Thermal energy from the Sun travels to Earth by
Hello User!
Here is the answer :
Radiation
Heat is transferred by radiation. The energy is carried by electromagnetic wave. The energy is carried from the Sun to space surrounding. Therefore, thermal energy from the Sun travels to Earth as electromagnetic waves
Reto: Aníbal desea construir una carpa de base hexagonal de 1,40 m de altura. El vértice de la base es de 0,80m y la longitud de la arista lateral mide 1,80m. ¿cuanto de tela necesito para cubrir la superficie lateral de la carpa? ¿cuanto de tela necesito para cubrir la base de la pirámide, que es un hexágono regular? Cuál es el volumen de la pirámide? ¿cuál es el área total de la pirámide?
Answer:
1.- para cubrir la superficie lateral 4.32 metros²
2.- Area de la base 2.15 metros²
3.- Volumen 1 m³
4.- Area total 6.47 metros²
Explanation:
El área lateral sera calcular el area de seis triangulos iguales cuya base es
0.80 de base x 6 lados = 4.80 metros perimetro de la base
4.80 perimetro de base x 1.80 arista lateral / 2 = 4.32m2
Area de la base:
Perímetro x Apotema / 2
Siendo la Apotema la altura de los triangulos que componen un hexagono calculada utilizando el teorema de pitágoras:
\(\sqrt{0.8^2 + (0.8/2)^2} = Apotema\)
Apotema = 0.894427191
Area: 4.80 x 0.894427191 / 2 = 2.146625258
sumando el area de la base mas el area lateral se obtiene el area total
2.15 + 4.32 = 6.47 metros
Volumen de la pirámide:
Area de la Base x Altura / 3
2.15 x 1.40 / 3 = 1.00333 m3
if tou were to become a scientist what will be your contribution to the society? why?
Question 4 How much time does it take to walk 8 km north at a velocity of 3.8 km/h?
Given parameters:
Displacement = 8km
Velocity = 3.8km/h
Unknown:
time = ?
Solution:
Velocity is displacement divided by time.
Velocity = \(\frac{displacement}{time}\)
Displacement = velocity x time
Input the parameters:
8 = 3.8 x time
Time = \(\frac{8}{3.8}\) = 2.1s
The time taken is 2.1s
What is the type of radioactive decay represented by the equation above? A. Gamma B. Fusion C. Alpha D. Fission 40. Alberta uses clean coal technology. This means that the coal has a lower i content than coal in other parts of Canada, which results in reduced ii The statement above is completed correctly by the information in row olla sdf to ridW Row i A. sulfur greenhouse gas emissions acid deposition sulfur carbon greenhouse gas emissions acid deposition carbon B. C. D. 29. Which of the following graphs depicts the relationship between gravitational field strength and the mass of the International Space Station orbiting Earth? A. Field Strength (N/kg) C. Field Strength (N/kg) Mass (kg) Mass (kg) B. Field Strength (N/kg) D. Field Strength (N/kg) Mass (kg) CADLC 30. Which of the following sequences of colours represents the changing temperatu from the surface to the atmosphere of the sun? a A. Red, orange, yellow, blue B. Yellow, red, orange, blue C. Orange, yellow, blue, red D. Blue, yellow, orange, red 1. When a star undergoes a blue shift, the star is A. moving away from an observer B. moving towards an observer C. moving parallel to an observer D. stationary Mass (kg)
The sun is Yellow, red, orange, and blue. Therefore option B is correct.
The star is moving toward an observer. Therefore option B is correct.
39. The type of radioactive decay represented by the equation provided Gamma. Therefore option A is correct.
40. The statement is completed correctly by the information which states that the coal in Alberta has a lower carbon content than coal in other parts of Canada, resulting in reduced greenhouse gas emissions.
29. graph B depicts the relationship between gravitational field strength and the mass of the International Space Station orbiting Earth.
30. The correct sequence of colors representing the changing temperature from the surface to the atmosphere of the sun is Yellow, red, orange, and blue. Therefore option B is correct.
1. When a star undergoes a blue shift, it indicates that the star is moving toward an observer. Therefore option B is correct.
