(x) = (x + 1)(3x² + 7x - 20)This means that (3x² + 7x - 20) is the other factor of venf(x) and the factor f(x) is given by:f(x) = 3x² + 7x - 20Therefore, we have found that f(x) = 3x² + 7x - 20, given that -1 is a zero of venf(x) = 3x³ + 10x² - 13x - 20.

To find the factor f(x) of venf(x) = 3x³ + 10x² - 13x - 20, given that -1 is a zero, we can use the factor theorem. By dividing venf(x) by (x + 1), we get the other factor of venf(x) and f(x) is obtained by factoring out (x + 1). Therefore, we have found that f(x) = 3x² + 7x - 20.

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given a set of data and a corresponding regression​ line, describe all values of x that provide meaningful predictions for y. A. Prediction values are meaningful for all X-values that are realistic in the context of the original data set. B. Prediction values are meaningful only for x-values that are not included in the original data set. C. Prediction values are meaningful only for X-values in (or close to the range of the original data.

Answers

The correct answer is (C) Prediction values are meaningful only for X-values in (or close to the range of the original data.

A regression line is a statistical model that is used to make predictions about the value of a dependent variable (Y) based on the value of an independent variable (X). The regression line is based on a sample of data, and it is typically used to make predictions about the population from which the sample was drawn.

The validity of the predictions made using a regression line depends on the assumptions that were used to create the model. One of these assumptions is that the relationship between X and Y is linear, which means that the predictions are only meaningful for X-values that are within (or close to) the range of the original data. If the X-value is outside this range, the prediction may not be accurate because the model may not accurately represent the underlying relationship between X and Y.

Therefore, to provide meaningful predictions for Y, the values of X should be within (or close to) the range of the original data.

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please help thank you.

please help thank you.

Answers

The Measure of angle A is 120°, Measure of angle C = 120° and the Measure of angle D is 60°

How to calculate the angle

In a parallelogram, opposite angles are congruent. Therefore, if the measure of angle A is 120°, then the measure of angle C is also 120°.

Since angle A and angle C are opposite angles, their adjacent angles are also congruent. This means that the measure of angle B is equal to the measure of angle Z.

Now, let's consider angle D. In a parallelogram, the sum of the measures of adjacent angles is always 180°. Since angle C is 120°, the adjacent angle D must be:

180° - 120°

= 60°.

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Find the value of csc 0 if cos 0 = -3/5 and 0 is in the second quadrant.

Answers

we know that the cos(θ) is -(3/5), however θ is in the II Quadrant, where the cosine is negative whilst the sine is positive, meaning the fraction is really (-3)/5, so

\(cos(\theta )=\cfrac{\stackrel{adjacent}{-3}}{\underset{hypotenuse}{5}}\qquad \qquad \textit{let's find the \underline{opposite side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases}\)

\(\pm\sqrt{5^2-(-3)^2}=b\implies \pm\sqrt{25-9}=b\implies \pm 4=b\implies \stackrel{II~Quadrant}{+4=b} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill csc(\theta )=\cfrac{\stackrel{hypotenuse}{5}}{\underset{opposite}{4}}~\hfill\)

En una escuela los hombres representan el 70% del alumnado si hay 153 mujeres ¿cuál es el total de alumnos de la escuela?

Answers

Queremos encontrar el número total de alumnos en una dada escuela dado que conocemos el número de de mujeres estudiantes y el porcentaje que representan.

Veremos que el número total de estudiantes es: 510

---------------------------------------

La información que se nos da es:

Los hombres representan el 70% del alumnado.Hay 153 mujeres.

De la primera parte podemos concluir que, si el 70% de los alumnos son hombres, entonces el otro 30% son mujeres.

Entonces el 30% del número total de estudiantes es 153.

Si definimos N como el número total de estudiantes, entonces tenemos:

(30%/100%)*N = 153

0.3*N = 153

N = 153/0.3 = 510

Es decir, hay 510 alumnos en la escuela.

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On a coordinate plane, a circle has a center at (4, 5) and a radius of 3 units.
Which equation represents a circle with the same center as the circle shown but with a radius of 2 units?

