Among the recorded exercises, running at 12 km/h expends the foremost vitality per diminutive, with a value of 60 kJ.
The amount of energy used each minute in different activitiesThe table gives data on the vitality consumption per miniature for different exercises, counting strolling at 6 km/h, running at 12 km/h, cycling at 16 km/h, swimming at 25 m/minute, and incredible vigorous exercise.
To decide which movement expends the foremost vitality per diminutive, we examine the values within the "Vitality utilized per minute/kJ" column.
Strolling (6 km/h) | 28Running (12 km/h) | 60Cycling (16 km/h) | 31Swimming (25 m/min) | 23Vigorous exercise (energetic) | 42Among the recorded exercises, running at 12 km/h expends the most elevated sum of vitality per miniature, with a value of 60 kJ. This implies that for each diminutive of running at this speed, around 60 kilojoules of vitality are used.
Comparatively, strolling at 6 km/h utilizes 28 kJ, cycling at 16 km/h requires 31 kJ, swimming at 25 m/minute expends 23 kJ, and incredible vigorous exercise exhausts 42 kJ per diminutive.
Subsequently, running at 12 km/h expends the foremost vitality per miniature, with the use of 60 kilojoules.
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The complete question:
The table underneath appears the sum of vitality utilized per miniature of completely different exercises: strolling at 6 km/h, running at 12 km/h, cycling at 16 km/h, swimming at 25 m/minute, and energetic vigorous exercise. Which action devours the foremost vitality per miniature, and how much vitality does it expend?
If you are driving 100 km/h
along a straight road and you look to the side for 3.0 s
, how far do you travel during this inattentive period?
The distance you will travel during this inattentive period is 0.083 Km
How do I determine the distance travelled?We'll begin by listing out the given parameters from the question. This is given below:
Speed = 100 Km/hrTime = 3 s = 3 / 3600 = 0.00083 hrDistance travelled = ?We know that speed is defined as:
Speed = distance / time
Cross multiply
Distance = speed × time
With the above formula, the distance travelled can be obtained as follow:
Distance = speed × time
Distance travelled = 100 × 0.00083
Distance travelled = 0.083 Km
Thus, from the above calculation, we conclude that the distance travelled is 0.083 Km
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A 100 kg cart is moving at 3 m/s. Calculate the cart’s kinetic energy.
Answer:
450
Explanation:
Given,
Mass= 100kg
Velocity= 3 m/s
Kinetic Energy= ?
Kinetic Energy= 1/2 mv^2
= 1/2× 100× 3^2
= 1/2× 900
= 450.
HOPE IT HELPED :)
An average person is 175 cm tall. How
many people could you stack one on top of
another to reach the top of the CN Tower
(553 m)?
The number of people you will stack to reach the top of the CN Tower (553 m) is 316 people
Hor to convert 175 centimeters to metersWe'll begin by converting 175 cm to m. This can be obtained as illustrated below:
100 cm = 1 m
Therefore,
175 cm = (175 cm × 1 m) / 100 cm
175 cm = 1.75 m
Thus, 175 cm is equivalent to 1.75 m
How to determine the number of people neededThe number of people needed to be stacked to get to the top of the CN tower can be o btained asfollow:
Height of tower = 553 mHeight of a person = 1.75 mNumber of people needed =?Number of people needed = Height of tower / height of a person
Number of people needed = 553 / 1.75
Number of people needed = 316 people
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Which metal is the hardest?
Copper
Lead
Nickel
Titanium
Which metal is the hardest?
Copper
Lead
Nickel
Titanium
25. The length of a bow is L. When it vibrates in the fundamental mode with a length of 2 L, the frequency is f. Taking half of the given length and pulling it to a length of 2L as before, the frequency obtained by vibrating in the basic method is,
(i) 3fo
(iv) √3f
(ii) 6fo
(v) √6fo
(iii) f/3
Taking half of the given length and pulling it to a length of 2L as before, the frequency obtained by vibrating in the basic method is 6fo. option(ii)
When a bow vibrates in its fundamental mode with a length of 2L, the frequency is denoted as f. Now, let's consider the scenario where half of the given length (L) is pulled to a length of 2L.
In the fundamental mode of vibration, the frequency is inversely proportional to the length of the vibrating object. Therefore, if the length of the bow is halved to L, the frequency would double to 2f.
When this new length of L is pulled to a length of 2L, we need to determine the frequency obtained in the fundamental mode.
Since the frequency is inversely proportional to the length, we can use the inverse relationship to find the new frequency.
