3. Given f(x) = x² - 7x +13 and g(x) = x-2, solve f(x) = g(x) using the substitution method. Show your


work.


Answer:

The value of x in the given quadratic equation is determined as -7 ± 8i.

The solutiion to the linear equation is determined as follows;

x² + 14x + 17 = -96

x² + 14x + 17 + 96 = 0

x² + 14x + 113 = 0

solve the equation using formula method;

a = 1, b = 14, c = 113

\(x = \frac{-b \ \ \pm\sqrt{b^2 - 4ac} }{2a} \\\\x = \frac{- 14\ \ \pm\sqrt{(14)^2 - 4(1\times 113)} }{2(1)} \\\\x = \frac{- 14\ \ \pm\sqrt{-256} }{2}\\\\x = \frac{- 14\ \ \pm\sqrt{256} \times \sqrt{-1} }{2}\\\\x = \frac{-14 \ \ \pm 16 \times i}{2} \\\\x = -7 \pm 8i\)

Thus, the value of x in the given quadratic equation is determined as -7 ± 8i.

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Answer:

-7 ± 8i.

Step-by-step explanation:

I took the test

Step-by-step explanation:

1. find P of semicircle

perimeter of a semicircle = pi×r+d

=3.14×5+10

=25.7

2.find P of rectangle

P=10×4=40cm

3. add P of semicircle and P of rectangle

25.7+40=65.7cm

Answer:

hypotenuse(?)

Step-by-step explanation:

There are 20 cars traveling at constant speeds on a 1 mile long ring track and the cars can pass each other freely. On the track 25% of the cars are traveling at 20 mph, 50% of the cars are traveling 10 mph, and the remaining 25% of the cars are traveling at an unknown speed. It was known that the space mean speed of all the cars on the track is 20 mph.

Therefore, the total number of cars with speed 20 mph is 0.25 × 20 = 5, and the total number of cars with speed 10 mph is 0.5 × 20 = 10.

Then, 5 cars are left with an unknown speed.

Given that the space mean speed of all the cars on the track is 20 mph,Therefore,5 × v + 10 × 10 + 5 × 20 = 20 × 20= 5v + 200 = 400

Thus, the speed of the remaining 25% of cars is:v = 40 mph(b) If an observer standing on the side of the track counted the number and measured t

Summary If an observer standing on the side of the track counted the number of cars passing him in 1 minute, he would see 20 cars and take 3 minutes to count them all.

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To find the joint density function, we need to calculate the Jacobian determinant of the transformation from (x, y) to (u, v)

The joint distribution of (u, v), where u and v are defined as

\(u = \frac{x}{{\sqrt{x^2 + y^2}}}\)  and \(v = \frac{y}{{\sqrt{x^2 + y^2}}}\), is given by:

\(f_{U,V}(u,v) = \frac{1}{{2\pi}} \cdot e^{-\frac{1}{2}(u^2 + v^2)}\)

To find the joint density function, we need to calculate the Jacobian determinant of the transformation from (x, y) to (u, v):

\(J = \frac{{du}}{{dx}} \frac{{du}}{{dy}}\)

\(\frac{{dv}}{{dx}} \frac{{dv}}{{dy}}\)

Substituting u and v in terms of x and y, we can evaluate the partial derivatives:

\(\frac{{du}}{{dx}} &= \frac{{y}}{{(x^2 + y^2)^{3/2}}} \\\frac{{du}}{{dy}} &= -\frac{{x}}{{(x^2 + y^2)^{3/2}}} \\\frac{{dv}}{{dx}} &= -\frac{{x}}{{(x^2 + y^2)^{3/2}}} \\\frac{{dv}}{{dy}} &= \frac{{y}}{{(x^2 + y^2)^{3/2}}}\)

Therefore, the Jacobian determinant is:

\(J &= \frac{y}{{(x^2 + y^2)^{\frac{3}{2}}}} - \frac{x}{{(x^2 + y^2)^{\frac{3}{2}}}} \\&= -\frac{x}{{(x^2 + y^2)^{\frac{3}{2}}}} + \frac{y}{{(x^2 + y^2)^{\frac{3}{2}}}} \\J &= \frac{1}{{(x^2 + y^2)^{\frac{1}{2}}}}\)

Now, we can find the joint density function of (u, v) as follows:

