3) Since we are treating light as a particle, it is appropriate to consider a pool ball bouncing off the edges of a pool table as analogous to reflection of a light particle from a mirror. Consider the pool table and cue ball shown below. The table is 8' x 4' and the spacing between white marks along the outer cushion of the table is l’. Imagine that you want to hit the cue ball in such a way as to hit the ball located near the top middle pocket. Based on the locations of the other balls, you determine that the only way to do this is to "double bank" the ball off two sides as shown below. If you estimate that you must hit the first side at a point 3 1/3 feet from the cue ball, determine the angle o which the cue ball will make as it is approaching the other ball. 8' l'ot 1' 100 45 55 Cue Ball 4' M2 120 M 901 3 1/3'​

Answers

Answer 1

By considering the principles of reflection of light particles, we can determine the angle at which the cue ball will approach the other ball after double banking.

To determine the angle at which the cue ball will approach the other ball after double banking, we need to consider the principles of reflection of light particles. Just like a pool ball bounces off the edges of a pool table, a light particle bounces off a mirror at the same angle it approaches the mirror. In this case, the first bank acts as the first mirror, and the second bank acts as the second mirror. Using the given dimensions, we can calculate that the distance from the first bank to the target ball is 4' - 1' = 3'. Since we need to hit the first bank at a point 3 1/3 feet from the cue ball, the angle of incidence (angle between the cue ball's path and the first bank) can be calculated as arctan(3 1/3 / 3) = 55.4 degrees.

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Related Questions

During an experiment, electron A is at rest and electron B is moving north with a constant velocity. A non-zero magnetic field directed south is then applied to the region. In what direction, if any, will each electron be moving after the field is applied

Answers

Electron B will continue moving north, but will experience a force that causes it to curve to the west. Electron A will remain at rest.

After the magnetic field is applied, the moving electron B will experience a magnetic force due to its velocity. The direction of the magnetic force can be determined using the right-hand rule, where if you point your thumb in the direction of the velocity (north) and your fingers in the direction of the magnetic field (south), the resulting force is perpendicular to both and points towards the west.

For electron A, which is initially at rest, it will not experience any magnetic force since it has no velocity. Therefore, electron A will remain at rest.

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Can a wire carry a current and still be neutral—that is, have a total charge of zero? Explain.

Answers

When a wire is carrying current, charges enter the wire at the positive terminal of the voltage source and exit at the negative terminal, keeping the overall charge at zero throughout the current's passage.

Wire carries a current and still be neutral:

Charge moving across a conductor produces current. There is always the same number of electrons in a wire today. As a result of an equal amount of electrons entering and exiting the circuit simultaneously, current flows through the wire when electrons enter the circuit. Current flow may nevertheless be neutral with no overall charge.

Neutral wires do indeed carry current. In single-phase circuits, the current flows in the opposite direction from the "phase" or "line" or "hot" wire, but it is exactly equal to that current. Out of "line," into "neutral," back into "line," and finally back into "neutral" and back into "line" (since it is AC the direction reverses every cycle.)

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pls hurrryyyy!!!!!!!! please

pls hurrryyyy!!!!!!!! please

Answers

Answer:

The penguins are gliding foward without stopping because there is no external force changing their state.

Explanation:

Newtons first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force.

bluetooth headsets use microwave radiation with a wavelength of 12.42 cm. what is the frequency of this electromagnetic radiation (s -1 )?

Answers

The frequency of this electromagnetic radiation is 2.4 GHz.

Frequency is a measure of the number of times that a periodic event, such as a wave, oscillation or rotation, occurs in a given unit of time. It is generally measured in Hertz (Hz), which is the number of cycles per second.

The frequency of an electromagnetic wave is related to its wavelength by the formula:

f = c / λ

where f is the frequency, c is the speed of light (\(3 \times 10^8 m/s\)) and λ is the wavelength.

Substituting the values, we get:

f = c / λ

=>\(\frac {3 \times 10^8 m/s }{ 0.1242 m}\)

=> \(2.4 \times 10^9 Hz\)

So, the frequency of the microwave radiation used in Bluetooth headsets is approximately 2.4 GHz (2.4 x 10^9 Hz).

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In order to cross the galaxy quickly, a spaceship leaves Earth traveling at 0.9999992c. After 19 minutes a radio message is sent from Earth to
the spacecraft.
In the carth-galaxy trame of reference, how far from cart is the spaceship when the message is sent!