If the original frequency was 2f at length 2L, when the length is reduced to L, the new frequency would be (2f)/(2L) = f/L.
Now, if this length of L is stretched to 2L again, the new frequency in the fundamental mode would be (f/L) * (2L) = 2f. option(ii)
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Help me in PE plzzzzzz
Answer:
Balance. Eyes. Elbow. Follow-Through
Explanation:
Answer:
you have to take 4 to 5 steps to do the step
Explanation:
which of the following liquid is miscible in water? a. Alcohol, b.mustard oil, c.Kerosene oil , d.None of these
Answer:
alcohol
Explanation:
Alcohol is miscible in water.
Wire A X is fold back at p such that /AP/= 40cm and its parallel with px which is 60cm long to form parallel combination. Calculate the effective resistance of the parallel combination if the resistance per unit length of the material of tge wire
Answer: To find the total resistance of the wires, we need to use a formula that takes into account the length and cross-sectional area of the wires and the resistivity of the material they are made of. By plugging in the appropriate values for the length, cross-sectional area, and resistivity of the wires in the formula, we can find the individual resistances of the wires. Then, by using another formula for the total resistance of a parallel combination, we can find the effective resistance of the wires in parallel.
Explanation:R = ρ * (L / A)
where R is the resistance of the wire, ρ is the material's resistivity (resistance per unit length), L is the length of the wire, and A is the cross-sectional area of the wire.
according to the given data
AP= 40 cm
px=60cm
Next, we need to calculate the wire PX's length and cross-sectional area. The length is given as 60 cm, and we can assume the same diameter of 1 mm, giving a cross-sectional area of 0.785 mm^2.
Now we can calculate the resistance of each wire using the formula above:
R_AX = ρ * (80 cm / 0.785 mm^2) = 101.91 * ρ
R_PX = ρ * (60 cm / 0.785 mm^2) = 76.43 * ρ
The total resistance of the parallel combination is given by the formula:
1/R_total = 1/R_AX + 1/R_PX
Substituting the values of R_AX and R_PX, we get:
1/R_total = 1/(101.91 * ρ) + 1/(76.43 * ρ)
1/R_total = (1.55 / ρ)
R_total = ρ / 1.55
therefore, the effective resistance of the parallel combination is (ρ / 1.55) ohms
According to The Flash, The heroes top speed is Mach 3.3, or 2,500 miles per hour. How
long would it take for him to run around the planet? (circumference of the earth is
roughly 25,000 miles) *
Answer:
nearly 2 days or less hes fast but not that fast
Explanation:
but maybe he can run it in five minutes
Consider a regular solution, for which energy
w =5 kJ/mol
At what temperature, in K, will a miscibility limit emerge?
At room temperature,300 K, will a miscibility limit emerge. At the temperature less than, the miscibility will fall below 1%.
What is temperature?Temperature directs the hotness or coldness of a body. In clear terms, it is the method of finding the kinetic energy of particles within an entity. Faster the motion of particles, more the temperature.
Hence, at room temperature,300 K, will a miscibility limit emerge. At the temperature less than, the miscibility will fall below 1%.
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Why might the current in a short circuit be higher than the current in the original circuit?
Answer:
Hope this helps =)
Explanation:
The current in a short circuit may be very high because the resistance in the short circuit is probably less than the resistance in the original circuit.
Group B[1] 12 State Huygens's Principle [2] b) In a Young's double slit experiment, the fringe width obtained is 0.6 cm. When light of wave length 4500 Aº is used if the distance between the screen and the slit is reduced in half, what should be the wavelength of light used to obtain fingers 0.0045 m wide? [3]
The wavelength of light that should be used to obtain fringes that are 0.0045 m wide after reducing the distance between the screen and the slit by half is 2.25 * 10^7 Å.
Huygens's Principle states that every point on a wavefront can be considered as a source of secondary spherical wavelets that spread out in all directions with the same speed as the original wave. The new wavefront is formed by the envelope of these secondary wavelets at a later time.
Now, let's consider a Young's double-slit experiment. In this experiment, when light passes through two narrow slits, it creates an interference pattern on a screen behind the slits. The fringe width is the distance between two consecutive bright or dark fringes in the pattern.
Given that the fringe width obtained is 0.6 cm and the wavelength of light used is 4500 Å (Angstroms), we can calculate the wavelength of light required to obtain fringes that are 0.0045 m wide.