\(f_{U,V}(u,v) &= f_{X,Y}(x,y) \cdot \left|\frac{{dx,dy}}{{du,dv}}\right| \\&= f_{X,Y}(x,y) / J \\&= f_{X,Y}(x,y) \cdot (x^2 + y^2)^{\frac{1}{2}}\)

Substituting the standard normal density function

\(f_{X,Y}(x,y) &= \frac{1}{2\pi} \cdot e^{-\frac{1}{2}(x^2 + y^2)} \\f_{U,V}(u,v) &= \frac{1}{2\pi} \cdot e^{-\frac{1}{2}(x^2 + y^2)} \cdot (x^2 + y^2)^{\frac{1}{2}} \\&= \frac{1}{2\pi} \cdot e^{-\frac{1}{2}(u^2 + v^2)}\)

Therefore, the joint distribution of (u, v) is given by:

\(f_{U,V}(u,v) &= \frac{1}{2\pi} \cdot \exp\left(-\frac{1}{2}(u^2 + v^2)\right)\)

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To find the joint density function, we need to calculate the Jacobian determinant of the transformation from (x, y) to (u, v)

The joint distribution of (u, v) is a bivariate normal distribution with mean (0,0) and variance-covariance matrix

\(\begin{bmatrix}2 & 0 \0 & 2\end{bmatrix}\)

The joint distribution of (u, v) can be found by transforming the independent random variables x and y using the following formulas:

\( u = x + y\)
\( v = x - y \)

To find the joint distribution of (u, v), we need to find the joint probability density function (pdf) of u and v.

Let's start by finding the Jacobian determinant of the transformation:

\(J = \frac{{\partial (x, y)}}{{\partial (u, v)}}\)

\(= \frac{{\partial x}}{{\partial u}} \cdot \frac{{\partial y}}{{\partial v}} - \frac{{\partial x}}{{\partial v}} \cdot \frac{{\partial y}}{{\partial u}}\)

\(= \left(\frac{1}{2}\right) \cdot \left(-\frac{1}{2}\right) - \left(\frac{1}{2}\right) \cdot \left(\frac{1}{2}\right)\)

\(J = -\frac{1}{2}\)

Next, we need to express x and y in terms of u and v:

\(x = \frac{u + v}{2}\)

\(y = \frac{u - v}{2}\)

Now, we can find the joint pdf of u and v by substituting the expressions for x and y into the joint pdf of x and y:

\(f(u, v) = f(x, y) \cdot |J|\)

\(f(u, v) = \left(\frac{1}{\sqrt{2\pi}}\right) \cdot \exp\left(-\frac{x^2}{2}\right) \cdot \left(\frac{1}{\sqrt{2\pi}}\right) \cdot \exp\left(-\frac{y^2}{2}\right) \cdot \left|-\frac{1}{2}\right|\)

\(f(u, v) = \frac{1}{2\pi} \cdot \exp\left(-\frac{u^2 + v^2}{8}\right)\)

Therefore, the joint distribution of (u, v) is given by:

\(f(u, v) = \frac{1}{2\pi} \cdot \exp\left(-\frac{{u^2 + v^2}}{8}\right)\)

In summary, the joint distribution of (u, v) is a bivariate normal distribution with mean (0,0) and variance-covariance matrix

\(\begin{bmatrix}2 & 0 \0 & 2\end{bmatrix}\)

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Answer:

I think its D

Step-by-step explanation:

You can rule out A and B because he would be able to throw it farther than 30 ft do that leaves C and D but davis Couldn't throw a 9.1 lb ball 30 ft so the answer is D

Given that the discharge current decreases to 27% of its initial value in 1.40 ms, we can use the equation of discharge current:

The capacitance of the capacitor is 0 F.

Part A:

Given that the discharge current decreases to 27% of its initial value in 1.40 ms, we can use the equation of discharge current:

I = I₀e^(-t/RC)

Here,

I₀ = initial current

R = resistance

C = capacitance

t = time

We are given that the current is 27% of the initial value, so the equation becomes:

0.27 = \(1e^(-1.40*10^-3/RC)\)

Simplifying the equation, we find:

RC =\(3.28* 10^-3 s\)   ----(1)

Part B:

The time taken to discharge a capacitor through a resistance R is given by:

t = RC ln (Vc/V₀)

where Vc = voltage across the capacitor at time t and V₀ = initial voltage across the capacitor.