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if two firecrackers produce a sound level of 86 db when fired simultaneously at a certain place, what will be the sound level if only one is exploded? [hint: add intensities, not db 's.] express your answer to two significant figures and include the appropriate units.
The sound level of 86dB when fired simultaneously will have sound level of 82.9898dB.
Theory-
According to the Beta factor model, the common cause will have an equal impact on every member of a component group that shares a common cause.
The beta factor model is simple to use, models common cause failures, and only requires one parameter to be determined.
A drawback of the beta factor model is that it is impossible to quantify the failure of k–m components within a common cause component group.
As a result of multiplying the partial beta factors, the beta factor is calculated.
Mathematics-
\(\beta =10log\frac{2I}{i} \\\\\beta 1=10log\frac{I}{i} \\\\\beta =10log2 +\beta 1\\\\\beta 1=\beta -10log2\)
Calculation-
\(\beta 1=86-10log2\\\\\beta 1=86-3.0102\\\\\beta 1= 82.9898dB\)
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What are the five elements of fitness?
Answer:
5 Components of Physical Fitness
Cardiovascular Endurance.
Muscular Strength.
Muscular endurance.
Flexibility.
Body Composition.
Asbestos would most likely be found where in a house?
a. around electrical wires
b. in the paint
c. around the fireplace
d. around pipes
Asbestos would most likely be found around pipes in a house.
Asbestos is nan organic naturally occurring mineral.
Its composition is similar to thin fibers like crystals of of silicate mineral.
The fibers of Asbestos are so thin and microscopic that they liberate into the atmosphere due to erosion and other processes.
These tiny particles are considered harmful for health as they are carcinogenic in nature and causes mesothelioma.
Its melting point is between 400 to 1,040 °C and is available in blue, green, grey white and yellow color.
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A bike rider was moving to the right at a constant speed. Suddenly the wind then starts blowing against her with 3 N of force to the left. What is happening the moment the wind starts blowing? A. The bike rider will start to speed up B. The bike rider will continue at a constant speed C. The bike rider instantly start moving will get blown back to the left. D. The bike rider will begin to slow down
Answer:
The correct option is D
Explanation:
This question can be better understood when discussed using the Newton's first law of motion which states that an object would continue to move with a uniform speed (in a straight line) unless acted upon by an external force. What happens here (in the question) is that the bike rider would have continued moving at a constant speed (to the right) if not for the opposing force of the wind that acted against her (to the left). This wind/force would cause her speed to reduce or slow down (as posited by the law).
how to tell how much work gravity does on something?
How many kilojoules of heat must be supplied to 4.1 g of ice at -26 oc to convert it to steam at 147 oc?
The amount of heat supplied to 4.1 g of ice at -26°C to convert it to steam at 147°C will be 12.81 kJ.
What is the heat supplied?The heat supplied is by the summation of the sensible heat and the latent heat of the substance.
Heat = Sensible heat + Latent heat
The mass of the substance is 4.1 grams (4.1 × 10⁻³ kilograms).
The sensible heat is given as
Q = mCΔT
Where C is the specific heat at constant volume (4.18 kJ / kg-K up to 100°C and 0.718 kJ / kg-K after 100°C), m is the mass and ΔT is the temperature difference.
The latent heat is given as
Q = mL, where L is the specific latent heat of a substance (334 kJ / kg at 0°C and 2230 kJ / kg at 100°C).
Heat = 4.1 × 10⁻³ × [4.18(0 + 26) + 334 + 4.18(100 - 0) + 2230 + 0.718(147 - 100)]
Heat = 4.1 × 10⁻³ × [108.68 + 334 + 418 + 2230 + 33.746]
Heat = 4.1 × 10⁻³ × 3124.426
Heat = 12.810 kJ
The amount of heat supplied to 4.1 g of ice at -26°C to convert it to steam at 147°C will be 12.81 kJ.
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7. A parachutist jumps from a plane and reaches a terminal velocity of 45.0 m/s. Once he
opens his parachute, he slows to 5.0 m/s it a span of 20 s. What was his rate of
deceleration?
(45. 0 m/s) - (5.0 m/s) ÷ 20
40 m/s ÷ 20 s = 2 meter second minus 2.