We can use the formula for fringe width in Young's double-slit experiment:
w = (λ * D) / d
Where:
w is the fringe width,
λ is the wavelength of light,
D is the distance between the screen and the double slits, and
d is the distance between the two slits.
Let's calculate the value of D/d using the given information:
D/d = w / λ
= 0.006 m / 4500 Å (1 m = 10^10 Å)
= 0.006 * 10^10 / 4500 m^-1
Now, if the distance between the screen and the slit is reduced by half, the new value of D/d would be:
(D'/d) = (0.006/2) * 10^10 / 4500 m^-1
Now, we can rearrange the equation to solve for the new wavelength (λ'):
(λ' * D') / d = (D/d)
λ' = (D/d) * d / D
= [(0.006/2) * 10^10 / 4500] * (4500 / 0.006) Å
= 0.0045 m * 10^10 / 2 Å
= \(0.00225 * 10^{10\) Å
=\(2.25 * 10^7\)Å
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Determine the percentage of kinetic energy lost by a small ball when it makes an elastic head-on collision with stationary bigger ball. The mass of the bigger ball is 12 times bigger than the mass of the small ball.
The small ball loses 2.37% of its kinetic energy during the elastic head-on collision with the stationary bigger ball.
\(\frac{Kf}{Ki} =\) \(1- [\frac{1}{2}][ \frac{M}{m}] [\frac{2mv^{2} }{[M+m]^{2} }\)
M = 12m
Kf/Ki = 1 - (1/2)(12m/m)[(2mv^2)/(13m)^2]
Kf/Ki = 165/169
(1 - Kf/Ki) x 100% = (1 - 165/169) x 100% = 2.37%
So, the small ball loses 2.37% of its kinetic energy during the elastic head-on collision with the stationary bigger ball.
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You throw a baseball directly upward at time =0 at an initial speed of 12.5 m/s. Ignore air resistance and take =9.80 m/s^2.
Relative to the point where it leaves your hand, what is the maximum height ℎmax
reached by the ball?
At what times t 1/2, up and 1/2, down does the ball pass through half the maximum height on the way up and the way down, respectively?
The ball passes through half the maximum height on the way up and down at approximately 1.28 seconds.
To determine the maximum height reached by the baseball and the times at which it passes through half the maximum height on the way up and down, we can use the equations of motion for vertical motion.
Maximum height (hmax):
The initial velocity (u) is 12.5 m/s and the acceleration due to gravity (g) is -9.8 m/s^2 (negative because it acts downward). The maximum height reached by the ball can be calculated using the equation:
hmax = (u^2) / (2g)
Substituting the given values:
hmax = (12.5^2) / (2 * 9.8) ≈ 8.04 meters
Therefore, the maximum height reached by the ball is approximately 8.04 meters.
Time at half maximum height (t1/2, up and t1/2, down):
The time taken for the ball to reach half the maximum height on the way up and on the way down will be the same. We can calculate this time using the equation:
t1/2 = (u - v) / g
Where v is the final velocity, which is 0 m/s at the highest point of the trajectory.
t1/2 = (12.5 - 0) / 9.8 ≈ 1.28 seconds
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HELP!!!
How does Dr. Hewitt define Potential Energy?
•Extra energy
•Energy that might or might not be there
•Energy of motion
•Energy of position
•Potent energy
Answer:
energy of position
Explanation:
I think that is the answer
To determine the acceleration of an object moving in a straight line, you must calculate the change in its speed during each unit of?
a. velocity
b. time
c. motion
d. declaration
*giving brainliest!*
laser light sent through a double slit produces an interference pattern on a screen 3.0 m from the slits. If the eighth order maximum occurs at an angle of 12.0, at what angle does the third order maximum occur
Solution :
Given the laser light which is sent through the double slit produces an interference pattern on the screen placed 3 meters from the slits.
The 8th order maximum occurs at angle = 12
So,
\($8^{th} \text{ order maxima} = d \sin \theta = m \lambda$\) , m = 8
\($d = \frac{8 \lambda}{\sin 12}$\)
\($\frac{\lambda}{d}= \frac{\sin 12}{8}$\)
\($3^{rd} \text{ order maxima}= d \sin \theta_2 = m_2 \lambda$\)
\($\sin \theta_2 = \frac{m_2 \lambda}{d}=\frac{3 \lambda}{d}$\) \($=0.75\ {\sin 12}$\)
\($\theta_2 = \sin^{-1}\left(0.75\ \sin 12\right)$\)
\($ = \sin^{-1}\left(0.155)$\)
\($=8.91^\circ$\)
1.) Describe the process you would use to find the magnitude (length) of the resultant of two perpendicular vectors, one in the x-direction, and another in the y-direction.