(x – 4)2 + (y – 5)2 = 2
(x – 4)2 + (y – 5)2 = 4
(x – 5)2 + (y – 4)2 = 2
(x – 5)2 + (y – 4)2 = 4

Answers

Answer:

(x - 4)² + (y - 5)² = 4

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k) = (4, 5) and r = 2, thus

(x - 4)² + (y - 5)² = 2², that is

(x - 4)² + (y - 5)² = 4 ← second option on list

The required equation represents a circle with the same center as the circle shown but with a radius of 2 units is (x-4)^2  + (y-5)^2 = 4

Equation of a circle

The standard equation of a circle is expressed as:

(x-a)^2  + (y-b)^2 = r^2

where:

(a, b) is the centre = (4, 5)

r is the radius = 3 units

Substitute to have;

(x-4)^2  + (y-5)^2 = 2^2

(x-4)^2  + (y-5)^2 = 4

Hence the required equation represents a circle with the same center as the circle shown but with a radius of 2 units is (x-4)^2  + (y-5)^2 = 4

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the sum of three numbers $x$ ,$y$, $z$ is $165$. when the smallest number $x$ is multiplied by $7$, the result is $n$. the value $n$ is obtained by subtracting $9$ from the largest number $y$. this number $n$ also results by adding $9$ to the third number $z$. what is the product of the three numbers?

Answers

The product of three numbers is 12,295.

We are given that the sum of three numbers x, y, and z is 165, so we can write:

x + y + z = 165

We are also told that when the smallest number x is multiplied by 7, the result is n. So we can write:

x * 7 = n

It is also given that the value n is obtained by subtracting 9 from the largest number y, so we can write:

y - 9 = n

And that this number n also results by adding 9 to the third number z, so we can write:

z + 9 = n

We have 3 equations with 3 unknowns, we can use these equations to solve the problem.

From the equation x * 7 = n, we can substitute n = y-9, and we get:

x * 7 = y - 9

From the equation z + 9 = n, we can substitute n = y-9, and we get:

z + 9 = y - 9

Now we have 2 equations with 3 unknowns x,y,z.

To solve for the third unknown, we can use the equation x + y + z = 165 and substitute the values that we know from the previous equations:

x + (y - 9) + (z + 9) = 165

Solving for x we get:

x = (165 - (y-9) - (z+9)) = (165 - y + 9 - z - 9) = (165 - y - z + 18) = (183 - (y+z))

Now we can substitute this value into one of the previous equations:

(183 - (y+z)) * 7 = y - 9

Solving for y and z we get:

y = 95 and z = 71

And the product of the three numbers is:

x * y * z = (183 - (y+z)) * y * z = (183 - (95 +71)) * 95 * 71 = (183 - 166) * 95 * 71 = 17 * 95 * 71 = 12,295

So the product of three numbers is 12,295.

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Please explain how to do it, don't just give answers, I wan' to learn!!!!

Please explain how to do it, don't just give answers, I wan' to learn!!!!

Answers

Answer:

when you do these types of problems, try to think of how you could find out if they are similar. Try to make the shapes bigger or rotate. ^^

Step-by-step explanation:

i hope this wasn't too much into and i hope this helped <3

edit: the answer is 1 and 2.

the reasoning is when you turn the rectangle and divide each correlating side (7.5 by 5 and 9 by 6) for both sides you get the same number: 1.5

when you get the same number, they are similar ^^

9514 1404 393

Answer:

  rectangles 1 and 2 are similar

Step-by-step explanation:

Polygons are similar when ...

corresponding angles are congruentcorresponding sides are proportional

In a rectangle, all angles are 90°, so all angles are congruent.

The question of proportionality can be answered a couple of ways. One is to identify corresponding sides in the different figures, then see if the ratios between figures are the same.

Another way is to identify corresponding sides in the same figure, find their ratios, then see if those match with the ratios in the other figure.

For triangles and parallelograms, it can be useful to use the ratios of the sides in order from shortest to longest.

Here, the ratios are ...

  rectangle 1: 5 : 6

  rectangle 2: 7.5 : 9 = 15 : 18 = 5 : 6 . . . . similar to rectangle 1

  rectangle 3: 12 : 15 = 4 : 5 . . . . not similar to the others

Rectangles 1 and 2 are similar.

_____

Additional comment

Ratios are equivalent if all the numbers involved have the same factor. For rectangle 2, we wanted to reduce the ratio to the lowest integer terms. Here, we recognize that 7.5 can be cleared of a decimal by multiplying by 2, so we did ...

  7.5 : 9 = (2)(7.5) : (2)(9) = 15 : 18

Now, we can see that these numbers have 3 as a common factor, so we can remove that factor.

  (3)(5) : (3)(6) = 5 : 6 . . . . reduced form of the ratio 7.5 : 9.

