3. Show that if A is a symmetric matrix with eigenvalues A₁, A2,..., An, then the singular values of A are |A₁|, |A2|, ..., |An|·

The distance traveled over 9 hours at a speed of 840 km/h is 7,560 km.

Speed can be thought of as the rate at which an object covers distance.

A fast-moving object has a high speed and covers a relatively large distance in a given amount of time, while a slow

moving object covers a relatively small amount of distance in the same amount of time.

To calculate the distance traveled over 9 hours at a speed of 840 km/h, follow these steps:

1. Identify the time and speed given in the student question: 9 hours and 840 km/h.

2. Use the formula for distance:

distance = speed × time.

3. Plug in the values:

distance = 840 km/h × 9 hours.

4. Calculate the distance:

distance = 7,560 km.

So, the distance traveled over 9 hours at a speed of 840 km/h is 7,560 km.

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Answer:the answer will be 6

Step-by-step explanation:

answer:

f (2) = 6

step-by-step explanation:

f (2) = 3(2)^0 - 2(2)^-1 + 4

f (2) = 3(2)^0 - 2(2)^-1 + 4

f (2) = 3 - 1 + 4

f (2) = 3 - 1 + 4

f (2) = 2 + 4

f (2) = 6

The correct answer is -6 and 4. The values of x for which the equation x^2 + 2x = 24 is true are x = 4 and x = -6.

To find the values of x for which the equation x^2 + 2x = 24 is true, we need to solve the equation.

First, we can rewrite the equation as x^2 + 2x - 24 = 0.

Next, we can factor the quadratic equation:

(x - 4)(x + 6) = 0

Setting each factor equal to zero and solving for x, we get:

x - 4 = 0 -> x = 4

x + 6 = 0 -> x = -6.

The values of x that satisfy the equation x^2 + 2x = 24 are x = 4 and x = -6.

Verifying these values by substituting them back into the equation:

For x = 4: 4^2 + 2(4) = 16 + 8 = 24 (True)

For x = -6: (-6)^2 + 2(-6) = 36 - 12 = 24 (True)

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Answer: The value of the integral is 49/4 ln(2).

Step-by-step explanation:

We begin by finding a suitable change of variables that simplifies the integrand and makes it easier to integrate over the region R. In this case, we can use the transformation:

u = x - 7y

v = 3x - y

To obtain the Jacobian of this transformation, we take the partial derivatives of u and v with respect to x and y:

∂u/∂x = 1, ∂u/∂y = -7

∂v/∂x = 3, ∂v/∂y = -1

So, the Jacobian is given by: J = ∂(u,v)/∂(x,y) = (1)(-1) - (-7)(3) = 20

Now we can rewrite the integral in terms of u and v:

∬R 7x - 7y/(3x - y) da = ∬R (7u + 7v)/(20v) |J| du dv

where R is the region enclosed by the lines u = 0, u = 5, v = 2, and v = 7.

The limits of integration for u and v are determined by the intersection points of the lines that form the boundary of the parallelogram R. To obtain these points, we solve the following system of equations:

u = 0 and u = 5 - 7v/3

v = 2 and v = 7 - 3u/2

Solving for u and v, we get the following limits of integration:

0 ≤ u ≤ 5 - 7v/3

2 ≤ v ≤ 7 - 3u/2

Substituting these limits of integration into the integral expression, we have:

∬R 7x - 7y/(3x - y) da = ∫2^7 ∫0^(5-7v/3) (7u + 7v)/(20v) |J| du dv

Evaluating this double integral gives:∬R 7x - 7y/(3x - y) da = 49/4 ln(2)

Therefore, the value of the integral is 49/4 ln(2).

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The volume of the solid formed by rotating the region inside the first quadrant enclosed by the curves y = x and y = 5x about the x-axis is (250π/7) cubic units. When finding the volume of a solid of revolution, we use the method of cylindrical shells.

To calculate the volume, we integrate the area of each cylindrical shell formed by rotating an infinitesimally small strip about the x-axis. The height of each shell is the difference between the y-values of the two curves, which is (5x - x²). The circumference of each shell is given by 2πx, and the thickness is dx. Therefore, the volume of each shell is 2πx(5x - x²)dx.

To find the total volume, we integrate this expression over the interval where the two curves intersect. Setting\(y = x^2\)and y = 5x equal to each other, we get x² = 5x. Solving this equation, we find two intersection points: x = 0 and x = 5. Thus, the limits of integration are from 0 to 5.

Integrating the expression \(2\pi x(5x - x^2)dx\) from 0 to 5 gives us the volume of the solid formed by rotating the region inside the first quadrant. Evaluating this integral, we find the volume to be (250π/7) cubic units.

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Answer:

Step-by-step explanation:

John has the same preference as Kim. John loves to eat mango and the banana. Kim loves to eat mango but not the apple. Jim loves to eat banana but not the mango. John and Kim have the same preference for mango.