Answers

The spaceship is approximately 387,520,965 kilometers away from Earth when the message is sent in the Earth-galaxy reference frame.

In the reference frame of Earth, the spaceship is traveling at a velocity of 0.9999992c. After 19 minutes, a radio message is sent from Earth to the spacecraft.

To calculate the distance from Earth to the spaceship in the Earth-galaxy reference frame, we can use the formula:

Distance = Velocity × Time

Assuming that the speed of light is approximately 299,792 kilometers per second, we can convert the time of 19 minutes to seconds (19 minutes × 60 seconds/minute = 1140 seconds).

Distance = (0.9999992c) × (1140 seconds) = 1.0791603088c × 299,792 km/s × 1140 s ≈ 387,520,965 kilometers

Therefore, in the Earth-galaxy reference frame, the spaceship is approximately 387,520,965 kilometers away from Earth when the message is sent.

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Please answer the following question

Please answer the following question

Answers

Answer:

1. Light Bulb

2. A switch

3. A battery

4. Ammeter

5. Resistor

6. Voltmeter

En un momento dado , la nadadora de una prueba de natación de 100 m espalda está debajo de la cuerda falsa de salida. Indica a) El camino recorrido si acaba de salir b) El camino recorrido si ya ha tocado el final de la piscina c) El desplazamiento de la nadadora en los casos a y b ¿Coincide en algún caso con el camino recorrido?

Answers

If at a given moment, the swimmer in a 100m backstroke swimming race then,

a) The distance traveled if she has just started is 0 meter.

b) The distance traveled if she has just started is 100 meters.

c) The displacement is 0 m in case a and 100 m is case b. No they do not coincide.

Since the swimmer has just started, therefore she has not traveled any distance yet.

As it is mentioned that the swimmer has already touched the end of the pool, she has traveled a distance of 100 meters.

The displacement of the swimmer in cases a and b is zero because displacement is the distance between the starting point and the ending point, regardless of the path taken. In case a, the swimmer has not moved from the starting point yet, so the displacement is zero. In case b, the swimmer has returned to the starting point, so the displacement is also zero.

No, the displacement does not coincide with the distance traveled in either case because the swimmer's path is not necessarily a straight line from the starting point to the ending point. The displacement only considers the initial and final positions of the swimmer, while the distance traveled takes into account the length of the path taken by the swimmer.

Therefore, it could be concluded that at the start diatance is 0m and at the end it is 100m and the displacement at starting is 0m and at the end it is 100m. These do not coincide with each other.

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The question is :

At a given moment, the swimmer in a 100m backstroke swimming race is below the false start rope. State :

a) The distance traveled if she has just started

b) The distance traveled if she has already touched the end of the pool

c) The displacement of the swimmer in cases a and b. Does it coincide with the distance traveled in any case?

Which statement compares the attractive forces that hold particles together?

A. Covalent bonding and Van der Waals forces join separate
molecules together, while ionic and hydrogen bonding produce
compounds.
B. Covalent and hydrogen bonding produce compounds, while ionic
bonding and Van der Waals forces join separate molecules
together.
C. lonic and covalent bonding produce compounds, while hydrogen
bonding and Van der Waals forces join separate molecules
together.
D. Ionic and covalent bonding join separate molecules together, while
hydrogen bonding and Van der Waals forces produce compounds.

Answers

Answer:

Ionic and covalent bonding produce compounds, while hydrogen bonding and Van der Waals forces join separate molecules together.

Ur welcome:)

Answer:

C) lonic and covalent bonding produce compounds, while hydrogen bonding and Van der Waals forces join separate molecules together.

Explanation:

Your friend's dad has a high-stress job, and has high blood pressure as a result. This has caused his arteries to stretch too much, leaving them vulnerable to damage. Which system would be most effected? nervous respiratroy circulatory digestive

Answers

Answer:

Explanation: "Warming up and cooling down are good for your exercise performance — you’ll do better, faster, stronger — and for your heart since the increased work on the heart ‘steps up’ with exercise,” said Richard Stein, M.D., professor of cardiology.

What do you call a molecule composed of two atoms of the same element?

Answers

Answer:

I believe it's called a diatomic atom

a proton in a high-energy accelerator moves with a speed of c/2. use the work–kinetic energy theorem to find the work required to increase its speed to the following speeds. (a) 0.740c (b) 0.873c

Answers

The work required to increase the speed of the proton to Therefore, the work required to increase the speed of the proton to (a) 0.740c is -3.52 x 10⁻¹¹ J and (b) 0.873c is 5.27 x 10⁻¹¹ J

The work-kinetic energy theorem states that the net work done on an object is equal to its change in kinetic energy. Therefore, we can use this theorem to find the work required to increase the speed of a proton in a high-energy accelerator.