__

We can also get there by finding the greatest common divisor* of 7.5 and 9. That is 1.5, so we have ...

  7.5 : 9 = (1.5)(5) : (1.5)(6) = 5 : 6

__

* Euclid's algorithm for finding the GCD works with decimals or fractions as well as integers. Basically, you see if the difference is a divisor of the numbers. If it is, that is the GCD. 9 -7.5 = 1.5 is a divisor of both 7.5 and 9, so that is the GCD. (If not; the difference replaces the larger number, and the process repeats.)

marie plans to apply for phd programs and is studying to take a required standardized test for graduate admissions. she would like to make the claim that the average score on the exam is less than 143 (on a scale of 150). marie samples 24 test takers and obtains a sample mean score of 130.

Answers

The Confidence mean of the following given data is  (146) (154)

Z Score

The Z-score provides information on how far a given value deviates from the standard deviation. The Z-score, also known as the standard score, indicates how many standard deviations above or below the mean a specific data point falls. The level of variability within a particular data collection is effectively reflected in the standard deviation.

Standard test

A standardized test is any type of test that (1) requires all test takers to respond to the same questions, or a set of questions from a common bank of questions, in the same way, and (2) is scored in a "standard" or consistent manner, making it possible to compare the relative performance of individual test takers.

Any exam that: (1) mandates that all test takers respond to the same questions, or a set of questions from a common bank of questions, in the same way; and (2) is scored in a "standard" or consistent manner, allowing for comparison of the relative performance of individual test takers.

The computation is shown below;

The z value for the 130 mean score is 2

The margin of error is

= (z × standard deviation) ÷ √n

= (2 × 24) ÷ √143

= (48 ) ÷ √143

= 48 ÷ 11.9

= 4.03

= 4

The confidence  mean is

= (150 - 4) (150 +4)

= (146)  (154)

Confidence  mean = (146)  (154)

Hence, the Confidence mean of the following given data is (146) (154)

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Can anyone pls help me with this question?

Can anyone pls help me with this question?

Answers

Answer:

K, N, and L are all on different lines

Step-by-step explanation:

JK and MC are on parallel lines if false because parallel lines is like an equal sign = and those lines are like a plus sign +

J, N, and L are collinear is also false because collinear means they are on the same line, and J, N, and L are not on the same line

K, M, and L are collinear is also false because collinear means they are on the same line, and K, M, and L are not on the same line

K, N, and L are on different lines is true. K is on a different line than N and L, N is on a different line that K and N, and N is on a different line that K and L

I hope this helps :)


Determine whether ΔA B C ≅ ΔX Y Z . Explain. A(3,-1), B(3,7), C(7,7), X(-7,0), Y(-7,4), Z(1,4)

Answers

By SSS (Side, side, side) congruency;

ΔA B C ≅ ΔX Y Z .

Given that;

The vertices of ΔA B C are;

A (3, -1) , B (3, 7) and C (7, 7)

The vertices of  ΔX Y Z  are;

X (-7, 0), Y (-7, 4), Z (1, 4)

We have to prove that ΔA B C ≅ ΔX Y Z .

What is congruency in triangle?

If all three corresponding sides are equal and all the three corresponding angles are equal in measure, then Two triangles are said to be congruent.

Now,

The vertices of ΔA B C are;

A (3, -1) , B (3, 7) and C (7, 7)

The vertices of  ΔX Y Z  are;

X (-7, 0), Y (-7, 4), and Z (1, 4)

To prove ΔA B C ≅ ΔX Y Z we use distance formula and prove all sides are equal.

In ΔA B C;

Distance between A and B;

\(D_{AB} = \sqrt{(3-3)^2 + (7 -(-1))^2} = \sqrt{64} = 8\)

Distance between B and C;

\(D_{BC} = \sqrt{(7-3)^2 + (7 -7)^2} = \sqrt{16} = 4\)

Distance between C and A;

\(D_{CA} = \sqrt{(7-3)^2 + (7 -(-1))^2} = \sqrt{80}\)

In ΔX Y Z;

Distance between X and Y;

\(D_{XY} = \sqrt{(-7-(-7))^2 + (4 -0)^2} = \sqrt{16} = 4\)

Distance between Y and Z;

\(D_{YZ} = \sqrt{(-7-1)^2 + (4 -4)^2} = \sqrt{64}= 8\)

Distance between Z and X;

\(D_{ZX} = \sqrt{(1-(-7))^2 + (4 -0)^2} = \sqrt{80}\)

Clearly, Distance between sides of  ΔA B C and  ΔX Y Z are;

\(D_{AB} = D_{YZ} \\\\D_{BC} = D_{XY}\\\\D_{CA} = D_{XZ}\)

Hence, By SSS congruency;

ΔA B C ≅ ΔX Y Z .