Substituting the values, we have:

\(1.40*10^-3\) = C*90 ln (0/100)

Since a fully discharged capacitor has a voltage of 0, we set Vc = 0. Thus, the equation becomes:

\(1.40*10^-3\)= C*90 ln (0)

The natural logarithm of 0 is negative infinity. Therefore, the equation becomes:

\(1.40*10^-3\)= C*90*(-infinity)

Simplifying further, we find:

C = 0

Thus, the value of capacitance is 0 F.

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Kosumi has 71 books.

Let's represent the number of books Kaden has as "K" and the number of books Kosumi has as "S". From the problem, we know that:

K + S = 189 (together they have 189 books)

K = S + 47 (Kaden has 47 more books than Kosumi)

We can substitute the second equation into the first equation to solve for S:

(S + 47) + S = 189

2S + 47 = 189

2S = 142

S = 71

Therefore, Kosumi has 71 books.

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Answer:

=42+115x

10x

Step-by-step explanation:

3(7/5x+ 4) – 2( 3/2- 5/4)

=21/5x+12-2(6/4-5/4)

=21/5x+12-2×1/4

=21/5x+12-1/2

=21/5x+24/2-1/2

=21/5x+23/2

=42/10x+115x/10x

=42+115x

10x

Answer:

13x

Step-by-step explanation:

Answer:

13x

Step-by-step explanation:

So we need to make the denominator equal in order to collect like terms.

25x^2/5x+8x^2/x =?

Denominator needs to be 5x so multiply the second quotient by 5.

25x^2/5x + 40x^2/5x = ?

=65x^2/5x

=13x^2/x      <---- x^2/x is like 2-1 which is exponent 1, x to the exponent 1 is x

=13x

Your answer is 13x

Answer:

1

Step-by-step explanation:

it just is

The graph will consist of two diagonal lines: one representing Mary's initial walk, turnaround, and return to the classroom, and the other representing her run to lunch with a gradual decrease in speed as she approaches the cafeteria.

To sketch a distance vs. time graph based on the given description, we'll represent the time on the x-axis and the distance on the y-axis.

A. Mary left her classroom and walked at a steady pace to head to lunch:

In this portion, Mary is walking at a steady pace, indicating a constant speed. We can represent this as a straight, diagonal line on the graph, starting from the initial distance (0) and increasing gradually over time until she reaches halfway to the lunch area.

B. Halfway there, Mary stopped to look through her bag for her phone but couldn't find it:

At the halfway point, Mary stops to search her bag. Since she is stationary during this time, the graph will show a horizontal line at the same distance she reached before stopping. This horizontal line represents the time Mary spends searching her bag.

C. Mary turned around to quickly return to her classroom to get her phone that she left at her desk:

After realizing her phone is in the classroom, Mary turns around to go back. This is represented by a straight, diagonal line on the graph, but in the opposite direction. The distance decreases as she retraces her steps until she reaches the classroom.

D. Mary then ran all the way to lunch, gradually decreasing her speed as she neared the cafeteria:

Once Mary retrieves her phone, she runs all the way to lunch. Initially, the graph will show a steeper diagonal line, indicating an increase in distance covered over time. However, as she approaches the cafeteria, her speed gradually decreases. This is represented by a shallower diagonal line on the graph, showing a slower increase in distance over time.

Overall, the graph will consist of two diagonal lines: one representing Mary's initial walk, turnaround, and return to the classroom, and the other representing her run to lunch with a gradual decrease in speed as she approaches the cafeteria. The horizontal line in the middle represents the time Mary spends searching her bag.

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Answer:

a = 3     b = -4

Step-by-step explanation:

 4  (0.1a -0.4b) = (1.9)      0.4a - 1.6b = 7.6

     0.4a - 1.6b = 7.6

-     0.4a +0.5b = -0.8

-2.1b = 8.4

b = -4

0.4a + 0.5(-4) = -0.8

0.4a - 2 = -0.8

0.4a = 1.2

a = 3

​

Answer: It will take approximately 30 months to pay off the $500.00.

Step-by-step explanation:

Since we have given that

Principal = $10.00

Amount = $500.00

Rate of interest = 18.24%

So, we will apply "Compound interest" to find the number of months:

\(A=P(1+\dfrac{r}{100})^n\\\\500=10(1+\dfrac{18.24}{100})^n\\\\500=11.824^n\\\\\n\approx 2.5\)

So, the number of months would be

\(2.5\times 12=30\ months\)

Hence, it will take approximately 30 months to pay off the $500.00.