Let's first find the kinetic energy of the proton with speed c/2. The kinetic energy (K) of an object with mass m and speed v is given by:

K = (1/2)mv²

Since the proton has a rest mass of 1.67 x 10⁻²⁷ kg, we can calculate its kinetic energy:

K = (1/2)(1.67 x 10⁻²⁷ kg)(c/2)²

K = 9.41 x 10⁻¹¹ J

(a) To find the work required to increase the speed of the proton to 0.740c, we first need to find its final kinetic energy. Since kinetic energy is proportional to the square of the speed, we can use the ratio of speeds to find the final kinetic energy:

(K_final)/(K_initial) = (v_final²)/(v_initial²)

(K_final) = (v_final²)/(v_initial²) * (K_initial)

(K_final) = (0.74c/c/2)² * (9.41 x 10⁻¹¹J)

(K_final) = 5.89 x 10⁻¹¹ J

The change in kinetic energy is:

ΔK = K_final - K_initial

ΔK = 5.89 x 10⁻¹¹ J - 9.41 x 10⁻¹¹J

ΔK = -3.52 x 10⁻¹¹ J

Since the final speed is greater than the initial speed, the work done on the proton is positive. Therefore, the work required to increase the speed of the proton to 0.740c is:

W = ΔK

W = -3.52 x 10⁻¹¹J

(b) To find the work required to increase the speed of the proton to 0.873c, we follow the same steps as in part (a). The final kinetic energy is:

(K_final) = (0.873c/c/2)² * (9.41 x 10⁻¹¹ J)

(K_final) = 1.47 x 10⁻¹⁰J

The change in kinetic energy is:

ΔK = K_final - K_initial

ΔK = 1.47 x 10⁻¹⁰ J - 9.41 x 10⁻¹¹ J

ΔK = 5.27 x 10⁻¹¹ J

Since the final speed is greater than the initial speed, the work done on the proton is positive. Therefore, the work required to increase the speed of the proton to 0.873c is:

W = ΔK

W = 5.27 x 10⁻¹¹J

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Select all of the factors that influence the gravitational potential energy of an object
movement
height
mass
compression

Answers

The answer to your question is mass

what is the width of a single slit through which 520 mm green light passes to form a first diffraction minimum at an angle of 20 degreees?

Answers

The width of the single slit is approximately 0.085 mm.

To find the width of the single slit, we can use the formula for the angle of the first diffraction minimum:

sinθ = λ / d

where θ is the angle of the first diffraction minimum, λ is the wavelength of the light, and d is the width of the slit.

Rearranging the formula, we can solve for d:

d = λ / sinθ

We know that the wavelength of green light is approximately 520 nm (or 0.00052 mm), and the angle of the first diffraction minimum is 20 degrees. Converting the angle to radians, we get:

θ = 20° × π / 180° = 0.349 radians

Plugging in the values, we get:

d = 0.00052 mm / sin(0.349) ≈ 0.085 mm

Therefore, the width of the single slit is approximately 0.085 mm.

The width of a single slit through which 520 mm green light passes to form a first diffraction minimum at an angle of 20 degrees is approximately 0.085 mm.

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Can someone help me plz I don’t know how to do this.

Can someone help me plz I dont know how to do this.

Answers

Answer:

You are right, the answer in neither

Explanation:

Auto A: 20 miles (in 10 seconds) and 25 miles (in 5 seconds)= 45 miles in 15 seconds

Auto B: 45 miles in 15 seconds

Auto A and B are equal

Hope this helps! :) If correct pls mark brainliest :)

Suppose A = B"Cm, where A has the dimensions LT, B has dimensions L²T-1, and C has dimensions LT2. Then the exponents n and have the values

Answers

Complete Question:

Suppose \(A = B^n C^m\), where A has the dimensions LT, B has dimensions L²T⁻¹, and C has dimensions LT². Then the exponents n and m have the values

Answer:

The value of n = ¹/₅

The value of m = ³/₅

Explanation:

Given dimensions;

A = LT

B = L²T⁻¹

C = LT²

The values of n and m are calculated as follows;