Pythagorean theorem is the process use to find the magnitude of the resultant of two perpendicular vectors.
The Pythagorean Theorem is used to calculate the steepness of slopes of hills or mountains. A surveyor appears via a telescope in the direction of a measuring stick a fixed distance away, so that the telescope's line of sight and the measuring stick form a right angle.
It allows to explain the space round us and is important no longer only in construction however suitably tailored in equations of thermodynamics and preferred relativity.
The Pythagorean Theorem is useful for two-dimensional navigation. you may use it and two lengths to discover the shortest distance. The distances north and west will be the two legs of the triangle, and the shortest line connecting them might be the diagonal. The same ideas may be used for air navigation.
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Use the model of a molecule to answer the question. How many atoms of carbon does this molecule have. URGENT
Answer:
Two
Explanation:
According to the model, there are only 2 carbon molecules.
Answer:
2
Explanation:
What is the height of a building if Kevin can throw a ball down with an initial velocity of 12m/s and it lands with a final velocity of 58m/s.
Answer:
164.29 m
Explanation:
By the conservation of energy, we can write the following equation:
\(\begin{gathered} E_i=E_f \\ \text{mgh}+\frac{1}{2}mv^2_i=\frac{1}{2}mv^2_f \end{gathered}\)Solving for the height h, we get:
\(\begin{gathered} \text{mgh}=\frac{1}{2}mv^2_f-\frac{1}{2}mv^2_i \\ \text{mgh}=\frac{1}{2}m(v^2_f-v^2_i) \\ h=\frac{1}{2mg}m(v^2_f-v^2_i) \\ h=\frac{1}{2g}(v^2_f-v^2_i) \end{gathered}\)So, replacing the initial velocity vi = 12 m/s, the final velocity vf = 58 m/s and the gravity g = 9.8 m/s², we get:
\(\begin{gathered} h=\frac{1}{2(9.8)}(58^2-12^2) \\ h=164.29\text{ m} \end{gathered}\)Therefore, the height of the building is 164.29 m
an inclined plane has a velocity ratio of 2 and efficiency of 95%. it is used to raise a load of 400newtons. determine mechanical advantage? effort required?
Answer:
1.9
Explanation:
Efficiency=mechanical advantage/velocity ratio×100
95=M.A/2×100
95=50M.A
M.A=95/50=1.9
The mechanical advantage of the inclined plane is approximately 2.1053, and the effort required to raise the load of 400 newtons is approximately 189.78 newtons.
To determine the mechanical advantage and effort required for the inclined plane, we can use the formula:
Mechanical Advantage (MA) = Velocity Ratio (VR) / Efficiency
Effort Required = Load / Mechanical Advantage
Given:
Velocity Ratio (VR) = 2
Efficiency = 95% = 0.95
Load = 400 newtons
Calculate the Mechanical Advantage (MA):
MA = VR / Efficiency
MA = 2 / 0.95
MA ≈ 2.1053
Calculate the Effort Required:
Effort Required = Load / MA
Effort Required = 400 / 2.1053
Effort Required ≈ 189.78 newtons
So, the mechanical advantage of the inclined plane is approximately 2.1053, and the effort required to raise the load of 400 newtons is approximately 189.78 newtons.
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A 450 N, uniform, 1.50m bar is suspended horizontally by two vertical cables at each end. Cable A can support a maximum tension of 550N tension without breaking and cable B can support up to 400N. You want to place a small weight on this bar. What is the heaviest weight you can put on without breaking either cable?
the space Hubble Telescope is orbiting earth at a constant speed of 20m/s.The distance between it and planet earth is 100m.The radius of planet earth is 300km. How long will it take for the Space Hubble Telescope to make a complete rotation?
It will take the Hubble Telescope 94,247 seconds or 26.18 hours to complete one full rotation around the Earth.
Rotation time of the Space Hub TelescopeThe Hubble Telescope is in a circular orbit around the Earth at a constant speed of 20 m/s. The distance between the telescope and the center of the Earth is:
300 km + 100 m = 300,100 m.
Orbital period T of the Hubble Telescope = T = 2πr / v
where
r is the radius of the orbit v is the orbital speed.In this case, r = 300,100 m and v = 20 m/s, so:
T = 2π(300,100 m) / (20 m/s) = 94247 seconds
Thus, it will take the Hubble Telescope approximately 94,247 seconds, or about 26.18 hours, to complete one full rotation around the Earth.