Answer:

A  5    is the distance between

Step-by-step explanation:

(-2 -2)^2   +  ( 0-3)^2 = d^2

d = 5

Answer:

Step-by-step explanation:

(2/3)20

All are favourite for me ....

Answer:  There is a total of 900 seats in the auditorium.

Step-by-step explanation:

there is a formula for this

t - n = a + ( n - 1) d

It is called a Arithmetic Progression.

We use this to find the number of seats in the last row first.

a = initial value, 12

d = common difference for each successive term

n = is the number of terms in the sequence

t - 25 = 12 + (25 -1) * 2

We ignore the left side for now, just solve the right and we get 60.

Now we use the equation,

n / 2 (2a + n -1 * d)

So,

25/2 ( 24 + 24 * d)

The answer is 900

The length of the curve x = 1/3 √y (y − 3)  is 64/3.

The distance between two point along a segment of a curve is known as the arc length.

The equation of the curve is given by:

x = 1/3 √y (y − 3), 16 ≤ y ≤ 25

Length of the curve y = f(x) between point  x =a to x = b is given by:  

\(\int\limits^b_a {\sqrt{1+[f'(x)]^2} } \, dx\)

 √1 + [f′(x)]2 dx.

x = 1/3 √y (y − 3)

x = 1/3 * \(y^\frac{3}{2}\) - \(y^\frac{1}{2}\)

Let's find the first derivative of x.

dx/dy = 1/3. 3/2.  \(y^\frac{1}{2}\)- 1/2 .  \(y^\frac{1}{2}\)

dx/ dy = 1/2 ( \(y^\frac{1}{2}\) - \(y^\frac{-1}{2}\))

(dx/dy)^2= 1/4 (  \(y^\frac{1}{2}\) - \(y^\frac{-1}{2}\))^2

= 1/4(y + \(y^-^1\)-2)

1 + {f′(x)}2 = 1 + 1/4(y +\(y^-^1\)-2)

= 1/4 y + 1/4\(y^-^1\)+ 1/2

1 + {f′(x)}2= 1/4 (y + \(y^-^1\) + 2)

√[1 + {f′(x)}2] = 1/2 (  \(y^\frac{1}{2}\) +  \(y^\frac{-1}{2}\))

Length of curve  is given by:  

25

∫   \(\frac{\sqrt{y} }{2} +\frac{1}{2\sqrt{y} }\) dy

16

= \(\left \{ {{y=25} \atop {x=16}} \right.\) [\(y^\frac{3}{2}\)/3 + √y]

= [(25)3/2 /3 + √25] - [(16)3/2 /3 + √16]

= [125/3 + 5] - [64/3 + 4]

= 140/3 - 76/3

= (140 - 76)/3

= 64/3

So the length of the curve is 64/3

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The area is 250.5 in^2

Answer:

Feature 1- Statement A, Feature 2-Statement 2, Feature 3- Statement 1

Answer: 11

Step-by-step explanation: Just took the test

The length of the apothem of the pentagon is approximately 11 meters.

Polygon is defined as a geometric shape that is composed of 3 or more sides these sides are equal in length, and an equal measure of angle at the vertex,

Examples of polygons, equilateral triangles, squares, pentagons etc.

Here,
To solve this problem, we can use the formula for the area of a regular pentagon:

A = (5/2) × s × a

Where A is the area of the pentagon, s is the length of one side, and a is the apothem (the distance from the center of the pentagon to the midpoint of a side).

We know that the area of the pentagon is 118.25 square meters and the length of one side is 4.3 meters. We can substitute these values into the formula and solve for the apothem:

118.25 = (5/2) × 4.3 × a

Divide both sides by (5/2) x 4.3:

a = 118.25 / ((5/2) × 4.3)
  = 118.25 / 10.75 ≈ 11 meters

Therefore, the length of the apothem of the pentagon is approximately 11 meters.

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Answer:

no pic or better explanation

Step-by-step explanation:

if you give a pic or explanation we cant help sorry

The sum of the lengths of the other two sides of a right triangle will be 841.

We have,

The shortest leg of a right triangle = 29,

And,

According to the question,

The other leg and hypotenuse of a right triangle are consecutive whole numbers,

i.e.

Let,

Other leg = x,

And,

Hypotenuse = x+1,

So,

Now,

Using Pythagoras Theorem,

(Hypotenuse)² = (Perpendicular)² + (Base)²

i.e.

H² = P² + B²

So,

Now Putting values,

i.e.