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José flips a coin two times. If H is heads and T is tails, what is the sample space for this compound event?
a. HH, HT, TH, TT
b. H, T
c. Head, Tail
d. Coin

Answers

When flipping a coin, there are two possible outcomes: heads or tails. When a coin is flipped twice, the sample space for this compound event includes all possible outcomes that can occur.

The sample space is a set of all possible outcomes for an experiment. It can be expressed using set notation. In this case, we can represent the possible outcomes using the terms H and T:HH, HT, TH, and TT. So, the answer is a. HH, HT, TH, TT.Let's take a look at each of these outcomes:1. HH (heads on both flips)2. HT (heads on the first flip and tails on the second)3. TH (tails on the first flip and heads on the second)4. TT (tails on both flips)Therefore, there are four possible outcomes in the sample space of flipping a coin twice.

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the radius of earth is 6371 km. how many times longer is the diameter of earth than the piece of wood's length? use scientific notation.

Answers

The  \(1.2742*10^4 km / L\) times longer is the diameter of earth than the piece of wood's length.

The radius of earth is 6371 km.

Let's say the length of the piece of wood is L.

The diameter of the Earth is 2 times its radius

The radius of our planet, The Earth, is the distance from the center of the Earth to a point on or near its surface, and it ranges from nearly 6,378 km to nearly 6,357 km.

Radius of a circle is the distance from the center of the circle to any point on it's circumference. It is usually denoted by 'R' or 'r'. The area and circumference of a circle are also measured in terms of radius.

The diameter of a circle is the length of the line starting from one point on a circle to another point and passing through the center of the circle. It is equal to twice the radius of the circle. It is usually denoted by ‘d’ or ‘D’.

Diameter = 2 x Radius

The diameter of the Earth is 2 times its radius, or 2 x 6371 km = 12742 km.

The diameter of the Earth is 12742 km / L times longer than the length of the piece of wood.

In scientific notation, we can express this as:

12742 km / L = \(1.2742*10^4 km / L\)

The  \(1.2742*10^4 km / L\) times longer is the diameter of earth than the piece of wood's length.

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the ramp measure 9 feet long and is 3 feet from the ground. what is the slope of the ramp?​

the ramp measure 9 feet long and is 3 feet from the ground. what is the slope of the ramp?

Answers

Answer:

c 1/3

Step-by-step explanation:

Answer:

c ....................








Given the differential equation: dy/dx +xy = 3x- e+ 2 with the initial condition y(O) = 1, find the values of y corresponding to the values of Xo+0.1 and Xo+0.2 correct to four decim

Answers

the approximate values of y at x = X₀ + 0.1 and x = X₀ + 0.2 are:

y ≈ 0.9282 at x = 0.1

y ≈ 0.8281 at x = 0.2

To solve the given differential equation, we will use an appropriate method, such as the Euler's method, to approximate the values of y at specific points.

The Euler's method uses the equation:

y₍ₙ₊₁₎ = yₙ + h * f(xₙ, yₙ),

where:

yₙ is the value of y at xₙ

h is the step size,

f(x, y) is the derivative of y with respect to x (i.e., dy/dx), and

y₍ₙ₊₁₎ is the approximation of y at the next point x₍ₙ₊₁₎ = xₙ + h.

Let's apply Euler's method to find the values of y at x = X₀ + 0.1 and x = X₀ + 0.2, where X₀ is the initial condition x = 0 and y(X₀) = 1.

Given the differential equation:

dy/dx + xy = 3x² - \(e^y\) + 2

Rewriting the equation in the form:

dy/dx = -xy + 3x² - \(e^y\) + 2

We have the initial condition:

y(0) = 1

Using Euler's method with a step size of h = 0.1:

1. At x = X₀ + 0.1:

  y₁ = y₀ + h * [ -x₀ * y₀ + 3 * x₀² - \(e^y_0\) + 2 ]

      = 1 + 0.1 * [ -(0) * (1) + 3 * (0)² - e¹ + 2 ]

      = 1 + 0.1 * (0 - e + 2)

      = 1 + 0.1 * (-e + 2)

      = 1 + 0.1 * (-2.7183 + 2)