John's preference for mango can be inferred from the given information that he loves to eat mango and the banana. However, it does not mention anything about his preference for apples. Kim, on the other hand, loves to eat mango but not the apple. This aligns with John's preference for mango.

Among the given children, John and Kim have the same preference for fruits. They both love to eat mango, while John also enjoys eating bananas.

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Answer:

9

Step-by-step explanation:

keep adding

T is the linear transformation described by T(w,z) in L(C2). This indicates that the linear transformation T changes two-dimensional vectors of the type (w,z) to (-z,w).

To get T's eigenvalues, solve the equation T(v) = v, where is the eigenvalue and v is the eigenvector. By solving this equation, we discover that T's eigenvalues are λ1 = -1 and λ2 = 1.

For each eigenvalue, the associated eigenspaces are the subspaces of C2 that are spanned by the eigenvectors of T. The eigenspace is the subspace covered by the eigenvector λ1= -1 is (1,0). The eigenspace is the subspace spanned by the eigenvector λ2= 1 is (0,1).

As a result, the subspaces covered by (1,0) and (1,1) are the generalized eigenspaces corresponding to the different eigenvalues of T. (0,1).

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Answer:

m∠WXY + m∠YXZ = 180

Step-by-step explanation:

happy to help.

Answer:

x=19/27

Step-by-step explanation:

\(3(5x+2)=-5(3x-5)+3x\\15x+6=-15x+25+3x\\15x+6=-12x+25\\27x=19\\x= 19/27\)

Hope this helps plz hit the crown :D

\(3(5x+2)=-5(3x-5)+3x\)

Distribute 3 in 5x+2 and -5 in 3x-5

\(15x+6=-15x+25+3x\)

Multiplying 2 negatives will be positive (Same goes to dividing 2 negatives.)

\(15x+15x-3x=25-6\)

Move the x term to the same side and constant term to the same side.

(Whenever you move to another side, change the sign/operator to opposite. From plus to minus and from multiply to divide.)

\(27x=19\\x=\frac{19}{27}\)

Thus, the answer is 19/27

The mean absolute deviation of the given data set is 1.6 (rounded to the nearest tenth).

We have,

In statistics, the mean (also known as the arithmetic mean or average) is a measure of central tendency that represents the sum of a set of numbers divided by the total number of numbers in the set.

To find the mean absolute deviation (MAD), we need to first calculate the mean of the given data set:

mean = (4 + 5 + 7 + 9 + 8) / 5 = 6.6

Next, we calculate the deviation of each data point from the mean:

|4 - 6.6| = 2.6

|5 - 6.6| = 1.6

|7 - 6.6| = 0.4

|9 - 6.6| = 2.4

|8 - 6.6| = 1.4

Then we find the average of these deviations, which gives us the mean absolute deviation:

MAD = (2.6 + 1.6 + 0.4 + 2.4 + 1.4) / 5 = 1.6

Therefore, the mean absolute deviation of the given data set is 1.6 (rounded to the nearest tenth).

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Answer: 7.29

Step-by-step explanation: you divide the total cost which is 21.87 by 3 to get how much one pair of socks would be and that would be the unit price hope this helps

Therefore, the circumference of the triangle is 2r, which is equal to the diameter of the circle.

To find the circumference of the triangle, we need to first find the lengths of its sides. Let the three sides be x, y, and z, such that x:y:z is the given ratio. Without loss of generality, we can assume that x is the shortest side.

Let k be a constant such that y = kx and z = lx, where k and l are constants. Then, we have:

x + kx + lx = 2r

Simplifying this equation, we get:

x(1 + k + l) = 2r

So, we have:

x = (2r)/(1 + k + l)

y = kx = k(2r)/(1 + k + l)

z = lx = l(2r)/(1 + k + l)

The circumference of the triangle is the sum of its three sides:

C = x + y + z

Substituting the expressions for x, y, and z, we get:

C = (2r)/(1 + k + l) + k(2r)/(1 + k + l) + l(2r)/(1 + k + l)

Simplifying this expression, we get:

C = (2r(1 + k + l))/(1 + k + l)

C = 2r

Therefore, the circumference of the triangle is 2r, which is equal to the diameter of the circle.

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The area of the triangle is equal to A) 8.64. The Correct option is A) 8.64.

Let the lengths of the triangle be, 3x,4x,5x

Square of largest side = \(25x^{2}\)

Sum of square of other sides = \(3x^{2} + 4x^{2} = 25x^{2}\)

It is a right-angled triangle because the square of the greatest side equals the sum of the squares of the other sides.