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Water has higher specific heat than aluminum. This is all what you should know to answer following questions. An aluminum rod of mass 1 kg at temperature of 80^0C is placed into 1l of water of temperature 10^0C . there is no heat exchange with surroundings. Which material experiences greater change in temperature while system is reaching the thermal equilibrium
Answer:
The Aluminum
Explanation:
With a larger specific heat, water requires more heat to raise its temperature by a temperature degree.
In this system, with equal masses of water and aluminum, the heat moving from the aluminum lowering its temperature by one degree is not sufficient to raise the water temperature by one degree.
an object of 30kg is in free fall in a vacuum where there is no air resistance. Determine the acceleration of the object.
We're missing one essential piece of information that we need in order to answer this question. You have not specified what planet the object is falling on. The answer depends on the gravitational acceleration on that planet, and they're all different.
Without that information, we'll just go ahead and assume that the object is falling to the surface of the Earth. Wherever on Earth this tense drama is unfolding, the acceleration of gravity is going to be around 9.8 m/s² everywhere.
So THAT's the object's acceleration if there is no air resistance. The object's MASS makes no difference. It doesn't matter whether the object is a sparrow feather or a school bus. Heavier objects DO NOT fall faster than light objects.
If there is no air resistance, then ALL objects fall with the same acceleration. It's called the "acceleration of gravity" on that planet or moon, and you can easily look it up. It's 9.8 m/s² on Earth, 1.62 m/s² on the Moon, 3.71 m/s² on Mars, 8.87 m/s² on Venus, and 24.8 m/s² on Jupiter.
A +2e charge is at the point (-1,0) mm in the x,y plane. A –e charge is at the point (0,1) mm. What is the electric field at the origin? What would be the force on a +3e charge at this point? Give the x and y components for both the field and force
Answer:
Let I and j be the unit vector along x and y axis respectively.
Electric field at origin is given by
E= kq1/r1^2 i + kq2/r2^2j
= 9*10^9*1.6*10^-19*/10^-6*(2i+ j)
= (2.88i + 1.44j)*10^-3 N/C
Force on charge= qE= 3*10^-19*1.6*(2.88i +1. 44 j) *10^-3
F= (1.382 i + 0.691 j) *10^-21
Goodluck
Explanation:
I have a material thats 65 cubic feet totaling 40000 cubic yards. How many dump trucks will it take to haul this material?
It will take about 2,500 dump trucks to haul the material. Assuming the capacity of the dump truck is 16 cubic yards.
Note: A standard dump truck is between 10 -16 cubic yards.
1 cubic yard = 27 cubic feet.
from the question:
40,000 cubic yards= 65 cubic feet
hence,
Assuming the dump truck capacity is 16 cubic yards
Then,
number of dump trucks = 40,000 cubic yards/16 cubic yards
=2,500
Therefore a dump truck of 16 cubic yards capacity, will need about 2,500 dump trucks to haul the material totaling 40,000 cubic yards.
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prepare a report on why a vehicle needs to be maintained/serviced after a certain period of time. How is servicing different in a petrol/diesel and electric vehicle?
Vehicles need to be serviced for several reasons such as preventing costly repairs and improving fuel economy.
Why should cars be maintained and / or serviced ?First, regular maintenance can help to prevent costly repairs down the road. Second, maintenance can help to improve fuel economy and emissions. Third, maintenance can help to keep your vehicle safe and reliable.
The servicing requirements for petrol/diesel and electric vehicles differ in a number of ways. Petrol/diesel vehicles require oil changes more frequently than electric vehicles. This is because petrol/diesel engines use oil to lubricate the moving parts, while electric motors do not. Petrol/diesel vehicles also require tune-ups more frequently than electric vehicles.
This is because petrol/diesel engines have more moving parts that need to be synchronized, while electric motors have fewer moving parts.
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19. If an atom has an atomic number of 6 and a
mass number of 14, how many protons,
electrons, and neutrons are in the atom?
Answer:
protons: 6
electrons: 6
neutrons: 8
Explanation:
atomic number -> number of protons -> 6
mass number -> number of protons + number of neutrons
so 14-6 = 8. 8 neutrons
this atom is neutral (net charge is 0), so the number of electrons is the same as the number of protons, which is 6
Explain why the bottom of the ship is deeper below the surface of the sea
when the ship is fully loaded with cargo
Answer:
uhh more mass = more pull by gravity = ship go sinky more
Explanation: