3. 200 × 38.4 =

4. 900 × 20.7 =
help please it has to be solved like this 400*45.2=400* 45+400*0.2=18000+80=18080

Answer:

The answer could be A

Step-by-step explanation:

Got this from another Brainly user

Answer:

Step-by-step explanation:

a-6

b-165-240

c-165

d-182 and 152

e-174

To determine the number of gallons of paint needed to cover office 143, we need to know the square footage of the office.

Once we have that information, we can divide the square footage by the coverage rate per gallon to calculate the required amount of paint.

Let's assume the square footage of office 143 is 800 square feet.

Number of gallons needed = Square footage / Coverage rate per gallon

Number of gallons needed = 800 square feet / 50 square feet per gallon

Number of gallons needed = 16 gallons

Therefore, you would need approximately 16 gallons of paint to cover office 143, assuming each gallon covers 50 square feet.

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The value of f(3) is 4. To find f(3), we need to use the given information about the slope of the tangent line and the point through which the graph passes.

The slope of the tangent line at any point (x,f(x)) on the graph is given as 7x + 5. This means that the derivative of f(x), denoted as f'(x), is equal to 7x + 5.

To find the function f(x), we need to integrate f'(x) with respect to x. Integrating 7x + 5 gives us the original function f(x) =\((7/2)x^2 + 5x + C,\)where C is the constant of integration.

We are given that the graph of f(x) passes through the point (6,8). Plugging these values into the equation, we get 8 = \((7/2)(6)^2 + 5(6) + C.\)Solving for C, we find C = -27.

Now we have the function f(x) = \((7/2)x^2 + 5x - 27\). To find f(3), we substitute x = 3 into the equation: f(3) =\((7/2)(3)^2 + 5(3) - 27 = 4.\)Therefore, f(3) equals 4.

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The associated doubling time is also approximately 27.725 (rounded to three significant digits).

To find the associated half-life time or doubling time, we first need to understand what these terms mean.
Half-life time (th) is the amount of time it takes for half of a substance to decay or be eliminated.

In this case, we are dealing with exponential decay, so we can use the formula:
q = q0 * e^(-kt)

where q is the amount of substance remaining at time t, q0 is the initial amount of substance, k is the decay constant, and e is Euler's number (approximately equal to 2.71828).

We are given the equation q = 800e^(-0.025t), which means that the initial amount of substance (q0) is 800 and the decay constant (k) is 0.025.

To find the half-life time, we need to find the value of t when q = q0/2:
q0/2 = 800/2 = 400
400 = 800e^(-0.025t)

Dividing both sides by 800, we get:
0.5 = e^(-0.025t)

Taking the natural logarithm of both sides, we get:
ln(0.5) = -0.025t

Solving for t, we get:
t = ln(0.5)/(-0.025)

Using a calculator to evaluate this expression, we get:
t ≈ 27.725

Therefore, the associated half-life time is approximately 27.725 (rounded to three significant digits).

Doubling time (td) is the amount of time it takes for a substance to double in amount. In this case, we can use the formula:
q = q0 * e^(kt)

where k is the growth constant (since we are looking at the increase in amount rather than the decrease).

To find the doubling time, we need to find the value of t when q = 2q0:
2q0 = 2 * 800 = 1600
1600 = 800e^(0.025t)

Dividing both sides by 800, we get:
2 = e^(0.025t)

Taking the natural logarithm of both sides, we get:
ln(2) = 0.025t

Solving for t, we get:
t = ln(2)/0.025

Using a calculator to evaluate this expression, we get:
t ≈ 27.725

Therefore, the associated doubling time is also approximately 27.725 (rounded to three significant digits).

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Answer:

x= -34/3

Step-by-step explanation:

just solve by multiplying both sides by 15, then distribute 10 and 3 through the parenthesis, multiply both sides by 2, move the variable to the left side and change the sign, move the constant and change the sign, combine like terms, calculate the sum, and finally divide both sides by -3

38 + ( 8m + 4 ) = 90

Subtract both sides 38

38 - 38 + ( 8m + 4 ) = 90 - 38

8m + 4 = 52

Subtract both sides 4

8m + 4 - 4 = 52 - 4

8m = 48

Divide both sides by 8

8m ÷ 8 = 48 ÷ 8

The solution to the systems of equations graphically is (2, 4)

From the question, we have the following parameters that can be used in our computation:

y = 2x

y = -x + 6

Next, we plot the graph of the system of the equations

See attachment for the graph

From the graph, we have solution to the system to be the point of intersection of the lines

This points are located at (2, 4)

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(a) Using a left-endpoint Riemann sum, we can estimate the integral of f(x) over the interval from 0 to 10.

