2x + 8y = 20
y = 3

Can someone tell me the answer to this pls I beg you

\({ \begin{array} {l}\\ \quad \qquad \huge\color{green}{\boxed{ \colorbox{black}{ \color{green}{ \tt {Answer}}} }} \\ \\ \dashrightarrow \sf5(9 - x) + 2 {}^{2} \div 2 \\ \\ \dashrightarrow \sf45 - 5x+ (4 \div 2) \\ \\ \dashrightarrow \sf45 - 5x + 2\\ \\ \dashrightarrow\sf47 - 5x\\ \\ \texttt{hence, the equivalent expression is : -5x + 47 }\end{array}} \)

The two-sample z-test statistic for evaluating the null hypothesis that the percentage of students who support capital punishment did not change from 1970 to 2005 is -4.08 (rounded to two decimal places).

To calculate the two-sample z-test statistic, we need to compare the proportions of students who support capital punishment in 1970 and 2005. The null hypothesis states that the percentage of students who support capital punishment did not change.

Let p1 be the proportion of students who support capital punishment in 1970, and p2 be the proportion in 2005. We can calculate the sample proportions as p1 = 590/1000 = 0.59 and p2 = 350/1000 = 0.35.

The formula for the two-sample z-test statistic is given by z = (p1 - p2) / sqrt((p(1 - p)(1/n1 + 1/n2))), where p is the pooled proportion and n1 and n2 are the sample sizes.

To calculate p, we compute the pooled proportion as p = (p1n1 + p2n2) / (n1 + n2) = (0.591000 + 0.351000) / (1000 + 1000) = 0.47.

Substituting the values into the formula, we have z = (0.59 - 0.35) / sqrt((0.47*(1 - 0.47)(1/1000 + 1/1000))) = -4.08.

Therefore, the two-sample z-test statistic for evaluating the null hypothesis is -4.08 (rounded to two decimal places).

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Answer:

Its asking what x 2=1 it would be

Step-by-step explanation: 0.5 or 1/2

Answer:

(8,0)

Step-by-step explanation:

the three points are col linear means they are on same line

R ___________________________P_________________Q

(-12,0)                                                   (0,0)                                  (x,y)

y is zero since P is at the origin with coordinate(0,0)

PR=12 ( the distance is the absolute value and always positive)

PQ/PR=2/3

PQ/12=2/3

PQ=24/3=8

(8,0)

We have the equation of a parabola.

We can express the coordinates of the vertex (h,k) using the coefficients of the parabola:

As the parabola is y=x²+4x-6, the expression for h and k is:

Then, the coordinates of the vertex are (h,k) = (-2,-10).

Answer: The vertex is (-2,-10)

To find the coordinates of the image of b1 under the transformation, we substitute [x1, x2] = [1, 0] (since b1 = b11 + b20):

X-Ax = [1 + 0; 4(1) + 6(0)] = [1; 4]

So we need to express [1; 4] as a linear combination of b1 and b2:

[1; 4] = a1b1 + a2b2

To find the coefficients a1 and a2, we solve the system of equations:

a1 + 6a2 = 1

a1 + a2 = 4

This gives a1 = 2 and a2 = 2/3. Therefore, the coordinates of the image of b1 under the transformation are [2; 2/3].

Similarly, we can find the coordinates of the image of b2:

X-Ax = [0 + 1; 4(0) + 6(1)] = [1; 6]

[1; 6] = b1c1 + b2c2

Solving for c1 and c2:

c1 = -5/3, c2 = 8/3

Therefore, the coordinates of the image of b2 under the transformation are [-5/3; 8/3].

Putting these results together, we get the B-matrix for the transformation X-Ax:

B = [2 -5/3; 2/3 8/3]

To find T(3b4 - 7b2), we need to express 3b4 - 7b2 as a linear combination of B:

[3; -7] = d1*[2; 2/3] + d2*[-5/3; 8/3]

Solving for d1 and d2:

d1 = -13/18, d2 = -11/18

Therefore, T(3b4 - 7b2) = d1T(b1) + d2T(b2) = (-13/18)*T(b1) + (-11/18)*T(b2)

Since [T]8 = [T(b1) T(b2)]^-1[B]8, we can find T(b1) and T(b2) by solving the system of equations:

T(b1)*[2 -5/3] = [1 0]

[2/3 8/3]

T(b2)*[2 -5/3] = [0 1]

[2/3 8/3]

This gives:

T(b1) = [5/3 -1/3; -1/3 2/3]

T(b2) = [2/3 1/3; 2/3 -1/3]

Therefore, T(3b4 - 7b2) = (-13/18)[5/3 -1/3; -1/3 2/3] + (-11/18)[2/3 1/3; 2/3 -1/3]

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In light of the query we've got D)x + y ≤ -2 and 2x - 3y ≤ -9 is a pair of inequalities for (-3, 1) is the correct answer.