The circumference of a right-angled triangle has a diameter equal to its hypotenuse.

hence, 5x=6 or x= \(\frac{6}{5}\)

Now, two perpendicular sides are then,  \(\frac{18 }{5} , \frac{24}{5}\)

\(Area = \frac{1}{2} \times \frac{18}{5} \times \frac{24}{5} = 8.64\)

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Question

A triangle with side lengths in the ratio 3 : 4 : 5 is inscribed in a circle of radius 3. The area of the triangle is equal to

A. 8.64

B. 12

C. 6

D. 10.5

Answer:

Step-by-step explanation:

9x - 2c = k

    9x = k + 2c

     x  = (k + 2c)/9

Answer: 1.4

Step-by-step explanation: First, swap the sides of the equation so that the one with the variable can be in front.

So, its 2y=2.8

To solve this, you simply divide both sides of the equation by 2.

2 divided by 2 is 0. That leaves you with the y by itself. Then, 2.8 divided by 2 is 1.4

So, y=1.4

\(\text {Hello! Let's solve this Equation!}\)

\(\text {The First Step is to Flip the Equation:}\)

\(\text {Before: 2.8=2y}\\\text {After: 2y=2.8}\)

\(\text {Your Final Step is to Divide by 2:}\)

\(\text {2y/2=2.8/2}\)

\(\text {Your Answer will be:}\)

\(\fbox {y=1.4}\)

\(\text {Best of Luck!}\)

\(\text {-LimitedX}\)

Answer:

84 ÷ -12 = -7

21 ÷ -3 = -7

Step-by-step explanation:

49 ÷ -7 = -7

Means that __ ÷ __ must equal -7

There are many options, here are a few:

84 ÷ -12 = -7

or -84 ÷ 12 = -7

21 ÷ -3 = -7 etc

The area of rhombus is 100m²

What is rhombus ?

A rhombus is a quadrilateral with four equal-length sides in planar Euclidean geometry. The term "equilateral quadrilateral" refers to a quadrilateral whose sides all have equal lengths.

A parallelogram is a particular instance of a rhombus. The opposing sides and angles in a rhombus are parallel and equal. A rhombus also has equal-length sides on each side, and its diagonals meet at right angles to form its shape. The rhombus is also referred to as a diamond or rhombus.

A quadrilateral with four equal sides that has the shape of a diamond is called a rhombus. In everyday life, rhombus-shaped objects can be seen. In the illustration below, two instances of rhombuses in nature are shown: a diamond and a kite.

The area of rhombus is

A = pq / 2

The  value of p is 10 and q is 20

A = (10 * 20) / 2

  = 100m²

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The major difference among three methods  for the evaluation of the accuracy of a classifier are, the hold-out method is simple and efficient, but may result in high variance. Cross-validation can reduce variance and is widely used in practice. Bootstrap can also reduce variance, but requires more computational resources.

The three methods for evaluating the accuracy of a classifier are the hold-out method, cross-validation, and bootstrap.

Here are the major differences among these methods:

Hold-out Method: This method involves splitting the original dataset into two subsets: a training set and a testing set. The training set is used to train the classifier, while the testing set is used to evaluate its accuracy.

The hold-out method is simple and efficient, but it may result in high variance because the testing set may not be representative of the population.

Cross-Validation: This method involves dividing the dataset into k equally-sized folds, where k is usually set to 5 or 10. The classifier is trained on k-1 folds, and the remaining fold is used to evaluate its accuracy.

This process is repeated k times, with each fold serving as the testing set exactly once. The results are averaged to obtain a more accurate estimate of the classifier's performance.

Cross-validation can reduce the variance associated with the hold-out method and is widely used in practice.

Bootstrap: This method involves randomly sampling the dataset with replacement to create a new dataset of the same size. The classifier is trained on the bootstrap sample, and the remaining data are used to evaluate its accuracy.

This process is repeated many times, and the results are averaged to obtain a more accurate estimate of the classifier's performance.

The bootstrap method can also reduce the variance associated with the hold-out method, but it requires more computational resources because the resampling is repeated many times.

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The quadrilateral with no pair of parallel sides is trapezium

Given data ,

A = a quadrilateral with no pair of parallel sides

This type of quadrilateral is called a trapezium. In some countries, a trapezium is defined as having exactly one pair of parallel sides, while in other countries, a trapezium is defined as having at least one pair of parallel sides.

In any case, a quadrilateral with no pair of parallel sides is not considered a trapezium. Instead, it is known as a general quadrilateral.

There are three types of trapezoids , and those are given below:

a) Isosceles Trapezoid

b) Scalene Trapezoid

c) Right Trapezoid

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The value of k that makes f(x) a probability density function is k = 1/9.

To determine the value of k that makes f(x) a probability density function, we must first determine if f(x) is non-negative and if its integral from negative infinity to infinity is equal to 1.

1. Since f(x) is non-negative for 0 ≤ x ≤ 3, we only need to check if f(x) is non-negative for x < 0 and x > 3.

2. f(x) = 0 for x < 0 and x > 3. Therefore, f(x) is non-negative for all x.