I am sry if my ans is wrong
A cyclist bikes with an average velocity of 20sm for 5 seconds. What is the magnitude of the cyclist's displacement? Your answer should have one significant figure. m
The magnitude of the cyclist's displacement is approximately 100 meters.
The average velocity of the cyclist is given as 20 meters per second (20 m/s) for a duration of 5 seconds. To find the displacement, we can use the formula:
Displacement = Average Velocity × Time Duration
Substituting the given values:
Displacement = 20 m/s × 5 s = 100 meters
Therefore, the magnitude of the cyclist's displacement is approximately 100 meters. This means that, on average, the cyclist travels a distance of 100 meters in the given time period. It's important to note that the magnitude of displacement only considers the total distance traveled, regardless of the direction. In this case, the direction of the displacement is not specified, and we are solely interested in the magnitude.
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please help me very urgent :((
What is the net force (including direction and magnitude) acting on the object on the above left?
What is the net force (including direction and magnitude) acting on the object on the above right?
Answer:
-150 N
Explanation:
(Newton's second law) F=ma
Sum of forces in Y direction= (+200 N)+(-200 N)= 0...
forces cancel, object does not accelerate up/down
Sum of forces in X direction= (+65 N)+(-65 N)+(-150 N)
= -150 N
notice that the +/- 65 components cancel, leaving a net force of 150 N in the LEFTwards direction (which is typically defined as negative)
Overall, the net force is -150 N
to determine the magnetic flux, magnetic field parallel to the surface is multiplied by the area of the surface. True or False
False. To determine the magnetic flux, multiply the magnetic field strength by the area, then multiply by the cosine of the angle between the field and area.
What is magnetic flux?Magnetic flux is a measurement of the total magnetic field which passes through a given area.
It is a useful tool for helping describe the effects of the magnetic force on something occupying a given area. The SI unit of magnetic flux is the Weber (named after German physicist and co-inventor of the telegraph Wilhelm Weber) and the unit has the symbol Wb.
Because the magnetic flux is just a way of expressing the magnetic field in a given area, it can be measured with a magnetometer in the same way as the magnetic field.
In conclusion, magnetic flux is not determined by the multiplication of the magnetic field parallel to the surface by the area of the surface.
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How much time does a car with an acceleration of 2 m/s2 take to go from 10 m/s to 30 m/s?
Answer: 10 seconds for the car to go from a velocity of 10 m/s to 30 m/s with an acceleration of 2 m/s^2.
Explanation:
To calculate the time it takes for a car with an acceleration of 2 m/s^2 to go from a velocity of 10 m/s to a velocity of 30 m/s, we can use the equation:
time = (final velocity - initial velocity) / acceleration
In this case:
time = (30 m/s - 10 m/s) / 2 m/s^2
time = 20 m/s / 2 m/s^2
time = 10 s
Therefore, it takes 10 seconds for the car to go from a velocity of 10 m/s to 30 m/s with an acceleration of 2 m/s^2.
suppose that a white dwarf is gaining mass through accretion in a binary system. what happens if the mass someday reaches the 1.4 solar mass limit?
Answer:
Hey there
When a white dwarf reaches 1.4 solar masses it implodes and becomes a neutron star. this mass limit is known as the "Chandrasekhar limit". It occurs when electron degeneracy pressure (the force that keeps the star from collapsing) is no longer strong enough to hold up aggainsed gravity.
When a substance changes from one phase to another, which of the following occurs?
ОА.
The substance loses or gains heat.
OB.
The average kinetic energy of the substance changes.
OC.
The temperature of the substance changes.
OD
The molecular motion of the substance changes.
Answer:
D
Explanation:
Hope this helped
service equipment at other than dwelling units shall be legibly marked in the field with the available fault current. the field marking(s) shall include ? and be of sufficient durability to withstand the environment involved
Service equipment at other than dwelling units shall be legibly marked in the field with the available fault current. the field marking(s) shall include the date the fault-current calculation and be of sufficient durability to withstand the environment involved
What is the power system fault current?The electrical current that passes across a circuit when there is an electrical defect is known as the fault current. When two or more electrical conductors short to one another or to ground, a fault condition is created.