The left-endpoint Riemann sum is obtained by multiplying the width of each subinterval by the function value at the left endpoint of that subinterval and summing all the products. In this case, the width of each subinterval is 2 units. Evaluating the sum: (2 * 45) + (2 * 44) + (2 * 42) + (2 * 37) + (2 * 27) + (2 * 7) gives us 212. Therefore, the estimate for the integral of f(x) using the left-endpoint Riemann sum is 212.

(b) Using a right-endpoint Riemann sum, we can estimate the integral of f(x) over the same interval. The right-endpoint Riemann sum is obtained by multiplying the width of each subinterval by the function value at the right endpoint of that subinterval and summing all the products. In this case, the width of each subinterval is still 2 units. Evaluating the sum: (2 * 44) + (2 * 42) + (2 * 37) + (2 * 27) + (2 * 7) + (2 * 0) gives us 202. Therefore, the estimate for the integral of f(x) using the right-endpoint Riemann sum is 202.

(c) To find the average of the left- and right-endpoint Riemann sums, we add the results from parts (a) and (b) and divide the sum by 2. (212 + 202) / 2 equals 207. Therefore, the average of the left- and right-endpoint Riemann sums gives us an estimate of 207 for the integral of f(x) over the interval from 0 to 10.

Using a left-endpoint Riemann sum, the estimated integral of f(x) over the interval from 0 to 10 is 212. Using a right-endpoint Riemann sum, the estimated integral is 202. The average of these two sums gives an estimate of 207 for the integral of f(x) over the same interval.

Riemann sums are methods used to approximate the area under a curve by dividing the interval into subintervals and summing the areas of rectangles. In this case, the table provides us with discrete values of f(x) at specific points. To estimate the integral, we divide the interval from 0 to 10 into subintervals of equal width, which is 2 units in this case. In a left-endpoint Riemann sum, we multiply the width of each subinterval by the function value at the left endpoint of that subinterval and sum all the products. The right-endpoint Riemann sum follows a similar principle, but we use the function value at the right endpoint of each subinterval. Taking the average of the left- and right-endpoint Riemann sums provides a more balanced estimate. In this example, the left-endpoint Riemann sum yields an estimate of 212, the right-endpoint Riemann sum gives 202, and their average is 207. These estimates provide approximations for the integral of f(x) over the given interval.

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Answer:

3y +9 = perimeter

Step-by-step explanation:

Answer:

4y+9

Step-by-step explanation:

To find the perimeter , you have to add up all the 4 sides

so y + y+2 + y+4 + y+3 = 4y+ 9

hope it helps

Looking at the function, there are two sections of the graph, one on the interval [-1, 1) and the other on the interval [1, ∞). On the first interval, the function corresponds to a quadratic function. The endpoints are (-1, 1) and (1, 1), so the function should be:

On the other hand, the second section of the graph is a horizontal parabola, so the function corresponds to a square root function. It passes through the points (1, 1), (4, 2), and (9, 3), so the function should be:

Then, the piecewise function is:

Step-by-step explanation:

the correct answer is option a 6a-7

The function f(x) = x^2 * e^(-x) is increasing on the interval (-∞, 2) and decreasing on the interval (2, ∞).

To determine where the function is increasing or decreasing, we need to analyze the sign of its derivative.

Taking the derivative of f(x) with respect to x, we have f'(x) = 2xe^(-x) - x^2e^(-x) = xe^(-x)(2 - x).

To find the intervals where the function is increasing or decreasing, we need to examine the sign of f'(x) in different intervals.

Considering the critical points, we set f'(x) equal to zero and solve for x:

xe^(-x)(2 - x) = 0.

This equation gives us two critical points: x = 0 and x = 2.

Now, we can analyze the sign of f'(x) in the intervals (-∞, 0), (0, 2), and (2, ∞).

For x < 0, both x and e^(-x) are negative, so f'(x) = xe^(-x)(2 - x) < 0.

Between 0 and 2, x is positive and e^(-x) is also positive, yielding f'(x) = xe^(-x)(2 - x) > 0.

For x > 2, x is positive and e^(-x) is negative, resulting in f'(x) = xe^(-x)(2 - x) < 0.

From this analysis, we conclude that f(x) is increasing on the interval (-∞, 2) and decreasing on the interval (2, ∞).