\(LT = [L^2T^{-1}]^n[LT^2]^m\\\\L^1T^1 = [L^{2n}T^{-n}]\times [L^mT^{2m}]\\\\L^1 \times T^1 = [L^{(2n+m)}] \times [T^{(-n +2m)}]\\\\1 = 2n + m -----(1)\\\\1 = -n + 2m ----(2)\\\\from \ (1); \ m = 1-2n, \ \ substitute \ the \ value \ of \ m \ in\ (2)\\\\1= -n +2(1-2n)\\\\1 = -n + 2-4n\\\\1-2 = -5n\\\\-1 = -5n\\\\1= 5n\\\\n = \frac{1}{5} \\\\m = 1 - 2n\\\\m = 1 - 2(\frac{1}{5} )\\\\m = 1- \frac{2}{5} \\\\m = \frac{3}{5}\)


1.
Give the number of significant figures in the following:
5
A.
2.9910 x 10 m
C.
.0405 ml
B.
4500 km
D.
2.000 m
4

Answers

Answer:

It's B .0405 I just did this

Explanation:

ur welcome

are intramolecular forces stronger than intermolecular?

Answers

Answer:

syk

yidixilyyiyoiydiydil5dmi6dmiydl

A transfer of energy from thermal to potential

Answers

Conduction

The material which suppose Conduction called conductorsIn this heat is transmitted from one thermal to another .Metals are usually good conductors where as non metals are not

Explanation:

According to online, "thermal energy is just a fancy word for heat energy. It's a form of both potential and kinetic energy. If you remember, the electrons of an atom have potential energy. Once you apply pressure to the electrons, they start to move rapidly, banging into each other, and releasing thermal energy as heat."

Thermal energy transfers occur in three ways: conduction, convection, and radiation

An electromagnetic wave Group of answer choices a.Never moves b.Can travel through empty space or matter. c. Can travel only through empty space. d. Cannot travel through matter

Answers

Answer:

b

Explanation:

because electromagnetic waves can travel in vacuum as they don't require particles to transfer energy from one point to another. they can also travel through mediums such as the wall or air, if not how do radio waves transfer energy in this hyper advanced world? through the air

hope this helps

please mark it brainliest

On a cold day, the temperature often feels colder due to a wind chill. This is an
example of what type of phenomenon?
Convection
O Conduction
Induction.
O Radiation.
O None of these.

Answers

Answer:

Thermal conduction is the transfer of internal energy by microscopic collisions of particles and movement of electrons within a body. The colliding particles, which include molecules, atoms and electrons, transfer disorganized microscopic kinetic and potential energy, jointly known as internal energy. 

I believe it's conduction

A 0.850 kg mass is placed on a
spring, pulled and released. It
oscillates 40 times in 66.4 s.
What is the spring constant k?
(Unit = N/m)

Answers

Answer:

Picture

Explanation:

I am trying to solve this Q

but not sure if this a correct answer

or not.

Hope this helps.

A 0.850 kg mass is placed on aspring, pulled and released. Itoscillates 40 times in 66.4 s.What is the

Answer:

12.161 n/m

Explanation:

Trust me bro.

10. While deciding where to drive a supporting nail, you are pressing a
18-N picture frame against the wall to keep it from falling. What is the
minimum force perpendicular to the wall that you must exert on the frame to
keep it stationary? The coefficient of kinetic friction for the two surfaces in
contact is 0.42.

Answers

The minimum force perpendicular to the wall that you must exert on the frame to keep it stationary is 43 N.

What is  force?

A force is described as an influence that causes the motion of an object with mass to change its velocity.

Given data :

Force = 18 newton

mass = ?

Acceleration = ?

We know that force = mass x Acceleration but in this case, we are looking for the minimum force perpendicular to the wall that you must exert on the frame to keep it stationary.

We get that

perpendicular Force =  force / coefficient of kinetic friction

perpendicular Force = 18 / 0.42

perpendicular Force = 43 newton

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All of the following are properties of water EXCEPT: A.It is a good solvent. B.It has high surface tension due to its hydrogen bonding: C.lt has high heat capacity: D.It has cohesion and adhesion properties. E.It is a nonpolar molecule

Answers

All of the following are properties of water except this that  it is a nonpolar molecule. So, option E is correct.

Following ae the qualities of Water:

1) it is a good solvent.

2) Because of the hydrogen bonds in it, it has a high surface tension.

3) It has high heat capacity 

4) It possesses adhesive and cohesion qualities.

The majority of the time, nonpolar or organic solvents are used to dissolve nonpolar compounds. The charge is symmetrically distributed throughout these molecules.