(x+1)² = x² + 29²

So,

On Solving we get,

x² + 1 + 2x = x² + 841

⇒

x² + 2x - x² = 841 - 1

We get,

2x = 840

So,

x = 420

I.e.

Other leg = 420,

So,

Hypotenuse = x+1 = 420 + 1 = 421,

Now,

The sum of the lengths of the other two sides of right triangle,

i.e.

Hypotenuse + Other leg = 420 + 421 = 841

Hence we can say that the sum of the lengths of the other two sides of a right triangle will be 841.

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The following answer is correct

To find the relative maxima and minima of the function f(x, y) = x^2 + xy + y^2 + 4x + 5y, we need to find the critical points by taking the partial derivatives with respect to x and y and setting them equal to zero.

∂f/∂x = 2x + y + 4 = 0 ...(1)

∂f/∂y = x + 2y + 5 = 0 ...(2)

Solving equations (1) and (2) simultaneously, we get:

x = -3

y = -1

To determine whether these critical points are relative maxima or minima, we need to evaluate the second partial derivatives. Calculate ∂^2f/∂x^2, ∂^2f/∂y^2, and ∂^2f/∂x∂y at the critical point (-3, -1).

∂^2f/∂x^2 = 2 ...(3)

∂^2f/∂y^2 = 2 ...(4)

∂^2f/∂x∂y = 1 ...(5)

To determine the nature of the critical point, we use the second derivative test. Since ∂^2f/∂x^2 > 0 and (∂^2f/∂x^2)(∂^2f/∂y^2) - (∂^2f/∂x∂y)^2 = 2*2 - 1^2 > 0, the critical point (-3, -1) is a relative minimum.

The function f(x, y) = x^2 - 3y^2 has only one critical point at (0, 0). To determine the type of the critical point, we use the second derivative test

∂^2f/∂x^2 = 2 ...(6)

∂^2f/∂y^2 = -6 ...(7)

∂^2f/∂x∂y = 0 ...(8)

At the critical point (0, 0), we have ∂^2f/∂x^2 > 0 and (∂^2f/∂x^2)(∂^2f/∂y^2) - (∂^2f/∂x∂y)^2 = 2*(-6) - 0^2 < 0. This indicates that the critical point (0, 0) is a saddle point.

The production capacity function is given as Y(K, L) = 2K^0.25L^0.75. To find the marginal product of labor (∂Y/∂L), we differentiate Y(K, L) with respect to L while treating K as a constant.

∂Y/∂L = 0.752K^0.25L^(0.75-1) = 1.5K^0.25L^-0.25

Given that the company hires 16 workers and rents a capital of $810,000, we can substitute these values into the derivative:

∂Y/∂L = 1.5*(810,000)^0.25*(16)^-0.25

Calculating this expression will give you the marginal product of labor.

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A type I error occurs when a researcher mistakenly rejects a true null hypothesis. In other words, it is a false positive result. Let's break down what happens in a type I error:

1. The researcher starts with a null hypothesis, which assumes that there is no significant relationship or effect between the variables being studied.

2. To test the null hypothesis, the researcher collects data and performs statistical analysis.

3. In a type I error, the researcher incorrectly concludes that there is a significant relationship or effect when, in fact, there is none.

4. This error can happen due to various reasons, such as sample size, random chance, or flaws in the experimental design.

To avoid type I errors, researchers typically set a predetermined significance level (often denoted as α) before conducting the study. The significance level represents the probability of making a type I error. By setting a lower significance level, such as α = 0.05, researchers aim to reduce the chances of mistakenly rejecting the null hypothesis.

In the context of the given question, if the researcher is trying to reduce error and avoid a type I error, it means they want to minimize the risk of incorrectly inferring findings to another practice setting. This would increase the confidence that nurses have in applying the research findings to their own work.

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The equation which has been given is a linear equation, therefore in order to solve the equation, simply the basic mathematical operation is to be performed. The acquired value of x is not the same as the value. So, when 12=13.x+5, the value of x=21 is not true.

Given information:

The equation given in the question is: 12 = 3x + 5

The value of x=21

Perform the basic mathematical operations and find the value of a variable.

  13x + 5 =12

⇒13x = 12 -5

⇒ 13x = 7

⇒ x = 7/13

⇒ x = 0.538

The acquired value of x is not the alike as the given value.

Hence, when 12=13.x+5 the value of x=21 is not true.

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