In Marking the field, the maximum available fault current must be legibly marked on service equipment at non-dwelling units. The field marking(s) must be durable enough to resist the environment and include the date the fault-current calculation was completed.
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water evaporates from a lake into the air, forming clouds. the clouds eventually form rain and it falls to the ground. in which spheres does this cycle happen?
The cycle of water or H₂O evaporating from lake and other bodies of water forming clouds and rain back to the surface of the earth happens in hydrosphere and stratosphere.
Hydrosphere is defined as water that is on the earth including surface of the planet such as ocean, lake and ice, underground source of water such as groundwater, as well as moisture in the air. The water, also known as H₂O gets heated up by the sun, evaporates into the air forming clouds happen in the atmosphere of the earth, specifically stratosphere, where most of the clouds are forming. After the clouds can no longer hold the accumulation of vaporization of the water, it will eventually get released back into the earth in the form of rain or snow.
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PLS HELP MEEEE (NO LINKS PLEASE)
The difference between visible light and gamma rays is that
a.
the amplitude of visible light is greater.
c.
they travel through a different medium.
b.
the speed of gamma rays is greater.
d.
the frequency of gamma rays is greater.
Answer:
D. the frequency of gamma rays is greater.
Explanation:
Gamma rays occupy the short-wavelength end of the spectrum; they can have wavelengths smaller than the nucleus of an atom. Visible light wavesare one-thousandths the width of human hair--about a million times longer than gamma rays. Radio waves, at the long-wavelength end of the spectrum, can be many meters long.
HAVE A WONDERFUL REST OF THE DAYYYY! :3
Help me please if you don’t mind. The question is:
Blaine hit the ball with 50 newtons of force. It accelerated of his bat at 50 meters per second squared. What is the mass of the ball? *
50 points
Procedure I. Confirm that torque = force times lever arm for a horizontal lever. Click "Reset All" to make sure that the apparatus is in its default arrangement. Leave Auto-Release on. 1. Drag and drop to attach a clamp at 0 cm. Attach a mass hanger to the clamp. This is Hanger 1. 2. Add enough masses to the hanger for a total mass of 100 g including the clamp, hanger and added mass. Since the clamp's mass is 20 g and the hanger's mass is 50 g. you'll need to add just 30 g. The 10 and 20-g masses are hard to grab. You can just grab the "10 g" and "20 g" labels below the mass images for convenience. Click on the masses on the hanger. The information box will read "Mass on this hanger-30. Don't forget to count the other 70 g when determining the total mass. For practice using rotational equilibrium you'll explore five different scenarios. In each case you'll make adjustments to a hanger on the right end to achieve balance. This will occur when the magnitude of the clockwise torque is equal to the magnitude of the counterclockwise torque. As a guide you'll fill in the blanks in a rows in Tables 1 and 2. The counter- clockwise torque due to the fixed mass at the left end of the beam is pre-calculated. torque,lever arm weight = 500 m.100 g N = .0500 gm N In Trials 1-3 you're given known positions for the right hanger. You'll then adjust its hanger weight to achieve balance.
To achieve rotational equilibrium in the given scenario, where a horizontal lever is being used, we need to ensure that the clockwise torque is equal to the counterclockwise torque.
Let's go through each trial and make the necessary adjustments to achieve balance.
Trial 1:
The total mass on the hanger is 100g, including the mass of the clamp, hanger, and additional mass. The mass on the hanger is 30g, and we need to add the other 70g to achieve a total of 100g.
Trial 2:
To achieve balance, we can adjust the position of the right hanger. The known positions for the right hanger are provided, so we can move it accordingly until the torques balance out.
Trial 3:
Similar to Trial 2, adjust the position of the right hanger until equilibrium is reached.
Trial 4:
In this trial, we need to adjust the hanger weight. By adding or removing mass from the hanger, we can achieve balance when the torques are equal.
Trial 5:
Again, adjust the hanger weight to achieve equilibrium by making the clockwise torque equal to the counterclockwise torque.
Remember, for rotational equilibrium, the torque is the product of the lever arm length and the force applied perpendicular to the lever arm. By adjusting the hanger weight or the position of the right hanger, we can balance the torques and achieve equilibrium in each trial.
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A baby born more than 3 weeks before the due date is considered
germinal.
fetal.
preterm.
prenatal.
Answer:
preterm baby
Explanation:
A ray in flint glass (n = 1.61)
reaches a boundary with glycerol
(n = 1.47) at 68.9 deg. Does it
reflect internally or refract into
the air?
Enter o for reflect, and 1 for refract.
(Water n = 1.33, Air n = 1.00)
Answer:0
Explanation:
0
The angle of refraction θ₂ is 73.3°. Since θ₂ is less than 90 degrees, the ray will refract.
To determine whether the ray will reflect internally or refract into the air at the boundary between flint glass (n = 1.61) and glycerol (n = 1.47), we can use Snell's law. Snell's law relates the angles of incidence and refraction at an interface between two different media.
Snell's Law is given as;
n₁ × sin(θ₁) = n₂ × sin(θ₂)
where:
n₁ and n₂ are refractive indices of two media,
θ₁ is the angle of incidence, and
θ₂ is the angle of refraction.
In this case, the ray is traveling from flint glass (n₁ = 1.61) to glycerol (n₂ = 1.47). The incident angle is given as 68.9 degrees.
To determine whether the ray will reflect or refract, we need to compare the angle of refraction (θ₂) to 90 degrees. If θ₂ is greater than 90 degrees, the ray will reflect internally. If θ₂ is less than 90 degrees, the ray will refract.
Let's calculate the angle of refraction (θ₂) using Snell's law:
n₁ × sin(θ₁) = n₂ × sin(θ₂)
1.61 × sin(68.9°) = 1.47 × sin(θ₂)
0.996 = 1.47 × sin(θ₂)
sin(θ₂) = 0.996 / 1.47
θ₂ ≈ 73.3°
Since θ₂ is less than 90 degrees, the ray will refract.
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microscope objectives stay relatively in focus when magnification is changed. ?
a. parfocal
b. field of view
c. resolution
d. lowest
Answer: Parfocal will be the answer.
Explanation:
Three liquids are at temperatures of 2°C, 21°C, and 34°C, respectively. Equal masses of the first two liquids are mixed, and the equilibrium temperature is 5 C. Equal masses of the second and third are then mixed, and the equilibrium temperature is 30.1°C.
Find the equilibrium temperature when equal masses of the first and
third are mixed.
Answer In units of 'C.
Answer:
m - mass of each liquids (all masses are equal )
C_1C 1 - specific heat of the first third C_2C 2 - specific heat of the second liquid
C_3C 3- specific heat of the third liquid
Temperature of liquids: T_1=7 ◦C,T_2=20◦C, T_3=34◦CT
1 =7◦C,T 2 =20◦C,T 3=34◦C
Temperature of 1+2 liquids mix: T_{12}=11^oCT
12 =11 oC
Temperature of 2+3 liquids mix: T_{23}=22.6^oCT
23=22.6 oC
Temperature of 1+3 liquids mix: T_{13} - ?T 13 −?
When the first two are mixed:
m C₁ (T₁ − T_{12}) + m C₂ (T₂ − T_{12}) = 0 \\ C₁ (7− 11) + C₂ (20 − 11) = 0\\ 4C_1=9C_2\\ C_1=2.25C_2mC₁(T₁−T 12)+mC₂(T₂−T 12 )=0C₁(7−11)+C₂(20−11)=04C \1=9C 2C 1 =2.25C 2
When the second and therd are mixed:
m C_2 (T_2 − T_{23}) + m C_3 (T_3 − T_{23}) = 0 \\ C_2 (20−22.6) + C₂ (34 −22.6) = 0\\ 2.6C_2=11.4C_3\\ C_2=4.38C_3mC 2 (T 2 −T 23 )+mC 3 (T 3 −T 23 )=0C 2(20−22.6)+C₂(34−22.6)=02.6C 2 =11.4C 3C2 =4.38C 3
When the first and therd are mixed:
m C_1 (T_1 − T_{13}) + m C_3 (T_3 − T_{13}) = 0 \\ C_1 (7−T_{13}) + C_3 (34 −T_{13}) = 0\\ C_1=2.25C_2=2.25(4.38C_3)=9.86C_3\\ 9.86C_3 (7−T_{13})=-C_3(34 −T_{13})\\ 9.86 (7−T_{13})=-(34 −T_{13})\\ T_{13}=9.5^oCmC 1(T1 −T13)+mC 3(T3−T13 )=0C1 (7−T13 )+C 3(34−T 13 )=0C1 =2.25C2=2.25(4.38C3 )=9.86C39.86C3 (7−T13 )=−C3(34−T13 )9.86(7−T13)=−(34−T13 )T13 =9.5 oCT_{13}=9.5^oCT 13 =9.5 o C:
Which observations correctly describe the second law of thermodynamics? check all that apply.