Water has five key characteristics, including high polarity, high specific heat, high heat of vaporization, low solid density, and attraction to other polar molecules.

Polar molecules include water. Despite having a neutral overall charge, the molecule has two poles due to the orientation of the two positively charged hydrogen atoms (+1 each) at one end and the negatively charged oxygen atom (-2) at the other.

Hydrogen bonds could not develop in water if nonpolar covalent bonds rather than polar covalent bonds were used to create it. Due to the small charge difference between its two ends, water is a covalent polar molecule.

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Determine the thrust that a boat with a volume of 1.2m³ receives when it is stranded at sea. The density of seawater is 1020kg / m³.

Answers

Answer:

The maximum possible up-thrust on the boat is 11,995.2 N

Explanation:

According to Archimedes' principle, the thrust received by an object immersed a fluid is equal to the weight of the fluid displaced;

The given parameter of the boat in sea water are;

The volume of the boat = 1.2 m³

The density of seawater = 1020 kg/m³

Density = Mass/Volume

Therefore, Mass = Density × Volume

The maximum volume of water that the boat displaces = 1.2 m³

The mass of the water displaced by the boat = (Density of seawater) × (Volume of seawater displaced)

∴ The maximum possible mass of the water displaced by the boat = 1.2 m³ × 1020 kg/m³ = 1224 kg

The maximum possible mass of the water displaced by the boat, m = 1224 kg

Weight = Mass, m × g

Where;

g = The acceleration due to gravity = 9.8 m/s²

The up-thrust on the boat = The weight of the seawater displaced

∴ The maximum possible up-thrust on the boat = m × g = 1224 kg × 9.8 m/s² = 11,995.2 N

The maximum possible up-thrust on the boat = 11,995.2 N.

The tires of a car make 64 revolutions as the car reduces its speed uniformly from 90.0 km/h to 65.0 km/h. The tires have a diameter of 0.90 m. angular acceleration = -2.2 t= 20 sec required to stop 1. If the car continues to decelerate at this rate, how far does it go? Find the total distance.

Answers

To find the total distance traveled by the car, we need to determine the distance covered during the initial deceleration phase and the distance covered during the subsequent constant speed phase.

First, let's find the distance covered during the deceleration phase:

Convert the initial and final speeds from km/h to m/s:

Initial speed = 90.0 km/h = 25.0 m/s

Final speed = 65.0 km/h = 18.1 m/s

Calculate the average speed during deceleration:

Average speed = (Initial speed + Final speed) / 2 = (25.0 m/s + 18.1 m/s) / 2 = 21.55 m/s

Calculate the time taken for deceleration using the given angular acceleration:

Angular acceleration = -2.2 rad/s^2

Time = 20 s

Use the formula for distance traveled during uniformly accelerated motion:

Distance = (Average speed) * (Time) + (1/2) * (Angular acceleration) * (Time)^2

Distance = (21.55 m/s) * (20 s) + (1/2) * (-2.2 rad/s^2) * (20 s)^2

Now let's find the distance covered during the constant speed phase:

Calculate the number of revolutions made by the tires:

Number of revolutions = 64

Calculate the circumference of the tires:

Circumference = π * Diameter

Circumference = π * 0.90 m

Calculate the distance covered during constant speed using the formula:

Distance = (Number of revolutions) * (Circumference)

Finally, we can calculate the total distance traveled by summing up the distances from the deceleration and constant speed phases.

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A car moves a distance of 50. 0 km West, followed by a distance of 72 km North. What is the total distance traveled, in units of kilometers?

Answers

The total distance traveled by the car is approximately 87.68 kilometers.

To find the total distance traveled, we can use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

In this case, the car travels 50.0 km west and 72 km north. These distances form the legs of a right triangle, and the total distance traveled is the hypotenuse.

Using the Pythagorean theorem:

Total distance² = (Distance traveled west)² + (Distance traveled north)²

Total distance² = (50.0 km)² + (72 km)²

Total distance² = 2500 km² + 5184 km²

Total distance² = 7684 km²

Taking the square root of both sides to find the total distance:

Total distance = √7684 km²

Total distance ≈ 87.68 km

Therefore, the total distance traveled by the car is approximately 87.68 kilometers.

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A 0.149 kg glider is moving to the right on a frictionless, horizontal air track with a speed of 0.710 m/s . It has a head-on collision with a 0.308 kg glider that is moving to the left with a speed of 2.27 m/s . Suppose the collision is elastic.1. Find the magnitude of the final velocity of the 0.157kg glider.
2. Find the magnitude of the final velocity of the 0.306kg glider.