When resolving an inequality, you can do one of the following: · Add a same number to each side; • Subtract the same amount from each side; • Multiply or divide either aspect by the exact positive amount. You must flip the inequality sign if you combine or split each end by a negative number.

According to the values x = -3, y = 1

-3 + 1 = -2, which is less than or equal to -2, so the first inequality is true.

2 * -3 - 3 * 1 = -9, which is less than or equal to -9, so the second inequality is also true.

Since both inequalities are true, (-3, 1) is a solution for the system of inequalities x + y ≤ -2 and 2x - 3y ≤ -9.

we get ,

x + y ≤ -2

2x - 3y ≤ -9

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The Complete Question :

For which system of inequalities is (-3, 1) a solution?

A. x+y<-2 and 2x-3y <-9

B. x+y<-2 and 2x-3y <-9

C. x+y≤-2 and 2x-3y <-9

D. x+y≤-2 and 2x-3y ≤-9

The points on the given curve where the tangent line has slope 1 are (-107/54, 19/54) and (-25/27, -91/108).

To find the points on the given curve where the tangent line has slope 1, we need to find where dy/dx = 1.
Using implicit differentiation, we get:
dx/dt = \(6t^2\)
dy/dt = 5/12 - 14t
dy/dx = (dy/dt) / (dx/dt) = (5/12 - 14t) / (\(6t^2\))
Now we set dy/dx = 1:
1 = (5/12 - 14t) / (\(6t^2\))
Simplifying, we get:
\(6t^2\) = 5/12 - 14t
Rearranging, we get a quadratic equation:
\(6t^2\) + 14t - 5/12 = 0
Using the quadratic formula, we get:
t = (-14 ± \(\sqrt{(14^2 - 4*6*(-5/12))}\)) / (2*6)
Simplifying, we get:
t = (-7 ± \(\sqrt{(157)}\))/12
Now we can find the corresponding values of x and y by plugging these values of t into the original equations:
When t = (-7 + \(\sqrt{(157)}\))/12:
x = \(2t^3\) = -107/54
y = 5/12 - 14t = 19/54
So the point is (-107/54, 19/54).
When t = (-7 - \(\sqrt{(157)}\))/12:
x = \(2t^3\) = -25/27
y = 5/12 - 14t = -91/108
So the point is (-25/27, -91/108).

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For a larger input size of 320,000 elements, it will take 240 ms to sort each half and 24 ms to merge the sorted halves, resulting in a total time of 264 ms.

The given information describes the time required for sorting and merging operations on two different input sizes. For 80,000 elements, it takes 18 ms to sort each half, resulting in a total of 36 ms for sorting. Merging the two sorted halves with 80,000 numbers in each takes 40 - 18 = 22 ms.

When the input size is doubled to 320,000 elements, the sorting time for each half increases to 240 ms, as it scales linearly with the input size. The merging time, however, remains constant at 4 ms since the size of the sorted halves being merged is the same.

Thus, the total time for sorting and merging 320,000 elements is the sum of the sorting time (240 ms) and the merging time (4 ms), resulting in a total of 264 ms.

Therefore, based on the given information, the total time required for sorting and merging 320,000 elements is 264 ms.

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Answer:

Step-by-step explanation:

Use the distance formula to determine the distance between the two points.

Distance = √ ( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2

Substitute the actual values of the points into the distance formula.

√ ( ( − 1 ) − 2 ) 2 + ( 4 − ( − 9 ) ) 2

Simplify.

√ 178

The result can be shown in multiple forms.

Exact Form:

√ 178

Decimal Form:

13.34166406 …

:) Hope this helped!! :)

Answer:

0.00128

Step-by-step explanation:

1.28 x 10^-1 x 10^-2

1.28 x 0.1 x 0.01

1.28 x 0.1 x 0.01

0.00128

Answer:

The slope between the two points: (3, 20) and (5, 8) is -6.​

Step-by-step explanation:

Put the points in the slope formula:

m = (y₂ - y₁)/(x₂ - x₁)

Substitute the values.

m = (8 - 20)/(5 - 3)

Subtract.

m = (-12)/2

Divide.

m = -6

Answer:

x= 68.19°

Step-by-step explanation:

you can use inverse of cos(x)

\(cos^{-1}\)(\(\frac{2}{5}\)) =68.19°

∴ x=68.19°

Answer:

we can find the value of x using cos.

cos=adjacent side/hypotenuse

\(cos(x)=2/5\\\)

Using inverse cos, we can find the value of x

\(cos^-1(2/5)=66.42182152\\x=66\)

(Rounded)

Step-by-step explanation:

Answer:

B 8.5 Pounds

Step-by-step explanation:

I hope this helps!