thermal energy that is not used to do work is often released to the surroundings.
thermal energy flows from a cooler object to a warmer object.
thermal energy flows from a warmer object to a cooler object.
thermal energy is released as unusable energy by a heat engine, which is never 100 percent efficient.
thermal energy flows when two objects in contact have a temperature difference.
answers: 1,3,4,5
Answer:
I would agree with the answers 1, 3, 4, 5
Obviously energy will not spontaneously flow from a cooler object to a warmer object
Answer:
A. Thermal energy that is not used to do work is often released to the surroundings.
C. Thermal energy flows from a warmer object to a cooler object.
D. Thermal energy is released as unusable energy by a heat engine, which is never 100 percent efficient.
E. Thermal energy flows when two objects in contact have a temperature difference.
Explanation:
Got it right on edge 23
Bone has a Young's modulus of about 1.8 x 1010 Pa. Under compression, it can withstand a stress of about 1.51 × 108 Pa before breaking. Assume that a femur (thigh bone) is 0.5 m long, and calculate the amount of compression this bone can withstand before breaking. Answer in units of mm.
The femur can withstand a compression of about 4.1945 mm before breaking.
Compression calculations explained.We can use the formula for compressive stress to calculate the amount of compression that the femur bone can withstand before breaking:
Stress = Force / Area
where the force is the force applied to the bone and the area is the cross-sectional area of the bone.
To find the cross-sectional area of the femur bone, we can assume that it has a circular cross-section and use the formula:
Area = πr^2
where r is the radius of the cross-section.
Since the length of the femur bone is 0.5 m, we can assume that the cross-sectional area remains constant along its length.
Let's assume that the force required to break the bone is the maximum compressive stress that it can withstand, which is 1.51 × 10^8 Pa. We can rearrange the stress formula to solve for the force.
We can use the equation for strain under compression:
strain = stress / Young's modulus
where stress is the maximum stress the bone can withstand before breaking, and Young's modulus is a measure of the stiffness of the material. The strain is a measure of how much the bone compresses under stress.
To find the compression distance, we can rearrange this equation to solve for the compression distance:
compression distance = strain x original length
where the original length is the length of the bone before compression
Substituting the given values:
stress = 1.51 × 10^8 Pa
Young's modulus = 1.8 × 10^10 Pa
original length = 0.5 m
First, we can calculate the strain:
strain = stress / Young's modulus = (1.51 × 10^8 Pa) / (1.8 × 10^10 Pa) ≈ 0.008389
Next, we can calculate the compression distance:
compression distance = strain x original length = (0.008389) x (0.5 m) = 0.0041945 m
Finally, we can convert the result to millimeters:
compression distance = 0.0041945 m x (1000 mm/m) = 4.1945 mm
Therefore, the femur can withstand a compression of about 4.1945 mm before breaking using Stress = Force / Area
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Please help me with 17 and 18!!!!!! (It's related to 16) It's due today!!!!! NO LINK PLEASE!!!!!!!!
Answer:17: A wave can be defined as follows: It is important to realize that a wave is quite a different object than a particle. A baseball thrown though a window transfers energy from one point to another, but this involves the movement of a material object between two points.
Explanation:
18: In this way, we classify waves into electromagnetic and mechanical waves. The main difference between mechanical and electromagnetic waves is that electromagnetic waves do not require a medium to propagate whereas mechanical waves require a medium in order to propagate.