Answers

Answer:

v1 = −2.201946 m/s ( to the left)

v2 = 0.7780534 m/s ( to the right)

Explanation:

Given the following :

Mass of first glider (m1) = 0.149kg

Initial Speed of first glider (u1) = 0.710 m/s

Mass of second glider (m2) = 0.308kg

Initial Speed of second glider (u2) = 2.27m/s

For elastic collision:

m1u1 + mu2u2 = m1v1 + m2v2

Where V1 and v2 = final velocities if the body after collision.

Taking right as positive ; left as negative

u1 = 0.710m/s ; u2 = - 2.27m/s

u1 - u2 = - (v1 - v2)

0.710 - - 2.27 = - v1 + v2

v2 - v1 = 2.98 - - - - (1)

From:

m1u1 + mu2u2 = m1v1 + m2v2

(0.149 * 0.710) + ( 0.308 * - 2.27) = (0.149 * v1) + (0.308 * v2)

0.10579 + (-0.69916) = 0.149 v1 + 0.308v2

−0.59337 = 0.149 v1 + 0.308v2

Dividing both sides by 0.149

v1 + 2.067v2 = −0.59337 - - - - - (2)

From (1)

v2 = 2.98 + v1

v1 + 2.067(2.98 + v1) = −0.59337

v1 + 6.16 + 2.067v1 = −0.59337

3.067v1 = −0.59337 - 6.16

3.067v1 = −6.75337

v1 = −6.75337 / 3.067

v1 = −2.201946 m/s ( to the left)

From v2 = 2.98 + v1

v2 = 2.98 + (-2.201946)

v2 = 0.7780534 m/s ( to the right)

how many strings of eight english letters are there that contain no vowels, if letters can be repeated?

Answers

There are 20,971,520 strings of eight English letters that contain no vowels when letters can be repeated.To calculate the number of strings of eight English letters that contain no vowels.

we need to consider the total number of possible choices for each letter position.

In the English alphabet, there are 26 letters, including five vowels (A, E, I, O, U) and 21 consonants.

Since we want to create strings without vowels, we can choose any of the 21 consonants for each position in the string.

For each of the eight positions in the string, there are 21 choices (consonants) available.

Therefore, the total number of strings can be calculated as:

Total number of strings = Number of choices for each position ^ Number of positions

Total number of strings = 21^8 = 20,971,520

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A tractor pulls a 978 kg wagon at a velocity of 4.9 m/s. How many watts of power are exerted by the tractor motor is the tractor pulls the wagon at a 60 degree angle?

Answers

Answer:

23481.78 W

Explanation:

The computation of number of watts of power is shown below:

M = 978 kg

V = 4.9 m/s

Theeta = 60°

As we know that  

 P = Fcos(theeta).V

F = Mg

P = (Mg)cos(theeta).V

P = 978×9.8×cos(60)×4.9

P = 23481.78 W

. Why are the Jovian planets formed from materials different from the terrestrial planets?
a. Terrestrial planets were protected by the asteroid belt between Mars and Jupiter.
b. The composition of elements in a planet was a random process after the big bang.
c. When the solar system first formed, the heaviest elements sank toward the center of the nebulae and the lightest elements floated out.
d. Gaseous Jovian planets, formed farther away from the heat of the Sun, are formed from light weight nebulae "dust."
e. Only the terrestrial planets formed from planetesimals.

Answers

The Jovian planets are formed from materials different from the terrestrial planets for the reason that gaseous Jovian planets, formed farther away from the heat of the Sun, are formed from light weight nebulae "dust."

A Jovian planet, also known as a gas giant, is a huge planet that has a primarily gaseous composition. The Jovian planets include Jupiter, Saturn, Uranus, and Neptune. They are primarily made up of hydrogen and helium, and they have enormous atmospheres.Jovian planets are formed farther away from the heat of the Sun, so they are formed from lighter-weight nebulae "dust." Terrestrial planets, on the other hand, are formed nearer to the Sun, so they are formed from heavier-weight nebulae "dust." The density of the materials that make up the Jovian planets is lower than that of the terrestrial planets due to this. This means that the Jovian planets have lower densities and a greater volume than the terrestrial planets.

Hence, the correct option is d. Gaseous Jovian planets, formed farther away from the heat of the Sun, are formed from light weight nebulae "dust."

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