Answer: 8.5

Step-by-step explanation:

16 ounces is a pound

so we divide 136 by 16 and get 8.5

Since n = 1 is a positive integer for which the proposition is true, then p(1) is true.

Direct Proof:

Assume n is a positive integer.

Show that n²  ≥ n.

Substitute n = 1 into the equation n²  ≥ n

Solve the equation 1² ≥ 1

Show that 1² = 1, and 1 ≥ 1.

Therefore, n² ≥ n is true for n = 1.

This is an example of a direct proof, in which we start by assuming the statement is true for a particular value before using logical processes to demonstrate that it must be true for all values.

Before solving the problem, we made the assumption that n was a positive integer, added n = 1, and then proved that the assertion was accurate for n = 1. This establishes the statement's applicability to all positive numbers.

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Answer:

11 packets both bread rolls and hotdogs. bread rolls 5 and hotdogs 6

Step-by-step explanation:

So it's LCM.

18:15

90:90

Answer:

5 packets of bread rolls and 6 packets of hotdogs.

Step-by-step explanation:

18x=15y

6x=5y

x/y=5/6

18(5)=15(6)

Answer:

opposite numbers

equidistant

Step-by-step explanation:

example, if 'b' = 1 then 'c' is the opposite which is -1

The experiment of drawing two cards without replacement from a deck consisting of only the ace through 10 of a single suit (e.g., only hearts) has a sample space consisting of all possible pairs of cards that can be drawn. There are a total of 45 possible outcomes in the sample space.



Ai = {(j,k) : j + k = i, where j and k are values of the cards in the suit}
For example, if i = 7, then the event A7 consists of the following outcomes:
A7 = {(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)}

Note that we have excluded the outcome (1,1) from this event, since we are assuming that an ace counts as 1 and not 11. If we wanted to include the possibility of an ace being worth 11, we would need to modify the definition of Ai to account for this. However, the problem statement specifies that we should treat the aces as having a value of 1, so we will stick with this convention.

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Answer:-22/3

Step-by-step explanation:

its negative because it represents an irrational number

Answer: -22/3

Why: It's irrational since it's negative

Answer:

The answer is: y=5x-4 (you had it right)

Answer:

Ok if u answer my questio...

Step-by-step explanation:

i can my snp is lit_dogface

The probability that a randomly chosen college student exercises in the morning or afternoon is 0.76

We have given that the M be the event that the student exercises in the morning and A be the event that the student exercises in the afternoon.

To find : The probability that a randomly chosen college student exercises in the morning or afternoon

P(M) = 0.25+0.37 = 0.62

P(A) = 0.14+0.37 = 0.51

P(M and A) = 0.37

Now,

P(M or A) = P(M) + P(A) - P(M and A)

                = 0.62 + 0.51 - 0.37

                = 0.76

Hence, Option last 0.76 is the correct choice.

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The expression does not have like terms that can be combined, so it remains as is:

4g² + 7ab - 2b²

5x8 - 5 can be simplified as follows:

5x8 - 5 = 40 - 5 = 35

x² - x² - x + 1 can be simplified as follows:

The x² terms cancel out:

x² - x² - x + 1 = -x + 1

6413 - 1 is a subtraction of two numbers:

6413 - 1 = 6412

4g² + 7ab - 2b² can be simplified further:

The expression does not have like terms that can be combined, so it remains as is:

4g² + 7ab - 2b²

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Answer:

area ≈ 12.505

perimeter ≈  16.1684

Step-by-step explanation:

We are given

- the radius of the circle (and therefore area of the circle)

- the area of the triangle

We want to find

- angle AOB/AOT. We want to find this because 360/the angle gives us how many OABs fit into the circle. For example, if AOT was 30 degrees, 360/30 = 12 (there are 360 degrees in a circle, so that's where 360 comes from). The area of the circle is equal to πr² = π6² = 36π, and because AOT is 30 degrees, there are 12 equal parts of sector OAB in the circle, so 36π/12=3π would be the area of the sector. A similar conclusion can be reached from the circumference instead of the area to find the distance between A and B along the circle, and OA + AB + BO = the perimeter of the minor sector.