      = 1 + 0.1 * (-0.7183)

      = 1 - 0.07183

      ≈ 0.9282

2. At x = X₀ + 0.2:

  y₂ = y₁ + h * [ -x₁ * y₁ + 3 * x₁² - \(e^y_1\) + 2 ]

      = 0.9282 + 0.1 * [ -(0.1) * (0.9282) + 3 * (0.1)₂ - \(e^{0.9282}\) + 2 ]

      = 0.9282 + 0.1 * (-0.009282 + 0.003 - \(e^{0.9282}\) + 2)

      ≈ 0.8281

Therefore, the approximate values of y at x = X₀ + 0.1 and x = X₀ + 0.2 are:

y ≈ 0.9282 (correct to four decimal places) at x = 0.1

y ≈ 0.8281 (correct to four decimal places) at x = 0.2

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show that the vectors ⟨1,2,1⟩,⟨1,3,1⟩,⟨1,4,1⟩ do not span r3 by giving a vector not in their span

Answers

It is not possible to find a vector in R3 that cannot be written as a linear combination of ⟨1,2,1⟩,⟨1,3,1⟩, and ⟨1,4,1⟩.

It is required to show that the vectors ⟨1,2,1⟩,⟨1,3,1⟩,⟨1,4,1⟩ do not span R3 by providing a vector that is not in their span. Here is a long answer of 200 words:The given vectors are ⟨1,2,1⟩,⟨1,3,1⟩, and ⟨1,4,1⟩, and it is required to prove that they do not span R3.

The span of vectors is the set of all linear combinations of these vectors, which can be written as the following:Span {⟨1,2,1⟩, ⟨1,3,1⟩, ⟨1,4,1⟩} = {a ⟨1,2,1⟩ + b ⟨1,3,1⟩ + c ⟨1,4,1⟩ | a, b, c ∈ R}where R represents real numbers.To show that the given vectors do not span R3, we need to find a vector in R3 that cannot be written as a linear combination of ⟨1,2,1⟩,⟨1,3,1⟩, and ⟨1,4,1⟩.Suppose the vector ⟨1,0,0⟩, which is a three-dimensional vector, is not in the span of the given vectors.

Now, we need to prove it.Let the vector ⟨1,0,0⟩ be the linear combination of ⟨1,2,1⟩,⟨1,3,1⟩, and ⟨1,4,1⟩.⟨1,0,0⟩ = a⟨1,2,1⟩ + b⟨1,3,1⟩ + c⟨1,4,1⟩Taking dot products of the above equation with each of the given vectors, we get,⟨⟨1,0,0⟩, ⟨1,2,1⟩⟩ = a⟨⟨1,2,1⟩, ⟨1,2,1⟩⟩ + b⟨⟨1,3,1⟩, ⟨1,2,1⟩⟩ + c⟨⟨1,4,1⟩, ⟨1,2,1⟩⟩⟨⟨1,0,0⟩, ⟨1,2,1⟩⟩ = a(6) + b(8) + c(10)1 = 6a + 8b + 10c

Similarly,⟨⟨1,0,0⟩, ⟨1,3,1⟩⟩ = 7a + 9b + 11c⟨⟨1,0,0⟩, ⟨1,4,1⟩⟩ = 8a + 11b + 14cNow, we have three equations and three unknowns.

Solving these equations simultaneously, we geta = 1/2, b = -1/2, and c = 0

The vector ⟨1,0,0⟩ can be expressed as a linear combination of ⟨1,2,1⟩ and ⟨1,3,1⟩, which implies that it is not possible to find a vector in R3 that cannot be written as a linear combination of ⟨1,2,1⟩,⟨1,3,1⟩, and ⟨1,4,1⟩.

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Inverse function f(x)= -3/5x -3

Answers

Answer:

f(x)⁻¹ = -5/3x - 5

Step-by-step explanation:

y = -3/5x - 3

x = -3/5y - 3

x + 3 = -3/5y

(x + 3)(-5/3) = y

-5/3x - 5 = y

Please helpppp meeeee !!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!

Please helpppp meeeee !!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!

Answers

Answer:

The code will stop when x = 12

Step-by-step explanation:

The code loops until x is less than 12. X cannot be equal to 12 it has to be less than.

Problem 6: (10 pts) In plane R², we define the taricab metric: d((₁, ₁), (2, 2)) = *₁-*₂|+|1- 92. Show that d is a metric. (Here is the absolute value sign.)