3. Now, we need to check if the integral of f(x) from negative infinity to infinity is equal to 1.

4. ∫(from -∞ to ∞) f(x) dx = ∫(from 0 to 3) k(3x − x^2) dx [since f(x) = 0 for x < 0 and x > 3]

5. ∫(from 0 to 3) k(3x − x^2) dx = k ∫(from 0 to 3) (3x − x^2) dx

6. ∫(from 0 to 3) (3x − x^2) dx = [3x^2/2 - x^3/3] (from 0 to 3) = 9

7. Therefore, ∫(from -∞ to ∞) f(x) dx = k ∫(from 0 to 3) (3x − x^2) dx = 9k

8. For f(x) to be a probability density function, ∫(from -∞ to ∞) f(x) dx = 1.

9. Therefore, 9k = 1

10. Solving for k, we get k = 1/9.

Therefore, the value of k that makes f(x) a probability density function is k = 1/9.

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Answer:

1) x = 9

2) y = 16

3) y = -1

Step-by-step explanation:

Do PEMDAS in reverse.

For every equation, your goal is to seperate the variable (x,y, or whatever letter) by itself.

1) 2x-7 = 11

Add 7 to both sides.

2x = 18

Divide both sides by 2.

x = 9

2) \(\frac{3}{4}y = 12\)

Divide both sides by 3/4 (which turns into multiplying by 4/3).

Left side

\(\frac{3}{4}x * \frac{4}{3}\\\\\frac{3}{4}x * \frac{4}{3} = \frac{3*4}{4*3}x\\1x\\x\)

Right side

\(12*\frac{4}{3}\\\\\frac{12}{1} *\frac{4}{3}\\\\ \frac{12}{1} *\frac{4}{3} = \frac{12*4}{1*3}\\\\\frac{48}{3} \\16\)

3) 9(y+3) = 18

Remember do PEMDAS in reverse.

Divide both sides by 9.

y+3 = 2

Subtract both sides by 3.

y = -1

Answer:

86

Step-by-step explanation:

74-(-12)=74+12=86

This answer cannot be in fraction because there is no fraction or decimal in the question .

Plz mark as brainliest

Answer:

-3

Step-by-step explanation:

cause positive = negative

the answer is = negative

Answer:

...…...................c = 50

The major methods of recording unstructured observational data are Narrative Description, Field Notes, Audio or Video Recording, Photography, Diagrams or Maps.

The major methods of recording unstructured observational data are:

1. Narrative Description: This method involves writing a detailed, chronological account of the observed events or behaviors, capturing the context and interactions as they occur naturally.

2. Field Notes: In this method, the observer takes brief, concise notes during the observation, focusing on key events, behaviors, or interactions. These notes can be expanded and organized later for further analysis.

3. Audio or Video Recording: Using audio or video equipment, the observer captures the events and interactions in their entirety. This allows for a more accurate record and the ability to review and analyze the data multiple times.

4. Photography: Taking photographs during the observation can provide a visual record of the events and behaviors. These images can supplement other data collection methods and help to illustrate specific aspects of the observation.

5. Diagrams or Maps: Drawing diagrams or maps of the observation setting can help capture the spatial relationships between individuals and objects, as well as the overall layout of the environment.

These methods can be used individually or in combination, depending on the research question and the specific needs of the study. Remember to always respect participants' privacy and obtain informed consent when necessary.

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Answer:

do the opposite

Step-by-step explanation:

multiply 8 times 4(instead of dividing)

x= 32

Answer:  here is your answer

Step-by-step explanation:

(9.3 × 10^6) + (1.8 × 10^4) is 93.18E+5.

(9.3 × 106) + (1.8 × 10^4)

(9.3 × 106) + (0.018 × 10^6)

(9.3 + 0.018)× 10^6

(9.318)× 10^6

scientific notation

(93.18E+5)

Classroom objects can be categorized as vertical or horizontal. Examples of vertical objects include doors, bookshelves, and clocks, while horizontal objects include desks, tables, and chairs.

In a classroom, there are many objects that are vertical and horizontal. Here are ten examples of each:

Vertical objects in a classroom:

1. Door                     6. Clock

2. Cabinet               7. Electrical outlets

3. Bookshelf            8. Light switches

4. Whiteboard         9. Window blinds

5. Flagpole             10. Bulletin board

Horizontal objects in a classroom:

1. Desks                  6. Keyboard trays

2. Chairs                 7. Carpet tiles

3. Tables                 8. Ceiling tiles

4. Countertops       9. Whiteboard markers

5. Shelves              10. Paper trays

These are just a few examples of vertical and horizontal objects that can be found in a classroom.

It is important to recognize the different shapes and orientations of objects in our environment, as they can affect the way we perceive and interact with them.

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