First, we can say that OAT is a right triangle because a tangent line is perpendicular to the line from the center to the point on the circle, so AT is perpendicular to OA. This forms two right angles, one of which is OAT

One thing that we can start to solve is AT. We know that the area of a triangle is equal to base * height /2, and the height of this triangle is AO, with the base being AT. Therefore, we can say

15 = AO * AT / 2

15 = 6 * AT / 2

15 = 3 * AT

divide both sides by 3 to isolate AT

AT = 5

Because OAT is a right triangle, we can say that the hypotenuse ² =  the sum of the squares of the two other lengths. The hypotenuse is opposite of the largest angle (in this case, the right angle, as in a right triangle, the right angle is always the largest), so it is OT in this case. The other two sides are OA and AT, so we can say that

OA² + AT² = OT²

5²+6² = OT²

25+36=61=OT²

square root both sides

OT = √61

Next, the Law of Sines states that

sinA/a = sinB/b = sinC/c with angles A, B, and C with sides a, b, and c. Corresponding sides are opposite their corresponding angles, so in this case, AT corresponds to angle AOT, OT corresponds to angle OAT, and AO corresponds to angle ATO.

We want to find angle AOT, as stated earlier, so we have

sin(OAT)/OT = sin(ATO)/OA = sin(AOT)/AT

We know the side lengths as well as OAT/sin(OAT) and want to figure out AOT/sin(AOT), so one equation that helps us get there is

sin(OAT)/OT = sin(AOT)/AT, encompassing our 3 known values and isolating the one unknown. We thus have

sin(90)/√61 = sin(AOT) /5

plug in sin(90) = 1

1/√61 = sin(AOT)/5

multiply both sides by 5 to isolate sin(AOT)

5/√61 = sin(AOT)

we can thus say that

arcsin(5/√61) = AOT ≈39.80557

As stated previously, given ∠AOT, we can find the area and perimeter of the sector. There are 360/39.80557 ≈ 9.04396 equal parts of sector OAB in the circle. The area of the circle is πr² = 36π, so 36π / 9.04396 ≈ 12.505 as the area. The circumference is equal to π * diameter = π * 2 * radius = 12 * π, and there are 9.04396 equal parts of arc AB in the circumference, so the length of arc is 12π / 9.04396 ≈ 4.1684. Add that to OA and OB (both are equal to the radius of 6, as any point from the center to a point on the circle is equal to the radius) to get 6+6 + 4.1684 = 16.1684 as the perimeter of the sector

Answer:

Always.

Step-by-step explanation:

Congruent means equal in mathematics. And equilateral triangles' sides are always equal. Therefore, always is your answer.

A) always

since equilateral triangles have the same side length.

Answer:

B. y = |2x| - 2.

Step-by-step explanation:

If we start with y = 2x:

this passes through the origin and has a slope of 2.

y = |2x| means the absolute ( positive) values only,  so the part of the line below the x axis is reflected in the axis to form a V shaped graph.

So we have a V shaped graph with the vertex at (0, 0).

Then -2 brings the vertex from (0, 0) to (0  -2) so we get:

y = |2x| - 2.

Answer:

4.95 mL

Step-by-step explanation:

Since we have 400 mg/m² of gemcitabine for a patient whose BSA is 0.47 m², the mass of drug required for the patient is thus m = 400 mg/m² × 0.47 m² = 188 mg.

Also, since 200 mg vial of gemcitabine for injection that contains 38 mg per mL, so the concentration of gemcitabine is 38 mg/mL.

Since concentration = mass/volume, and

volume = mass/concentration,

the volume of gemcitabine injection required is

V = mass of gemcitabine/concentration of gemcitabine in injection

V = 188 mg/38 mg/mL

V = 4.95 mL

Answer:

can you please send the diagram for it to be clear

The equation for the temperature, d, in terms of t (the number of hours since midnight), is:  d = 16 × sin((π/12) × t) + 55

To find an equation for the temperature, we need to determine the amplitude, period, phase shift, and vertical shift of the sinusoidal function.

The amplitude is half the difference between the high and low temperatures, which is (71 - 39) / 2 = 16 degrees. The period is the number of hours in a day, which is 24 hours. Since the temperature is at its highest point at 12:00 PM (midday), there is no phase shift. The vertical shift is the average of the high and low temperatures, which is (71 + 39) / 2 = 55 degrees.

Putting these values together, the equation for the temperature, d, in terms of t can be written as:

d = 16 × sin((2π/24) × t) + 55

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