Answers

The taxicab metric, d((x₁, y₁), (x₂, y₂)) = |x₁ - x₂| + |y₁ - y₂|, is a metric in R².

Is the function f(x) = 2x + 3 a linear function?

To prove that the taxicab metric, d((x₁, y₁), (x₂, y₂)) = |x₁ - x₂| + |y₁ - y₂|, is a metric in R², we need to demonstrate that it satisfies the three properties: non-negativity, identity of indiscernibles, and triangle inequality.

Firstly, the non-negativity property is satisfied since the absolute value of any real number is non-negative.

Secondly, the identity of indiscernibles property holds because if two points have the same coordinates, the absolute differences in the x and y directions will be zero, resulting in a zero distance.

Lastly, the triangle inequality property is fulfilled because the sum of two absolute values is always greater than or equal to the absolute value of their sum.

Therefore, the taxicab metric satisfies all the necessary conditions to be considered a metric in R².

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2 1/4 ÷ 4 1/5 the anser can not be improper

Answers

Answer:

15/28, 15/28, 15/28

Step-by-step explanation:

1. Is simplified

2. Divided

3. Evaluated

(Yes I know there the same but its just in case.)

A student said that 42% of 78 is 45. Is this answer reasonable? Explain.

Answers

Answer:

No because 42% of 78 is 32.76

Step-by-step explanation:

Answer:

Answer: Sample response: 42% can round to 40%, and 78 can round to 80. 40% of 80 is 32, so 42% of 78 should be about 32. 45 is much greater than 32, so the answer is not reasonable.

Step-by-step explanation:

Hope this helps :)

help me please i need to finish my math

help me please i need to finish my math

Answers

The exponential value equation is solved the expression 11^(1/8) can be rewritten as x⁸.

Given data ,

Let the exponential equation be represented as A

Now , the value of A is

The exponential form of a number is a way of representing a number using exponents, where the base is typically a number greater than 1.

x = 11^(1/8)

From the laws of exponents , we get

( mᵃ )ᵇ = mᵃᵇ

mᵃ / nᵃ = ( m / n )ᵃ

And , If we substitute x = 11^(1/8), we can rewrite the expression by replacing 11^(1/8) with x. The expression becomes:

A = x⁸

Hence , if x = 11^(1/8), then the expression 11^(1/8) can be rewritten as x⁸.

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everything you need is in the image
pls help TT

everything you need is in the imagepls help TT

Answers

Answer:

6 x 7 is 42, so A m a y b e?

Step-by-step explanation:

Geometric sequences find the 8th term 12, 4, 4/3

Answers

Answer:

Step-by-step explanation:

first term = 12
common ratio = 1/3

a1 = 12

a2 = 4

a3 = 1.333

a4 = 0.4444

a5 = 0.1481

a6 = 0.04938

a7 = 0.01646

a8 = 0.005487

suppose that we repeatedly draw a random card from a standard deck of 52 cards with replacement until we draw a heart or a face card. note: in each suit, only jacks, queens, and kings are face cards. (a) what is the probability that we draw a total of 4 cards? (b) what is the probability that we draw total of n cards, where n is a positive integer? (c) what is the expected number of times we draw a card?

Answers

The probability that we draw a total of 4 cards is approximately 0.074.

The probability that we draw a total of n cards is a function of n.

the expected number of times we draw a card until we get a heart or a face card is: E(X) = 1/p = 3.25.

How we get the probability?

To solve this problem, we can use the geometric distribution, which models the number of trials needed to get the first success in a sequence of independent trials.

Find the probability of success p.

Since we are drawing a heart or a face card, there are 16 cards (4 face cards and 12 hearts) out of 52 that are successful. Therefore, the probability of success is:

p = 16/52 = 4/13

Use the geometric distribution to answer the questions.

What is the probability that we draw a total of 4 cards

We want to find the probability that we get the first success on the fourth trial, i.e., we draw three non-successes followed by a success. The probability of this event is:

P(X = 4) = \((1 - p)^3 * p = (9/13)^3 * (4/13) = 0.074\)

What is the probability that we draw a total of n cards, where n is a positive integer

We want to find the probability that we get the first success on the nth trial, i.e., we draw n-1 non-successes followed by a success. The probability of this event is:

\(P(X = n) = (1 - p)^(^n^-^1^) * p\)

What is the expected number of times we draw a card

The expected value of a geometric distribution is 1/p. Therefore, the expected number of times we draw a card until we get a heart or a face card is:

E(X) = 1/p = 13/4

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