In summary, the function f(x) = x^2 * e^(-x) is increasing on the interval (-∞, 2) and decreasing on the interval (2, ∞). The critical point x = 0 acts as a local minimum, while x = 2 serves as a local maximum. The function rises from negative infinity to the local maximum at x = 2 and then declines indefinitely.

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Answer:

56 marbles in total

Step-by-step explanation:

32 blue marbles + 24 green marbles

yes what the person above me said

Answer:

above sea level

Step-by-step explanation:

Answer:

8 hours

Step-by-step explanation:

Convert all the hours to minutes, then convert back at the end.

Answer:

OK SO THE OTHER THING DOES NOT LET US TEXT SOOO HERES THE OTHER ONE

Step-by-step explanation:

Answer:

2.71428571429

Step-by-step explanation:

lol

Answer:

x = 2, y = - 1

Step-by-step explanation:

Given the 2 equations

y = - 7x + 13 → (1)

y = - 1 → (2)

Substitute y = - 7x + 13 into (2)

- 7x + 13 = - 1 ( subtract 13 from both sides )

- 7x = - 14 ( divide both sides by - 7 )

x = 2

y = - 1 is already given in (2)

Then x = 2, y = - 1

Answer:

36.25 miles per gallon

Step-by-step explanation:

4/5 = .8

29/.8 = x/1

cross-multiply:

.8x = 29

x = 36.25

If a scatterplot shows a non-linear relationship between the response and explanatory variable, several options can be considered depending on the purpose of the analysis and the nature of the data.

Here are some possible actions:

Transform the data: One common approach is to transform the data to make the relationship linear. For example, if the relationship appears to be exponential, taking the logarithm of the response variable might make it linear. Similarly, taking the square root, cube root, or inverse of one or both variables might also help.

Use a non-linear model: Another option is to fit a non-linear model that can capture the curvature in the relationship. There are many types of non-linear models, such as quadratic, cubic, exponential, logistic, or spline models. The choice of model depends on the shape of the curve and the underlying theory or hypothesis.

Resample or subset the data: If the non-linear relationship is driven by outliers, influential points, or a subset of the data, it might be helpful to resample or subset the data to remove them. For example, trimming the extreme values, bootstrapping the data, or stratifying the data by a third variable might help.

Explore alternative variables or interactions: If the non-linear relationship is due to an unobserved or omitted variable, it might be useful to explore alternative variables or interactions that could explain the pattern. For example, if the response is sales and the explanatory variable is price, adding a competitor's price or a marketing variable might improve the fit.

Use caution in interpretation: Finally, if the non-linear relationship persists after exploring the above options, it might be necessary to acknowledge the non-linearity and use caution in interpreting the results. Non-linear relationships can be more difficult to interpret and extrapolate, and the statistical inference might be more uncertain or sensitive to assumptions.

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Answer:

Do you still need this question answered?

Step-by-step explanation:

Some exponential for you completed. As attached.

Answer:

10

One tank is 25 buckets of water, so 2/5 of a tank is 10 buckets of water.

Answer:

62.5

Step-by-step explanation:

Let the capacity of 1 bucket = x.

Then, the capacity of tank = 25x.

New capacity of bucket = 2x/5

Required number of buckets = 25x / (2x/5)

= 25x * 5/2x

= 125/2 = 62.5

The translation of the coordinate points on the graph by linear displacement in comparison of original points ( x , y ) get translated to     ( x + h,  y + k ) where h ∈R , k ∈R.

As given in the question,

Let us consider original coordinate point on a given graph be ( x ,y ).

Translation represents the change in the linear displacement or the location without changing the shape and size.

Shift of the point may be horizontally or vertically.

Let 'h' and 'k' be the horizontal and vertical shift.

If the horizontal shift is right then it is represented by x + h

If the horizontal shift is left then it is represented by x - h

If the vertical shift is up then it is represented by y +k

If the vertical shift is down then it is represented by y - k.

Therefore, the translation of the coordinate points on a given graph represented by original points ( x , y ) get translated to ( x + h,  y + k ) where h ∈R , k ∈R.

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Answer: Hello, hope this helps :)

Step-by-step explanation:

Total number of vacant seats = 4 seat

Number of students Looking for Seats = 12 Student

We have to fill the four Seats and there are 12 students.

First Seat can be filled in 12 ways,11 students are left, So, second seat can be filled in 11 ways ,Now, there are 10 students left ,So, third seat can be filled in 10 ways, Now there are 9 students left, so last seat can be filled in 9 ways.

Total number of ways of filling 4 seats if there are 12 number of students

              =12 × 11 × 10 × 9

             =132 × 90

            =  11880 ways

Or ,you can solve it directly by the concept of Permutation.

Total ways of filling 4 vacant seats if there are 12 students in all

=12/4 P= 12/(12-4)= 12x 11 x 10 x 9 x 8 / 8 = 12x 11 x 10 x 9 x 8= 11880

So your answer would be:

11880

Happy Halloween! Let me know if this helps please, thanks!

Answer:

8 red flyers and 8 blue flyers

Step-by-step explanation:

Packs of red flyers = 8

Blue flyers = 4

Jenny realizes that she gave out the same number of red and blue flyers

Find the lowest multiples of 8 and 4

8 = 8, 16, 24, 32

4 = 4, 8, 12, 16

The lowest common multiples of 8 and 4 is 8

Therefore,

The minimum number of flyers of each color is

8 red flyers and 8 blue flyers

Hey there!

Finding the the answer to the [Binomial]

(a + b)^2

CONVERT:

= (a + b)(a + b)

DISTRIBUTE

= a(a) + a(b) + b(a) + b(b)

= a^2 + ab + ab + b^2

COMBINE the LIKE TERMS

= (a^2) + (ab + ab) + (b^2)

= a^2 + ab + ab + b^2

= a^2 + 1ab + 1ab + b^2

= a^2 + 2ab + b^2

Therefore, your answer should be:

a^2 + 2ab + b^2

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

We have the parabola with equation y = 4x².

We have to determine the shape and direction of it.

If we compare it to the standard equation y = ax² + bx + c, we can see that a = 4, b = 0 and c = 0.

As the value of a is positive, the parabola will open upward.

The parameter has an absolute value greater than 1. This means that y increases "faster" relative to x that a parabola with a = 1.

This means that the parabola will be narrow about its line of symmetry which we call vertical strecth.

Answer:

Because a is positive the parabola opens upward.

Because a has an absolute value larger than 1 the parabola is narrow about its line of symmetry which we call vertical stretch.

1) The value of unit tangent vector T is,  (-√(3)/2√(50), -1/2√(50), -1/√(50))

2) The value of unit normal vector N is, (-1/2, -(√(3))/2, 0)

3) The value of unit binormal vector B is, ( (√(3))/2, -1/2, 0)

At t = π/6, we have:

r(π/6) = (cos(7(π/6)), sin(7(π/6)), -1(π/6)) = (1/2, (√(3))/2, (-π/6))

To find the unit tangent vector T, we differentiate r(t) with respect to t and then normalize the result:

r'(t) = (-7sin(7t), 7cos(7t), -1) | r'(π/6)| = √( (7sin(7(π/6)))² + (7cos(7(π/6)))² + (-1)² ) = √( 49 + 1 ) = √(50)

T = r'(π/6) / |r'(π/6)| = (-7sin(7(π/6))/√(50), 7cos(7(π/6))/√(50), -1/√(50))

= (-√(3)/2√(50), -1/2√(50), -1/√(50))

Next, we can find the unit normal vector N by differentiating T with respect to t, normalizing the result, and then making sure it is orthogonal to T:

T'(t) = (-49cos(7t), -49sin(7t), 0)

|T'(π/6)| = √(49²) = 49

N = T'(π/6) / |T'(π/6)| = (-cos(7(π/6)), -sin(7(π/6)), 0)

= (-1/2, -(√(3))/2, 0)

To find the unit binormal vector B, we can use the cross product of T and N, which will also be a unit vector:

B = T x N = ( (√(3))/2, -1/2, 0)

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To determine whether the vector u belongs to the null space of the matrix A, we need to check if Au equals the zero vector. The vector u is given as u = [2], and matrix A is given as A = [-2 3 -8; 4 -3 18; 1]. We need to determine if the equation Au = 0 holds.

To check if the vector u belongs to the null space of matrix A, we multiply matrix A by vector u and see if the resulting vector is the zero vector. Multiplying the given values, we have Au = [-22 + 34 - 81; 42 - 32 + 181; 1*2] = [-4 + 12 - 8; 8 - 6 + 18; 2] = [0; 20; 2].

Since the resulting vector Au is not equal to the zero vector [0; 0; 0], we can conclude that the vector u does not belong to the null space of matrix A.

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